Problem:


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Depth First Search

  Depth-first search (DFS) follows the strategy to search ”deeper” in the graph whenever possible. In DFS, edges are recursively explored out of the most recently discovered vertex $v$ that still has unexplored edges leaving it. When all of $v$'s edges have been explored, the search ”backtracks” to explore edges leaving the vertex from which $v$ was discovered.

  This process continues until all the vertices that are reachable from the original source vertex have been discovered. If any undiscovered vertices remain, then one of them is selected as a new source and the search is repeated from that source.

  DFS timestamps each vertex as follows:

$d[v]$ records when $v$ is first discovered.

$f[v]$ records when the search finishes examining $v$’s adjacency list.

  Write a program which reads a directed graph $G = (V, E)$ and demonstrates DFS on the graph based on the following rules:

$G$ is given in an adjacency-list. Vertices are identified by IDs $1, 2,... n$ respectively.

IDs in the adjacency list are arranged in ascending order.

The program should report the discover time and the finish time for each vertex.

When there are several candidates to visit during DFS, the algorithm should select the vertex with the smallest ID.

The timestamp starts with 1.

Input

  In the first line, an integer $n$ denoting the number of vertices of $G$ is given. In the next $n$ lines, adjacency lists of $u$ are given in the following format:

$u$ $k$ $v_1$ $v_2$ ... $v_k$

$u$ is ID of the vertex and $k$ denotes its degree. $v_i$ are IDs of vertices adjacent to $u$.

Output

  For each vertex, print $id$, $d$ and $f$ separated by a space character in a line. $id$ is ID of the vertex, $d$ and $f$ is the discover time and the finish time respectively. Print in order of vertex IDs.

Constraints

$1 \leq n \leq 100$

Sample Input 1

4
1 1 2
2 1 4
3 0
4 1 3

Sample Output 1

1 1 8
2 2 7
3 4 5
4 3 6

Sample Input 2

6
1 2 2 3
2 2 3 4
3 1 5
4 1 6
5 1 6
6 0

Sample Output 2

1 1 12
2 2 11
3 3 8
4 9 10
5 4 7
6 5 6

  This is example for Sample Input 2 (discover/finish)

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.



Sample input:
4
1 1 2
2 1 4
3 0
4 1 3


Sample output:
1 1 8
2 2 7
3 4 5
4 3 6

Submission status: Accepted

Solution code:
import sys, math
from itertools import permutations, combinations, accumulate
from collections import defaultdict, Counter, deque
from math import factorial#, gcd
from bisect import bisect_left #bisect_left(list, value)
sys.setrecursionlimit(10**7)
enu = enumerate
MOD = 10**9+7
def input(): return sys.stdin.readline()[:-1]
def pri(x): print('\n'.join(map(str, x)))

N = int(input())
G = [list(map(int, input().split())) for _ in range(N)]
c = [0]*N # 0:not found, 1:found, 2:finished
res = [[0]*2 for _ in range(N)]

time = 1
def dfs(index):
#    print('index:', index)
    global time
    if c[index]==0:
        c[index]=1
        res[index][0] = time # found
        time += 1
    elif c[index]==1:
        return
    elif c[index]==2:
        return

    u, k, *v = G[index]
    for node in v:
        dfs(node-1) # 1-index -> 0-index

    c[index] = 2
    res[index][1] = time # finished
    time += 1
    return

for i in range(N):
    dfs(i)
res = [[val1]+val2 for val1, val2 in zip(list(range(1, N+1)), res)]
for val in res:
    print(*val)

Submission status: Accepted

Solution code:
N = int(input())

from collections import deque,defaultdict
G = defaultdict(deque)
for i in range(1,N+1):
    t = [int(i) for i in input().split(' ')]
    for j in range(t[1]):
        G[t[0]].append(t[j+2])

time = 1
arrive_time = [-1] * (N + 1) # 到着時刻
finish_time = [-1] * (N + 1) # 到着時刻

def dfs(G,s):
    global time
    stack = deque([s])
    arrive_time[s] = time
    while stack:
        t = stack[-1]
        if G[t]:
            w = G[t].popleft()
            if arrive_time[w] >= 0:
                continue
            elif w in stack:
                continue
            else:
                time += 1
                arrive_time[w] = time
                stack.append(w)
        else:
            time += 1
            finish_time[t] = time
            stack.pop()
            
    return arrive_time,finish_time

for i in range(1,N+1):
    if arrive_time[i] < 0:
        arrive,finish = dfs(G,i)
        time += 1

for i, (a, f) in enumerate(zip(arrive,finish)):
    if not i == 0:
        print(i,a,f)

Submission status: Accepted

Solution code:
from collections import deque
n = int(input())
v = {i:[] for i in range(n)}
for i in range(n):
    u = list(map(int, input().split()))
    for j in range(2, 2+u[1]):
        v[u[0]-1].append(u[j]-1)

global cnt1 
cnt1 = 0
visited = [False for _ in range(n)]
f = [0 for _ in range(n)]
l = [0 for _ in range(n)]
def DFS(now, visited):
    global cnt1
    cnt1 += 1
    f[now] = cnt1
    visited[now] = True
    for nv in v[now]:
        if visited[nv]:
            continue
        DFS(nv, visited)
    cnt1 += 1
    l[now] = cnt1

for value in range(n):
    if not visited[value]:
        DFS(value, visited)
    
for i in range(n):
    print(i+1, f[i], l[i])

Submission status: Accepted

Solution code:
n = int(input())
vert = [[0,0]+list(map(int,range(1,n+1)))]
parents = [0]
now = 0
time = 0
for i in range(n):
    ukv = list(map(int,input().split()))
    vert.append([0,0]+ukv[2:])
while(parents):
    for i in range(2,len(vert[now])):
        if vert[vert[now][i]][0] == 0:
            parents.append(now)
            now = vert[now][i]
            time += 1
            vert[now][0] = time
            break
    else:
        if now != 0:
            time += 1
        vert[now][1] = time
        now = parents.pop()
for i in range(1,n+1):
    print(i,*vert[i][0:2])

Submission status: Accepted

Solution code:
def dfs(G,n):

	global ptr
	
	#探索済
	seen[n] = True

	#行き
	F[n] = ptr
	ptr += 1

	for i in G[n]:
		#次に行けるかを判定
		if seen[i] == True :
			continue
		dfs(G,i)

	#帰り
	L[n] = ptr
	ptr += 1

if __name__ == '__main__':

	n = int(input())
	
	G = [[] for _ in range(n+1)] 
	F = [0 for _ in range(n+1)]
	L = [0 for _ in range(n+1)]

	#深さ優先探索
	#探索済配列
	seen = [False for _ in range(n+1)]

	for i in range(n):
		cmd = list(map(int,input().split()))
		m = cmd[1]
		if m != 0:
			for j in range(m):
				G[i+1].append(cmd[j+2])
	ptr = 1
	for i in range(1,n):
		if seen[i] == False :
			dfs(G,i)

	for i in range(1,n+1):
		print(i,F[i],L[i])

Submission status: Accepted

Solution code:
n = int(input())
u = [list(map(int,input().split())) for _ in range(n)]
ts = [[0,0] for _ in range(n)]
time = 0

def dfs(i):
  global time
  ts[i][0] = time
  for j in range(u[i][1]):
    a = u[i][j+2]-1
    if ts[a][0] == 0:
      time += 1
      dfs(a)
  time += 1
  ts[i][1] = time
  
for i in range(n):
  if ts[i][0] == 0:
    time += 1
    dfs(i)
  
for i in range(n):
  print(i+1, ts[i][0], ts[i][1])

Submission status: Accepted

Solution code:
#深さ優先探索
import sys
input = sys.stdin.readline
from collections import deque

#グラフ作成(無向グラフでは#を消す)
N = int(input())
graph = [deque([]) for _ in range(N+1)]
for _ in range(N):
    u, k, *v = [int(x) for x in input().split()]
    v.sort()
    for i in v:
        graph[u].append(i)
        #graph[i].append(u)
        
time = 0
arrive_time = [-1] * (N+1) #到着時刻
finish_time = [-1] * (N+1) #終了時刻

def dfs(v):
    global time
    time += 1
    stack = [v]
    arrive_time[v] = time
    while stack:
        v = stack[-1]
        if graph[v]:
            w = graph[v].popleft()
            if arrive_time[w] < 0:
                time += 1
                arrive_time[w] = time
                stack.append(w)
        else:
            time += 1
            finish_time[v] = time
            stack.pop()
    return [arrive_time, finish_time]


# 孤立している頂点対策
for i in range(N):
    if arrive_time[i+1] < 0:
        ans = dfs(i+1)

# 頂点番号、発見時刻、完了時刻
for i in range(N):
    temp = [i + 1, ans[0][i+1], ans[1][i+1]]
    print(* temp)

Submission status: Accepted

Solution code:
import sys
sys.setrecursionlimit(10**6)

n = int(input())
graph = []
chart = [[int(i)] for i in range(1,n+1)]
for i in range(n):
    z = [c-1 for c in list(map(int,input().split()))][2:]
    graph.append(z)
time = 0

def dfs(nod):
    global graph
    global time
    #break condition
    if len(chart[nod]) != 1:
        return 
    #end condition not necessary
    #if not graph[nod]:
    #    time += 1
    #    chart[nod].append(time)
    #    return
    # command
    time += 1
    chart[nod].append(time)
    
    # move
    for dis in graph[nod]:
            dfs(dis)

    # post-command
    time += 1
    chart[nod].append(time)
for i in range(n):
    dfs(i)
for i in range(n):
    print(*chart[i])

Submission status: Accepted

Solution code:
def dfs(index):
    global count
    d[index] = count
    count += 1
    for i in field[index]:
        if d[i]:
            continue
        count = dfs(i)
    f[index] = count
    return count + 1

n = int(input())
field = [[0,0]]
for _ in range(n):
    u, k, *v = map(int, input().split())
    field.append(v)
d = [0 for _ in range(n + 1)]
f = [0 for _ in range(n + 1)]

count = 1
for i in range(1, n + 1):
    if d[i]:
        continue
    count = dfs(i)
for i in range(1, n + 1):
    print(i, d[i], f[i])

Submission status: Accepted

Solution code:
# -*- coding: utf-8 -*-
import sys
INF=10**18
MOD=10**9+7
def input(): return sys.stdin.readline().rstrip()


c=0
def main():
    N=int(input())
    edge=[[] for _ in range(N)]
    for i in range(N):
        l=list(map(lambda x:int(x)-1,input().split()))
        for x in l[2:]:
            edge[i].append(x)
    d=[-1]*N
    f=[-1]*N
    used=[False]*N
    def dfs(v):
        global c
        used[v]=True
        d[v]=c
        for nv in edge[v]:
            if not used[nv]:
                c+=1
                dfs(nv)
        c+=1
        f[v]=c
    global c
    while not all(used):
        for i in range(N):
            if not used[i]:
                c+=1
                dfs(i)

    for i in range(N):
        print(i+1,d[i],f[i])
    
                

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
#http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_11_B&lang=ja

def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))

n = INT()
adj = [None]
for _ in range(n):
    adj_i = list(map(int, input().split()[2:]))
    adj.append(adj_i)

sndf = [None]
for i in range(1, n+1):
    sndf.append([False, i])

path = []

time = 0

def dfs(u):
    global time
    sndf[u][0] = True
    time += 1
    sndf[u].append(time)

    for v in adj[u]:
        if not sndf[v][0]:
            dfs(v)
    time += 1
    sndf[u].append(time)

for i in range(1, n+1):
    if not sndf[i][0]:
        dfs(i)

for x in sndf[1:]:
    print(*x[1:])

Submission status: Accepted

Solution code:
# 深さ優先探索 Depth first search: DFS


def dfs(u):
    global time
    color[u - 1] = 0
    time += 1
    d[u - 1] = time
    for v in range(1, n + 1):
        if A[u - 1][v - 1] == 1 and color[v - 1] == -1:
            dfs(v)
    color[u - 1] = 1
    time += 1
    f[u - 1] = time


n = int(input())
A = [[0 for i in range(n)] for i in range(n)]
for i in range(n):
    dat = [int(j) for j in input().split()]
    for j in range(dat[1]):
        A[dat[0] - 1][dat[2 + j] - 1] = 1

color = [-1 for i in range(n)]
d = [-1 for i in range(n)]
f = [-1 for i in range(n)]
time = 0
for i in range(n):
    if color[i] == -1:
        dfs(i+1)

for id in range(n):
    print(id + 1, d[id], f[id])

Submission status: Accepted

Solution code:
import sys
input = lambda: sys.stdin.readline().rstrip() 
import bisect as bs

def resolve():
    n = int(input())
    ukv = [list(map(int, input().split())) for _ in range(n)]

    d = [-1]*n
    f = [-1]*n
    stk = []
    status = [0]*n

    t = 1
    for i in range(n):
        if status[i]==0:
            stk.append(i)
            while len(stk)>0:
                a = stk[-1]
                if status[a]==0:
                    d[a] = t
                    t += 1
                    status[a] = 1
                elif status[a]==1:
                    stk.pop()
                    f[a] = t
                    t += 1
                    status[a] = 2
                else:
                    stk.pop()
                for i in reversed(ukv[a][2:]):
                    if status[i-1]==0:
                        stk.append(i-1) 

    for i in range(n):
        print(i+1, d[i], f[i])

if __name__ == '__main__':
    resolve()

Submission status: Accepted

Solution code:
mod = 10 ** 9 + 7
mod2 = 2 ** 61 + 1
from collections import deque
import heapq
import time
from bisect import bisect_left, insort_left, bisect_right
import sys
import random
import itertools

input = sys.stdin.readline
_NUMINT_ALL = list(range(10))
_START_TIME = time.time()
INDEX_KETA = 10**12

def main():
    ans = solve()

    if ans is True or ans is False:
        YesNo(ans)
    elif ans is None:
        return

    if isinstance(ans, tuple):
        split_print_space(ans)


def solve():

    G = iip()
    ukv = iipt(G)

    edge = {}
    for i, d in enumerate(ukv):
        if d[1] == 0:
            continue
        a, b, *c = d
        if isinstance(c, int):
            c = [c]

        for j in c:
            edge[(a, j)] = True


    ans = [[i+1, 0, 0] for i in range(G)]
    t = 0
    ans[0] = [1, 1, G*2]
    found = {0:True}

    def src(node):
        nonlocal t
        found[node] = True
        for j in range(1, G+1):
            if (node, j) in edge and j not in found:
                found[j] = True
                t += 1
                ans[j - 1][1] = t
                src(j)

        t += 1
        ans[node-1][2] = t

    for i in range(1, G+1):
        if i not in found:
            t += 1
            ans[i - 1][1] = t
            src(i)
    #print(ans)

    for i in ans:
        split_print_space(i)







#####################################################ライブラリ集ここから



def kiriage_warizan(a, b):
    return -(-a//b)


def iip(listed=False):  # 数字のinputをlistで受け取る
    d = input().rstrip("\n").split()
    try:
        ret = [int(i) for i in d]
    except:
        ret = [int(i) if i in _NUMINT_ALL else i for i in d]
        if len(ret) == 1 and listed is False:
            return ret[0]

    if len(ret) == 1 and not listed:
        return ret[0]
    return ret

def iipt(l, listed=True, num_only=True):  # 縦向きに並んでいるデータをリストに落とし込む(iip利用)
    if isinstance(l, list):
        l = l[0] # 間違って要素１個のタプルを渡されても受け取る
    ret = []
    for i in range(l):
        ret.append(iip(listed=listed))
    return ret


def saidai_kouyakusuu(A):  # 最大公約数
    l = len(A)
    while True:
        m = min(A)
        mx = max(A)
        if m == mx:
            return m

        for i in range(l):
            if A[i] % m == 0:
                A[i] = m
            else:
                A[i] %= m


def index_sorted(sorted_list, target):
    idx = bisect_left(sorted_list, target)
    if idx != len(sorted_list) and sorted_list[idx] == target:
        return idx
    else:
        return False


def time_debug_10percent():
    a = random.randint(0, 9)
    if a == 9:
        sys.exit()

def time_debug(t):
    time.sleep(_START_TIME + t - time.time())
    sys.exit()


def make_graph_edge_flat(N):  # グラフ作成のための辺をリストで返す
    ret = []
    for i in range(N-1):
        a, b, c = iip()
        a -= 1
        b -= 1
        ret[a].append((b, c))
        ret[b].append((a, c))
    return ret


def sort_tuples(l, index):  # タプルのリストを特定のインデックスでソートする
    if isinstance(l, list):
        l.sort(key=lambda x: x[index])
        return l
    else:
        l = list(l)
        return sorted(l, key=lambda x: x[index])


def count_elements(l):  # リストの中身の個数を種類分けして辞書で返す
    d = {}
    for i in l:
        if i in d:
            d[i] += 1
        else:
            d[i] = 1
    return d


def safeget(l, index, default="exception"):  # listの中身を取り出す時、listからはみ出たり
    if index >= len(l):                      # マイナスインデックスになったりするのを防ぐ
        if default == "exception":
            raise Exception("".join(["safegetに不正な値 ", index, "が渡されました。配列の長さは", len(l), "です"]))
        else:
            return default
    elif index < 0:
        if default == "exception":
            raise Exception("".join(["safegetに不正な値 ", index, "が渡されました。負の値は許可されていません"]))
        else:
            return default
    else:
        return l[index]


def sortstr(s):  # 文字列をソートする
    return "".join(sorted(s))


def iip_ord(startcode="a"):  # 文字列を数字の列に変換する(数字と文字は1:1対応)
    if isinstance(startcode, str):
        startcode = ord(startcode)
    return [ord(i) - startcode for i in input()]


def YesNo(s):  # TrueFalseや1, 0をYesNoに変換する
    if s:
        print("Yes")
    else:
        print("No")


def fprint(s):  # リストを平たくしてprintする(二次元リストを見やすくしたりとか)
    for i in s:
        print(i)


def bitall(N):  # ビット全探索用のインデックスを出力
    ret = []
    for i in range(2 ** N):
        a = []
        for j in range(N):
            a.append(i % 2)
            i //= 2
        ret.append(a)
    return ret

def split_print_space(s):  # リストの中身をスペース区切りで出力する
    print(" ".join([str(i) for i in s]))


def split_print_enter(s):  # リストの中身を改行区切りで出力する
    print("\n".join([str(i) for i in s]))


def soinsuu_bunkai(n):  # 素因数分解
    ret = []
    for i in range(2, int(n ** 0.5) + 1):
        while n % i == 0:
            n //= i
            ret.append(i)
        if i > n:
            break
    if n != 1:
        ret.append(n)
    return ret


def conbination(n, r, mod, test=False):  # nCrをmodを使って計算する
    if n <= 0:
        return 0
    if r == 0:
        return 1
    if r < 0:
        return 0
    if r == 1:
        return n
    ret = 1
    for i in range(n - r + 1, n + 1):
        ret *= i
        ret = ret % mod

    bunbo = 1
    for i in range(1, r + 1):
        bunbo *= i
        bunbo = bunbo % mod

    ret = (ret * inv(bunbo, mod)) % mod
    if test:
        # print(f"{n}C{r} = {ret}")
        pass
    return ret


def inv(n, mod):  #  modnにおける逆元を計算
    return power(n, mod - 2)


def power(n, p, mod_=mod):  # 繰り返し二乗法でn**p % modを計算
    if p == 0:
        return 1
    if p % 2 == 0:
        return (power(n, p // 2, mod_) ** 2) % mod_
    if p % 2 == 1:
        return (n * power(n, p - 1, mod_)) % mod_


def nibutan_func(func, target, left, right, side="left", seido = 1): # 関数を二分探索
    l = left
    r = right
    if seido == 1:
        x = (l + r) // 2
    else:
        x = (l + r) / 2
    while r-l > seido:
        #print(x)
        if seido == 1:
            x = (l + r) // 2
        else:
            x = (l + r) / 2
        if func(x) == target:
            if side == "left":
                r=x
            else:
                l=x


        elif func(x) > target:
            r = x
        else:
            #print(r, l)
            l = x

    #print(l, r)
    if side == "left" and func(r) == target:
        return r
    elif side != "left" and func(l) == target:
        return l
    elif side == "left":
        return l
    else:
        return r


def nibutan_list(list_, target, side="left"):  # リストを二分探索
    if not isinstance(list_, list):
        list_ = list(list_)

    l = 0
    r = len(list_)
    x = (l + r) // 2
    while r-l > 1:
        x = (l+r)//2
        if list_[x] == target:
            return x
        elif list_[x] > target:
            r = x
        else:
            l = x

    if side == "left" or list_[x] == target:
        return l
    else:
        return r


class UfTree():
    def __init__(self, maxnum):
        self.parent = list(range(maxnum))
        self._size = [1] * maxnum
        self.rank = [0] * maxnum

    def size(self, a):
        return self._size[self.root(a)]

    def root(self, a):
        rank = 0
        cur = a
        while True:
            if self.parent[cur] == cur:
                #for i in path: # 経路圧縮
                #    self.parent[i] = cur
                return cur
            else:
                self.parent[cur] = self.parent[self.parent[cur]]
                cur = self.parent[cur]
                rank += 1

    def unite(self, a, b):
        ra = self.root(a)
        rb = self.root(b)
        if ra == rb:
            return self

        self._size[ra] += self._size[rb]
        self.parent[rb] = ra
        return self

if __name__ == "__main__":
    main()

Submission status: Accepted

Solution code:
n=int(input())
seen=[-1]*n
first_order=[0]*n
last_order=[0]*n
cnt=0
def dfs(G,s):
    global cnt
    first_order[s]=cnt+1
    cnt+=1
    seen[s]=1
    for nv in G[s]:
        if(seen[nv]!=-1):
            continue
        dfs(G,nv)
    last_order[s]=cnt+1
    cnt+=1

G=[[] for i in range(n)]
for i in range(n):
    li=list(map(int,input().split()))
    for x in range(2,len(li)):
        G[i].append(li[x]-1)
for i in range(n):
    if(seen[i]==-1):
        dfs(G,i)
for i in range(n):
    print(i+1,first_order[i],last_order[i])

Submission status: Accepted

Solution code:
# coding: utf-8
# Your code here!

import sys
read = sys.stdin.read
readline = sys.stdin.readline


def dfs(G, v, d, f, time):
    time += 1
    d[v] = time

    for e in G[v]:
        if d[e] == 0:
            time = dfs(G, e, d, f, time)

    time += 1
    f[v] = time

    return time


def main():
    n = int(readline())

    E = [[]]
    for _ in range(n):
        u,k,*v = map(int, readline().split())
        E.append(v)

    d = [0] * (n+1)
    f = [0] * (n+1)
    time = 0
    
    for i in range(1,n+1):
        if d[i] == 0:
            time = dfs(E, i, d, f, time)
    
    for i in range(1, n+1):
        print(i, d[i], f[i])


if __name__ == "__main__":
    main()

Submission status: Accepted

Solution code:
import sys
sys.setrecursionlimit(10**7) 

def dfs(G,v):
    global ptr
    first_order[v] = ptr
    ptr += 1
    seen[v] = True
    for next in G[v]:
        if seen[next]:
            continue
        dfs(G,next)

    last_order[v] = ptr
    ptr+=1

n = int(input())
G = [[] for _ in range(n)]
for _ in range(n):
    a = list(map(int, input().split()))
    u = a[0]
    k = a[1]
    v = a[2:]
    for i in v:
        G[u-1].append(i-1)

seen = [False]*n
first_order = [0]*n
last_order = [0]*n
ptr = 0
for i in range(n):
    if seen[i]:
        continue
    dfs(G,i)

for i in range(n):
    print('{} {} {}'.format(i+1,first_order[i]+1,last_order[i]+1))

Submission status: Accepted

Solution code:
import math
import copy
import sys
import fractions
# import numpy as np
# import statistics
import decimal
import heapq
import collections
import itertools
import bisect


# from operator import mul

# sys.setrecursionlimit(100001)


# input = sys.stdin.readline
# sys.setrecursionlimit(10**6)

# ===FUNCTION===

def getInputIntList():
    outputDataList = []
    inputData = input().split()
    outputDataList = [int(n) for n in inputData]

    return outputDataList


def getSomeInputInt(n):
    outputDataList = []
    for i in range(n):
        inputData = int(input())
        outputDataList.append(inputData)

    return outputDataList


def getSomeInputListInt(n):
    inputDataList = []
    outputDataList = []
    for i in range(n):
        inputData = input().split()
        inputDataList = [int(n) - 1 for n in inputData]
        outputDataList.append(inputDataList)

    return outputDataList


# ===CODE===

n = int(input())

data = getSomeInputListInt(n)

ans = [[] for _ in range(n)]

edge = []
for d in data:
    edge.append(d[2:])


def dfs(i, cnt):
    if len(ans[i]) > 0:
        return cnt

    cnt += 1

    ans[i].append(cnt)
    for j in range(len(edge[i])):
        cnt = dfs(edge[i][j], cnt)

    cnt += 1
    ans[i].append(cnt)

    return cnt

tmp = 0
for i in range(n):
    tmp = dfs(i, tmp)

for i in range(n):
    print(i + 1, *ans[i], sep=" ")

Submission status: Accepted

Solution code:
n=int(input())
adj=[]
for i in range(n):
	a=list(map(int,input().split()))
	for j in range(2,len(a)):
		a[j]-=1
	adj.append(a[2:])
visit_time1=[0]*n
visit_time2=[0]*n
visited=[0]*n
def dfs(now):
	global time
	visit_time1[now]=time
	time+=1
	for next in adj[now]:
		if not visited[next]:
			visited[next]=True
			dfs(next)
	visit_time2[now]=time
	time+=1
time=1
for i in range(n):
	if not visited[i]:
		visited[i]=True
		dfs(i)
for i in range(n):
	print(i+1,visit_time1[i],visit_time2[i])

Submission status: Accepted

Solution code:
# 深さ優先探索（行きがけ、帰りがけ）
import sys
input = sys.stdin.readline
from collections import deque

# グラフの作成(無向グラフでは#を消す)
N = int(input())
graph = [deque([]) for _ in range(N + 1)]
for _ in range(N):
    u, k, * v = [int(x) for x in input().split()] # uは頂点番号、kは隣接頂点の個数
    v.sort()
    for i in v:
        graph[u].append(i)
        # graph[i].append(u) # 無向グラフ

time = 0
arrive_time = [-1] * (N + 1) # 到着時刻
finish_time = [-1] * (N + 1) # 探索終了時刻

# 深さ優先探索
def dfs(v):
    global time
    time += 1
    stack = [v]
    arrive_time[v] = time
    while stack:
        v = stack[-1]
        if graph[v]:
            w = graph[v].popleft()
            if arrive_time[w] < 0:
                time += 1
                arrive_time[w] = time
                stack.append(w) 
        else:
            time += 1
            finish_time[v] = time
            stack.pop()          
    return [arrive_time, finish_time]

# 孤立している頂点対策
for i in range(N):
    if arrive_time[i + 1] < 0:
        ans = dfs(i + 1)

# 頂点番号、到着時刻、終了時刻
for j in range(N):
    temp = [j + 1, ans[0][j + 1], ans[1][j + 1]]
    print(* temp)

Submission status: Accepted

Solution code:
n = int(input())
graph = [-1] + [list(map(int, input().split())) for _ in range(n)]
seen = [False]*(n+1)
seen[0] = True
d = [-1]*(n+1)
f = [-1]*(n+1)
time = 0


def dfs(v):
    global time
    time += 1
    d[v] = time
    seen[v] = True
    k = graph[v][1]
    if k > 0:
        for i in range(k):
            w = graph[v][i+2]
            if seen[w] is False:
                dfs(w)
    
    time += 1
    f[v] = time

v = 0
while v <= n:
    if seen[v] is False:
        dfs(v)
    
    v += 1

for i in range(1, n+1):
    print(i, d[i], f[i])

Submission status: Accepted

Solution code:
from collections import deque
time = 1

def dfs(adj_list, d, f, color, u):

    global time
    S = list()

    S.append(u)
    color[u] = "G"
    d[u] = time
    time += 1

    while len(S) != 0:
        u = S[-1]

        if len(adj_list[u]) != 0:
            v = adj_list[u].popleft()

            if color[v] == "W":
                color[v] = "G"
                d[v] = time
                time += 1
                S.append(v)
        else:
            S.pop()
            color[u] = "B"
            f[u] = time
            time += 1

def Main():
    
    N = int(input())
    adj_list = [deque() for n in range(N)]
    d = [0] * N
    f = [0] * N
    color = [ "W" for i in range(len(d)) ]

    for n in range(N):
        u, k, *V = map(int, input().split())

        if k > 0:
            for i in V:
                adj_list[n].append(i - 1)

    while(True):

        ind = None
        for i in range(N):
            if color[i] == "W":
                ind = i
                break

        if ind == None:
            break
        else:
            dfs(adj_list, d, f, color, ind)

    for i in range(N):
        print("{} {} {}".format(i + 1, d[i], f[i] ))

Main()

Submission status: Accepted

Solution code:
n = int(input())
M = [[0]*n for _ in range(n)]
st = [0]*n
d = [0]*n
f = [0]*n
tt = 0

def dfs(u,t):
    st[u] = 1
    t += 1
    d[u] = t
    for v in range(n):
        if M[u][v] == 0: continue
        if st[v] == 0: t = dfs(v,t)
    st[u] = 2
    t += 1
    f[u] = t
    return t

for _ in range(n):
    i = [int(i) for i in input().split()]
    u = i[0]
    k = i[1]
    V = i[2:]
    for v in V: M[u-1][v-1] = 1

for i in range(n):
    if st[i] == 0: tt = dfs(i,tt)

for i in range(n): print(i+1,d[i],f[i])

Submission status: Accepted

Solution code:
def main():

    inf = 1000000007
    n = int(input())
    e = [[] for _ in range(n)]
    d = [inf]*n
    f = [inf]*n
    step = 1

    def dfs(v):
        nonlocal step
        d[v] = step
        step+=1
        for u in e[v]:
            if d[u] == inf:dfs(u)
        f[v] = step
        step +=1

    e = [[] for _ in range(n)]
    for i in range(n):
        m = list(map(int,input().split()))
        for j in range(2,len(m)):
            e[m[0]-1].append(m[j]-1)
    for i in range(n):
        if d[i]==inf:dfs(i)
    for i in range(n):
        print (i+1,d[i],f[i])

if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
# https://onlinejudge.u-aizu.ac.jp/courses/lesson/1/ALDS1/11/ALDS1_11_B

G = {}
d = {}
f = {}
used = set()
t = 1


def dfs(cur):
    global G, d, f, t

    used.add(cur)
    d[cur] = t

    for i in G[cur]:
        if i in used:
            continue
        t += 1
        dfs(i)
    t += 1
    f[cur] = t


if __name__ == "__main__":
    N = int(input())

    for _ in range(N):
        u, k, *V = list(map(int, input().split()))
        G[u] = V

    for i in range(1, N+1):
        if i not in used:
            dfs(i)
            t += 1

    for i in G.keys():
        print(i, d[i], f[i])

Submission status: Accepted

Solution code:
n = int(input())
a = [None]
for i in range(n):
    adj = list(map(int,input().split()))
    a.append(adj[2:])
    
s = [None]
for i in range(1, n + 1):
    s.append([False, i])
    
time = 0

def dfs(u):
    global time
    s[u][0] = True
    time += 1
    s[u].append(time)
    
    for v in a[u]:
        if s[v][0] == False:
            dfs(v)
            
    time += 1
    s[u].append(time)
    
for i in range(1,n+1):
    if s[i][0] == False:
        dfs(i)
        
for x in s[1:]:
    print(*x[1:])

Submission status: Accepted

Solution code:
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time

sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7

stdin = sys.stdin

ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
ns = lambda: stdin.readline().rstrip()  # ignore trailing spaces

n = ni()
g = []
for i in range(n):
    t = na()
    u = t[0] - 1
    k = t[1]
    v = [x-1 for x in t[2:]]
    g.append(v)
d = [0] * n
f = [0] * n
#print(g)
seen = [False] * n
s = 0
t = 0
def dfs(g, v):
    global t
    #print(v+1, t)
    if seen[v]:
        return
    seen[v] = True
    d[v] = t
    t += 1    
    for next_v in g[v]:
        #if seen[next_v]: continue
        dfs(g, next_v)
    f[v] = t
    t += 1
for i in range(n):
    if len(g[i]) != 0:
        dfs(g, i)
for i in range(n):
    print(i+1, d[i]+1, f[i]+1)

Submission status: Accepted

Solution code:
def inpl():
    return list(map(int, input().split()))


def dfs(v, step):
    if f[v] != -1:
        return step
    f[v] = step
    step += 1
    for nv in E[v]:
        # print("now", v, nv, step)
        step = dfs(nv - 1, step)
    d[v] = step
    return step + 1


n = int(input())
E = [[] for i in range(n)]
for _ in range(n):
    tmp = inpl()
    u, k = tmp[:2]
    E[u - 1] = tmp[2:]

d = [-1 for i in range(n)]
f = [-1 for i in range(n)]

step = 1
for v in range(n):
    step = dfs(v, step)

for i in range(n):
    print(i + 1, f[i], d[i])

Submission status: Accepted

Solution code:
#!/usr/bin/env python3
import sys
sys.setrecursionlimit(15000)
n = int(sys.stdin.readline())

ret = []
inp = sys.stdin.readlines()
G = [None]*(n)
d = [0]*(n)
f = [0]*(n)
def dfs(i,t):
  if d[i] != 0:
    return t
  t = t+1
  d[i] = t
  for j in G[i]:
    t = dfs(j,t)
  f[i] = t+1
  return f[i]
for i in range(n):
  v = list(map(int,inp[i].split()))
  G[v[0]-1] = list(map(lambda x: int(x-1),v[2:]))
#print(G)
t = 0
for j in range(n):
  t = dfs(j,t)

for i in range(n):
  print(i+1,d[i],f[i])