lianghsun/spider-text2sql-bench huggingface dataset:
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
How many characteristics does the product named "sesame" have?

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id WHERE t1.product_name  =  "sesame"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Count the number of characteristics the product 'sesame' has.

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id WHERE t1.product_name  =  "sesame"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
How many distinct characteristic names does the product "cumin" have?

### SQL
SELECT count(DISTINCT t3.characteristic_name) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "sesame"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Count the number of different characteristic names the product 'cumin' has.

### SQL
SELECT count(DISTINCT t3.characteristic_name) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "sesame"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
What are all the characteristic names of product "sesame"?

### SQL
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "sesame"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Return the characteristic names of the 'sesame' product.

### SQL
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "sesame"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
List all the characteristic names and data types of product "cumin".

### SQL
SELECT t3.characteristic_name ,  t3.characteristic_data_type FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "cumin"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
What are the names and data types of the characteristics of the 'cumin' product?

### SQL
SELECT t3.characteristic_name ,  t3.characteristic_data_type FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "cumin"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
List all characteristics of product named "sesame" with type code "Grade".

### SQL
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "sesame" AND t3.characteristic_type_code  =  "Grade"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
What are the names of the characteristics of the product 'sesame' that have the characteristic type code 'Grade'?

### SQL
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "sesame" AND t3.characteristic_type_code  =  "Grade"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
How many characteristics does the product named "laurel" have?

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "laurel"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Count the number of characteristics of the product named 'laurel'.

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "laurel"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Find the number of characteristics that the product "flax" has.

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "flax"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Count the number of characteristics of the 'flax' product.

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t1.product_name  =  "flax"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Find the name of the products that have the color description "red" and have the characteristic name "fast".

### SQL
SELECT product_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code  =  t4.color_code WHERE t4.color_description  =  "red" AND t3.characteristic_name  =  "fast"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
What are the names of the products that have a color description of 'red' and the 'fast' characteristic?

### SQL
SELECT product_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code  =  t4.color_code WHERE t4.color_description  =  "red" AND t3.characteristic_name  =  "fast"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
How many products have the characteristic named "hot"?

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t3.characteristic_name  =  "hot"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Count the number of products with the 'hot' charactersitic.

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t3.characteristic_name  =  "hot"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
List the all the distinct names of the products with the characteristic name 'warm'.

### SQL
SELECT DISTINCT t1.product_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t3.characteristic_name  =  "warm"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
What are the different product names for products that have the 'warm' characteristic:?

### SQL
SELECT DISTINCT t1.product_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id WHERE t3.characteristic_name  =  "warm"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Find the number of the products that have their color described as "red" and have a characteristic named "slow".

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code  =  t4.color_code WHERE t4.color_description  =  "red" AND t3.characteristic_name  =  "slow"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
How many products have the color description 'red' and the characteristic name 'slow'?

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code  =  t4.color_code WHERE t4.color_description  =  "red" AND t3.characteristic_name  =  "slow"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
Count the products that have the color description "white" or have the characteristic name "hot".

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code  =  t4.color_code WHERE t4.color_description  =  "white" OR t3.characteristic_name  =  "hot"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
How many products have their color described as 'white' or have a characteristic with the name 'hot'?

### SQL
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id  =  t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id  =  t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code  =  t4.color_code WHERE t4.color_description  =  "white" OR t3.characteristic_name  =  "hot"
### Database Schema
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
)

CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
)

CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
)

CREATE TABLE `Characteristics` (
`characteristic_id` INTEGER PRIMARY KEY,
`characteristic_type_code` VARCHAR(15) NOT NULL,
`characteristic_data_type` VARCHAR(10),
`characteristic_name` VARCHAR(80),
`other_characteristic_details` VARCHAR(255),
FOREIGN KEY (`characteristic_type_code` ) REFERENCES `Ref_Characteristic_Types`(`characteristic_type_code` )
)

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`color_code` VARCHAR(15) NOT NULL,
`product_category_code` VARCHAR(15) NOT NULL,
`product_name` VARCHAR(80),
`typical_buying_price` VARCHAR(20),
`typical_selling_price` VARCHAR(20),
`product_description` VARCHAR(255),
`other_product_details` VARCHAR(255),
FOREIGN KEY (`product_category_code` ) REFERENCES `Ref_Product_Categories`(`product_category_code` ),FOREIGN KEY (`color_code` ) REFERENCES `Ref_Colors`(`color_code` )
)

CREATE TABLE `Product_Characteristics` (
`product_id` INTEGER NOT NULL,
`characteristic_id` INTEGER NOT NULL,
`product_characteristic_value` VARCHAR(50),
FOREIGN KEY (`characteristic_id` ) REFERENCES `Characteristics`(`characteristic_id` ),
FOREIGN KEY (`product_id` ) REFERENCES `Products`(`product_id` )
)

### Question
What is the unit of measuerment of the product category code "Herbs"?

### SQL
SELECT unit_of_measure FROM ref_product_categories WHERE product_category_code  =  "Herbs"