Problem:


Score : 200 points

Problem Statement

We have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.

We will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?

Constraints

All values in input are integers.

0 \leq A, B, C

1 \leq K \leq A + B + C \leq 2 \times 10^9

Input

Input is given from Standard Input in the following format:

A B C K

Output

Print the maximum possible sum of the numbers written on the cards chosen.

Sample Input 1

2 1 1 3

Sample Output 1

2

Consider picking up two cards with 1s and one card with a 0.
In this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.

Sample Input 2

1 2 3 4

Sample Output 2

0

Sample Input 3

2000000000 0 0 2000000000

Sample Output 3

2000000000



Sample input:
2 1 1 3


Sample output:
2

Submission status: Accepted

Solution code:
def main(sample_file = ''):

    """ convenient functions
    # for i, a in enumerate(iterable)
    # q, mod = divmod(a, b)
    # divmod(x, y) returns the tuple (x//y, x%y)
    # Higher-order function: reduce(operator.mul, xyz_count, 1)
    # manage median(s) using two heapq https://atcoder.jp/contests/abc127/tasks/abc127_f
    """

    """convenient decorator
    # @functools.lru_cache():
    # to facilitate use of recursive function
        # ex:
        # from functools import lru_cache
        # import sys
        # sys.setrecursionlimit(10**9)
        # @lru_cache(maxsize=None)
        # def fib(n):
        #     if n < 2:
        #         return n
        #     return fib(n-1) + fib(n-2)
        # print(fib(1000))
    """
    
    # import numpy as np
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product # https://docs.python.org/ja/3/library/itertools.html
    # accumulate() returns iterator! to get list: list(accumulate())
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  # prime factor
        b, e = 2, 0  # base, exponent
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        # TODO: How should I do when n - r is negative?
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict # https://docs.python.org/ja/3/library/collections.html#collections.deque
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest # https://docs.python.org/ja/3/library/heapq.html
    from copy import deepcopy, copy # https://docs.python.org/ja/3/library/copy.html
    import operator
    from operator import itemgetter #sort 
    # ex1: List.sort(key=itemgetter(1))
    # ex2: sorted(tuples, key=itemgetter(1,2))
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd # Deprecated since version 3.5: Use math.gcd() instead.
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    # first create factorial_list
    # fac_list = mod_factorial_list(n)
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz') # 26
    modpow = lambda a, n, p = MOD: pow(a, n, p) # Recursive function in python is slow!
    def modinv(a, p = MOD):
        # evaluate reciprocal using Fermat's little theorem:
        # a**(p-1) is identical to 1 (mod p) when a and p is coprime
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        # fac_list = modfactorial_list(100)
        # print(modcomb(100, 5, modfactorial_list(100)))
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    class SegTree:
        """
        ref: https://qiita.com/takayg1/items/c811bd07c21923d7ec69
        init(init_val, ide_ele): 配列init_valで初期化 O(N)
        update(k, x): k番目の値をxに更新 O(logN)
        query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
        """
        def __init__(self, init_val, segfunc, ide_ele):
            """
            init_val: 配列の初期値
            segfunc: 区間にしたい操作
            ide_ele: 単位元
            n: 要素数
            num: n以上の最小の2のべき乗
            tree: セグメント木(1-index)
            """
            n = len(init_val)
            self.segfunc = segfunc
            self.ide_ele = ide_ele
            self.num = 1 << (n - 1).bit_length()
            self.tree = [ide_ele] * 2 * self.num
            # 配列の値を葉にセット
            for i in range(n):
                self.tree[self.num + i] = init_val[i]
            # 構築していく
            for i in range(self.num - 1, 0, -1):
                self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])

        def update(self, k, x):
            """
            k番目の値をxに更新
            k: index(0-index)
            x: update value
            """
            k += self.num
            self.tree[k] = x
            while k > 1:
                self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
                k >>= 1

        def query(self, l, r):
            """
            [l, r)のsegfuncしたものを得る
            l: index(0-index)
            r: index(0-index)
            """
            res = self.ide_ele
            l += self.num
            r += self.num
            while l < r:
                if l & 1:
                    res = self.segfunc(res, self.tree[l])
                    l += 1
                if r & 1:
                    res = self.segfunc(res, self.tree[r - 1])
                l >>= 1
                r >>= 1
            return res

    # ************ Graph ************
    # Graph: https://en.wikipedia.org/wiki/Directed_graph
    # 最短経路問題: https://ja.wikipedia.org/wiki/%E6%9C%80%E7%9F%AD%E7%B5%8C%E8%B7%AF%E5%95%8F%E9%A1%8C
    
    # Bellman-Ford: O(|V||E|). Use this if there exists an edge with negative length in the graph
    # After N steps, the shortest path has converded if there doesn't exist an cycle of edges with negative
    # Watch out: d[N] == d[2*N] doesn't necessarily mean the graph doesn't have negative cycle
    # ref: https://www.youtube.com/watch?v=1Z6ofKN03_Y

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    # Warshall Floyd O(V**3)
    def warshall_floyd(number_vertex, XYD, shift_one_for_vertex=False):
        # ref: https://juppy.hatenablog.com/entry/2018/11/01/%E8%9F%BB%E6%9C%AC_python_%E5%85%A8%E7%82%B9%E5%AF%BE%E6%9C%80%E7%9F%AD%E7%B5%8C%E8%B7%AF%E6%B3%95%EF%BC%88%E3%83%AF%E3%83%BC%E3%82%B7%E3%83%A3%E3%83%AB%E3%83%95%E3%83%AD%E3%82%A4%E3%83%89%E6%B3%95
        # number_vertex: len(vertex)
        # XYD: list of distance from x to y
        # shift_one_for_vertex: XYDの値が1~Nの時(0~N-1でない時)に調整するフラグ。
        # d[i][j]: iからjへの最短距離
        d = [[float("inf")]*number_vertex for i in range(number_vertex)]
        for x, y, dist in XYD:
            if shift_one_for_vertex:
                x = x - 1
                y = y - 1
            d[x][y] = dist
            d[y][x] = dist
        for i in range(number_vertex):
            d[i][i] = 0 # distance of same vertex is 0
        for k in range(number_vertex):
            for i in range(number_vertex):
                for j in range(number_vertex):
                    d[i][j] = min(d[i][j],d[i][k] + d[k][j])
        return d


    """ initialize variables and set inputs
    # initialize variables
        # to initialize list, use [0] * n
        # to initialize two dimentional array:
            # ex) [[0] * N for _ in range(N)]
            # ex2) dp = [[0] * (N+1) for _ in range(W*2)]
    # set inputs
        # put inputs between specific values (almost as quickly)
        # ex) S = [-INF] + [int(r()) for _ in range(A)] + [INF]
        # open(0).read() is sometimes useful:
        # ex) n, m, *x = map(int, open(0).read().split())
        #     min(x[::2]) - max(x[1::2])
        # ex2) *x, = map(int, open(0).read().split())
        #     don't forget to add comma after *x if only one variable is used
    # preprocessing
        # transpose = [x for x in zip(*data)]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
        # flat = [flatten for inner in data for flatten in inner]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [1, 2, 3, 4, 5, 6, 7, 8, 9]
    # calculate and output
        # output pattern
        # ex1) print(*l) => when l = [2, 5, 6], printed 2 5 6
    """

    # functions to read input
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    # single int: int(r())
    # single string: r()
    # single float: float(r())
    # line int: R()
    # line string: r().split()
    # line (str, int, int): [j if i == 0 else int(j) for i, j in enumerate(r().split())]
    # lines int: [R() for _ in range(n)]
    """

    # for test
    if sample_file:
        sys.stdin = open(sample_file)
        
    # ----------------------------------
    # main
    #%%
    A, B, C, K = R()
    if K <= A:
        print(K)
    elif K <= A + B:
        print(A)
    else:
        print(A-(K-A-B))

        
    
    
    # 小文字をカウントしたリストを持つセグ木で行けそう。

    
    # a = [14, 5, 9, 13, 7, 12, 11, 1, 7, 8]
    


    #%%
    # end of main
    # ----------------------------------

    """memo: how to use defaultdict of list
    # initialize
    Dic = defaultdict(list)
    # append / extend
    Dic[x].append(y)
    # three methods for loop: keys(), values(), items()
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    # to make binary digits text
    >>> a = 5
    >>> bin_str_a = format(a, '#06b')
    >>> print(bin_str_a)
    0b0101 # first 2 strings (='0b') indicates it is binary
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
a, b, c, k = map(int, input().split())

ia = min(max(0, k), a)
ib = min(max(0, k - ia), b)
ic = min(max(0, k - ia - ib), c)


answer = ia * 1 + ib * 0 + ic * (-1)
print(answer)

Submission status: Accepted

Solution code:
a, b, c, k = map(int, input().split())
if a >= k:
    print(k)
elif a + b >= k:
    print(a)
else:
    print(a - (k-a-b))

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

n_A = min(K, A)
K -= n_A

n_B = min(K, B)
K -= n_B

n_C = min(K, C)
K -= n_C

print(n_A - n_C)

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

if A >= K:
  print(K)
else:
  if B >= K - A:
    print(A)
  else:
    print(A - (K - A - B))

Submission status: Accepted

Solution code:
a,b,c,k=map(int,input().split( ))
g=0
if a>=k:
    print(k)
else:
    g+=a
    k-=a
    if b>=k:
        print(g)
    else:
        k-=b
        if c>=k:
            g-=k
            print(g)

Submission status: Accepted

Solution code:
# coding: utf-8
A,B,C,K=map(int,input().split())

if A>=K:
    ans=K
elif A+B>=K:
    ans=A
else:
    ans=A-(K-(A+B))
        
print(ans)

Submission status: Accepted

Solution code:
import sys
from collections import Counter
from collections import deque
def input(): return sys.stdin.readline().strip()
def mp(): return map(int,input().split())
def lmp(): return list(map(int,input().split()))

a,b,c,k=mp()
if k<=a:
    print(k)
elif k<=a+b:
    print(a)
else:
    print(2*a-k+b)

Submission status: Accepted

Solution code:
# Template 1.0
import sys, re
from collections import deque, defaultdict, Counter, OrderedDict
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians, log
from heapq import heappush, heappop, heapify, nlargest, nsmallest
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
def list2d(a, b, c): return [[c] * b for i in range(a)]
def sortListWithIndex(listOfTuples, idx):   return (sorted(listOfTuples, key=lambda x: x[idx]))
def sortDictWithVal(passedDic):
    temp = sorted(passedDic.items(), key=lambda kv: (kv[1], kv[0]))
    toret = {}
    for tup in temp:
        toret[tup[0]] = tup[1]
    return toret
def sortDictWithKey(passedDic):
    return dict(OrderedDict(sorted(passedDic.items())))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10 ** 9 + 7

a,b,c,k = MAP()

if(k<=a):
    print(k)
else:
    temp = k-a
    if(temp<=b):
        print(a)
    else:
        print(a-(k-a-b))

Submission status: Accepted

Solution code:
def read_int():
    return int(input())

def read_int_map():
    return map(int,input().split(' '))

def read_int_list():
    return list(map(int,input().split(' ')))

def read_s_list_loop(n):
    return [input() for _ in range(n)]

A,B,C,K = read_int_map()
if K <= A:
    print(K)
elif K <= A + B:
    print(A)
else:
    minus = K - (A+B)
    print(A - minus)

Submission status: Accepted

Solution code:
#!/usr/bin/env python3
import sys

def main():
    A, B, C, K = map(int, input().split())
    if K <= A+B:
        print(min(K,A))
    else:
        print(A-(K-A-B))

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
A,B,C,K=map(int,input().split())
a=0
if K>A:
    K-=A
    a+=A
else:
    a=K
    K=0
if K>B:
    K-=B
else:
    K=0
a-=K
print(a)

Submission status: Accepted

Solution code:
a, b, c, k = list(map(int, input().split(' ')))

if a + b >= k:
    print(min(a, k))
else:
    print(a - (k - a - b))

Submission status: Accepted

Solution code:
a,b,c,k=map(int,input().split())
if a>=k:
	print(k)
elif a+b>=k:
	print(a)
else:
	k-=(a+b)
	print(a-k)

Submission status: Accepted

Solution code:
A,B,C,K = map(int, input().split())

if A >= K:
    print(K)
elif A + B >= K:
    print(A)
else:
    print(A - (K - (A+B)))

Submission status: Accepted

Solution code:
A,B,C,K=map(int,input().split())

if A>=K:
  print(K)
elif A+B>=K:
  print(A)
else:
  CC=K-A-B
  print(A-CC)

Submission status: Accepted

Solution code:
a, b, c, k = map(int, input().split())

if k <= a:
    print(k)
elif a < k and k <= a+b:
    print(a)
elif a+b < k:
    minus = k - (a+b)
    print(a-minus)

Submission status: Accepted

Solution code:
a,b,c,k = map(int, input().split())
if (a>=k):
    print(k)
elif (a+b>=k):
    print(a)
elif (a+b+c>=k):
    print(a-(k-a-b))

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

ans = min(A, K) - max(K - A - B, 0)
print(ans)

Submission status: Accepted

Solution code:
a,b,c,k=map(int,input().split())
ans=0
if a>=k:
  ans=k
elif a+b>=k:
  ans=a
else:
  ans=a-(k-a-b)
print(ans)

Submission status: Accepted

Solution code:
import sys
sys.setrecursionlimit(10 ** 6)  # 再帰関数の再帰の深さを設定
to_index = lambda x: int(x) - 1  # 入力した数字に1を引いたものを返す
print_list_in_2D = lambda x: print(*x, sep="\n")  # リストの要素を改行を挟んで表示する関数

# 入力を整数に変換して受け取る
def input_int():
    return int(input())

def map_int_input():
    return map(int, input())

MII = map_int_input

def MII_split():
    return map(int, input().split())

def MII_to_index():
    return map(to_index, input())

def MII_split_to_index():
    return map(to_index, input().split())

# 入力全てを整数に変換したものの配列を受け取る
def list_int_inputs():
    return list(map(int, input()))

LII = list_int_inputs

def LII_split():
    return list(map(int, input().split()))

# 2次元リスト化
def LII_2D(rows_number):
    return [LII() for _ in range(rows_number)]

def LII_split_2D(rows_number):
    return [LII_split() for _ in range(rows_number)]

A, B, C, K = MII_split()

if K <= A:
    print(K)
elif K <= A + B:
    print(A)
else:
    c = K - A - B
    print(A - c)

Submission status: Accepted

Solution code:
a, b, c, k = map(int, input().split())
if k <= a:
    print(k)
elif k <= a + b:
    print(a)
else:
    print(a - (k - a - b))

Submission status: Accepted

Solution code:
#map(int,input().split())
a,b,c,k=map(int,input().split())
#aは1
#bは0
#cは-1
if k<=a:
	print(k)
elif k<=a+b:
	print(a)
else:
	print(a-(k-a-b))

Submission status: Accepted

Solution code:
A, B, C, D = list(map(int, input().split()))

ones = min(A, D)

A -= ones
D -= ones

zeros = min(B, D)

B -= zeros
D -= zeros

C = min(C, D)

print(ones - C)

Submission status: Accepted

Solution code:
a,b,c,k = list(map(int, input().split()))

if k <= a:
    print(k)
elif k <= (a +b):
    print(a)
else:
    print(a - (k -a-b))

Submission status: Accepted

Solution code:


import sys

sys.setrecursionlimit(10 ** 7)

# ----------

INF = float("inf")
MOD = 10 ** 9 + 7
# ----------

A, B, C, K = map(int, input().split())

ans = 0
ans += min(K, A)
K -= min(K, A)
if K > 0:
    K -= min(K, B)
if K > 0:
    ans -= min(K, C)

print(ans)

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())
if K <= A:
    print(K)
elif K <= A + B:
    print(A)
else:
    excess = K - A - B
    print(A - excess)

Submission status: Accepted

Solution code:
a,b,c,k = map(int,input().split())
if k <= a:
  print(k)
elif a < k <= a + b:
  print(a)
else:
  k -= a + b
  print(a-k)

Submission status: Accepted

Solution code:
a,b,c,k = map(int,input().split())
ans = min(a,k)
if ans<k:
	k-=ans
	k -= b
	if k>0:
		ans-=min(c,k)
print(ans)

Submission status: Accepted

Solution code:
a,b,c,k = map(int,input().split())


if k<=a:
    print(k)
elif k<=a+b:
    print(a)
else:
    print(a-(k-a-b) )

Submission status: Accepted

Solution code:
#!/usr/bin/env python3
import sys


def solve(A: int, B: int, C: int, K: int):

    a = K - A
    if a <= 0:
        print(K)
        return
    b = a - B
    if b <= 0:
        print(A)
        return
    c = b - C
    print(A-b)

    return


# Generated by 1.1.6 https://github.com/kyuridenamida/atcoder-tools  (tips: You use the default template now. You can remove this line by using your custom template)
def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    A = int(next(tokens))  # type: int
    B = int(next(tokens))  # type: int
    C = int(next(tokens))  # type: int
    K = int(next(tokens))  # type: int
    solve(A, B, C, K)

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

ans = 0
if A < K:
    ans += A
    K -= A
else:
    ans += K
    print (ans)
    exit()

if B < K:
    K -= B
else:
    print (ans)
    exit()

print (ans - K)

Submission status: Accepted

Solution code:
a,b,c,k = map(int, input().split())
if k <= a+b:
  print(min(a,k))
else:
  minus = k-a-b
  print(a-minus)

Submission status: Accepted

Solution code:
a,b,c,k = map(int, input().split())
if k <= a:
    print(k)
elif k <= a+b:
    print(a)
else:
    print((k-(a+b))*-1 + a)

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

if K <= A:
  print(K)
elif K <= A + B:
  print(A)
else:
  print(2*A + B - K)

Submission status: Accepted

Solution code:
import sys

readline = sys.stdin.readline
MOD = 10 ** 9 + 7
INF = float('INF')
sys.setrecursionlimit(10 ** 5)


def main():
    a, b, c, k = list(map(int, readline().split()))
    if a + b >= k:
        print(min(a, k))
    else:
        print(a - (k - a - b))


if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
def main():
    a, b, c, d = map(int, input().split())
    ans = 0
    if a < d:
        ans += a
        d -= a
    else:
        ans += d
        d = 0
    if b < d:
        d -= b
    else:
        d = 0
    if c < d:
        ans -= a
        d -= c
    else:
        ans -= d
        d = 0
    print(ans)


main()

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

ans = 0
d = min(A, K)
#print('d:', d)
ans += d
K -= d
d = min(B, K)
#print('d:', d)
ans += 0
K -= d
d = min(C, K)
#print('d:', d)
ans -= d
K -= d

print(ans)

Submission status: Accepted

Solution code:
a,b,c,k=list(map(int,input().split(" ")))
ans=0
if(k>0):
	ans+=min(a,k)
	k-=min(a,k)
if(k>0):
	# ans+=min(b,k)
	k-=min(b,k)
if(k>0):
	ans-=min(c,k)
	k-=min(c,k)
print(ans)

Submission status: Accepted

Solution code:
def solve(A, B, C, K):
    count = 0
    a = min(A, K)
    count += a
    K -= a
    b = min(B, K)
    K -= b
    c = min(C, K)
    count -= c
    K -= a
    return count

if __name__ == "__main__":
    A, B, C, K = tuple(map(int, input().split(" ")))

    print(solve(A, B, C, K))

Submission status: Accepted

Solution code:
import sys

def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10 ** 9)
INF = 10 ** 18
MOD = 10 ** 9 + 7

a, b, c, K = MAP()

if a >= K:
    print(K)
    exit()
K -= a
ans = a
if b >= K:
    print(ans)
    exit()
K -= b
ans -= K
print(ans)

Submission status: Accepted

Solution code:
a,b,c,k = map(int,input().split())
if a >= k:
    print(k)
elif a + b >= k:
    print(a)
else:
    print(a - (k - a - b))

Submission status: Accepted

Solution code:
A, B, C, K = map(int, input().split())

if K <= A:
    print(K)
elif A < K <= A + B:
    print(A)
else:
    print(A - (K - A - B))

Submission status: Accepted

Solution code:
a, b, c, k = list(map(int, input().split()))

ans = 0
ans += 1 * min(k, a)

if a+b < k:
    ans += (-1) * (k-a-b)
print(ans)