user: ### NOW ANSWER:
Question: What is the 2009 average when the 2007 average is more than 018?
Columns: ['Country', 'Unit p koe/$05', '2006', '2007', '2008', '2009']
Types: ['text', 'text', 'real', 'real', 'real', 'real']
Sample row: ['World', 'koe/$05p', 2.0, 2.0, 19.0, 19.0]
SQL:

assistant: SELECT AVG("2009") FROM "Table" WHERE "2007" > 18.0;