CREATE TABLE "by_county" (
  "county" text,
  "bush_num" real,
  "bush_pct" text,
  "kerry_num" real,
  "kerry_pct" text,
  "others_num" real,
  "others_pct" text,
  "total" real
);

Question: What was the other number with 63.98% bush?
SQL: SELECT "others_num" FROM "by_county" WHERE "bush_pct"='63.98%';