Task: Long primes
C#: using System;
using System.Collections.Generic;
using System.Linq;

public static class LongPrimes
{
    public static void Main() {
        var primes = SomePrimeGenerator.Primes(64000).Skip(1).Where(p => Period(p) == p - 1).Append(99999);
        Console.WriteLine(string.Join(" ", primes.TakeWhile(p => p <= 500)));
        int count = 0, limit = 500;
        foreach (int prime in primes) {
            if (prime > limit) {
                Console.WriteLine($"There are {count} long primes below {limit}");
                limit *= 2;
            }
            count++;
        }

        int Period(int n) {
            int r = 1, rr;
            for (int i = 0; i <= n; i++) r = 10 * r % n;
            rr = r;
            for (int period = 1;; period++) {
                r = (10 * r) % n;
                if (r == rr) return period;
            }
        }
    }

}

static class SomePrimeGenerator {

    public static IEnumerable<int> Primes(int lim) {
        bool [] flags = new bool[lim + 1]; int j = 2;
        for (int d = 3, sq = 4; sq <= lim; j++, sq += d += 2)
            if (!flags[j]) {
                yield return j; for (int k = sq; k <= lim; k += j)
                    flags[k] = true;
            }
        for (; j<= lim; j++) if (!flags[j]) yield return j;
    }
}

C++: #include <iomanip>
#include <iostream>
#include <list>
using namespace std;
  
void sieve(int limit, list<int> &primes)
{
  bool *c = new bool[limit + 1];
  for (int i = 0; i <= limit; i++)
    c[i] = false;
  
  int p = 3, n = 0;
  int p2 = p * p;
  while (p2 <= limit)
  {
    for (int i = p2; i <= limit; i += 2 * p)
      c[i] = true;
    do
      p += 2;
    while (c[p]);
    p2 = p * p;
  }
  for (int i = 3; i <= limit; i += 2) 
    if (!c[i]) 
      primes.push_back(i);
  delete [] c;
}
 

int findPeriod(int n) 
{
  int r = 1, rr, period = 0;
  for (int i = 1; i <= n + 1; ++i)
    r = (10 * r) % n;
  rr = r;
  do
  {
    r = (10 * r) % n;
    period++;
  }
  while (r != rr);
  return period;
}
 
int main()
{
  int count = 0, index = 0;
  int numbers[] = {500, 1000, 2000, 4000, 8000, 16000, 32000, 64000};
  list<int> primes;
  list<int> longPrimes;
  int numberCount = sizeof(numbers) / sizeof(int);
  int *totals = new int[numberCount];
  cout << "Please wait." << endl << endl;
  sieve(64000, primes);  
  for (list<int>::iterator iterPrime = primes.begin();  
    iterPrime != primes.end(); 
    iterPrime++)
  {  
    if (findPeriod(*iterPrime) == *iterPrime - 1)
      longPrimes.push_back(*iterPrime);
  }    
  
  for (list<int>::iterator iterLongPrime = longPrimes.begin();
    iterLongPrime != longPrimes.end(); 
    iterLongPrime++)
  {
    if (*iterLongPrime > numbers[index])
      totals[index++] = count;
        ++count;
  }
  totals[numberCount - 1] = count;
  cout << "The long primes up to " << totals[0] << " are:" << endl;
  cout << "[";
  int i = 0;
  for (list<int>::iterator iterLongPrime = longPrimes.begin(); 
    iterLongPrime != longPrimes.end() && i < totals[0]; 
    iterLongPrime++, i++)
  {  
    cout << *iterLongPrime << " ";
  }  
  cout << "\b]" << endl;
  cout << endl << "The number of long primes up to:" << endl;
  for (int i = 0; i < 8; ++i)
    cout << "  " << setw(5) << numbers[i] << " is " << totals[i] << endl;
  delete [] totals;
}