jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE exhibition_record (exhibition_id VARCHAR, attendance VARCHAR, date VARCHAR), CREATE TABLE exhibition (theme VARCHAR, year VARCHAR, exhibition_id VARCHAR)
user: 返回在2004发生的展览的主题、日期和出席情况。

assistant: SELECT T2.theme ,  T1.date ,  T1.attendance FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T2.year  =  2004
Schema: CREATE TABLE artist (artist_id VARCHAR, name VARCHAR), CREATE TABLE exhibition (year VARCHAR, artist_id VARCHAR)
user: 展示所有在2004没有展览的艺术家名字。

assistant: SELECT name FROM artist EXCEPT SELECT T2.name FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id  =  T2.artist_id WHERE T1.year  =  2004
Schema: CREATE TABLE artist (artist_id VARCHAR, name VARCHAR), CREATE TABLE exhibition (year VARCHAR, artist_id VARCHAR)
user: 2004没有举办展览的艺术家的名字是什么？

assistant: SELECT name FROM artist EXCEPT SELECT T2.name FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id  =  T2.artist_id WHERE T1.year  =  2004
Schema: CREATE TABLE exhibition_record (attendance INTEGER, exhibition_id VARCHAR), CREATE TABLE exhibition (theme VARCHAR, exhibition_id VARCHAR)
user: 显示参展人数记录包括低于100人及超过500人的展览的主题。

assistant: SELECT T2.theme FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T1.attendance  <  100 INTERSECT SELECT T2.theme FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T1.attendance  >  500
Schema: CREATE TABLE exhibition_record (attendance INTEGER, exhibition_id VARCHAR), CREATE TABLE exhibition (theme VARCHAR, exhibition_id VARCHAR)
user: 展览的出席人数曾在100以下和500以上的主题有哪些？

assistant: SELECT T2.theme FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T1.attendance  <  100 INTERSECT SELECT T2.theme FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T1.attendance  >  500
Schema: CREATE TABLE exhibition_record (attendance INTEGER, exhibition_id VARCHAR), CREATE TABLE exhibition (exhibition_id VARCHAR, ticket_price INTEGER)
user: 有多少展览的参观人数超过100人或门票价格低于10？

assistant: SELECT count(*) FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T1.attendance  >  100 OR T2.ticket_price  <  10
Schema: CREATE TABLE exhibition_record (attendance INTEGER, exhibition_id VARCHAR), CREATE TABLE exhibition (exhibition_id VARCHAR, ticket_price INTEGER)
user: 数一数出席人数超过100人或门票价格低于10人的展览会数量。

assistant: SELECT count(*) FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id WHERE T1.attendance  >  100 OR T2.ticket_price  <  10
Schema: CREATE TABLE exhibition_record (attendance INTEGER, exhibition_id VARCHAR), CREATE TABLE exhibition (artist_id VARCHAR, exhibition_id VARCHAR), CREATE TABLE artist (artist_id VARCHAR, name VARCHAR)
user: 显示平均展览出席人数超过200的所有艺术家的姓名，。

assistant: SELECT T3.name FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id JOIN artist AS T3 ON T3.artist_id  =  T2.artist_id GROUP BY T3.artist_id HAVING avg(T1.attendance)  >  200
Schema: CREATE TABLE exhibition_record (attendance INTEGER, exhibition_id VARCHAR), CREATE TABLE exhibition (artist_id VARCHAR, exhibition_id VARCHAR), CREATE TABLE artist (artist_id VARCHAR, name VARCHAR)
user: 展览平均吸引200多位参展者的艺术家的名字是什么？

assistant: SELECT T3.name FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id  =  T2.exhibition_id JOIN artist AS T3 ON T3.artist_id  =  T2.artist_id GROUP BY T3.artist_id HAVING avg(T1.attendance)  >  200
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR)
user: 找到标题为“橙色”的项目的ID。

assistant: SELECT i_id FROM item WHERE title  =  "橙色"
Schema: CREATE TABLE item (Id VARCHAR)
user: 列出项目表中的所有信息。

assistant: SELECT * FROM item
Schema: CREATE TABLE review (Id VARCHAR)
user: 找到评论的数量。

assistant: SELECT count(*) FROM review
Schema: CREATE TABLE useracct (Id VARCHAR)
user: 有多少用户？

assistant: SELECT count(*) FROM useracct
Schema: CREATE TABLE review (rating INTEGER)
user: 查找所有评论的平均和最大评级。

assistant: SELECT avg(rating) ,  max(rating) FROM review
Schema: CREATE TABLE review (rank INTEGER)
user: 找到所有评论的最高评级。

assistant: SELECT min(rank) FROM review
Schema: CREATE TABLE review (u_id VARCHAR)
user: 有多少不同的用户写了一些评论？

assistant: SELECT count(DISTINCT u_id) FROM review
Schema: CREATE TABLE review (i_id VARCHAR)
user: 有多少不同的项目被一些用户评论？

assistant: SELECT count(DISTINCT i_id) FROM review
Schema: CREATE TABLE item (i_id VARCHAR), CREATE TABLE review (i_id VARCHAR)
user: 查找没有收到任何评论的项目的数量。

assistant: SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE review (name VARCHAR, u_id VARCHAR)
user: 查找没有留下任何评论的用户的姓名。

assistant: SELECT name FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rating VARCHAR, i_id VARCHAR)
user: 查找评级为10的商品名称。

assistant: SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id WHERE T2.rating  =  10
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rating INTEGER)
user: 查找评级高于所有项目的平均评级的项目的标题。

assistant: SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id WHERE T2.rating  >  (SELECT avg(rating) FROM review)
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rating INTEGER, i_id VARCHAR)
user: 找到任何评分低于5的项目的标题。

assistant: SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id WHERE T2.rating  <  5
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rating INTEGER, i_id VARCHAR)
user: 查找同时获得高于8和低于5的评分的项目的标题。

assistant: SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id WHERE T2.rating  >  8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id WHERE T2.rating  <  5
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rank INTEGER, rating INTEGER, i_id VARCHAR)
user: 查找评分高于3且平均评分高于5的项目的名称。

assistant: SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id WHERE T2.rank  >  3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id GROUP BY T2.i_id HAVING avg(T2.rating)  >  5
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rating INTEGER, i_id VARCHAR)
user: 查找具有最低平均评分的项目的名称。

assistant: SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) LIMIT 1
Schema: CREATE TABLE item (title VARCHAR)
user: 按字母顺序列出所有项目的标题。

assistant: SELECT title FROM item ORDER BY title
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE review (u_id VARCHAR)
user: 查找提供最多评论的用户的名称。

assistant: SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id  =  T2.u_id GROUP BY T2.u_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rating INTEGER, i_id VARCHAR)
user: 查找具有最高平均评级的项目的名称和ID。

assistant: SELECT T1.title ,  T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) DESC LIMIT 1
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (rank INTEGER, i_id VARCHAR)
user: 找出具有最高平均评分的项目的名称和ID。

assistant: SELECT T1.title ,  T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id  =  T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rank) DESC LIMIT 1
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE review (u_id VARCHAR, rating INTEGER)
user: 对于每个用户，返回他们给出的评论的名称和平均评级。

assistant: SELECT T1.name ,  avg(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id  =  T2.u_id GROUP BY T2.u_id
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE review (u_id VARCHAR)
user: 对于每个用户，找到他们的名字和他们写的评论的数量。

assistant: SELECT T1.name ,  count(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id  =  T2.u_id GROUP BY T2.u_id
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE review (rating VARCHAR, u_id VARCHAR)
user: 找到最高评级的用户的名字。

assistant: SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id  =  T2.u_id ORDER BY T2.rating DESC LIMIT 1
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE trust (source_u_id VARCHAR)
user: 查找具有最高平均信任分数的源用户的名称。

assistant: SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id  =  T2.source_u_id GROUP BY T2.source_u_id ORDER BY avg(trust) DESC LIMIT 1
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE trust (target_u_id VARCHAR)
user: 查找每个目标用户的姓名和平均信任分数。

assistant: SELECT T1.name ,  avg(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id  =  T2.target_u_id GROUP BY T2.target_u_id
Schema: CREATE TABLE useracct (name VARCHAR, u_id VARCHAR), CREATE TABLE trust (target_u_id VARCHAR)
user: 查找最低信任分数的目标用户的姓名。

assistant: SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id  =  T2.target_u_id ORDER BY trust LIMIT 1
Schema: CREATE TABLE item (title VARCHAR, i_id VARCHAR), CREATE TABLE review (title VARCHAR, i_id VARCHAR)
user: 查找没有收到任何评论的项目的名称。

assistant: SELECT title FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
Schema: CREATE TABLE useracct (u_id VARCHAR), CREATE TABLE review (u_id VARCHAR)
user: 找到没有写任何评论的用户的数量。

assistant: SELECT count(*) FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
Schema: CREATE TABLE item (i_id VARCHAR), CREATE TABLE review (i_id VARCHAR)
user: 查找没有任何评论的项目的数量。

assistant: SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
Schema: CREATE TABLE player (Id VARCHAR)
user: 有多少运动员？

assistant: SELECT count(*) FROM player
Schema: CREATE TABLE player (Votes VARCHAR, Player_name VARCHAR)
user: 按升序排列运动员的名字。

assistant: SELECT Player_name FROM player ORDER BY Votes ASC
Schema: CREATE TABLE player (Occupation VARCHAR, Gender VARCHAR)
user: 运动员的性别和职业是什么？

assistant: SELECT Gender ,  Occupation FROM player
Schema: CREATE TABLE player (Occupation VARCHAR, residence VARCHAR, Player_name VARCHAR)
user: 列出职业不是“研究员”的运动员的姓名和住所。

assistant: SELECT Player_name ,  residence FROM player WHERE Occupation != "研究员"
Schema: CREATE TABLE player (Sponsor_name VARCHAR, Residence VARCHAR)
user: 显示住在“池”或“皓”的球员的赞助商的名字。

assistant: SELECT Sponsor_name FROM player WHERE Residence  =  "池" OR Residence  =  "皓"
Schema: CREATE TABLE player (Votes VARCHAR, Player_name VARCHAR)
user: 票数最多的运动员叫什么名字？

assistant: SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1
Schema: CREATE TABLE player (Occupation VARCHAR)
user: 显示不同的职业和每个职业运动员的数量。

assistant: SELECT Occupation ,  COUNT(*) FROM player GROUP BY Occupation
Schema: CREATE TABLE player (Occupation VARCHAR)
user: 请显示最常见的运动员职业。

assistant: SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE player (Residence VARCHAR)
user: 显示至少有两个运动员的住址。

assistant: SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*)  >=  2
Schema: CREATE TABLE player_coach (Coach_ID VARCHAR, Player_ID VARCHAR), CREATE TABLE coach (Coach_ID VARCHAR, coach_name VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR)
user: 显示运动员姓名和教练员姓名。

assistant: SELECT T3.Player_name ,  T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID  =  T2.Coach_ID JOIN player AS T3 ON T1.Player_ID  =  T3.Player_ID
Schema: CREATE TABLE player_coach (Coach_ID VARCHAR, Player_ID VARCHAR), CREATE TABLE coach (Coach_ID VARCHAR, Rank VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR)
user: 显示排名第1的教练执教的球员的名字。

assistant: SELECT T3.Player_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID  =  T2.Coach_ID JOIN player AS T3 ON T1.Player_ID  =  T3.Player_ID WHERE T2.Rank  =  1
Schema: CREATE TABLE player_coach (Coach_ID VARCHAR, Player_ID VARCHAR, Starting_year INTEGER), CREATE TABLE coach (Coach_ID VARCHAR), CREATE TABLE player (Player_ID VARCHAR, gender VARCHAR, Player_name VARCHAR)
user: 显示2011年后开始有教练的球员的名字和性别。

assistant: SELECT T3.Player_name ,  T3.gender FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID  =  T2.Coach_ID JOIN player AS T3 ON T1.Player_ID  =  T3.Player_ID WHERE T1.Starting_year  >  2011
Schema: CREATE TABLE player_coach (Coach_ID VARCHAR, Player_ID VARCHAR), CREATE TABLE coach (Coach_ID VARCHAR, coach_name VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Votes VARCHAR, Player_name VARCHAR)
user: 按照选手投票的降序，显示选手姓名和教练姓名。

assistant: SELECT T3.Player_name ,  T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID  =  T2.Coach_ID JOIN player AS T3 ON T1.Player_ID  =  T3.Player_ID ORDER BY T3.Votes DESC
Schema: CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR), CREATE TABLE player_coach (Player_ID VARCHAR, Player_name VARCHAR)
user: 列出没有教练的运动员的名字。

assistant: SELECT Player_name FROM player WHERE Player_ID NOT IN (SELECT Player_ID FROM player_coach)
Schema: CREATE TABLE player (gender VARCHAR, Residence VARCHAR)
user: 显示既有性别为“男”又有性别为“女”的运动员的住址。

assistant: SELECT Residence FROM player WHERE gender  =  "男" INTERSECT SELECT Residence FROM player WHERE gender  =  "女"
Schema: CREATE TABLE club (club_name VARCHAR, club_id VARCHAR), CREATE TABLE coach (club_id VARCHAR)
user: 每个俱乐部有多少教练？列出教练员的ID、姓名和教练员数量。

assistant: SELECT T1.club_id ,  T1.club_name, count(*) FROM club AS T1 JOIN coach AS T2 ON T1.club_id  =  T2.club_id GROUP BY T1.club_id
Schema: CREATE TABLE match_result (gold VARCHAR, club_id VARCHAR), CREATE TABLE coach (club_id VARCHAR)
user: 拥有最多教练的俱乐部有多少枚金牌？

assistant: SELECT T1.club_id ,  T1.gold FROM match_result AS T1 JOIN coach AS T2 ON T1.club_id  =  T2.club_id GROUP BY T1.club_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE gymnast (Id VARCHAR)
user: 有多少体操运动员？

assistant: SELECT count(*) FROM gymnast
Schema: CREATE TABLE gymnast (Id VARCHAR)
user: 计算体操运动员的数量。

assistant: SELECT count(*) FROM gymnast
Schema: CREATE TABLE gymnast (Total_Points VARCHAR)
user: 按降序，列出体操运动员的总分。

assistant: SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
Schema: CREATE TABLE gymnast (Total_Points VARCHAR)
user: 按降序排列，所有体操运动员的总分是多少？

assistant: SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
Schema: CREATE TABLE gymnast (Floor_Exercise_Points VARCHAR, Total_Points VARCHAR)
user: 按自由体操点数降序列出体操运动员的总分。

assistant: SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
Schema: CREATE TABLE gymnast (Floor_Exercise_Points VARCHAR, Total_Points VARCHAR)
user: 体操运动员按自由体操点数的下降顺序，总分是多少？

assistant: SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
Schema: CREATE TABLE gymnast (Horizontal_Bar_Points INTEGER)
user: 所有体操运动员的平均单杠得分是多少？

assistant: SELECT avg(Horizontal_Bar_Points) FROM gymnast
Schema: CREATE TABLE gymnast (Horizontal_Bar_Points INTEGER)
user: 返回所有体操运动员的平均单杠得分。

assistant: SELECT avg(Horizontal_Bar_Points) FROM gymnast
Schema: CREATE TABLE People (Name VARCHAR)
user: 按字母顺序排列的人的名字是什么？

assistant: SELECT Name FROM People ORDER BY Name ASC
Schema: CREATE TABLE People (Name VARCHAR)
user: 按字母顺序排列人名。

assistant: SELECT Name FROM People ORDER BY Name ASC
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Name VARCHAR)
user: 体操运动员的名字是什么？

assistant: SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Name VARCHAR)
user: 返回体操运动员的名字。

assistant: SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR, Name VARCHAR)
user: 家乡不是“洛阳”的体操运动员的名字是什么？

assistant: SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID WHERE T2.Hometown != "洛阳"
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR, Name VARCHAR)
user: 返回不是在“洛阳”长大的体操运动员的名字。

assistant: SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID WHERE T2.Hometown != "洛阳"
Schema: CREATE TABLE people (Age VARCHAR, Height VARCHAR)
user: 最高的人年龄是多少岁？

assistant: SELECT Age FROM people ORDER BY Height DESC LIMIT 1
Schema: CREATE TABLE people (Age VARCHAR, Height VARCHAR)
user: 返回身高最大的人的年龄。

assistant: SELECT Age FROM people ORDER BY Height DESC LIMIT 1
Schema: CREATE TABLE People (Age VARCHAR, Name VARCHAR)
user: 列出5个最老的人的名字。

assistant: SELECT Name FROM People ORDER BY Age DESC LIMIT 5
Schema: CREATE TABLE People (Age VARCHAR, Name VARCHAR)
user: 五个最老的人的名字是什么？

assistant: SELECT Name FROM People ORDER BY Age DESC LIMIT 5
Schema: CREATE TABLE gymnast (Total_Points VARCHAR, Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
user: 最年轻的体操运动员的总得分是多少？

assistant: SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID ORDER BY T2.Age ASC LIMIT 1
Schema: CREATE TABLE gymnast (Total_Points VARCHAR, Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
user: 返回最年轻的体操运动员的总得分。

assistant: SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID ORDER BY T2.Age ASC LIMIT 1
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age INTEGER)
user: 所有体操运动员的平均年龄是多少？

assistant: SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age INTEGER)
user: 返回所有体操运动员的平均年龄。

assistant: SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID
Schema: CREATE TABLE gymnast (Total_Points INTEGER, Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 总得分超过57.5的体操运动员的不同家乡是什么？

assistant: SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID WHERE T1.Total_Points  >  57.5
Schema: CREATE TABLE gymnast (Total_Points INTEGER, Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 给出总分在57.5以上的体操运动员的不同家乡。

assistant: SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID WHERE T1.Total_Points  >  57.5
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 体操运动员的家乡和体操运动员的数量是多少？

assistant: SELECT T2.Hometown ,  COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID GROUP BY T2.Hometown
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 每个家乡有多少体操运动员？

assistant: SELECT T2.Hometown ,  COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID GROUP BY T2.Hometown
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 体操运动员最多的家乡是什么？

assistant: SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 返回体操运动员中最多的家乡。

assistant: SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 哪些家乡有至少两名体操运动员？

assistant: SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*)  >=  2
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR)
user: 给我两个或更多体操运动员来自的家乡。

assistant: SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*)  >=  2
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Height VARCHAR, Name VARCHAR)
user: 按身高顺序排列体操运动员的名字。

assistant: SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID ORDER BY T2.Height ASC
Schema: CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Height VARCHAR, Name VARCHAR)
user: 按照身高排序，体操运动员的名字是什么？

assistant: SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID ORDER BY T2.Height ASC
Schema: CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR), CREATE TABLE gymnast (Gymnast_ID VARCHAR)
user: 列出没有体操运动员的不同家乡。

assistant: SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID
Schema: CREATE TABLE people (People_ID VARCHAR, Hometown VARCHAR), CREATE TABLE gymnast (Gymnast_ID VARCHAR)
user: 哪一个家乡没有体操运动员？

assistant: SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID
Schema: CREATE TABLE people (Hometown VARCHAR, Age INTEGER)
user: 展示有23岁以上和20岁以下的人的家乡。

assistant: SELECT Hometown FROM people WHERE Age  >  23 INTERSECT SELECT Hometown FROM people WHERE Age  <  20
Schema: CREATE TABLE people (Hometown VARCHAR, Age INTEGER)
user: 哪个家乡有23岁以上和20岁以下的人？

assistant: SELECT Hometown FROM people WHERE Age  >  23 INTERSECT SELECT Hometown FROM people WHERE Age  <  20
Schema: CREATE TABLE people (Hometown VARCHAR)
user: 这些人有多少不同的家乡？

assistant: SELECT count(DISTINCT Hometown) FROM people
Schema: CREATE TABLE people (Hometown VARCHAR)
user: 数一数这些人的不同家乡。

assistant: SELECT count(DISTINCT Hometown) FROM people
Schema: CREATE TABLE gymnast (Total_Points VARCHAR, Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
user: 以总分递减顺序显示体操运动员的年龄。

assistant: SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID ORDER BY T1.Total_Points DESC
Schema: CREATE TABLE gymnast (Total_Points VARCHAR, Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
user: 按它们总得分降序，体操运动员的年龄是多少？

assistant: SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID  =  T2.People_ID ORDER BY T1.Total_Points DESC
Schema: CREATE TABLE accounts (name VARCHAR, custid VARCHAR), CREATE TABLE savings (custid VARCHAR, balance INTEGER)
user: 找出除了名为“小智”的账户的所有账户的总储蓄余额。

assistant: SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid  =  T2.custid WHERE T1.name != '小智'
Schema: CREATE TABLE accounts (name VARCHAR, custid VARCHAR), CREATE TABLE savings (custid VARCHAR, balance INTEGER)
user: 不属于“小智”这个名字的人的储蓄账户的总储蓄余额是多少？

assistant: SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid  =  T2.custid WHERE T1.name != '小智'
Schema: CREATE TABLE accounts (Id VARCHAR)
user: 总共有多少个帐户？

assistant: SELECT count(*) FROM accounts
Schema: CREATE TABLE accounts (Id VARCHAR)
user: 计算账户数量。

assistant: SELECT count(*) FROM accounts
Schema: CREATE TABLE checking (balance INTEGER)
user: 所有帐户的总储蓄余额是多少？

assistant: SELECT sum(balance) FROM checking
Schema: CREATE TABLE checking (balance INTEGER)
user: 找到在支票账户上的总储蓄余额。

assistant: SELECT sum(balance) FROM checking
Schema: CREATE TABLE checking (balance INTEGER)
user: 找到平均支票余额。

assistant: SELECT avg(balance) FROM checking
Schema: CREATE TABLE checking (balance INTEGER)
user: 支票账户的平均余额是多少？

assistant: SELECT avg(balance) FROM checking
Schema: CREATE TABLE savings (balance INTEGER)
user: 有多少账户储蓄余额高于平均储蓄余额？

assistant: SELECT count(*) FROM savings WHERE balance  >  (SELECT avg(balance) FROM savings)
Schema: CREATE TABLE savings (balance INTEGER)
user: 查找存款余额高于平均存款余额的账户数量。

assistant: SELECT count(*) FROM savings WHERE balance  >  (SELECT avg(balance) FROM savings)
Schema: CREATE TABLE accounts (name VARCHAR, custid VARCHAR), CREATE TABLE checking (balance INTEGER)
user: 查找支票余额低于最大支票余额的帐户的名称和id。

assistant: SELECT T1.custid ,  T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid  =  T2.custid WHERE T2.balance  <  (SELECT max(balance) FROM checking)
Schema: CREATE TABLE accounts (name VARCHAR, custid VARCHAR), CREATE TABLE checking (balance INTEGER)
user: 支票余额小于最大支票余额的账户相对应的客户ID和名称是什么？

assistant: SELECT T1.custid ,  T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid  =  T2.custid WHERE T2.balance  <  (SELECT max(balance) FROM checking)