Given an array nums of integers, return how many of them contain an even number of digits.
 
Example 1:
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:
Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

 
Constraints:

1 <= nums.length <= 500
1 <= nums[i] <= 10^5

Difficulty: EASY
Starter code: class Solution:
    def findNumbers(self, nums: List[int]) -> int:
        

Solutions:
class Solution:

	def findNumbers(self, nums: List[int]) -> int:

		def has_even_digits(number: int):
			if number < 10:
				return False
			elif number < 100:
				return True
			elif number < 1000:
				return False
			elif number < 10000:
				return True
			elif number < 100000:
				return False
			return True
		return sum([1 for num in nums if has_even_digits(num)])


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		return len([i for i in nums if len(str(i)) % 2 == 0])


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		return sum([1 if len(str(num)) % 2 == 0 else 0 for num in nums])


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		ec = 0
		digit = 0
		for value in nums:
			digit = len(str(value))
			if digit % 2 == 0:
				ec += 1
		return ec


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		count = 0
		track = 0
		for num in nums:
			count = 0
			if len(str(num)) % 2 == 0:
				track += 1
		return track


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		count = 0
		string_map = map(str, nums)
		for i in string_map:
			if len(i) % 2 == 0:
				count += 1
		return count


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		nums.sort()
		ans = 0
		for i in nums:
			if i >= 10 and i < 100 or (i >= 1000 and i < 10000) or (i >= 100000 and i < 1000000):
				ans += 1
		return ans


class Solution:

	def findNumbers(self, nums: List[int]) -> int:
		result = 0
		for num in nums:
			count = 0
			while num:
				num = num // 10
				count += 1
			if count % 2 == 0:
				result += 1
		return result


class Solution:

	def digits(self, num):
		count = 0
		while num:
			num = num // 10
			count += 1
		if count % 2 == 0:
			return True
		else:
			return False

	def findNumbers(self, nums: List[int]) -> int:
		c = 0
		for i in nums:
			if Solution().digits(i):
				c += 1
		return c