Chef has two numbers X and Y. Chef wants to find three integers A, B, and C such that:
-1000 ≤ A, B, C ≤ 1000
mean([A, B, C]) = X
median([A, B, C]) = Y

Can you help Chef find such three integers?

As a reminder, mean([P, Q, R]) = \frac{P + Q + R}{3} and median([P, Q, R]) is the element at the 2^{nd} (middle) position after we sort [P, Q, R] in non-decreasing order.

------ Input Format ------ 

- The first line contains a single integer T — the number of test cases. Then the test cases follow.
- The first and only line of each test case contains two space-separated integers X and Y — the required mean and median of the three integers.

------ Output Format ------ 

For each test case, output three integers A, B, C which satisfy the given conditions.

It is guaranteed that an answer always exists under the given constraints.
 
If multiple answers exist, output any.

------ Constraints ------ 

$1 ≤ T ≤ 10^{5}$
$-100 ≤X, Y ≤100$

----- Sample Input 1 ------ 
3
5 5
67 100
4 5

----- Sample Output 1 ------ 
5 5 5
0 100 101
0 5 7
----- explanation 1 ------ 
Test Case 1: $mean([5, 5, 5]) = \frac{5 + 5 + 5}{3} = 5$, $median([5, 5, 5]) = 5$.

Test Case 2: $mean([0, 100, 101]) = \frac{0 + 100 + 101}{3} = \frac{201}{3} = 67$, $median([0, 100, 101]) = 100$.

Test Case 3: $mean([0, 5, 7]) = \frac{0 + 5 + 7}{3} = 4$, $median([0, 5, 7]) = 5$.

Difficulty: EASY

Solutions:
T = int(input())
for i in range(T):
	line = input().split(' ')
	X = int(line[0])
	B = Y = int(line[1])
	if X == Y:
		print(line[0] + ' ' + line[0] + ' ' + line[0])
	else:
		if B > 0:
			A = 0
		elif B == 0:
			A = -1
		else:
			A = 2 * B
		C = 3 * X - A - B
		while C < B:
			if C <= A:
				A = A - (B - C)
			else:
				A = A + (B - C)
			C = 3 * X - A - B
		print(str(A) + ' ' + str(B) + ' ' + str(C))