lianghsun/bird-text2sql-bench huggingface dataset:
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
What are the names of the person that were not credited at the end of episode tt0629391?

### Hint
not credited refers to credited = ''; episode tt0629391 refers to episode_id = 'tt0629391'

### SQL
SELECT T2.name FROM Credit AS T1 INNER JOIN Person AS T2 ON T2.person_id = T1.person_id WHERE T1.credited = 'false' AND T1.episode_id = 'tt0629391'
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
How many people have won at least 3 awards?

### Hint
won refers to result = 'Winner'; at least 3 awards refers to count(result) > 3

### SQL
SELECT COUNT(T1.person_id) FROM Person AS T1 INNER JOIN Award AS T2 ON T1.person_id = T2.person_id WHERE T2.result = 'Winner' GROUP BY T1.person_id HAVING COUNT(T2.award_id) >= 3
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
Who is the script supervisor of the series in episode tt0629204?

### Hint
who refers to name; script supervisor refers to role = 'script supervisor'; episode tt0629204 refers to episode_id = 'tt0629204'

### SQL
SELECT T2.name FROM Credit AS T1 INNER JOIN Person AS T2 ON T2.person_id = T1.person_id WHERE T1.episode_id = 'tt0629204' AND T1.role = 'script supervisor'
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
How many awards has Julia Roberts been nominated for?

### Hint
been nominated refers to result = 'Nominee'

### SQL
SELECT COUNT(T2.award_id) FROM Person AS T1 INNER JOIN Award AS T2 ON T1.person_id = T2.person_id WHERE T1.name = 'Julia Roberts' AND T2.result = 'Nominee'
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
Who is the tallest camera operator?

### Hint
who refers to name; the tallest refers to max(height_meters); camera operator refers to role = 'camera operator'

### SQL
SELECT T2.name FROM Credit AS T1 INNER JOIN Person AS T2 ON T2.person_id = T1.person_id WHERE T1.role = 'camera operator' ORDER BY T2.height_meters DESC LIMIT 1
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
How many people, who were born in Canada, won an award in 1999?

### Hint
born in Canada refers to birth_country = 'Canada'; in 1999 refers to year = 1999

### SQL
SELECT COUNT(T1.person_id) FROM Person AS T1 INNER JOIN Award AS T2 ON T1.person_id = T2.person_id WHERE T2.year = 1999 AND T1.birth_country = 'Canada'
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
How many people gave the most enjoyed episode a 10-star rating?

### Hint
the most enjoyed refers max(rating); 10-star refers to stars = 10

### SQL
SELECT COUNT(T1.episode_id) FROM Episode AS T1 INNER JOIN Vote AS T2 ON T1.episode_id = T2.episode_id WHERE T2.stars = 10
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
What are the keywords of the "Shield" episode?

### Hint
"Shield" episode refers to title = 'Shield'

### SQL
SELECT T2.keyword FROM Episode AS T1 INNER JOIN Keyword AS T2 ON T1.episode_id = T2.episode_id WHERE T1.title = 'Shield'
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
What is the percentage of people who gave the "True North" episode a 1-star rating?

### Hint
the "True North" episode refers to title = 'True North'; 1-star refers to stars = 1; percentage = divide(count(episode_id where stars = 1), count(episode_id)) * 100% where title = 'True North'

### SQL
SELECT CAST(SUM(CASE WHEN T2.stars = 1 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.episode_id) FROM Episode AS T1 INNER JOIN Vote AS T2 ON T1.episode_id = T2.episode_id WHERE T1.title = 'True North' AND T1.episode_id = 'tt0629477'
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
What is the title of the episode with the highest number of keywords?

### Hint
the highest number of keywords refers to max(count(keyword))

### SQL
SELECT T1.title FROM Episode AS T1 INNER JOIN Keyword AS T2 ON T1.episode_id = T2.episode_id GROUP BY T1.episode_id ORDER BY COUNT(T2.keyword) DESC LIMIT 1
### Database Schema
CREATE TABLE Episode
(
    episode_id       TEXT
            primary key,
    series           TEXT,
    season           INTEGER,
    episode          INTEGER,
    number_in_series INTEGER,
    title            TEXT,
    summary          TEXT,
    air_date         DATE,
    episode_image    TEXT,
    rating           REAL,
    votes            INTEGER
)

CREATE TABLE Keyword
(
    episode_id TEXT,
    keyword    TEXT,
    primary key (episode_id, keyword),
    foreign key (episode_id) references Episode(episode_id)
)

CREATE TABLE Person
(
    person_id     TEXT
            primary key,
    name          TEXT,
    birthdate     DATE,
    birth_name    TEXT,
    birth_place   TEXT,
    birth_region  TEXT,
    birth_country TEXT,
    height_meters REAL,
    nickname      TEXT
)

CREATE TABLE Award
(
    award_id       INTEGER
            primary key,
    organization   TEXT,
    year           INTEGER,
    award_category TEXT,
    award          TEXT,
    series         TEXT,
    episode_id     TEXT,
    person_id      TEXT,
    role           TEXT,
    result         TEXT,
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Credit
(
    episode_id TEXT,
    person_id  TEXT,
    category   TEXT,
    role       TEXT,
    credited   TEXT,
    primary key (episode_id, person_id),
    foreign key (episode_id) references Episode(episode_id),
    foreign key (person_id) references Person(person_id)
)

CREATE TABLE Vote
(
    episode_id TEXT,
    stars      INTEGER,
    votes      INTEGER,
    percent    REAL,
    foreign key (episode_id) references Episode(episode_id)
)

### Question
Among the episodes that were aired in 1998, how many won an International Monitor Awards?

### Hint
aired in 1998 refers to air_date like '1998%'; won refers to result = 'Winner'; International Monitor Awards refers to organization = 'International Monitor Awards'

### SQL
SELECT COUNT(T1.episode_id) FROM Episode AS T1 INNER JOIN Award AS T2 ON T1.episode_id = T2.episode_id WHERE strftime('%Y', T1.air_date) = '1998' AND T2.organization = 'International Monitor Awards' AND T2.result = 'Winner'