lianghsun/spider-text2sql-bench huggingface dataset:
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M and make the result set in ascending order by department number.

### SQL
SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What are the full name, hire data, salary and department id for employees without the letter M in their first name, ordered by ascending department id?

### SQL
SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
what is the phone number of employees whose salary is in the range of 8000 and 12000?

### SQL
SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Return the phone numbers of employees with salaries between 8000 and 12000.

### SQL
SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number does not equal to 40.

### SQL
SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR  department_id != 40
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Return all information about employees with salaries between 8000 and 12000 for which commission is not null or where their department id is not 40.

### SQL
SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR  department_id != 40
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What are the full name (first and last name) and salary for all employees who does not have any value for commission?

### SQL
SELECT first_name ,  last_name ,  salary FROM  employees WHERE commission_pct  =  "null"
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Return the full names and salaries of employees with null commissions.

### SQL
SELECT first_name ,  last_name ,  salary FROM  employees WHERE commission_pct  =  "null"
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Display the first and last name, and salary for those employees whose first name is ending with the letter m.

### SQL
SELECT first_name ,  last_name ,  salary FROM employees WHERE first_name LIKE '%m'
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Return the full names and salaries for employees with first names that end with the letter m.

### SQL
SELECT first_name ,  last_name ,  salary FROM employees WHERE first_name LIKE '%m'
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Find job id and date of hire for those employees who was hired between November 5th, 2007 and July 5th, 2009.

### SQL
SELECT job_id ,  hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What are the job ids and dates of hire for employees hired after November 5th, 2007 and before July 5th, 2009?

### SQL
SELECT job_id ,  hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What are the first and last name for those employees who works either in department 70 or 90?

### SQL
SELECT first_name ,  last_name FROM employees WHERE department_id  =  70 OR department_id  =  90
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What are the full names of employees who with in department 70 or 90?

### SQL
SELECT first_name ,  last_name FROM employees WHERE department_id  =  70 OR department_id  =  90
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
Find the salary and manager number for those employees who is working under a manager.

### SQL
SELECT salary ,  manager_id FROM employees WHERE manager_id != "null"
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What are the salaries and manager ids for employees who have managers?

### SQL
SELECT salary ,  manager_id FROM employees WHERE manager_id != "null"
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
display all the details from Employees table for those employees who was hired before 2002-06-21.

### SQL
SELECT * FROM employees WHERE hire_date  <  '2002-06-21'
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
What is all the information about employees hired before June 21, 2002?

### SQL
SELECT * FROM employees WHERE hire_date  <  '2002-06-21'
### Database Schema
CREATE TABLE `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
)

CREATE TABLE `countries` (
  `COUNTRY_ID` varchar(2) NOT NULL,
  `COUNTRY_NAME` varchar(40) DEFAULT NULL,
  `REGION_ID` decimal(10,0) DEFAULT NULL,
  PRIMARY KEY (`COUNTRY_ID`),
  FOREIGN KEY (`REGION_ID`) REFERENCES regions (`REGION_ID`)
)

CREATE TABLE `departments` (
  `DEPARTMENT_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `DEPARTMENT_NAME` varchar(30) NOT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `LOCATION_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`DEPARTMENT_ID`)
)

CREATE TABLE `jobs` (
  `JOB_ID` varchar(10) NOT NULL DEFAULT '',
  `JOB_TITLE` varchar(35) NOT NULL,
  `MIN_SALARY` decimal(6,0) DEFAULT NULL,
  `MAX_SALARY` decimal(6,0) DEFAULT NULL,
  PRIMARY KEY (`JOB_ID`)
)

CREATE TABLE `employees` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL DEFAULT '0',
  `FIRST_NAME` varchar(20) DEFAULT NULL,
  `LAST_NAME` varchar(25) NOT NULL,
  `EMAIL` varchar(25) NOT NULL,
  `PHONE_NUMBER` varchar(20) DEFAULT NULL,
  `HIRE_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `SALARY` decimal(8,2) DEFAULT NULL,
  `COMMISSION_PCT` decimal(2,2) DEFAULT NULL,
  `MANAGER_ID` decimal(6,0) DEFAULT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `job_history` (
  `EMPLOYEE_ID` decimal(6,0) NOT NULL,
  `START_DATE` date NOT NULL,
  `END_DATE` date NOT NULL,
  `JOB_ID` varchar(10) NOT NULL,
  `DEPARTMENT_ID` decimal(4,0) DEFAULT NULL,
  PRIMARY KEY (`EMPLOYEE_ID`,`START_DATE`),
  FOREIGN KEY (`EMPLOYEE_ID`) REFERENCES employees(`EMPLOYEE_ID`),
  FOREIGN KEY (`DEPARTMENT_ID`) REFERENCES departments(`DEPARTMENT_ID`),
  FOREIGN KEY (`JOB_ID`) REFERENCES jobs(`JOB_ID`)
)

CREATE TABLE `locations` (
  `LOCATION_ID` decimal(4,0) NOT NULL DEFAULT '0',
  `STREET_ADDRESS` varchar(40) DEFAULT NULL,
  `POSTAL_CODE` varchar(12) DEFAULT NULL,
  `CITY` varchar(30) NOT NULL,
  `STATE_PROVINCE` varchar(25) DEFAULT NULL,
  `COUNTRY_ID` varchar(2) DEFAULT NULL,
  PRIMARY KEY (`LOCATION_ID`),
  FOREIGN KEY (`COUNTRY_ID`) REFERENCES countries(`COUNTRY_ID`)
)

### Question
display all the information for all employees who have the letters D or S in their first name and also arrange the result in descending order by salary.

### SQL
SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC