A balanced parenthesis string is defined as follows:
- The empty string is balanced
- If P is balanced, (P) is also 
- If P and Q are balanced, PQ is also balanced
You are given two even integers n$n$ and k$k$. Find any balanced paranthesis string of length n$n$ that doesn't contain a balanced substring of length k$k$, or claim that no such string exists.

-----Input-----
- First line will contain T$T$, number of testcases. Then the testcases follow. 
- Each testcase contains of a single line containing n$n$ and k$k$.

-----Output-----
For every testcase, print on a new line, any balanced paranthesis string of length n$n$ that doesn't contain a balanced substring of length k$k$. If there doesn't exist any such string, print −1$-1$ instead.

-----Constraints-----
- 1≤T≤50000$1 \leq T \leq 50000$
- 2≤k≤n≤105$2 \leq k \leq n \leq 10^5$
- Sum of n$n$ over all testcases doesn't exceed 105$10^5$.
- n$n$ and k$k$ are both even integers.

-----Example Input-----
2
4 2
8 6

-----Example Output-----
-1
(())(())

-----Explanation-----
In the first testcase, the only balanced strings of length 4$4$ are (()) and ()(), both of which contain () as a substring.
In the second testcase, (())(()) is a balanced string that doesn't contain any balanced substring of length 6$6$.

Difficulty: UNKNOWN_DIFFICULTY

Solutions:
import sys

def input():
	return sys.stdin.readline().strip()
for i in range(int(input())):
	(n, k) = map(int, input().split())
	arr = []
	if k == 2 or k == 4 or n % 2 != 0 or (n == k):
		arr.append('-1')
	elif k % 2 != 0:
		for i in range(int(n / 2)):
			arr.append('(')
		for i in range(int(n / 2)):
			arr.append(')')
	elif int(n / (k - 2)) == 1:
		if (n - 2) % 4 == 0:
			for i in range(int((n - 2) / 4)):
				arr.append('(')
			for i in range(int((n - 2) / 4)):
				arr.append(')')
			arr.append('()')
			for i in range(int((n - 2) / 4)):
				arr.append('(')
			for i in range(int((n - 2) / 4)):
				arr.append(')')
		else:
			for i in range(int((n - 4) / 4)):
				arr.append('(')
			for i in range(int((n - 4) / 4)):
				arr.append(')')
			arr.append('(())')
			for i in range(int((n - 4) / 4)):
				arr.append('(')
			for i in range(int((n - 4) / 4)):
				arr.append(')')
	else:
		for i in range(int(n % (k - 2) / 2)):
			arr.append('(')
		for i in range(int(n / (k - 2))):
			for j in range(int((k - 2) / 2)):
				arr.append('(')
			for j in range(int((k - 2) / 2)):
				arr.append(')')
		for i in range(int(n % (k - 2) / 2)):
			arr.append(')')
	print(''.join(arr))


a = int(input())
while a != 0:
	(b, c) = map(int, input().split())
	p = c - 2
	if p == 0 or p == 2 or b == c:
		print(-1)
	else:
		q = b // p
		r = b % p
		k = 0
		if p + r == c:
			print('(', end='')
			while k != q:
				for i in range(1, p + 1):
					if i <= p // 2:
						print('(', end='')
					else:
						print(')', end='')
				k += 1
			print(')')
			a -= 1
			print()
			continue
		while k != q:
			for i in range(1, p + 1):
				if i <= p // 2:
					print('(', end='')
				else:
					print(')', end='')
			k += 1
		for i in range(1, r + 1):
			if i <= r // 2:
				print('(', end='')
			else:
				print(')', end='')
		print()
	a -= 1