lianghsun/bird-text2sql-bench huggingface dataset:
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
What is the average GPA of the students with the highest research capability and high salary? List the full names of the students.

### Hint
the highest research capability refers to capability = 5; high salary refers to salary = 'high'; prof_id refers to professor’s ID; GPA is an abbreviated name of Grade Point Average where average GPA refers to AVG(gpa);

### SQL
SELECT AVG(T2.gpa), T2.f_name, T2.l_name FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'high' AND T1.capability = 5 GROUP BY T2.student_id
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
List the professors' IDs and students' IDs with the lowest research ability.

### Hint
the lowest research ability refers to MIN(capability); professor’s ID refers to prof_id;

### SQL
SELECT prof_id, student_id FROM RA WHERE capability = ( SELECT MIN(capability) FROM RA )
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Name the professor who got graduation from the University of Boston.

### Hint
Name the professor refers to full name which includes f_name and l_name;

### SQL
SELECT first_name, last_name FROM prof WHERE graduate_from = 'University of Boston'
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
List the courses' IDs and students' IDs who failed to pass the course.

### Hint
If grade is null or empty, it means that this student fails to pass the course;

### SQL
SELECT course_id, student_id FROM registration WHERE grade IS NULL OR grade = ''
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
What is the male and female ratio among the professors?

### Hint
DIVIDE(COUNT(prof_id where gender = 'Male'), COUNT(prof_id where gender = 'Female'));

### SQL
SELECT CAST(SUM(CASE WHEN gender = 'Male' THEN 1 ELSE 0 END) AS REAL) / SUM(CASE WHEN gender = 'Female' THEN 1 ELSE 0 END) FROM prof
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Describe the names and credits of the least difficult courses.

### Hint
diff refers to difficulty; the least difficult courses refer to MIN(diff);

### SQL
SELECT name, credit FROM course WHERE diff = ( SELECT MIN(diff) FROM course )
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Describe the students' full names and GPAs under the supervision of the most popular professor.

### Hint
student's full names = f_name, l_name; most popular refers to MAX(popularity);

### SQL
SELECT T3.f_name, T3.l_name, T3.gpa FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id ORDER BY T1.popularity DESC LIMIT 1
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Provide the full names and emails of unpaid research assistants.

### Hint
full names = f_name, l_name; research assistant refers to the student who serves for research where the abbreviation is RA; unpaid research assistant refers to salary = 'free';

### SQL
SELECT T2.f_name, T2.l_name, T2.email FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'free'
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
List the research assistants' full names, capabilities and GPAs who were under the supervision of Merwyn Conkay.

### Hint
research assistant refers to the student who serves for research where the abbreviation is RA; full names = f_name, l_name;

### SQL
SELECT T3.f_name, T3.l_name, T2.capability, T3.gpa FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T1.first_name = 'Merwyn' AND T1.last_name = 'Conkay'
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Describe the students' full names and grades in Intro to BlockChain course.

### Hint
student's full names = f_name, l_name;

### SQL
SELECT T1.f_name, T1.l_name, T2.grade FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Intro to BlockChain'
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Among students registered for the most difficult course, list the students' full names who got grade A.

### Hint
difficulty refers to diff; most difficult course refers to MAX(diff); student's full names = f_name, l_name;

### SQL
SELECT T1.f_name, T1.l_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T2.grade = 'A' ORDER BY T3.diff DESC LIMIT 1
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Describe the full names and graduated universities of the professors who advised Olia Rabier.

### Hint
full names of the professors = first_name, last_name; graduated universities of the professors refers to graduate_from;

### SQL
SELECT T1.first_name, T1.last_name, T1.graduate_from FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T3.f_name = 'Olia' AND T3.l_name = 'Rabier'
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Name the students of the Advanced Database Systems course with the highest satisfaction.

### Hint
full the students = f_name, l_name; course refers to name; satisfaction refers to sat; highest satisfaction refers to MAX(sat);

### SQL
SELECT T1.f_name, T1.l_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Advanced Database Systems' ORDER BY T2.sat DESC LIMIT 1
### Database Schema
CREATE TABLE "course"
(
    course_id INTEGER
        constraint course_pk
            primary key,
    name      TEXT,
    credit    INTEGER,
    diff      INTEGER
)

CREATE TABLE prof
(
    prof_id         INTEGER
        constraint prof_pk
            primary key,
    gender          TEXT,
    first_name      TEXT,
    last_name       TEXT,
    email           TEXT,
    popularity      INTEGER,
    teachingability INTEGER,
    graduate_from   TEXT
)

CREATE TABLE RA
(
    student_id INTEGER,
    capability INTEGER,
    prof_id    INTEGER,
    salary     TEXT,
    primary key (student_id, prof_id),
    foreign key (prof_id) references prof(prof_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE registration
(
    course_id  INTEGER,
    student_id INTEGER,
    grade      TEXT,
    sat        INTEGER,
    primary key (course_id, student_id),
    foreign key (course_id) references course(course_id),
    foreign key (student_id) references student(student_id)
)

CREATE TABLE student
(
    student_id   INTEGER
            primary key,
    f_name       TEXT,
    l_name       TEXT,
    phone_number TEXT,
    email        TEXT,
    intelligence INTEGER,
    gpa          REAL,
    type         TEXT
)

### Question
Calculate the GPA of the semester for Laughton Antonio.

### Hint
GPA of the semester = DIVIDE(SUM(MULTIPLY(credit, grade)), SUM(credit)); grade 'A' refers to gpa = 4; grade 'B' refers to gpa = 3; grade 'C' refers to gpa = 2; grade 'D' refers to gpa = 1;

### SQL
SELECT CAST(SUM(T3.credit * CASE T1.grade WHEN 'A' THEN 4 WHEN 'B' THEN 3 WHEN 'C' THEN 2 WHEN 'D' THEN 1 ELSE 1 END) AS REAL) / COUNT(T3.credit) FROM registration AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T1.course_id = T3.course_id WHERE T2.f_name = 'Laughton' AND T2.l_name = 'Antonio'