* Please wrap code elements in backticks as it renders better (e.g. around `STDOUT` and `STDOUT.puts ...`)..
* The second case is when a reference to `$stderr` is stored before, not when a reference to `STDOUT` is stored (`STDOUT` will never work, regardless of if the ref is stored before or after...`$stdout` works as long as the user isn't using a prior reference to it).