Task: Mian-Chowla sequence
Java: import java.util.Arrays;

public class MianChowlaSequence {

    public static void main(String[] args) {
        long start = System.currentTimeMillis();
        System.out.println("First 30 terms of the Mian–Chowla sequence.");
        mianChowla(1, 30);
        System.out.println("Terms 91 through 100 of the Mian–Chowla sequence.");
        mianChowla(91, 100);
        long end = System.currentTimeMillis();
        System.out.printf("Elapsed = %d ms%n", (end-start));
    }

    private static void mianChowla(int minIndex, int maxIndex) {
        int [] sums = new int[1];
        int [] chowla = new int[maxIndex+1];
        sums[0] = 2;
        chowla[0] = 0;
        chowla[1] = 1;
        if ( minIndex == 1 ) {
            System.out.printf("%d ", 1);
        }
        int chowlaLength = 1;
        for ( int n = 2 ; n <= maxIndex ; n++ ) {

            
            int test = chowla[n - 1];
            
            int[] sumsNew = Arrays.copyOf(sums, sums.length + n);
            int sumNewLength = sums.length;
            int savedsSumNewLength = sumNewLength;
            
            
            boolean found = false;
            while ( ! found ) {
                test++;
                found = true;
                sumNewLength = savedsSumNewLength;
                
                for ( int j = 0 ; j <= chowlaLength ; j++ ) {
                    int testSum = (j == 0 ? test : chowla[j]) + test;
                    boolean duplicate = false;
                    
                    
                    for ( int k = 0 ; k < sumNewLength ; k++ ) {
                        if ( sumsNew[k] == testSum ) {
                            duplicate = true;
                            break;
                        }
                    }
                    if ( ! duplicate ) {
                        
                        sumsNew[sumNewLength] = testSum;
                        sumNewLength++;
                    }
                    else {
                        
                        found = false;
                        break;
                    }
                }
            }
            
            
            chowla[n] = test;
            chowlaLength++;            
            sums = sumsNew;
            if ( n >= minIndex ) {
                System.out.printf("%d %s", chowla[n], (n==maxIndex ? "\n" : ""));
            }
        }
    }

}

VB: 
    Const m = 100, mm=28000
    ReDim r(mm), v(mm * 2)
    Dim n, t, i, j, l, s1, s2, iterate_t
    ReDim seq(m)
    t0=Timer
    s1 = "1": s2 = ""
    seq(1) = 1: n = 1: t = 1
    Do While n < m
        t = t + 1
        iterate_t = False
        For i = 1 to t * 2
            v(i) = 0
        Next
        i = 1
        Do While i <= t And Not iterate_t
            If r(i) = 0 Then
                j = i
                Do While j <= t And Not iterate_t
                    If r(j) = 0 Then
                        l = i + j
                        If v(l) = 1 Then
                            r(t) = 1
                            iterate_t = True
                        End If
                        If Not iterate_t Then v(l) = 1
                    End If
                    j = j + 1
                Loop
            End If
            i = i + 1
        Loop
        If Not iterate_t Then
            n = n + 1
            seq(n) = t
            if           n<= 30 then s1 = s1 & " " & t
            if n>=91 and n<=100 then s2 = s2 & " " & t
        End If
    Loop
    wscript.echo "t="& t
    wscript.echo "The Mian-Chowla sequence for elements 1 to 30:"
    wscript.echo s1
    wscript.echo "The Mian-Chowla sequence for elements 91 to 100:"
    wscript.echo s2
    wscript.echo "Computation time: "&  Int(Timer-t0) &" sec"