Problem:


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Sliding Minimum Element

  For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $L$, find the minimum of each possible sub-arrays with size $L$ and print them from the beginning. For example, for an array $\{1, 7, 7, 4, 8, 1, 6\}$ and $L = 3$, the possible sub-arrays with size $L = 3$ includes $\{1, 7, 7\}$, $\{7, 7, 4\}$, $\{7, 4, 8\}$, $\{4, 8, 1\}$, $\{8, 1, 6\}$ and the minimum of each sub-array is 1, 4, 4, 1, 1 respectively.

Constraints

 $1 \leq N \leq 10^6$ 

 $1 \leq L \leq 10^6$

 $1 \leq a_i \leq 10^9$

 $L \leq N$ 

Input

The input is given in the following format.

$N$ $L$

$a_1$ $a_2$ ... $a_N$

Output

  Print a sequence of the minimum in a line. Print a space character between adjacent elements.

Sample Input 1

7 3
1 7 7 4 8 1 6

Sample Output 1

1 4 4 1 1



Sample input:
7 3
1 7 7 4 8 1 6


Sample output:
1 4 4 1 1

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 500 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.97
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 300 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.97
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 200 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.97
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 400 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.97
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 350 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.97
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
from functools import reduce
import operator
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if not ANS[idx]:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if not ANS[i] : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if not ANS[i] : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.991
INIT = None
ANS = [INIT]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
from functools import reduce
import operator
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if not ANS[idx]:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if not ANS[i] : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if not ANS[i] : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.9905
INIT = None
ANS = [INIT]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
from functools import reduce
import operator
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if not ANS[idx]:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if not ANS[i] : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if not ANS[i] : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.9907
INIT = None
ANS = [INIT]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
from functools import reduce
import operator
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if not ANS[idx]:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if not ANS[i] : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if not ANS[i] : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.9906
INIT = None
ANS = [INIT]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
from functools import reduce
import operator
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if not ANS[idx]:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if not ANS[i] : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if not ANS[i] : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.99065
INIT = None
ANS = [INIT]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import array
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx]==0 : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i]==0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i]==0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.9907
ANS = array.array('I',[0]*N)
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import array
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx]==0 : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i]==0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i]==0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.999
ANS = array.array('I',[0]*N)
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import array
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx]==0 : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i]==0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i]==0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
 
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
parameter = 0.995
ANS = array.array('I',[0]*N)
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 275 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 300 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 350 : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * 0.999 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N -50 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > K * 0.999  : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > K * 0.9  : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 100 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 90 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 200 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > K * 0.999 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = N // 2
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 300 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):
    A = []
    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 400 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(Whole,start,end,L,ANS):

    if end > N : end = N
    count = 0
    count2 = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(AA,[x,i])
    for j in range(start,end):
        a = heapq.heappop(AA)
        tmp = count
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] == 0 and idx < end:
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count == tmp : count2 += 1
        if count2 > 400 : break
    for i in range(L):
        if ANS[i] == 0 : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] == 0 : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS

[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
AA = []
ANS = [0]*N
start = 0
K = L * int(N ** 0.3 + 2 )
if K > N : K = N
end = K
while (end <= N):
    ANS = SME(A, start, end, L, ANS)
    start = end
    end += K 
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):

    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
  
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
A = []
parameter = 0.991
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):

    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
  
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
A = []
parameter = 0.9998
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):

    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
  
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
A = []
parameter = 0.998
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])

Submission status: Time Limit Exceeded

Solution code:
import heapq
def SME(start,end):

    if end > N : end = N
    count = 0
    for i,x in enumerate(Whole[start:end]):
        heapq.heappush(A,[x,i])
    for j in range(start,end):
        a = heapq.heappop(A)
        for i in range(L):
            idx = a[1] + i
            try :
                if ANS[idx] : continue
                else :
                    ANS[idx] = a[0]
                    count += 1
            except IndexError : continue
        if count > N * parameter : break
    for i in range(L):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[:i+1])
    for i in range(L,N):
        if ANS[i] : continue
        else : ANS[i] = min(Whole[i+1-L:i+1])
    return ANS
  
[N,L] = [int(x) for x in input().split()]
Whole = [int(x) for x in input().split()]
A = []
parameter = 0.997
ANS = [None]*N
ANS = SME(0, N)
for i in ANS[L-1:-1]:print(i, end=" ")
print(ANS[-1])