user: ### NOW ANSWER:
Question: What is the 2012 value with 479 in 2008?
Columns: ['Tournament', '2006', '2007', '2008', '2009', '2010', '2011', '2012']
Types: ['text', 'text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['Australian Open', 'A', '1R', 'A', 'A', '2R', '1R', 'Q1']
SQL:

assistant: SELECT "2012" FROM "Table" WHERE "2008" = '479';