That looks not too bad:

```
>>> import re
>>> token_pattern = re.compile(r'(?u)\b[^\d\W]\w+\b')
>>> token_pattern.findall('This, is a test:with 12 "som3" l337 or 3l337 words.')
['This', 'is', 'test', 'with', 'som3', 'l337', 'or', 'words']
```

@larsmans or others: any opinion, best suggestion?