Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).


Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 



Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 



Note:
Length of the array will not exceed 10,000.

Difficulty: EASY
Starter code: class Solution:
    def findLengthOfLCIS(self, nums: List[int]) -> int:
        

Solutions:
class Solution:

	def findLengthOfLCIS(self, nums):
		if len(nums) < 1:
			return 0
		cur_len = 1
		max_len = 1
		for i in range(1, len(nums)):
			if nums[i] > nums[i - 1]:
				cur_len = cur_len + 1
			else:
				cur_len = 1
			if cur_len > max_len:
				max_len = cur_len
		return max_len


class Solution:

	def findLengthOfLCIS(self, nums):
		if not nums:
			return 0
		result = 1
		max_result = 1
		for i in range(len(nums) - 1):
			if nums[i + 1] > nums[i]:
				result += 1
				if result > max_result:
					max_result = result
			else:
				result = 1
		return max_result


class Solution:

	def findLengthOfLCIS(self, nums):
		if not len(nums):
			return 0
		res = 0
		temp_res = 1
		for i in range(len(nums) - 1):
			if nums[i] < nums[i + 1]:
				temp_res += 1
			else:
				if temp_res > res:
					res = temp_res
				temp_res = 1
		return max(res, temp_res)


class Solution:

	def findLengthOfLCIS(self, nums):
		if nums == []:
			return 0
		elif len(nums) == 1:
			return 1
		(ans, max_ans) = (1, 1)
		for i in range(len(nums) - 1):
			if nums[i] < nums[i + 1]:
				ans += 1
				max_ans = ans if ans > max_ans else max_ans
			else:
				ans = 1
		return max_ans


class Solution:

	def findLengthOfLCIS(self, nums):
		if not nums:
			return 0
		(seq, max_seq) = (1, 1)
		for i in range(1, len(nums)):
			if nums[i] > nums[i - 1]:
				seq += 1
			else:
				max_seq = max(max_seq, seq)
				seq = 1
		max_seq = max(max_seq, seq)
		return max_seq


class Solution:

	def findLengthOfLCIS(self, nums):
		ans = anchor = 0
		for i in range(len(nums)):
			if i and nums[i - 1] >= nums[i]:
				anchor = i
			ans = max(ans, i - anchor + 1)
		return ans


class Solution:

	def findLengthOfLCIS(self, nums):
		if not nums:
			return 0
		longest = 0
		count = 1
		for i in range(1, len(nums)):
			if nums[i] > nums[i - 1]:
				count += 1
			else:
				longest = max(longest, count)
				count = 1
		return max(longest, count)


class Solution:

	def findLengthOfLCIS(self, nums):
		if not nums:
			return 0
		ret = 0
		cnt = 1
		for i in range(1, len(nums)):
			if nums[i] > nums[i - 1]:
				cnt += 1
			else:
				ret = max(ret, cnt)
				cnt = 1
		return max(ret, cnt)


class Solution:

	def findLengthOfLCIS(self, nums):
		current_count = 0
		max_count = 0
		for (index, num) in enumerate(nums):
			current_count += 1
			if index < len(nums) - 1:
				if num >= nums[index + 1]:
					max_count = max(max_count, current_count)
					current_count = 0
		return max(max_count, current_count)


class Solution:

	def findLengthOfLCIS(self, nums):
		LCIS = 0
		i = 0
		j = 1
		while j <= len(nums):
			if j == len(nums) or nums[j - 1] >= nums[j]:
				l = j - i
				if LCIS < l:
					LCIS = l
				i = j
			j += 1
		return LCIS


class Solution:

	def findLengthOfLCIS(self, nums):
		if nums == []:
			return 0
		longest = 1
		curr = 1
		for i in range(0, len(nums) - 1):
			if nums[i] < nums[i + 1]:
				curr += 1
				print(curr)
			else:
				longest = max(longest, curr)
				curr = 1
		longest = max(longest, curr)
		return longest


class Solution:

	def findLengthOfLCIS(self, nums):
		if nums == []:
			return 0
		n = 1
		ans = [1]
		for i in range(0, len(nums) - 1):
			if nums[i + 1] > nums[i]:
				n += 1
			else:
				ans.append(n)
				n = 1
			if i == len(nums) - 2:
				ans.append(n)
		return max(ans)


class Solution:

	def findLengthOfLCIS(self, nums):
		counter = 1
		L = []
		if len(nums) >= 2:
			for i in range(0, len(nums) - 1):
				if nums[i + 1] > nums[i]:
					counter += 1
				else:
					counter = 1
				L.append(counter)
			return max(L)
		elif len(nums) == 1:
			return 1
		else:
			return 0