Students are taught to add multi-digit numbers from right-to-left one digit at a time.
Many find the "carry" operation - in which 1 is carried from one digit position
to be added to the next - to be a significant challenge.  Your job is to
count the number of carry operations for each of addition problem so that educators may assess their difficulty.

For the input first line contains n number of records which is less then 1000. And then each line contains two numbers with spacing between them as shown in sample. 

SAMPLE INPUT
3
123 456
555 555
123 594

SAMPLE OUTPUT
No carry operation
3 carry operations
1 carry operation

Explanation

EXAMPLE 1:-

when the digits are added then there is no carry found as 3+6=9,2+5=7 and 1+4=5.

EXAMPLE 2:-

when the digits are added then carry is generated as 5+5 =10 so carry is found 3 times.

EXAMPLE 3:-

when the digits 9 and 2 are added only then carry is found so 1 time only.

Difficulty: UNKNOWN_DIFFICULTY

Solutions:
t = int(input())
for i in range(t):
	i1 = list(map(int, input().split(' ')))
	carryCount = 0
	carry = 0
	
	while i1[0] != 0 and i1[1] != 0:
		#print i1[0] % 10 + i1[1] % 10 + carry
		if i1[0] % 10 + i1[1] % 10 + carry > 9:
			carryCount = carryCount + 1
			#print carryCount
			carry = 1
		else:
			carry = 0
		i1[0] = i1[0] / 10
		i1[1] = i1[1] / 10
	#print "dasd", carryCount
	if carryCount == 0:
		print("No carry operation")
	elif carryCount == 1:
		print("1 carry operation")	
	else:
		print("{} carry operations".format(carryCount))


for _ in range(eval(input())):
	a, b = input().split()
	a = list(map(int, list(a)))
	b = list(map(int, list(b)))
	i = len(a)-1
	j = len(b)-1
	flg = 0
	while(i>=0 and j>=0):
		if b[i]+a[j]>=10:
			flg+=1
		i-=1
		j-=1
	if flg==1:
		print(flg,"carry operation")
	elif flg>1:
		print(flg,"carry operations")
	else:
		print("No carry operation")


t=eval(input())
for _ in range(t):
	l=list(map(int,input().split()))
	a=l[0]
	b=0
	if len(l)>1:
		b=l[1]
	carry=0
	cnt=0
	if not a or not b:
		print("No carry operation")
		continue
	while a or b:
		s=a%10+b%10+carry
		if s>=10: 
			carry=1
			cnt+=1
		else:
			carry=0
		a/=10
		b/=10
	if not cnt:
		print("No", end=' ')
	else:
		print(cnt, end=' ')
	if cnt<2:
		print("carry operation")
	else:
		print("carry operations")