Let's consider a rectangular table R consisting of N rows and M columns. Rows are enumerated from 1  to N from top to bottom. Columns are enumerated from 1 to M from left to right. Each element of R is a non-negative integer. R is called steady if the sum of elements in the ith row is not less then the sum of elements in the (i-1)th row for each i where 2 ≤ i ≤ N and the sum of elements in the Nth row is less than or equal to M. Your task is to find the number of different steady tables of size N x M modulo 1 000 000 000. 

-----Input-----
The first line of input contains a single integer T denoting number of test cases. First and the only line of each test case contains two space separated integers N and M denoting the number of rows and columns respectively.

-----Output-----
For each test case, print a single integer corresponding to the answer.

-----Constraints-----
- 1 ≤ T ≤ 10
- 1 ≤ N, M ≤ 2000

-----Subtasks-----
- Subtask 1 : 1 ≤ T ≤ 10 , 1 ≤ N,M ≤ 50 : ( 23 pts )
- Subtask 2 : 1 ≤ T ≤ 10 , 1 ≤ N,M ≤ 500 : ( 29 pts )
- Subtask 3 : 1 ≤ T ≤ 10 , 1 ≤ N,M ≤ 2000 : ( 48 pts )

-----Example-----
Input:
3
1 1
2 2
2 3
Output:
2
25
273

-----Explanation-----
Test case 1 : There are only 2 such grids possible 0 and 1.

Difficulty: MEDIUM_HARD

Solutions:
def compute_nCr(n, r):
	C[0][0] = 1
	for i in range(1, n + 1):
		C[i][0] = 1
		for j in range(1, min(i, r) + 1):
			if i != j:
				C[i][j] = (C[i - 1][j - 1] + C[i - 1][j]) % MOD
			else:
				C[i][j] = 1

def solve(n, m):
	store = [C[m + i - 1][i] for i in range(m + 1)]
	for i in range(1, n + 1):
		s = 1
		for j in range(1, m + 1):
			s = (s + store[j]) % MOD
			store[j] = s * C[m + j - 1][j] % MOD
	return s
MOD = 1000000000
LIMIT = 2000
C = [[0] * (LIMIT + 1) for _ in range(2 * LIMIT + 1)]
compute_nCr(2 * LIMIT, LIMIT)
t = int(input())
while t:
	(n, m) = list(map(int, input().split()))
	print(solve(n, m))
	t -= 1


import sys
if sys.version_info > (3,):
	long = int
	xrange = range

def choose(n, k):
	ntok = 1
	ktok = 1
	for t in xrange(1, min(k, n - k) + 1):
		ntok *= n
		ktok *= t
		n -= 1
	return ntok // ktok

def C(X, M):
	return choose(X + M - 1, M - 1)
import numpy as np

def R(N, M):
	Base = [C(0, M)]
	for i in range(1, M + 1):
		Base.append(Base[i - 1] * (M + i - 1) // i)
	Base = np.array([i % 1000000000 for i in Base], dtype=np.int64)
	Next = Base[:]
	for i in range(1, N):
		Next = np.multiply(Base, np.cumsum(Next) % 1000000000, dtype=np.int64) % 1000000000
	return sum((i for i in Next)) % 1000000000
T = int(input())
for i in range(T):
	(N, M) = list(map(int, input().split()))
	print(R(N, M))