Problem:


Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.



Sample input:
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Sample output:
3
1
5

Submission status: Accepted

Solution code:
import sys
sys.setrecursionlimit(2147483647)
INF = 1 << 60
MOD = 10**9 + 7 # 998244353
input = lambda:sys.stdin.readline().rstrip()

class SegmentTree(object):
    def __init__(self, A, dot, unit):
        n = 1 << (len(A) - 1).bit_length()
        tree = [unit] * (2 * n)
        for i, v in enumerate(A):
            tree[i + n] = v
        for i in range(n - 1, 0, -1):
            tree[i] = dot(tree[i << 1], tree[i << 1 | 1])
        self._n = n
        self._tree = tree
        self._dot = dot
        self._unit = unit

    def __getitem__(self, i):
        return self._tree[i + self._n]

    def update(self, i, v):
        i += self._n
        self._tree[i] = v
        while i != 1:
            i >>= 1
            self._tree[i] = self._dot(self._tree[i << 1], self._tree[i << 1 | 1])

    def add(self, i, v):
        self.update(i, self[i] + v)

    def sum(self, l, r):
        l += self._n
        r += self._n
        l_val = r_val = self._unit
        while l < r:
            if l & 1:
                l_val = self._dot(l_val, self._tree[l])
                l += 1
            if r & 1:
                r -= 1
                r_val = self._dot(self._tree[r], r_val)
            l >>= 1
            r >>= 1
        return self._dot(l_val, r_val)

def resolve():
    n = int(input())
    trees = [[0] * n for _ in range(26)]
    character = [None] * n

    for i, c in enumerate(input()):
        c = ord(c) - ord('a')
        character[i] = c
        trees[c][i] = 1
    for i in range(26):
        trees[i] = SegmentTree(trees[i], max, 0)

    for _ in range(int(input())):
        q, *A = input().split()
        if q == '1':
            i, c = A
            i = int(i) - 1
            c = ord(c) - ord('a')
            trees[character[i]].update(i, 0)
            character[i] = c
            trees[c].update(i, 1)
        else:
            l, r = map(int, A)
            l -= 1
            print(sum(trees[i].sum(l, r) for i in range(26)))
resolve()

Submission status: Accepted

Solution code:
class Segment_tree():
    def __init__(self, n, s):
        self.alphabet_list = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]
        self.key = dict()
        self.k = 1
        for value in self.alphabet_list:
            self.key[value] = self.k
            self.k *= 2
        self.inf = pow(2, 32)
        self.n = n
        self.s = s
        self.N = 1
        while self.N < self.n:
            self.N *= 2
        self.size = self.N * 2
        self.size -= 1
        self.N -= 1
        self.segment = [0]*(self.N) + [self.key[self.s[i]] for i in range(self.n)] + [0]*(self.size-self.N-self.n)
        for i in range(self.N-1, -1, -1):
            self.segment[i] = self.segment[2*i+1]|self.segment[2*i+2]

    def update(self, i, x):
        i += (self.N-1)
        self.segment[i] = self.key[x]
        while i > 0:
            i = (i-1)//2
            self.segment[i] = self.segment[2*i+1]|self.segment[2*i+2]
        
    def find(self, a, b, k, l, r):
        if r <= a or b <= l:
            return 0
        elif a <= l and r <= b:
            return self.segment[k]
        else:
            find_l = self.find(a, b, 2*k+1, l, (l+r)//2)
            find_r = self.find(a, b, 2*k+2, (l+r)//2, r)
            return find_l|find_r


n = int(input())
s = input()
segment = Segment_tree(n, s)
q = int(input())
N = 1
while N < n:
  N *= 2
for i in range(q):
    quer = [x for x in input().split()]
    if quer[0] == "1":
        i, c = int(quer[1]), quer[2]
        segment.update(i, c)
    else:
        l, r = int(quer[1]), int(quer[2])
        key = segment.find(l-1, r, 0, 0, N)
        ans = 0
        for i in range(26):
            if (key>>i)&1:
                ans += 1
        print(ans)

Submission status: Accepted

Solution code:
def main(sample_file = ''):

    """ convenient functions
    # for i, a in enumerate(iterable)
    # q, mod = divmod(a, b)
    # divmod(x, y) returns the tuple (x//y, x%y)
    # Higher-order function: reduce(operator.mul, xyz_count, 1)
    # manage median(s) using two heapq https://atcoder.jp/contests/abc127/tasks/abc127_f
    """

    """convenient decorator
    # @functools.lru_cache():
    # to facilitate use of recursive function
        # ex:
        # from functools import lru_cache
        # import sys
        # sys.setrecursionlimit(10**9)
        # @lru_cache(maxsize=None)
        # def fib(n):
        #     if n < 2:
        #         return n
        #     return fib(n-1) + fib(n-2)
        # print(fib(1000))
    """
    
    # import numpy as np
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product # https://docs.python.org/ja/3/library/itertools.html
    # accumulate() returns iterator! to get list: list(accumulate())
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  # prime factor
        b, e = 2, 0  # base, exponent
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        # TODO: How should I do when n - r is negative?
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict # https://docs.python.org/ja/3/library/collections.html#collections.deque
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest # https://docs.python.org/ja/3/library/heapq.html
    from copy import deepcopy, copy # https://docs.python.org/ja/3/library/copy.html
    import operator
    from operator import itemgetter #sort 
    # ex1: List.sort(key=itemgetter(1))
    # ex2: sorted(tuples, key=itemgetter(1,2))
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd # Deprecated since version 3.5: Use math.gcd() instead.
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    # first create factorial_list
    # fac_list = mod_factorial_list(n)
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz') # 26
    modpow = lambda a, n, p = MOD: pow(a, n, p) # Recursive function in python is slow!
    def modinv(a, p = MOD):
        # evaluate reciprocal using Fermat's little theorem:
        # a**(p-1) is identical to 1 (mod p) when a and p is coprime
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        # fac_list = modfactorial_list(100)
        # print(modcomb(100, 5, modfactorial_list(100)))
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    # ************ Graph ************
    # Graph: https://en.wikipedia.org/wiki/Directed_graph
    # 最短経路問題: https://ja.wikipedia.org/wiki/%E6%9C%80%E7%9F%AD%E7%B5%8C%E8%B7%AF%E5%95%8F%E9%A1%8C
    
    # Bellman-Ford: O(|V||E|). Use this if there exists an edge with negative length in the graph
    # After N steps, the shortest path has converded if there doesn't exist an cycle of edges with negative
    # Watch out: d[N] == d[2*N] doesn't necessarily mean the graph doesn't have negative cycle
    # ref: https://www.youtube.com/watch?v=1Z6ofKN03_Y

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    # Warshall Floyd O(V**3)
    def warshall_floyd(number_vertex, XYD, shift_one_for_vertex=False):
        # ref: https://juppy.hatenablog.com/entry/2018/11/01/%E8%9F%BB%E6%9C%AC_python_%E5%85%A8%E7%82%B9%E5%AF%BE%E6%9C%80%E7%9F%AD%E7%B5%8C%E8%B7%AF%E6%B3%95%EF%BC%88%E3%83%AF%E3%83%BC%E3%82%B7%E3%83%A3%E3%83%AB%E3%83%95%E3%83%AD%E3%82%A4%E3%83%89%E6%B3%95
        # number_vertex: len(vertex)
        # XYD: list of distance from x to y
        # shift_one_for_vertex: XYDの値が1~Nの時(0~N-1でない時)に調整するフラグ。
        # d[i][j]: iからjへの最短距離
        d = [[float("inf")]*number_vertex for i in range(number_vertex)]
        for x, y, dist in XYD:
            if shift_one_for_vertex:
                x = x - 1
                y = y - 1
            d[x][y] = dist
            d[y][x] = dist
        for i in range(number_vertex):
            d[i][i] = 0 # distance of same vertex is 0
        for k in range(number_vertex):
            for i in range(number_vertex):
                for j in range(number_vertex):
                    d[i][j] = min(d[i][j],d[i][k] + d[k][j])
        return d


    """ initialize variables and set inputs
    # initialize variables
        # to initialize list, use [0] * n
        # to initialize two dimentional array:
            # ex) [[0] * N for _ in range(N)]
            # ex2) dp = [[0] * (N+1) for _ in range(W*2)]
    # set inputs
        # put inputs between specific values (almost as quickly)
        # ex) S = [-INF] + [int(r()) for _ in range(A)] + [INF]
        # open(0).read() is sometimes useful:
        # ex) n, m, *x = map(int, open(0).read().split())
        #     min(x[::2]) - max(x[1::2])
        # ex2) *x, = map(int, open(0).read().split())
        #     don't forget to add comma after *x if only one variable is used
    # preprocessing
        # transpose = [x for x in zip(*data)]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
        # flat = [flatten for inner in data for flatten in inner]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [1, 2, 3, 4, 5, 6, 7, 8, 9]
    # calculate and output
        # output pattern
        # ex1) print(*l) => when l = [2, 5, 6], printed 2 5 6
    """

    # functions to read input
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    # single int: int(r())
    # single string: r()
    # single float: float(r())
    # line int: R()
    # line string: r().split()
    # line (str, int, int): [j if i == 0 else int(j) for i, j in enumerate(r().split())]
    # lines int: [R() for _ in range(n)]
    """

    # for test
    if sample_file:
        sys.stdin = open(sample_file)
        
    # ----------------------------------
    # main
    #%%
    N = r_int()
    S = r()
    Q = r_int()
    Que = [R_str() for _ in range(Q)]
    
    # 小文字をカウントしたリストを持つセグ木で行けそう。
    class SegTree:
        """
        ref: https://qiita.com/takayg1/items/c811bd07c21923d7ec69
        init(init_val, ide_ele): 配列init_valで初期化 O(N)
        update(k, x): k番目の値をxに更新 O(logN)
        query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
        """
        def __init__(self, init_val, segfunc, ide_ele):
            """
            init_val: 配列の初期値
            segfunc: 区間にしたい操作
            ide_ele: 単位元
            n: 要素数
            num: n以上の最小の2のべき乗
            tree: セグメント木(1-index)
            """
            n = len(init_val)
            self.segfunc = segfunc
            self.ide_ele = ide_ele
            self.num = 1 << (n - 1).bit_length()
            self.tree = [ide_ele] * 2 * self.num
            # 配列の値を葉にセット
            for i in range(n):
                self.tree[self.num + i] = init_val[i]
            # 構築していく
            for i in range(self.num - 1, 0, -1):
                self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])

        def update(self, k, x):
            """
            k番目の値をxに更新
            k: index(0-index)
            x: update value
            """
            k += self.num
            self.tree[k] = x
            while k > 1:
                self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
                k >>= 1

        def query(self, l, r):
            """
            [l, r)のsegfuncしたものを得る
            l: index(0-index)
            r: index(0-index)
            """
            res = self.ide_ele

            l += self.num
            r += self.num
            while l < r:
                if l & 1:
                    res = self.segfunc(res, self.tree[l])
                    l += 1
                if r & 1:
                    res = self.segfunc(res, self.tree[r - 1])
                l >>= 1
                r >>= 1
            return res
    
    # a = [14, 5, 9, 13, 7, 12, 11, 1, 7, 8]
    
    def segfunc(x, y):
        return x | y
    
    def count_ones_by_bitmask(num):
        count = 0
        while num:
            count += num & 1
            num >>= 1
        return count
    
    S_int = [2**(ord(i)-97) for i in S]
    ide_ele = 0
    seg = SegTree(S_int, segfunc, ide_ele)
    for i, a, b in Que:
        if i == '1':
            seg.update(int(a)-1, 2**(ord(b)-97))
        else:
            print(count_ones_by_bitmask(seg.query(int(a)-1, int(b))))

    #%%
    # end of main
    # ----------------------------------

    """memo: how to use defaultdict of list
    # initialize
    Dic = defaultdict(list)
    # append / extend
    Dic[x].append(y)
    # three methods for loop: keys(), values(), items()
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    # to make binary digits text
    >>> a = 5
    >>> bin_str_a = format(a, '#06b')
    >>> print(bin_str_a)
    0b0101 # first 2 strings (='0b') indicates it is binary
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
import sys
from bisect import bisect_left, bisect_right, insort

sr = lambda: sys.stdin.readline().rstrip()
ir = lambda: int(sr())
lr = lambda: list(map(int, sr().split()))

N = ir()
S = list('-' + sr())
d = [[] for _ in range(26)]
for i in range(1, N+1):
    s = S[i]
    o = ord(s) - ord('a')
    d[o].append(i)

Q = ir()
for _ in range(Q):
    q, a, b = sr().split()
    if q == '1':
        a = int(a)
        if S[a] == b:
            continue
        prev = ord(S[a]) - ord('a')
        d[prev].pop(bisect_left(d[prev], a))
        next = ord(b) - ord('a')
        insort(d[next], a)
        S[a] = b
    else:
        left = int(a); right = int(b)
        ans = 0
        for alpha in range(26):
            index = bisect_left(d[alpha], left)
            if index < len(d[alpha]) and d[alpha][index] <= right:
                ans += 1
        print(ans)

Submission status: Accepted

Solution code:
import bisect
import sys
input = lambda: sys.stdin.readline().rstrip()

n=int(input())
s= list(input())
q=[]
qq=int(input())
for i in range(qq):
    q.append(list(input().split()))

# アルファベットごとに出現位置を記録
x=[[] for i in range(26)]
for i,j in enumerate(s):
    x[ord(j)-97].append(i)

# 終点対策
for i in range(26):
    x[i].append(5*10**5)


for i,j,k in q:
    if int(i)==1:
        if s[int(j)-1]!=k:
            v=s[int(j)-1]
            s[int(j)-1]=k
            # 変更前の要素を削除
            index=bisect.bisect_right(x[ord(v)-97], int(j)-1) - 1
            x[ord(v)-97].pop(index)
            # 変更後の要素を加える
            bisect.insort_right(x[ord(k)-97],int(j)-1)
    else:
        cnt=0
        j=int(j)-1
        k=int(k)-1
        for l in range(26):
            index=bisect.bisect_left(x[l],j)
            if x[l][index]<=k:
                cnt+=1


        print(cnt)

Submission status: Accepted

Solution code:
f=input; from bisect import bisect_left as g, insort as h
d={chr(97+i):[] for i in range(26)}
f(); s,i=list(f()),0
for c in s: d[c]+=[i]; i+=1
for _ in range(int(f())):
  a,b,c=f().split(); b=int(b)-1
  if a>'1': print(sum(1 for l in d.values() if g(l,b)<len(l) and l[g(l,b)]<int(c)))
  elif s[b]!=c: l=d[s[b]]; l.pop(g(l,b)); s[b]=c; h(d[c],b)

Submission status: Accepted

Solution code:
f=input; from bisect import bisect_left as g, insort as h
f(); s,i=list(f()),0
from collections import *
d=defaultdict(list)
for c in s: d[c]+=[i]; i+=1
for _ in range(int(f())):
  a,b,c=f().split(); b=int(b)-1
  if a>'1': print(sum(1 for l in d.values() if g(l,b)<len(l) and l[g(l,b)]<int(c)))
  elif s[b]!=c: l=d[s[b]]; l.pop(g(l,b)); s[b]=c; h(d[c],b)

Submission status: Accepted

Solution code:
f=input
from bisect import bisect_left as g, insort as h
n,s=int(f()),list(f())
d={chr(97+i):[] for i in range(26)}
for i in range(n): d[s[i]]+=[i]
for _ in range(int(f())):
  a,b,c=f().split(); b=int(b)-1
  if a>'1': print(sum(1 for l in d.values() if g(l,b)<len(l) and l[g(l,b)]<int(c)))
  elif s[b]!=c: l=d[s[b]]; l.pop(g(l,b)); s[b]=c; h(d[c],b)

Submission status: Accepted

Solution code:
f=input
n,s,q=int(f()),list(f()),int(f())
d={chr(97+i):[] for i in range(26)}
for i in range(n):
  d[s[i]]+=[i]
from bisect import *
for i in range(q):
  a,b,c=f().split()
  b=int(b)-1
  if a=='1':
    if s[b]==c: continue
    d[s[b]].pop(bisect(d[s[b]],b)-1)
    s[b]=c
    insort(d[c],b)
  else:
    t=0
    for l in d.values():
      m=bisect(l,b-1)
      if m<len(l) and l[m]<int(c): t+=1
    print(t)

Submission status: Accepted

Solution code:
f=input
n,l,q=int(f()),list(f()),int(f())
B=[[0]*-~n for i in range(26)]
def S(o,i):
  s=0
  while i: s+=B[o][i]; i-=i&-i
  return s
def A(o,i,x):
  while i<=n: B[o][i]+=x; i+=i&-i
for i in range(n): A(ord(l[i])-97,i+1,1)
for i in range(q):
  a,b,c=f().split(); b=int(b)
  if a>'1': print(sum(1 for o in range(26) if S(o,int(c))-S(o,b-1)))
  else: A(ord(l[b-1])-97,b,-1); l[b-1]=c; A(ord(c)-97,b,1)

Submission status: Accepted

Solution code:
f=input;n,l,q=int(f()),list(f()),int(f())
B=[[0]*-~n for i in range(26)]
def S(o,i):
  s=0
  while i: s+=B[o][i]; i-=i&-i
  return s
def A(o,i,x):
  while i<=n: B[o][i]+=x; i+=i&-i
for i in range(n): A(ord(l[i])-97,i+1,1)
for i in range(q):
  a,b,c=input().split(); b=int(b)
  if a>'1': print(sum(1 for o in range(26) if S(o,int(c))-S(o,b-1)))
  else: A(ord(l[b-1])-97,b,-1); l[b-1]=c; A(ord(c)-97,b,1)

Submission status: Accepted

Solution code:
n=int(input())
l=list(input())
q=int(input())
bit=[[0]*(n+1) for i in range(26)]
def bit_sum(o,i):
  s=0
  while i:
    s+=bit[o][i]
    i-=i&-i
  return s
def bit_add(o,i,x):
  while i<=n:
    bit[o][i] += x
    i+=i&-i
for i in range(n):
  bit_add(ord(l[i])-97,i+1,1)
for i in range(q):
  a,b,c=input().split()
  b=int(b)-1
  if a=='1':
    bit_add(ord(l[b])-97,b+1,-1)
    l[b]=c
    bit_add(ord(c)-97,b+1,1)
  else:
    c=int(c)
    print(sum(1 for o in range(26) if bit_sum(o,c)-bit_sum(o,b)))

Submission status: Accepted

Solution code:
import sys
from bisect import bisect_left, bisect_right, insort

sr = lambda: sys.stdin.readline().rstrip()
ir = lambda: int(sr())
lr = lambda: list(map(int, sr().split()))

N = ir()
S = list('-' + sr())
d = [[] for _ in range(26)]
for i in range(1, N+1):
    s = S[i]
    o = ord(s) - ord('a')
    d[o].append(i)

Q = ir()
for _ in range(Q):
    q, a, b = sr().split()
    if q == '1':
        a = int(a)
        if S[a] == b:
            continue
        prev = ord(S[a]) - ord('a')
        d[prev].pop(bisect_left(d[prev], a))
        next = ord(b) - ord('a')
        insort(d[next], a)
        S[a] = b
    else:
        a = int(a); b = int(b)
        ans = 0
        for alpha in range(26):
            if bisect_right(d[alpha], b) - bisect_left(d[alpha], a) >= 1:
                ans += 1
        print(ans)

Submission status: Accepted

Solution code:
import sys
from bisect import bisect_left, bisect_right, insort

sr = lambda: sys.stdin.readline().rstrip()
ir = lambda: int(sr())
lr = lambda: list(map(int, sr().split()))

N = ir()
S = list('-' + sr())
d = [[] for _ in range(26)]
for i in range(1, N+1):
    s = S[i]
    o = ord(s) - ord('a')
    d[o].append(i)

Q = ir()
for _ in range(Q):
    q, a, b = sr().split()
    if q == '1':
        a = int(a)
        if S[a] == b:
            continue
        prev = ord(S[a]) - ord('a')
        d[prev].remove(a)
        next = ord(b) - ord('a')
        insort(d[next], a)
        S[a] = b
    else:
        a = int(a); b = int(b)
        ans = 0
        for alpha in range(26):
            if bisect_right(d[alpha], b) - bisect_left(d[alpha], a) >= 1:
                ans += 1
        print(ans)