CREATE TABLE "by_county" (
  "county" text,
  "kerrypct" text,
  "kerrynum" real,
  "bushpct" text,
  "bushnum" real,
  "otherspct" text,
  "othersnum" real
);

Question: When Keey has 58.1% what % does Bush have?
SQL: SELECT "bushpct" FROM "by_county" WHERE "kerrypct"='58.1%';