## Task:

You have to write a function `pattern` which returns the following Pattern(See Examples) upto n number of rows. 

* Note:```Returning``` the pattern is not the same as ```Printing``` the pattern.

### Rules/Note:

* The pattern should be created using only unit digits.
* If `n < 1` then it should return "" i.e. empty string.
* `The length of each line is same`, and is equal to the number of characters in a line i.e `n`.
* Range of Parameters (for the sake of CW Compiler) :
  + `n ∈ (-50,150]`
   
### Examples:

 + pattern(8):

       88888888
       87777777
       87666666
       87655555
       87654444
       87654333
       87654322
       87654321
       
 + pattern(17):
   
       77777777777777777
       76666666666666666
       76555555555555555
       76544444444444444
       76543333333333333
       76543222222222222
       76543211111111111
       76543210000000000
       76543210999999999
       76543210988888888
       76543210987777777
       76543210987666666
       76543210987655555
       76543210987654444
       76543210987654333
       76543210987654322
       76543210987654321


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Difficulty: EASY
Starter code: def pattern(n):
	

Solutions:
def pattern(n):
	return '\n'.join((''.join((str((n - min(j, i)) % 10) for j in range(n))) for i in range(max(n, 0))))


def pattern(n):
	return '\n'.join([''.join([str(j % 10) for j in range(n, n - i, -1)]).ljust(n, str((n - i) % 10)) for i in range(n)])


def pattern(n):
	return '\n'.join((''.join((str(max(r, c) % 10) for c in range(n, 0, -1))) for r in range(n, 0, -1)))


def pattern(n):
	s = ''.join((str(x % 10) for x in reversed(range(1, n + 1))))
	return '\n'.join((s[:x + 1] + s[x] * (n - x - 1) for x in range(n)))


def pattern(n):
	if n < 1:
		return ''
	res = []
	current = str(n)[-1]
	strng = ''
	res.append(current * n)
	for i in range(1, n):
		strng = strng + current
		if current == '0':
			res.append(strng.ljust(n, '9'))
			current = '9'
		else:
			res.append(strng.ljust(n, str(int(current) - 1)))
			current = str(int(current) - 1)
	return '\n'.join(res)


def pattern(n):
	pattern = ''
	pattern_sub = ''
	for x in range(n, 0, -1):
		pattern += pattern_sub
		pattern += str(x % 10) * x
		pattern_sub += str(x % 10)
		if x > 1:
			pattern += '\n'
	return pattern


def pattern(n):
	if n < 1:
		return ''
	if n == 1:
		return '1'
	res = []
	for i in range(1, n + 1):
		res.append(''.join([str(i % 10)] * i + [str(s % 10) for s in range(i + 1, n + 1)])[::-1])
	return '\n'.join(res[::-1])


def pattern(n):
	d = int(str(n)[-1])
	ptn = str(d) * n
	arr = [ptn]
	for i in range(n - 1):
		if ptn[-1] != '0':
			ptn = ptn[:i + 1] + str(int(ptn[-1]) - 1) * (n - i - 1)
		else:
			ptn = ptn[:i + 1] + '9' * (n - i - 1)
		arr.append(''.join(ptn))
	result = '\n'.join(arr)
	return result