Assignment3 submission

You don't need `.update()` here. You can simply assign the key value pair:

    table13[key] = value

It's fewer characters and doesn't result in the creation of an intermediate dictionary. However, there is a way that `.update()` can be used that eliminates the need for the entire `for` loop. Review the [docs on `.update()`](https://docs.python.org/2/library/stdtypes.html#dict.update)