user: ### NOW ANSWER:
Question: What is the result for 1989 that has a 1992 result of 0 / 1?
Columns: ['Tournament', '1987', '1988', '1989', '1990', '1991', '1992', '1993', '1994', 'Career SR']
Types: ['text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text', 'text']
Sample row: ['Australian Open', 'A', '2R', '2R', '3R', '1R', 'A', '2R', '1R', '0 / 6']
SQL:

assistant: SELECT "1989" FROM "Table" WHERE "1992" = '0 / 1';