Problem:


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Single Source Shortest Path II

  For a given weighted graph $G = (V, E)$, find the shortest path from a source to each vertex. For each vertex $u$, print the total weight of edges on the shortest path from vertex $0$ to $u$.

Input

  In the first line, an integer $n$ denoting the number of vertices in $G$ is given. In the following $n$ lines, adjacency lists for each vertex $u$ are respectively given in the following format:

$u$ $k$ $v_1$ $c_1$ $v_2$ $c_2$ ... $v_k$ $c_k$

  Vertices in $G$ are named with IDs $0, 1, ..., n-1$. $u$ is ID of the target vertex and $k$ denotes its degree. $v_i (i = 1, 2, ... k)$ denote IDs of vertices adjacent to $u$ and $c_i$ denotes the weight of a directed edge connecting $u$ and $v_i$ (from $u$ to $v_i$).

Output

  For each vertex, print its ID and the distance separated by a space character in a line respectively. Print in order of vertex IDs.

Constraints

$1 \leq n \leq 10,000$

$0 \leq c_i \leq 100,000$

$|E| < 500,000$

All vertices are reachable from vertex $0$

Sample Input 1

5
0 3 2 3 3 1 1 2
1 2 0 2 3 4
2 3 0 3 3 1 4 1
3 4 2 1 0 1 1 4 4 3
4 2 2 1 3 3

Sample Output 1

0 0
1 2
2 2
3 1
4 3

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.



Sample input:
5
0 3 2 3 3 1 1 2
1 2 0 2 3 4
2 3 0 3 3 1 4 1
3 4 2 1 0 1 1 4 4 3
4 2 2 1 3 3


Sample output:
0 0
1 2
2 2
3 1
4 3

Submission status: Accepted

Solution code:
import sys

def dijkstra(v_count: int, edges: list, start: int,
             *, adj_matrix: bool = False, unreachable=float("inf")) -> list:
    """ ダイクストラ法
    :param v_count: 頂点数
    :param edges: 辺のリスト(隣接リストor隣接行列)
    :param start: スタートする頂点
    :param adj_matrix: edgesに渡したリストが隣接行列ならTrue
    :param unreachable: 到達不能を表すコスト値
                        隣接行列の辺の有無の判定および返すリストの初期値に使用
    """
    from heapq import heappush, heappop

    vertices = [unreachable] * v_count
    vertices[start] = 0
    q, rem = [(0, start)], v_count - 1

    while q and rem:
        cost, v = heappop(q)
        if vertices[v] < cost:
            continue
        rem -= 1

        dests = (filter(lambda x: x[1] != unreachable, enumerate(edges[v]))
                 if adj_matrix else edges[v])

        for dest, _cost in dests:
            newcost = cost + _cost
            if vertices[dest] > newcost:
                vertices[dest] = newcost
                heappush(q, (newcost, dest))

    return vertices

n = int(input())
edges = [[] for _ in [0]*n]
for a in (tuple(map(int, l.split())) for l in sys.stdin):
    edges[a[0]] = tuple(zip(a[2::2], a[3::2]))
vertices = dijkstra(n, edges, 0)
for i, n in enumerate(vertices):
    print(i, n)

Submission status: Accepted

Solution code:
import sys
import heapq
n = int(input())
V = [[int(i) for i in input().split()] for _ in range(n)]
dis = [sys.maxsize for _ in range(n)]
dis[0] = 0
h = []
for i in range(n):
    heapq.heappush(h,(dis[i],i))
while(len(h)>0):
    node = heapq.heappop(h)
    tmp = node[1]
    for i in range(V[tmp][1]):
        ind = V[tmp][2*i+2]
        cos = V[tmp][2*i+3]
        if cos + dis[tmp] < dis[ind]:
            dis[ind] = cos + dis[tmp]
            heapq.heappush(h,(dis[ind],ind))
for i,j in enumerate(dis):
    print(i,j)

Submission status: Accepted

Solution code:
from sys import maxsize
from heapq import heappop, heappush


class Node:
    WHITE = 0
    GRAY = 1
    BLACK = 2

    def __init__(self):
        self.adjs = []
        self.color = Node.WHITE
        self.dist = maxsize

    def __lt__(self, other):
        return self.dist < other.dist

    def __repr__(self):
        return "Node({},{},{})".format(self.adjs, self.color, self.dist)


def read_adj():
    n = int(input())
    nodes = [Node() for _ in range(n)]

    for i in range(n):
        u, _, *rest = [int(x) for x in input().split()]
        for i in range(0, len(rest) - 1, 2):
            nodes[u].adjs.append((nodes[rest[i]], rest[i+1]))

    return nodes


def shortest_path(nodes):
    h = []

    nodes[0].dist = 0
    nodes[0].color = Node.GRAY
    heappush(h, nodes[0])

    while True:
        while len(h) > 0:
            min_node = heappop(h)
            if min_node.color != Node.BLACK:
                break
        else:
            break

        min_node.color = Node.BLACK

        for adj, c in min_node.adjs:
            if min_node.dist + c < adj.dist:
                adj.dist = min_node.dist + c
                adj.color = Node.GRAY
                heappush(h, adj)


def print_dist(nodes):
    for u, n in enumerate(nodes):
        print(u, n.dist)


def main():
    nodes = read_adj()
    shortest_path(nodes)
    print_dist(nodes)


if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
from sys import maxsize
from heapq import heappop, heappush


class Node:
    WHITE = 0
    GRAY = 1
    BLACK = 2

    def __init__(self):
        self.adjs = []
        self.color = Node.WHITE
        self.dist = maxsize

    def __lt__(self, other):
        return self.dist < other.dist

    def __repr__(self):
        return "Node({},{},{})".format(self.adjs, self.color, self.dist)


def read_adj():
    n = int(input())
    nodes = [Node() for _ in range(n)]

    for i in range(n):
        u, _, *rest = [int(x) for x in input().split()]
        for i in range(0, len(rest) - 1, 2):
            nodes[u].adjs.append((rest[i], rest[i+1]))

    return nodes


def shortest_path(nodes):
    h = []

    nodes[0].dist = 0
    nodes[0].color = Node.GRAY
    heappush(h, (0, 0))

    while len(h) > 0:
        min_node, min_dist = heappop(h)
        if nodes[min_node].dist < min_dist:
            continue

        nodes[min_node].color = Node.BLACK

        for adj, c in nodes[min_node].adjs:
            if nodes[min_node].dist + c < nodes[adj].dist:
                nodes[adj].dist = nodes[min_node].dist + c
                nodes[adj].color = Node.GRAY
                heappush(h, (adj, nodes[adj].dist))


def print_dist(nodes):
    for u, n in enumerate(nodes):
        print(u, n.dist)


def main():
    nodes = read_adj()
    shortest_path(nodes)
    print_dist(nodes)


if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
from sys import maxsize
from heapq import heappop, heappush


class Node:
    WHITE = 0
    GRAY = 1
    BLACK = 2

    def __init__(self):
        self.adjs = []
        self.color = Node.WHITE
        self.dist = maxsize

    def __lt__(self, other):
        return self.dist < other.dist

    def __repr__(self):
        return "Node({},{},{})".format(self.adjs, self.color, self.dist)


def read_adj():
    n = int(input())
    nodes = [Node() for _ in range(n)]

    for i in range(n):
        u, _, *rest = [int(x) for x in input().split()]
        for i in range(0, len(rest) - 1, 2):
            nodes[u].adjs.append((rest[i], rest[i+1]))

    return nodes


def shortest_path(nodes):
    h = []

    nodes[0].dist = 0
    nodes[0].color = Node.GRAY
    heappush(h, (0, 0))

    while len(h) > 0:
        min_dist, min_node = heappop(h)

        nodes[min_node].color = Node.BLACK
        if nodes[min_node].dist < min_dist:
            continue

        for adj, c in nodes[min_node].adjs:
            if nodes[adj].color == Node.BLACK:
                continue
            if nodes[min_node].dist + c < nodes[adj].dist:
                nodes[adj].dist = nodes[min_node].dist + c
                nodes[adj].color = Node.GRAY
                heappush(h, (nodes[adj].dist, adj))


def print_dist(nodes):
    for u, n in enumerate(nodes):
        print(u, n.dist)


def main():
    nodes = read_adj()
    shortest_path(nodes)
    print_dist(nodes)


if __name__ == '__main__':
    main()

Submission status: Accepted

Solution code:
# -*- coding: utf-8 -*-

import sys
from heapq import heappush, heappop

sys.setrecursionlimit(10 ** 9)
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
INF=float('inf')

# ダイクストラ(頂点数, 隣接リスト(0-indexed), 始点)
def dijkstra(N: int, nodes: list, src: int) -> list:
    # 頂点[ある始点からの最短距離]
    # (経路自体を知りたい時はここに前の頂点も持たせる)
    res = [float('inf')] * N
    # スタート位置
    que = [(0, src)]
    res[src] = 0
    # キューが空になるまで
    while len(que) != 0:
        # srcからの距離, 現在のノード
        dist, cur = heappop(que)
        # 出発ノードcurの到着ノードでループ
        for nxt, cost in nodes[cur]:
            # 今回の経路のが短い時
            if res[cur] + cost < res[nxt]:
                res[nxt] = res[cur] + cost
                # 現在の移動距離をキューの優先度として、早い方から先に処理するようにする
                heappush(que, (res[nxt], nxt))
    # ノードsrcからの最短距離リストを返却
    return res

N=INT()
nodes=[[] for i in range(N)]
for i in range(N):
    l=LIST()
    u=l[0]
    k=l[1]
    l=l[2:]
    for j in range(0, k*2, 2):
        nodes[u].append((l[j], l[j+1]))

ans=dijkstra(N, nodes, 0)
for i in range(N):
    print(i, ans[i])

Submission status: Accepted

Solution code:
import sys, itertools
f = sys.stdin

def take2(iterable):
    i = iter(iterable)
    while True:
        yield next(i), next(i)

n = int(f.readline())
adj =[[(v, c) for v, c in take2(map(int, f.readline().split()[2:]))] for _ in range(n)]
d = [100000 * 100 + 1] * n

d[0] = 0
queue ={0}
while len(queue):
    parent = queue.pop()
    for v, c in adj[parent]:
        if d[v] > d[parent] + c:
            d[v] = d[parent] + c
            queue.update([v])

for i in range(n):
    print(i, d[i])

Submission status: Accepted

Solution code:
import heapq

INFTY = 100000000000000000000000000
heap = []
n = int(raw_input())
graph = {}
for i in range(n):
    entry = map(int, raw_input().split(' '))
    u = entry[0]
    k = entry[1]
    graph[u] = {}
    for j in range(k):
        v = entry[2+j*2]
        c = entry[2+j*2+1]
        graph[u][v] = c

d = {}
visited = {}
heap = []
for i in range(n):
    d[i] = INFTY
    visited[i] = False

s = 0
d[s] = 0
visited[s] = True
heapq.heappush(heap,(0,s))

while len(heap) > 0:
    mincost,minnode = heapq.heappop(heap)
    if mincost > d[minnode]: continue
    visited[minnode] = True
    for i in graph[minnode]:
        if not visited[i] and d[i] > d[minnode] + graph[minnode][i]:
            d[i] = d[minnode] + graph[minnode][i]
            heapq.heappush(heap, (d[i],i))

for i in range(n):
    print i,d[i]

Submission status: Accepted

Solution code:
#!/usr/bin/python3
from heapq import heappop, heappush
n = int(input())
inf = 100 * 100000

M = [[] for i in range(n)]

for i in range(n):
    L = list(map(int, input().split()))
    u = L[0]
    k = L[1]
    v = L[2::2]
    c = L[3::2]
    for j in range(k):
        M[u].append((v[j], c[j]))
result = [0] * n
S = set()
V = set(range(n))
S.add(0)
d = []
for m in M[0]:
    heappush(d, (m[1], m[0]))
T = V - S

while len(T) != 0:
    c, v = heappop(d)
    while v in S:
        c, v = heappop(d)
    result[v] = c
    S.add(v)
    T.remove(v)
    for m in M[v]:
        if m[0] in T:
            heappush(d, (result[v] + m[1], m[0]))

for i, v in enumerate(result):
    print(i, v)

Submission status: Accepted

Solution code:
import heapq

n = int(input())
edges = [None] * n
for _ in range(n):
    l = list(map(int, input().split()))
    edges[l[0]] = set((c, j) for j, c in (l[i:i + 2] for i in range(2, l[1] * 2 + 2, 2)))

min_costs = [0] * n
visited = [False] * n
visited[0] = True
queue = list(edges[0])
heapq.heapify(queue)

while queue:
    total_cost, vertex = heapq.heappop(queue)
    if visited[vertex]:
        continue
    visited[vertex] = True
    min_costs[vertex] = total_cost
    for cost, vertex2 in edges[vertex]:
        if not visited[vertex2]:
            heapq.heappush(queue, (total_cost + cost, vertex2))

for r in enumerate(min_costs):
    print(*r)

Submission status: Accepted

Solution code:
import heapq

n = int(input())
edges = [None] * n
for _ in range(n):
    l = list(map(int, input().split()))
    edges[l[0]] = set((c, j) for j, c in (l[i:i + 2] for i in range(2, l[1] * 2 + 2, 2)))

min_costs = [0] * n
visited = [False] * n
visited[0] = True
queue = list(edges[0])
heapq.heapify(queue)
remains = n - 1

while True:
    total_cost, vertex = heapq.heappop(queue)
    if visited[vertex]:
        continue
    visited[vertex] = True
    min_costs[vertex] = total_cost
    remains -= 1
    if not remains:
        break
    for cost, vertex2 in edges[vertex]:
        if not visited[vertex2]:
            heapq.heappush(queue, (total_cost + cost, vertex2))

for r in enumerate(min_costs):
    print(*r)

Submission status: Accepted

Solution code:
import heapq
from collections import deque

WHITE = 0
GRAY = 1
BLACK = 2

n = int(raw_input())
M = []
for i in xrange(n):
    M.append(deque([]))
color = [WHITE] * n
d = [float('inf')] * n

for i in xrange(n):
    a = map(int, raw_input().split())
    for j in xrange(a[1]):
        M[a[0]].append((a[2*(j+1)],a[2*(j+1)+1]))

def dijkstra():
    d[0] = 0

    PQ = []
    heapq.heappush(PQ,(0,0))#value, node
    
    color[0] = GRAY

    while len(PQ) > 0:
        f = heapq.heappop(PQ)
        u = f[1]
        color[u] = BLACK

        if d[u] < f[0]:
            continue

        for j in xrange(len(M[u])):
            v = M[u][j][0]
            if color[v] == BLACK:
                continue
            if d[v] > d[u] + M[u][j][1]:
                d[v] = d[u] + M[u][j][1]
                heapq.heappush(PQ, (d[v],v))
                color[v] = GRAY

    for i in xrange(n):
        print "{} {}".format(i, d[i])

    return 0

def main():
    dijkstra()
    return 0

main()

Submission status: Accepted

Solution code:
import heapq
from collections import deque

WHITE = 0
GRAY = 1
BLACK = 2

n = int(raw_input())
M = [ [] for _ in xrange(n)]
color = [WHITE] * n
d = [float('inf')] * n

for i in xrange(n):
    a = map(int, raw_input().split())
    for j in xrange(a[1]):
        M[a[0]].append((a[2*(j+1)],a[2*(j+1)+1]))

def dijkstra():
    d[0] = 0

    PQ = []
    heapq.heappush(PQ,(0,0))#value, node
    
    color[0] = GRAY

    while len(PQ) > 0:
        f = heapq.heappop(PQ)
        u = f[1]
        color[u] = BLACK

        if d[u] < f[0]:
            continue

        for j in xrange(len(M[u])):
            v = M[u][j][0]
            if color[v] == BLACK:
                continue
            if d[v] > d[u] + M[u][j][1]:
                d[v] = d[u] + M[u][j][1]
                heapq.heappush(PQ, (d[v],v))
                color[v] = GRAY

    for i in xrange(n):
        print "{} {}".format(i, d[i])

    return 0

def main():
    dijkstra()
    return 0

main()

Submission status: Accepted

Solution code:
import heapq


class ShortestPath:
    """Dijkstra's algorithm : find the shortest path from a vertex
       Complexity: O(E + log(V))
       used in GRL1A(AOJ)
    """

    def __init__(self, V, E, start, INF=10**9):
        """ V: the number of vertexes
            E: adjacency list (all edge in E must be 0 or positive)
            start: start vertex
            INF: Infinity distance
        """
        self.V = V
        self.E = E
        self.dijkstra(start, INF)

    def dijkstra(self, start, INF):
        que = list()
        self.distance = [INF] * self.V  # distance from start
        self.prev = [-1] * self.V  # prev vertex of shortest path
        self.distance[start] = 0
        heapq.heappush(que, (0, start))

        while len(que) > 0:
            dist, fr = heapq.heappop(que)
            if self.distance[fr] < dist:
                continue
            for to, cost in self.E[fr]:
                if self.distance[fr] + cost < self.distance[to]:
                    self.distance[to] = self.distance[fr] + cost
                    heapq.heappush(que, (self.distance[to], to))
                    self.prev[to] = fr

    def getPath(self, end):
        path = [end]
        while self.prev[end] != -1:
            end = self.prev[end]
        return path[::-1]
V = int(input())
edge = [[] for _ in range(V)]
for _ in range(V):
    u, _, *e = map(int, input().split())
    for t, d in zip(e[::2], e[1::2]):
        edge[u].append((t, d))

sp = ShortestPath(V, edge, 0)
for i, d in enumerate(sp.distance):
    print(i, d)

Submission status: Accepted

Solution code:
import heapq


def dijkstra(n):
    inf = 10 ** 6 + 1
    dist = [0] + [inf] * (n - 1)
    q = [(0, 0)]
    while q:
        u = heapq.heappop(q)[1]
        for (v, c) in edge[u]:
            alt = dist[u] + c
            if dist[v] > alt:
                dist[v] = alt
                heapq.heappush(q, (alt, v))
    return dist

n = int(input())
edge = [[]] * n
for _ in range(n):
    l = list(map(int, input().split()))
    edge[l[0]] = (e for e in zip(l[2::2], l[3::2]))
for i, c in enumerate(dijkstra(n)):
    print(i, c)

Submission status: Accepted

Solution code:
import heapq

def dijkstra_priorityqueue(s):
    global pq
    global d
    color=[0]*n
    d=[float('inf')]*n
    d[s]=0
    heapq.heappush(pq,[0,s])
    while len(pq)!=0:
        t,u=heapq.heappop(pq)
        color[u]=2
        if d[u]<t:
            continue
        j=-1
        for v in m[u][0::2]:
            j+=2
            if color[v]!= 2:
                if d[u]+m[u][j]<d[v]:
                    d[v]=d[u]+m[u][j]
                    color[v]=1
                    heapq.heappush(pq,[d[v],v])

n=input()
pq=[]
en=[]
m=[]
for i in xrange(n):
    en.append(map(int,raw_input().split()))
en.sort()
for i in xrange(n):
    m.append(en[i][2:])
dijkstra_priorityqueue(0)
for i in xrange(n):
    print i,d[i]

Submission status: Accepted

Solution code:
import heapq as hq

INF = 100000000

def dijkstra(n):
    global INF, W
    D = [INF] * n
    D[0] = 0
    Q = []
    hq.heappush(Q, (0, 0))

    while len(Q) != 0:
        minw, i = hq.heappop(Q)
        if D[i] < minw:
            continue
        for j in W[i].keys():
            w = W[i][j]
            if D[j] > D[i] + w:
                D[j] = D[i] + w
                hq.heappush(Q, (D[j], j))

    for i in range(n):
        print i, D[i]

n = int(input())
W = [{} for _ in range(n)]
for _ in range(n):
    l = map(int, raw_input().split())
    for i in range(l[1]):
        W[l[0]][l[2 * i + 2]] = l[2 * i + 3]

dijkstra(n)

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

class VCost:
    def __init__(self, v, cost):
        self.v_n = v
        self.cost = cost
    def __lt__(self, other):
        return self.cost < other.cost
    def __gt__(self, other):
        return self.cost > other.cost

adj = [[VCost(int(v), int(c)) for v, c in zip(x.split()[2::2], x.split()[3::2])] for x in f_i]

import heapq

def dijkstra():
    PQ = []
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    heapq.heappush(PQ, VCost(0, 0))
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc.v_n

        if uc.cost > distance[uc.v_n]:
            continue

        isVisited[u] = True
        
        for vc in adj[u]:
            v = vc.v_n
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + vc.cost
            if t_cost < distance[v]:
                distance[v] = t_cost = distance[u] + vc.cost
                heapq.heappush(PQ, VCost(v, t_cost))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

class VCost:
    def __init__(self, v, cost):
        self.v_n = v
        self.cost = cost
    def __lt__(self, other):
        return self.cost < other.cost
    def __gt__(self, other):
        return self.cost > other.cost

adj = [[VCost(int(v), int(c)) for v, c in zip(x.split()[2::2], x.split()[3::2])] for x in f_i]

import heapq

def dijkstra():
    PQ = []
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    heapq.heappush(PQ, VCost(0, 0))
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc.v_n

        if uc.cost > distance[uc.v_n]:
            continue

        isVisited[u] = True
        
        for vc in adj[u]:
            v = vc.v_n
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + vc.cost
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, VCost(v, t_cost))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[(int(cost), int(v_n)) for v_n, cost in zip(x.split()[2::2], x.split()[3::2])] for x in f_i]

import heapq

def dijkstra():
    PQ = []
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    heapq.heappush(PQ, (0, 0))
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc[1]

        if uc[0] > distance[u]:
            continue

        isVisited[u] = True
        
        for vc in adj[u]:
            v = vc[1]
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + vc[0]
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[(int(cost), int(v_n)) for v_n, cost in zip(x.split()[2::2], x.split()[3::2])] for x in f_i]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc[1]

        if uc[0] > distance[u]:
            continue

        isVisited[u] = True
        
        for vc in adj[u]:
            v = vc[1]
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + vc[0]
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[(int(cost), int(v_n)) for v_n, cost in zip(x.split()[2::2], x.split()[3::2])] for x in f_i]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc[1]
        
        for vc in adj[u]:
            v = vc[1]
            t_cost = distance[u] + vc[0]
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[]] * n
for x in f_i:
    x = list(map(int, x.split()))
    adj[x[0]] = [c_v for c_v in zip(x[3::2], x[2::2])]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc[1]

        if uc[0] > distance[u]:
            continue

        isVisited[u] = True
        
        for vc in adj[u]:
            v = vc[1]
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + vc[0]
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[]] * n
for x in f_i:
    x = list(map(int, x.split()))
    adj[x[0]] = [c_v for c_v in zip(x[3::2], x[2::2])]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc = heapq.heappop(PQ)
        u = uc[1]

        if uc[0] > distance[u]:
            continue

        isVisited[u] = True
        
        for c, v in adj[u]:
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + c
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[]] * n
for x in f_i:
    x = list(map(int, x.split()))
    adj[x[0]] = [c_v for c_v in zip(x[3::2], x[2::2])]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc, u = heapq.heappop(PQ)

        if uc > distance[u]:
            continue

        isVisited[u] = True
        
        for vc, v in adj[u]:
            if isVisited[v] == True:
                continue
            t_cost = distance[u] + vc
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[]] * n
for x in f_i:
    x = list(map(int, x.split()))
    adj[x[0]] = [c_v for c_v in zip(x[3::2], x[2::2])]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc, u = heapq.heappop(PQ)

        if uc > distance[u]:
            continue

        isVisited[u] = True
        
        for vc, v in adj[u]:
            if isVisited[v] == False:
                t_cost = distance[u] + vc
                if t_cost < distance[v]:
                    distance[v] = t_cost
                    heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[]] * n
for x in f_i:
    x = list(map(int, x.split()))
    adj[x[0]] = [c_v for c_v in zip(x[3::2], x[2::2])]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc, u = heapq.heappop(PQ)

        if uc <= distance[u]:
            isVisited[u] = True
        
            for vc, v in adj[u]:
                if isVisited[v] == False:
                    t_cost = distance[u] + vc
                    if t_cost < distance[v]:
                        distance[v] = t_cost
                        heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
n = int(input())

adj = [[]] * n
for i in range(n):
    x = list(map(int, input().split()))
    adj[x[0]] = [c_v for c_v in zip(x[3::2], x[2::2])]

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc, u = heapq.heappop(PQ)

        if uc > distance[u]:
            continue

        isVisited[u] = True
        
        for vc, v in adj[u]:
            if isVisited[v] == True:
                continue
            
            t_cost = distance[u] + vc
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import sys

f_i = sys.stdin

n = int(f_i.readline())

adj = [[]] * n
for x in f_i:
    x = list(map(int, x.split()))
    adj[x[0]] = (c_v for c_v in zip(x[3::2], x[2::2]))

import heapq

def dijkstra():
    PQ = [(0, 0)]
    isVisited = [False] * n
    distance = [999900001] * n

    distance[0] = 0
    
    while PQ:
        uc, u = heapq.heappop(PQ)

        if uc > distance[u]:
            continue

        isVisited[u] = True
        
        for vc, v in adj[u]:
            if isVisited[v] == True:
                continue
            
            t_cost = distance[u] + vc
            if t_cost < distance[v]:
                distance[v] = t_cost
                heapq.heappush(PQ, (t_cost, v))

    for v, d in enumerate(distance):
        print(v, d)


dijkstra()

Submission status: Accepted

Solution code:
import heapq
def Dsa(n):
    inf = 10 ** 6 + 1
    dt = [0] + [inf] * (n - 1)
    q = [(0, 0)]
    while q:
        u = heapq.heappop(q)[1]
        for (v, c) in ed[u]:
            alt = dt[u] + c
            if dt[v] > alt:
                dt[v] = alt
                heapq.heappush(q, (alt, v))
    return dt
 
n = int(input())
ed = [[]] * n
for _ in range(n):
    l = list(map(int, input().split()))
    ed[l[0]] = (e for e in zip(l[2::2], l[3::2]))
for i, c in enumerate(Dsa(n)):
    print(i, c)

Submission status: Accepted

Solution code:
import heapq as hq

def relax(u, v, w):
    if D[u] + w < D[v]:
        D[v] = D[u] + w
        P[v] = u
        hq.heappush(H, (D[v], v))

INF = float('inf')
N = int(input())
D = [INF for i in range(N)]
P = [None for i in range(N)]
D[0] = 0

G = [{} for i in range(N)]
for i in range(N):
    x = list(map(int, input().split()))
    g = x[2:]
    for j, n in enumerate(g):
        if j % 2 == 0:
            G[i][n] = g[j + 1]

H = [(0, 0)]

while 0 < len(H):
    d_u, u = hq.heappop(H)
    for v, w in G[u].items():
        relax(u, v, w)

for i, d in enumerate(D):
    print('{0} {1}'.format(i, d))