Problem:


Score : 100 points

Problem Statement

Taro and Jiro will play the following game against each other.

Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N).
Until a becomes empty, the two players perform the following operation alternately, starting from Taro:

Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.

Let X and Y be Taro's and Jiro's total score at the end of the game, respectively.
Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.

Assuming that the two players play optimally, find the resulting value of X - Y.

Constraints

All values in input are integers.

1 \leq N \leq 3000

1 \leq a_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 \ldots a_N

Output

Print the resulting value of X - Y, assuming that the two players play optimally.

Sample Input 1

4
10 80 90 30

Sample Output 1

10

The game proceeds as follows when the two players play optimally (the element being removed is written bold):

Taro: (10, 80, 90, 30) → (10, 80, 90)

Jiro: (10, 80, 90) → (10, 80)

Taro: (10, 80) → (10)

Jiro: (10) → ()

Here, X = 30 + 80 = 110 and Y = 90 + 10 = 100.

Sample Input 2

3
10 100 10

Sample Output 2

-80

The game proceeds, for example, as follows when the two players play optimally:

Taro: (10, 100, 10) → (100, 10)

Jiro: (100, 10) → (10)

Taro: (10) → ()

Here, X = 10 + 10 = 20 and Y = 100.

Sample Input 3

1
10

Sample Output 3

10

Sample Input 4

10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1

Sample Output 4

4999999995

The answer may not fit into a 32-bit integer type.

Sample Input 5

6
4 2 9 7 1 5

Sample Output 5

2

The game proceeds, for example, as follows when the two players play optimally:

Taro: (4, 2, 9, 7, 1, 5) → (4, 2, 9, 7, 1)

Jiro: (4, 2, 9, 7, 1) → (2, 9, 7, 1)

Taro: (2, 9, 7, 1) → (2, 9, 7)

Jiro: (2, 9, 7) → (2, 9)

Taro: (2, 9) → (2)

Jiro: (2) → ()

Here, X = 5 + 1 + 9 = 15 and Y = 4 + 7 + 2 = 13.



Sample input:
4
10 80 90 30


Sample output:
10

Submission status: Time Limit Exceeded

Solution code:
# coding: utf-8
from functools import lru_cache
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**6)

@lru_cache(maxsize = None)
def f2(i, j):
    if i == j:
        return(a[i])
    r = a[i] - f2(i + 1, j)
    l = a[j] - f2(i, j - 1)
    return(r if r > l else l)

n = int(input()) # 1 <= n <= 3000
a = list(map(int, input().split()))
print(f2(0, n - 1))

Submission status: Time Limit Exceeded

Solution code:
# coding: utf-8
from functools import lru_cache

import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**6)

@lru_cache(maxsize = None)
def f2(i, j):
    if i == j:
        return(a[i])
    return(max(a[i] - f2(i + 1, j), a[j] - f2(i, j - 1)))

n = int(input()) # 1 <= n <= 3000
a = list(map(int, input().split()))
print(f2(0, n - 1))

Submission status: Time Limit Exceeded

Solution code:
# coding: utf-8

import sys
input = sys.stdin.readline

def f(n, a):
    dp = [[0] * n for _ in range(n)]
    # dp[i][i] を a[i] で初期化
    for i in range(n):
        dp[i][i] = a[i]
    for i in range(n - 2, -1, -1):
        for j in range(i + 1, n):
            dp[i][j] = max(a[i] - dp[i + 1][j], a[j] - dp[i][j - 1])
    return(dp[0][-1])

n = int(input()) # 1 <= n <= 3000
a = list(map(int, input().split()))
print(f(n, a))

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    n = I()
    a = LI()
    ma = n*(n+1)//2
    su = sum(a)
    s = [1 for i in range(n+1)]
    for i in range(1,n):
        s[i+1] = s[i]+n-i+1
    d = [None for i in range(ma+1)]
    d[0] = 0
    k = 1
    for i in range(1,n+1):
        for j in range(n+1-i):
            d[k+j] = i
        k += n+1-i
    k = n%2
    dp = [su if (d[i]+k)%2 else -su for i in range(ma+1)]
    dp[0] = 0
    if k:
        for i in range(n):
            dp[i+1] = a[n-1-i]
    else:
        for i in range(n):
            dp[i+1] = -a[n-1-i]
    for i in range(1,ma):
        r = n-1-(i-s[d[i]])
        l = r+1-d[i]
        j = i+(n-d[i])
        j2 = j+1
        if (d[i]+k)%2:
            if r < n-1:
                if a[r+1]+dp[i] > dp[j]:
                    dp[j] = a[r+1]+dp[i]
            if l > 0:
                if a[l-1]+dp[i] > dp[j2]:
                    dp[j2] = a[l-1]+dp[i]
        else:
            if r < n-1:
                if -a[r+1]+dp[i] < dp[j]:
                    dp[j] = -a[r+1]+dp[i]
            if l > 0:
                if -a[l-1]+dp[i] < dp[j2]:
                    dp[j2] = -a[l-1]+dp[i]
    print(dp[ma])
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [1 for i in range(n+1)]
    for i in range(1,n):
        s[i+1] = s[i]+n-i+1
    d = [None for i in range(ma+1)]
    d[0] = 0
    k = 1
    for i in range(1,n+1):
        for j in range(n+1-i):
            d[k+j] = i
        k += n+1-i
    k = n%2
    dp = [0.0 for i in range(ma+1)]
    dp[0] = 0
    for i in range(n+1,ma+1):
        if (d[i]+k)%2:
            dp[i] = float("inf")
        else:
            dp[i] = -float("inf")
    if k:
        for i in range(n):
            dp[i+1] = a[n-1-i]
    else:
        for i in range(n):
            dp[i+1] = -a[n-1-i]
    for i in range(1,ma):
        r = n-1-(i-s[d[i]])
        l = r+1-d[i]
        j = i+(n-d[i])
        j2 = j+1
        if (d[i]+k)%2:
            if r < n-1:
                if a[r+1]+dp[i] > dp[j]:
                    dp[j] = a[r+1]+dp[i]
            if l > 0:
                if a[l-1]+dp[i] > dp[j2]:
                    dp[j2] = a[l-1]+dp[i]
        else:
            if r < n-1:
                if -a[r+1]+dp[i] < dp[j]:
                    dp[j] = -a[r+1]+dp[i]
            if l > 0:
                if -a[l-1]+dp[i] < dp[j2]:
                    dp[j2] = -a[l-1]+dp[i]
    print(dp[ma])
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [1 for i in range(n+1)]
    for i in range(1,n):
        s[i+1] = s[i]+n-i+1
    d = [None for i in range(ma+1)]
    d[0] = 0
    k = 1
    for i in range(1,n+1):
        for j in range(n+1-i):
            d[k+j] = i
        k += n+1-i
    k = n%2
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    for i in range(n+1,ma+1):
        if (d[i]+k)%2:
            dp[i] = float("inf")
        else:
            dp[i] = -float("inf")
    if k:
        for i in range(n):
            dp[i+1] = a[n-1-i]
    else:
        for i in range(n):
            dp[i+1] = -a[n-1-i]
    for i in range(1,ma):
        r = n-1-(i-s[d[i]])
        l = r+1-d[i]
        j = i+(n-d[i])
        j2 = j+1
        if (d[i]+k)%2:
            if r < n-1:
                if a[r+1]+dp[i] > dp[j]:
                    dp[j] = a[r+1]+dp[i]
            if l > 0:
                if a[l-1]+dp[i] > dp[j2]:
                    dp[j2] = a[l-1]+dp[i]
        else:
            if r < n-1:
                if -a[r+1]+dp[i] < dp[j]:
                    dp[j] = -a[r+1]+dp[i]
            if l > 0:
                if -a[l-1]+dp[i] < dp[j2]:
                    dp[j2] = -a[l-1]+dp[i]
    print(dp[ma])
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [1 for i in range(n+1)]
    for i in range(1,n):
        s[i+1] = s[i]+n-i+1
    d = [None for i in range(ma+1)]
    d[0] = 0
    k = 1
    for i in range(1,n+1):
        for j in range(n+1-i):
            d[k+j] = i
        k += n+1-i
    k = n%2
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    for i in range(n+1,ma+1):
        if (d[i]+k)%2:
            dp[i] = float("inf")
        else:
            dp[i] = -float("inf")
    if k:
        for i in range(n):
            dp[i+1] = a[n-1-i]
    else:
        for i in range(n):
            dp[i+1] = -a[n-1-i]
    d.append(d[-1])
    for i in range(1,ma):
        r = n-1-(i-s[d[i]])
        l = r+1-d[i]
        j = i+(n-d[i])
        j2 = j+1
        if (d[i]+k)%2:
            if r < n-1:
                dp[j] = max(dp[j],a[r+1]+dp[i])
            if l > 0:
                dp[j2] = max(dp[j2],a[l-1]+dp[i])
        else:
            if r < n-1:
                dp[j] = min(dp[j],-a[r+1]+dp[i])
            if l > 0:
                dp[j2] = min(dp[j2],-a[l-1]+dp[i])
    print(dp[ma])
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m):
        if dp[m] != None:
            return dp[m]
        else:
            l = [n-(m-s[d])-1-(n-d-1),n-(m-s[d])-1]
            if not d%2:
                dp[m] = -float("inf")
                for i in range(2):
                    dp[m] = max(dp[m],a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
                return dp[m]
            else:
                dp[m] = float("inf")
                for i in range(2):
                    dp[m] = min(dp[m],-a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
                return dp[m]
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [None for i in range(n)]
    s[0] = ma
    for i in range(n-1):
        s[i+1] = s[i]-(i+2)
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    dfs(0,ma)
    print(dp[ma])
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m):
        if dp[m] != None:
            return dp[m]
        l = [n-(m-s[d])-1-(n-d-1),n-(m-s[d])-1]
        if not d%2:
            dp[m] = -float("inf")
            for i in range(2):
                dp[m] = max(dp[m],a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
            return dp[m]
        else:
            dp[m] = float("inf")
            for i in range(2):
                dp[m] = min(dp[m],-a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
            return dp[m]
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [None for i in range(n)]
    s[0] = ma
    for i in range(n-1):
        s[i+1] = s[i]-(i+2)
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    dfs(0,ma)
    print(dp[ma])
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m):
        if dp[m] != None:
            return dp[m]
        l = [n-(m-s[d])-1-(n-d-1),n-(m-s[d])-1]
        if not d%2:
            dp[m] = -float("inf")
            for i in range(2):
                dp[m] = max(dp[m],a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
            return dp[m]
        else:
            dp[m] = float("inf")
            for i in range(2):
                dp[m] = min(dp[m],-a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
            return dp[m]
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [None for i in range(n)]
    s[0] = ma
    for i in range(n-1):
        s[i+1] = s[i]-(i+2)
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    print(dfs(0,ma))
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m):
        if dp[m] != None:
            return dp[m]
        l = [n-(m-s[d])-1-(n-d-1),n-(m-s[d])-1]
        if not d%2:
            res = -float("inf")
            for i in range(2):
                res = max(res,a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
            dp[m] = res
            return dp[m]
        else:
            res = float("inf")
            for i in range(2):
                res = min(res,-a[l[i]]+dfs(d+1,max(0,m-2-d+i)))
            dp[m] = res
            return dp[m]
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [None for i in range(n)]
    s[0] = ma
    for i in range(n-1):
        s[i+1] = s[i]-(i+2)
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    print(dfs(0,ma))
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m):
        if dp[m] != None:
            return dp[m]
        l = [n-(m-s[d])-1-(n-d-1),n-(m-s[d])-1]
        if not d%2:
            res = -float("inf")
            res = max(res,a[l[0]]+dfs(d+1,max(0,m-2-d)))
            res = max(res,a[l[1]]+dfs(d+1,max(0,m-1-d)))
            dp[m] = res
            return dp[m]
        else:
            res = float("inf")
            for i in l:
                res = min(res,-a[l[0]]+dfs(d+1,max(0,m-2-d)))
                res = min(res,-a[l[1]]+dfs(d+1,max(0,m-1-d)))
            dp[m] = res
            return dp[m]
    n = I()
    a = LI()
    ma = n*(n+1)//2
    s = [None for i in range(n)]
    s[0] = ma
    for i in range(n-1):
        s[i+1] = s[i]-(i+2)
    dp = [None for i in range(ma+1)]
    dp[0] = 0
    print(dfs(0,ma))
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m,k):
        if dp[m] != None:
            return dp[m]
        l = [k,k+n-1-d]
        if not d%2:
            res = -float("inf")
            res = max(res,a[l[0]]+dfs(d+1,m^p[l[0]],k+1))
            res = max(res,a[l[1]]+dfs(d+1,m^p[l[1]],k))
            dp[m] = res
            return dp[m]
        else:
            res = float("inf")
            for i in l:
                res = min(res,-a[l[0]]+dfs(d+1,m^p[l[0]],k+1))
                res = min(res,-a[l[1]]+dfs(d+1,m^p[l[1]],k))
            dp[m] = res
            return dp[m]
    n = I()
    a = LI()
    p = [1 for i in range(n+1)]
    for i in range(n):
        p[i+1] = p[i]*2
    dp = defaultdict(lambda:None)
    dp[0] = 0
    print(dfs(0,p[-1]-1,0))
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m,k):
        if dp[m] != None:
            return dp[m]
        l = [k,k+n-1-d]
        if not d%2:
            res = -float("inf")
            res = max(res,a[l[0]]+dfs(d+1,m^p[l[0]],k+1))
            res = max(res,a[l[1]]+dfs(d+1,m^p[l[1]],k))
            dp[m] = res
            return dp[m]
        else:
            res = float("inf")
            for i in l:
                    res = min(res,-a[l[0]]+dfs(d+1,m^p[l[0]],k+1))
                    res = min(res,-a[l[1]]+dfs(d+1,m^p[l[1]],k))
            dp[m] = res
            return dp[m]
    n = I()
    a = LI()
    p = [1 for i in range(n+1)]
    for i in range(n):
        p[i+1] = p[i]*2
    dp = [None for i in range(p[-1])]
    dp[0] = 0
    print(dfs(0,p[-1]-1,0))
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()

Submission status: Time Limit Exceeded

Solution code:
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = SR()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007


#A
def A():
    n,k = LI()
    a = LI()
    dp = [0 for i in range(k+1)]
    f = [0 for i in range(k+1)]
    for i in range(k+1):
        if not f[i]:
            for j in a:
                if i-j >= 0:
                    dp[i] = 1-dp[i-j]
                    if dp[i] == 0:
                        break
            else:
                dp[i] = 1
    print(["First","Second"][dp[k]])
#B
def B():
    def dfs(d,m,k):
        if dp[m] != None:
            return dp[m]
        l = [k,k+n-1-d]
        if not d%2:
            res = -float("inf")
            res = max(res,a[l[0]]+dfs(d+1,m^p[l[0]],k+1))
            res = max(res,a[l[1]]+dfs(d+1,m^p[l[1]],k))
            dp[m] = res
            return dp[m]
        else:
            res = float("inf")
            for i in l:
                    res = min(res,-a[l[0]]+dfs(d+1,m^p[l[0]],k+1))
                    res = min(res,-a[l[1]]+dfs(d+1,m^p[l[1]],k))
            dp[m] = res
            return dp[m]
    n = I()
    a = LI()
    b = deque()
    p = [1 for i in range(n+1)]
    for i in range(n):
        p[i+1] = p[i]*2
    for i in range(1,n+1):
        b += [(p[i]-1) << j for j in range(n+1-i)]
    dp = [None for i in range(b[-1]+1)]
    dp[0] = 0
    print(dfs(0,b[-1],0))
    return

#C
def C():
    return

#D
def D():
    return

#E
def E():
    return

#F
def F():
    return

#G
def G():
    return

#H
def H():
    return

#Solve
if __name__ == "__main__":
    B()