page_title: 1988 United States presidential election in Nebraska
section_title: Partisan background
hierarchical_section_title: 1988 United States presidential election in Nebraska / Partisan background
caption_attribution_description: Vice President George H. W. Bush attends a campaign rally in Omaha, Nebraska
context_page_description: The 1988 United States presidential election in Nebraska took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Voters chose 5 electors to the Electoral College, which selected the president and vice president.
  Nebraska was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.
  Nebraska weighed in for this election as 7% more Republican than the national average.
context_section_description: The presidential election of 1988 was a very partisan election for Nebraska, with more than 99% of the electorate voting for either the Democratic or Republican parties, and only 4 political parties appearing on the ballot. As typical for the time, nearly every county in Nebraska turned out primarily for the Republican candidate, with the exception of the Democratic stronghold of Saline County, and a few counties conglomerate with Sioux City, Iowa, in the Northeastern corner of Nebraska, which tended to vote Democratic at this time.
caption: Bush's largely socially conservative rhetoric garnered him much support among social-conservatives nationwide. Seen here at campaign rally in Omaha, Nebraska.
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