/-- A finite type torsion free module over a PID admits a basis. -/
noncomputable def Module.basisOfFiniteTypeTorsionFree [Fintype ι] {s : ι → M}
    (hs : span R (range s) = ⊤) [NoZeroSMulDivisors R M] : Σn : ℕ, Basis (Fin n) R M := by
  classical
    -- We define `N` as the submodule spanned by a maximal linear independent subfamily of `s`
    have := exists_maximal_independent R s
    let I : Set ι := this.choose
    obtain
      ⟨indepI : LinearIndependent R (s ∘ (fun x => x) : I → M), hI :
        ∀ i ∉ I, ∃ a : R, a ≠ 0 ∧ a • s i ∈ span R (s '' I)⟩ :=
      this.choose_spec
    let N := span R (range <| (s ∘ (fun x => x) : I → M))
    -- same as `span R (s '' I)` but more convenient
    let _sI : I → N := fun i ↦ ⟨s i.1, subset_span (mem_range_self i)⟩
    -- `s` restricted to `I` is a basis of `N`
    let sI_basis : Basis I R N := Basis.span indepI
    -- Our first goal is to build `A ≠ 0` such that `A • M ⊆ N`
    have exists_a : ∀ i : ι, ∃ a : R, a ≠ 0 ∧ a • s i ∈ N := by
      intro i
      by_cases hi : i ∈ I
      · use 1, zero_ne_one.symm
        rw [one_smul]
        exact subset_span (mem_range_self (⟨i, hi⟩ : I))
      · simpa [image_eq_range s I] using hI i hi
    choose a ha ha' using exists_a
    let A := ∏ i, a i
    have hA : A ≠ 0 := by
      rw [Finset.prod_ne_zero_iff]
      simpa using ha
    -- `M ≃ A • M` because `M` is torsion free and `A ≠ 0`
    let φ : M →ₗ[R] M := LinearMap.lsmul R M A
    have : LinearMap.ker φ = ⊥ := @LinearMap.ker_lsmul R M _ _ _ _ _ hA
    let ψ := LinearEquiv.ofInjective φ (LinearMap.ker_eq_bot.mp this)
    have : LinearMap.range φ ≤ N := by
      -- as announced, `A • M ⊆ N`
      suffices ∀ i, φ (s i) ∈ N by
        rw [LinearMap.range_eq_map, ← hs, map_span_le]
        rintro _ ⟨i, rfl⟩
        apply this
      intro i
      calc
        (∏ j, a j) • s i = (∏ j in {i}ᶜ, a j) • a i • s i := by
          rw [Fintype.prod_eq_prod_compl_mul i, mul_smul]
        _ ∈ N := N.smul_mem _ (ha' i)

    -- Since a submodule of a free `R`-module is free, we get that `A • M` is free
    

Proof state:
case intro
ι : Type u_1
R : Type u_2
inst✝⁶ : CommRing R
inst✝⁵ : IsDomain R
inst✝⁴ : IsPrincipalIdealRing R
M : Type u_3
inst✝³ : AddCommGroup M
inst✝² : Module R M
b : ι → M
inst✝¹ : Fintype ι
s : ι → M
hs : span R (range s) = ⊤
inst✝ : NoZeroSMulDivisors R M
this✝¹ : ∃ I, (LinearIndependent R fun (x : ↑I) => s ↑x) ∧ ∀ i ∉ I, ∃ a, a ≠ 0 ∧ a • s i ∈ span R (s '' I)
I : Set ι := Exists.choose this✝¹
indepI : LinearIndependent (ι := ↑I) R (s ∘ fun x => ↑x)
hI : ∀ i ∉ I, ∃ a, a ≠ 0 ∧ a • s i ∈ span R (s '' I)
N : Submodule R M := span R (range (s ∘ fun x => ↑x))
_sI : ↑I → ↥N := fun i => { val := s ↑i, property := (_ : s ↑i ∈ ↑(span R (range (s ∘ fun x => ↑x)))) }
sI_basis : Basis (↑I) R ↥N := Basis.span indepI
a : ι → R
ha : ∀ (i : ι), a i ≠ 0
ha' : ∀ (i : ι), a i • s i ∈ N
A : R := ∏ i : ι, a i
hA : A ≠ 0
φ : M →ₗ[R] M := (LinearMap.lsmul R M) A
this✝ : LinearMap.ker φ = ⊥
ψ : M ≃ₗ[R] ↥(LinearMap.range φ) := LinearEquiv.ofInjective φ (_ : Function.Injective ⇑φ)
this : LinearMap.range φ ≤ N
⊢ (n : ℕ) × Basis (Fin n) R M

Next tactic:
obtain ⟨n, b : Basis (Fin n) R (LinearMap.range φ)⟩ := Submodule.basisOfPidOfLE this sI_basis