Create a function `isAlt()` that accepts a string as an argument and validates whether the vowels (a, e, i, o, u) and consonants are in alternate order.

```python
is_alt("amazon")
// true
is_alt("apple")
// false
is_alt("banana")
// true
```

Arguments consist of only lowercase letters.

Difficulty: EASY
Starter code: def is_alt(s):
	

Solutions:
import re

def is_alt(s):
	return not re.search('[aeiou]{2}|[^aeiou]{2}', s)


def is_alt(s):
	vowels = list('aeiou')
	v = s[0] in vowels
	for i in s:
		if (i in vowels) != v:
			return False
		v = not v
	return True


def is_alt(s):
	a = s[::2]
	b = s[1::2]
	if b[0] in 'aeiou':
		c = a
		a = b
		b = c
	return all((x in 'aeiou' for x in a)) and all((x not in 'aeiou' for x in b))


vowels = 'aeiou'

def is_alt(s):
	if len(s) < 2:
		return False
	prevIsVowel = s[0] in vowels
	for c in s[1:]:
		isVowel = c in vowels
		if prevIsVowel == isVowel:
			return False
		prevIsVowel = isVowel
	return True


import re

def is_alt(s):
	return False if re.findall('[aeiou0]{2,}|[^aeiou0-9\\W]{2,}', s) else True


def is_alt(s):
	return helper(s, 0, 1) if s[0] in 'aeiou' else helper(s, 1, 0)

def helper(s, n, m):
	for i in range(n, len(s), 2):
		if s[i] not in 'aeiou':
			return False
	for i in range(m, len(s), 2):
		if s[i] in 'aeiou':
			return False
	return True


from itertools import groupby

def is_alt(s):
	return all((len(list(gp)) == 1 for (_, gp) in groupby(s, key=lambda x: x in 'aeiou')))


def is_alt(s):
	vowels = 'aeiou'
	prev = s[0]
	for ch in s[1:]:
		if prev in vowels and ch in vowels or (prev not in vowels and ch not in vowels):
			return False
		prev = ch
	return True


import re

def is_alt(s):
	return bool(re.search('^([aeiou][^aeiou])*[aeiou]?$|^([^aeiou][aeiou])*[^aeiou]?$', s))


from itertools import tee

def is_alt(s):
	(xs1, xs2) = tee(map(lambda x: x in 'aeiou', s))
	next(xs2)
	return all((a != b for (a, b) in zip(xs1, xs2)))