Eric is the teacher of graph theory class. Today, Eric teaches independent set and edge-induced subgraph.

Given a graph $G=(V,E)$, an independent set is a subset of vertices $V' \subset V$ such that for every pair $u,v \in V'$, $(u,v) \not \in E$ (i.e. no edge in $E$ connects two vertices from $V'$).

An edge-induced subgraph consists of a subset of edges $E' \subset E$ and all the vertices in the original graph that are incident on at least one edge in the subgraph.

Given $E' \subset E$, denote $G[E']$ the edge-induced subgraph such that $E'$ is the edge set of the subgraph. Here is an illustration of those definitions: [Image] 

In order to help his students get familiar with those definitions, he leaves the following problem as an exercise:

Given a tree $G=(V,E)$, calculate the sum of $w(H)$ over all except null edge-induced subgraph $H$ of $G$, where $w(H)$ is the number of independent sets in $H$. Formally, calculate $\sum \limits_{\emptyset \not= E' \subset E} w(G[E'])$.

Show Eric that you are smarter than his students by providing the correct answer as quickly as possible. Note that the answer might be large, you should output the answer modulo $998,244,353$.


-----Input-----

The first line contains a single integer $n$ ($2 \le n \le 3 \cdot 10^5$), representing the number of vertices of the graph $G$.

Each of the following $n-1$ lines contains two integers $u$ and $v$ ($1 \le u,v \le n$, $u \not= v$), describing edges of the given tree.

It is guaranteed that the given edges form a tree.


-----Output-----

Output one integer, representing the desired value modulo $998,244,353$.


-----Examples-----
Input
2
2 1

Output
3

Input
3
1 2
3 2

Output
11



-----Note-----

For the second example, all independent sets are listed below. $\vdots : \vdots : \vdots$

Difficulty: MEDIUM

Solutions:
import sys
input = sys.stdin.readline
n = int(input())
mod = 998244353
E = [[] for i in range(n + 1)]
for i in range(n - 1):
	(x, y) = map(int, input().split())
	E[x].append(y)
	E[y].append(x)
ROOT = 1
QUE = [ROOT]
Parent = [-1] * (n + 1)
Parent[ROOT] = n + 1
TOP_SORT = []
while QUE:
	x = QUE.pop()
	TOP_SORT.append(x)
	for to in E[x]:
		if Parent[to] == -1:
			Parent[to] = x
			QUE.append(to)
DP0 = [1] * (n + 1)
DP1 = [1] * (n + 1)
DP2 = [1] * (n + 1)
DP3 = [1] * (n + 1)
for x in TOP_SORT[::-1]:
	if x != 1 and len(E[x]) == 1:
		DP0[x] = 1
		DP1[x] = 1
		DP2[x] = 0
		DP3[x] = 1
		continue
	ANS0 = 1
	ANS2 = 1
	ANS3 = 1
	for to in E[x]:
		if to == Parent[x]:
			continue
		ANS0 = ANS0 * (DP0[to] + DP1[to] + DP2[to] + DP3[to]) % mod
		ANS2 = ANS2 * (DP0[to] + DP2[to]) % mod
		ANS3 = ANS3 * (DP0[to] + DP1[to] + DP2[to]) % mod
	DP0[x] = ANS0
	DP1[x] = ANS0
	DP2[x] = ANS3 - ANS2
	DP3[x] = ANS3
print((DP0[1] + DP2[1] - 1) % mod)


import sys
readline = sys.stdin.readline

def ParentOrder(Edge, p):
	N = len(Edge)
	par = [0] * N
	par[p] = -1
	stack = [p]
	order = []
	visited = set([p])
	ast = stack.append
	apo = order.append
	while stack:
		vn = stack.pop()
		apo(vn)
		for vf in Edge[vn]:
			if vf in visited:
				continue
			visited.add(vf)
			par[vf] = vn
			ast(vf)
	return (par, order)

def GetChild(p):
	res = [[] for _ in range(len(p))]
	for (i, v) in enumerate(p[1:], 1):
		res[v].append(i)
	return res
N = int(readline())
MOD = 998244353
Edge = [[] for _ in range(N)]
for _ in range(N - 1):
	(a, b) = map(int, readline().split())
	a -= 1
	b -= 1
	Edge[a].append(b)
	Edge[b].append(a)
(P, L) = ParentOrder(Edge, 0)
C = GetChild(P)
dp = [[1, 1, 0, 0, 1] for _ in range(N)]
for p in L[::-1]:
	if not C[p]:
		continue
	res = 1
	res2 = 1
	res3 = 1
	for ci in C[p]:
		res = res * (dp[ci][2] + dp[ci][3] + dp[ci][4]) % MOD
		res2 = res2 * (dp[ci][1] + dp[ci][2] + 2 * dp[ci][3] + dp[ci][4]) % MOD
		res3 = res3 * (sum(dp[ci]) + dp[ci][2] + dp[ci][3]) % MOD
	dp[p][0] = res
	dp[p][1] = res
	dp[p][2] = (res2 - res) % MOD
	dp[p][3] = (res3 - res) % MOD
	dp[p][4] = res
print((dp[0][2] + dp[0][3] + dp[0][4] - 1) % MOD)