user: ### NOW ANSWER:
Question: Which 1988 has a 1985 of 2R?
Columns: ['Tournament', '1981', '1982', '1983', '1984', '1985', '1986', '1987', '1988', '1989']
Types: ['text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['Australian Open', '3R', 'A', '3R', 'A', '3R', 'NH', '4R', 'A', 'A']
SQL:

assistant: SELECT "1988" FROM "Table" WHERE "1985" = '2R';