user: ### NOW ANSWER:
Question: What shows for 2013 when 2012 is 2R?
Columns: ['Tournament', '2008', '2010', '2011', '2012', '2013']
Types: ['text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['Australian Open', 'A', '1R', '1R', 'Q1', '2R']
SQL:

assistant: SELECT "2013" FROM "Table" WHERE "2012" = '2R';