user: ### NOW ANSWER:
Question: What is the 2006 value with 3R in 2007?
Columns: ['Tournament', '2006', '2007', '2008', '2009', '2010', '2011', '2012']
Types: ['text', 'text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['Australian Open', 'A', '1R', 'A', 'A', '2R', '1R', 'Q1']
SQL:

assistant: SELECT "2006" FROM "Table" WHERE "2007" = '3R';