Find the volume of a cone whose radius and height are provided as parameters to the function `volume`. Use the value of PI provided by your language (for example: `Math.PI` in JS, `math.pi` in Python or `Math::PI` in Ruby) and round down the volume to an Interger.

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Difficulty: EASY
Starter code: def volume(r,h):
	

Solutions:
from math import pi

def volume(r, h):
	return pi * r ** 2 * h // 3


from math import pi

def volume(r, h):
	return int(pi * r * r * h / 3)


import math

def volume(r, h):
	return math.floor(1 / 3 * math.pi * r ** 2 * h)


from math import pi

def volume(r, h):
	return int(1 / 3 * pi * r ** 2 * h)


volume = lambda r, h: __import__('math').pi * r * r * h // 3