user: ### NOW ANSWER:
Question: Tell me the average year for rank more than 3 and 28 floors
Columns: ['Rank', 'Name', 'Height m ( ft )', 'Floors', 'Year']
Types: ['real', 'text', 'text', 'real', 'real']
Sample row: [1.0, 'Édifice Marie-Guyart', 'm (ft)', 33.0, 1972.0]
SQL:

assistant: SELECT AVG("Year") FROM "Table" WHERE "Rank" > 3.0 AND "Floors" = 28.0;