Unnamed: 0 int64 0 999 | name stringlengths 9 60 | description stringlengths 168 5.26k | solution stringlengths 38 20.8k |
|---|---|---|---|
100 | 846_B. Math Show | Polycarp takes part in a math show. He is given n tasks, each consists of k subtasks, numbered 1 through k. It takes him tj minutes to solve the j-th subtask of any task. Thus, time required to solve a subtask depends only on its index, but not on the task itself. Polycarp can solve subtasks in any order.
By solving s... | n, k, m = list(map(int, input().split()))
t = sorted(map(int, input().split()))
res = 0
for x in range(min(m//sum(t),n)+1):
rem = m - x*sum(t)
r = x*(k+1)
for i in range(k):
div = min(rem//t[i], n-x)
rem -= div*t[i]
r += div
res = max(res, r)
print(res) |
101 | 893_A. Chess For Three | Alex, Bob and Carl will soon participate in a team chess tournament. Since they are all in the same team, they have decided to practise really hard before the tournament. But it's a bit difficult for them because chess is a game for two players, not three.
So they play with each other according to following rules:
... | num=int(input())
spectator=3
p1=1
p2=2
yes=True
for i in range(0,num):
winner=int(input())
if winner is spectator:
print("NO")
yes=False
break
if p1 is winner:
temp=spectator
spectator=p2
p2=temp
else:
temp=spectator
spectator=p1
p1... |
102 | 937_D. Sleepy Game | Petya and Vasya arranged a game. The game runs by the following rules. Players have a directed graph consisting of n vertices and m edges. One of the vertices contains a chip. Initially the chip is located at vertex s. Players take turns moving the chip along some edge of the graph. Petya goes first. Player who can't m... | n,m = map(int, input().split())
g = [[] for i in range(n)]
fs = set()
for i in range(n):
a = list(map(int , input().split()))
c = a[0]
if c == 0:
fs.add(i)
continue
for j in range(1,c+1):
g[i].append(a[j]-1)
s = int(input())-1
prev0 = [None for i in range(n)]
prev1=[None for i i... |
103 | 990_B. Micro-World | You have a Petri dish with bacteria and you are preparing to dive into the harsh micro-world. But, unfortunately, you don't have any microscope nearby, so you can't watch them.
You know that you have n bacteria in the Petri dish and size of the i-th bacteria is a_i. Also you know intergalactic positive integer constan... | n, m = map(int, input().split())
l = sorted(map(int, input().split()))
t, b = l[::-1], -m
for a in l:
while b < a:
if a <= b + m:
n -= 1
b = t.pop()
print(n) |
104 | 1030_E. Vasya and Good Sequences | Vasya has a sequence a consisting of n integers a_1, a_2, ..., a_n. Vasya may pefrom the following operation: choose some number from the sequence and swap any pair of bits in its binary representation. For example, Vasya can transform number 6 (... 00000000110_2) into 3 (... 00000000011_2), 12 (... 000000001100_2), 10... | #Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
import collections
from itertools import permutations
from collections import defaultdict
from collections import deque
import threadi... |
105 | 1096_E. The Top Scorer | Hasan loves playing games and has recently discovered a game called TopScore. In this soccer-like game there are p players doing penalty shoot-outs. Winner is the one who scores the most. In case of ties, one of the top-scorers will be declared as the winner randomly with equal probability.
They have just finished the... | base=998244353;
def power(x, y):
if(y==0):
return 1
t=power(x, y//2)
t=(t*t)%base
if(y%2):
t=(t*x)%base
return t;
def inverse(x):
return power(x, base-2)
f=[1]
iv=[1]
for i in range(1, 5555):
f.append((f[i-1]*i)%base)
iv.append(inverse(f[i]))
def C(n, k):
return (f[n]... |
106 | 1144_B. Parity Alternated Deletions | Polycarp has an array a consisting of n integers.
He wants to play a game with this array. The game consists of several moves. On the first move he chooses any element and deletes it (after the first move the array contains n-1 elements). For each of the next moves he chooses any element with the only restriction: its... | n=int(input())
arr=list(map(int,input().split()))
arr.sort()
even=[]
odd=[]
e=0
o=0
for i in arr:
if (i%2)==0:
even=even+[i]
e=e+1
else:
odd=odd+[i]
o=o+1
if (e>o) and (e-o)>1:
print(sum(even[:(e-o-1)]))
elif (o>e) and (o-e)>1:
print(sum(odd[:(o-e-1)]))
else:
print(0)
|
107 | 1165_A. Remainder | You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly zero) operations with this number. During each operation you are allowed to change any digit of your number; you may change 0... | n,x,y = map(int,input().split())
s = input()[-x:]
if(y == 0):
num = s[:-(y+1)].count('1')
else:
num = s[:-(y+1)].count('1') + s[-y:].count('1')
if(s[-(y+1)] == "0"):
num = num + 1
print(num) |
108 | 1244_C. The Football Season | The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match, it gets w points, and the opposing team gets 0 points. If the game results in ... | import sys
from sys import argv
def extendedEuclideanAlgorithm(old_r, r):
negative = False
s, old_t = 0, 0
old_s, t = 1, 1
if (r < 0):
r = abs(r)
negative = True
while r > 0:
q = old_r // r
#MCD:
r, old_r = old_r - q * r, r
#Coeficiente s:
... |
109 | 1264_A. Beautiful Regional Contest | So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by the number of solved problems, then p_1 ≥ p_2 ≥ ... ≥ p_n.
Help the jury distrib... | '''input
5
12
5 4 4 3 2 2 1 1 1 1 1 1
4
4 3 2 1
1
1000000
20
20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1
32
64 64 63 58 58 58 58 58 37 37 37 37 34 34 28 28 28 28 28 28 24 24 19 17 17 17 17 16 16 16 16 11
'''
t=int(input())
for i in range(t):
n=int(input())
s=list(map(int,input().split()))
if n//2<3:
print("... |
110 | 1285_C. Fadi and LCM | Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.
LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.
O... | def LMC(a, b):
n = a * b
while a != 0 and b != 0:
if a > b:
a = a % b
else:
b = b % a
nod = a + b
nok = n // nod
return nok
from math import sqrt, ceil
n = int(input())
dividers = []
for i in range(1, ceil(sqrt(n))):
if n % i == 0:
dividers.appe... |
111 | 1304_E. 1-Trees and Queries | Gildong was hiking a mountain, walking by millions of trees. Inspired by them, he suddenly came up with an interesting idea for trees in data structures: What if we add another edge in a tree?
Then he found that such tree-like graphs are called 1-trees. Since Gildong was bored of solving too many tree problems, he wan... | import sys, os
class RangeQuery:
def __init__(self, data, func=min):
self.func = func
self._data = _data = [list(data)]
i, n = 1, len(_data[0])
while 2 * i <= n:
prev = _data[-1]
_data.append([func(prev[j], prev[j + i]) for j in range(n - 2 * i + 1)])
... |
112 | 1328_F. Make k Equal | You are given the array a consisting of n elements and the integer k ≤ n.
You want to obtain at least k equal elements in the array a. In one move, you can make one of the following two operations:
* Take one of the minimum elements of the array and increase its value by one (more formally, if the minimum value of ... | n, k = map(int, input().split())
a = sorted(list(map(int, input().split())))
cnt = dict()
sum = dict()
res = n * 20
for x in a:
y = x
cur = 0
while True:
if y == 0:
break
if y not in cnt:
cnt[y] = 0
sum[y] = 0
if cnt[y] < k:
cnt[y] +... |
113 | 1369_D. TediousLee | Lee tried so hard to make a good div.2 D problem to balance his recent contest, but it still doesn't feel good at all. Lee invented it so tediously slow that he managed to develop a phobia about div.2 D problem setting instead. And now he is hiding behind the bushes...
Let's define a Rooted Dead Bush (RDB) of level n ... | import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): retu... |
114 | 1391_C. Cyclic Permutations | A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).
Consider a permutation p of length ... | n = int(input())
M = 10**9+7
fact = [1]*(n+2)
for i in range(2, n+1):
fact[i] = (i*fact[i-1])%M
print(((fact[n]-pow(2, n-1, M))+M)%M) |
115 | 180_D. Name | Everything got unclear to us in a far away constellation Tau Ceti. Specifically, the Taucetians choose names to their children in a very peculiar manner.
Two young parents abac and bbad think what name to give to their first-born child. They decided that the name will be the permutation of letters of string s. To keep... | def findmin(lcopy, toexceed):
toex = ord(toexceed) - 97
for each in lcopy[(toex+1):]:
if each > 0:
return True
return False
def arrange(lcopy, toexceed = None):
if toexceed is None:
ans = ""
for i in range(26):
ans += chr(i+97)*lcopy[i]
return ans... |
116 | 252_B. Unsorting Array | Little Petya likes arrays of integers a lot. Recently his mother has presented him one such array consisting of n elements. Petya is now wondering whether he can swap any two distinct integers in the array so that the array got unsorted. Please note that Petya can not swap equal integers even if they are in distinct po... | n=int(input())
a=[int(i) for i in input().split()]
b=len(set(a))
c=sorted(a,reverse=True)
if n==1 or n==2 or b==1:
print("-1")
elif n==3:
if b==2:
if a[0]==a[2]:
print("-1")
elif a[0]==a[1]:
print("2 3")
else:
print("1 2")
elif a[1]!=max(a[0],a[1],... |
117 | 348_A. Mafia | One day n friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other n - 1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the i-th person wants to play ai rounds. What is the minimum number ... | # mafia
N=int(input())
a=list(map(int,input().split()))
def isok(X):
sums=0
for num in a:
if X<num:
return False
sums+=max(0,X-num)
if sums>=X:
return True
return False
l=0
r=10**12
#l -- case_impossible
#r --case_possible
while r-l>1:
m=(l+r)//2
... |
118 | 371_B. Fox Dividing Cheese | Two little greedy bears have found two pieces of cheese in the forest of weight a and b grams, correspondingly. The bears are so greedy that they are ready to fight for the larger piece. That's where the fox comes in and starts the dialog: "Little bears, wait a little, I want to make your pieces equal" "Come off it fox... | from math import pow
def take_input(s): #for integer inputs
if s == 1: return int(input())
return map(int, input().split())
def factor(n,k):
i = 0
while(n%k==0):
i += 1
n //= k
return i
a, b = take_input(2)
count = 0
if a == b:
print(0)
exit()
a_fac_2 = f... |
119 | 442_C. Artem and Array | Artem has an array of n positive integers. Artem decided to play with it. The game consists of n moves. Each move goes like this. Artem chooses some element of the array and removes it. For that, he gets min(a, b) points, where a and b are numbers that were adjacent with the removed number. If the number doesn't have a... |
MAXN = 5 * 10**5 + 100
a = []
ans = 0
n = int(input())
a = list( map ( int, input().split() ) )
a.append(0)
a = [0] + a
n = n + 2
arr = []
arr.append( a[0] )
arr.append( a[1] )
i = 2
while i < n :
ln = a[i]
l1 = arr[-1]
l0 = arr[-2]
while l1 <= l0 and l1 <= ln :
ans = ans + min ( l0 , ln )
arr.pop()
... |
120 | 488_C. Fight the Monster | A monster is attacking the Cyberland!
Master Yang, a braver, is going to beat the monster. Yang and the monster each have 3 attributes: hitpoints (HP), offensive power (ATK) and defensive power (DEF).
During the battle, every second the monster's HP decrease by max(0, ATKY - DEFM), while Yang's HP decreases by max(0,... | # HEY STALKER
hp_y, at_y, df_y = map(int, input().split())
hp_m, at_m, df_m = map(int, input().split())
cst_hp, cst_at, cst_df = map(int, input().split())
ans = 2e18
for ati in range(201):
for dfi in range(201):
if ati + at_y > df_m:
k = hp_m // ((at_y + ati) - df_m)
if hp_m % ((at_y... |
121 | 512_B. Fox And Jumping | Fox Ciel is playing a game. In this game there is an infinite long tape with cells indexed by integers (positive, negative and zero). At the beginning she is standing at the cell 0.
There are also n cards, each card has 2 attributes: length li and cost ci. If she pays ci dollars then she can apply i-th card. After app... | def gcd(x,y):
while x % y > 0:
x, y = y, x % y
return y
n = int(input())
a, b, c = [int(x) for x in input().split()], [int(x) for x in input().split()], [{} for i in range(n)]
def f(i,g):
if g == 1:
return 0
if i == n:
return 100000000000
if g in c[i]:
return c[i][g]
... |
122 | 560_D. Equivalent Strings | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases:
1. They are equal.
2. If we split string a into two halves of the same size a1 and a2, and string b into two halves of the same size b1 and b2... | def equals(a, b):
if (a == b):
return True
len_a, len_b = len(a), len(b)
if (len_a & 1 or len_b & 1):
return False
if (len_a == 1):
return False
as1 = a[0:len_a//2]
as2 = a[len_a//2:(len_a//2)*2]
bs1 = b[:len_b//2]
bs2 = b[len_b//2:(len_b//2)*2]
return (equals(as1, bs2) and equals... |
123 | 586_F. Lizard Era: Beginning | In the game Lizard Era: Beginning the protagonist will travel with three companions: Lynn, Meliana and Worrigan. Overall the game has n mandatory quests. To perform each of them, you need to take exactly two companions.
The attitude of each of the companions to the hero is an integer. Initially, the attitude of each o... | #!/usr/bin/env python3
n = int(input())
a = [0] * n
b = [0] * n
c = [0] * n
for i in range(n):
a[i], b[i], c[i] = map(int, input().split())
middle = { }
stack = [ ]
result = (-1e10, ())
phase = 1
def search(pos, l, m, w):
global result
if (pos == n >> 1) if phase == 1 else (pos < n >> 1):
if phas... |
124 | 609_B. The Best Gift | Emily's birthday is next week and Jack has decided to buy a present for her. He knows she loves books so he goes to the local bookshop, where there are n books on sale from one of m genres.
In the bookshop, Jack decides to buy two books of different genres.
Based on the genre of books on sale in the shop, find the nu... | n, m = list(map(int, input().split()))
a = list(map(int, input().split()))
t = 0
for i in range(m):
cnt = a.count(i + 1)
t += cnt * (n - cnt)
n -= cnt
print(t)
|
125 | 630_A. Again Twenty Five! | The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the number. Yes, of course, n can be rather big, and one cannot find the power using ... | n=int(input())
if(n==0):
print(1)
elif(n==1):
print(5)
else:
print(25) |
126 | 656_E. Out of Controls | You are given a complete undirected graph. For each pair of vertices you are given the length of the edge that connects them. Find the shortest paths between each pair of vertices in the graph and return the length of the longest of them.
Input
The first line of the input contains a single integer N (3 ≤ N ≤ 10).
Th... | #!/usr/bin/python3
import sys
sys.setrecursionlimit(10000)
n = int(input())
a = []
def read(i):
try:
1 / (n - i)
a.append(list(map(int, input().split())))
read(i + 1);
except:
pass
def f(i, j, k):
try:
1 / (n - i)
1 / (n - j)
1 / (n - k)
a... |
127 | 702_E. Analysis of Pathes in Functional Graph | You are given a functional graph. It is a directed graph, in which from each vertex goes exactly one arc. The vertices are numerated from 0 to n - 1.
Graph is given as the array f0, f1, ..., fn - 1, where fi — the number of vertex to which goes the only arc from the vertex i. Besides you are given array with weights o... | import sys
n, k = map(int, sys.stdin.buffer.readline().decode('utf-8').split())
a = list(map(int, sys.stdin.buffer.readline().decode('utf-8').split()))
b = list(map(int, sys.stdin.buffer.readline().decode('utf-8').split()))
logk = len(bin(k)) - 2
sum_w, sum_w_p = b[:], b[:]
min_w, min_w_p = b[:], b[:]
dest, dest_p = a... |
128 | 814_C. An impassioned circulation of affection | Nadeko's birthday is approaching! As she decorated the room for the party, a long garland of Dianthus-shaped paper pieces was placed on a prominent part of the wall. Brother Koyomi will like it!
Still unsatisfied with the garland, Nadeko decided to polish it again. The garland has n pieces numbered from 1 to n from le... | """ Python 3 compatibility tools. """
from __future__ import division, print_function
import itertools
import sys
import os
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
input = raw_input
range = xrange
filter = itertools.ifilter
map = itertools.imap
zip = itertools.izip
def is_it_local():
... |
129 | 83_C. Track | You already know that Valery's favorite sport is biathlon. Due to your help, he learned to shoot without missing, and his skills are unmatched at the shooting range. But now a smaller task is to be performed, he should learn to complete the path fastest.
The track's map is represented by a rectangle n × m in size divi... | import sys
from array import array # noqa: F401
from itertools import combinations
from collections import deque
def input():
return sys.stdin.buffer.readline().decode('utf-8')
n, m, k = map(int, input().split())
chars = (
['}' * (m + 2)]
+ ['}' + ''.join('{' if c == 'S' else '|' if c == 'T' else c for... |
130 | 886_D. Restoration of string | A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Res... | StringsNumber = int(input())
FinalStrings = []
Strings = []
for i in range(StringsNumber):
Strings.append(input())
LetterGraph = {}
# Генерим граф
for i in range(len(Strings)):
if len(Strings[i]) == 1:
if Strings[i] not in LetterGraph:
LetterGraph[Strings[i]] = ""
#print("заа... |
131 | 909_D. Colorful Points | You are given a set of points on a straight line. Each point has a color assigned to it. For point a, its neighbors are the points which don't have any other points between them and a. Each point has at most two neighbors - one from the left and one from the right.
You perform a sequence of operations on this set of p... | name = input()
blocks = []
now = name[0]
counter = 1
for x in range(1, len(name)):
if name[x] != now:
blocks.append((now, counter))
now = name[x]
counter = 1
else:
counter += 1
blocks.append((now, counter))
counter = 0
temp = []
while len(blocks) > 1:
counter += 1
temp ... |
132 | 931_A. Friends Meeting | Two friends are on the coordinate axis Ox in points with integer coordinates. One of them is in the point x1 = a, another one is in the point x2 = b.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the f... | a=int(input())
b=int(input())
def fact(a):
ans=0
for i in range(a,0,-1):
ans=ans+i
return ans
d=abs(a-b)
if d==1:
print("1")
elif d%2==0:
a=fact(d//2)
a=a*2
print(a)
else:
a=fact(d//2)
b=fact((d+1)//2)
print(a+b)
|
133 | 985_A. Chess Placing | You are given a chessboard of size 1 × n. It is guaranteed that n is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than one chess piece. It is known that the total number of pieces equals to <image>.
In one step you can mov... | import re
import math
import decimal
import bisect
def read():
return input().strip()
n = int(read())
ps = [0 for i in range(1, n+1)]
nadd = 10
for x in sorted([int(_) for _ in read().split()]):
ps[x-1] = nadd
nadd += 10
nadd = 15
for i, p in enumerate(ps):
if p == 0:
ps[i] = nadd
nadd += 10
# print(ps)
swap... |
134 | 1003_D. Coins and Queries | Polycarp has n coins, the value of the i-th coin is a_i. It is guaranteed that all the values are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
Polycarp wants to know answers on q queries. The j-th query is described as integer number b_j. The answer to the query is the minimum number of... | # @oj: codeforces
# @id: hitwanyang
# @email: 296866643@qq.com
# @date: 2020-10-14 16:44
# @url:https://codeforc.es/contest/1003/problem/D
import sys,os
from io import BytesIO, IOBase
import collections,itertools,bisect,heapq,math,string
from decimal import *
# region fastio
BUFSIZE = 8192
BUFSIZE = 8192
class FastI... |
135 | 1027_E. Inverse Coloring | You are given a square board, consisting of n rows and n columns. Each tile in it should be colored either white or black.
Let's call some coloring beautiful if each pair of adjacent rows are either the same or different in every position. The same condition should be held for the columns as well.
Let's call some col... | import sys
from array import array # noqa: F401
def readline(): return sys.stdin.buffer.readline().decode('utf-8')
n, k = map(int, readline().split())
mod = 998244353
if k == 1:
print(0)
exit()
dp1 = [array('i', [0])*n for _ in range(n)]
dp2 = [array('i', [0])*n for _ in range(n)]
dp1[0][0] = 1
for i i... |
136 | 1110_E. Magic Stones | Grigory has n magic stones, conveniently numbered from 1 to n. The charge of the i-th stone is equal to c_i.
Sometimes Grigory gets bored and selects some inner stone (that is, some stone with index i, where 2 ≤ i ≤ n - 1), and after that synchronizes it with neighboring stones. After that, the chosen stone loses its ... | n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
f=a[0]==b[0]
a=sorted([a[i+1]-a[i] for i in range(n-1)])
b=sorted([b[i+1]-b[i] for i in range(n-1)])
print('YES' if f and a==b else 'NO')
|
137 | 1140_B. Good String | You have a string s of length n consisting of only characters > and <. You may do some operations with this string, for each operation you have to choose some character that still remains in the string. If you choose a character >, the character that comes right after it is deleted (if the character you chose was the l... | t = int(input())
tests = []
for i in range(t):
length = int(input())
tests.append(input())
def solve(s):
streak1 = 0
streak2 = 0
for i in range(len(s)):
if s[i] == "<":
streak1 +=1
else:
break
for i in range(len(s)):
if s[-i-1] == ">":
... |
138 | 1199_E. Matching vs Independent Set | You are given a graph with 3 ⋅ n vertices and m edges. You are to find a matching of n edges, or an independent set of n vertices.
A set of edges is called a matching if no two edges share an endpoint.
A set of vertices is called an independent set if no two vertices are connected with an edge.
Input
The first line... | import sys
input = sys.stdin.readline
T = int(input())
for _ in range(T):
n, m = map(int, input().split())
v = [True] * (3 * n + 1)
e = [0] * n
ptr = 0
for i in range(1, m + 1):
a, b = map(int, input().split())
if ptr < n and v[a] and v[b]:
e[ptr] = i
ptr += 1... |
139 | 1216_D. Swords | There were n types of swords in the theater basement which had been used during the plays. Moreover there were exactly x swords of each type. y people have broken into the theater basement and each of them has taken exactly z swords of some single type. Note that different people might have taken different types of swo... | n= int(input())
s = list(map(int,input().split()))
s.sort()
maxm = s[n-1]
ans = 0
def computeGCD(x, y):
while(y):
x, y = y, x % y
return x
a = maxm-s[0]
for i in range(1,n-1):
a = computeGCD(a,maxm-s[i])
for i in range(0,n-1):
ans += maxm - s[i]
print(ans//a,a)
|
140 | 1281_B. Azamon Web Services | Your friend Jeff Zebos has been trying to run his new online company, but it's not going very well. He's not getting a lot of sales on his website which he decided to call Azamon. His big problem, you think, is that he's not ranking high enough on the search engines. If only he could rename his products to have better ... | for _ in range(int(input())):
a,c=input().split()
a=list(a)
b=sorted(a)
if a!=b:
for i,x in enumerate(b):
if a[i]!=x:
tmp=a[i]
a[i]=x
break
for i in range(len(a)-1,-1,-1):
if a[i]==x:
a[i]=tmp
... |
141 | 1325_B. CopyCopyCopyCopyCopy | Ehab has an array a of length n. He has just enough free time to make a new array consisting of n copies of the old array, written back-to-back. What will be the length of the new array's longest increasing subsequence?
A sequence a is a subsequence of an array b if a can be obtained from b by deletion of several (pos... | t = int(input())
for i in range(t):
n = int(input())
a = input().split()
s_a = set(a)
print(f"{len(s_a)}\n")
|
142 | 1344_A. Hilbert's Hotel | Hilbert's Hotel is a very unusual hotel since the number of rooms is infinite! In fact, there is exactly one room for every integer, including zero and negative integers. Even stranger, the hotel is currently at full capacity, meaning there is exactly one guest in every room. The hotel's manager, David Hilbert himself,... | # cook your dish here
t=int(input())
for _ in range(t):
n=int(input())
a=list(map(int,input().split()))
l=[0]*n
d={}
f=0
for i in range(n):
l[i]=i+a[i%n]
d[l[i]]=d.get(l[i],0)+1
if d[l[i]]==2:
f=1
break
r={}
for i in range(n):
r[l[i... |
143 | 1366_A. Shovels and Swords | Polycarp plays a well-known computer game (we won't mention its name). In this game, he can craft tools of two types — shovels and swords. To craft a shovel, Polycarp spends two sticks and one diamond; to craft a sword, Polycarp spends two diamonds and one stick.
Each tool can be sold for exactly one emerald. How many... | import math
t=int(input())
for i in range(t):
a,b=map(int,input().split())
m=min(a,b,(a+b)/3)
print(math.floor(m))
|
144 | 1408_A. Circle Coloring | You are given three sequences: a_1, a_2, …, a_n; b_1, b_2, …, b_n; c_1, c_2, …, c_n.
For each i, a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i.
Find a sequence p_1, p_2, …, p_n, that satisfy the following conditions:
* p_i ∈ \\{a_i, b_i, c_i\}
* p_i ≠ p_{(i mod n) + 1}.
In other words, for each element, you need to choose ... | import sys
from sys import stdin,stdout
import math
import random
import heapq
from collections import Counter
from functools import lru_cache
#@lru_cache(maxsize=None) #for optimizing the execution time of callable objects/functions(placed above callable functions)
try:
for _ in range(int(input())):
n=int(... |
145 | 1428_D. Bouncing Boomerangs | To improve the boomerang throwing skills of the animals, Zookeeper has set up an n × n grid with some targets, where each row and each column has at most 2 targets each. The rows are numbered from 1 to n from top to bottom, and the columns are numbered from 1 to n from left to right.
For each column, Zookeeper will t... | n, *a = map(int, open(0).read().split())
now = 1
heights = [[] for _ in range(n)]
st0 = []
st1 = []
failed = False
for i in range(n - 1, -1, -1):
if a[i] == 1:
heights[i].append(now)
st0.append((now, i))
now += 1
elif a[i] == 2:
if len(st0):
h, j = st0.pop()
... |
146 | 1475_D. Cleaning the Phone | Polycarp often uses his smartphone. He has already installed n applications on it. Application with number i takes up a_i units of memory.
Polycarp wants to free at least m units of memory (by removing some applications).
Of course, some applications are more important to Polycarp than others. He came up with the fol... | #lösningsmängd är nedåtbegränsad och ordnad. -> optimal minsta existerar i kontext.
#Vet att det är sant att lösning består av x stna 1-cost x tillhör [0..all(1-cost)]
#för x stna 1-cost bestäms y stna 2-cost entydligt.
#itererar alla x, försök i varje steg reducera y från mx(2-cost)
#same hold tru if conv points 1 an... |
147 | 1500_B. Two chandeliers | Vasya is a CEO of a big construction company. And as any other big boss he has a spacious, richly furnished office with two crystal chandeliers. To stay motivated Vasya needs the color of light at his office to change every day. That's why he ordered both chandeliers that can change its color cyclically. For example: r... | def main():
n, m, k = list(map(lambda x: int(x), str(input()).split(' ')))
a = list(map(lambda x: int(x), str(input()).split(' ')))
b = list(map(lambda x: int(x), str(input()).split(' ')))
if n < m:
print(solve(m, n, k, b, a))
return
print(solve(n, m, k, a, b))
def solve(n, m, k, a,... |
148 | 1525_D. Armchairs | There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not greater than n/2.
For some reason, you would like to tell people to move from their armchairs to some other ones. If the i-th ... | import sys
input = sys.stdin.buffer.readline
import math
n=int(input())
arr=[int(x) for x in input().split()]
h=[]
v=[]
for i in range(n):
if arr[i]:
v.append(i)
else:
h.append(i)
hh=len(h)
vv=len(v)
dp=[[0 for j in range(hh+1)] for i in range(vv+1)]
for i in range(1,vv+1):
dp[i][0]=mat... |
149 | 157_A. Game Outcome | Sherlock Holmes and Dr. Watson played some game on a checkered board n × n in size. During the game they put numbers on the board's squares by some tricky rules we don't know. However, the game is now over and each square of the board contains exactly one number. To understand who has won, they need to count the number... | n = int(input())
r = lambda : list(map(int, input().split()))
arr = []
for i in range(n):
a = r()
arr.append(a)
row = [sum(i) for i in arr]
col = []
for i in range(n):
c = 0
for j in range(n): c+=arr[j][i]
col.append(c)
ans = 0
for i in range(n):
for j in range(n):
if row[i] < col[j... |
150 | 178_A1. Educational Game | The Smart Beaver from ABBYY began to develop a new educational game for children. The rules of the game are fairly simple and are described below.
The playing field is a sequence of n non-negative integers ai numbered from 1 to n. The goal of the game is to make numbers a1, a2, ..., ak (i.e. some prefix of the sequenc... | n = int(input())
a = [int(t) for t in input().split()]
c = 0
for i in range(n - 1):
if a[i] > 0:
c += a[i]
print(c)
j = 0
while 2 ** j + i < n:
j += 1
a[2 ** (j - 1) + i] += a[i]
a[i] = 0
else:
print(c) |
151 | 19_B. Checkout Assistant | Bob came to a cash & carry store, put n items into his trolley, and went to the checkout counter to pay. Each item is described by its price ci and time ti in seconds that a checkout assistant spends on this item. While the checkout assistant is occupied with some item, Bob can steal some other items from his trolley. ... | n=int(input())
ar=[float('inf')]*(n+1)
ar[0]=0
for i in range(n):
t,c=map(int,input().split())
for j in range(n-1,-1,-1):
w=min(j+t+1,n)
ar[w]=min(ar[w],ar[j]+c)
print(ar[n])
|
152 | 223_C. Partial Sums | You've got an array a, consisting of n integers. The array elements are indexed from 1 to n. Let's determine a two step operation like that:
1. First we build by the array a an array s of partial sums, consisting of n elements. Element number i (1 ≤ i ≤ n) of array s equals <image>. The operation x mod y means that ... | n, k = map(int, input().split())
num = list(map(int, input().split()))
MOD = 10 ** 9 + 7
cf = [1]
for i in range(1, 2020):
cf.append((cf[-1] * (k + i - 1) * pow(i, MOD - 2, MOD)) % MOD)
ans = [0 for i in range(n)]
for i in range(n):
for j in range(i + 1):
ans[i] = (ans[i] + cf[i - j] * num[j]) % MOD
... |
153 | 248_A. Cupboards | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on n wooden ... | k = int(input())
lo=ro=rc=lc=0
for _ in range(k):
n , m = map(int,input().split())
if(n==0):
lo+=1
else:
lc=lc+1
if(m==0):
ro+=1
else :
rc=rc+1
print(min(lo,lc)+min(ro,rc))
|
154 | 272_B. Dima and Sequence | Dima got into number sequences. Now he's got sequence a1, a2, ..., an, consisting of n positive integers. Also, Dima has got a function f(x), which can be defined with the following recurrence:
* f(0) = 0;
* f(2·x) = f(x);
* f(2·x + 1) = f(x) + 1.
Dima wonders, how many pairs of indexes (i, j) (1 ≤ i < j ≤... | def f(x):
return str(bin(x)).count('1')
n = int(input())
a = list(map(int, input().split()))
ans = [f(x) for x in a]
s = set(ans)
counts = {x:ans.count(x) for x in s}
ans = 0
for i in counts:
ans += (counts[i]*(counts[i]-1))//2
print(ans) |
155 | 319_B. Psychos in a Line | There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho might kill and get killed at the same step.
You're given the initial arrangeme... | n, t = int(input()), list(map(int, input().split()))
p, s, r = [0] * n, [0] * n, t[0]
for i in range(n - 1):
j = i + 1
x = t[j]
if x > r: r = x
else:
while t[i] < x: s[j], i = max(s[j], s[i]), p[i]
p[j] = i
s[j] += 1
print(max(s))
# Made By Mostafa_Khaled |
156 | 343_B. Alternating Current | Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended u... | list_inp=input()
stack_jud=[]
for i in list_inp:
if len(stack_jud)>0:
if stack_jud[-1]==i:stack_jud.pop()
else: stack_jud.append(i)
else: stack_jud.append(i)
if stack_jud==[]:print ('Yes')
else:print ('No')
|
157 | 38_C. Blinds | The blinds are known to consist of opaque horizontal stripes that can be rotated thus regulating the amount of light flowing in the room. There are n blind stripes with the width of 1 in the factory warehouse for blind production. The problem is that all of them are spare details from different orders, that is, they ma... | m, l = map(int, input().split())
a = list(map(int, input().split()))
print(max(i * sum(ai // i for ai in a) for i in range(l, 101))) |
158 | 40_B. Repaintings | A chessboard n × m in size is given. During the zero minute we repaint all the black squares to the 0 color. During the i-th minute we repaint to the i color the initially black squares that have exactly four corner-adjacent squares painted i - 1 (all such squares are repainted simultaneously). This process continues a... | import itertools
import math
n, m = [int(k) for k in input().split()]
x = int(input())
if n-2*(x-1) < 1 or m-2*(x-1) < 1:
print(0)
elif n-2*(x-1) == 1 or m-2*(x-1) == 1:
print((n+m-4*(x-1))//2)
else: print(n+m-2 - 4*(x-1))
|
159 | 438_A. The Child and Toy | On Children's Day, the child got a toy from Delayyy as a present. However, the child is so naughty that he can't wait to destroy the toy.
The toy consists of n parts and m ropes. Each rope links two parts, but every pair of parts is linked by at most one rope. To split the toy, the child must remove all its parts. The... | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return list(map(int, sys.stdin.readline().sp... |
160 | 483_B. Friends and Presents | You have two friends. You want to present each of them several positive integers. You want to present cnt1 numbers to the first friend and cnt2 numbers to the second friend. Moreover, you want all presented numbers to be distinct, that also means that no number should be presented to both friends.
In addition, the fir... | c1,c2,x,y=map(int,input().split())
def fn(val):
f=[val//x,val//y]
both=val//(x*y)
f=[i-both for i in f]
oth=val-f[0]-f[1]-both
cnt=[c1-f[1],c2-f[0]]
if cnt[0]<0:cnt[0]=0
if cnt[1] < 0: cnt[1] = 0
return (sum(cnt)<=oth)
l=0;r=int(1e18)
while r-l>1:
m=(r+l)//2
if fn(m):
r=m... |
161 | 507_B. Amr and Pins | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius r and center in point (x, y). He wants the circle center to be in new position (x', y').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle ... | import math #.sqrt
def ceil (a, b):
return -(-a // b)
def answer(r, x, y, xp, yp):
d = math.sqrt((xp-x)**2 + (yp-y)**2)
num_rs = ceil(d, 2*r)
return int(num_rs)
def main():
r, x, y, xp, yp = [int(i) for i in input().split()]
print(answer(r, x, y, xp, yp))
return
main() |
162 | 556_C. Case of Matryoshkas | Andrewid the Android is a galaxy-famous detective. He is now investigating the case of vandalism at the exhibition of contemporary art.
The main exhibit is a construction of n matryoshka dolls that can be nested one into another. The matryoshka dolls are numbered from 1 to n. A matryoshka with a smaller number can be ... | n, m = [int(x) for x in input().split()]
a = []
for i in range(m):
a.append([int(x) for x in input().split()][1:])
b = []
curt = 0
for i in a:
j = 0
b.append([])
while (j < len(i)) and (i[j] == (j + 1)):
j += 1
if j != 0:
b[-1] = [j]
b[-1] += [1] * (len(i) - j)
curt += len(b[... |
163 | 582_A. GCD Table | The GCD table G of size n × n for an array of positive integers a of length n is defined by formula
<image>
Let us remind you that the greatest common divisor (GCD) of two positive integers x and y is the greatest integer that is divisor of both x and y, it is denoted as <image>. For example, for array a = {4, 3, 6,... | import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.wri... |
164 | 604_A. Uncowed Forces | Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challenging tasks, Kevin was uncowed and bulldozed through all of them, distinguishing himself from the herd a... | t=list(map(int,input().split()))
w=list(map(int,input().split()))
q,z=map(int,input().split())
c=0
v=0
for i in range(500,3000,500):
x=(1-(t[v]/250))*i-50*w[v]
a=max(0.3*i,x)
c=c+a
v=v+1
f=q*100-z*50
dp=c+f
print(int(dp))
|
165 | 650_B. Image Preview | Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Similarly, by swiping right from the last photo you reach photo 1. It takes a sec... | def main():
n, a, b, t = map(int, input().split())
b += 1
l = [b if char == "w" else 1 for char in input()]
t -= sum(l) - a * (n + 2)
hi, n2 = n, n * 2
n21 = n2 + 1
lo = res = 0
l *= 2
while lo <= n and hi < n2:
t -= l[hi]
hi += 1
b = hi - n
while lo <... |
166 | 675_E. Trains and Statistic | Vasya commutes by train every day. There are n train stations in the city, and at the i-th station it's possible to buy only tickets to stations from i + 1 to ai inclusive. No tickets are sold at the last station.
Let ρi, j be the minimum number of tickets one needs to buy in order to get from stations i to station j.... | n=int(input())
a=list(map(int, input().split()))
a=[ai-1 for ai in a]
a[n:n] = [n - 1]
dp=[0]*n
ans=0
i=n-2
nmax=2**17
tree=[[0,0]]*2*nmax;
#Build Segment tree
j=0
while j<n:
tree[nmax + j] = [a[j], j]
j=j+1
j=nmax-1
while j>0:
tree[j]=max(tree[j*2],tree[j*2+1])
j=j-1
#get max of a interval [lef... |
167 | 765_D. Artsem and Saunders | Artsem has a friend Saunders from University of Chicago. Saunders presented him with the following problem.
Let [n] denote the set {1, ..., n}. We will also write f: [x] → [y] when a function f is defined in integer points 1, ..., x, and all its values are integers from 1 to y.
Now then, you are given a function f: [... | n = int(input())
f = list(map(int, input().split()))
h = []
ind_h = [-1] * (n + 1)
g = [0] * n
occs = {}
for i in range(len(f)):
if f[i] not in occs:
occs[f[i]] = {i + 1}
h.append(f[i])
ind_h[f[i]] = len(h) - 1
g[i] = len(h)
else:
g[i] = ind_h[f[i]] + 1
occs[f[i]]... |
168 | 789_A. Anastasia and pebbles | Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has only two pockets. She can put at most k pebbles in each pocket at the same time.... | import math
n,k = map(int,input().split())
stones = list(map(int, input().split()))
days = 0
for i in range(n):
days += math.ceil(stones[i]/k)
print(math.ceil(days/2)) |
169 | 80_C. Heroes | The year of 2012 is coming...
According to an ancient choradrican legend in this very year, in 2012, Diablo and his brothers Mephisto and Baal will escape from hell, and innumerable hordes of demons will enslave the human world. But seven brave heroes have already gathered on the top of a mountain Arreat to protect us... | # -*- coding: utf-8 -*-
"""
Created on Fri Nov 1 14:28:37 2019
@author: PC-4
"""
from itertools import combinations, product
Teams = [[1, 1, 5],
[1, 2, 4],
[1, 3, 3],
[2, 2, 3]]
Names = {}
Names["Anka"] = 0
Names["Chapay"] = 1
Names["Cleo"] = 2
Names["Dracul"] = 3
Names["Hexadecimal"] = 4... |
170 | 835_A. Key races | Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 millis... | s, v1, v2, t1, t2 = list(map(int, input().split()))
a = 2*t1 + s*v1
b = 2*t2 + s*v2
if a > b:
print("Second")
elif a < b:
print("First")
else:
print("Friendship")
|
171 | 87_B. Vasya and Types | Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the actual C-like languages are unapplicable to it. To fully understand the statement, please read the language's description below... | types = {'void':'void', 'errtype':'errtype'}
def getRealType(type_expr):
expr_type = type_expr.strip('&*')
full_type_name = type_expr.replace(expr_type, types.get(expr_type, "errtype"))
base_type = full_type_name.strip('&*')
if base_type == "void":
addr_count = full_type_name.count('*')
deref_c... |
172 | 903_D. Almost Difference | Let's denote a function
<image>
You are given an array a consisting of n integers. You have to calculate the sum of d(ai, aj) over all pairs (i, j) such that 1 ≤ i ≤ j ≤ n.
Input
The first line contains one integer n (1 ≤ n ≤ 200000) — the number of elements in a.
The second line contains n integers a1, a2, ..., ... | from sys import stdin, stdout
n = int(stdin.readline())
a = [int(i) for i in stdin.readline().split()]
d = dict()
ans, sm = 0, 0
for i in range(n):
if a[i] not in d.keys():
d[a[i]] = 0
d[a[i]] += 1
ans += i * a[i] - sm
if (a[i] + 1) in d.keys():
ans += 1 * d[a[i] + 1]
if (a[i] - 1) i... |
173 | 954_F. Runner's Problem | You are running through a rectangular field. This field can be represented as a matrix with 3 rows and m columns. (i, j) denotes a cell belonging to i-th row and j-th column.
You start in (2, 1) and have to end your path in (2, m). From the cell (i, j) you may advance to:
* (i - 1, j + 1) — only if i > 1,
* (i, ... | from operator import itemgetter
import sys
input = sys.stdin.buffer.readline
def _mul(A, B, MOD):
C = [[0] * len(B[0]) for i in range(len(A))]
for i in range(len(A)):
for k in range(len(B)):
for j in range(len(B[0])):
C[i][j] = (C[i][j] + A[i][k] * B[k][j]) % MOD
return... |
174 | 9_E. Interesting Graph and Apples | Hexadecimal likes drawing. She has drawn many graphs already, both directed and not. Recently she has started to work on a still-life «interesting graph and apples». An undirected graph is called interesting, if each of its vertices belongs to one cycle only — a funny ring — and does not belong to any other cycles. A f... | def dfs(v, comp):
used[v] = comp
for u in graph[v]:
if not used[u]:
dfs(u, comp)
n, m = map(int, input().split())
graph = [[] for i in range(n)]
for i in range(m):
v, u = map(int, input().split())
graph[v - 1].append(u - 1)
graph[u - 1].append(v - 1)
used = [0] * n
ncomp = 0
fo... |
175 | 1011_A. Stages | Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
There are n stages available. The rock... | n,k = list(map(int,input().split()))
data = sorted(list(input()))
data = list(map(lambda x:ord(x)-ord('a')+1,data))
result = 0
used = 0
idx =0
prev = -2
# print(data)
for d in data:
if d > prev+1:
result+= d
prev = d
used += 1
if used == k:
break
if used < k:
print(-... |
176 | 1059_A. Cashier | Vasya has recently got a job as a cashier at a local store. His day at work is L minutes long. Vasya has already memorized n regular customers, the i-th of which comes after t_{i} minutes after the beginning of the day, and his service consumes l_{i} minutes. It is guaranteed that no customer will arrive while Vasya is... | n,l,a = map(int,input().split())
b =[]
for i in range(n):
b.append([int(e) for e in input().split()])
ans = 0
for i in range(n-1):
ans += (b[i+1][0] - b[i][1] - b[i][0])//a
if(n > 0):
ans += b[0][0]//a
ans += (l - b[n-1][1] - b[n-1][0])//a
else:
ans += l//a
print(ans)
|
177 | 1080_C. Masha and two friends | Recently, Masha was presented with a chessboard with a height of n and a width of m.
The rows on the chessboard are numbered from 1 to n from bottom to top. The columns are numbered from 1 to m from left to right. Therefore, each cell can be specified with the coordinates (x,y), where x is the column number, and y is ... | def num_sq(x,y,x2,y2):
# b, w
a = (abs(x2-x)+1)
b = (abs(y2-y)+1)
if a % 2 == 0 or b % 2 == 0:
return (a*b // 2, a*b // 2)
if (x+y) % 2 == 0:
num_b = a * b // 2
return (num_b, a * b - num_b)
num_w = a * b // 2
return (a * b - num_w, num_w)
def pt_in(p1, r1, r2):
r... |
178 | 10_B. Cinema Cashier | All cinema halls in Berland are rectangles with K rows of K seats each, and K is an odd number. Rows and seats are numbered from 1 to K. For safety reasons people, who come to the box office to buy tickets, are not allowed to choose seats themselves. Formerly the choice was made by a cashier, but now this is the respon... | __author__ = 'Darren'
def solve():
n, k = map(int, input().split())
group = map(int, input().split())
available = [[k, 1][:] for _ in range(k+1)]
center = (k + 1) // 2
for m in group:
closest, best_row, best_col = 10000, -1, -1
for row in range(1, k+1):
col = 0
... |
179 | 1121_A. Technogoblet of Fire | Everybody knows that the m-coder Tournament will happen soon. m schools participate in the tournament, and only one student from each school participates.
There are a total of n students in those schools. Before the tournament, all students put their names and the names of their schools into the Technogoblet of Fire. ... | n,m,k=map(int,input().split())
p=list(map(int,input().split()))
s=list(map(int,input().split()))
c=set(map(int,input().split()))
d={}
for i in range(n):
if s[i] not in d:
d[s[i]]=[-1]
if p[i]>d[s[i]][0]:
d[s[i]]=(p[i],i)
st=set()
for i in d:
st.add(d[i][1]+1)
#print(c,st)
c=c.difference(st)
... |
180 | 1148_C. Crazy Diamond | You are given a permutation p of integers from 1 to n, where n is an even number.
Your goal is to sort the permutation. To do so, you can perform zero or more operations of the following type:
* take two indices i and j such that 2 ⋅ |i - j| ≥ n and swap p_i and p_j.
There is no need to minimize the number of... |
n = int(input())
p = [*map(int, input().split())]
p = [i - 1 for i in p]
#print(p)
pos = {}
ans = []
for i, j in enumerate(p):
pos[j] = i
def swap(i, j):
ans.append((i + 1, j + 1))
pos[p[i]], pos[p[j]] = pos[p[j]], pos[p[i]]
p[i], p[j] = p[j], p[i]
def do(i):
j=pos[i]
if j<n//2:
... |
181 | 1206_F. Almost All | You are given a tree with n nodes. You have to write non-negative integers on its edges so that the following condition would be satisfied:
For every two nodes i, j, look at the path between them and count the sum of numbers on the edges of this path. Write all obtained sums on the blackboard. Then every integer from ... | import math
n = int(input())
if n == 1:
print()
else:
edge = [list(map(int, input().split())) for i in range(1, n) ]
g = {}
for x, y in edge:
if x not in g:
g[x] = []
if y not in g:
g[y] = []
g[x].append(y)
g[y].append(x)
... |
182 | 1225_B1. TV Subscriptions (Easy Version) | The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ k), where a_i is the show, the episode of which will be shown in i-th day.
The... | x = int(input())
for i in range(x):
n, k, d = map(int, input().split(' '))
l = map(int, input().split(' '))
l = list(l)
ar = []
for j in range(n-d+1):
ar.append(len(set(l[j:(j+d)])))
print(min(ar)) |
183 | 1267_L. Lexicography | Lucy likes letters. She studied the definition of the lexicographical order at school and plays with it.
At first, she tried to construct the lexicographically smallest word out of given letters. It was so easy! Then she tried to build multiple words and minimize one of them. This was much harder!
Formally, Lucy want... | # ------------------- fast io --------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode... |
184 | 1353_C. Board Moves | You are given a board of size n × n, where n is odd (not divisible by 2). Initially, each cell of the board contains one figure.
In one move, you can select exactly one figure presented in some cell and move it to one of the cells sharing a side or a corner with the current cell, i.e. from the cell (i, j) you can move... | I = input
for _ in range(int(I())):
n = int(I())+1
s = 0
for i in range(1,n//2):
s += 8*i*i
print(s) |
185 | 1373_B. 01 Game | Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent char... | from sys import stdin,stdout
t=int(stdin.readline().strip())
for _ in range(t):
s=stdin.readline().strip()
stdout.write(("NET","DA")[min(s.count('0'),s.count('1')) % 2]+"\n")
|
186 | 148_B. Escape | The princess is going to escape the dragon's cave, and she needs to plan it carefully.
The princess runs at vp miles per hour, and the dragon flies at vd miles per hour. The dragon will discover the escape after t hours and will chase the princess immediately. Looks like there's no chance to success, but the princess ... | vp = int(input())
vd = int(input())
t = int(input())
f = int(input())
c = int(input())
distance = t * vp
time = t
treasure = 0
if vp == vd:
if t == 0:
print(1)
else:
print(0)
elif vp > vd:
print(0)
else:
while distance < c:
timeadd = distance/(vd - vp)
distance += vp * ti... |
187 | 1539_D. PriceFixed | Lena is the most economical girl in Moscow. So, when her dad asks her to buy some food for a trip to the country, she goes to the best store — "PriceFixed". Here are some rules of that store:
* The store has an infinite number of items of every product.
* All products have the same price: 2 rubles per item.
* ... | n = int(input())
arr = []
for _ in range(n):
arr.append(list(map(int, input().split())))
arr.sort(key=lambda x:x[1])
# print(arr)
lo, hi = 0, n-1
ans, counter = 0, 0
while lo<=hi:
# print(lo, hi, counter)
to_buy, req = arr[lo]
if counter>=req or to_buy==0:
counter += to_buy
ans += to_bu... |
188 | 166_A. Rank List | Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place.
You know the rules of comparing the results of two give... | n, k = map(int, input().split())
table =[]
table_dic = dict()
for i in range(n):
p, t = map(int, input().split())
table_dic[i + 1] = [p,t]
table.append([p, 50 - t])
ranking = sorted(table, key=lambda table: (table[0], table[1]), reverse=True)
for i in range(n):
ranking[i][1] = 50 - ranking[i][1]
coun... |
189 | 233_C. Cycles | John Doe started thinking about graphs. After some thought he decided that he wants to paint an undirected graph, containing exactly k cycles of length 3.
A cycle of length 3 is an unordered group of three distinct graph vertices a, b and c, such that each pair of them is connected by a graph edge.
John has been pa... | n, k = 0, int(input())
p = [['0'] * 100 for i in range(100)]
while k:
for i in range(n):
if i > k: break
p[n][i] = p[i][n] = '1'
k -= i
n += 1
print(n)
for i in range(n): print(''.join(p[i][:n])) |
190 | 259_B. Little Elephant and Magic Square | Little Elephant loves magic squares very much.
A magic square is a 3 × 3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals 15... | l=[]
for i in range(3):
l.append(list(map(int,input().split())))
l[1][1]=(l[1][0]+l[1][2])//2
c=sum(l[1])
l[0][0]=c-(l[0][1]+l[0][2])
l[2][2]=c-(l[2][0]+l[2][1])
for i in range(3):
for j in range(3):
print(l[i][j],end=" ")
print() |
191 | 282_B. Painting Eggs | The Bitlandians are quite weird people. They have very peculiar customs.
As is customary, Uncle J. wants to have n eggs painted for Bitruz (an ancient Bitland festival). He has asked G. and A. to do the work.
The kids are excited because just as is customary, they're going to be paid for the job!
Overall uncle J. h... | import sys
input = lambda: sys.stdin.readline()
n = int(input())
S = 0
ans = ''
for i in range(n):
a, g = [int(x) for x in input().split(' ')]
if abs(S + a) <= 500:
S += a
ans += 'A'
else:
S -= g
ans += 'G'
print(ans) |
192 | 331_A2. Oh Sweet Beaverette | — Oh my sweet Beaverette, would you fancy a walk along a wonderful woodland belt with me?
— Of course, my Smart Beaver! Let us enjoy the splendid view together. How about Friday night?
At this point the Smart Beaver got rushing. Everything should be perfect by Friday, so he needed to prepare the belt to the upcomin... | n, t = int(input()), list(map(int, input().split()))
a, b = {}, {}
for i, j in enumerate(t):
if not j in a: a[j] = i
else: b[j] = i
p = [(a[j], b[j] - 1) for j in b]
s = [j if j > 0 else 0 for j in t]
u = v = 2 * t[p[0][0]] - 1
for i in range(n - 1): s[i + 1] += s[i]
for i, j in p:
u = 2 * t[i] + s[j] - s[i... |
193 | 377_A. Maze | Pavel loves grid mazes. A grid maze is an n × m rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to any oth... | from collections import defaultdict
from sys import stdin
def put(): return map(int, stdin.readline().split())
def find():
for i in range(n):
for j in range(m):
if mat[i][j]=='.':
return i,j
return -1,-1
def dfs(i,j):
s = [(i,j)]
t = 1
vis[i][j]=1
while s:
... |
194 | 399_C. Cards | User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. F... | a, b = map(int, input().split())
sx = lambda p: (a - p + 1) ** 2 + p - 1
sy = lambda q: (b % q) * (1 + b // q) ** 2 + (b // q) ** 2 * (q - b % q)
n = min(a, b)
if a == 0:
print( -b ** 2)
print( b * "x" )
elif b <= 1:
print( a ** 2 - b ** 2 )
print ( a * "o" + b * "x" )
else:
res = - (a + b) ** 2
... |
195 | 421_D. Bug in Code | Recently a serious bug has been found in the FOS code. The head of the F company wants to find the culprit and punish him. For that, he set up an organizational meeting, the issue is: who's bugged the code? Each of the n coders on the meeting said: 'I know for sure that either x or y did it!'
The head of the company d... | from collections import defaultdict
from bisect import bisect_left as lower
import sys
input = sys.stdin.readline
def put():
return map(int, input().split())
try:
n,m = put()
cnt, mp, ans = [0]*n, defaultdict(), [0]*n
for _ in range(n):
x,y = put()
x,y = x-1,y-1
key = (min(x,y),... |
196 | 448_B. Suffix Structures | Bizon the Champion isn't just a bison. He also is a favorite of the "Bizons" team.
At a competition the "Bizons" got the following problem: "You are given two distinct words (strings of English letters), s and t. You need to transform word s into word t". The task looked simple to the guys because they know the suffix... | s = input()
t = input()
ind = 0
for x in t:
ind = s.find(x, ind) + 1
if ind <= 0:
break
if ind > 0 or len(t) == 0:
print('automaton')
else:
ss = list(s)
tt = list(t)
bb1 = True
if len(ss) >= len(tt):
for x in tt:
bb = False
for y in ss:
... |
197 | 46_C. Hamsters and Tigers | Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap the animals' positions so that all the hamsters stood together and all the tigers also stood together... | n=int(input())
s=input()
h=0
for i in s:
if i=='H':h+=1
r=[]
t=0
for i in range(0,n):
if s[i]=='H':
for b in range((i+1)%n,min(((i+1)%n+h-1),n)):
if s[b]=='T':
t+=1
if ((i+1)%n+(h-1))>n:
for q in range(0,(((i+1)%n+(h-1))%n)):
if s[q]=='T':... |
198 | 492_D. Vanya and Computer Game | Vanya and his friend Vova play a computer game where they need to destroy n monsters to pass a level. Vanya's character performs attack with frequency x hits per second and Vova's character performs attack with frequency y hits per second. Each character spends fixed time to raise a weapon and then he hits (the time to... | n, x, y = map(int, input().split())
for _ in range(n):
a = int(input())
c1, c2 = ((a + 1) * x // (x + y)) / x, ((a + 1) * y // (x + y)) / y
if c1 == c2:
print('Both')
elif c1 > c2:
print('Vanya')
else:
print('Vova')
|
199 | 56_E. Domino Principle | Vasya is interested in arranging dominoes. He is fed up with common dominoes and he uses the dominoes of different heights. He put n dominoes on the table along one axis, going from left to right. Every domino stands perpendicular to that axis so that the axis passes through the center of its base. The i-th domino has ... | from typing import TypeVar, Generic, Callable, List
import sys
from array import array # noqa: F401
from bisect import bisect_left, bisect_right
def input():
return sys.stdin.buffer.readline().decode('utf-8')
T = TypeVar('T')
class SegmentTree(Generic[T]):
__slots__ = ["size", "tree", "identity", "op", "... |
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