Destructuring

This pull request adds support for ECMAScript 6 destructuring declarations and assignments with down-level ES3 and ES5 code generation. For example:
```typescript
var [x, y] = [10, 20];
[x, y] = [y, x];
```
The above example generates:
```javascript
var _a = [10, 20], x = _a[0], y = _a[1];
_b = [y, x], x = _b[0], y = _b[1];
```
Another example:
```typescript
interface NameAndLocation {
    name: string;
    location: [number, number];
}

function getNameAndLocation(): NameAndLocation {
    return { name: "top-left", location: [10, 20] };
}

function displayNameAndLocation({name, location: [x, y] = [0, 0]}: NameAndLocation) {
    console.log("name=" + name + " x=" + x + " y=" + y);
}

var {name, location: [x, y]} = getNameAndLocation();
displayNameAndLocation(getNameAndLocation());
```
The above example generates:
```javascript
function getNameAndLocation() {
    return { name: "top-left", location: [10, 20] };
}
function displayNameAndLocation(_a) {
    var name = _a.name, _b = _a.location, _c = _b === void 0 ? [0, 0] : _b, x = _c[0], y = _c[1];
    console.log("name=" + name + " x=" + x + " y=" + y);
}
var _a = getNameAndLocation(), name = _a.name, _b = _a.location, x = _b[0], y = _b[1];
displayNameAndLocation(getNameAndLocation());
```
Work still remaining:
* Support for rest elements in array destructuring.
* Pure ES6 code generation with no rewriting (under -target ES6 switch).
* Updated spec.

It is if there is not an initializer. If you're suggesting it should be `any` regardless of the initializer, then no. Consider:
```typescript
var a: any;
var [x, y = 1] = a;
```
Here, `a` provides no clue as to the intended type of `x` and `y`, so we infer from the type of the initializer. This contrasts with:
```typescript
var a: any;
var [x, y = 1] = [a, a];
```
Here, the type of `a` is the intended type for `y`, and the initializer is required to be assignment compatible with that type.