user: ### NOW ANSWER:
Question: What was the average value in 2005 when 2008 is 61837716, and a 2006 is more than 57126389?
Columns: ['Years', '2004', '2005', '2006', '2007', '2008', '2009', '2010', '2011']
Types: ['text', 'real', 'real', 'real', 'real', 'real', 'real', 'real', 'real']
Sample row: ['Total traffic *', 50914096.0, 60631737.0, 57126389.0, 57779915.0, 61837716.0, 42014178.0, 47563879.0, 45972095.0]
SQL:

assistant: SELECT AVG("2005") FROM "Table" WHERE "2008" = 61837716.0 AND "2006" > 57126389.0;