Find the difference between two collections. The difference means that either the character is present in one collection or it is present in other, but not in both. Return a sorted set with difference.

The collections can contain any character and can contain duplicates.

For instance:

A = [a,a,t,e,f,i,j]

B = [t,g,g,i,k,f]

difference = [a,e,g,j,k]

Difficulty: EASY
Starter code: def diff(a, b):
	

Solutions:
def diff(a, b):
	return sorted(set(a) ^ set(b))


def diff(a, b):
	a = set(a)
	b = set(b)
	c = a.symmetric_difference(b)
	return sorted(list(c))


diff = lambda a, b: sorted(set([e for e in a if e not in b] + [e for e in b if e not in a]))


def diff(a, b):
	c = []
	for i in a:
		if i not in b and i not in c:
			c.append(i)
	for i in b:
		if i not in a and i not in c:
			c.append(i)
	return sorted(c)


def diff(a, b):
	first = []
	second = []
	for element in a:
		if element not in b:
			first.append(element)
	for word in b:
		if word not in a:
			second.append(word)
	third = first + second
	third = sorted(third)
	for element in third:
		if third.count(element) > 1:
			third.remove(element)
	return third


def diff(a, b):
	output = []
	for elem in a:
		if elem not in b:
			output.append(elem)
	for elem in b:
		if elem not in a:
			output.append(elem)
	return sorted(list(set(output)))