jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE track (seating INTEGER)
user: 所有轨道最小，最大，平均座位数是什么？

assistant: SELECT min(seating) ,  max(seating) ,  avg(seating) FROM track
Schema: CREATE TABLE track (seating INTEGER)
user: 返回所有轨道上的最小、最大和平均座椅数。

assistant: SELECT min(seating) ,  max(seating) ,  avg(seating) FROM track
Schema: CREATE TABLE track (LOCATION VARCHAR, year_opened VARCHAR, name VARCHAR, seating INTEGER)
user: 显示座位数高于平均水平的所有轨道的名称、位置、开放年份。

assistant: SELECT name ,  LOCATION ,  year_opened FROM track WHERE seating  >  (SELECT avg(seating) FROM track)
Schema: CREATE TABLE track (LOCATION VARCHAR, year_opened VARCHAR, name VARCHAR, seating INTEGER)
user: 座位数高于平均水平的轨道的名称、位置和开放年份是什么？

assistant: SELECT name ,  LOCATION ,  year_opened FROM track WHERE seating  >  (SELECT avg(seating) FROM track)
Schema: CREATE TABLE track (LOCATION VARCHAR)
user: 轨道的不同位置是什么？

assistant: SELECT DISTINCT LOCATION FROM track
Schema: CREATE TABLE track (LOCATION VARCHAR)
user: 给出轨道的不同位置。

assistant: SELECT DISTINCT LOCATION FROM track
Schema: CREATE TABLE race (Id VARCHAR)
user: 一共有多少场比赛？

assistant: SELECT count(*) FROM race
Schema: CREATE TABLE race (Id VARCHAR)
user: 计算比赛的次数。

assistant: SELECT count(*) FROM race
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 比赛有哪些不同的类别？

assistant: SELECT DISTINCT CLASS FROM race
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 返回比赛的不同种类。

assistant: SELECT DISTINCT CLASS FROM race
Schema: CREATE TABLE race (CLASS VARCHAR, name VARCHAR, date VARCHAR)
user: 显示所有比赛的名字、类别和日期。

assistant: SELECT name ,  CLASS ,  date FROM race
Schema: CREATE TABLE race (CLASS VARCHAR, name VARCHAR, date VARCHAR)
user: 所有比赛的名字、类别和日期是什么？

assistant: SELECT name ,  CLASS ,  date FROM race
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 显示比赛类别和每种类别的比赛数量。

assistant: SELECT CLASS ,  count(*) FROM race GROUP BY CLASS
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 不同的比赛类别是什么？每个类别有多少比赛？

assistant: SELECT CLASS ,  count(*) FROM race GROUP BY CLASS
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 比赛数量最多的比赛类别是什么？

assistant: SELECT CLASS FROM race GROUP BY CLASS ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 给出比赛最多的类别。

assistant: SELECT CLASS FROM race GROUP BY CLASS ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 列出有至少两个比赛的比赛类别。

assistant: SELECT CLASS FROM race GROUP BY CLASS HAVING count(*)  >=  2
Schema: CREATE TABLE race (CLASS VARCHAR)
user: 有两个或多个比赛的比赛类别有哪些？

assistant: SELECT CLASS FROM race GROUP BY CLASS HAVING count(*)  >=  2
Schema: CREATE TABLE track (name VARCHAR, track_id VARCHAR), CREATE TABLE race (track_id VARCHAR, class VARCHAR)
user: 没有“GT”类别比赛的赛道名称是什么？

assistant: SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id WHERE T1.class  =  'GT'
Schema: CREATE TABLE track (name VARCHAR, track_id VARCHAR), CREATE TABLE race (track_id VARCHAR, class VARCHAR)
user: 给出没有“GT”类别比赛的赛道的名称。

assistant: SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id WHERE T1.class  =  'GT'
Schema: CREATE TABLE track (name VARCHAR, track_id VARCHAR), CREATE TABLE race (name VARCHAR, track_id VARCHAR)
user: 显示所有没有比赛的赛道名称。

assistant: SELECT name FROM track WHERE track_id NOT IN (SELECT track_id FROM race)
Schema: CREATE TABLE track (name VARCHAR, track_id VARCHAR), CREATE TABLE race (name VARCHAR, track_id VARCHAR)
user: 返回没有任何比赛的赛道的名称。

assistant: SELECT name FROM track WHERE track_id NOT IN (SELECT track_id FROM race)
Schema: CREATE TABLE track (seating INTEGER, year_opened VARCHAR)
user: 显示至少有5000和不超过40000座位数的赛道开放的年份。

assistant: SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000
Schema: CREATE TABLE track (seating INTEGER, year_opened VARCHAR)
user: 在4000到5000座位数的赛道的开放年是多少？

assistant: SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000
Schema: CREATE TABLE race (track_id VARCHAR), CREATE TABLE track (name VARCHAR, track_id VARCHAR)
user: 显示赛道的名称和每个赛道上的比赛数。

assistant: SELECT T2.name ,  count(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id
Schema: CREATE TABLE race (track_id VARCHAR), CREATE TABLE track (name VARCHAR, track_id VARCHAR)
user: 不同的赛道名称是什么，每个赛道有多少比赛？

assistant: SELECT T2.name ,  count(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id
Schema: CREATE TABLE race (track_id VARCHAR), CREATE TABLE track (name VARCHAR, track_id VARCHAR)
user: 显示比赛次数最多的赛道名称。

assistant: SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE race (track_id VARCHAR), CREATE TABLE track (name VARCHAR, track_id VARCHAR)
user: 有最多比赛次数的赛道的名字是什么？

assistant: SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE race (name VARCHAR, date VARCHAR, track_id VARCHAR), CREATE TABLE track (name VARCHAR, track_id VARCHAR)
user: 显示每个比赛的名称和日期及其赛道名称。

assistant: SELECT T1.name ,  T1.date ,  T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id
Schema: CREATE TABLE race (name VARCHAR, date VARCHAR, track_id VARCHAR), CREATE TABLE track (name VARCHAR, track_id VARCHAR)
user: 比赛的名称和日期，以及举行比赛的赛道的名称？

assistant: SELECT T1.name ,  T1.date ,  T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id
Schema: CREATE TABLE race (track_id VARCHAR), CREATE TABLE track (name VARCHAR, location VARCHAR, track_id VARCHAR)
user: 显示有1个比赛的赛道的名称和位置。

assistant: SELECT T2.name ,  T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id HAVING count(*)  =  1
Schema: CREATE TABLE race (track_id VARCHAR), CREATE TABLE track (name VARCHAR, location VARCHAR, track_id VARCHAR)
user: 有1个比赛的赛道的名称和位置是什么？

assistant: SELECT T2.name ,  T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id HAVING count(*)  =  1
Schema: CREATE TABLE track (LOCATION VARCHAR, seating INTEGER)
user: 找到有超过90000个座位的赛道和少于70000个座位的赛道的位置。

assistant: SELECT LOCATION FROM track WHERE seating  >  90000 INTERSECT SELECT LOCATION FROM track WHERE seating  <  70000
Schema: CREATE TABLE track (LOCATION VARCHAR, seating INTEGER)
user: 哪些地方有超过90000个座位的赛道和少于70000个座位的赛道？

assistant: SELECT LOCATION FROM track WHERE seating  >  90000 INTERSECT SELECT LOCATION FROM track WHERE seating  <  70000
Schema: CREATE TABLE member (Membership_card VARCHAR)
user: 有多少会员有黑会员卡？

assistant: SELECT count(*) FROM member WHERE Membership_card  =  '黑卡'
Schema: CREATE TABLE member (address VARCHAR)
user: 找到每个住址的会员的数量。

assistant: SELECT count(*) ,  address FROM member GROUP BY address
Schema: CREATE TABLE member (address VARCHAR, name VARCHAR)
user: 请告诉我地址在“金华”或“湖州”的会员的名字。

assistant: SELECT name FROM member WHERE address  =  '金华' OR address  =  '湖州'
Schema: CREATE TABLE member (age INTEGER, Membership_card VARCHAR, name VARCHAR, member_id VARCHAR)
user: 查找30岁以下或持有黑会员卡的会员的ID和姓名。

assistant: SELECT name ,  member_id FROM member WHERE Membership_card  =  '黑卡' OR age  <  30
Schema: CREATE TABLE member (address VARCHAR, age VARCHAR, Time_of_purchase VARCHAR)
user: 查找每个会员的购买时间、年龄和地址，并按照购买时间的顺序显示结果。

assistant: SELECT Time_of_purchase ,  age ,  address FROM member ORDER BY Time_of_purchase
Schema: CREATE TABLE member (Membership_card VARCHAR)
user: 哪一张会员卡有超过5名会员？

assistant: SELECT Membership_card FROM member GROUP BY Membership_card HAVING count(*)  >  5
Schema: CREATE TABLE member (age INTEGER, address VARCHAR)
user: 哪个地址既有会员年龄小于30岁，又有会员超过40岁？

assistant: SELECT address FROM member WHERE age  <  30 INTERSECT SELECT address FROM member WHERE age  >  40
Schema: CREATE TABLE member (address VARCHAR, membership_card VARCHAR)
user: 住在“金华”的会员和住在“湖州”的会员都持有的卡都有哪些？

assistant: SELECT membership_card FROM member WHERE address  =  '金华' INTERSECT SELECT membership_card FROM member WHERE address  =  '湖州'
Schema: CREATE TABLE member (address VARCHAR)
user: 有多少会员不住在“金华”？

assistant: SELECT count(*) FROM member WHERE address != '金华'
Schema: CREATE TABLE member (address VARCHAR, Membership_card VARCHAR)
user: 哪个地址没有黑色会员卡的会员？

assistant: SELECT address FROM member EXCEPT SELECT address FROM member WHERE Membership_card  =  '黑卡'
Schema: CREATE TABLE shop (address VARCHAR, open_year VARCHAR)
user: 按照开业时间排列显示商店地址。

assistant: SELECT address FROM shop ORDER BY open_year
Schema: CREATE TABLE shop (num_of_staff INTEGER, score INTEGER)
user: 所有商店的平均分和平均员工数是多少？

assistant: SELECT avg(num_of_staff) ,  avg(score) FROM shop
Schema: CREATE TABLE shop (address VARCHAR, shop_id VARCHAR, score INTEGER)
user: 找出得分低于平均分的商店的ID和地址。

assistant: SELECT shop_id ,  address FROM shop WHERE score  <  (SELECT avg(score) FROM shop)
Schema: CREATE TABLE shop (address VARCHAR, shop_id VARCHAR, num_of_staff VARCHAR), CREATE TABLE happy_hour (address VARCHAR, shop_id VARCHAR, num_of_staff VARCHAR)
user: 找到没有快乐时间的商店的地址和员工数量。

assistant: SELECT address ,  num_of_staff FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM happy_hour)
Schema: CREATE TABLE shop (address VARCHAR, shop_id VARCHAR), CREATE TABLE happy_hour (shop_id VARCHAR)
user: 五月份有一个欢乐时间的商店的ID和地址是什么？

assistant: SELECT t1.address ,  t1.shop_id FROM shop AS t1 JOIN happy_hour AS t2 ON t1.shop_id  =  t2.shop_id WHERE MONTH  =  '五月'
Schema: CREATE TABLE happy_hour (shop_id VARCHAR)
user: 哪个商店的开心时间最多？列出它的ID和快乐时间的数量。

assistant: SELECT shop_id ,  count(*) FROM happy_hour GROUP BY shop_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE happy_hour (MONTH VARCHAR)
user: 哪一个月有最多的快乐时间？

assistant: SELECT MONTH FROM happy_hour GROUP BY MONTH ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE happy_hour (MONTH VARCHAR)
user: 哪几个月有超过2个快乐时间？

assistant: SELECT MONTH FROM happy_hour GROUP BY MONTH HAVING count(*)  >  2
Schema: CREATE TABLE ALBUM (Id VARCHAR)
user: 有多少张专辑？

assistant: SELECT count(*) FROM ALBUM
Schema: CREATE TABLE ALBUM (Id VARCHAR)
user: 找到专辑的数量。

assistant: SELECT count(*) FROM ALBUM
Schema: CREATE TABLE GENRE (Name VARCHAR)
user: 列出所有音乐流派的名称。

assistant: SELECT Name FROM GENRE
Schema: CREATE TABLE GENRE (Name VARCHAR)
user: 不同音乐流派的名字是什么？

assistant: SELECT Name FROM GENRE
Schema: CREATE TABLE CUSTOMER (State VARCHAR)
user: 查找“广东”州所有客户信息。

assistant: SELECT * FROM CUSTOMER WHERE State  =  "广东"
Schema: CREATE TABLE CUSTOMER (State VARCHAR)
user: “广东”州客户的所有客户信息是什么？

assistant: SELECT * FROM CUSTOMER WHERE State  =  "广东"
Schema: CREATE TABLE EMPLOYEE (FirstName VARCHAR, City VARCHAR, LastName VARCHAR)
user: 住在“青岛”市的员工的名字和姓是什么？

assistant: SELECT FirstName ,  LastName FROM EMPLOYEE WHERE City  =  "青岛"
Schema: CREATE TABLE EMPLOYEE (FirstName VARCHAR, City VARCHAR, LastName VARCHAR)
user: 查找居住在“青岛”市的雇员的全名。

assistant: SELECT FirstName ,  LastName FROM EMPLOYEE WHERE City  =  "青岛"
Schema: CREATE TABLE INVOICE (BillingCountry VARCHAR)
user: 不同发票的收费国家有哪些？

assistant: SELECT distinct(BillingCountry) FROM INVOICE
Schema: CREATE TABLE INVOICE (BillingCountry VARCHAR)
user: 查找所有发票不同的收费国家。

assistant: SELECT distinct(BillingCountry) FROM INVOICE
Schema: CREATE TABLE ARTIST (Name VARCHAR)
user: 找出所有名字中有“a”的艺术家的名字。

assistant: SELECT Name FROM ARTIST WHERE Name LIKE "安"
Schema: CREATE TABLE ARTIST (Name VARCHAR)
user: 名字中有字母“a”的艺术家有哪些？

assistant: SELECT Name FROM ARTIST WHERE Name LIKE "安"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: 找到“吴亦凡”艺术家的所有专辑的标题。

assistant: SELECT Title FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId WHERE T2.Name  =  "吴亦凡"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: “吴亦凡”艺术家的专辑的标题是什么？

assistant: SELECT Title FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId WHERE T2.Name  =  "吴亦凡"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: “陈奕迅”艺术家有多少张专辑？

assistant: SELECT COUNT(*) FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId WHERE T2.Name  =  "陈奕迅"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: 找到“陈奕迅”艺术家的专辑数量。

assistant: SELECT COUNT(*) FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId WHERE T2.Name  =  "陈奕迅"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR, Title VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: “奇幻旅程”专辑是哪一位艺术家？

assistant: SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId WHERE T1.Title  =  "奇幻旅程"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR, Title VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: 找到制作“奇幻旅程”专辑艺术家的名字。

assistant: SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId WHERE T1.Title  =  "奇幻旅程"
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: 哪位艺术家的专辑最多？

assistant: SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId GROUP BY T2.Name ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE ALBUM (ArtistId VARCHAR), CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR)
user: 专辑数量最多的艺人叫什么名字？

assistant: SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId  =  T2.ArtistId GROUP BY T2.Name ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE TRACK (Name VARCHAR)
user: 找出包含“你”这个词的所有曲目的名字。

assistant: SELECT Name FROM TRACK WHERE Name LIKE '你'
Schema: CREATE TABLE TRACK (Name VARCHAR)
user: 包含了“你”这个词的曲目的名字是什么？

assistant: SELECT Name FROM TRACK WHERE Name LIKE '你'
Schema: CREATE TABLE TRACK (UnitPrice INTEGER)
user: 所有歌曲的平均单价是多少？

assistant: SELECT AVG(UnitPrice) FROM TRACK
Schema: CREATE TABLE TRACK (UnitPrice INTEGER)
user: 找到歌曲的平均单价。

assistant: SELECT AVG(UnitPrice) FROM TRACK
Schema: CREATE TABLE TRACK (Milliseconds INTEGER)
user: 最长和最短的歌曲的持续时间是多少毫秒？

assistant: SELECT max(Milliseconds) ,  min(Milliseconds) FROM TRACK
Schema: CREATE TABLE TRACK (Milliseconds INTEGER)
user: 找到毫秒下歌曲的最大和最小持续时间。

assistant: SELECT max(Milliseconds) ,  min(Milliseconds) FROM TRACK
Schema: CREATE TABLE ALBUM (AlbumId VARCHAR, Title VARCHAR), CREATE TABLE TRACK (AlbumID VARCHAR, AlbumId VARCHAR)
user: 显示专辑名称、ID和每张专辑的曲目数量。

assistant: SELECT T1.Title ,  T2.AlbumID ,  COUNT(*) FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId  =  T2.AlbumId GROUP BY T2.AlbumID
Schema: CREATE TABLE ALBUM (AlbumId VARCHAR, Title VARCHAR), CREATE TABLE TRACK (AlbumID VARCHAR, AlbumId VARCHAR)
user: 不同专辑的名称和ID是什么？每个专辑有多少首曲目？

assistant: SELECT T1.Title ,  T2.AlbumID ,  COUNT(*) FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId  =  T2.AlbumId GROUP BY T2.AlbumID
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 所有曲目中最常见的类型是什么？

assistant: SELECT T1.Name FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId GROUP BY T2.GenreId ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 找出所有曲目中最常见的类型的名称。

assistant: SELECT T1.Name FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId GROUP BY T2.GenreId ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE MEDIATYPE (Name VARCHAR, MediaTypeId VARCHAR), CREATE TABLE TRACK (MediaTypeId VARCHAR)
user: 在所有歌曲中最常见的媒体类型是什么？

assistant: SELECT T1.Name FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId  =  T2.MediaTypeId GROUP BY T2.MediaTypeId ORDER BY COUNT(*) ASC LIMIT 1
Schema: CREATE TABLE MEDIATYPE (Name VARCHAR, MediaTypeId VARCHAR), CREATE TABLE TRACK (MediaTypeId VARCHAR)
user: 在所有音乐中，什么类型的媒体类型是最不常见的？

assistant: SELECT T1.Name FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId  =  T2.MediaTypeId GROUP BY T2.MediaTypeId ORDER BY COUNT(*) ASC LIMIT 1
Schema: CREATE TABLE ALBUM (AlbumId VARCHAR, Title VARCHAR), CREATE TABLE TRACK (AlbumID VARCHAR, AlbumId VARCHAR, UnitPrice INTEGER)
user: 显示包含单价大于1的曲目的专辑的名称和ID。

assistant: SELECT T1.Title ,  T2.AlbumID FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId  =  T2.AlbumId WHERE T2.UnitPrice  >  1 GROUP BY T2.AlbumID
Schema: CREATE TABLE ALBUM (AlbumId VARCHAR, Title VARCHAR), CREATE TABLE TRACK (AlbumID VARCHAR, AlbumId VARCHAR, UnitPrice INTEGER)
user: 包含单价大于1的歌曲的专辑的标题和ID是什么？

assistant: SELECT T1.Title ,  T2.AlbumID FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId  =  T2.AlbumId WHERE T2.UnitPrice  >  1 GROUP BY T2.AlbumID
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 摇滚流派有多少曲目？

assistant: SELECT COUNT(*) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId WHERE T1.Name  =  "摇滚"
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 计算摇滚类型的歌曲的数量。

assistant: SELECT COUNT(*) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId WHERE T1.Name  =  "摇滚"
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 属于爵士乐风格的曲目的平均单价是多少？

assistant: SELECT AVG(UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId WHERE T1.Name  =  "爵士"
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 找到爵士乐曲目的平均单价。

assistant: SELECT AVG(UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId WHERE T1.Name  =  "爵士"
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, Email VARCHAR, LastName VARCHAR)
user: 电子邮件为“luisg@embraer.com.br”的客户的名字和姓是什么？

assistant: SELECT FirstName ,  LastName FROM CUSTOMER WHERE Email  =  "luisg@embraer.com.br"
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, Email VARCHAR, LastName VARCHAR)
user: 查找电子邮件“luisg@embraer.com.br”的客户的全名。

assistant: SELECT FirstName ,  LastName FROM CUSTOMER WHERE Email  =  "luisg@embraer.com.br"
Schema: CREATE TABLE CUSTOMER (Email VARCHAR)
user: 有多少客户有电子邮件包含"gmail.com"？

assistant: SELECT COUNT(*) FROM CUSTOMER WHERE Email LIKE "qq.com"
Schema: CREATE TABLE CUSTOMER (Email VARCHAR)
user: 计算包含"gmail.com"的电子邮件的客户数量。

assistant: SELECT COUNT(*) FROM CUSTOMER WHERE Email LIKE "qq.com"
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, SupportRepId VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR, FirstName VARCHAR, LastName VARCHAR)
user: 帮助过名为“小红”的客户的员工的名字和姓氏是什么？

assistant: SELECT T2.FirstName ,  T2.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId WHERE T1.FirstName  =  "小红"
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, SupportRepId VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR, FirstName VARCHAR, LastName VARCHAR)
user: 查找帮助客户“小红”的员工的全名。

assistant: SELECT T2.FirstName ,  T2.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId WHERE T1.FirstName  =  "小红"
Schema: CREATE TABLE CUSTOMER (PostalCode VARCHAR, SupportRepId VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR, City VARCHAR)
user: 帮助住在邮政编码为“70174”的客户的员工住在哪个城市？

assistant: SELECT T2.City FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId WHERE T1.PostalCode  =  "70174"
Schema: CREATE TABLE CUSTOMER (PostalCode VARCHAR, SupportRepId VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR, City VARCHAR)
user: 找到帮助使用邮政编码“70174”的客户的雇员相对应的城市。

assistant: SELECT T2.City FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId WHERE T1.PostalCode  =  "70174"
Schema: CREATE TABLE EMPLOYEE (city VARCHAR)
user: 员工住多少个不同的城市？

assistant: SELECT COUNT(DISTINCT city) FROM EMPLOYEE
Schema: CREATE TABLE EMPLOYEE (city VARCHAR)
user: 找到员工居住的不同城市的数量。

assistant: SELECT COUNT(DISTINCT city) FROM EMPLOYEE
Schema: CREATE TABLE CUSTOMER (CustomerId VARCHAR, FirstName VARCHAR), CREATE TABLE INVOICE (CustomerId VARCHAR, InvoiceDate VARCHAR)
user: 查找与名为“卢”姓为“军”的客户相对应的所有发票日期。

assistant: SELECT T2.InvoiceDate FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T1.FirstName  =  "卢" AND LastName  =  "军"
Schema: CREATE TABLE CUSTOMER (CustomerId VARCHAR, FirstName VARCHAR), CREATE TABLE INVOICE (CustomerId VARCHAR, InvoiceDate VARCHAR)
user: 名是“卢”姓是“军”的客户的发票日期是什么？

assistant: SELECT T2.InvoiceDate FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T1.FirstName  =  "卢" AND LastName  =  "军"
Schema: CREATE TABLE CUSTOMER (CustomerId VARCHAR, LastName VARCHAR), CREATE TABLE Invoice (CustomerId VARCHAR, total INTEGER)
user: 查找所有发票总额没有大于20的客户姓氏。

assistant: SELECT LastName FROM CUSTOMER EXCEPT SELECT T1.LastName FROM CUSTOMER AS T1 JOIN Invoice AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T2.total  >  20
Schema: CREATE TABLE CUSTOMER (CustomerId VARCHAR, LastName VARCHAR), CREATE TABLE Invoice (CustomerId VARCHAR, total INTEGER)
user: 发票总额不超过20的客户的姓氏是什么？

assistant: SELECT LastName FROM CUSTOMER EXCEPT SELECT T1.LastName FROM CUSTOMER AS T1 JOIN Invoice AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T2.total  >  20
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, country VARCHAR, CustomerId VARCHAR), CREATE TABLE INVOICE (CustomerId VARCHAR)
user: 查找居住在“巴西”的有发票的所有客户的名字。

assistant: SELECT DISTINCT T1.FirstName FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T1.country  =  "巴西"
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, country VARCHAR, CustomerId VARCHAR), CREATE TABLE INVOICE (CustomerId VARCHAR)
user: 对于来自“巴西”有发票的顾客，他们有什么不同的名字？

assistant: SELECT DISTINCT T1.FirstName FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T1.country  =  "巴西"
Schema: CREATE TABLE CUSTOMER (Address VARCHAR, CustomerId VARCHAR, country VARCHAR), CREATE TABLE INVOICE (CustomerId VARCHAR)
user: 查找所有居住在“德国”有发票的客户的地址。

assistant: SELECT DISTINCT T1.Address FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T1.country  =  "德国"
Schema: CREATE TABLE CUSTOMER (Address VARCHAR, CustomerId VARCHAR, country VARCHAR), CREATE TABLE INVOICE (CustomerId VARCHAR)
user: 在“德国”居住的有发票的客户地址是什么？

assistant: SELECT DISTINCT T1.Address FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId  =  T2.CustomerId WHERE T1.country  =  "德国"
Schema: CREATE TABLE EMPLOYEE (Phone VARCHAR)
user: 列出所有员工的电话号码。

assistant: SELECT Phone FROM EMPLOYEE
Schema: CREATE TABLE EMPLOYEE (Phone VARCHAR)
user: 每个员工的电话号码是什么？

assistant: SELECT Phone FROM EMPLOYEE
Schema: CREATE TABLE MEDIATYPE (Name VARCHAR, MediaTypeId VARCHAR), CREATE TABLE TRACK (MediaTypeId VARCHAR)
user: 有多少歌是“AAC”媒体类型？

assistant: SELECT COUNT(*) FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId  =  T2.MediaTypeId WHERE T1.Name  =  "AAC"
Schema: CREATE TABLE MEDIATYPE (Name VARCHAR, MediaTypeId VARCHAR), CREATE TABLE TRACK (MediaTypeId VARCHAR)
user: 计算媒体类型为“AAC”的歌曲数。

assistant: SELECT COUNT(*) FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId  =  T2.MediaTypeId WHERE T1.Name  =  "AAC"
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 属于“拉丁”和“流行”音乐的曲目平均持续时间是几毫秒？

assistant: SELECT AVG(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId WHERE T1.Name  =  "拉丁" OR T1.Name  =  "流行"
Schema: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR), CREATE TABLE TRACK (GenreId VARCHAR)
user: 找到“拉丁”和“流行”歌曲的平均毫秒长度。

assistant: SELECT AVG(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId  =  T2.GenreId WHERE T1.Name  =  "拉丁" OR T1.Name  =  "流行"
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, SupportRepId VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR)
user: 请出示为至少10位客户服务的员工姓名和ID。

assistant: SELECT T1.FirstName ,  T1.SupportRepId FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*)  >=  10
Schema: CREATE TABLE CUSTOMER (FirstName VARCHAR, SupportRepId VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR)
user: 为10个或更多客户服务的员工的名字和支持代表ID的是什么？

assistant: SELECT T1.FirstName ,  T1.SupportRepId FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*)  >=  10
Schema: CREATE TABLE CUSTOMER (SupportRepId VARCHAR, LastName VARCHAR), CREATE TABLE EMPLOYEE (EmployeeId VARCHAR)
user: 请显示为不超过20名顾客服务的雇员的姓氏。

assistant: SELECT T1.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId  =  T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*)  <=  20