Chef had an array A with length N, but some of its elements got lost. Now, each element of this array is either unknown (denoted by -1) or a positive integer not exceeding K.
Chef decided to restore the array A by replacing each unknown element by a positive integer not exceeding K.
However, Chef has M restrictions that must hold for the restored array. There are two types of restrictions:

- I L R, meaning that for each i such that L < i ≤ R, the condition Ai - Ai-1 = 1 should be satisfied.
- D L R, meaning that for each i such that L < i  ≤ R, the condition Ai - Ai-1 = -1 should be satisfied.

Chef would like to know the number of ways to restore the array while satisfying all restrictions, modulo 109+7.

-----Input-----
- The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.
- The first line of each test case contains three space-separated integers N, M and K.
- The second line contains N integers A1, A2, ..., AN.
- Each of the following M lines contains one restriction in the form I L R or D L R.

-----Output-----
For each test case, print a single line containing one integer - the number of ways to restore the array modulo 109+7.

-----Constraints-----
- 1 ≤ T ≤ 10
- 1 ≤ N, M ≤ 100,000
- 1 ≤ K ≤ 1,000,000,000
- 1 ≤ L < R ≤ N
- 1 ≤ Ai ≤ K or Ai = -1 for each valid i
- 1 ≤ sum of N over all test cases ≤ 500,000
- 1 ≤ sum of M over all test cases ≤ 500,000

-----Example-----
Input:

3
4 2 10
2 3 5 4
I 1 2 
D 3 4
5 2 10
-1 -1 -1 -1 -1
I 1 3
D 3 5
6 2 2
-1 -1 -1 -1 -1 -1
I 1 4
D 4 6

Output:

1
8
0

Difficulty: VERY_HARD

Solutions:
mod = 10 ** 9 + 7
for t in range(int(input())):
	(N, M, K) = map(int, input().split())
	A = list(map(int, input().split()))
	(I, D) = ([0] * (N + 2), [0] * (N + 2))
	for i in range(M):
		(x, L, R) = input().split()
		(L, R) = (int(L), int(R))
		if x == 'I':
			I[L] += 1
			I[R] -= 1
		else:
			D[L] += 1
			D[R] -= 1
	impossibru = mx = mn = 0
	ans = 1
	for i in range(N):
		I[i] += I[i - 1]
		D[i] += D[i - 1]
		if I[i] and D[i]:
			impossibru = 1
			break
		if not I[i] and (not D[i]):
			ans = ans * (mx - mn + 1) % mod
			(mn, mx) = (1, K)
		elif I[i]:
			mx = min(mx + 1, K)
			mn += 1
		elif D[i]:
			mn = max(1, mn - 1)
			mx -= 1
		if mn > mx:
			impossibru = 1
			break
		if A[i] != -1:
			if not mn <= A[i] <= mx:
				impossibru = 1
				break
			mn = mx = A[i]
	ans = ans * (mx - mn + 1) % mod
	print(0 if impossibru else ans)