user: ### NOW ANSWER:
Question: What 2011 has 12.7% as the 2010?
Columns: ['Score', '2007', '2008', '2009', '2010', '2011', '2012']
Types: ['text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['5', '15.3%', '18.4%', '18.0%', '17.1%', '17.0%', '16.4%']
SQL:

assistant: SELECT "2011" FROM "Table" WHERE "2010" = '12.7%';