Task: Greedy algorithm for Egyptian fractions
C: #include <stdbool.h>
#include <stdint.h>
#include <stdio.h>

typedef int64_t integer;

struct Pair {
    integer md;
    int tc;
};

integer mod(integer x, integer y) {
    return ((x % y) + y) % y;
}

integer gcd(integer a, integer b) {
    if (0 == a) return b;
    if (0 == b) return a;
    if (a == b) return a;
    if (a > b) return gcd(a - b, b);
    return gcd(a, b - a);
}

void write0(bool show, char *str) {
    if (show) {
        printf(str);
    }
}

void write1(bool show, char *format, integer a) {
    if (show) {
        printf(format, a);
    }
}

void write2(bool show, char *format, integer a, integer b) {
    if (show) {
        printf(format, a, b);
    }
}

struct Pair egyptian(integer x, integer y, bool show) {
    struct Pair ret;
    integer acc = 0;
    bool first = true;

    ret.tc = 0;
    ret.md = 0;

    write2(show, "Egyptian fraction for %lld/%lld: ", x, y);
    while (x > 0) {
        integer z = (y + x - 1) / x;
        if (z == 1) {
            acc++;
        } else {
            if (acc > 0) {
                write1(show, "%lld + ", acc);
                first = false;
                acc = 0;
                ret.tc++;
            } else if (first) {
                first = false;
            } else {
                write0(show, " + ");
            }
            if (z > ret.md) {
                ret.md = z;
            }
            write1(show, "1/%lld", z);
            ret.tc++;
        }
        x = mod(-y, x);
        y = y * z;
    }
    if (acc > 0) {
        write1(show, "%lld", acc);
        ret.tc++;
    }
    write0(show, "\n");

    return ret;
}

int main() {
    struct Pair p;
    integer nm = 0, dm = 0, dmn = 0, dmd = 0, den = 0;;
    int tm, i, j;

    egyptian(43, 48, true);
    egyptian(5, 121, true); 
    egyptian(2014, 59, true);

    tm = 0;
    for (i = 1; i < 100; i++) {
        for (j = 1; j < 100; j++) {
            p = egyptian(i, j, false);
            if (p.tc > tm) {
                tm = p.tc;
                nm = i;
                dm = j;
            }
            if (p.md > den) {
                den = p.md;
                dmn = i;
                dmd = j;
            }
        }
    }
    printf("Term max is %lld/%lld with %d terms.\n", nm, dm, tm); 
    printf("Denominator max is %lld/%lld\n", dmn, dmd);           
    egyptian(dmn, dmd, true);                                     

    return 0;
}

C++: #include <iostream>
#include <optional>
#include <vector>
#include <string>
#include <sstream>
#include <boost/multiprecision/cpp_int.hpp>

typedef boost::multiprecision::cpp_int integer;

struct fraction {
    fraction(const integer& n, const integer& d) : numerator(n), denominator(d) {}
    integer numerator;
    integer denominator;
};

integer mod(const integer& x, const integer& y) {
    return ((x % y) + y) % y;
}

size_t count_digits(const integer& i) {
    std::ostringstream os;
    os << i;
    return os.str().length();
}

std::string to_string(const integer& i) {
    const int max_digits = 20;
    std::ostringstream os;
    os << i;
    std::string s = os.str();
    if (s.length() > max_digits) {
        s = s.substr(0, max_digits/2) + "..." + s.substr(s.length()-max_digits/2);
    }
    return s;
}

std::ostream& operator<<(std::ostream& out, const fraction& f) {
    return out << to_string(f.numerator) << '/' << to_string(f.denominator);
}

void egyptian(const fraction& f, std::vector<fraction>& result) {
    result.clear();
    integer x = f.numerator, y = f.denominator;
    while (x > 0) {
        integer z = (y + x - 1)/x;
        result.emplace_back(1, z);
        x = mod(-y, x);
        y = y * z;
    }
}

void print_egyptian(const std::vector<fraction>& result) {
    if (result.empty())
        return;
    auto i = result.begin();
    std::cout << *i++;
    for (; i != result.end(); ++i)
        std::cout << " + " << *i;
    std::cout << '\n';
}

void print_egyptian(const fraction& f) {
    std::cout << "Egyptian fraction for " << f << ": ";
    integer x = f.numerator, y = f.denominator;
    if (x > y) {
        std::cout << "[" << x/y << "] ";
        x = x % y;
    }
    std::vector<fraction> result;
    egyptian(fraction(x, y), result);
    print_egyptian(result);
    std::cout << '\n';
}

void show_max_terms_and_max_denominator(const integer& limit) {
    size_t max_terms = 0;
    std::optional<fraction> max_terms_fraction, max_denominator_fraction;
    std::vector<fraction> max_terms_result;
    integer max_denominator = 0;
    std::vector<fraction> max_denominator_result;
    std::vector<fraction> result;
    for (integer b = 2; b < limit; ++b) {
        for (integer a = 1; a < b; ++a) {
            fraction f(a, b);
            egyptian(f, result);
            if (result.size() > max_terms) {
                max_terms = result.size();
                max_terms_result = result;
                max_terms_fraction = f;
            }
            const integer& denominator = result.back().denominator;
            if (denominator > max_denominator) {
                max_denominator = denominator;
                max_denominator_result = result;
                max_denominator_fraction = f;
            }
        }
    }
    std::cout << "Proper fractions with most terms and largest denominator, limit = " << limit << ":\n\n";
    std::cout << "Most terms (" << max_terms << "): " << max_terms_fraction.value() << " = ";
    print_egyptian(max_terms_result);
    std::cout << "\nLargest denominator (" << count_digits(max_denominator_result.back().denominator)
        << " digits): " << max_denominator_fraction.value() << " = ";
    print_egyptian(max_denominator_result);
}

int main() {
    print_egyptian(fraction(43, 48));
    print_egyptian(fraction(5, 121));
    print_egyptian(fraction(2014, 59));
    show_max_terms_and_max_denominator(100);
    show_max_terms_and_max_denominator(1000);
    return 0;
}