[SPARK-2010] [PySpark] [SQL] support nested structure in SchemaRDD

Convert Row in JavaSchemaRDD into Array[Any] and unpickle them as tuple in Python, then convert them into namedtuple, so use can access fields just like attributes.

This will let nested structure can be accessed as object, also it will reduce the size of serialized data and better performance.

root
 |-- field1: integer (nullable = true)
 |-- field2: string (nullable = true)
 |-- field3: struct (nullable = true)
 |    |-- field4: integer (nullable = true)
 |    |-- field5: array (nullable = true)
 |    |    |-- element: integer (containsNull = false)
 |-- field6: array (nullable = true)
 |    |-- element: struct (containsNull = false)
 |    |    |-- field7: string (nullable = true)

Then we can access them by row.field3.field5[0]  or row.field6[5].field7

It also will infer the schema in Python, convert Row/dict/namedtuple/objects into tuple before serialization, then call applySchema in JVM. During inferSchema(), the top level of dict in row will be StructType, but any nested dictionary will be MapType.

You can use pyspark.sql.Row to convert unnamed structure into Row object, make the RDD can be inferable. Such as:

ctx.inferSchema(rdd.map(lambda x: Row(a=x[0], b=x[1]))

Or you could use Row to create a class just like namedtuple, for example:

Person = Row("name", "age")
ctx.inferSchema(rdd.map(lambda x: Person(*x)))

Also, you can call applySchema to apply an schema to a RDD of tuple/list and turn it into a SchemaRDD. The `schema` should be StructType, see the API docs for details. 

schema = StructType([StructField("name, StringType, True),
                                    StructType("age", IntegerType, True)])
ctx.applySchema(rdd, schema)

PS: In order to use namedtuple to inferSchema, you should make namedtuple picklable.
`private[spark]`?