made it so that -1/b x is bizarro equivalent to -x/b
Merge pull request #175 from Alex-Jordan/bizarroBug

made it so that -1/b x is bizarro equivalent to -x/b

The changes fix the test problem, and since its so targeted I'm going to merge. 

Just out of curiosity though, before when you had the 1 case you returned `return bizarro::f(1 * bizarro::g(1/$b));`.  Now you just return `$a/$b$.  What does this change?