Ahora anda todo menos la fft de cernlib

Paolo me dice que pruebe con otra, asi que eso voy a hacer.

"The specific problem you rise can be trivial. The program you mention
was written by Andrea, who used a CERNLIB. The objective of CSFTFT
however is just to make a FFT. I suspect the problem can be in the NF
parameter, which was defined as:
NF = -NINT(LOG(REAL(NM))/LOG(2.))
and is passed by MOD_FOREST_PARAMETERS.

More simply, you can find an explicit Fortran code for FFT in the
programs I recently sent to Cintia."