Simple, given a string of words, return the length of the shortest word(s).

String will never be empty and you do not need to account for different data types.

Difficulty: EASY
Starter code: def find_short(s):
	

Solutions:
def find_short(s):
	return min((len(x) for x in s.split()))


def find_short(s):
	return len(min(s.split(' '), key=len))


def find_short(s):
	return min(map(len, s.split(' ')))


def find_short(s):
	return min((len(a) for a in s.split()))


def find_short(s):
	sList = s.split()
	shortestLength = len(sList[0])
	for item in sList:
		if len(item) < shortestLength:
			shortestLength = len(item)
	return shortestLength


def find_short(s):
	return len(sorted(s.split(), key=len)[0])


def find_short(s):
	l = 100000
	a = s.split(' ')
	for i in a:
		if len(i) < l:
			l = len(i)
	return l


def find_short(s):
	return min([len(i) for i in s.split()])


find_short = lambda s: min((len(e) for e in s.split()))