user: ### NOW ANSWER:
Question: what is 1980 when 1978 is 2.3?
Columns: ['1976', '1977', '1978', '1979', '1980']
Types: ['text', 'text', 'text', 'text', 'text']
Sample row: ['Chile', 'Chile', 'Chile', 'Chile', 'Chile']
SQL:

assistant: SELECT "1980" FROM "Table" WHERE "1978" = '2.3';