CREATE TABLE "breakdown_by_nationality" (
  "country" text,
  "2012" real,
  "2011" real,
  "2010" real,
  "2009" real,
  "2008" real,
  "2007" real,
  "2006" real,
  "2005" real,
  "2004" real,
  "2003" real,
  "2002" real,
  "2001" real,
  "2000" real,
  "1999" real,
  "1998" real,
  "1997" real,
  "1996" real,
  "1995" real,
  "1994" real,
  "1993" real,
  "1992" real,
  "1991" real,
  "1990" real,
  "1989" real,
  "1988" real
);

Question: What is the average for 2009 when 2001 is more than 0, 1996 is less than 1 and 2004 is more than 2
SQL: SELECT AVG("2009") FROM "breakdown_by_nationality" WHERE "2001">0 AND "1996"<1 AND "2004">2;

Question: What is the listing for 2009 when 1989 is less than 0?
SQL: SELECT SUM("2009") FROM "breakdown_by_nationality" WHERE "1989"<0;

Question: what is the average for 2005 when 1995 is more than 3, 1996 is less than 4, and 2011 is more than 5?
SQL: SELECT AVG("2005") FROM "breakdown_by_nationality" WHERE "1995">3 AND "1996"<4 AND "2011">5;

Question: what is the listing for 1999 when 1990 is more than 0, 2003 is 3, 2007 is more than 1 and 1996 is more than 0?
SQL: SELECT SUM("1999") FROM "breakdown_by_nationality" WHERE "1990">0 AND "2003"=3 AND "2007">1 AND "1996">0;

Question: what is the listing for 2012 when 2004 is more than 0, 2008 is more than 1 1994 is 8 and 2005 is less than 11?
SQL: SELECT MIN("2012") FROM "breakdown_by_nationality" WHERE "2004">0 AND "2008">1 AND "1994"=8 AND "2005"<11;

Question: what is the listing for 1992 when 1999 is more than 1, 2008 is less than 2 and 2003 is less than 2?
SQL: SELECT SUM("1992") FROM "breakdown_by_nationality" WHERE "1999">1 AND "2008"<2 AND "2003"<2;