Problem:


Score: 100 points

Problem Statement

Takahashi the Jumbo will practice golf.

His objective is to get a carry distance that is a multiple of K, while he can only make a carry distance of between A and B (inclusive).

If he can achieve the objective, print OK; if he cannot, print NG.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 1000

1 \leq K \leq 1000

Input

Input is given from Standard Input in the following format:

K
A B

Output

If he can achieve the objective, print OK; if he cannot, print NG.

Sample Input 1

7
500 600

Sample Output 1

OK

Among the multiples of 7, for example, 567 lies between 500 and 600.

Sample Input 2

4
5 7

Sample Output 2

NG

No multiple of 4 lies between 5 and 7.

Sample Input 3

1
11 11

Sample Output 3

OK



Sample input:
7
500 600


Sample output:
OK

Submission status: Accepted

Solution code:
def main(sample_file = ''):

    """ convenient functions
    # for i, a in enumerate(iterable)
    # q, mod = divmod(a, b)
    # divmod(x, y) returns the tuple (x//y, x%y)
    # Higher-order function: reduce(operator.mul, xyz_count, 1)
    # manage median(s) using two heapq https://atcoder.jp/contests/abc127/tasks/abc127_f
    """

    """convenient decorator
    # @functools.lru_cache():
    # to facilitate use of recursive function
        # ex:
        # from functools import lru_cache
        # import sys
        # sys.setrecursionlimit(10**9)
        # @lru_cache(maxsize=None)
        # def fib(n):
        #     if n < 2:
        #         return n
        #     return fib(n-1) + fib(n-2)
        # print(fib(1000))
    """
    
    # import numpy as np
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product # https://docs.python.org/ja/3/library/itertools.html
    # accumulate() returns iterator! to get list: list(accumulate())
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  # prime factor
        b, e = 2, 0  # base, exponent
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        # TODO: How should I do when n - r is negative?
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict # https://docs.python.org/ja/3/library/collections.html#collections.deque
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest # https://docs.python.org/ja/3/library/heapq.html
    from copy import deepcopy, copy # https://docs.python.org/ja/3/library/copy.html
    import operator
    from operator import itemgetter #sort 
    # ex1: List.sort(key=itemgetter(1))
    # ex2: sorted(tuples, key=itemgetter(1,2))
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd # Deprecated since version 3.5: Use math.gcd() instead.
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    # first create factorial_list
    # fac_list = mod_factorial_list(n)
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz')
    modpow = lambda a, n, p = MOD: pow(a, n, p) # Recursive function in python is slow!
    def modinv(a, p = MOD):
        # evaluate reciprocal using Fermat's little theorem:
        # a**(p-1) is identical to 1 (mod p) when a and p is coprime
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        # fac_list = modfactorial_list(100)
        # print(modcomb(100, 5, modfactorial_list(100)))
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    # Graph: https://en.wikipedia.org/wiki/Directed_graph
    # Bellman-Ford: O(|V||E|). Use this if there exists an edge with negative length in the graph
    # After N steps, the shortest path has converded if there doesn't exist an cycle of edges with negative
    # Watch out: d[N] == d[2*N] doesn't necessarily mean the graph doesn't have negative cycle
    # ref: https://www.youtube.com/watch?v=1Z6ofKN03_Y

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    """ initialize variables and set inputs
    # initialize variables
        # to initialize list, use [0] * n
        # to initialize two dimentional array:
            # ex) [[0] * N for _ in range(N)]
            # ex2) dp = [[0] * (N+1) for _ in range(W*2)]
    # set inputs
        # put inputs between specific values (almost as quickly)
        # ex) S = [-INF] + [int(r()) for _ in range(A)] + [INF]
        # open(0).read() is sometimes useful:
        # ex) n, m, *x = map(int, open(0).read().split())
        #     min(x[::2]) - max(x[1::2])
        # ex2) *x, = map(int, open(0).read().split())
        #     don't forget to add comma after *x if only one variable is used
    # preprocessing
        # transpose = [x for x in zip(*data)]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
        # flat = [flatten for inner in data for flatten in inner]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [1, 2, 3, 4, 5, 6, 7, 8, 9]
    # calculate and output
        # output pattern
        # ex1) print(*l) => when l = [2, 5, 6], printed 2 5 6
    """

    # functions to read input
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    # single int: int(r())
    # single string: r()
    # single float: float(r())
    # line int: R()
    # line string: r().split()
    # line (str, int, int): [j if i == 0 else int(j) for i, j in enumerate(r().split())]
    # lines int: [R() for _ in range(n)]
    """

    # for test
    if sample_file:
        sys.stdin = open(sample_file)
        
    # ----------------------------------
    # main
    #%%
    K = r_int()
    A, B = R()
    for i in range(A, B+1):
        if i % K == 0:
            print('OK')
            return
    print('NG')
    
    
    #%%
    # end of main
    # ----------------------------------

    """memo: how to use defaultdict of list
    # initialize
    Dic = defaultdict(list)
    # append / extend
    Dic[x].append(y)
    # three methods for loop: keys(), values(), items()
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    # to make binary digits text
    >>> a = 5
    >>> bin_str_a = format(a, '#06b')
    >>> print(bin_str_a)
    0b0101 # first 2 strings (='0b') indicates it is binary
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
K = int(input())
A, B = map(int, input().split())
yes = False
for i in range(A, B + 1):
    if i % K == 0:
        yes = True
        break
if yes:
    print("OK")
else:
    print("NG")

Submission status: Accepted

Solution code:
# -*- coding: utf-8 -*-
import numpy as np
from collections import deque
k = int(input())
a, b = list(map(int, input().split()))
for i in range(a, b + 1):
    if (i % k == 0):
        print('OK')
        exit()
print('NG')

Submission status: Accepted

Solution code:
import sys
# 再起回数上限変更
# sys.setrecursionlimit(1000000)

K=int(input())
A, B = map(int, input().split())


for i in range(A, B+1):
    if i % K == 0:
        print('OK')
        sys.exit()

print('NG')

Submission status: Accepted

Solution code:
k=int(input())
a,b= map(int, input().split())
for i in range(a,b+1):
    if i%k==0:
        print('OK')
        exit()
    
print('NG')

Submission status: Accepted

Solution code:
#!/usr/bin/env python3

import sys

DEBUG = False

def read(t):
    return t(sys.stdin.readline().rstrip())


def read_list(t, sep = " "):
    return [t(s) for s in sys.stdin.readline().rstrip().split(sep)]


def dprint(*args, **kwargs):
    if DEBUG:
        print(*args, **kwargs)
    return


def main():
    k = read(int)
    a, b = read_list(int)
    for i in range(a, b + 1):
        if i % k == 0:
            print("OK")
            return
    print("NG")


if __name__ == "__main__":
    main()

Submission status: Accepted

Solution code:
K = int(input())
A,B = [int(i) for i in input().split(" ")]

for i in range(A,B+1):
    if i % K == 0:
        print("OK")
        break
else:
    print("NG")

Submission status: Accepted

Solution code:
k = int(input())
a, b = map(int, input().split())

for i in range(a,b+1):
    if i%k == 0:
        print('OK')
        exit()
print('NG')

Submission status: Accepted

Solution code:
k = int(input())
a, b = map(int, input().split())

for i in range(a, b+1):
    if(i%k==0):
        print('OK')
        exit()

print('NG')

Submission status: Accepted

Solution code:
k = int(input())
a, b = map(int, input().split())
for i in range(a, b + 1):
  if i % k == 0:
    print('OK')
    break
else:
  print('NG')

Submission status: Accepted

Solution code:
k=int(input())
a,b=map(int,input().split())
f=0
for x in range(a,b+1):
  if x%k==0:
    f=1
if f:
  print("OK")
else:
  print("NG")

Submission status: Accepted

Solution code:
INT = lambda: int(input())
INTM = lambda: map(int,input().split())
STRM = lambda: map(str,input().split())
STR = lambda: str(input())
LIST = lambda: list(map(int,input().split()))
LISTS = lambda: list(map(str,input().split()))
def do(): 
    flg=0
    k=INT()
    a,b=INTM()
    for i in range(a,b+1):
        if i%k==0:
            flg=1
    if flg==0:
        print('NG')
    else:
        print('OK')
if __name__ == '__main__':
    do()

Submission status: Accepted

Solution code:
import sys
k = int(input())
a,b = map(int,input().split())

for i in range(b-a+1):
    if (a + i) % k == 0:
        print('OK')
        sys.exit()





print('NG')

Submission status: Accepted

Solution code:
K = int(input())
A, B = list(map(int, input().split()))

for i in range(A, B + 1):
    if (i % K == 0):
        print("OK")
        exit(0)

print("NG")

Submission status: Accepted

Solution code:
import sys
sys.setrecursionlimit(10**9)
K= int(input())
A,B = map(int,input().split())

for i in range(A,B+1):
    if i%K==0:
        print("OK")
        exit()

print("NG")

Submission status: Accepted

Solution code:
K=int(input())
A,B=map(int,input().split())
import sys

for i in range(A,B+1):
    if i%K==0:
        print("OK")
        sys.exit()
print("NG")

Submission status: Accepted

Solution code:
import bisect
import collections
import sys

sys.setrecursionlimit(100000)
input = sys.stdin.readline
ACMOD = 1000000007
INF = 1 << 62


def lmi():
    return list(map(int, input().split()))


def llmi(n):
    return [lmi() for _ in range(n)]


K = int(input())
A, B = lmi()
for i in range(1001):
    if A <= K * i and K * i <= B:
        print("OK")
        exit()
print("NG")

Submission status: Accepted

Solution code:
k = int(input())
a,b = map(int,input().split())
for i in range(a,b+1):
    if i%k == 0:
        print('OK')
        break
else:print('NG')

Submission status: Accepted

Solution code:
import sys
input=sys.stdin.readline
sys.setrecursionlimit(10 ** 6)
#from collections import defaultdict
#d = defaultdict(int)
#import fractions
#import math
#import collections
#from collections import deque
#from bisect import bisect_left
#from bisect import insort_left
#N = int(input())
#A = list(map(int,input().split()))
#S = list(input())
#S.remove("\n")
#N,M = map(int,input().split())
#S,T = map(str,input().split())
#A = [int(input()) for _ in range(N)]
#S = [input() for _ in range(N)]
#A = [list(map(int,input().split())) for _ in range(N)]
#import itertools
#import heapq
#import numpy as np
K = int(input())
A,B = map(int,input().split())
c = 0
for i in range(A,B+1):
    if i % K == 0:
        c = 1
        break
if c == 1:
    print("OK")
else:
    print("NG")

Submission status: Accepted

Solution code:
k = int(input())
#n, m = list(map(int, input().split()))
a, b = list(map(int, input().split()))
# sy, sx = map(int, input().split())
# gy, gx = map(int, input().split())
for i in range(a, b+1):
    if i % k == 0:
        print("OK")
        exit()

print("NG")

Submission status: Accepted

Solution code:
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**7)
INF = 10**10
MOD = 10**9 + 7
k = int(input())
a, b = map(int,input().split())
for i in range(a,b+1):
    if i%k==0:
        print ('OK')
        exit()
print ('NG')

Submission status: Accepted

Solution code:
import sys
int1 = lambda x: int(x) - 1
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(500000)

K = int(readline())
A, B = map(int, readline().split())

ans = "NG"
for i in range(A, B + 1):
    if i % K == 0:
        ans = "OK"

print(ans)

Submission status: Accepted

Solution code:
import sys

K = int(input())
A, B = map(int, input().split())

for i in range(A, B+1):
    if i % K == 0:
        print('OK')
        sys.exit()

print('NG')

Submission status: Accepted

Solution code:
k = int(input())
a,b = map(int, input().split(' '))

for i in range(a,b+1):
    if i % k ==0:
        print('OK')
        break
else:
    print('NG')

Submission status: Accepted

Solution code:
import numpy as np
import sys
import math
read = sys.stdin.readline

k = int(input())
a , b = map(int,input().split())

for x in range(a,b+1):
    if x % k == 0:
        print("OK")
        sys.exit()

print("NG")

Submission status: Accepted

Solution code:
f=0
k=int(input())
a,b=map(int,input().split())
for i in range(a,b+1):
	if i%k==0:
		f=1
		break
print("OK" if f else "NG")

Submission status: Accepted

Solution code:
K = int(input())
A, B = map(int, input().split())
for i in range(A, B + 1):
    if i % K == 0:
        ans = 'OK'
        break
else:
    ans = 'NG'
print(ans)

Submission status: Accepted

Solution code:
import sys
import math
from collections import deque
import heapq
MAX_INT = int(10e10)
MIN_INT = -MAX_INT
mod = 1000000007
sys.setrecursionlimit(1000000)
def IL(): return list(map(int,input().split()))
def SL(): return input().split()
def I(): return int(sys.stdin.readline())
def S(): return input()

K = I()
a,b = IL()

for i in range(a,b+1):
  if i%K == 0:
    print("OK")
    exit()
print("NG")

Submission status: Accepted

Solution code:
k = int(input())
a, b = tuple(map(int, input().split()))

for i in range(a, b+1):
    if i % k == 0:
        print('OK')
        exit()

print('NG')

Submission status: Accepted

Solution code:
#!/usr/bin/env python3
import sys
input = sys.stdin.readline

k = int(input())
a, b = map(int, input().split())
ok = False
for i in range(1, 1001):
    if a <= k * i <= b:
        ok = True
if ok:
    print("OK")
else:
    print("NG")

Submission status: Accepted

Solution code:
#
# 　　  ⋀_⋀　 
#　　  (･ω･)  
# .／ Ｕ ∽ Ｕ＼
#  │＊　合　＊│
#  │＊　格　＊│ 
#  │＊　祈　＊│ 
#  │＊　願　＊│ 
#  │＊　　　＊│ 
#      ￣
#
import sys
sys.setrecursionlimit(10**6)
input=sys.stdin.readline
from math import floor,sqrt,factorial,hypot,log #log2ないｙｐ
from heapq import heappop, heappush, heappushpop
from collections import Counter,defaultdict,deque
from itertools import accumulate,permutations,combinations,product,combinations_with_replacement
from bisect import bisect_left,bisect_right
from copy import deepcopy
from fractions import gcd
from random import randint
def ceil(a,b): return (a+b-1)//b
inf=float('inf')
mod = 10**9+7
def pprint(*A): 
    for a in A:     print(*a,sep='\n')
def INT_(n): return int(n)-1
def MI(): return map(int,input().split())
def MF(): return map(float, input().split())
def MI_(): return map(INT_,input().split())
def LI(): return list(MI())
def LI_(): return [int(x) - 1 for x in input().split()]
def LF(): return list(MF())
def LIN(n:int): return [I() for _ in range(n)]
def LLIN(n: int): return [LI() for _ in range(n)]
def LLIN_(n: int): return [LI_() for _ in range(n)]
def LLI(): return [list(map(int, l.split() )) for l in input()]
def I(): return int(input())
def F(): return float(input())
def ST(): return input().replace('\n', '')
def main():
    K=I()
    A,B=MI()
    if(A%K==0 or A//K!=B//K or B%K==0):
        print("OK")
    else:
        print("NG")
if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
k = int(input())
a, b = map(int, input().split())
for i in range(a, b + 1):
    if i % k == 0:
        print('OK')
        break
else:
    print('NG')

Submission status: Accepted

Solution code:
K = int(input())
A, B = map(int, input().split())

num1 = (A-1)//K
num2 = B//K

if num1 != num2:
    print('OK')
else:
    print('NG')

Submission status: Accepted

Solution code:
k=int(input())
a,b=map(int,input().split())

f=0
for i in range(a,b+1):
    if i%k==0:
        f=1
if f==1:
    print("OK")
else:
    print("NG")

Submission status: Accepted

Solution code:
# -*- coding: utf-8 -*-
import bisect
import heapq
import math
import random
import sys
from collections import Counter, defaultdict, deque
from decimal import ROUND_CEILING, ROUND_HALF_UP, Decimal
from functools import lru_cache, reduce
from itertools import combinations, combinations_with_replacement, product, permutations
from operator import add, mul, sub

# sys.setrecursionlimit(100000)
input = sys.stdin.buffer.readline
INF = 2**62-1

def read_int():
    return int(input())


def read_int_n():
    return list(map(int, input().split()))


def read_float():
    return float(input())


def read_float_n():
    return list(map(float, input().split()))


def read_str():
    return input().strip()


def read_str_n():
    return list(map(str, input().split()))


def error_print(*args):
    print(*args, file=sys.stderr)


def mt(f):
    import time

    def wrap(*args, **kwargs):
        s = time.time()
        ret = f(*args, **kwargs)
        e = time.time()

        error_print(e - s, 'sec')
        return ret

    return wrap


@mt
def slv(K, A, B):
    ans = 0
    for i in range(100000):
        if A <= i*K <= B:
            return 'OK'
        if i * K > B:
            break
    return 'NG'


def main():
    K = read_int()
    A, B = read_int_n()
    print(slv(K, A, B))


if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
K = int(input())
A, B = map(int, input().split())
for i in range(A, B+1):
  if i % K == 0:
    print("OK")
    break
else:
  print("NG")

Submission status: Accepted

Solution code:
#!/usr/bin/env python3
#%% for atcoder uniittest use
import sys
input= lambda: sys.stdin.readline().rstrip()
def pin(type=int):return map(type,input().split())
def tupin(t=int):return tuple(pin(t))
#%%code
def resolve():
    K,=pin()
    A,B=pin()
    for i in range(A,B+1):
        if i%K==0:
            print("OK")
            return
    print("NG")
#%%submit!
resolve()

Submission status: Accepted

Solution code:
k = int(input())
a,b = map(int, input().split())
flag = False
for i in range(a, b+1):
    if i % k == 0:
        flag = True
print("OK" if flag else "NG")

Submission status: Accepted

Solution code:
import sys
from math import ceil, floor, sqrt, sin, cos, pi
from itertools import accumulate, permutations, combinations
from fractions import gcd # 最大公約数
from collections import deque, Counter
from operator import itemgetter
from heapq import heappop,heappush
sys.setrecursionlimit(10**7)
def lcm(x, y): return ((x * y) // gcd(x, y)) # 最小公倍数
# list(map(int, input().split()))
k = int(input())
a, b = map(int, input().split())

for i in range(a, b+1):
    if i%k == 0:
        print('OK')
        sys.exit()
print('NG')

Submission status: Accepted

Solution code:
def LI():return list(map(int,input().split()))

# for i in range(10):
#     print(i&1^0)

k=int(input())
a,b=LI()

for i in range(2000):
    if a<=k*i<=b:
        print("OK")
        exit()
print("NG")

Submission status: Accepted

Solution code:
k = int(input())
a, b = map(int, input().split())

for num in range(a, b+1):
    if num % k == 0:
        print('OK')
        exit()

print('NG')

Submission status: Accepted

Solution code:
K=int(input())
A,B=map(int,input().split())

ans="NG"
for i in range(A,B+1):
    if i%K==0:
        ans="OK"
        break
print(ans)

Submission status: Accepted

Solution code:
k = int(input())
a,b = map(int,input().split())
flag = False
for i in range(a,b+1):
    if i%k == 0:
        flag = True
if flag:
    print('OK')
else:
    print('NG')

Submission status: Accepted

Solution code:
k = int(input())
a, b = [int(i) for i in input().split(' ')]
for i in range(a, b + 1):
    if i % k == 0:
        print('OK')
        break
else:
    print('NG')

Submission status: Accepted

Solution code:
K = int(input())
A, B = map(int, input().split())


for i in range(A, B + 1):
    if i % K == 0:
        print('OK')
        exit()

print('NG')

Submission status: Accepted

Solution code:
K=int(input())
A,B=map(int,input().split())
a=False
for i in range(A,B+1):
    if i%K==0:
        a=True
print("OK" if a else 'NG')

Submission status: Accepted

Solution code:
k = int(input())
a, b = map(int, input().split())
ans = "NG"
for i in range(a, b+1):
    if i % k == 0:
        ans = "OK"
print(ans)

Submission status: Accepted

Solution code:
n = int(input())
a,b = map(int,input().split())
ans="NG"
for i in range(a,b+1):
    if i % n == 0:
        ans = "OK"
print(ans)

Submission status: Accepted

Solution code:
ii = lambda : int(input())
mi = lambda : map(int,input().split())
li = lambda : list(map(int,input().split()))

k = ii()
a,b = mi()

flag = 0
for i in range(a,b+1):
    if i % k == 0:
        flag = 1
if flag:
    print("OK")
else:
    print("NG")

Submission status: Accepted

Solution code:
import sys

K = int(input())
A,B = map(int, input().split())

for i in range(A,B+1,1):
    if i%K==0:
        print("OK")
        sys.exit()
print("NG")

Submission status: Accepted

Solution code:
import sys

k = int(input())
a,b = map(int,input().split())

for i in range(a,b+1):
    if i % k == 0:
        print('OK')
        sys.exit()

print('NG')