You were given a string of integer temperature values. Create a function `close_to_zero(t)` and return the closest value to 0 or `0` if the string is empty. If two numbers are equally close to zero, return the positive integer.

Difficulty: EASY
Starter code: def close_to_zero(t):
	

Solutions:
def close_to_zero(t):
	if len(t) == 0:
		return 0
	x = t.split(' ')
	l = []
	poz = []
	neg = []
	for i in x:
		l.append(int(i))
	for i in l:
		if i == 0:
			return 0
		if i > 0:
			poz.append(i)
		if i < 0:
			neg.append(i)
	if 0 - min(poz) == max(neg):
		return min(poz)
	if 0 - min(poz) > max(neg):
		return min(poz)
	else:
		return max(neg)


def close_to_zero(t):
	n = min([int(s) for s in t.split()] or [0], key=abs)
	return abs(n) if str(-n) in t.split() else n


def close_to_zero(t):
	return min((int(n) for n in t.split()), key=lambda n: (abs(n), n < 0), default=0)


def close_to_zero(t):
	return sorted(map(int, t.split()), key=lambda i: (abs(i), -i))[0] if t else 0


def close_to_zero(t):
	T = [int(v) for v in t.split()]
	return T and sorted(sorted(T, reverse=True), key=abs)[0] or 0


def close_to_zero(t):
	t = [int(x) for x in t.split()]
	return min(t or [0], key=lambda t: (abs(t), -t))


close_to_zero = lambda t: min(map(int, t.split()), key=lambda n: (abs(n), -n), default=0)


def close_to_zero(t):
	return 0 if not t else int(min(sorted(t.split(), reverse=True), key=lambda x: abs(int(x))))