Problem:


Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000



Sample input:
2 3


Sample output:
6

Submission status: Runtime Error

Solution code:
def main(sample_file = ''):

    """ convenient functions
    # for i, a in enumerate(iterable)
    # q, mod = divmod(a, b)
    # divmod(x, y) returns the tuple (x//y, x%y)
    # Higher-order function: reduce(operator.mul, xyz_count, 1)
    # manage median(s) using two heapq https://atcoder.jp/contests/abc127/tasks/abc127_f
    """

    """convenient decorator
    # @functools.lru_cache():
    # to facilitate use of recursive function
        # ex:
        # from functools import lru_cache
        # import sys
        # sys.setrecursionlimit(10**9)
        # @lru_cache(maxsize=None)
        # def fib(n):
        #     if n < 2:
        #         return n
        #     return fib(n-1) + fib(n-2)
        # print(fib(1000))
    """
    
    # import numpy as np
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product # https://docs.python.org/ja/3/library/itertools.html
    # accumulate() returns iterator! to get list: list(accumulate())
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  # prime factor
        b, e = 2, 0  # base, exponent
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        # TODO: How should I do when n - r is negative?
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict # https://docs.python.org/ja/3/library/collections.html#collections.deque
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest # https://docs.python.org/ja/3/library/heapq.html
    from copy import deepcopy, copy # https://docs.python.org/ja/3/library/copy.html
    import operator
    from operator import itemgetter #sort 
    # ex1: List.sort(key=itemgetter(1))
    # ex2: sorted(tuples, key=itemgetter(1,2))
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd # Deprecated since version 3.5: Use math.gcd() instead.
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    # first create factorial_list
    # fac_list = mod_factorial_list(n)
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    modpow = lambda a, n, p = MOD: pow(a, n, p) # Recursive function in python is slow!
    def modinv(a, p = MOD):
        # evaluate reciprocal using Fermat's little theorem:
        # a**(p-1) is identical to 1 (mod p) when a and p is coprime
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        # fac_list = modfactorial_list(100)
        # print(modcomb(100, 5, modfactorial_list(100)))
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    # Graph: https://en.wikipedia.org/wiki/Directed_graph
    # Bellman-Ford: O(|V||E|). Use this if there exists an edge with negative length in the graph
    # After N steps, the shortest path has converded if there doesn't exist an cycle of edges with negative
    # Watch out: d[N] == d[2*N] doesn't necessarily mean the graph doesn't have negative cycle
    # ref: https://www.youtube.com/watch?v=1Z6ofKN03_Y

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    """ initialize variables and set inputs
    # initialize variables
        # to initialize list, use [0] * n
        # to initialize two dimentional array:
            # ex) [[0] * N for _ in range(N)]
            # ex2) dp = [[0] * (N+1) for _ in range(W*2)]
    # set inputs
        # put inputs between specific values (almost as quickly)
        # ex) S = [-INF] + [int(r()) for _ in range(A)] + [INF]
        # open(0).read() is sometimes useful:
        # ex) n, m, *x = map(int, open(0).read().split())
        #     min(x[::2]) - max(x[1::2])
        # ex2) *x, = map(int, open(0).read().split())
        #     don't forget to add comma after *x if only one variable is used
    # preprocessing
        # transpose = [x for x in zip(*data)]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
        # flat = [flatten for inner in data for flatten in inner]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [1, 2, 3, 4, 5, 6, 7, 8, 9]
    # calculate and output
        # output pattern
        # ex1) print(*l) => when l = [2, 5, 6], printed 2 5 6
    """

    # functions to read input
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    # single int: int(r())
    # single string: r()
    # single float: float(r())
    # line int: R()
    # line string: r().split()
    # line (str, int, int): [j if i == 0 else int(j) for i, j in enumerate(r().split())]
    # lines int: [R() for _ in range(n)]
    """

    # for test
    if sample_file:
        sys.stdin = open(sample_file)
        
    # ----------------------------------
    # main

    A, B = R()
    print(lcm(A, B))
    
    # to finish code, use return instead of exit()
    # end of main
    # ----------------------------------

    """memo: how to use defaultdict of list
    # initialize
    Dic = defaultdict(list)
    # append / extend
    Dic[x].append(y)
    # three methods for loop: keys(), values(), items()
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    # to make binary digits text
    >>> a = 5
    >>> bin_str_a = format(a, '#06b')
    >>> print(bin_str_a)
    0b0101 # first 2 strings (='0b') indicates it is binary
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':

Submission status: Runtime Error

Solution code:
import math

a,b = map(int,input().split())



def lcm(x, y):
    return (x * y) // math.gcd(x, y)

print(lcm(a, b))

Submission status: Runtime Error

Solution code:
import math
a, b = map(int, input().split())
res = int(a*b / math.gcd(a, b))
print(res)

Submission status: Runtime Error

Solution code:
import math
a,b=map(int,input().split())
s=a*b//math.gcd(a, b)
print(s)

Submission status: Runtime Error

Solution code:
import math
a,b=map(int,input().split())
a*b//math.gcd(a, b)

Submission status: Runtime Error

Solution code:
import fractions as fr
A,B=map(int,input().split())
print(A*B//fr.gcd(A,B)

Submission status: Runtime Error

Solution code:
import math
def lcm(x, y):
    return int((x * y) / math.gcd(x, y))
  

A, B = map(int, input().split())
print(lcm(A, B))

Submission status: Runtime Error

Solution code:
import math
def lcm(x, y):
    return (x * y) // math.gcd(x, y)
A, B = map(int, input().split())
print(lcm(A, B))

Submission status: Runtime Error

Solution code:
from math import god

a, b = map(int, input().split())
print(a*b/god(a, b))

Submission status: Runtime Error

Solution code:
import numpy as np
a,b = map(int,input().split())
print(np.lcm(a, b))

Submission status: Runtime Error

Solution code:
# C - Snack
from math import gcd
A, B = map(int, input().split())
ans = A
while ans % B != 0:
    ans += A
print(ans)

Submission status: Runtime Error

Solution code:
# C - Snack
from math import gcd
A, B = map(int, input().split())
i = 1 
ans = A
while ans % B != 0:
    i += 1
    ans = A * i
print(ans)

Submission status: Runtime Error

Solution code:
# C - Snack
from math import gcd
A, B = map(int, input().split())
print(A * B // gcd(A, B))

Submission status: Runtime Error

Solution code:
# C - Snack
from math import gcd
A, B = map(int, input().split())
print(int(A * B / gcd(A, B)))

Submission status: Runtime Error

Solution code:
import math

X = [int(x) for x in input().split()]

v = math.gcd(X[0], X[1])
j = X[0] / v
p = int(X[1] * j)

print(p)

Submission status: Runtime Error

Solution code:
import fractions

X = [int(x) for x in input().split()]

v = fractions.gcd(X[0], X[1])
j = X[0] / v
p = int(X[1] * j)

print(p)

Submission status: Runtime Error

Solution code:
import functions

X = [int(x) for x in input().split()]

v = functions.gcd(X[0], X[1])
j = X[0] / v
p = int(X[1] * j)

print(p)

Submission status: Runtime Error

Solution code:
import math

X = [int(x) for x in input().split()]

v = math.gcd(X[0], X[1])
j = X[0] / v
p = int(X[1] * j)

print(p)

Submission status: Runtime Error

Solution code:
import math

A, B = map(int, input().split())

print(A * B // math.gcd(A, B))

Submission status: Runtime Error

Solution code:
import math
a,b = map(int,input().split())
div = math.gcd(a,b)
pro = a*b
print(pro//div)

Submission status: Runtime Error

Solution code:
import math

a, b = map(int, input().split())
ans = a * b / math.gcd(a,b)
print(int(ans))

Submission status: Runtime Error

Solution code:

import math

a,b=map(int,input().split())
print(int(a*b/math.gcd(a,b)))

Submission status: Runtime Error

Solution code:

def gcd(a,b):
    if(a>b):swap(a,b)
    if(a==0):return b
    return gcd(b%a,a)

a,b=map(int,input().split())
print(int(a*b/gcd(a,b)))

Submission status: Runtime Error

Solution code:
import fractions

def main():
    A, B = list(map(int, input().split()))
    print(lcm(A, B))

def lcm(a, b):
    return a * b // fractions.lcm(a, b)

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import numpy as np

def main():
    A, B = list(map(int, input().split()))
    print(np.lcm(A, B))

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import numpy as np

def main():
    row_input = input()
    A, B = list(map(int, input().split()))
    print(np.lcm(A, B))

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
A,B=map(int,input().split())
C=A*B
if A<B :
    A,B=B,A
while a%b=0:
    A,B=B,A%B 
D=C/B
print(D)

Submission status: Runtime Error

Solution code:
import math

def main():
    row_input = input()
    A = int(row_input.split()[0])
    B = int(row_input.split()[1])
    #A, B = list(map(int, input().split()))
    result = lcm(A, B)
    print(result)

def lcm(x, y):
    return int((x * y) / math.gcd(x, y))

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import math

def main():
    row_input = input()
    A = int(row_input.split()[0])
    B = int(row_input.split()[1])
    #A, B = list(map(int, input().split()))
    print(lcm(A, B))

def lcm(x, y):
    return int((x * y) / math.gcd(x, y))

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import math

def main():
    A, B = list(map(int, input().split()))
    print(lcm(A, B))

def lcm(x, y):
    return int((x * y) / math.gcd(x, y))

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import math

def main():
    A, B = map(int, input().split())
    print(lcm(A, B))

def lcm(x, y):
    return int((x * y) / math.gcd(x, y))

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import math

def main():
    A, B = map(int, input().split())
    print(lcm(A, B))

def lcm(x, y):
    return (x * y) // math.gcd(x, y)

if __name__ == "__main__":
    main()

Submission status: Runtime Error

Solution code:
import math
A, B = [int(i) for i in input().split()]

def func_ABC148(x, y):
    return (x * y) // math.gcd(x, y)

print(func_ABC148(A, B))

Submission status: Runtime Error

Solution code:
A, B = [int(i) for i in input().split()]

import math
def func_ABC148(x, y):
    return (x * y) // math.gcd(x, y)

print(func_ABC148(A, B))

Submission status: Runtime Error

Solution code:
import math

s = list(map(int,input().split()))

print((s[0] * s[1]) // math.gcd(s[0], s[1]))

Submission status: Runtime Error

Solution code:
import math

s = list(map(int,input().split()))

def lcm(x, y):
    return (x * y) // math.gcd(x, y)

print(lcm(s[0], s[1]))

Submission status: Runtime Error

Solution code:
import math
a = list(map(int, input().split()))
print(a[0]*a[1]//math.gcd(a[0],a[1]))

Submission status: Runtime Error

Solution code:
import math
a = list(map(int, input().split()))
print(int(a[0]*a[1]/math.gcd(a[0],a[1])))

Submission status: Runtime Error

Solution code:
import math
a,b = map(int, input().split())

print((a * b) // math.gcd(a,b))

Submission status: Runtime Error

Solution code:
import math

a,b = map(int,input().split())

x = math.gcd(a,b)

s = -(-a//x)
t = -(-b//x)

if a >= b:
  print(s)
else:
  print(t)

Submission status: Runtime Error

Solution code:
from math import gcd
A,B = map(int, input().split())
print(A * B // gcd(A,B))

Submission status: Runtime Error

Solution code:
a, b = map(int, input().split())
m = 0
for i in range(1, min(a, b)):
    if a%i==0 and b%i==0:
        m = i
print(int(a*b/m))

Submission status: Runtime Error

Solution code:
#include <bits/stdc++.h>
using namespace std;

int gcd(long long  x, long long  y) {
    long long  tmp;
    while ((fmod(x, y)) != 0) {
        tmp = y;
        y = fmod(x, y);
        x = tmp;
    }
    return y;
}

int main() {
    long long  a,b;
    cin >> a >> b;
    long long  lcd = (a * b) / gcd(max(a, b), min(a, b));
    cout << lcd << endl;
    return 0;
}

Submission status: Runtime Error

Solution code:
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
import itertools
from itertools import permutations,combinations
import sys
import bisect
import string
import math
import time
import random
def I():
    return int(input())
def MI():
    return map(int,input().split())
def LI():
    return [int(i) for i in input().split()]
def LI_():
    return [int(i)-1 for i in input().split()]
def StoI():
    return [ord(i)-97 for i in input()]
def ItoS(nn):
    return chr(nn+97)
def GI(V,E,Directed=False,index=0):
    org_inp=[]
    g=[[] for i in range(n)]
    for i in range(E):
        inp=LI()
        org_inp.append(inp)
        if index==0:
            inp[0]-=1
            inp[1]-=1
        if len(inp)==2:
            a,b=inp
            g[a].append(b)
            if not Directed:
                g[b].append(a)
        elif len(inp)==3:
            a,b,c=inp
            aa=(inp[0],inp[2])
            bb=(inp[1],inp[2])
            g[a].append(bb)
            if not Directed:
                g[b].append(aa)
    return g,org_inp
def show(*inp,end='\n'):
    if show_flg:
        print(*inp,end=end)
YN=['Yes','No']
mo=10**9+7
inf=float('inf')
l_alp=string.ascii_lowercase
u_alp=string.ascii_uppercase
ts=time.time()
#sys.setrecursionlimit(10**5)
input=lambda: sys.stdin.readline().rstrip()

def ran_input():
    import random
    n=random.randint(4,16)
    rmin,rmax=1,10
    a=[random.randint(rmin,rmax) for _ in range(n)]
    return n,a

show_flg=False
show_flg=True
#for i in range(n):

ans=0
a,b=LI()
print(a*b//math.gcd(a,b))

Submission status: Runtime Error

Solution code:
import math
x,y = input().split()
a = int(x)
b = int(y)
print(int((a*b)/math.gcd(a,b)))

Submission status: Runtime Error

Solution code:
import math
x,y = input().split()
a = int(x)
b = int(y)
print((a*b)/math.gcd(a,b))

Submission status: Runtime Error

Solution code:
import math
x, y = map(int, input().split())
print((x * y) // math.gcd(x, y))

Submission status: Runtime Error

Solution code:
x,y = input().split()
a = int(x)
b = int(y)
for i in range(1,200000):
    if i%a == 0 and i%b ==0:
        return i
        m = i
        break
    else:
        pass

Submission status: Runtime Error

Solution code:
import math
x, y = map(int, input())
print((x * y) // math.gcd(x, y))

Submission status: Runtime Error

Solution code:
x,y = input("Enter a two value: ").split()
a = int(x)
b = int(y)
for i in range(1,200000):
    if i%a == 0 and i%b ==0:
        return i
        m = i
        break
    else:
        pass

Submission status: Runtime Error

Solution code:
#coding:utf-8
import fractions
a = int(input())
b = int(input())
print( a * b // fractions.gcd(a, b))

Submission status: Runtime Error

Solution code:
import math
A,B = map(int,input().split())

def lcd(x,y):
  return (x*y)//math.gcd(x,y)

print(lcd(A,B))

Submission status: Runtime Error

Solution code:
import math
A,B=map(int,input().split())
print(A*B/gcd(A,B))

Submission status: Runtime Error

Solution code:
A, B = map(int, input().split())
numberA = 0
numberB = 0
dataA = []
dataB = []
sosuA = []
sosuB = []
flagA = []
flagB = []
i = 1
boc = 0
while i <= A:
    dataA += [i]
    i += 1
i = 1
while i <= B:
    dataB += [i]
    i += 1
n = 1
while n <= A:
    if A == 1:
        sosuA += [n]
        numberA += 1
        break
    if A % n == 0:
        sosuA += [n]
        A = A / n
        numberA += 1
        if n == 1:
            n += 1
    else:
        n += 1
n = 1
while n <= B:
    if B == 1:
        sosuB += [n]
        numberB += 1
        break
    if B % n == 0:
        sosuB += [n]
        B = B / n
        numberB += 1
        if n == 1:
            n += 1
    else:
        n += 1
i = 0
n = 0
rase = 0
while i <= numberA - 1:
    if i != 0 and sosuA[i] == sosuA[i - 1]:
        kai = sosuA[i]
        flagA += [kai]
        i += 1
        n = 0
        continue
    if sosuA[i] == sosuB[n]:
        kai = sosuA[i]
        flagA += [kai]
        n += 1
        rase = 1
        boc = n
        if n == numberB - 1 or numberB:
            i += 1
            n = 0
            rase = 0
            continue
        if i == numberA - 1:
            break
    elif rase == 1:
        i += 1
        n = 0
        rase = 0
    elif sosuA[i] != sosuB[n] and n == numberB - 1:
        kai = sosuA[i]
        flagA += [kai]
        if i == numberA - 1:
            break
        i += 1
        n = 0
    else:
        n += 1
i = 0
n = 0
rase = 0
while i <= numberB - 1:
    if i != 0 and sosuB[i] == sosuB[i - 1]:
        kai = sosuB[i]
        flagB += [kai]
        i += 1
        n = 0
        continue
    if sosuB[i] == sosuA[n]:
        kai = sosuB[i]
        flagB += [kai]
        n += 1
        rase = 1
        if n == numberA - 1 or numberA:
            i += 1
            n = 0
            rase = 0
            continue
        if i == numberB - 1:
            break
    elif rase == 1:
        i += 1
        n = 0
        rase = 0
    elif sosuB[i] != sosuA[n] and n == numberA - 1:
        kai = sosuB[i]
        flagB += [kai]
        if i == numberB - 1:
            break
        i += 1
        n = 0
    else:
        n += 1
i = 0
n = 0
tuika = []
if len(flagA) >= len(flagB):
    while i <= numberB - 1:
        if sosuB[i] == flagA[n]:
            n += 1
            i += 1
            if n == len(flagA):
                sai = len(sosuB) - i
                for m in range(sai):
                    tuika += [sosuB[i]]
                    i += 1
                break
        elif n == numberA - 1:
            kai = sosuB[i]
            tuika += [kai]
            i += 1
            n = 0
        elif sosuB[i] < sosuA[n]:
            kai = sosuB[i]
            tuika += [kai]
            n = 0
            i += 1
        else:
            n += 1
    flagA += tuika
    ans = 1
    for i in flagA:
        ans = ans * i
    print(ans)
else:
    while i <= numberA - 1:
        if sosuA[i] == flagB[n]:
            n += 1
            i += 1
        if n == len(flagB):
                sai = len(sosuA) - i
                for m in range(sai):
                    tuika += [sosuA[i]]
                    i += 1
                break
        elif n == numberB - 1:
            kai = sosuA[i]
            tuika += [kai]
            i += 1
            n = 0
        elif sosuA[i] < sosuB[n]:
            kai = sosuA[i]
            tuika += [kai]
            n = 0
            i += 1
        else:
            n += 1
    flagB += tuika
    ans = 1
    for i in flagB:
        ans = ans * i
    print(ans)