jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE Reservations (Rate VARCHAR, Room VARCHAR, CheckOut VARCHAR, CheckIn VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 返回房价最高的房间的名称、房价、入住日期和退房日期。

assistant: SELECT T2.roomName ,  T1.Rate ,  T1.CheckIn ,  T1.CheckOut FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T1.Room ORDER BY T1.Rate DESC LIMIT 1;
Schema: CREATE TABLE Reservations (FirstName VARCHAR, Adults VARCHAR, CheckIn VARCHAR, LastName VARCHAR)
user: “康” “运杰”在2010年10月23日登记入住的房间内有多少成年人？

assistant: SELECT Adults FROM Reservations WHERE CheckIn  =  "2010-10-23" AND FirstName  =  "康" AND LastName  =  "运杰";
Schema: CREATE TABLE Reservations (FirstName VARCHAR, Adults VARCHAR, CheckIn VARCHAR, LastName VARCHAR)
user: 查找由“康” “运杰”于2010年10月23日预订和登记的房间的成人数量。

assistant: SELECT Adults FROM Reservations WHERE CheckIn  =  "2010-10-23" AND FirstName  =  "康" AND LastName  =  "运杰";
Schema: CREATE TABLE Reservations (FirstName VARCHAR, Kids VARCHAR, CheckIn VARCHAR, LastName VARCHAR)
user: 有多少孩子待在2010年9月21日“田” “智”入住的房间里？

assistant: SELECT Kids FROM Reservations WHERE CheckIn  =  "2010-09-21" AND FirstName  =  "田" AND LastName  =  "智";
Schema: CREATE TABLE Reservations (FirstName VARCHAR, Kids VARCHAR, CheckIn VARCHAR, LastName VARCHAR)
user: 返回由“田” “智”于2010年9月21日预订并登记入住的房间的孩子数量。

assistant: SELECT Kids FROM Reservations WHERE CheckIn  =  "2010-09-21" AND FirstName  =  "田" AND LastName  =  "智";
Schema: CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR)
user: 那里有多少张“大床”？

assistant: SELECT sum(beds) FROM Rooms WHERE bedtype  =  '大床';
Schema: CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR)
user: 找到可用的“大床”的总数。

assistant: SELECT sum(beds) FROM Rooms WHERE bedtype  =  '大床';
Schema: CREATE TABLE Rooms (basePrice VARCHAR, decor VARCHAR, bedtype VARCHAR, roomName VARCHAR)
user: 按价格排序列出有“大床”的房间的名称和装饰。

assistant: SELECT roomName ,  decor FROM Rooms WHERE bedtype  =  '大床' ORDER BY basePrice;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, decor VARCHAR, bedtype VARCHAR, roomName VARCHAR)
user: 按价格排序排列的有一张“大床”的房间的名称和装饰是什么。

assistant: SELECT roomName ,  decor FROM Rooms WHERE bedtype  =  '大床' ORDER BY basePrice;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, roomName VARCHAR)
user: 哪个房间的底价最便宜？列出房间的名称和底价。

assistant: SELECT roomName ,  basePrice FROM Rooms ORDER BY basePrice ASC LIMIT 1;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, roomName VARCHAR)
user: 最低底价的房间名称和底价是多少？

assistant: SELECT roomName ,  basePrice FROM Rooms ORDER BY basePrice ASC LIMIT 1;
Schema: CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR)
user: “北欧风格”房间的装饰是什么？

assistant: SELECT decor FROM Rooms WHERE roomName  =  "北欧风格";
Schema: CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR)
user: 返回房间名为“北欧风格”的装饰。

assistant: SELECT decor FROM Rooms WHERE roomName  =  "北欧风格";
Schema: CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER)
user: 不同床位的平均底价是多少？列出床位类型和平均底价。

assistant: SELECT bedType ,  avg(basePrice) FROM Rooms GROUP BY bedType;
Schema: CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER)
user: 对于每一床类型，找出不同床类型对应的平均底价。

assistant: SELECT bedType ,  avg(basePrice) FROM Rooms GROUP BY bedType;
Schema: CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR)
user: 能住在这家旅店的现代风格客房的总人数是多少？

assistant: SELECT sum(maxOccupancy) FROM Rooms WHERE decor  =  '现代化';
Schema: CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR)
user: 总共有多少人能住在这家旅店的现代风格房间里？

assistant: SELECT sum(maxOccupancy) FROM Rooms WHERE decor  =  '现代化';
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR)
user: 什么样的装饰预订量最少？

assistant: SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T2.decor ORDER BY count(T2.decor) ASC LIMIT 1;
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR)
user: 预定量最少的装饰是什么？

assistant: SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T2.decor ORDER BY count(T2.decor) ASC LIMIT 1;
Schema: CREATE TABLE Reservations (Adults VARCHAR, Room VARCHAR, Kids VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR)
user: 列出房间人的数量达到最大容量的次数。人的数量包括成年人和孩子。

assistant: SELECT count(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId WHERE T2.maxOccupancy  =  T1.Adults + T1.Kids;
Schema: CREATE TABLE Reservations (Adults VARCHAR, Room VARCHAR, Kids VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR)
user: 住在一个房间里的成年人和孩子的数量达到房间最大容量的次数是多少？

assistant: SELECT count(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId WHERE T2.maxOccupancy  =  T1.Adults + T1.Kids;
Schema: CREATE TABLE Reservations (firstname VARCHAR, Rate VARCHAR, lastname VARCHAR, Room VARCHAR), CREATE TABLE Rooms (basePrice VARCHAR, RoomId VARCHAR)
user: 找出支付高于房间底价的人的名字和姓氏。

assistant: SELECT T1.firstname ,  T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId WHERE T1.Rate - T2.basePrice  >  0
Schema: CREATE TABLE Reservations (firstname VARCHAR, Rate VARCHAR, lastname VARCHAR, Room VARCHAR), CREATE TABLE Rooms (basePrice VARCHAR, RoomId VARCHAR)
user: 支付高于房间底价的人的名字和姓氏是什么？

assistant: SELECT T1.firstname ,  T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId WHERE T1.Rate - T2.basePrice  >  0
Schema: CREATE TABLE Rooms (Id VARCHAR)
user: 有多少房间？

assistant: SELECT count(*) FROM Rooms;
Schema: CREATE TABLE Rooms (Id VARCHAR)
user: 这家旅店的房间总数是多少？

assistant: SELECT count(*) FROM Rooms;
Schema: CREATE TABLE Rooms (bedType VARCHAR)
user: 找一张有“大床”的房间。

assistant: SELECT count(*) FROM Rooms WHERE bedType  =  "大床";
Schema: CREATE TABLE Rooms (bedType VARCHAR)
user: 有多少个房间有“大床”国王床？

assistant: SELECT count(*) FROM Rooms WHERE bedType  =  "大床";
Schema: CREATE TABLE Rooms (bedType VARCHAR)
user: 找出每种床类型的房间数。

assistant: SELECT bedType ,  count(*) FROM Rooms GROUP BY bedType;
Schema: CREATE TABLE Rooms (bedType VARCHAR)
user: 每种床类型的房间数是多少？

assistant: SELECT bedType ,  count(*) FROM Rooms GROUP BY bedType;
Schema: CREATE TABLE Rooms (maxOccupancy VARCHAR, roomName VARCHAR)
user: 找出最大容量房间的名称。

assistant: SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1;
Schema: CREATE TABLE Rooms (maxOccupancy VARCHAR, roomName VARCHAR)
user: 能容纳人数最多的房间叫什么名字？

assistant: SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, RoomId VARCHAR, roomName VARCHAR)
user: 找到底价最贵的房间的ID和房间名称。

assistant: SELECT RoomId ,  roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, RoomId VARCHAR, roomName VARCHAR)
user: 哪一个房间的底价最高？

assistant: SELECT RoomId ,  roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1;
Schema: CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR, roomName VARCHAR)
user: 列出所有传统类型房间的床的类型和名称。

assistant: SELECT roomName ,  bedType FROM Rooms WHERE decor = "传统";
Schema: CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR, roomName VARCHAR)
user: 有传统类型装饰的所有房间的床的类型和名称是什么？

assistant: SELECT roomName ,  bedType FROM Rooms WHERE decor = "传统";
Schema: CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR)
user: 找到每一个装饰类型有“大床”的房间数。

assistant: SELECT decor ,  count(*) FROM Rooms WHERE bedType = "大床" GROUP BY decor;
Schema: CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR)
user: 有多少个房间有“大床”？报告每个装饰类型的这样房间数量。

assistant: SELECT decor ,  count(*) FROM Rooms WHERE bedType = "大床" GROUP BY decor;
Schema: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER)
user: 找出不同装修风格的房间平均价格和最低价格。

assistant: SELECT decor , avg(basePrice) ,  min(basePrice) FROM Rooms GROUP BY decor;
Schema: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER)
user: 每个不同装修风格的房间平均最低价格是多少？

assistant: SELECT decor , avg(basePrice) ,  min(basePrice) FROM Rooms GROUP BY decor;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, roomName VARCHAR)
user: 列出按其价格排序的所有房间名称。

assistant: SELECT roomName FROM Rooms ORDER BY basePrice;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, roomName VARCHAR)
user: 按价格排序所有房间的名称。

assistant: SELECT roomName FROM Rooms ORDER BY basePrice;
Schema: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER)
user: 找到不同装修风格且价格超过120的房间数量。

assistant: SELECT decor , count(*) FROM Rooms WHERE basePrice  >  120 GROUP BY decor;
Schema: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER)
user: 每一种不同的装修风格，有多少房间的价格超过120？

assistant: SELECT decor , count(*) FROM Rooms WHERE basePrice  >  120 GROUP BY decor;
Schema: CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER)
user: 对于每个床类型，找到平均房间价格。

assistant: SELECT bedType ,  avg(basePrice) FROM Rooms GROUP BY bedType;
Schema: CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER)
user: 每种不同床类型的房间的平均底价是多少？

assistant: SELECT bedType ,  avg(basePrice) FROM Rooms GROUP BY bedType;
Schema: CREATE TABLE Rooms (bedType VARCHAR, roomName VARCHAR)
user: 列出有“大床”或“双人”床的房间名称。

assistant: SELECT roomName FROM Rooms WHERE bedType  =  "大床" OR bedType  =  "双人";
Schema: CREATE TABLE Rooms (bedType VARCHAR, roomName VARCHAR)
user: 有“大床”或“双人”床的房间的名称是什么？

assistant: SELECT roomName FROM Rooms WHERE bedType  =  "大床" OR bedType  =  "双人";
Schema: CREATE TABLE Rooms (bedType VARCHAR)
user: 有多少种不同的床？

assistant: SELECT count(DISTINCT bedType) FROM Rooms;
Schema: CREATE TABLE Rooms (bedType VARCHAR)
user: 在旅店找出不同床类型的数量。

assistant: SELECT count(DISTINCT bedType) FROM Rooms;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, RoomId VARCHAR, roomName VARCHAR)
user: 找到最贵的3个房间的名字和ID。

assistant: SELECT RoomId ,  roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3;
Schema: CREATE TABLE Rooms (basePrice VARCHAR, RoomId VARCHAR, roomName VARCHAR)
user: 三个最高价房间的名字和ID是什么？

assistant: SELECT RoomId ,  roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3;
Schema: CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER)
user: 查找价格高于平均价格的房间名称。

assistant: SELECT roomName FROM Rooms WHERE basePrice  >  ( SELECT avg(basePrice) FROM Rooms );
Schema: CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER)
user: 哪些房间的价格比平均价格高？

assistant: SELECT roomName FROM Rooms WHERE basePrice  >  ( SELECT avg(basePrice) FROM Rooms );
Schema: CREATE TABLE rooms (room VARCHAR, roomid VARCHAR), CREATE TABLE reservations (room VARCHAR, roomid VARCHAR)
user: 找出没有预订的房间的数量。

assistant: SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations)
Schema: CREATE TABLE rooms (room VARCHAR, roomid VARCHAR), CREATE TABLE reservations (room VARCHAR, roomid VARCHAR)
user: 还有多少房间没有预订？

assistant: SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations)
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 返回每个房间的名字和被预定的次数。

assistant: SELECT T2.roomName ,  count(*) ,  T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T1.Room
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 对于每个房间，找到它的名字和预订的次数。

assistant: SELECT T2.roomName ,  count(*) ,  T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T1.Room
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 查找已预订超过60次的房间名称。

assistant: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T1.Room HAVING count(*)  >  60
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 预订次数超过60的房间名称是什么？

assistant: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId GROUP BY T1.Room HAVING count(*)  >  60
Schema: CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER)
user: 找到底价在120和150之间的房间名称。

assistant: SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150
Schema: CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER)
user: 哪些房间的价格在120到150之间？返回房间的名字。

assistant: SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 找出客户名包括'浩'字的客户预定的房间的名称。

assistant: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId WHERE firstname LIKE '浩'
Schema: CREATE TABLE Reservations (Room VARCHAR), CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR)
user: 客户名包括“浩”字的客户预订的房间叫什么名字？

assistant: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room  =  T2.RoomId WHERE firstname LIKE '浩'
Schema: CREATE TABLE Customer_Master_Index (cmi_details VARCHAR, master_customer_id VARCHAR), CREATE TABLE CMI_Cross_References (master_customer_id VARCHAR, source_system_code VARCHAR)
user: 交叉参考码的“税收”的cmi的详细信息是什么？

assistant: SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id  =  T2.master_customer_id WHERE T2.source_system_code  =  '税收'
Schema: CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR), CREATE TABLE Council_Tax (cmi_cross_ref_id VARCHAR)
user: 与至少一个理事会税务条目相关的cmi交叉参考ID是什么？列出交叉引用ID和源系统代码。

assistant: SELECT T1.cmi_cross_ref_id ,  T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id  =  T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING count(*)  >=  1
Schema: CREATE TABLE Business_Rates (cmi_cross_ref_id VARCHAR), CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR)
user: 与每个CMI交叉引用相关的业务费率有多少？列出交叉引用ID、主客户ID和数量。

assistant: SELECT T2.cmi_cross_ref_id ,  T2.master_customer_id ,  count(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id  =  T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id
Schema: CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR), CREATE TABLE Benefits_Overpayments (cmi_cross_ref_id VARCHAR, council_tax_id VARCHAR)
user: 什么是与利润和超额支付有关的税源系统代码？按利润ID排序列出代码和利润ID，。

assistant: SELECT T1.source_system_code ,  T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id  =  T2.cmi_cross_ref_id ORDER BY T2.council_tax_id
Schema: CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR, source_system_code VARCHAR), CREATE TABLE Parking_Fines (cmi_cross_ref_id VARCHAR, council_tax_id VARCHAR)
user: 与每个停车罚款ID相关税的税源系统代码和主客户ID是什么？

assistant: SELECT T1.source_system_code ,  T1.master_customer_id ,  T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id  =  T2.cmi_cross_ref_id
Schema: CREATE TABLE Rent_Arrears (cmi_cross_ref_id VARCHAR, council_tax_id VARCHAR), CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR), CREATE TABLE Customer_Master_Index (master_customer_id VARCHAR, cmi_details VARCHAR)
user: 客户主指数的详细信息不是与“高端”相关的租金拖欠税id是什么？

assistant: SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id  =  T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id  =  T2.master_customer_id WHERE T3.cmi_details != '高端'
Schema: CREATE TABLE Electoral_Register (electoral_register_id VARCHAR, cmi_cross_ref_id VARCHAR), CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR)
user: 有交叉参考源代码“选举”或“税收”的选举登记处的登记ID是什么？

assistant: SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id  =  T2.cmi_cross_ref_id WHERE T2.source_system_code  =  '选举' OR T2.source_system_code  =  '税收'
Schema: CREATE TABLE CMI_cross_references (source_system_code VARCHAR)
user: CMI交叉引用有多少种不同的源代码？

assistant: SELECT count(DISTINCT source_system_code) FROM CMI_cross_references
Schema: CREATE TABLE customer_master_index (cmi_details VARCHAR)
user: 按详细信息按降序排序列出有关客户主索引的所有信息。

assistant: SELECT * FROM customer_master_index ORDER BY cmi_details DESC
Schema: CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR, council_tax_id VARCHAR)
user: 列出所有停车罚款的市政税ID和相关的cmi。

assistant: SELECT council_tax_id ,  cmi_cross_ref_id FROM parking_fines
Schema: CREATE TABLE rent_arrears (Id VARCHAR)
user: 征收拖欠的市政税有多少？

assistant: SELECT count(*) FROM rent_arrears
Schema: CREATE TABLE customer_master_index (master_customer_id VARCHAR, cmi_details VARCHAR), CREATE TABLE cmi_cross_references (master_customer_id VARCHAR, source_system_code VARCHAR)
user: 与主客户详细信息“普通”相关的不同的交叉参考源系统代码是什么？

assistant: SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id  =  T2.master_customer_id WHERE T1.cmi_details  =  '普通'
Schema: CREATE TABLE cmi_cross_references (cmi_cross_ref_id VARCHAR), CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR)
user: 哪一个CMI交叉参考ID与任何停车税无关？

assistant: SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines
Schema: CREATE TABLE cmi_cross_references (source_system_code VARCHAR)
user: 哪种不同的源代码包含子字符串'en'？

assistant: SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE 'en'
Schema: CREATE TABLE party (Id VARCHAR)
user: 有多少个聚会？

assistant: SELECT count(*) FROM party
Schema: CREATE TABLE party (Id VARCHAR)
user: 统计聚会的数目。

assistant: SELECT count(*) FROM party
Schema: CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR)
user: 以主持人数量升序列出各个聚会的主题。

assistant: SELECT Party_Theme FROM party ORDER BY Number_of_hosts ASC
Schema: CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR)
user: 由主持人数量升序排序的每个聚会的主题是什么？

assistant: SELECT Party_Theme FROM party ORDER BY Number_of_hosts ASC
Schema: CREATE TABLE party (LOCATION VARCHAR, Party_Theme VARCHAR)
user: 聚会的主题和地点是什么？

assistant: SELECT Party_Theme ,  LOCATION FROM party
Schema: CREATE TABLE party (LOCATION VARCHAR, Party_Theme VARCHAR)
user: 给出每个聚会的主题和地点。

assistant: SELECT Party_Theme ,  LOCATION FROM party
Schema: CREATE TABLE party (Last_year VARCHAR, First_year VARCHAR, Party_Theme VARCHAR)
user: 列出已“春季”或“科技”为主题的聚会第一年和最后一年。

assistant: SELECT First_year ,  Last_year FROM party WHERE Party_Theme  =  "春季" OR Party_Theme  =  "科技"
Schema: CREATE TABLE party (Last_year VARCHAR, First_year VARCHAR, Party_Theme VARCHAR)
user: 主题为“春季”或“科技”的聚会的第一年和最后一年是什么？

assistant: SELECT First_year ,  Last_year FROM party WHERE Party_Theme  =  "春季" OR Party_Theme  =  "科技"
Schema: CREATE TABLE party (Number_of_hosts INTEGER)
user: 每个聚会的主持人的平均人数是多少？

assistant: SELECT avg(Number_of_hosts) FROM party
Schema: CREATE TABLE party (Number_of_hosts INTEGER)
user: 计算每个聚会的主持人的平均数量。

assistant: SELECT avg(Number_of_hosts) FROM party
Schema: CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR)
user: 有最多主持人的聚会在什么地方？

assistant: SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1
Schema: CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR)
user: 哪个聚会的主持人数最多？给出聚会的地点。

assistant: SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1
Schema: CREATE TABLE HOST (Nationality VARCHAR)
user: 显示不同的国籍，以及每个国家的主持人人数。

assistant: SELECT Nationality ,  COUNT(*) FROM HOST GROUP BY Nationality
Schema: CREATE TABLE HOST (Nationality VARCHAR)
user: 每个国家有多少主持人？列出国籍和对应数量。

assistant: SELECT Nationality ,  COUNT(*) FROM HOST GROUP BY Nationality
Schema: CREATE TABLE HOST (Nationality VARCHAR)
user: 显示主持人最常见的国籍。

assistant: SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE HOST (Nationality VARCHAR)
user: 哪个国家拥有最多数量的主持人？

assistant: SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER)
user: 展示拥有45岁以上和35岁以下的主持人的国家。

assistant: SELECT Nationality FROM HOST WHERE Age  >  45 INTERSECT SELECT Nationality FROM HOST WHERE Age  <  35
Schema: CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER)
user: 哪些国家有年龄在45岁以上的主持人和35岁以下的主持人？

assistant: SELECT Nationality FROM HOST WHERE Age  >  45 INTERSECT SELECT Nationality FROM HOST WHERE Age  <  35
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Name VARCHAR), CREATE TABLE party (Party_ID VARCHAR, Party_Theme VARCHAR)
user: 显示聚会的主题和主持人的名字。

assistant: SELECT T3.Party_Theme ,  T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Name VARCHAR), CREATE TABLE party (Party_ID VARCHAR, Party_Theme VARCHAR)
user: 对于每一聚会，返回它的主题的名称和对应的主持人的名字。

assistant: SELECT T3.Party_Theme ,  T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Age VARCHAR, Name VARCHAR), CREATE TABLE party (Party_ID VARCHAR, Location VARCHAR)
user: 按照主持人年龄的升序显示聚会的位置和聚会主持人的名称。

assistant: SELECT T3.Location ,  T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID ORDER BY T2.Age
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Age VARCHAR, Name VARCHAR), CREATE TABLE party (Party_ID VARCHAR, Location VARCHAR)
user: 对于每一聚会，找出它的位置和主持人的名称。将结果按主持人年龄的升序排序。

assistant: SELECT T3.Location ,  T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID ORDER BY T2.Age
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER), CREATE TABLE party (Party_ID VARCHAR, Location VARCHAR)
user: 显示主持人年龄大于50的聚会的位置。

assistant: SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID WHERE T2.Age  >  50
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER), CREATE TABLE party (Party_ID VARCHAR, Location VARCHAR)
user: 哪些聚会有的年龄超过50岁的主持人？给出聚会的地点。

assistant: SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID WHERE T2.Age  >  50
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Name VARCHAR), CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER)
user: 显示主持人数大于20的聚会的主持人名字。

assistant: SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID WHERE T3.Number_of_hosts  >  20
Schema: CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR), CREATE TABLE HOST (Host_ID VARCHAR, Name VARCHAR), CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER)
user: 哪些聚会拥有超过20个主持人？给我这些聚会的名字。

assistant: SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID  =  T2.Host_ID JOIN party AS T3 ON T1.Party_ID  =  T3.Party_ID WHERE T3.Number_of_hosts  >  20
Schema: CREATE TABLE HOST (Nationality VARCHAR, Name VARCHAR, Age VARCHAR)
user: 显示最老主持人的名字和国籍。

assistant: SELECT Name ,  Nationality FROM HOST ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE HOST (Nationality VARCHAR, Name VARCHAR, Age VARCHAR)
user: 最高年龄的主持人的姓名和国籍是什么？

assistant: SELECT Name ,  Nationality FROM HOST ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE HOST (Host_ID VARCHAR, Name VARCHAR), CREATE TABLE party_host (Host_ID VARCHAR, Name VARCHAR)
user: 列出在我们的记录中没有作为任何聚会的主持人的名字。

assistant: SELECT Name FROM HOST WHERE Host_ID NOT IN (SELECT Host_ID FROM party_host)
Schema: CREATE TABLE HOST (Host_ID VARCHAR, Name VARCHAR), CREATE TABLE party_host (Host_ID VARCHAR, Name VARCHAR)
user: 在我们的记录中没有主办任何聚会的主持人的名字是什么？

assistant: SELECT Name FROM HOST WHERE Host_ID NOT IN (SELECT Host_ID FROM party_host)
Schema: CREATE TABLE region (Id VARCHAR)
user: 计算地区的数量。

assistant: SELECT count(*) FROM region
Schema: CREATE TABLE region (region_name VARCHAR, region_code VARCHAR)
user: 显示按代码排序的所有地区代码和地区名称。

assistant: SELECT region_code ,  region_name FROM region ORDER BY region_code
Schema: CREATE TABLE region (region_name VARCHAR, region_code VARCHAR)
user: 按代码排序所有地区的代码和名称是什么？

assistant: SELECT region_code ,  region_name FROM region ORDER BY region_code
Schema: CREATE TABLE region (region_name VARCHAR)
user: 按字母顺序列出所有区域名称。

assistant: SELECT region_name FROM region ORDER BY region_name