Will do, cause of:
```
f (x) = pow(10.0f, x/20);
```
f(0) = 1.0
f(-0.1) = 0.9885
==============
f(-0.01)= 0.9988
f(-0.001)=0.99988

All those under the == would be scaled, cause of a minimal uncertainty, which can be easily introduced by the logarithm