jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 找出所有是“张晋”和“甄子丹”主演的电影

assistant: SELECT t4.title FROM CAST AS t5 JOIN actor AS t1 ON t5.aid  =  t1.aid JOIN movie AS t4 ON t4.mid  =  t5.msid JOIN CAST AS t3 ON t4.mid  =  t3.msid JOIN actor AS t2 ON t3.aid  =  t2.aid WHERE t1.name  =  "张晋" AND t2.name  =  "甄子丹";
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 找出“张晋”和“甄子丹”是主要角色的所有电影

assistant: SELECT t4.title FROM CAST AS t5 JOIN actor AS t1 ON t5.aid  =  t1.aid JOIN movie AS t4 ON t4.mid  =  t5.msid JOIN CAST AS t3 ON t4.mid  =  t3.msid JOIN actor AS t2 ON t3.aid  =  t2.aid WHERE t1.name  =  "张晋" AND t2.name  =  "甄子丹";
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 找出所有的“张晋”和“甄子丹”都是主要角色的电影

assistant: SELECT t4.title FROM CAST AS t5 JOIN actor AS t1 ON t5.aid  =  t1.aid JOIN movie AS t4 ON t4.mid  =  t5.msid JOIN CAST AS t3 ON t4.mid  =  t3.msid JOIN actor AS t2 ON t3.aid  =  t2.aid WHERE t1.name  =  "张晋" AND t2.name  =  "甄子丹";
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 找出“甄子丹”和“张晋”是主要角色的所有电影

assistant: SELECT t4.title FROM CAST AS t5 JOIN actor AS t1 ON t5.aid  =  t1.aid JOIN movie AS t4 ON t4.mid  =  t5.msid JOIN CAST AS t3 ON t4.mid  =  t3.msid JOIN actor AS t2 ON t3.aid  =  t2.aid WHERE t1.name  =  "张晋" AND t2.name  =  "甄子丹";
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (mid VARCHAR)
user: 找出所有和“周润发”出演同一部电影的演员

assistant: SELECT t1.name FROM CAST AS t4 JOIN actor AS t1 ON t4.aid  =  t1.aid JOIN movie AS t5 ON t5.mid  =  t4.msid JOIN CAST AS t3 ON t5.mid  =  t3.msid JOIN actor AS t2 ON t3.aid  =  t2.aid WHERE t2.name  =  "周润发";
Schema: CREATE TABLE director (did VARCHAR), CREATE TABLE directed_by (did VARCHAR, msid VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 什么电影和电影“上甘岭”有同样的导演？

assistant: SELECT t3.title FROM director AS t5 JOIN directed_by AS t2 ON t5.did  =  t2.did JOIN directed_by AS t1 ON t5.did  =  t1.did JOIN movie AS t4 ON t4.mid  =  t2.msid JOIN movie AS t3 ON t3.mid  =  t1.msid WHERE t4.title  =  "上甘岭";
Schema: CREATE TABLE genre (genre VARCHAR, gid VARCHAR), CREATE TABLE classification (msid VARCHAR, gid VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 找出被分类为最多数量的流派的电影

assistant: SELECT t3.title FROM genre AS t2 JOIN classification AS t1 ON t2.gid  =  t1.gid JOIN movie AS t3 ON t3.mid  =  t1.msid GROUP BY t3.title ORDER BY COUNT ( DISTINCT t2.genre  ) DESC LIMIT 1;
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR, nationality VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR)
user: 哪部电影“中国”演员最多？

assistant: SELECT t2.title FROM CAST AS t3 JOIN actor AS t1 ON t3.aid  =  t1.aid JOIN movie AS t2 ON t2.mid  =  t3.msid WHERE t1.nationality  =  "中国" GROUP BY t2.title ORDER BY COUNT ( DISTINCT t1.name  ) DESC LIMIT 1;
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (mid VARCHAR, release_year VARCHAR), CREATE TABLE directed_by (did VARCHAR, msid VARCHAR), CREATE TABLE director (name VARCHAR, did VARCHAR)
user: 找出在“李安”的最新电影中出演的演员

assistant: SELECT t1.name FROM CAST AS t4 JOIN actor AS t1 ON t4.aid  =  t1.aid JOIN movie AS t5 ON t5.mid  =  t4.msid JOIN directed_by AS t2 ON t5.mid  =  t2.msid JOIN director AS t3 ON t3.did  =  t2.did WHERE t3.name  =  "李安" ORDER BY t5.release_year DESC LIMIT 1;
Schema: CREATE TABLE director (name VARCHAR, did VARCHAR), CREATE TABLE directed_by (did VARCHAR, msid VARCHAR), CREATE TABLE movie (title VARCHAR, budget VARCHAR, mid VARCHAR, release_year VARCHAR)
user: 通过“李安”导演的最新电影的名字和预算

assistant: SELECT t3.budget  ,  t3.title FROM director AS t2 JOIN directed_by AS t1 ON t2.did  =  t1.did JOIN movie AS t3 ON t3.mid  =  t1.msid WHERE t2.name  =  "李安" ORDER BY t3.release_year DESC LIMIT 1;
Schema: CREATE TABLE director (name VARCHAR, did VARCHAR), CREATE TABLE directed_by (did VARCHAR, msid VARCHAR), CREATE TABLE movie (title VARCHAR, mid VARCHAR, release_year VARCHAR)
user: “姜文”的最新电影是什么？

assistant: SELECT t3.title FROM director AS t2 JOIN directed_by AS t1 ON t2.did  =  t1.did JOIN movie AS t3 ON t3.mid  =  t1.msid WHERE t2.name  =  "姜文" ORDER BY t3.release_year DESC LIMIT 1;
Schema: CREATE TABLE director (name VARCHAR, did VARCHAR), CREATE TABLE directed_by (did VARCHAR, msid VARCHAR), CREATE TABLE movie (mid VARCHAR), CREATE TABLE made_by (pid VARCHAR, msid VARCHAR), CREATE TABLE producer (name VARCHAR, pid VARCHAR)
user: 哪个制片人的导演数量最多？

assistant: SELECT t1.name FROM director AS t3 JOIN directed_by AS t2 ON t3.did  =  t2.did JOIN movie AS t4 ON t4.mid  =  t2.msid JOIN made_by AS t5 ON t4.mid  =  t5.msid JOIN producer AS t1 ON t1.pid  =  t5.pid GROUP BY t1.name ORDER BY COUNT ( DISTINCT t3.name  ) DESC LIMIT 1;
Schema: CREATE TABLE CAST (aid VARCHAR, msid VARCHAR), CREATE TABLE actor (aid VARCHAR, name VARCHAR), CREATE TABLE movie (mid VARCHAR, release_year VARCHAR)
user: 找出“黄渤”表演最新的电影

assistant: SELECT t1.name FROM CAST AS t2 JOIN actor AS t1 ON t2.aid  =  t1.aid JOIN movie AS t3 ON t3.mid  =  t2.msid WHERE t1.name  =  "黄渤" ORDER BY t3.release_year DESC LIMIT 1;
Schema: CREATE TABLE restaurant (name VARCHAR, id VARCHAR), CREATE TABLE LOCATION (city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”有多少“日本料理”？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.name  =  "日本料理";
Schema: CREATE TABLE restaurant (food_type VARCHAR, city_name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”有多少家“四川”餐馆？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.region  =  "厦门" AND t1.food_type  =  "四川";
Schema: CREATE TABLE restaurant (food_type VARCHAR, city_name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”有多少吃“四川”菜的地方？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.region  =  "厦门" AND t1.food_type  =  "四川";
Schema: CREATE TABLE restaurant (food_type VARCHAR, city_name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”有多少饭店做“四川”菜？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.region  =  "厦门" AND t1.food_type  =  "四川";
Schema: CREATE TABLE restaurant (food_type VARCHAR, city_name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”有多少吃“四川”餐的地方？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.region  =  "厦门" AND t1.food_type  =  "四川";
Schema: CREATE TABLE restaurant (city_name VARCHAR, name VARCHAR), CREATE TABLE geographic (city_name VARCHAR, county VARCHAR)
user: “洛阳”有多少种“四川”菜肴？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.county  =  "洛阳" AND t1.name  =  "四川";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR)
user: “四川”菜在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t1.name  =  "四川";
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”最好的“淮南”餐馆是哪家？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”最好的“淮南”餐是什么？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“深圳”吃“淮南”菜最好的地方是什么？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”最好的“淮南”餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”最好的“淮南”菜在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“深圳”最好吃的“淮南”菜

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”评价最高的“淮南”餐馆在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 给出“深圳”吃“淮南”菜最好的餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”口碑最好的“淮南”餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”最好的“淮南”餐馆是哪一家？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”最好的“淮南”餐馆的地址在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" AND t1.rating  =  ( SELECT MAX ( t1.rating ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.food_type  =  "淮南" );
Schema: CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR)
user: “丹尼尔”餐厅在“厦门”哪里？

assistant: SELECT t3.house_number  ,  t1.name FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name JOIN LOCATION AS t3 ON t1.id  =  t3.restaurant_id WHERE t2.region  =  "厦门" AND t1.name  =  "丹尼尔";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: “鼓浪屿”“龙头路”有什么好餐馆？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "鼓浪屿" AND t2.street_name  =  "龙头路" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: 该出地址是“鼓浪屿”“龙头路”的好口碑餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "鼓浪屿" AND t2.street_name  =  "龙头路" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: 给出一家在“鼓浪屿”“龙头路”的好吃的餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "鼓浪屿" AND t2.street_name  =  "龙头路" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: “鼓浪屿”“龙头路”的好评餐馆是什么？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "鼓浪屿" AND t2.street_name  =  "龙头路" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 我们在哪里可以找出在“泉州”的餐馆？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 给出在“泉州”的餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 我们可以找的“泉州”的餐馆在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 位于“泉州”的餐馆在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 一些在“泉州”的餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州";
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR)
user: 一些“淮南”菜出名的餐馆好吗？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t1.food_type  =  "淮南" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR)
user: 那些餐馆“淮南”菜好吃？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t1.food_type  =  "淮南" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR), CREATE TABLE LOCATION (city_name VARCHAR, restaurant_id VARCHAR)
user: 在“苏州”有多少地方吃“淮南”菜？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "苏州" AND t1.food_type  =  "淮南";
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR), CREATE TABLE LOCATION (city_name VARCHAR, restaurant_id VARCHAR)
user: “苏州”有多少家“淮南”餐馆？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "苏州" AND t1.food_type  =  "淮南";
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR), CREATE TABLE LOCATION (city_name VARCHAR, restaurant_id VARCHAR)
user: 在“苏州”有多少做“淮南”菜的餐厅？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "苏州" AND t1.food_type  =  "淮南";
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR), CREATE TABLE LOCATION (city_name VARCHAR, restaurant_id VARCHAR)
user: “苏州”有多少家吃“淮南”菜的餐厅？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "苏州" AND t1.food_type  =  "淮南";
Schema: CREATE TABLE restaurant (food_type VARCHAR, city_name VARCHAR), CREATE TABLE geographic (city_name VARCHAR, county VARCHAR)
user: “昆山”有多少“鲁”餐厅？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.county  =  "昆山" AND t1.food_type  =  "鲁";
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”哪里可以吃“淮南”菜？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "淮南";
Schema: CREATE TABLE restaurant (city_name VARCHAR, name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”有多少“海鲜”餐厅？

assistant: SELECT COUNT ( * ) FROM restaurant AS t1 JOIN geographic AS t2 ON t1.city_name  =  t2.city_name WHERE t2.region  =  "厦门" AND t1.name  =  "海鲜";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“泉州”一家好餐馆？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“泉州”有什么好的餐馆？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “泉州”的好餐馆是什么？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 能一些在“泉州”的好饭店

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "泉州" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: 在“深圳”“福田”哪里有一家好的“东北”餐厅？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t2.street_name  =  "福田" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: “深圳”的“福田”哪里有好的“东北”菜？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t2.street_name  =  "福田" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: 在“深圳”“福田”好的“东北”餐厅在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t2.street_name  =  "福田" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: 在“深圳”“福田”有哪些吃“东北”菜的好地方？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t2.street_name  =  "福田" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR, street_name VARCHAR)
user: 一个关于“深圳”“福田”的“东北”餐厅好吗

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t2.street_name  =  "福田" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;