/-- An auxiliary lemma for
`MeasureTheory.integral_divergence_of_hasFDerivWithinAt_off_countable`. Compared to the previous
lemma, here we drop the assumption of differentiability on the boundary of the box. -/
theorem integral_divergence_of_hasFDerivWithinAt_off_countable_aux₂ (I : Box (Fin (n + 1)))
    (f : ℝⁿ⁺¹ → Eⁿ⁺¹)
    (f' : ℝⁿ⁺¹ → ℝⁿ⁺¹ →L[ℝ] Eⁿ⁺¹)
    (s : Set ℝⁿ⁺¹) (hs : s.Countable) (Hc : ContinuousOn f (Box.Icc I))
    (Hd : ∀ x ∈ Box.Ioo I \ s, HasFDerivAt f (f' x) x)
    (Hi : IntegrableOn (∑ i, f' · (e i) i) (Box.Icc I)) :
    (∫ x in Box.Icc I, ∑ i, f' x (e i) i) =
      ∑ i : Fin (n + 1),
        ((∫ x in Box.Icc (I.face i), f (i.insertNth (I.upper i) x) i) -
          ∫ x in Box.Icc (I.face i), f (i.insertNth (I.lower i) x) i) := by
  /- Choose a monotone sequence `J k` of subboxes that cover the interior of `I` and prove that
    these boxes satisfy the assumptions of the previous lemma. -/
  rcases I.exists_seq_mono_tendsto with ⟨J, hJ_sub, hJl, hJu⟩
  have hJ_sub' : ∀ k, Box.Icc (J k) ⊆ Box.Icc I := fun k => (hJ_sub k).trans I.Ioo_subset_Icc
  have hJ_le : ∀ k, J k ≤ I := fun k => Box.le_iff_Icc.2 (hJ_sub' k)
  have HcJ : ∀ k, ContinuousOn f (Box.Icc (J k)) := fun k => Hc.mono (hJ_sub' k)
  have HdJ : ∀ (k), ∀ x ∈ (Box.Icc (J k)) \ s, HasFDerivWithinAt f (f' x) (Box.Icc (J k)) x :=
    fun k x hx => (Hd x ⟨hJ_sub k hx.1, hx.2⟩).hasFDerivWithinAt
  have HiJ : ∀ k, IntegrableOn (∑ i, f' · (e i) i) (Box.Icc (J k)) volume := fun k =>
    Hi.mono_set (hJ_sub' k)
  -- Apply the previous lemma to `J k`.
  have HJ_eq := fun k =>
    integral_divergence_of_hasFDerivWithinAt_off_countable_aux₁ (J k) f f' s hs (HcJ k) (HdJ k)
      (HiJ k)
  -- Note that the LHS of `HJ_eq k` tends to the LHS of the goal as `k → ∞`.
  have hI_tendsto :
    Tendsto (fun k => ∫ x in Box.Icc (J k), ∑ i, f' x (e i) i) atTop
      (𝓝 (∫ x in Box.Icc I, ∑ i, f' x (e i) i)) := by
    simp only [IntegrableOn, ← Measure.restrict_congr_set (Box.Ioo_ae_eq_Icc _)] at Hi ⊢
    rw [← Box.iUnion_Ioo_of_tendsto J.monotone hJl hJu] at Hi ⊢
    exact tendsto_set_integral_of_monotone (fun k => (J k).measurableSet_Ioo)
      (Box.Ioo.comp J).monotone Hi
  -- Thus it suffices to prove the same about the RHS.
  

Proof state:
case intro.intro.intro
E : Type u
inst✝² : NormedAddCommGroup E
inst✝¹ : NormedSpace ℝ E
inst✝ : CompleteSpace E
n : ℕ
I : Box (Fin (n + 1))
f : (Fin (n + 1) → ℝ) → Fin (n + 1) → E
f' : (Fin (n + 1) → ℝ) → (Fin (n + 1) → ℝ) →L[ℝ] Fin (n + 1) → E
s : Set (Fin (n + 1) → ℝ)
hs : Set.Countable s
Hc : ContinuousOn f (Box.Icc I)
Hd : ∀ x ∈ Box.Ioo I \ s, HasFDerivAt f (f' x) x
Hi : IntegrableOn (fun x => ∑ i : Fin (n + 1), (f' x) (e i) i) (Box.Icc I)
J : ℕ →o Box (Fin (n + 1))
hJ_sub : ∀ (n_1 : ℕ), Box.Icc (J n_1) ⊆ Box.Ioo I
hJl : Tendsto (Box.lower ∘ ⇑J) atTop (𝓝 I.lower)
hJu : Tendsto (Box.upper ∘ ⇑J) atTop (𝓝 I.upper)
hJ_sub' : ∀ (k : ℕ), Box.Icc (J k) ⊆ Box.Icc I
hJ_le : ∀ (k : ℕ), J k ≤ I
HcJ : ∀ (k : ℕ), ContinuousOn f (Box.Icc (J k))
HdJ : ∀ (k : ℕ), ∀ x ∈ Box.Icc (J k) \ s, HasFDerivWithinAt f (f' x) (Box.Icc (J k)) x
HiJ : ∀ (k : ℕ), IntegrableOn (fun x => ∑ i : Fin (n + 1), (f' x) (e i) i) (Box.Icc (J k))
HJ_eq :
  ∀ (k : ℕ),
    ∫ (x : Fin (n + 1) → ℝ) in Box.Icc (J k), ∑ i : Fin (n + 1), (f' x) (e i) i =
      ∑ i : Fin (n + 1),
        ((∫ (x : Fin n → ℝ) in Box.Icc (Box.face (J k) i), f (Fin.insertNth i (Box.upper (J k) i) x) i) -
          ∫ (x : Fin n → ℝ) in Box.Icc (Box.face (J k) i), f (Fin.insertNth i (Box.lower (J k) i) x) i)
hI_tendsto :
  Tendsto (fun k => ∫ (x : Fin (n + 1) → ℝ) in Box.Icc (J k), ∑ i : Fin (n + 1), (f' x) (e i) i) atTop
    (𝓝 (∫ (x : Fin (n + 1) → ℝ) in Box.Icc I, ∑ i : Fin (n + 1), (f' x) (e i) i))
⊢ ∫ (x : Fin (n + 1) → ℝ) in Box.Icc I, ∑ i : Fin (n + 1), (f' x) (e i) i =
    ∑ i : Fin (n + 1),
      ((∫ (x : Fin n → ℝ) in Box.Icc (Box.face I i), f (Fin.insertNth i (Box.upper I i) x) i) -
        ∫ (x : Fin n → ℝ) in Box.Icc (Box.face I i), f (Fin.insertNth i (Box.lower I i) x) i)

Next tactic:
refine' tendsto_nhds_unique_of_eventuallyEq hI_tendsto _ (eventually_of_forall HJ_eq)