Apple considers any iPhone with a battery health of 80\% or above, to be in *optimal* condition. 

Given that your iPhone has X\% battery health, find whether it is in *optimal* condition.

------ Input Format ------ 

- The first line of input will contain a single integer T, denoting the number of test cases.
- The first and only line of each test case contains an integer X — the battery health.

------ Output Format ------ 

For each test case, output on a new line, YES, if the battery is in *optimal* condition, and NO otherwise.

You may print each character in uppercase or lowercase. For example, NO, no, No and nO, are all considered identical.

------ Constraints ------ 

$1 ≤ T ≤ 100$
$0 ≤ X ≤ 100$

----- Sample Input 1 ------ 
4
97
42
80
10

----- Sample Output 1 ------ 
YES
NO
YES
NO

----- explanation 1 ------ 
Test case $1$: The battery health is $97 \%$ which is greater than equal to $80 \%$. Thus, the battery is in optimal condition.

Test case $2$: The battery health is $42 \%$ which is less than $80 \%$. Thus, the battery is not in optimal condition.

Test case $3$: The battery health is $80 \%$ which is greater than equal to $80 \%$. Thus, the battery is in optimal condition.

Test case $4$: The battery health is $10 \%$ which is less than $80 \%$. Thus, the battery is not in optimal condition.

Difficulty: EASY

Solutions:
m = int(input())
for i in range(m):
	per = int(input())
	if per >= 80:
		print('YES')
	else:
		print('NO')


T = int(input())
for i in range(T):
	X = int(input())
	if X >= 80:
		print('YES')
	else:
		print('NO')


t = int(input())
for i in range(t):
	x = int(input())
	if x >= 80:
		print('YES')
	else:
		print('NO')


def iphone_battery(X):
	if X >= 80:
		return 'YES'
	else:
		return 'NO'
N = int(input())
for i in range(N):
	X = int(input())
	print(iphone_battery(X))


t = int(input())
for _ in range(t):
	b = int(input())
	print('YES' if b >= 80 else 'NO')


for _ in range(int(input())):
	n = int(input())
	if n >= 80:
		print('YES')
	else:
		print('NO')


n = int(input())
for i in range(n):
	a = int(input())
	if a >= 80:
		print('YES')
	else:
		print('NO')


def is_optimal(health):
	return health >= 80
t = int(input())
for i in range(t):
	health = int(input())
	if is_optimal(health):
		print('YES')
	else:
		print('NO')


test = int(input())
ans = []
while test:
	test = test - 1
	X = int(input())
	if X >= 80:
		ans.append('YES')
	else:
		ans.append('NO')
for i in ans:
	print(i)


Test = int(input())
for _ in range(Test):
	X = int(input())
	if X >= 80:
		print('YES')
	else:
		print('NO')


a = int(input())
l = []
for i in range(0, a):
	aa = int(input())
	if aa > 80 or aa == 80:
		l.append('YES')
	else:
		l.append('NO')
for i in l:
	print(i)


test_cases = int(input())
for i in range(test_cases):
	battery = int(input())
	if battery >= 80:
		print('YES')
	else:
		print('NO')


t = int(input())
while t > 0:
	x = int(input())
	if x >= 80:
		print('YES')
	else:
		print('NO')
	t -= 1


m = int(input())
for _ in range(m):
	x = int(input())
	if x >= 80:
		print('YES')
	else:
		print('NO')


tc = int(input())
for i in range(tc):
	battrey = int(input())
	if battrey >= 80:
		print('YES')
	else:
		print('NO')


t = int(input())

def iphone(t):
	for i in range(1, t + 1):
		x = int(input())
		if x >= 80:
			print('YES')
		else:
			print('NO')
iphone(t)