user: ### NOW ANSWER:
Question: Name the average 2008 for beijing and 2005 more than 2
Columns: ['Year', '2010', '2009', '2008', '2005', '2000']
Types: ['text', 'real', 'real', 'real', 'real', 'real']
Sample row: ['Shanghai', 1.0, 2.0, 1.0, 1.0, 1.0]
SQL:

assistant: SELECT AVG("2008") FROM "Table" WHERE "Year" = 'beijing' AND "2005" > 2.0;