# Sort an array by value and index

Your task is to sort an array of integer numbers by the product of the value and the index of the positions.

For sorting the index starts at 1, NOT at 0!
The sorting has to be ascending.
The array will never be null and will always contain numbers.

Example:
```
Input: 23, 2, 3, 4, 5
Product of value and index:
23 => 23 * 1 = 23  -> Output-Pos 4
 2 =>  2 * 2 = 4   -> Output-Pos 1
 3 =>  3 * 3 = 9   -> Output-Pos 2
 4 =>  4 * 4 = 16  -> Output-Pos 3
 5 =>  5 * 5 = 25  -> Output-Pos 5

Output: 2, 3, 4, 23, 5
```

Have fun coding it and please don't forget to vote and rank this kata! :-) 

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Difficulty: EASY
Starter code: def sort_by_value_and_index(arr):
	

Solutions:
def sort_by_value_and_index(arr):
	return [y[1] for y in sorted(enumerate(arr), key=lambda x: (x[0] + 1) * x[1])]


def sort_by_value_and_index(arr):
	return [b for (_, b) in sorted(enumerate(arr, 1), key=lambda x: int.__mul__(*x))]


def sort_by_value_and_index(arr):
	return [b for (_, b) in sorted(enumerate(arr, 1), key=lambda a: a[0] * a[1])]


def sort_by_value_and_index(arr):
	return [e for (i, e) in sorted(enumerate(arr, 1), key=lambda t: t[0] * t[1])]


def sort_by_value_and_index(arr):
	return [elem[1] for elem in sorted(enumerate(arr, 1), key=lambda elem: elem[0] * elem[1])]


import itertools

def sort_by_value_and_index(nums):
	seq = itertools.count(1)
	return sorted(nums, key=lambda num: num * next(seq))


def sort_by_value_and_index(arr):
	arr = zip(range(1, len(arr) + 1), arr)
	return [x[1] for x in sorted(arr, key=lambda x: x[0] * x[1])]


def sort_by_value_and_index(arr):
	vals = [(index + 1) * element for (index, element) in enumerate(arr)]
	newList = [(i, j) for (i, j) in zip(vals, arr)]
	newList = sorted(newList, key=lambda element: element[0])
	return [i[1] for i in newList]


sort_by_value_and_index = lambda arr: [elem for (key, original_index, elem) in sorted(((i * elem, i, elem) for (i, elem) in enumerate(arr, 1)))]