Kevin is noticing his space run out! Write a function that removes the spaces from the values and returns an array showing the space decreasing.
For example, running this function on the array ['i', 'have','no','space'] would produce ['i','ihave','ihaveno','ihavenospace'].

Difficulty: EASY
Starter code: def spacey(array):
	

Solutions:
from itertools import accumulate

def spacey(a):
	return list(accumulate(a))


def spacey(array):
	return [''.join(array[:i + 1]) for i in range(len(array))]


def spacey(array):
	strr = ''
	out = []
	for el in array:
		strr += str(el)
		out.append(strr)
	return out


def spacey(array):
	return [''.join(array[:i]) for (i, _) in enumerate(array, 1)]


from itertools import accumulate

def spacey(array):
	return list(accumulate(array))


def spacey(array):
	new_s = []
	s = ''
	for i in array:
		s += i
		new_s.append(s)
	return new_s


from functools import reduce

def spacey(array):
	return reduce(lambda a, b: a + [a[-1] + b] if a else [b], array, [])


def spacey(array):
	if len(array) != 0:
		string = [array[0]]
		for index in range(2, len(array) + 1):
			for i in range(index - 1, index):
				string = string + [string[i - 1] + array[i]]
		return string
	else:
		return array


spacey = lambda a: list(__import__('itertools').accumulate(a))


from itertools import accumulate

def spacey(array):
	return list(map(''.join, accumulate(array)))