user: Question: Name the year with percentage of 9.66%
Columns: ['Year', 'Office', 'Candidate', 'Popular Votes', 'Percentage']
Types: ['real', 'text', 'text', 'real', 'text']
Sample row: [1986.0, 'MN Attorney General', 'Derrick Grimmer', 16394.0, '1.17%']
SQL:

assistant: SELECT "Year" FROM "Table" WHERE "Percentage" = '9.66%';