There are several (or no) spiders, butterflies, and dragonflies. 

In this kata, a spider has eight legs. A dragonfly or a butterfly has six legs. A __dragonfly__ has __two__ pairs of wings, while a __butterfly__ has __one__ pair of wings. __I am not sure whether they are biologically correct, but the values apply here. __

Given the number of total heads, legs, and __pairs of__ wings, please calculate numbers of each kind of bugs. Of course they are integers. 
_However, I do not guarantee that they are positive in the test cases. 
Please regard the minus numbers as cases that does not make sense. _

If answers make sense, return [n\_spider, n\_butterfly, n\_dragonfly]; 
else, please return [-1, -1, -1]. 

Example: 

cal\_n\_bug(3, 20, 3) = [1, 1, 1]
One spider, one butterfly, one dragonfly in total have three heads, twenty legs (8 for the spider, 6 for the butterfly, and 6 for the dragonfly), and _three pairs_ of wings (1 for the butterfly and 2 for the dragonfly).

Difficulty: EASY
Starter code: def cal_n_bug(n_head, n_leg, n_wing):
	

Solutions:
def cal_n_bug(n_head, n_leg, n_wing):
	spider = (n_leg - n_head * 6) // (8 - 6)
	butterfly = n_wing - (n_head - spider)
	dragonfly = n_head - spider - butterfly
	return [spider, butterfly, dragonfly] if spider >= 0 and butterfly >= 0 and (dragonfly >= 0) else [-1, -1, -1]


def cal_n_bug(n_head, n_leg, n_wing):
	s = (n_leg - 6 * n_head) / 2
	b = 8 * n_head - n_wing - n_leg
	d = s + n_wing - n_head
	return [s, b, d] if s >= 0 and b >= 0 and (d >= 0) else [-1, -1, -1]


def cal_n_bug(head, leg, wing):
	x = leg / 2 - head * 3
	head -= x
	y = head * 2 - wing
	z = head - y
	if all((n >= 0 for n in (x, y, z))):
		return [x, y, z]
	return [-1, -1, -1]


def cal_n_bug(n_head, n_leg, n_wing):
	n_s = (n_leg - 6 * n_head) / 2
	n_d = (n_leg - 8 * n_head + 2 * n_wing) / 2
	n_b = -n_leg + 8 * n_head - n_wing
	if n_s > -1 and n_d > -1 and (n_b > -1):
		return [n_s, n_b, n_d]
	else:
		return [-1, -1, -1]


def cal_n_bug(h, l, p):
	d = l / 2 - 4 * h + p
	b = p - 2 * d
	s = h - d - b
	return [-1, -1, -1] if s < 0 or b < 0 or d < 0 else [s, b, d]


def cal_n_bug(h, l, w):
	lst = [l // 2 - 3 * h, 8 * h - l - w, w - 4 * h + l // 2]
	return lst if lst[0] >= 0 and lst[1] >= 0 and (lst[2] >= 0) else [-1, -1, -1]


def cal_n_bug(n_head, n_leg, n_wing):
	if n_head < 0 or n_leg < 0 or n_wing < 0:
		return [-1, -1, -1]
	x = n_leg - 6 * n_head
	y = 8 * n_head - n_leg - n_wing
	z = n_leg + 2 * n_wing - 8 * n_head
	if x % 2 != 0 or z % 2 != 0 or x < 0 or (y < 0) or (z < 0):
		return [-1, -1, -1]
	return [x // 2, y, z // 2]


def cal_n_bug(heads, legs, wings):
	spiders = legs // 2 - heads * 3
	dragonflies = wings + spiders - heads
	r = [spiders, heads - spiders - dragonflies, dragonflies]
	return r if all((x >= 0 for x in r)) else [-1] * 3


def cal_n_bug(h, l, w):
	if h < 0 or l < 0 or w < 0 or l % 2 or (l < 6 * h) or (l > 8 * h):
		return [-1, -1, -1]
	(d, b) = (w // 2, w % 2)
	s = h - d - b
	return [h - d - b, b, d] if s * 8 + d * 6 + b * 6 == l else [-1, -1, -1]


import numpy as np

def cal_n_bug(x, y, z):
	a = np.array([[1, 1, 1], [8, 6, 6], [0, 2, 1]])
	b = np.array([x, y, z])
	s = np.linalg.solve(a, b)
	return list(map(int, s)) if all((x >= 0 for x in s)) else [-1, -1, -1]