user: ### NOW ANSWER:
Question: What is the average year with a 1:42.85 time?
Columns: ['Year', 'Winner', 'Jockey', 'Trainer', 'Owner', 'Distance', 'Time', 'Purse']
Types: ['real', 'text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: [2013.0, 'Summer Applause', 'John Velazquez', 'Chad Brown', 'Greenwood Lodge Farm', '1-1/16', '1:46.54', '$150,000']
SQL:

assistant: SELECT AVG("Year") FROM "Table" WHERE "Time" = '1:42.85';