Problem:


Score : 2100 points

Problem Statement

There are N jewelry shops numbered 1 to N.

Shop i (1 \leq i \leq N) sells K_i kinds of jewels.
The j-th of these jewels (1 \leq j \leq K_i) has a size and price of S_{i,j} and P_{i,j}, respectively, and the shop has C_{i,j} jewels of this kind in stock.

A jewelry box is said to be good if it satisfies all of the following conditions:

For each of the jewelry shops, the box contains one jewel purchased there.

All of the following M restrictions are met.

Restriction i (1 \leq i \leq M): (The size of the jewel purchased at Shop V_i)\leq (The size of the jewel purchased at Shop U_i)+W_i

Answer Q questions.
In the i-th question, given an integer A_i, find the minimum total price of jewels that need to be purchased to make A_i good jewelry boxes. If it is impossible to make A_i good jewelry boxes, report that fact.

Constraints

1 \leq N \leq 30

1 \leq K_i \leq 30

1 \leq S_{i,j} \leq 10^9

1 \leq P_{i,j} \leq 30

1 \leq C_{i,j} \leq 10^{12}

0 \leq M \leq 50

1 \leq U_i,V_i \leq N

U_i \neq V_i

0 \leq W_i \leq 10^9

1 \leq Q \leq 10^5

1 \leq A_i \leq 3 \times 10^{13}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
Description of Shop 1
Description of Shop 2
\vdots
Description of Shop N
M
U_1 V_1 W_1
U_2 V_2 W_2
\vdots
U_M V_M W_M
Q
A_1
A_2
\vdots
A_Q

The description of Shop i (1 \leq i \leq N) is in the following format:

K_i
S_{i,1} P_{i,1} C_{i,1}
S_{i,2} P_{i,2} C_{i,2}
\vdots
S_{i,K_i} P_{i,K_i} C_{i,K_i}

Output

Print Q lines.
The i-th line should contain the minimum total price of jewels that need to be purchased to make A_i good jewelry boxes, or -1 if it is impossible to make them.

Sample Input 1

3
2
1 10 1
3 1 1
3
1 10 1
2 1 1
3 10 1
2
1 1 1
3 10 1
2
1 2 0
2 3 0
3
1
2
3

Sample Output 1

3
42
-1

Let (i,j) represent the j-th jewel sold at Shop i.
The answer to each query is as follows:

A_1=1: Making a box with (1,2),(2,2),(3,1) costs 1+1+1=3, which is optimal.

A_2=2: Making a box with (1,1),(2,1),(3,1) and another with (1,2),(2,3),(3,2) costs (10+10+1)+(1+10+10)=42, which is optimal.

A_3=3: We cannot make three good boxes.

Sample Input 2

5
5
86849520 30 272477201869
968023357 28 539131386006
478355090 8 194500792721
298572419 6 894877901270
203794105 25 594579473837
5
730211794 22 225797976416
842538552 9 420531931830
871332982 26 81253086754
553846923 29 89734736118
731788040 13 241088716205
5
903534485 22 140045153776
187101906 8 145639722124
513502442 9 227445343895
499446330 6 719254728400
564106748 20 333423097859
5
332809289 8 640911722470
969492694 21 937931959818
207959501 11 217019915462
726936503 12 382527525674
887971218 17 552919286358
5
444983655 13 487875689585
855863581 6 625608576077
885012925 10 105520979776
980933856 1 711474069172
653022356 19 977887412815
10
1 2 231274893
2 3 829836076
3 4 745221482
4 5 935448462
5 1 819308546
3 5 815839350
5 3 513188748
3 1 968283437
2 3 202352515
4 3 292999238
10
510266667947
252899314976
510266667948
374155726828
628866122125
628866122123
1
628866122124
510266667949
30000000000000

Sample Output 2

26533866733244
13150764378752
26533866733296
19456097795056
-1
33175436167096
52
33175436167152
26533866733352
-1



Sample input:
3
2
1 10 1
3 1 1
3
1 10 1
2 1 1
3 10 1
2
1 1 1
3 10 1
2
1 2 0
2 3 0
3
1
2
3


Sample output:
3
42
-1

Submission status: Wrong Answer

Solution code:
import math

print(math.floor(1.1421))
#1
print(math.floor(1.7320))
#1
print(math.floor(1.5))
#1
print(math.floor(2.5))
#2
print(math.floor(3.5))
#3