Problem:


Score: 400 points

Problem Statement

The Kingdom of Takahashi has N towns, numbered 1 through N.

There is one teleporter in each town. The teleporter in Town i (1 \leq i \leq N) sends you to Town A_i.

Takahashi, the king, loves the positive integer K. The selfish king wonders what town he will be in if he starts at Town 1 and uses a teleporter exactly K times from there.

Help the king by writing a program that answers this question.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

1 \leq K \leq 10^{18}

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \dots A_N

Output

Print the integer representing the town the king will be in if he starts at Town 1 and uses a teleporter exactly K times from there.

Sample Input 1

4 5
3 2 4 1

Sample Output 1

4

If we start at Town 1 and use the teleporter 5 times, our travel will be as follows: 1 \to 3 \to 4 \to 1 \to 3 \to 4.

Sample Input 2

6 727202214173249351
6 5 2 5 3 2

Sample Output 2

2



Sample input:
4 5
3 2 4 1


Sample output:
4

Submission status: Wrong Answer

Solution code:
def main(sample_file = ''):

    """ convenient functions
    # for i, a in enumerate(iterable)
    # q, mod = divmod(a, b)
    # divmod(x, y) returns the tuple (x//y, x%y)
    # Higher-order function: reduce(operator.mul, xyz_count, 1)
    # manage median(s) using two heapq https://atcoder.jp/contests/abc127/tasks/abc127_f
    """

    """convenient decorator
    # @functools.lru_cache():
    # to facilitate use of recursive function
        # ex:
        # from functools import lru_cache
        # import sys
        # sys.setrecursionlimit(10**9)
        # @lru_cache(maxsize=None)
        # def fib(n):
        #     if n < 2:
        #         return n
        #     return fib(n-1) + fib(n-2)
        # print(fib(1000))
    """
    
    # import numpy as np
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product # https://docs.python.org/ja/3/library/itertools.html
    # accumulate() returns iterator! to get list: list(accumulate())
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  # prime factor
        b, e = 2, 0  # base, exponent
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        # TODO: How should I do when n - r is negative?
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict # https://docs.python.org/ja/3/library/collections.html#collections.deque
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest # https://docs.python.org/ja/3/library/heapq.html
    from copy import deepcopy, copy # https://docs.python.org/ja/3/library/copy.html
    import operator
    from operator import itemgetter #sort 
    # ex1: List.sort(key=itemgetter(1))
    # ex2: sorted(tuples, key=itemgetter(1,2))
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd # Deprecated since version 3.5: Use math.gcd() instead.
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    # first create factorial_list
    # fac_list = mod_factorial_list(n)
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz') # 26
    modpow = lambda a, n, p = MOD: pow(a, n, p) # Recursive function in python is slow!
    def modinv(a, p = MOD):
        # evaluate reciprocal using Fermat's little theorem:
        # a**(p-1) is identical to 1 (mod p) when a and p is coprime
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        # fac_list = modfactorial_list(100)
        # print(modcomb(100, 5, modfactorial_list(100)))
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    class SegTree:
        """
        ref: https://qiita.com/takayg1/items/c811bd07c21923d7ec69
        init(init_val, ide_ele): 配列init_valで初期化 O(N)
        update(k, x): k番目の値をxに更新 O(logN)
        query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
        """
        def __init__(self, init_val, segfunc, ide_ele):
            """
            init_val: 配列の初期値
            segfunc: 区間にしたい操作
            ide_ele: 単位元
            n: 要素数
            num: n以上の最小の2のべき乗
            tree: セグメント木(1-index)
            """
            n = len(init_val)
            self.segfunc = segfunc
            self.ide_ele = ide_ele
            self.num = 1 << (n - 1).bit_length()
            self.tree = [ide_ele] * 2 * self.num
            # 配列の値を葉にセット
            for i in range(n):
                self.tree[self.num + i] = init_val[i]
            # 構築していく
            for i in range(self.num - 1, 0, -1):
                self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])

        def update(self, k, x):
            """
            k番目の値をxに更新
            k: index(0-index)
            x: update value
            """
            k += self.num
            self.tree[k] = x
            while k > 1:
                self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
                k >>= 1

        def query(self, l, r):
            """
            [l, r)のsegfuncしたものを得る
            l: index(0-index)
            r: index(0-index)
            """
            res = self.ide_ele
            l += self.num
            r += self.num
            while l < r:
                if l & 1:
                    res = self.segfunc(res, self.tree[l])
                    l += 1
                if r & 1:
                    res = self.segfunc(res, self.tree[r - 1])
                l >>= 1
                r >>= 1
            return res

    # ************ Graph ************
    # Graph: https://en.wikipedia.org/wiki/Directed_graph
    # 最短経路問題: https://ja.wikipedia.org/wiki/%E6%9C%80%E7%9F%AD%E7%B5%8C%E8%B7%AF%E5%95%8F%E9%A1%8C
    
    # Bellman-Ford: O(|V||E|). Use this if there exists an edge with negative length in the graph
    # After N steps, the shortest path has converded if there doesn't exist an cycle of edges with negative
    # Watch out: d[N] == d[2*N] doesn't necessarily mean the graph doesn't have negative cycle
    # ref: https://www.youtube.com/watch?v=1Z6ofKN03_Y

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    # Warshall Floyd O(V**3)
    def warshall_floyd(number_vertex, XYD, shift_one_for_vertex=False):
        # ref: https://juppy.hatenablog.com/entry/2018/11/01/%E8%9F%BB%E6%9C%AC_python_%E5%85%A8%E7%82%B9%E5%AF%BE%E6%9C%80%E7%9F%AD%E7%B5%8C%E8%B7%AF%E6%B3%95%EF%BC%88%E3%83%AF%E3%83%BC%E3%82%B7%E3%83%A3%E3%83%AB%E3%83%95%E3%83%AD%E3%82%A4%E3%83%89%E6%B3%95
        # number_vertex: len(vertex)
        # XYD: list of distance from x to y
        # shift_one_for_vertex: XYDの値が1~Nの時(0~N-1でない時)に調整するフラグ。
        # d[i][j]: iからjへの最短距離
        d = [[float("inf")]*number_vertex for i in range(number_vertex)]
        for x, y, dist in XYD:
            if shift_one_for_vertex:
                x = x - 1
                y = y - 1
            d[x][y] = dist
            d[y][x] = dist
        for i in range(number_vertex):
            d[i][i] = 0 # distance of same vertex is 0
        for k in range(number_vertex):
            for i in range(number_vertex):
                for j in range(number_vertex):
                    d[i][j] = min(d[i][j],d[i][k] + d[k][j])
        return d


    """ initialize variables and set inputs
    # initialize variables
        # to initialize list, use [0] * n
        # to initialize two dimentional array:
            # ex) [[0] * N for _ in range(N)]
            # ex2) dp = [[0] * (N+1) for _ in range(W*2)]
    # set inputs
        # put inputs between specific values (almost as quickly)
        # ex) S = [-INF] + [int(r()) for _ in range(A)] + [INF]
        # open(0).read() is sometimes useful:
        # ex) n, m, *x = map(int, open(0).read().split())
        #     min(x[::2]) - max(x[1::2])
        # ex2) *x, = map(int, open(0).read().split())
        #     don't forget to add comma after *x if only one variable is used
    # preprocessing
        # transpose = [x for x in zip(*data)]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
        # flat = [flatten for inner in data for flatten in inner]
        # ex) [[1, 2, 3], [4, 5, 6], [7, 8, 9]] => [1, 2, 3, 4, 5, 6, 7, 8, 9]
    # calculate and output
        # output pattern
        # ex1) print(*l) => when l = [2, 5, 6], printed 2 5 6
    """

    # functions to read input
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    # single int: int(r())
    # single string: r()
    # single float: float(r())
    # line int: R()
    # line string: r().split()
    # line (str, int, int): [j if i == 0 else int(j) for i, j in enumerate(r().split())]
    # lines int: [R() for _ in range(n)]
    """

    # for test
    if sample_file:
        sys.stdin = open(sample_file)
        
    # ----------------------------------
    # main
    #%%
    N, K = R()
    A = R()
    arrived = [False] * N
    here = 0
    arrived[0] = True
    first_visit = [-1] * N
    visiting = 0
    first_visit[0] = visiting
    while True:
        here = A[here] - 1
        visiting += 1
        if arrived[here]:
            loop_num = visiting - first_visit[here]
            break
        else:
            arrived[here] = True
            first_visit[here] = visiting
    kk = K - first_visit[here] 
    if kk < 0:
        here = 0
        for i in range(K):
            here = A[here]
        print(here)
        return
    kkk = kk % loop_num
    for i in range(kkk):
        here = A[here] - 1
    print(here+1)
    
            
        
        
        

        
    
    
    # 小文字をカウントしたリストを持つセグ木で行けそう。

    
    # a = [14, 5, 9, 13, 7, 12, 11, 1, 7, 8]
    


    #%%
    # end of main
    # ----------------------------------

    """memo: how to use defaultdict of list
    # initialize
    Dic = defaultdict(list)
    # append / extend
    Dic[x].append(y)
    # three methods for loop: keys(), values(), items()
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    # to make binary digits text
    >>> a = 5
    >>> bin_str_a = format(a, '#06b')
    >>> print(bin_str_a)
    0b0101 # first 2 strings (='0b') indicates it is binary
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Submission status: Wrong Answer

Solution code:
n,k=map(int,input().split())
a=list(map(int,input().split()))
t=0
j=0
c=[1]
b={1:1}

for i in range(n):
    j=a[j]-1


    if j+1 in b:

        break
    c.append(j + 1)
    b[j + 1] = 1
m=c.index(a[c[-1]-1])

c=c[m:]

s=(k-m)%(len(c))
print(c[s])

Submission status: Wrong Answer

Solution code:
#!/usr/bin/env python3
from collections import defaultdict
N, K = map(int, input().split())
A = list(map(int, input().split()))

dst = defaultdict(int)

for i, a in enumerate(A, 1):
    dst[i] = a

done = [0] * (N + 1)
done[1] = 1
hist = [1]

now = 1
cnt = 0
while True:
    now = dst[now]
    cnt += 1
    if done[now] == 0:
        done[now] = 1
        hist.append(now)
    else:
        syuki = len(hist) - hist.index(now)
        print(hist[hist.index(now) + (K - cnt) % syuki])
        exit()

Submission status: Wrong Answer

Solution code:
n, k = map(int, input().split())
a = list(map(int, input().split()))

root = [-1] * n
i = 0
j = 0
flag = False
while a[i] not in root:
    root[j] = a[i]
    i = a[i] - 1
    j += 1
    if a[i] == root[0]:
        flag = True
s_i = root.index(a[i])
if k < s_i or flag:
    print(root[(k - 1) % j])
else:
    print(root[(k - s_i) % (j - s_i)])

Submission status: Wrong Answer

Solution code:
N, K = map(int, input().split())
la = list(map(int, input().split()))

lc = [1]
lcnt = [1]
lcnt.extend([0]*(N-1))

i = 1
while lcnt[lc[i-1]-1] == 1:
    if i == N:
        break
    else:
        lc.append(la[lc[i-1]-1])
        lcnt[la[lc[i-1]-1]-1] += 1
        i += 1

lpst = lc.index(lc[-1])
lpnum = len(lc) - lpst - 1
if lpnum == 0:
    loclst = lpst
else:
    loclst = (K - lpst) % lpnum + lpst

print(lc[loclst])

Submission status: Wrong Answer

Solution code:
def main():
    N,K = [int(x) for x in input().split()]
    Al = [int(x) for x in input().split()]
    current = 1
    steps = []
    initial_step = 0
    while current not in steps:
        steps.append(current)
        current = Al[current-1]
        initial_step += 1
    loop_step = len(steps) - steps.index(current)
    if len(steps) == initial_step:
        initial_step = 0
    print((K-initial_step)%loop_step)

if __name__ == '__main__':
    main()

Submission status: Wrong Answer

Solution code:
# # for i in range(m):
# s = input()
# t = input()
# n = len(s)
# m = len(t)
# # print(s,t,n,m)
# if n+1==m:
# 	for i in range(n):
# 		# print(s[i], t[i])
# 		if s[i]!=t[i]:
# 			print("No")
# 			break
# 	else:
# 		print("Yes")
# else:
# 	print("No")
	# l, r = [int(j)-1 for j in input().split()]
	################
# def fun(a,b,c,k):
# 	ans =0 
# 	if k<=a:
# 		return k
# 	else:
# 		ans = a
# 		k-=a
# 	if k<=b:
# 		return ans
# 	else:
# 		k-=b
# 	# if k<=c:
# 	# print(ans, c)
# 	return ans-min(c,k)
# a,b,c,k = [int(j) for j in input().split()]
# # l = [a,b,c]
# # j = 0
# print(fun(a,b,c,k))
################################

# while(k>0):
# 	a = min(k, l[j])
# 	k-=a

#######################

n,k = [int(j) for j in input().split()]
a = [int(j) for j in input().split()]
s = dict()
l = []
temp = 1
ct = 0
rep = None
# k_copy = 
while(k>0):
	ct+=1
	k-=1
	# print(temp)
	temp = a[temp-1]
	if temp in s:
		rep = s[temp]
		break
	else:
		s[temp]=ct
		l.append(temp)
if k==0:
	print(l[-1])
else:
	n = len(l)
	# print(l, rep, k, n)


	print(l[rep-1+(k)%(max(n-rep, 1))])
# print(l[s[a[ct]]-1+(k-s[a[ct]]+1)%(-1*s[a[ct]]+ct+1)])

Submission status: Wrong Answer

Solution code:
import sys
def input():
    return sys.stdin.readline().rstrip('\n')


def calc(N, K, A):
    n = 1
    k = 0
    d = {n: k}
    i = 0
    while True:
        k += 1
        n = A[n - 1]
        i += 1
        if i == K:
            return n
        if not n in d:
            d[n] = k
        else:
            if k - d[n] == 1:
                return n
            else:
                x = (K - d[n] + 1) % (k - d[n])
                for i in d:
                    if d[n] - 1 + x == d[i]:
                        return i

    

(N, K) = tuple([int(s) for s in input().split()])
A = [int(s) for s in input().split()]
print(calc(N, K, A))

Submission status: Wrong Answer

Solution code:
N, K = map(int, input().split())
A = list(map(int, input().split()))
X = [1]
pos = 0
for i in range(2 * N):
    X.append(A[pos])
    pos = A[pos] - 1
print(X)

s = set()
loop = len(X)
for i, x in enumerate(X):
    if x in s:
        loop = i
        break
    else:
        s.add(x)
#print(loop)
x, y = X[loop], X[loop + 1]
for i in range(N-1):
    if X[i] == x and X[i + 1] == y:
        base = i
        break
# print(base)
diff = loop - base
if K < base:
    print(X[K])
else:
    mod = K % diff
    # print(mod)
    print(A[mod])

Submission status: Wrong Answer

Solution code:
import sys

n,k = map(int,input().split())
a = list(map(int,input().split()))

array = [-1] * (n+1)
array[1] = 0

li = []
li.append(1)

tmp = -1
index = 0
for i in range(2 * (10**5)):
  if array[a[index]] != -1:
    tmp = array[a[index]]
    break
    
  if i == k:
    print(index)
    sys.exit(0)
    
  li.append(a[index])
  array[a[index]] = i+1
  index = a[index] -1
  
k -= tmp
d = len(li) - tmp

k %= d

print(li[k+tmp])

Submission status: Wrong Answer

Solution code:
import sys
import re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians
from itertools import accumulate, permutations, combinations, product
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
from bisect import bisect, bisect_left
from fractions import gcd
from heapq import heappush, heappop
from functools import reduce


def input(): return sys.stdin.readline().strip()


def INT(): return int(input())


def MAP(): return map(int, input().split())


def LIST(): return list(map(int, input().split()))


def ZIP(n): return zip(*(MAP() for _ in range(n)))


sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10 ** 9 + 7


def main():
    N, K = MAP()
    A = LIST()
    po = 1
    lis = [1]
    ct = defaultdict(int)
    ct[1] += 1
    while ct[po] < 2:
        po = A[po-1]
        ct[po] += 1
        lis.append(po)

    q = lis.index(po)
    # print(q)

    K -= q
    lis_ = lis[q:N-1]
    K %= len(lis_)
    # print(lis_)
    print(lis_[K])


if __name__ == '__main__':
    main()

Submission status: Wrong Answer

Solution code:
def solve():
    n, k = map(int, input().split())
    a = list(map(int, input().split()))

    p_list = [1]
    ne_p = a[0]
    p_bool = [False for _ in range(n)]
    p_bool[0] = True
    for _ in range(n):
        p_bool[ne_p-1] = True
        p_list.append(ne_p)
        ne_p = a[ne_p-1]
        # if ne_p in p_list:
        #     ind = p_list.index(ne_p)
        #     break
        if p_bool[ne_p-1]:
            break
    #print(p_list)
    #print(p_bool)
    ind = p_list.index(ne_p)
    k = k - ind
    #print(ind)
    #print(k)
    #print(p_list)
    #print(k%(len(p_list)-ind))
    print(p_list[ind + k%(len(p_list)-ind)])

solve()

Submission status: Wrong Answer

Solution code:
def find_size(A):
    visited = set()
    visited_index = dict()
    now = 0
    size = 0
    while True:
        if now in visited:
            return visited_index[now], size - visited_index[now]
        visited.add(now)
        visited_index[now] = size
        now = A[now]
        size += 1
    return None

def find_n(A, N):
    now = 0
    for _ in range(N):
        now = A[now]
    return now

int1 = lambda s: int(s)-1

N, K = map(int, input().split())
A = list(map(int1, input().split()))

start, size = find_size(A)
if K <= start:
    print(find_n(A, start + size) + 1)
else:
    print(find_n(A, (start + ((K - start) % size))) + 1)

Submission status: Wrong Answer

Solution code:
N, K = map(int, input().split())
K += 1
A = [int(i) for i in input().split()]
s = []
i = 0
length = 0
while True:
    if i + 1 in s:
        start = i + 1
        break
    s.append(i + 1)
    i = A[i] - 1
    length += 1

if start == A[0]:
    loop = K // length
    amari = K % length

    if amari - 1 == -1:
        print(s[length - 1])
    else:
        print(s[amari - 1])
else:
    idx = s.index(start)
    s2 = s[idx:]
    length2 = len(s2)
    tmp = length - length2

    if K < tmp:
        print(s[K])
    else:
        K -= tmp
        amari = K % length2

        if amari - 1 == -1:
            print(s2[length2 - 1])
        else:
            print(s2[amari - 1])

Submission status: Wrong Answer

Solution code:
import math
def py():
    print("Yes")
def pn():
    print("No")
def iin():
    x = int(input())
    return x

neko = 0
nya = 0
nuko = 0
t = 1
n,k = map(int,input().split())
a = [int(x) for x in input().split()]
f = [0] * n
c = 0
for i in range(k):
    if (f[t-1] == 1):
        break
    f[t-1] = 1
    t = a[t-1]
b = t
while True:
    t = a[t-1]
    c = c + 1
    if t == b:
        break
k = k%c
t = 1
for i in range(k):
    t = a[t-1]
print(t)

Submission status: Wrong Answer

Solution code:
# Problem D - Teleporter

# input
N, K = map(int, input().split())
a_nums = list(map(int, input().split()))

# initialization
visit_list = [0]*N
visit_list[0] = 1
pos = a_nums[0]
visit_count = 1

while visit_list[pos-1]==0:
    visit_count += 1
    visit_list[pos-1] = visit_count
    pos = a_nums[pos-1]
visit_count += 1

# calc 1
tmp_1 = visit_count - visit_list[pos-1] # 周期
tmp_2 = (K-(visit_count-1)) % tmp_1
# tmp_2回分ループ処理を行う
for i in range(tmp_2):
    pos = a_nums[pos-1]

# output
print(pos)

Submission status: Wrong Answer

Solution code:
n,k = map(int,input().split())
a = [-1] + list(map(int,input().split()))

ispass = [False]*n
now = 1
loop = set()
loop_first = -1
for _ in range(2*n):
    if ispass[now-1] == False:
        ispass[now-1] = True
    else:
        if loop_first == -1:
            loop_first = now
        loop.add(now)
    now = a[now]

k = k - (ispass.count(1) - len(loop))
k = k % len(loop)

now = loop_first
for _ in range(k):
    now = a[now]
print(now)

Submission status: Wrong Answer

Solution code:
n,k=map(int,input().split())
a=list(map(int,input().split()))
i=0
s=set()
s.add(1)
order=[1]
while 1:
    if a[i] in s:
        order.append(a[i])
        break
    else:
        order.append(a[i])
        s.add(a[i])
    i=a[i]-1
for i in range(len(order)):
    if order[-1]==order[i]:
        idx=i
        break

cnt=len(order)-(idx+1)
k%=cnt
print(order[k])
#print(order)

Submission status: Wrong Answer

Solution code:
N, K = map(int, input().split())
A = input().split()
A_MAP = {}
for i in range(N):
    A_MAP[str(i+1)] = A[i]

route_hash = {'1': 0}
current_pos = '1'
next_pos = ''
counter = 0
while counter <= K:
    next_pos = A_MAP[current_pos]
    counter+=1
    if next_pos in route_hash:
        break
    route_hash[next_pos] = counter # たどり着くまでにかかった回数
    current_pos = next_pos

if counter >= K:
    print(current_pos)
    exit()

remain = K - counter
counter -= route_hash[next_pos]
remain = remain % counter

current_pos = next_pos
for i in range(remain):
    next_pos = A_MAP[current_pos]
    route_hash[next_pos] = counter # たどり着くまでにかかった回数
    current_pos = next_pos
print(current_pos)