Bohan loves milk tea so much and he drinks one cup of milk tea every day. The local shop sells milk tea in two sizes: a Medium cup for $3 and a Large cup for $4. For every cup of milk tea purchased Bohan receives a promotional stamp. Bohan may redeem 6 stamps for a free drink of milk tea regardless of the size. No stamp will be given for a free drink.


Determine the amount of money Bohan have spent on milk tea, given a sequence of milk tea sizes he got in the past a few days. Assume Bohan had no stamps in the beginning and he always redeemed the stamps for the next drink once he had collected 6 stamps.

-----Input-----
The input begins with the number of test cases T.
Each test case has a single line of letters. The i-th letter is either 'M' or 'L' denoting a Medium cup or a Large cup of milk tea Bohan got on the i-th day.

-----Output-----
For each case, output the amount of money in dollars Bohan have spent on milk tea.

-----Constraints-----
- T ≤ 100 
- 1 ≤  length of each sequence ≤ 100 

-----Example-----
Input:
3
MLM
MMLLMMLL
MMMMMMML

Output:
10
24
22

-----Explanation-----
Example 1: Bohan didn't redeem any stamps.
Example 2: Bohan redeemed 6 stamps for the Large cup of milk tea on the 7th day.
Example 3: Bohan redeemed 6 stamps for the Medium cup of milk tea on the 7th day.

Difficulty: UNKNOWN_DIFFICULTY

Solutions:
t = int(input())
for tc in range(t):
	seq = input()
	dollar = 0
	stamp = 0
	for ct in seq:
		if stamp >= 6:
			stamp -= 6
			continue
		elif ct == 'M':
			dollar += 3
		elif ct == 'L':
			dollar += 4
		stamp += 1
	print(dollar)


t = int(input())
while t > 0:
	t -= 1
	s = input()
	val = 0
	ctr = 0
	for i in s:
		if ctr == 6:
			ctr = 0
		elif i == 'M':
			val += 3
			ctr += 1
		else:
			val += 4
			ctr += 1
	print(val)


t = eval(input())
while t > 0:
	p = input()
	count = 0
	cost = 0
	i = 0
	while i < len(p):
		if count == 6:
			count = 0
			i = i + 1
			continue
		if p[i] == 'M':
			cost = cost + 3
		else:
			cost = cost + 4
		count = count + 1
		i = i + 1
	print(cost)
	t = t - 1


t = int(input())
for _ in range(t):
	a = input()
	c = 0
	m = 0
	for i in range(len(a)):
		if c == 6:
			c = 0
			continue
		if a[i] == 'M':
			m += 3
			c += 1
			continue
		if a[i] == 'L':
			m += 4
			c += 1
			continue
	print(m)


for _ in range(eval(input())):
	l = list(map(str, input().strip()))
	print(sum([3 if j == 'M' else 4 for (i, j) in enumerate(l) if (i + 1) % 7 != 0]))


def f(s):
	s = list(s)
	cost = count = 0
	for i in s:
		if count == 6:
			count = 0
			continue
		else:
			count += 1
			if i == 'M':
				cost += 3
			else:
				cost += 4
	return cost
t = int(input())
for i in range(t):
	s = input()
	print(f(s))