l3lab/ntp-mathlib huggingface dataset:
/-- Version of `isProperMap_iff_isCompact_preimage` in terms of `cocompact`. -/
lemma isProperMap_iff_tendsto_cocompact [T2Space Y] [WeaklyLocallyCompactSpace Y] :
    IsProperMap f ↔ Continuous f ∧ Tendsto f (cocompact X) (cocompact Y) := by
  simp_rw [isProperMap_iff_isCompact_preimage, hasBasis_cocompact.tendsto_right_iff,
    ← mem_preimage, eventually_mem_set, preimage_compl]
  refine and_congr_right fun f_cont ↦
    ⟨fun H K hK ↦ (H hK).compl_mem_cocompact, fun H K hK ↦ ?_⟩
  rcases mem_cocompact.mp (H K hK) with ⟨K', hK', hK'y⟩
  

Proof state:
case intro.intro
X : Type u_2
Y : Type u_1
Z : Type ?u.49273
W : Type ?u.49276
inst✝⁵ : TopologicalSpace X
inst✝⁴ : TopologicalSpace Y
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f : X → Y
inst✝¹ : T2Space Y
inst✝ : WeaklyLocallyCompactSpace Y
f_cont : Continuous f
H : ∀ (i : Set Y), IsCompact i → (f ⁻¹' i)ᶜ ∈ cocompact X
K : Set Y
hK : IsCompact K
K' : Set X
hK' : IsCompact K'
hK'y : K'ᶜ ⊆ (f ⁻¹' K)ᶜ
⊢ IsCompact (f ⁻¹' K)

Next tactic:
exact hK'.of_isClosed_subset (hK.isClosed.preimage f_cont)
    (compl_le_compl_iff_le.mp hK'y)
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  

Proof state:
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
⊢ IsProperMap f ↔ Continuous f ∧ IsClosedMap (Prod.map f id)

Next tactic:
constructor
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> 

Proof state:
case mp
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
⊢ IsProperMap f → Continuous f ∧ IsClosedMap (Prod.map f id)

Next tactic:
intro H
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> 

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
⊢ Continuous f ∧ IsClosedMap (Prod.map f id) → IsProperMap f

Next tactic:
intro H
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · 

Proof state:
case mp
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : IsProperMap f
⊢ Continuous f ∧ IsClosedMap (Prod.map f id)

Next tactic:
exact ⟨H.continuous, H.universally_closed _⟩
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · 

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
⊢ IsProperMap f

Next tactic:
rw [isProperMap_iff_ultrafilter]
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
⊢ Continuous f ∧ ∀ ⦃𝒰 : Ultrafilter X⦄ ⦃y : Y⦄, Tendsto f (↑𝒰) (𝓝 y) → ∃ x, f x = y ∧ ↑𝒰 ≤ 𝓝 x

Next tactic:
refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
  -- In `X × Filter X`, consider the closed set `F := closure {(x, ℱ) | ℱ = pure x}`
    

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
𝒰 : Ultrafilter X
y : Y
hy : Tendsto f (↑𝒰) (𝓝 y)
⊢ ∃ x, f x = y ∧ ↑𝒰 ≤ 𝓝 x

Next tactic:
let F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
  -- In `X × Filter X`, consider the closed set `F := closure {(x, ℱ) | ℱ = pure x}`
    let F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
  -- Since `f × id` is closed, the set `(f × id) '' F` is also closed.
    

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
𝒰 : Ultrafilter X
y : Y
hy : Tendsto f (↑𝒰) (𝓝 y)
F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
⊢ ∃ x, f x = y ∧ ↑𝒰 ≤ 𝓝 x

Next tactic:
have := H.2 F isClosed_closure
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
  -- In `X × Filter X`, consider the closed set `F := closure {(x, ℱ) | ℱ = pure x}`
    let F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
  -- Since `f × id` is closed, the set `(f × id) '' F` is also closed.
    have := H.2 F isClosed_closure
  -- Let us show that `(y, 𝒰) ∈ (f × id) '' F`.
    

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
𝒰 : Ultrafilter X
y : Y
hy : Tendsto f (↑𝒰) (𝓝 y)
F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
this : IsClosed (Prod.map f id '' F)
⊢ ∃ x, f x = y ∧ ↑𝒰 ≤ 𝓝 x

Next tactic:
have : (y, ↑𝒰) ∈ Prod.map f id '' F :=
  -- Note that, by the properties of the topology on `Filter X`, the function `pure : X → Filter X`
  -- tends to the point `𝒰` of `Filter X` along the filter `𝒰` on `X`. Since `f` tends to `y` along
  -- `𝒰`, we get that the function `(f, pure) : X → (Y, Filter X)` tends to `(y, 𝒰)` along
  -- `𝒰`. Furthermore, each `(f, pure)(x) = (f × id)(x, pure x)` is clearly an element of
  -- the closed set `(f × id) '' F`, thus the limit `(y, 𝒰)` also belongs to that set.
      this.mem_of_tendsto (hy.prod_mk_nhds (Filter.tendsto_pure_self (𝒰 : Filter X)))
        (eventually_of_forall fun x ↦ ⟨⟨x, pure x⟩, subset_closure rfl, rfl⟩)
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
  -- In `X × Filter X`, consider the closed set `F := closure {(x, ℱ) | ℱ = pure x}`
    let F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
  -- Since `f × id` is closed, the set `(f × id) '' F` is also closed.
    have := H.2 F isClosed_closure
  -- Let us show that `(y, 𝒰) ∈ (f × id) '' F`.
    have : (y, ↑𝒰) ∈ Prod.map f id '' F :=
  -- Note that, by the properties of the topology on `Filter X`, the function `pure : X → Filter X`
  -- tends to the point `𝒰` of `Filter X` along the filter `𝒰` on `X`. Since `f` tends to `y` along
  -- `𝒰`, we get that the function `(f, pure) : X → (Y, Filter X)` tends to `(y, 𝒰)` along
  -- `𝒰`. Furthermore, each `(f, pure)(x) = (f × id)(x, pure x)` is clearly an element of
  -- the closed set `(f × id) '' F`, thus the limit `(y, 𝒰)` also belongs to that set.
      this.mem_of_tendsto (hy.prod_mk_nhds (Filter.tendsto_pure_self (𝒰 : Filter X)))
        (eventually_of_forall fun x ↦ ⟨⟨x, pure x⟩, subset_closure rfl, rfl⟩)
  -- The above shows that `(y, 𝒰) = (f x, 𝒰)`, for some `x : X` such that `(x, 𝒰) ∈ F`.
    

Proof state:
case mpr
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
𝒰 : Ultrafilter X
y : Y
hy : Tendsto f (↑𝒰) (𝓝 y)
F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
this✝ : IsClosed (Prod.map f id '' F)
this : (y, ↑𝒰) ∈ Prod.map f id '' F
⊢ ∃ x, f x = y ∧ ↑𝒰 ≤ 𝓝 x

Next tactic:
rcases this with ⟨⟨x, _⟩, hx, ⟨_, _⟩⟩
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
  -- In `X × Filter X`, consider the closed set `F := closure {(x, ℱ) | ℱ = pure x}`
    let F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
  -- Since `f × id` is closed, the set `(f × id) '' F` is also closed.
    have := H.2 F isClosed_closure
  -- Let us show that `(y, 𝒰) ∈ (f × id) '' F`.
    have : (y, ↑𝒰) ∈ Prod.map f id '' F :=
  -- Note that, by the properties of the topology on `Filter X`, the function `pure : X → Filter X`
  -- tends to the point `𝒰` of `Filter X` along the filter `𝒰` on `X`. Since `f` tends to `y` along
  -- `𝒰`, we get that the function `(f, pure) : X → (Y, Filter X)` tends to `(y, 𝒰)` along
  -- `𝒰`. Furthermore, each `(f, pure)(x) = (f × id)(x, pure x)` is clearly an element of
  -- the closed set `(f × id) '' F`, thus the limit `(y, 𝒰)` also belongs to that set.
      this.mem_of_tendsto (hy.prod_mk_nhds (Filter.tendsto_pure_self (𝒰 : Filter X)))
        (eventually_of_forall fun x ↦ ⟨⟨x, pure x⟩, subset_closure rfl, rfl⟩)
  -- The above shows that `(y, 𝒰) = (f x, 𝒰)`, for some `x : X` such that `(x, 𝒰) ∈ F`.
    rcases this with ⟨⟨x, _⟩, hx, ⟨_, _⟩⟩
  -- We already know that `f x = y`, so to finish the proof we just have to check that `𝒰` tends
  -- to `x`. So, for `U ∈ 𝓝 x` arbitrary, let's show that `U ∈ 𝒰`. Since `𝒰` is a ultrafilter,
  -- it is enough to show that `Uᶜ` is not in `𝒰`.
    

Proof state:
case mpr.intro.mk.intro.refl
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
𝒰 : Ultrafilter X
F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
this : IsClosed (Prod.map f id '' F)
x : X
hy : Tendsto f (↑𝒰) (𝓝 (f x))
hx : (x, 𝒰.1) ∈ F
⊢ ∃ x_1, f x_1 = f x ∧ ↑𝒰 ≤ 𝓝 x_1

Next tactic:
refine ⟨x, rfl, fun U hU ↦ Ultrafilter.compl_not_mem_iff.mp fun hUc ↦ ?_⟩
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Filter X → Y × Filter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_filter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Filter X → Y × Filter X) := by
  constructor <;> intro H
  -- The direct implication is clear.
  · exact ⟨H.continuous, H.universally_closed _⟩
  · rw [isProperMap_iff_ultrafilter]
  -- Let `𝒰 : Ultrafilter X`, and assume that `f` tends to some `y` along `𝒰`.
    refine ⟨H.1, fun 𝒰 y hy ↦ ?_⟩
  -- In `X × Filter X`, consider the closed set `F := closure {(x, ℱ) | ℱ = pure x}`
    let F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
  -- Since `f × id` is closed, the set `(f × id) '' F` is also closed.
    have := H.2 F isClosed_closure
  -- Let us show that `(y, 𝒰) ∈ (f × id) '' F`.
    have : (y, ↑𝒰) ∈ Prod.map f id '' F :=
  -- Note that, by the properties of the topology on `Filter X`, the function `pure : X → Filter X`
  -- tends to the point `𝒰` of `Filter X` along the filter `𝒰` on `X`. Since `f` tends to `y` along
  -- `𝒰`, we get that the function `(f, pure) : X → (Y, Filter X)` tends to `(y, 𝒰)` along
  -- `𝒰`. Furthermore, each `(f, pure)(x) = (f × id)(x, pure x)` is clearly an element of
  -- the closed set `(f × id) '' F`, thus the limit `(y, 𝒰)` also belongs to that set.
      this.mem_of_tendsto (hy.prod_mk_nhds (Filter.tendsto_pure_self (𝒰 : Filter X)))
        (eventually_of_forall fun x ↦ ⟨⟨x, pure x⟩, subset_closure rfl, rfl⟩)
  -- The above shows that `(y, 𝒰) = (f x, 𝒰)`, for some `x : X` such that `(x, 𝒰) ∈ F`.
    rcases this with ⟨⟨x, _⟩, hx, ⟨_, _⟩⟩
  -- We already know that `f x = y`, so to finish the proof we just have to check that `𝒰` tends
  -- to `x`. So, for `U ∈ 𝓝 x` arbitrary, let's show that `U ∈ 𝒰`. Since `𝒰` is a ultrafilter,
  -- it is enough to show that `Uᶜ` is not in `𝒰`.
    refine ⟨x, rfl, fun U hU ↦ Ultrafilter.compl_not_mem_iff.mp fun hUc ↦ ?_⟩
    

Proof state:
case mpr.intro.mk.intro.refl
X✝ : Type ?u.51378
Y✝ : Type ?u.51381
Z : Type ?u.51384
W : Type ?u.51387
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
H : Continuous f ∧ IsClosedMap (Prod.map f id)
𝒰 : Ultrafilter X
F : Set (X × Filter X) := closure {xℱ | xℱ.2 = pure xℱ.1}
this : IsClosed (Prod.map f id '' F)
x : X
hy : Tendsto f (↑𝒰) (𝓝 (f x))
hx : (x, 𝒰.1) ∈ F
U : Set X
hU : U ∈ 𝓝 x
hUc : Uᶜ ∈ 𝒰
⊢ False

Next tactic:
rw [mem_closure_iff_nhds] at hx
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Ultrafilter X → Y × Ultrafilter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_ultrafilter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Ultrafilter X → Y × Ultrafilter X) := by
  -- The proof is basically the same as above.
  

Proof state:
X✝ : Type ?u.53372
Y✝ : Type ?u.53375
Z : Type ?u.53378
W : Type ?u.53381
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
⊢ IsProperMap f ↔ Continuous f ∧ IsClosedMap (Prod.map f id)

Next tactic:
constructor
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Ultrafilter X → Y × Ultrafilter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_ultrafilter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Ultrafilter X → Y × Ultrafilter X) := by
  -- The proof is basically the same as above.
  constructor <;> 

Proof state:
case mp
X✝ : Type ?u.53372
Y✝ : Type ?u.53375
Z : Type ?u.53378
W : Type ?u.53381
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
⊢ IsProperMap f → Continuous f ∧ IsClosedMap (Prod.map f id)

Next tactic:
intro H
/-- A map `f : X → Y` is proper if and only if it is continuous and the map
`(Prod.map f id : X × Ultrafilter X → Y × Ultrafilter X)` is closed. This is stronger than
`isProperMap_iff_universally_closed` since it shows that there's only one space to check to get
properness, but in most cases it doesn't matter. -/
theorem isProperMap_iff_isClosedMap_ultrafilter {X : Type u} {Y : Type v} [TopologicalSpace X]
    [TopologicalSpace Y] {f : X → Y} :
    IsProperMap f ↔ Continuous f ∧ IsClosedMap
      (Prod.map f id : X × Ultrafilter X → Y × Ultrafilter X) := by
  -- The proof is basically the same as above.
  constructor <;> 

Proof state:
case mpr
X✝ : Type ?u.53372
Y✝ : Type ?u.53375
Z : Type ?u.53378
W : Type ?u.53381
inst✝⁵ : TopologicalSpace X✝
inst✝⁴ : TopologicalSpace Y✝
inst✝³ : TopologicalSpace Z
inst✝² : TopologicalSpace W
f✝ : X✝ → Y✝
X : Type u
Y : Type v
inst✝¹ : TopologicalSpace X
inst✝ : TopologicalSpace Y
f : X → Y
⊢ Continuous f ∧ IsClosedMap (Prod.map f id) → IsProperMap f

Next tactic:
intro H