jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE professor (prof_office VARCHAR, dept_code VARCHAR, emp_num VARCHAR, prof_high_degree VARCHAR), CREATE TABLE employee (emp_num VARCHAR, emp_fname VARCHAR), CREATE TABLE department (dept_name VARCHAR, dept_code VARCHAR)
user: 没有“博士”学位的“历史"系教授的名字和办公室是什么？

assistant: SELECT T2.emp_fname ,  T1.prof_office FROM professor AS T1 JOIN employee AS T2 ON T1.emp_num  =  T2.emp_num JOIN department AS T3 ON T1.dept_code  =  T3.dept_code WHERE T3.dept_name  =  '旧' AND T1.prof_high_degree != '博士'
Schema: CREATE TABLE CLASS (prof_num VARCHAR), CREATE TABLE employee (emp_num VARCHAR, emp_fname VARCHAR)
user: 找出教一门课的教授的名字。

assistant: SELECT T2.emp_fname FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num  =  T2.emp_num GROUP BY T1.prof_num HAVING count(*)  >  1
Schema: CREATE TABLE CLASS (prof_num VARCHAR), CREATE TABLE employee (emp_num VARCHAR, emp_fname VARCHAR)
user: 所有教至少一门课的教授的名字是什么？

assistant: SELECT T2.emp_fname FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num  =  T2.emp_num GROUP BY T1.prof_num HAVING count(*)  >  1
Schema: CREATE TABLE student (stu_num VARCHAR, stu_fname VARCHAR), CREATE TABLE enroll (stu_num VARCHAR)
user: 找到只上一门课的学生的名字。

assistant: SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num  =  T2.stu_num GROUP BY T2.stu_num HAVING count(*)  =  1
Schema: CREATE TABLE student (stu_num VARCHAR, stu_fname VARCHAR), CREATE TABLE enroll (stu_num VARCHAR)
user: 只有一门课的学生的名字是什么？

assistant: SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num  =  T2.stu_num GROUP BY T2.stu_num HAVING count(*)  =  1
Schema: CREATE TABLE course (dept_code VARCHAR, crs_description VARCHAR), CREATE TABLE department (dept_name VARCHAR, dept_code VARCHAR)
user: 找到描述包含“统计”一词的课程所属的院系。

assistant: SELECT T2.dept_name FROM course AS T1 JOIN department AS T2 ON T1.dept_code  =  T2.dept_code WHERE T1.crs_description LIKE '统计'
Schema: CREATE TABLE course (dept_code VARCHAR, crs_description VARCHAR), CREATE TABLE department (dept_name VARCHAR, dept_code VARCHAR)
user: 提供包含“统计”一词的描述课程的系名是什么？

assistant: SELECT T2.dept_name FROM course AS T1 JOIN department AS T2 ON T1.dept_code  =  T2.dept_code WHERE T1.crs_description LIKE '统计'
Schema: CREATE TABLE student (stu_num VARCHAR, stu_lname VARCHAR, stu_fname VARCHAR), CREATE TABLE enroll (stu_num VARCHAR, class_code VARCHAR), CREATE TABLE CLASS (crs_code VARCHAR, class_code VARCHAR)
user: 姓氏以字母“少”开头而且正在上“美术”课的学生的名字是什么？

assistant: SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num  =  T2.stu_num JOIN CLASS AS T3 ON T2.class_code  =  T3.class_code WHERE T3.crs_code  =  '美术' AND T1.stu_lname LIKE '少'
Schema: CREATE TABLE student (stu_num VARCHAR, stu_lname VARCHAR, stu_fname VARCHAR), CREATE TABLE enroll (stu_num VARCHAR, class_code VARCHAR), CREATE TABLE CLASS (crs_code VARCHAR, class_code VARCHAR)
user: 姓氏以字母“少”开头，正在上“美术”的学生的名字是什么？

assistant: SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num  =  T2.stu_num JOIN CLASS AS T3 ON T2.class_code  =  T3.class_code WHERE T3.crs_code  =  '美术' AND T1.stu_lname LIKE '少'
Schema: CREATE TABLE club (Id VARCHAR)
user: 有多少个俱乐部？

assistant: SELECT count(*) FROM club
Schema: CREATE TABLE club (Id VARCHAR)
user: 俱乐部的总数是多少？

assistant: SELECT count(*) FROM club
Schema: CREATE TABLE club (Region VARCHAR)
user: 按字母升序顺序列出俱乐部的不同区域。

assistant: SELECT DISTINCT Region FROM club ORDER BY Region ASC
Schema: CREATE TABLE club (Region VARCHAR)
user: 俱乐部按字母顺序排列的不同区域是什么？

assistant: SELECT DISTINCT Region FROM club ORDER BY Region ASC
Schema: CREATE TABLE club_rank (Gold INTEGER)
user: 俱乐部的平均金牌数是多少？

assistant: SELECT avg(Gold) FROM club_rank
Schema: CREATE TABLE club_rank (Gold INTEGER)
user: 一个俱乐部的平均金牌数是多少？

assistant: SELECT avg(Gold) FROM club_rank
Schema: CREATE TABLE competition (Country VARCHAR, Competition_type VARCHAR)
user: 比赛的类型和国家是什么？

assistant: SELECT Competition_type ,  Country FROM competition
Schema: CREATE TABLE competition (Country VARCHAR, Competition_type VARCHAR)
user: 每一种比赛的类型和所在的国家是什么？

assistant: SELECT Competition_type ,  Country FROM competition
Schema: CREATE TABLE competition (Competition_type VARCHAR, YEAR VARCHAR)
user: 比赛类型不是“锦标赛”的不同年份是什么？

assistant: SELECT DISTINCT YEAR FROM competition WHERE Competition_type != "锦标赛"
Schema: CREATE TABLE competition (Competition_type VARCHAR, YEAR VARCHAR)
user: 比赛类型不是“锦标赛”的所有比赛的不同的年份有哪些？

assistant: SELECT DISTINCT YEAR FROM competition WHERE Competition_type != "锦标赛"
Schema: CREATE TABLE club_rank (Silver INTEGER)
user: 俱乐部银牌的最大和最小数量是多少？

assistant: SELECT max(Silver) ,  min(Silver) FROM club_rank
Schema: CREATE TABLE club_rank (Silver INTEGER)
user: 所有俱乐部的银牌的最大和最小数量是多少？

assistant: SELECT max(Silver) ,  min(Silver) FROM club_rank
Schema: CREATE TABLE club_rank (Total INTEGER)
user: 有多少俱乐部总奖牌数不到10？

assistant: SELECT count(*) FROM club_rank WHERE Total  <  10
Schema: CREATE TABLE club_rank (Total INTEGER)
user: 总共有少于10枚奖牌的俱乐部总数是多少？

assistant: SELECT count(*) FROM club_rank WHERE Total  <  10
Schema: CREATE TABLE club (Start_year VARCHAR, name VARCHAR)
user: 按开始年份升序，列出所有俱乐部名称。

assistant: SELECT name FROM club ORDER BY Start_year ASC
Schema: CREATE TABLE club (Start_year VARCHAR, name VARCHAR)
user: 从最古老的俱乐部开始，所有俱乐部的名字是什么？

assistant: SELECT name FROM club ORDER BY Start_year ASC
Schema: CREATE TABLE club (name VARCHAR)
user: 按字母顺序降序，列出所有俱乐部名称。

assistant: SELECT name FROM club ORDER BY name DESC
Schema: CREATE TABLE club (name VARCHAR)
user: 所有俱乐部按字母顺序降序排列的名字是什么？

assistant: SELECT name FROM club ORDER BY name DESC
Schema: CREATE TABLE club (Club_ID VARCHAR, name VARCHAR), CREATE TABLE player (Player_id VARCHAR, Club_ID VARCHAR)
user: 请显示俱乐部的名字和球员。

assistant: SELECT T1.name ,  T2.Player_id FROM club AS T1 JOIN player AS T2 ON T1.Club_ID  =  T2.Club_ID
Schema: CREATE TABLE club (Club_ID VARCHAR, name VARCHAR), CREATE TABLE player (Player_id VARCHAR, Club_ID VARCHAR)
user: 所有俱乐部的名字和球员是什么？

assistant: SELECT T1.name ,  T2.Player_id FROM club AS T1 JOIN player AS T2 ON T1.Club_ID  =  T2.Club_ID
Schema: CREATE TABLE club (Club_ID VARCHAR, name VARCHAR), CREATE TABLE player (Club_ID VARCHAR, Position VARCHAR)
user: 显示位置包含“右前锋”的球员的俱乐部名字。

assistant: SELECT T1.name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID  =  T2.Club_ID WHERE T2.Position  =  "右前锋"
Schema: CREATE TABLE club (Club_ID VARCHAR, name VARCHAR), CREATE TABLE player (Club_ID VARCHAR, Position VARCHAR)
user: 位置包括“右前锋”的球员的俱乐部叫什么名字？

assistant: SELECT T1.name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID  =  T2.Club_ID WHERE T2.Position  =  "右前锋"
Schema: CREATE TABLE club (name VARCHAR, Club_ID VARCHAR), CREATE TABLE player (Club_ID VARCHAR, Points INTEGER)
user: “国安”俱乐部的球员平均得分是多少？

assistant: SELECT avg(T2.Points) FROM club AS T1 JOIN player AS T2 ON T1.Club_ID  =  T2.Club_ID WHERE T1.name  =  "国安"
Schema: CREATE TABLE club (name VARCHAR, Club_ID VARCHAR), CREATE TABLE player (Club_ID VARCHAR, Points INTEGER)
user: “国安”俱乐部的球员平均有多少得分？

assistant: SELECT avg(T2.Points) FROM club AS T1 JOIN player AS T2 ON T1.Club_ID  =  T2.Club_ID WHERE T1.name  =  "国安"
Schema: CREATE TABLE player (POSITION VARCHAR, Points INTEGER)
user: 列出球员的位置和每个位置球员的平均得分数。

assistant: SELECT POSITION ,  avg(Points) FROM player GROUP BY POSITION
Schema: CREATE TABLE player (POSITION VARCHAR, Points INTEGER)
user: 对于每个位置，球员在那个位置的平均得分是多少？

assistant: SELECT POSITION ,  avg(Points) FROM player GROUP BY POSITION
Schema: CREATE TABLE player (POSITION VARCHAR, name VARCHAR, Points INTEGER)
user: 列出平均得分数大于20分的球员的位置。

assistant: SELECT POSITION FROM player GROUP BY name HAVING avg(Points)  >=  20
Schema: CREATE TABLE player (POSITION VARCHAR, name VARCHAR, Points INTEGER)
user: 那些平均得分高于20分的球员的位置是什么？

assistant: SELECT POSITION FROM player GROUP BY name HAVING avg(Points)  >=  20
Schema: CREATE TABLE competition (Competition_type VARCHAR)
user: 列出比赛的类型和每种类型比赛的数目。

assistant: SELECT Competition_type ,  COUNT(*) FROM competition GROUP BY Competition_type
Schema: CREATE TABLE competition (Competition_type VARCHAR)
user: 比赛的类型有哪些？每种类型的比赛的数量是多少？

assistant: SELECT Competition_type ,  COUNT(*) FROM competition GROUP BY Competition_type
Schema: CREATE TABLE competition (Competition_type VARCHAR)
user: 列出最常见的比赛类型。

assistant: SELECT Competition_type FROM competition GROUP BY Competition_type ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE competition (Competition_type VARCHAR)
user: 最常见的比赛类型是什么？

assistant: SELECT Competition_type FROM competition GROUP BY Competition_type ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE competition (Competition_type VARCHAR)
user: 列出最多有五场比赛的比赛类型。

assistant: SELECT Competition_type FROM competition GROUP BY Competition_type HAVING COUNT(*)  <=  5
Schema: CREATE TABLE competition (Competition_type VARCHAR)
user: 最多有5场比赛的比赛类型是什么？

assistant: SELECT Competition_type FROM competition GROUP BY Competition_type HAVING COUNT(*)  <=  5
Schema: CREATE TABLE CLub (Club_ID VARCHAR, name VARCHAR), CREATE TABLE player (Club_ID VARCHAR, name VARCHAR)
user: 列出没有球员的俱乐部的名字。

assistant: SELECT name FROM CLub WHERE Club_ID NOT IN (SELECT Club_ID FROM player)
Schema: CREATE TABLE CLub (Club_ID VARCHAR, name VARCHAR), CREATE TABLE player (Club_ID VARCHAR, name VARCHAR)
user: 所有没有球员的俱乐部的名字是什么？

assistant: SELECT name FROM CLub WHERE Club_ID NOT IN (SELECT Club_ID FROM player)
Schema: CREATE TABLE player (POSITION VARCHAR, Points INTEGER)
user: 哪些位置既有得分都超过20分的球员又有得分低于10分的球员？

assistant: SELECT POSITION FROM player WHERE Points  >  20 INTERSECT SELECT POSITION FROM player WHERE Points  <  10
Schema: CREATE TABLE player (POSITION VARCHAR, Points INTEGER)
user: 哪些位置既有得分超过20又有得分低于10的球员 ？

assistant: SELECT POSITION FROM player WHERE Points  >  20 INTERSECT SELECT POSITION FROM player WHERE Points  <  10
Schema: CREATE TABLE player (Points INTEGER)
user: 显示所有球员的总点数。

assistant: SELECT sum(Points) FROM player
Schema: CREATE TABLE player (Points INTEGER)
user: 所有球员的总点数是多少？

assistant: SELECT sum(Points) FROM player
Schema: CREATE TABLE player (POSITION VARCHAR)
user: 有多少个不同的位置？

assistant: SELECT count(DISTINCT POSITION) FROM player
Schema: CREATE TABLE player (POSITION VARCHAR)
user: 球员有多少种不同的位置？

assistant: SELECT count(DISTINCT POSITION) FROM player
Schema: CREATE TABLE player (points INTEGER, name VARCHAR)
user: 得分高于平均得分的球员的名字是什么？

assistant: SELECT name FROM player WHERE points  >  (SELECT avg(points) FROM player)
Schema: CREATE TABLE player (points INTEGER, name VARCHAR)
user: 所有得分高于平均分数的球员的名字是什么？

assistant: SELECT name FROM player WHERE points  >  (SELECT avg(points) FROM player)
Schema: CREATE TABLE player (POSITION VARCHAR, points INTEGER)
user: 找出每个位置得分低于30的球员的数量。

assistant: SELECT count(*) ,  POSITION FROM player WHERE points  <  30 GROUP BY POSITION
Schema: CREATE TABLE player (POSITION VARCHAR, points INTEGER)
user: 每个位置的得分少于30的球员的数量是多少？

assistant: SELECT count(*) ,  POSITION FROM player WHERE points  <  30 GROUP BY POSITION
Schema: CREATE TABLE competition (country VARCHAR, competition_type VARCHAR)
user: 哪个国家参加过最多的比赛？

assistant: SELECT country FROM competition WHERE competition_type  =  '锦标赛' GROUP BY country ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE competition (country VARCHAR, competition_type VARCHAR)
user: 参加过最多的“锦标赛”的国家叫什么名字？

assistant: SELECT country FROM competition WHERE competition_type  =  '锦标赛' GROUP BY country ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE competition (country VARCHAR, competition_type VARCHAR)
user: 哪些国家参加了“友谊型”和“锦标赛”类型的比赛？

assistant: SELECT country FROM competition WHERE competition_type  =  '友谊型' INTERSECT SELECT country FROM competition WHERE competition_type  =  '锦标赛'
Schema: CREATE TABLE competition (country VARCHAR, competition_type VARCHAR)
user: 哪些国家既参加了“友谊型”又参加了“锦标赛”？

assistant: SELECT country FROM competition WHERE competition_type  =  '友谊型' INTERSECT SELECT country FROM competition WHERE competition_type  =  '锦标赛'
Schema: CREATE TABLE competition (country VARCHAR, competition_type VARCHAR)
user: 找到那些从未参加过任何“友谊型”的国家。

assistant: SELECT country FROM competition EXCEPT SELECT country FROM competition WHERE competition_type  =  '友谊型'
Schema: CREATE TABLE competition (country VARCHAR, competition_type VARCHAR)
user: 哪些国家从未参加过“友谊型”？

assistant: SELECT country FROM competition EXCEPT SELECT country FROM competition WHERE competition_type  =  '友谊型'
Schema: CREATE TABLE furniture (num_of_component INTEGER)
user: 总共有多少家具部件？

assistant: SELECT sum(num_of_component) FROM furniture
Schema: CREATE TABLE furniture (market_rate VARCHAR, furniture_id VARCHAR, name VARCHAR)
user: 以最高的市场价格返回家具的名称和ID。

assistant: SELECT name ,  furniture_id FROM furniture ORDER BY market_rate DESC LIMIT 1
Schema: CREATE TABLE furniture (market_rate INTEGER)
user: 找到市场份额前2的家具的总市场价格。

assistant: SELECT sum(market_rate) FROM furniture ORDER BY market_rate DESC LIMIT 2
Schema: CREATE TABLE furniture (Num_of_Component INTEGER, name VARCHAR)
user: 查找有超过10个组件的所有家具的组件数量和名称。

assistant: SELECT Num_of_Component ,  name FROM furniture WHERE Num_of_Component  >  10
Schema: CREATE TABLE furniture (market_rate VARCHAR, name VARCHAR, Num_of_Component VARCHAR)
user: 找出最不受欢迎的家具的名称和部件数量。

assistant: SELECT name ,  Num_of_Component FROM furniture ORDER BY market_rate LIMIT 1
Schema: CREATE TABLE furniture (Furniture_ID VARCHAR, name VARCHAR), CREATE TABLE furniture_manufacte (Price_in_Dollar INTEGER)
user: 查找价格低于最高价格的家具名称。

assistant: SELECT t1.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID  =  t2.Furniture_ID WHERE t2.Price_in_Dollar  <  (SELECT max(Price_in_Dollar) FROM furniture_manufacte)
Schema: CREATE TABLE manufacturer (open_year VARCHAR, num_of_shops VARCHAR, name VARCHAR)
user: 哪个制造商的商店最多？列出其名称和开业年份。

assistant: SELECT open_year ,  name FROM manufacturer ORDER BY num_of_shops DESC LIMIT 1
Schema: CREATE TABLE manufacturer (num_of_shops INTEGER, Num_of_Factories INTEGER)
user: 找出拥有超过20个商店的制造商的平均工厂数量。

assistant: SELECT avg(Num_of_Factories) FROM manufacturer WHERE num_of_shops  >  20
Schema: CREATE TABLE manufacturer (manufacturer_id VARCHAR, name VARCHAR, open_year VARCHAR)
user: 列出其开张年度所订购的所有制造商名称和ID。

assistant: SELECT name ,  manufacturer_id FROM manufacturer ORDER BY open_year
Schema: CREATE TABLE manufacturer (num_of_shops INTEGER, open_year VARCHAR, name VARCHAR, Num_of_Factories INTEGER)
user: 请告诉我工厂少于10家或商店多于10家的制造商的名称和开业年份。

assistant: SELECT name ,  open_year FROM manufacturer WHERE num_of_shops  >  10 OR Num_of_Factories  <  10
Schema: CREATE TABLE manufacturer (num_of_shops INTEGER, Num_of_Factories INTEGER, open_year INTEGER)
user: 工厂的平均数量和1990年前开业的制造商的最大商店数量是多少？

assistant: SELECT max(num_of_shops) ,  avg(Num_of_Factories) FROM manufacturer WHERE open_year  <  1990
Schema: CREATE TABLE manufacturer (manufacturer_id VARCHAR, num_of_shops VARCHAR), CREATE TABLE furniture_manufacte (manufacturer_id VARCHAR, Price_in_Dollar VARCHAR)
user: 查找生产最贵家具的公司的id和商店的数量。

assistant: SELECT t1.manufacturer_id ,  t1.num_of_shops FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id  =  t2.manufacturer_id ORDER BY t2.Price_in_Dollar DESC LIMIT 1
Schema: CREATE TABLE manufacturer (manufacturer_id VARCHAR, name VARCHAR), CREATE TABLE furniture_manufacte (manufacturer_id VARCHAR)
user: 查找每个制造商生产的产品类型以及公司名称。

assistant: SELECT count(*) ,  t1.name FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id  =  t2.manufacturer_id GROUP BY t1.manufacturer_id
Schema: CREATE TABLE furniture (Furniture_ID VARCHAR, name VARCHAR), CREATE TABLE furniture_manufacte (price_in_dollar VARCHAR, Furniture_ID VARCHAR)
user: 请告诉我一些公司制造的家具的名称和价格。

assistant: SELECT t1.name ,  t2.price_in_dollar FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID  =  t2.Furniture_ID
Schema: CREATE TABLE furniture (name VARCHAR, Market_Rate VARCHAR, Furniture_ID VARCHAR), CREATE TABLE furniture_manufacte (name VARCHAR, Market_Rate VARCHAR, Furniture_ID VARCHAR)
user: 查找我们的记录里没有公司正在生产的家具的市场份额和名称。

assistant: SELECT Market_Rate ,  name FROM furniture WHERE Furniture_ID NOT IN (SELECT Furniture_ID FROM furniture_manufacte)
Schema: CREATE TABLE furniture (num_of_component INTEGER, Furniture_ID VARCHAR), CREATE TABLE furniture_manufacte (Furniture_ID VARCHAR, manufacturer_id VARCHAR), CREATE TABLE manufacturer (manufacturer_id VARCHAR, name VARCHAR)
user: 请查找生产的家具的部件小于6和多于10的公司的名称。

assistant: SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID  =  t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id  =  t3.manufacturer_id WHERE t1.num_of_component  <  6 INTERSECT SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID  =  t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id  =  t3.manufacturer_id WHERE t1.num_of_component  >  10
Schema: CREATE TABLE employees (first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 显示每个雇员的名字和部门名称。

assistant: SELECT T1.first_name ,  T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id
Schema: CREATE TABLE employees (first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 所有员工的名字和部门名称是什么？

assistant: SELECT T1.first_name ,  T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR)
user: 列出那些收入低于6000的员工的全名（名字和姓氏）以及薪水。

assistant: SELECT first_name ,  last_name ,  salary FROM employees WHERE salary  <  6000
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR)
user: 对于少于6000岁的员工，他们的全名和薪水是多少？

assistant: SELECT first_name ,  last_name ,  salary FROM employees WHERE salary  <  6000
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR)
user: 显示姓氏为“何”的所有员工的姓氏和部门号码。

assistant: SELECT first_name ,  department_id FROM employees WHERE last_name  =  '何'
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR)
user: 姓“何”的员工的姓氏和部门号码是什么？

assistant: SELECT first_name ,  department_id FROM employees WHERE last_name  =  '何'
Schema: CREATE TABLE employees (department_id VARCHAR)
user: 返回所有没有任何部门号码的员工的所有信息。

assistant: SELECT * FROM employees WHERE department_id  =  "空"
Schema: CREATE TABLE employees (department_id VARCHAR)
user: 没有部门编号的员工是什么？

assistant: SELECT * FROM employees WHERE department_id  =  "空"
Schema: CREATE TABLE departments (department_name VARCHAR)
user: 显示“市场”部的所有信息。

assistant: SELECT * FROM  departments WHERE department_name  =  '市场'
Schema: CREATE TABLE departments (department_name VARCHAR)
user: “市场”部的所有信息是什么？

assistant: SELECT * FROM  departments WHERE department_name  =  '市场'
Schema: CREATE TABLE employees (first_name VARCHAR, hire_date VARCHAR)
user: 那些名字不包含“男”字的雇员的雇佣日期是什么时候？

assistant: SELECT hire_date FROM employees WHERE first_name NOT LIKE '男'
Schema: CREATE TABLE employees (first_name VARCHAR, hire_date VARCHAR)
user: 名字里没有“男”字的雇员是在什么日期被雇用的？

assistant: SELECT hire_date FROM employees WHERE first_name NOT LIKE '男'
Schema: CREATE TABLE employees (department_id VARCHAR, first_name VARCHAR, salary VARCHAR, hire_date VARCHAR, last_name VARCHAR)
user: 显示名字不包含“男”字的雇员的全名（名字和姓氏）、雇用日期、工资和部门号码。

assistant: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '男'
Schema: CREATE TABLE employees (department_id VARCHAR, first_name VARCHAR, salary VARCHAR, hire_date VARCHAR, last_name VARCHAR)
user: 名字中没有“男”字的员工的全名、聘用日期、薪水和部门ID是什么？

assistant: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '男'
Schema: CREATE TABLE employees (department_id VARCHAR, first_name VARCHAR, salary VARCHAR, hire_date VARCHAR, last_name VARCHAR)
user: 显示名字不包含“男”字的雇员的全名（姓氏和名字）、雇用日期、工资和部门编号，并将结果按部门编号升序排列。

assistant: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '男' ORDER BY department_id
Schema: CREATE TABLE employees (department_id VARCHAR, first_name VARCHAR, salary VARCHAR, hire_date VARCHAR, last_name VARCHAR)
user: 名字中没有“男”字的员工的全名、雇佣数据、工资和部门ID是什么？

assistant: SELECT first_name ,  last_name ,  hire_date ,  salary ,  department_id FROM employees WHERE first_name NOT LIKE '男' ORDER BY department_id
Schema: CREATE TABLE employees (salary INTEGER, phone_number VARCHAR)
user: 工资在8000和120000范围内的雇员的电话号码是多少？

assistant: SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
Schema: CREATE TABLE employees (salary INTEGER, phone_number VARCHAR)
user: 返回工资在8000到12000之间的雇员的电话号码。

assistant: SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
Schema: CREATE TABLE employees (commission_pct VARCHAR, salary INTEGER, department_id VARCHAR)
user: 显示工资在8000到12000范围内且佣金不为“空”或部门编号不等于40的员工的所有信息。

assistant: SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "空" OR  department_id != 40
Schema: CREATE TABLE employees (commission_pct VARCHAR, salary INTEGER, department_id VARCHAR)
user: 返回所有有关工资在8000至12000之间而且佣金不为“空”，或者部门ID不为40的员工的信息。

assistant: SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "空" OR  department_id != 40
Schema: CREATE TABLE employees (last_name VARCHAR, commission_pct VARCHAR, first_name VARCHAR, salary VARCHAR)
user: 对于那些没有任何佣金的员工，他们的全名（名字和姓氏）和薪水是多少？

assistant: SELECT first_name ,  last_name ,  salary FROM  employees WHERE commission_pct  =  "空"
Schema: CREATE TABLE employees (last_name VARCHAR, commission_pct VARCHAR, first_name VARCHAR, salary VARCHAR)
user: 返回佣金为“空”的雇员的全名和工资。

assistant: SELECT first_name ,  last_name ,  salary FROM  employees WHERE commission_pct  =  "空"
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, salary VARCHAR)
user: 显示名字以字母“明”结尾的雇员的名字和姓氏，以及工资。

assistant: SELECT first_name ,  last_name ,  salary FROM employees WHERE first_name LIKE '明'
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, salary VARCHAR)
user: 返回名字以字母“明”结尾的员工的全名和薪水。

assistant: SELECT first_name ,  last_name ,  salary FROM employees WHERE first_name LIKE '明'
Schema: CREATE TABLE employees (job_id VARCHAR, hire_date VARCHAR)
user: 找到在“2007-11-05”和“2009-07-05”之间被雇佣的员工的职位id和雇佣日期。

assistant: SELECT job_id ,  hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
Schema: CREATE TABLE employees (job_id VARCHAR, hire_date VARCHAR)
user: “2009-07-05”以后和“2009-07-05”之前雇佣的雇员的职位id和雇佣日期是什么？

assistant: SELECT job_id ,  hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR)
user: 在70或90部门工作的员工的名字和姓是什么？

assistant: SELECT first_name ,  last_name FROM employees WHERE department_id  =  70 OR department_id  =  90
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR)
user: 在部门70或90的员工的全名是什么？

assistant: SELECT first_name ,  last_name FROM employees WHERE department_id  =  70 OR department_id  =  90
Schema: CREATE TABLE employees (manager_id VARCHAR, salary VARCHAR)
user: 找到那些在经理手下工作的员工的薪水和经理号码。

assistant: SELECT salary ,  manager_id FROM employees WHERE manager_id != "空"
Schema: CREATE TABLE employees (manager_id VARCHAR, salary VARCHAR)
user: 有经理的员工的工资和经理id是什么？

assistant: SELECT salary ,  manager_id FROM employees WHERE manager_id != "空"
Schema: CREATE TABLE employees (hire_date INTEGER)
user: 显示员工表中在“2002-06-21”之前雇佣的员工的所有细节。

assistant: SELECT * FROM employees WHERE hire_date  <  '2002-06-21'
Schema: CREATE TABLE employees (hire_date INTEGER)
user: “2002-06-21”之前雇用的员工的信息是什么？

assistant: SELECT * FROM employees WHERE hire_date  <  '2002-06-21'
Schema: CREATE TABLE employees (first_name VARCHAR, salary VARCHAR)
user: 显示所有名字中包含“安”字或“文”的所有员工的所有信息，并将结果按工资降序排列。

assistant: SELECT * FROM employees WHERE first_name LIKE '安' OR first_name LIKE 'S' ORDER BY salary DESC
Schema: CREATE TABLE employees (first_name VARCHAR, salary VARCHAR)
user: 按工资递减顺序排列，名字中包含“安”或“文”的员工有哪些信息？

assistant: SELECT * FROM employees WHERE first_name LIKE '安' OR first_name LIKE 'S' ORDER BY salary DESC
Schema: CREATE TABLE employees (hire_date INTEGER)
user: 显示“1987-09-07”后加入的员工。

assistant: SELECT * FROM employees WHERE hire_date  >  '1987-09-07'