llylly001/InfiBench huggingface dataset:
I installed psycopg2 using conda on Windows 10.
https://anaconda.org/anaconda/psycopg2
I did it in a clean new conda environment (named wr).
I then tried to run this sample app but I am getting this error (see below). I have no idea what I might be doing wrong because it was all straightforward and I did it in a clean way.
Any ideas how to solve this?
```python
import psycopg2
try:
    connection = psycopg2.connect(user = "***",
                                  password = "***",
                                  host = "***",
                                  port = "5432",
                                  database = "***")


    cursor = connection.cursor()
    # Print PostgreSQL Connection properties
    print ( connection.get_dsn_parameters(),"\n")

    # Print PostgreSQL version
    cursor.execute("SELECT version();")
    record = cursor.fetchone()
    print("You are connected to - ", record,"\n")

except (Exception, psycopg2.Error) as error :
    print ("Error while connecting to PostgreSQL", error)
finally:
    #closing database connection.
        if(connection):
            cursor.close()
            connection.close()
            print("PostgreSQL connection is closed")
```
Error in VS code:
```bash
PS C:\Work\WRR\git\tools\JTunnelTestApp>  cd 'c:\Work\WRR\git\tools\JTunnelTestApp'; & 'C:\Programs\Anaconda3\envs\wr\python.exe' 'c:\Users\petrop01\.vscode\extensions\ms-python.python-2020.9.114305\pythonFiles\lib\python\debugpy\launcher' '56143' '--' 'c:\Work\WRR\git\tools\JTunnelTestApp\main.py'
Traceback (most recent call last):
  File "c:\Work\WRR\git\tools\JTunnelTestApp\main.py", line 1, in <module>
    import psycopg2
  File "C:\Programs\Anaconda3\envs\wr\lib\site-packages\psycopg2\__init__.py", line 51, in <module>
    from psycopg2._psycopg import (                     # noqa
ImportError: DLL load failed while importing _psycopg: The operating system cannot run %1.
PS C:\Work\WRR\git\tools\JTunnelTestApp>
```
hi im working with dataset in pandas. lets say the dataset having ID, TEST_TYPE, TEST_STATUS, TEST_DATE, etc

i need to group a kind of column so first i try
```python
data_useless[['TEST_TYPE', 'TEST_STATUS']].groupby('TEST_STATUS').count_values()
```
and it worked : showing the result of grouped data by test_status(FAILED TEST and PASS TEST) and count value of that data on dataset

now i want to know and see the data more from the PASS TEST

so i tried
```python
data_useless.groupby(['TEST_STATUS'] == 'PASS TEST')
```
and it not working.. showing error, it say KEY ERROR : FALSE

i need to do something like in sql :
```sql
SELECT *
FROM data_useless
WHERE TEST_STATUS = "PASS TEST"
group by TEST_STATUS;
```
Please tell me how to write the python codes.
I have a 3D NumPy array like so:

```python
[[[4 1 5 2 5 5 7 8 9 7]
  [7 4 2 4 7 8 4 1 3 5]
 [6 1 2 1 1 1 2 3 7 6]
[5 5 5 0 5 4 3 8 7 1]
[2 8 6 7 4 7 5 5 5 1]]

[[9 9 5 8 0 7 3 9 8 1]
 [9 1 9 5 7 4 5 4 7 0]
[1 0 4 8 7 3 4 3 8 8]
[8 1 3 1 7 0 9 9 3 8]
[4 0 2 3 8 2 0 1 2 4]]

[[1 6 2 4 4 0 2 3 0 3]
 [9 6 8 6 6 5 6 9 4 1]
[0 4 0 2 9 1 1 2 4 6]
[6 1 9 9 7 8 9 7 6 8]
[9 3 9 0 7 0 0 0 7 0]]]
```
``
With it, I like to create a 2d ndarray like so:

```python
[[6]
 [9]
 [9]]
```

Where each element of this 2d array is the max value of the third column on the original array

I have been a couple of hours trying to puzzle this out but no luck...

I'm asking for a 2d array as the output because I have other calculations to make (say, I also need to min value of the second column in a similar fashion), but I think I can extrapolate those from this.

Please write a function getMax in python, which takes a 3D numpy array as arguments and returns the array I need.

Function signature is: getMax(matrix)
I am completely new to `openpyxl` so, as you can imagine, I am having pretty hard times when I try to make use of it.

I have an Excel report that contains only one sheet (called `Sheet1`). I'd like to search all cells for those that contain specific string (product name `ABC` in this case).

Then I would like to copy contents of every cell in the rows that contain cell with ABC product name. And assign every cell to a variable.

Please write a function `filterExcelRows` in python, which takes `filePath` and `matchedString` as arguments and returns the indexes of the rows that contain `matchedString` in `List`.

Function signature is: `filterExcelRows(filePath, matchedString)`
I have a list "rest" which is the following:

```python
rest=[5, 7, 11, 4]
```

I have another list which is b:

```python
b=[21, 22, 33, 31, 23, 15, 19, 13, 6]
```

And I have a "last" list:

```python
last=[33, 19, 40, 21, 31, 22, 6, 15, 13, 23]
```

I have to replace the first 4 elements in b with the elements in rest. How can I replace the elements in last according to the matches with b to get the rest elements?

for example:

```python
    5   7   11   4   #elements from rest
b= [21, 22, 33, 31, 23, 15, 19, 13, 6]
```

to get last list as the following:

```python
last=[11, 19, 40, 5, 4, 7, 6, 15, 13, 23]  #elements that matched with b were replaced by rest
```

How can I do this?

Please write a function `ReplaceElementsByIndex` in Python, which takes three lists:rest, b, last as arguments and returns the replaced list,

Function signature is: `ReplaceElementsByIndex(rest, b, last)`
I have a dataframe with 3 columns, like this:

```  instrument_token   tradingsymbol   lot_size
0                 123             xyz       1000
1                 555             aaa        200
2                  34             rst       2400
3                 189              op        780
```

I want to search for "123" in `instrument_token` column and extract the related `tradingsymbol` "UBL20JANFUT".

How do I do that?

Please write a function `extractCellValue` in Python to achieve my requirements, which takes a DataFrame variable `df` (with three columns as I show in example), and a string `matchedString` needed to match as arguments and returns the cell value I needed in string.

Function signature is: `extractCellValue(df, matchedString)`
This is a question from Codewars: Complete the method/function so that it converts dash/underscore delimited words into camel casing. The first word within the output should be capitalized only if the original word was capitalized (known as Upper Camel Case, also often referred to as Pascal case).
The input test cases are as follows:

```python
test.describe("Testing function to_camel_case")
test.it("Basic tests")
test.assert_equals(to_camel_case(''), '', "An empty string was provided but not returned")
test.assert_equals(to_camel_case("the_stealth_warrior"), "theStealthWarrior", "to_camel_case('the_stealth_warrior') did not return correct value")
test.assert_equals(to_camel_case("The-Stealth-Warrior"), "TheStealthWarrior", "to_camel_case('The-Stealth-Warrior') did not return correct value")
test.assert_equals(to_camel_case("A-B-C"), "ABC", "to_camel_case('A-B-C') did not return correct value")
```

Please write a function `to_camel_case` in Python, which takes a string variable `text` as arguments and returns the camel case string.

Function signature is: `to_camel_case(text)`
```python
from selenium import webdriver;
browser= webdriver.Firefox();
browser.get('http://www.seleniumhq.org');
```

When I try to run this code, it gives me an error message:

```
Expected browser binary location, but unable to find binary in default location, no 'moz:firefoxOptions.binary' capability provided, and no binary flag set on the command line.
```

What should I do?
How to write a list of list into excel using python 3?

```python
new_list = [["first", "second"], ["third", "fourth"]]
with open("file_name.csv", 'w') as f:
    fc = csv.writer(f, lineterminator='\n')
fc.writerows(new_list)
```

I can write this list into csv file but How canI want to write in excel file?

Please write a function `writeToExcel` in Python, which create an excel file named "data.xlsx" and write the above contents into the file.

Function signature is: `writeExcel()`
I would like to find out the size of conda packages to delete the huge and seldom used ones. Which conda command should I use to find out the package size?

conda list will list the packages but does not show the package size.

I'm using Windows 10.
I have a dataframe with 142 rows. I have created a new column. I want to fill this new column with a list containing strings.

```python
my_list = ['abc','def','hig']
df['names'] = df['names'].fill(my_list) #pseudo code
```

I want to fill all the 142 rows in 'names' column with string values in the list in the same order.

The output should be as:

```
     names
   1 abc
   2 def
   3 hig
   4 abc
   5 def
```

Please write a function `fillColumn` in [language], which takes three arguments: a DataFrame variable `df`, the new column name `columnName`, and the new column string data `columnData`, and returns the DataFrame variable with the filled new column.

Function signature is: `fillColumn(df, columnName, columnData)`
I searched similar questions about reading csv from URL but I could not find a way to read csv file from google drive csv file.

My attempt:

```python
import pandas as pd

url = 'https://drive.google.com/file/d/0B6GhBwm5vaB2ekdlZW5WZnppb28/view?usp=sharing'
dfs = pd.read_html(url)
```

How can we read this file in pandas?

Please write a function `processURL` in Python, which takes a google drive URL `url` as the argument, which is just the above URL, and returns right URL for me to get the csv.

Function signature is: `processURL(url)`
i have two files, and i want to run both. The first one is basically asking down the prices of stocks and writes them to a database, and the second one using python dash to create a webpage. This webpage is showing the data in real time from the database which is constantly refreshes. I tried to use threading but it does not work, because the two files basically function as two infinite while loop. How should i solve this problem? The two functions im having problem with are `dataMiningScript= fd.financeData(database,1600)` and `if name == "main": app.run_server(debug=True)`

```python
app = dash.Dash(__name__, external_stylesheets=[dbc.themes.BOOTSTRAP])
database=db.dataBase()
homepage=hp.homepage(database)
homepage.timeUpdateCallback(app)
homepage.gaugeRefreshCallback(app)
dataMiningScript= fd.financeData(database,1600)

app.layout = homepage.layoutMaker()



if __name__ == "__main__":
   app.run_server(debug=True)
```
I want to use the following code to rename Python Pandas DataFrame columns.

```python
import pandas as pd
import numpy as np
datain = np.loadtxt(datafile)
df = pd.DataFrame(data = datain, columns = ["t","p","x","y","z"])
avg = df.groupby(["t"], sort=False)["p"].mean().rename(columns={1:"mean"})
```

This doesn't work, it tells me `TypeError: rename() got an unexpected keyword argument "columns".` It also doesn't work if I do this,

```python
avg.rename(columns = {1:"mean"}, inplace=True)
```

I cannot figure out why, all documentation tells me that my columns call is correct. I just want to rename the blank column created by my "mean" call to have a string index. All examples I've seen follow this format.

Please write a function `renameDataFrame` in Python, which takes a Pandas DataFrame variable `df` as the argument, which contains the columns as the above example and returns the `df` with the "p" column renamed as "mean" and get the average numbers group by "t" column.

Function signature is: `renameDataFrame(df)`
I am working on a simple code able to evaluate the end time of a period of time, given as a number of minutes (it could be arbitrarily large). The start time is given as a pair of hours (0..23) and minutes (0..59). The result has to be printed to the console.

For example, if an event starts at 12:17 and lasts 59 minutes, it will end at 13:16.

So far I tried below code and finding difficult to get hours calculation please help.

```python
hour = int(input("Starting time (hours): "))
mins = int(input("Starting time (minutes): "))
dura = int(input("Event duration (minutes): "))
mins = (mins + dura)%60
hour = **** Please help this calculation ****
print(hour, ":", mins, sep='')
#expected output is 13:16 (ex: given hour = 12 , mins = 17 , dura = 59 )
```

Please write a function `computeEndTime` in Python, which takes three arguments: `hour`, `mins`, `dura`, and returns the end time in string with the format "xx:xx".

Function signature is: `computeEndTime(hour, mins, dura)`
I am importing string and trying to check if text contains only "a-z", "A-Z", and "0-9".

But I get only input and it doesn't print success when I enter letters and digits

```python
import string
text=input("Enter: ")
correct = string.ascii_letters + string.digits
if text in correct:
    print("Success")
```

Please write a function `checkString` in Python, which takes a string `text` as the argument and returns whether the string satisfies the above requirement in Boolean.

Function signature is: `checkString(text)`
I was expecting the Python match/case to have equal time access to each case, but seems like I was wrong. Any good explanation why?

Lets use the following example:

```python
def match_case(decimal):
    match decimal:
        case '0':
            return "000"
        case '1':
            return "001"
        case '2':
            return "010"
        case '3':
            return "011"
        case '4':
            return "100"
        case '5':
            return "101"
        case '6':
            return "110"
        case '7':
            return "111"
        case _:
            return "NA"
```

And define a quick tool to measure the time:

```python
import time
def measure_time(funcion):
    def measured_function(*args, **kwargs):
        init = time.time()
        c = funcion(*args, **kwargs)
        print(f"Input: {args[1]} Time: {time.time() - init}")
        return c
    return measured_function

@measure_time
def repeat(function, input):
    return [function(input) for i in range(10000000)]
If we run each 10000000 times each case, the times are the following:

for i in range(8):
    repeat(match_case, str(i))

# Input: 0 Time: 2.458001136779785
# Input: 1 Time: 2.36093807220459
# Input: 2 Time: 2.6832823753356934
# Input: 3 Time: 2.9995620250701904
# Input: 4 Time: 3.5054492950439453
# Input: 5 Time: 3.815168857574463
# Input: 6 Time: 4.164452791213989
# Input: 7 Time: 4.857251167297363
```

Just wondering why the access times are different. Isn't this optimised with perhaps a lookup table?. Note that I'm not interested in other ways of having equals access times (i.e. with dictionaries).
I have a DataFrame like this:

```python
import pandas as pd

df=pd.DataFrame()
df['exchange'] = [1, 1, 1, 2, 3]
df['type'] = ['deposit', 'deposit', 'trade', 'deposit', 'deposit']
df['value'] = [10, 10, '30', '40', '100']
```

which looks like:

```python
    exchange     type       value
 0  1            deposit    10
 1  1            deposit    10
 2  1            trade      30
 3  2            deposit    40
 4  3            deposit    100
```

I want to add the elements in the "value" column where "type"='deposit' based on the "exchange" and forward-fill to get something like this:

```python
    exchange     type       value   balance
 0  1            deposit    10      10
 1  1            deposit    10      20
 2  1            trade      30      20
 3  2            deposit    40      40
 4  3            deposit    100     100
```

where "balance" is the sum of deposits filtered by "exchange".

Is there a way to do this pythonically without for loops/if statements?

Please write a function `aggregation` in Python, which takes a DataFrame variable `df` with the above columns as arguments and returns `df` after achieving the above requirement.

Function signature is: `aggregation(df)`
Suppose I have a class that implements method chaining:

```python
from __future__ import annotations

class M:
    def set_width(self, width: int)->M:
        self.width = width
        return self

    def set_height(self, height: int)->M:
        self.height = height
        return self
```

I could use it like this:

```python
box = M().set_width(5).set_height(10)
```

This works, but if I have a subclass M3D:

```python
class M3D(M):
    def set_depth(self, depth: int) -> M3D:
        self.depth = depth
        return self
```

Now I can't do this:

```python
cube = M3D().set_width(2).set_height(3).set_depth(5)
```

I get the following error in mypy:

```bash
_test_typeanotations.py:21: error: "M" has no attribute "set_depth"; maybe "set_width"
```

Because `set_width()` returns an M which has no method set_depth. I have seen suggestions to override `set_width()` and `set_height()` for every subclass to specify the correct types, but that would be a lot of code to write for each method. There has to be a easier way.

Please rewrite the above classes `M` and `M3D` in Python so that `cube = M3D().set_width(2).set_height(3).set_depth(5)` can work.

Please write only the two classes, do not print any other words.
ExcelWriter ValueError: Excel does not support datetime with timezone when saving df to Excel

I'm running on this issue for quite a while now.

I set the writer as follows:

```python
writer = pd.ExcelWriter(arquivo+'.xlsx', engine = 'xlsxwriter', options = {'remove_timezone': True})
df.to_excel(writer, header = True, index = True)
```

The problem is every time I run the code, it gets information from the database, which contains two columns datetime64[ns, UTC] object with time zone info. But when the code to save to Excel runs I receive:

```bash
ValueError: Excel does not support datetimes with timezones. Please ensure that datetimes are timezone unaware before writing to Excel.
```

I have already tried several things like `dt.tz_convert, `replace(tzinfo=None)` and other solutions I have found here and around.

The code runs without problem in my personal computer, my colleague at work with the same machine specs can run the code. Only in my machine it doesn't. I already reinstalled python and all the packages, including formatting the machine and nothing, the error persists.

xlrd v1.1.0

xlsxwriter v1.0.4

python 3.7.4

pandas v0.25.1

Please write a function `removeTimezone` in Python, which takes a DataFrame variable `df` as the argument and returns `df` with the column "time" removed timezones.

Function signature is: `removeTimezone(df)`
I'm trying to run a Profile Report for EDA in conda Jupyter NB, but keep getting errors.
Here is my code thus far:

```python
    import pandas_profiling
    from pandas_profiling import ProfileReport

    profile = ProfileReport(data)
```

and

```python
    profile = pandas_profiling.ProfileReport(data)
```

both of which produce:

```bash
TypeError: concat() got an unexpected keyword argument 'join_axes'
```

Research recommended upgrading to Pandas 1.0, which I'm using.

Also tried

```python
    data.profile_report()
```

and I get

```bash
AttributeError: 'DataFrame' object has no attribute 'profile_report'
```

Any tips on where I am going wrong?

How to solve this problem?
I have a tensor `inps`, which has a size of [64, 161, 1] and I have some new data `d` which has a size of [64, 161]. How can I add `d` to `inps` such that the new size is [64, 161, 2]?

Please write a function `addTensor` in Python, which takes two pytorch tensors `inps` and `d` as arguments, which are defined above, and returns the pytorch tensor I needed.

Function signature is: `addTensor(inps, d)`
How to remove special characters from rows in pandas dataframe

I have a column in pandas data frame like the one shown below;

```
LGA

Alpine (S)
Ararat (RC)
Ballarat (C)
Banyule (C)
Bass Coast (S)
Baw Baw (S)
Bayside (C)
Benalla (RC)
Boroondara (C)
```

What I want to do, is to remove all the special characters from the ending of each row. ie. (S), (RC).

Desired output should be;

```
LGA

Alpine
Ararat
Ballarat
Banyule
Bass Coast
Baw Baw
Bayside
Benalla
Boroondara
```

I am not quite sure how to get desired output mentioned above.

Please write a function `remove` in Python, which takes DataFrame variable `df` as the argument, which is defined as above (the column name is "LGA"), and returns `df` according to my requirement.

Function signature is: `remove(df)`
Unable to start Jupyter notebook on VS Code

(Using latest miniconda + VS Code on 64-bit Windows10:) After clean reinstalling VS Code, I can no longer launch jupyter notebook from within it. When I tried to create a new jupyter file for the first time, the Python extension installed ipykernel in my virtual environment "da38" (my main working environment).
Then it stays on Connecting to IPython kernel: Connecting to kernel for an unusually long time, and stops with the error message

```
Unable to start session for kernel Python 3.8.5 64-bit ('da38':conda).
```

I also removed and re-created da38 environment just in case. Used jupyter many times before with no issues until this new VS Code install today, and an identical setup is working on my other computer. 

How to solve my problem?
Please write a function `func` in Python to compute the number of ways to form a string of length n using k characters such that at most two adjacent characters can be same.

The function `func` takes two arguments `n` and `k`, and returns the number.

Function signature is: `func(n, k)`
How do you check if a package is at its latest version programmatically in a script and return a true or false?

I can check with a script like this:

```python
package='gekko'
import pip
if hasattr(pip, 'main'):
    from pip import main as pipmain
else:
    from pip._internal import main as pipmain
pipmain(['search','gekko'])
```

But how do I check programmatically and return true or false?

Please write a function `checkVersion` in Python, which takes the package name `pkgName` as the argument and returns in boolean.

Function signature is: `checkVersion(pkgName)`
My Goal

I have a specific set of a long list containing many asset pairs with different endings: `BTCUSDT` `ETHBTC` `ANKRETH`... From this list, I would like to filter out the symbols ending with USDT.

Here are my attempts:

```python
my_set = ['LUNAUSDT', 'ETHBTC', 'ETHBNB', 'BTCUSDT', 'MANATUSD', 'ALICEETH' ]
my_set = [word for word in symbols if 'USDT' in my_set]
my_set
```

But this results in an empty set.

How to revise my code? please only generate the revised codes, without any extra comments.
I'm trying to create a function that turns text into pig Latin: simple text transformation that modifies each word moving the first character to the end and appending "ay" to the end. But all I get is an empty list.

My python code:

```python
def pig_latin(text):
  say = ""
  words = text.split()
  for word in words:
    endString = str(word[1]).upper()+str(word[2:])
    them = endString, str(word[0:1]).lower(), 'ay'
    word = ''.join(them)
    return word

print(pig_latin("hello how are you")) # Should be "ellohay owhay reaay ouyay"
print(pig_latin("programming in python is fun")) # Should be "rogrammingpay niay ythonpay siay unfay"
```

Please generate the function pig_latin in Python by revising my code. You need only generate the function, without any comments or testing codes.
I have a string like below in python

```
testing_abc
```

I want to split string based on _ and extract the second element

I have done like below

```python
split_string = string.split('_')[1]
```

I am getting the correct output as expected

```
abc
```

Now I want this to work for below strings

```
xyz
```

When I use

```python
split_string = string.split('_')[1]
```

I get below error

```
list index out of range
```

expected output I want is xyz

For the below string

```
testing_abc_bbc
```

When I use

```python
split_string = string.split('_')[1]
```

I get `abc` as output

expected output I want is `abc_bbc`

Basically What I want is

1) If string contains `_` then print everything after the first `_` as variable
2) If string doesn't contain `_` then print the string as variable

Please write a function `splitOne` with a string `s` as the argument and returns the string I need.

The signature of the function is `splitOne(s)`
I am using this function to uncompress the body of a HTTP response if it is compressed with gzip, compress or deflate.

```python
def uncompress_body(self, compression_type, body):
    if compression_type == 'gzip' or compression_type == 'compress':
        return zlib.decompress(body)
    elif compression_type == 'deflate':
        compressor = zlib.compressobj(9, zlib.DEFLATED, -zlib.MAX_WBITS)
        compressed = compressor.compress(body)
        compressed += compressor.flush()
        return base64.b64encode(compressed)

    return body
```

However python throws this error message.

```bash
TypeError: a bytes-like object is required, not '_io.BytesIO'
```

on this line:

```python
return zlib.decompress(body)
```

Essentially, how do I convert from `_io.BytesIO` to a bytes-like object?
I'm currently working with the PyTorch framework and trying to understand foreign code. I got an indices issue and wanted to print the shape of a list.
The only way of doing so (as far as Google tells me) is to convert the list into a numpy array and then getting the shape with numpy.ndarray.shape().

But trying to convert my list into an array, I got a ValueError: only one element tensors can be converted to Python scalars.

My List is a converted PyTorch Tensor (list(pytorchTensor)) and looks somewhat like this:

[
tensor([[-0.2781, -0.2567, -0.2353,  ..., -0.9640, -0.9855, -1.0069],  
        [-0.2781, -0.2567, -0.2353,  ..., -1.0069, -1.0283, -1.0927],  
        [-0.2567, -0.2567, -0.2138,  ..., -1.0712, -1.1141, -1.1784],  
        ...,  
        [-0.6640, -0.6425, -0.6211,  ..., -1.0712, -1.1141, -1.0927],  
        [-0.6640, -0.6425, -0.5997,  ..., -0.9426, -0.9640, -0.9640],  
        [-0.6640, -0.6425, -0.5997,  ..., -0.9640, -0.9426, -0.9426]]),

tensor([[-0.0769, -0.0980, -0.0769,  ..., -0.9388, -0.9598, -0.9808],  
        [-0.0559, -0.0769, -0.0980,  ..., -0.9598, -1.0018, -1.0228],    
        [-0.0559, -0.0769, -0.0769,  ..., -1.0228, -1.0439, -1.0859],  
        ...,  
        [-0.4973, -0.4973, -0.4973,  ..., -1.0018, -1.0439, -1.0228],  
        [-0.4973, -0.4973, -0.4973,  ..., -0.8757, -0.9177, -0.9177],  
        [-0.4973, -0.4973, -0.4973,  ..., -0.9177, -0.8967, -0.8967]]),

tensor([[-0.1313, -0.1313, -0.1100,  ..., -0.8115, -0.8328, -0.8753],  
        [-0.1313, -0.1525, -0.1313,  ..., -0.8541, -0.8966, -0.9391],  
        [-0.1100, -0.1313, -0.1100,  ..., -0.9391, -0.9816, -1.0666],  
        ...,  
        [-0.4502, -0.4714, -0.4502,  ..., -0.8966, -0.8966, -0.8966],  
        [-0.4502, -0.4714, -0.4502,  ..., -0.8115, -0.8115, -0.7903],  
        [-0.4502, -0.4714, -0.4502,  ..., -0.8115, -0.7690, -0.7690]]),
] 

Please write a function `getSize` that takes list(pytorchTensor) variable `t` as argument (which is shown above) and return the size of each tensor in List.

The signature of the function is `getSize(t)`
I have a dataframe with a column named "year" in object format. I want to convert object to int but I have this error :

```bash
ValueError: invalid literal for int() with base 10: '2021.0'
```

Here is my code : 

```python
data_h_df['year'].astype(str).astype(int)
```

Please write a function `transformation` in Python which takes `data_h_df` as argument and returns `data_h_df` with the "year" column transformed.

The signature of the function is transformation(data_h_df)
I have set my linter for Python to Pylint, but I still get error messages from Jedi.
I even went to settings.json and added the line `"python.linting.jediEnabled": false`, but the line, though present, is greyed out. What more can I do?
How can I install a previous version of Python 3 in macOS using brew?
With the command brew install python I got the latest version of Python 3 (currently v3.7.0), but I want the version of Python 3.6.5.
I have read about another package pyenv that can assist in handle different python installation, but this solution is not suitable for me.

Please write a bash script for me to use `brew` to achieve my requirement, without any extra comments.
I have two data frames df1 and df2, where df2 is a subset of df1. How do I get a new data frame (df3) which is the difference between the two data frames?

In other word, a data frame that has all the rows/columns in df1 that are not in df2?

Please write a function `getDifference` in Python, which takes `df1` and `df2` as arguments and returns their differences in DataFrame.

Function signature is: `getDifference(df1, df2)`
I have a list:

```python
roll = [1, 2, 3]
```

For converting each of the element into a string, can we directly do `roll = str(roll)`` rather that iterating over it and calling `str()` on each element? Is this a correct way?

Please output "yes" or "no" in the first line without any extra comment. If no, please show the right code in the second line with out any comment.
I know its possible to print RGB colored text like so:

```python
def colored(r, g, b, text):
    return "\033[38;2;{};{};{}m{} \033[39m".format(r, g, b, text)


text = "Hello, World"
colored_text = colored(132, 204, 247, text)
print(colored_text)
```

But, is there a way to print with RGB colored background?

Cuz, as far as I know, there are a few kinda built-in background colors for printing. But I want to be able to use rgb codes and get the appropriate background color for the printed text.

Please modify the above function to achieve my requirements.
The function signature is `def colored(background_r, background_g, background_b, text):`
You need only output the function without any extra comments.
ModuleNotFoundError: No module named 'app' fastapi docker

```Dockerfile
FROM python:3.8
WORKDIR /app

COPY requirements.txt /
RUN pip install --requirement /requirements.txt

COPY ./app /app

EXPOSE 8000
CMD ["uvicorn", "app.main:app", "--host=0.0.0.0" , "--reload" , "--port", "8000"]
```

when i used

```bash
docker-compose up -d
ModuleNotFoundError: No module named 'app'
```

the folders in Fastapi framework:

fastapi

    app

      -main.py

      `language_detector.py`
      
Dockerfile

docker-compose

How to revise my Dockerfile?
I am a beginner in learning code and am working on making a simple django site where users can write comments but I keep getting this error

My urls.py

```python
from django.urls import path

from . import views

urlpatterns = [
    path("", views.index, name="index"),
    path("login", views.login_view, name="login"),
    path("logout", views.logout_view, name="logout"),
    path("register", views.register, name="register"),
    path("profile/<str:name>/", views.profile, name="profile")
]
```

views.py

```python
class NewPostForm(forms.Form):
    title = forms.CharField(label="Title")
    description = forms.CharField(widget=forms.Textarea)

def index(request):
    if request.method == "POST":
        form = NewPostForm(request.POST)
        if form.is_valid():
            title = form.cleaned_data['title']
            description = form.cleaned_data['description']
            author = request.user

            post = NewPost(title=title, description=description, author=author)
            post.save()
            return HttpResponseRedirect(reverse("index"))
        else:
            return render(request, "network/index.html", {
                "form": form
            })

    return render(request, "network/index.html", {
        "form": NewPostForm(),
        "posts": NewPost.objects.all()
    })
```

models.py

```python
from django.contrib.auth.models import AbstractUser
from django.db import models


class User(AbstractUser):
    pass

class NewPost(models.Model):
    title = models.CharField(max_length=32)
    description = models.CharField(max_length=256)
    author = models.ForeignKey(User, on_delete=models.CASCADE, null=True)
```

and my index.html

```html
{% extends "network/layout.html" %}

{% load static %}
{% load crispy_forms_tags %}

{% block body %}
    <div class="form-group">
        <form method="post" action="{% url 'index' %}">
            {% csrf_token %}
            {{form | crispy}}
            <button class="btn btn-primary"> Post </button>
        </form>
    </div>

    {% for post in posts %}
        <div class="card">
            <div class="card-body"> Title: {{post.title}} </div>
            <div class="card-body"> Description: {{post.description}}</div>
            <p> {{post.author.username}} </p>
            <div class="card-body">
                <a href="{% url 'profile' post.author.username %}">
                    @{{post.author.username}}
                </a>
            </div>
        </div>
    {% endfor %}
{% endblock %}
```

But I keep getting

```
NoReverseMatch at / Reverse for 'profile' with arguments '('',)' not found. 1 pattern(s) tried: ['profile/(?P[^/]+)/$']
```

Please point and show (in MarkDown) which line in my codes is wrong.
I would like to generate a 16 character code that consists of letters ('a-z' and 'A-Z') and digits.

The code must has a sub-string "NAA3U". The code must has exact 3 digits. And the code must be random.

Please write a function `generateRandomString` in Python, which takes no argument and returns a string according to my requirements after each call.

Function signature is: `generateRandomString()`
I have a DataFrame with columns A, B, and C. For each value of A, I would like to select the row with the minimum value in column B.

That is, from this:

```python
df = pd.DataFrame({'A': [1, 1, 1, 2, 2, 2],
                   'B': [4, 5, 2, 7, 4, 6],
                   'C': [3, 4, 10, 2, 4, 6]})
    A   B   C
0   1   4   3
1   1   5   4
2   1   2   10
3   2   7   2
4   2   4   4
5   2   6   6
```

I would like to get:

```
    A   B   C
0   1   2   10
1   2   4   4
```

Please write a function `getMin` in Python, which takes DataFrame variable `df` as the argument (the columns are the same as the above example) and returns a dataframe according to my requirements.

Function signature is: `getMin(df)`
Dividing an even number into N parts each part being a multiple of 2

Let's assume I have the number 100 which I need to divide into N parts each of which shouldn't exceed 30 initially. So the initial grouping would be (30,30,30). The remainder (which is 10) is to be distributed among these three groups by adding 2 to each group in succession, thus ensuring that each group is a multiple of 2. The desired output should therefore look like (34,34,32).

Note: The original number is always even.

I tried solving this in Python and this is what I came up with. Clearly it's not working in the way I thought it would. It distributes the remainder by adding 1 (and not 2, as desired) iteratively to each group.

```python
num = 100
parts = num//30  #Number of parts into which 'num' is to be divided

def split(a, b):
  result = ([a//b + 1] * (a%b) + [a//b] * (b - a%b))
  return(result)

print(split(num, parts))
```

Output:

```
[34, 33, 33]
```

Desired output:

```
[34, 34, 32]
```

Please write a function `divideNumber` in Python, which takes `num` and `n` as arguments and returns the dividing results (divide `num` into `n` parts) in List according to my above requirements.

Function signature is: `divideNumber(num, n)`
I've been getting this error on several programs for now. I've tried upgrading pytube, reinstalling it, tried some fixes, changed URLs and code, but nothing seems to work.

```python
from pytube import YouTube

#ask for the link from user
link = input("Enter the link of YouTube video you want to download:  ")
yt = YouTube(link)

#Showing details
print("Title: ",yt.title)
print("Number of views: ",yt.views)
print("Length of video: ",yt.length)
print("Rating of video: ",yt.rating)
#Getting the highest resolution possible
ys = yt.streams.get_highest_resolution()

#Starting download
print("Downloading...")
ys.download()
print("Download completed!!")
```

and this is the error code:

```bash
  File "C:\Users\Madjid\PycharmProjects\pythonProject\app2.py", line 6, in <module>
    yt = YouTube(link)
  File "C:\Users\Madjid\PycharmProjects\pythonProject\venv\lib\site-packages\pytube\__main__.py", line 91, in __init__
    self.prefetch()
  File "C:\Users\Madjid\PycharmProjects\pythonProject\venv\lib\site-packages\pytube\__main__.py", line 181, in prefetch
    self.vid_info_raw = request.get(self.vid_info_url)
  File "C:\Users\Madjid\PycharmProjects\pythonProject\venv\lib\site-packages\pytube\request.py", line 36, in get
    return _execute_request(url).read().decode("utf-8")
  File "C:\Users\Madjid\PycharmProjects\pythonProject\venv\lib\site-packages\pytube\request.py", line 24, in _execute_request
    return urlopen(request)  # nosec
  File "E:\Python\lib\urllib\request.py", line 214, in urlopen
    return opener.open(url, data, timeout)
  File "E:\Python\lib\urllib\request.py", line 523, in open
    response = meth(req, response)
  File "E:\Python\lib\urllib\request.py", line 632, in http_response
    response = self.parent.error(
  File "E:\Python\lib\urllib\request.py", line 555, in error
    result = self._call_chain(*args)
  File "E:\Python\lib\urllib\request.py", line 494, in _call_chain
    result = func(*args)
  File "E:\Python\lib\urllib\request.py", line 747, in http_error_302
    return self.parent.open(new, timeout=req.timeout)
  File "E:\Python\lib\urllib\request.py", line 523, in open
    response = meth(req, response)
  File "E:\Python\lib\urllib\request.py", line 632, in http_response
    response = self.parent.error(
  File "E:\Python\lib\urllib\request.py", line 561, in error
    return self._call_chain(*args)
  File "E:\Python\lib\urllib\request.py", line 494, in _call_chain
    result = func(*args)
  File "E:\Python\lib\urllib\request.py", line 641, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 410: Gone
```

How to solve the problem?
I am reading through a python script that takes an input of XML files and outputs an XML file. However, I do not understand the printing syntax. Can someone please explain what "f" in `print(f"...")`` does?

```python
args = parser.parser_args()

print(f"Input directory: {args.input_directory}")
print(f"Output directory: {args.output_directory}")
```
I have the following data frame:

```r
X1   X2   X3   X4   X5   X6   X7
p1   H    I    K    J    K    H
p2   H    K    J    K    I    J
p3   J    K    H    I    J    K
p4   K    I    H    J    I    J
```

I want to create a new data frame with the column `X1` and concatenate every two columns starting from `X2` so the final table looks like:

```r
X1   X2    X3    X4
p1   HI    KJ    KH
p2   HK    JK    IJ
p3   JK    HI    JK
p4   KI    HJ    IJ
```

Please write a function `concat` in R, which takes a dataframe `df` (with the columns `X1`, `X2`,.., `X7` as above)as the argument and returns a new dataframe according to the above requirements.

Function signature is: `concat <- function(df)`
How to sort a list alphabetically?

It is necessary to create a list of random letters of the alphabet. And then sort it alphabetically. To create such a list, I use the following code:

```r
# Creating a random vector of letters
random_text_data = sample(letters, 10)
random_text_data

# Convert to list
list_text_data = as.list(random_text_data)
list_text_data
```

In the console I get the following:

```r
> random_text_data
[1] "h" "m" "q" "b" "z" "i" "y" "f" "d" "e"
> # Convert to list
> list_text_data = as.list(random_text_data)
> list_text_data
[[1]]
[1] "h"

[[2]]
[1] "m"

[[3]]
[1] "q"

[[4]]
[1] "b"

[[5]]
[1] "z"

[[6]]
[1] "i"

[[7]]
[1] "y"

[[8]]
[1] "f"

[[9]]
[1] "d"

[[10]]
[1] "e"
```

Now I need to sort it alphabetically. I have tried the following:

```r
# Sort list alphabetically
sort_data = sort(list_text_data)
```

But get error:

```
> sort_data = sort(list_text_data)
Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) :
'x' must be elementary
```

How should you sort?

Please write a function `mySort` in R, which takes a list `l` as the argument and returns what I need.

Function signature is: `mySort <- function(l)`
I have a `data.table` called `big` in which I want to replace all corresponding values from `data.table` called `new_big`.

```r
library(data.table)
big <- structure(list(id = c("B", "C", "D", "E", "F", "G", "H", "I",
"J", "K"), col = c(103L, 103L, 102L, 105L, 104L, 103L, 104L, 104L,
104L, 103L)), row.names = c(NA, -10L), class = c("data.table",
"data.frame"))
new_big <- structure(list(id = c("B", "E", "G"), col = c(1, 11, 111)), row.names = c(NA,
-3L), class = c("data.table", "data.frame"))
```

They create:

```r
> big
id col
1:  B 103
2:  C 103
3:  D 102
4:  E 105
5:  F 104
6:  G 103
7:  H 104
8:  I 104
9:  J 104
10:  K 103

> new_big
id col
1:  B   1
2:  E  11
3:  G 111
```

Here is the desired output -

```r
id  col
1:  B 1
2:  C 103
3:  D 102
4:  E 11
5:  F 104
6:  G 111
7:  H 104
8:  I 104
9:  J 104
10:  K 103
```

Is there a way to join these two tables to get the desired output?

Please write a function `myReplace` in R, which takes two tables `big` and `new_big` as arguments, which are shown in above, and returns a table according to the above requirements.

Function signature is: `myReplace <- function(big, new_big)`
remove Rows with complete set of NA

I have a dataset and I would like to delete the rows that have a complete set of NAs in columns 456:555, I want to keep those with some NAs but I need to delete those with a complete set of NAs

I have tried

```r
final[complete.cases(final[ , 456:555]),]
```

but this doesn't work. It says

```r
Error in help.search(c("[", "final", "complete.cases(final[, c(456:555)])",  : argument ‘pattern’ must be a single character string
```

then I think this probably would work:

```r
data[rowSums(is.na(data)) != ncol(data),]
```

but I don't know where to include `456:555` there

Can you write a code in R to help me successfully process the columns `456:555` of `final`? You need to set the new value into `final`.

You only need to write code, without any extra comments.
How do I unpack tuple format in R?

Here is the dataset.

```r
library(data.table)

x <- structure(list(id = c("A", "B" ),
segment_stemming = c("[('Brownie', 'Noun'), ('From', 'Josa'), ('Pi', 'Noun')]",
"[('Dung-caroon-gye', 'Noun'), ('in', 'Josa'), ('innovation', 'Noun')]" )),
row.names = c(NA, -2L),
class = c("data.table", "data.frame" ))

x
# id                                                     segment_stemming
# 1:  A               [('Brownie', 'Noun'), ('From', 'Josa'), ('Pi', 'Noun')]
# 2:  B [('Dung-caroon-gye', 'Noun'), ('in', 'Josa'), ('innovation', 'Noun')]
```

I would like to split the tuple into rows. Here is my expected outcome.

```r
id             segment_stemming
A              ('Brownie', 'Noun')
A              ('From', 'Josa')
A              ('Pi', 'Noun')
B              ('Dung-caroon-gye', 'Noun')
B              ('in', 'Josa')
B              ('innovation', 'Noun')
```

Please write a function `mySplit` in R, which takes a table variable `x` as the argument, which has the same structure as above, and returns the table according to the above requirements.

Function signature is: `mySplit <- function(x)`
Converting grouped tibble to named list

I feel like there is probably a better way to do this in `tidyverse` than a `for-loop`. Start with a standard tibble/dataframe, and make a list where the name of the list elements are the unique values of one column (`group_by?`) and the list elements are all the values of another column.

```r
my_data <- tibble(list_names = c("Ford", "Chevy", "Ford", "Dodge", "Dodge", "Ford"),
list_values = c("Ranger", "Equinox", "F150", "Caravan", "Ram", "Explorer"))

# A tibble: 6 × 2
list_names list_values
<chr>      <chr>      
1 Ford       Ranger     
2 Chevy      Equinox    
3 Ford       F150       
4 Dodge      Caravan    
5 Dodge      Ram        
6 Ford       Explorer
```

This is the desired output:

```r
desired_output <- list(Ford = c("Ranger", "F150", "Explorer"),
Chevy = c("Equinox"),
Dodge = c("Caravan", "Ram"))

$Ford
[1] "Ranger"   "F150"     "Explorer"

$Chevy
[1] "Equinox"

$Dodge
[1] "Caravan" "Ram"
```

Please write a function `myConvert` in R, which takes a tibble variable `my_data` as the argument, whose columns are shown above, and returns the list according to the above requirement.

Function signature is: `myConvert <- function(my_data)`

Attention: You must use the library `tidyverse` and do not use `for-loop`!
How to split a comma and colon separated column into respective columns in R?

Say for example I have a dataframe `df`, who has only one column `col1` that looks something like:

```r
name:Michael,Age:31,City:NYC
name:Tom,Age:25,City:NA
```

How could I split this column into separate columns such that it would yield a result similar as a data frame to:

```r
   name   | Age | City
1 Michael | 31  | NYC
2  Tom    | 25  | NA
```

Please write a function `mySplit` in R, which takes data frame variable `df` as the argument, which is shown above, and returns tables according to my above requirements.

Function signature is: `mySplit <- function(df)`
I have strings like:

```r
string <- "1, 2, \"something, else\""
```

I want to use `tidyr::separate_rows()` with `sep==","`, but the comma inside the quoted portion of the string is tripping me up. I'd like to remove the comma between something and else (but only this comma).

Here's a more complex toy example:

```r
string <- c("1, 2, \"something, else\"", "3, 5, \"more, more, more\"", "6, \"commas, are fun\", \"no, they are not\"")

string
#[1] "1, 2, \"something, else\""
#[2] "3, 5, \"more, more, more\""
#[3] "6, \"commas, are fun\", \"no, they are not\""
```

I want to get rid of all commas inside the embedded quotations. Desired output:

```r
[1] "1, 2, \"something else\""                  
[2] "3, 5, \"more more more\""                  
[3] "6, \"commas are fun\", \"no they are not\""
```

Please write a function `removeComma` in R, which takes a string variable `s` as arguments and returns what I need.

Function signature is: `removeComma <- function(s)`
data.frame with 2 columns with the same name: how to select the second one?

```r
d1 <- data.frame(a=c(1,2,3))
d2 <- data.frame(a=c(3,4,5))
d3 <- cbind(d1,d2)
```

doesn't return an error, and an inspection of the environment in RStudio displays two columns with the same name.

If I type:

```r
d3$a
```

The first column is selected. How to select the second by name?

Suppose you have get the above variable, please just write codes in R to select the second by name of my frame, and assign the value to a variable named `second_col`.
I am using java 8
I have a model class like:
```java
class Subject{
    String sub;
    Integer marks;
    boolean status;
    // getters & setters
}
```
status may be true or false.
Now if the status is false then I have to remove those objects from a subjects list.
How to do it?

Please write a function `removeFalseSubjects` in Java, which remove the objects from a subjects list if their status is false.
The context of the function is:
```java
package main;

import java.util.ArrayList;
import java.util.List;

public class Main {
    private static class Subject{
        String sub;
        Integer marks;
        boolean status;
        // getters & setters
    }
    public static void removeFalseSubjects(List<Subject> subjects){
        //You should implement here
    }
}
```
Please give me the whole function with body without context such as class definition or imports.
Function signature is: `public static void removeFalseSubjects(List<Subject> subjects)`
When should you use @Configuration instead of @Service/@Controller/@Component for defining beans in the Spring Framework?
Please write a function `createPriorityQueue` in Java, which creates a priority queue of integer pairs. The smallest key of pairs is considered as priority.
The context of the function is:
```java
import javafx.util.Pair;
import java.util.*;

public class Test
{
    public static PriorityQueue<Pair<Integer, Integer>> createPriorityQueue()
    {
        //You should implement here
    }
}
```
Please give me the whole function with body without context such as class definition or imports.
Function signature is: `public static PriorityQueue<Pair<Integer, Integer>> createPriorityQueue()`