/-- Existence of a conditional kernel. Use the definition `condKernel` to get that kernel. -/
theorem exists_cond_kernel (γ : Type*) [MeasurableSpace γ] :
    ∃ (η : kernel α Ω) (_h : IsMarkovKernel η), kernel.const γ ρ =
      (kernel.const γ ρ.fst) ⊗ₖ (kernel.prodMkLeft γ η) := by
  obtain ⟨f, hf⟩ := exists_measurableEmbedding_real Ω
  let ρ' : Measure (α × ℝ) := ρ.map (Prod.map id f)
  -- The general idea is to define `η = kernel.comapRight (condKernelReal ρ') hf`. There is
  -- however an issue: that `η` may not be a Markov kernel since its value is only a
  -- probability distribution almost everywhere with respect to `ρ.fst`, not everywhere.
  -- We modify it to obtain a Markov kernel which is almost everywhere equal.
  let ρ_set := (toMeasurable ρ.fst {a | condKernelReal ρ' a (range f) = 1}ᶜ)ᶜ
  have hm : MeasurableSet ρ_set := (measurableSet_toMeasurable _ _).compl
  have h_eq_one_of_mem : ∀ a ∈ ρ_set, condKernelReal ρ' a (range f) = 1 := by
    intro a ha
    rw [mem_compl_iff] at ha
    have h_ss := subset_toMeasurable ρ.fst {a : α | condKernelReal ρ' a (range f) = 1}ᶜ
    suffices ha' : a ∉ {a : α | condKernelReal ρ' a (range f) = 1}ᶜ
    · rwa [not_mem_compl_iff] at ha'
    exact not_mem_subset h_ss ha
  have h_prod_embed : MeasurableEmbedding (Prod.map (id : α → α) f) :=
    MeasurableEmbedding.id.prod_mk hf
  have h_fst : ρ'.fst = ρ.fst := by
    ext1 u hu
    rw [Measure.fst_apply hu, Measure.fst_apply hu,
      Measure.map_apply h_prod_embed.measurable (measurable_fst hu)]
    rfl
  have h_ae : ∀ᵐ a ∂ρ.fst, a ∈ ρ_set := by
    rw [ae_iff]
    simp only [not_mem_compl_iff, setOf_mem_eq, measure_toMeasurable]
    change ρ.fst {a : α | a ∉ {a' : α | condKernelReal ρ' a' (range f) = 1}} = 0
    rw [← ae_iff, ← h_fst]
    refine' ae_condKernelReal_eq_one ρ' hf.measurableSet_range _
    rw [Measure.map_apply h_prod_embed.measurable]
    swap; · exact measurable_snd hf.measurableSet_range.compl
    convert measure_empty (α := α × Ω)
    ext1 x
    simp only [mem_compl_iff, mem_range, preimage_setOf_eq, Prod_map, mem_setOf_eq,
      mem_empty_iff_false, iff_false_iff, Classical.not_not, exists_apply_eq_apply]
  classical
  obtain ⟨x₀, hx₀⟩ : ∃ x, x ∈ range f := range_nonempty _
  let η' :=
    kernel.piecewise hm (condKernelReal ρ') (kernel.deterministic (fun _ => x₀) measurable_const)
  -- We show that `kernel.comapRight η' hf` is a suitable Markov kernel.
  refine' ⟨kernel.comapRight η' hf, _, _⟩
  · 

Proof state:
case intro.intro.refine'_1
α : Type u_1
mα : MeasurableSpace α
Ω : Type u_2
inst✝⁴ : MeasurableSpace Ω
inst✝³ : StandardBorelSpace Ω
inst✝² : Nonempty Ω
ρ : Measure (α × Ω)
inst✝¹ : IsFiniteMeasure ρ
γ : Type u_3
inst✝ : MeasurableSpace γ
f : Ω → ℝ
hf : MeasurableEmbedding f
ρ' : Measure (α × ℝ) := Measure.map (Prod.map id f) ρ
ρ_set : Set α := (toMeasurable (Measure.fst ρ) {a | ↑↑((condKernelReal ρ') a) (range f) = 1}ᶜ)ᶜ
hm : MeasurableSet ρ_set
h_eq_one_of_mem : ∀ a ∈ ρ_set, ↑↑((condKernelReal ρ') a) (range f) = 1
h_prod_embed : MeasurableEmbedding (Prod.map id f)
h_fst : Measure.fst ρ' = Measure.fst ρ
h_ae : ∀ᵐ (a : α) ∂Measure.fst ρ, a ∈ ρ_set
x₀ : ℝ
hx₀ : x₀ ∈ range f
η' : ↥(kernel α ℝ) :=
  kernel.piecewise hm (condKernelReal ρ') (kernel.deterministic (fun x => x₀) (_ : Measurable fun x => x₀))
⊢ IsMarkovKernel (kernel.comapRight η' hf)

Next tactic:
refine' kernel.IsMarkovKernel.comapRight _ _ fun a => _