user: ### NOW ANSWER:
Question: With a 1986 of NH and a career SR of 0 / 5 what is the results in 1985?
Columns: ['Tournament', '1983', '1984', '1985', '1986', '1987', '1988', '1989', '1990', 'Career SR', 'Career Win-Loss']
Types: ['text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['Australian Open', '1R', '2R', 'A', 'NH', 'QF', 'A', 'F', '4R', '0 / 5', '12–5']
SQL:

assistant: SELECT "1985" FROM "Table" WHERE "Career SR" = '0 / 5' AND "1986" = 'NH';