jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE payment (staff_id VARCHAR)
user: 给出处理付款最少的工作人员的全名和工作人员ID。

assistant: SELECT T1.first_name ,  T1.last_name ,  T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE film (title VARCHAR, language_id VARCHAR), CREATE TABLE LANGUAGE (name VARCHAR, language_id VARCHAR)
user: 电影“暗战”使用的是哪种语言？列出语言名称。

assistant: SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id  =  T2.language_id WHERE T1.title  =  '暗战'
Schema: CREATE TABLE film (title VARCHAR, language_id VARCHAR), CREATE TABLE LANGUAGE (name VARCHAR, language_id VARCHAR)
user: 电影“暗战”中使用的语言是什么？

assistant: SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id  =  T2.language_id WHERE T1.title  =  '暗战'
Schema: CREATE TABLE store (Id VARCHAR)
user: 有多少商店？

assistant: SELECT count(*) FROM store
Schema: CREATE TABLE store (Id VARCHAR)
user: 统计商店的数量。

assistant: SELECT count(*) FROM store
Schema: CREATE TABLE film (rating VARCHAR)
user: 一共有多少种不同的评级？

assistant: SELECT count(DISTINCT rating) FROM film
Schema: CREATE TABLE film (rating VARCHAR)
user: 计算电影的不同评级的数量。

assistant: SELECT count(DISTINCT rating) FROM film
Schema: CREATE TABLE film (title VARCHAR, special_features VARCHAR)
user: 哪些电影有“删除场景”作为特色的一部分？

assistant: SELECT title FROM film WHERE special_features LIKE '删除场景'
Schema: CREATE TABLE film (title VARCHAR, special_features VARCHAR)
user: 返回包含“删除场景”作为特色的电影的标题。

assistant: SELECT title FROM film WHERE special_features LIKE '删除场景'
Schema: CREATE TABLE inventory (store_id VARCHAR)
user: 商店1的库存中有多少种物品？

assistant: SELECT count(*) FROM inventory WHERE store_id  =  1
Schema: CREATE TABLE inventory (store_id VARCHAR)
user: 统计商店1库存物品的数量。

assistant: SELECT count(*) FROM inventory WHERE store_id  =  1
Schema: CREATE TABLE payment (payment_date VARCHAR)
user: 第一次付款是什么时候发生的？

assistant: SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
Schema: CREATE TABLE payment (payment_date VARCHAR)
user: 最早付款的日期是什么？

assistant: SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
Schema: CREATE TABLE customer (email VARCHAR, address_id VARCHAR, first_name VARCHAR), CREATE TABLE address (address VARCHAR, address_id VARCHAR)
user: 名为“天天”的客户住在哪里？她的电子邮件是什么？

assistant: SELECT T2.address ,  T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id  =  T1.address_id WHERE T1.first_name  =  '天天'
Schema: CREATE TABLE customer (email VARCHAR, address_id VARCHAR, first_name VARCHAR), CREATE TABLE address (address VARCHAR, address_id VARCHAR)
user: 返回名为“天天”的客户的地址和电子邮件。

assistant: SELECT T2.address ,  T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id  =  T1.address_id WHERE T1.first_name  =  '天天'
Schema: CREATE TABLE film (title VARCHAR, LENGTH INTEGER, rating VARCHAR, replacement_cost INTEGER)
user: 找到所有超过100分钟或评级为“限制”的电影，去掉那些替换时间花费超过200的。列出标题。

assistant: SELECT title FROM film WHERE LENGTH  >  100 OR rating  =  '限制' EXCEPT SELECT title FROM film WHERE replacement_cost  >  200
Schema: CREATE TABLE film (title VARCHAR, LENGTH INTEGER, rating VARCHAR, replacement_cost INTEGER)
user: 除了那些替换时间花费超过200多分钟的电影之外，超过100分钟或者评级为限制级的电影的片名是什么？

assistant: SELECT title FROM film WHERE LENGTH  >  100 OR rating  =  '限制' EXCEPT SELECT title FROM film WHERE replacement_cost  >  200
Schema: CREATE TABLE customer (last_name VARCHAR, customer_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (rental_date VARCHAR, customer_id VARCHAR)
user: 最早租房的客户的名字和姓氏是什么？

assistant: SELECT T1.first_name ,  T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id  =  T2.customer_id ORDER BY T2.rental_date ASC LIMIT 1
Schema: CREATE TABLE customer (last_name VARCHAR, customer_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (rental_date VARCHAR, customer_id VARCHAR)
user: 返回最早租房的客户的全名。

assistant: SELECT T1.first_name ,  T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id  =  T2.customer_id ORDER BY T2.rental_date ASC LIMIT 1
Schema: CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (staff_id VARCHAR, customer_id VARCHAR), CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
user: 租了一部电影给一位名为“晓月”姓为“张”的顾客的职员的全名是什么？

assistant: SELECT DISTINCT T1.first_name ,  T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id  =  T2.staff_id JOIN customer AS T3 ON T2.customer_id  =  T3.customer_id WHERE T3.first_name  =  '晓月' AND T3.last_name  =  '张'
Schema: CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (staff_id VARCHAR, customer_id VARCHAR), CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
user: 返回给姓是“张”名是“晓月”的客户提供电影租赁的员工的全名。

assistant: SELECT DISTINCT T1.first_name ,  T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id  =  T2.staff_id JOIN customer AS T3 ON T2.customer_id  =  T3.customer_id WHERE T3.first_name  =  '晓月' AND T3.last_name  =  '张'
Schema: CREATE TABLE customer (store_id VARCHAR)
user: 哪个商店的顾客最多？

assistant: SELECT store_id FROM customer GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE customer (store_id VARCHAR)
user: 返回顾客最多的商店的id。

assistant: SELECT store_id FROM customer GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE payment (amount VARCHAR)
user: 最大的支付金额是多少？

assistant: SELECT amount FROM payment ORDER BY amount DESC LIMIT 1
Schema: CREATE TABLE payment (amount VARCHAR)
user: 返回最大的支付的金额。

assistant: SELECT amount FROM payment ORDER BY amount DESC LIMIT 1
Schema: CREATE TABLE staff (address_id VARCHAR, first_name VARCHAR), CREATE TABLE address (address VARCHAR, address_id VARCHAR)
user: 姓“严”的工作人员住在哪里？

assistant: SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id  =  T2.address_id WHERE T1.first_name  =  '严'
Schema: CREATE TABLE staff (address_id VARCHAR, first_name VARCHAR), CREATE TABLE address (address VARCHAR, address_id VARCHAR)
user: 请给出姓为“严”的工作人员的地址。

assistant: SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id  =  T2.address_id WHERE T1.first_name  =  '严'
Schema: CREATE TABLE customer (rental_date INTEGER, customer_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (rental_date INTEGER, customer_id VARCHAR, first_name VARCHAR)
user: 在“2005-08-2302:06:01”之后没有租过电影的客户的名字是什么？

assistant: SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date  >  '2005-08-23 02:06:01' )
Schema: CREATE TABLE customer (rental_date INTEGER, customer_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (rental_date INTEGER, customer_id VARCHAR, first_name VARCHAR)
user: 返回在“2005-08-2302:06:01”之后没有租电影的客户的名字。

assistant: SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date  >  '2005-08-23 02:06:01' )
Schema: CREATE TABLE bank (Id VARCHAR)
user: 有多少银行分行？

assistant: SELECT count(*) FROM bank
Schema: CREATE TABLE bank (Id VARCHAR)
user: 统计银行分行的数量。

assistant: SELECT count(*) FROM bank
Schema: CREATE TABLE bank (no_of_customers INTEGER)
user: 有多少顾客？

assistant: SELECT sum(no_of_customers) FROM bank
Schema: CREATE TABLE bank (no_of_customers INTEGER)
user: 银行的总客户数是多少？

assistant: SELECT sum(no_of_customers) FROM bank
Schema: CREATE TABLE bank (city VARCHAR, no_of_customers INTEGER)
user: 找到“上海市”的银行的客户数量。

assistant: SELECT sum(no_of_customers) FROM bank WHERE city  =  '上海'
Schema: CREATE TABLE bank (city VARCHAR, no_of_customers INTEGER)
user: 使用“上海市”的银行的客户总数是多少？

assistant: SELECT sum(no_of_customers) FROM bank WHERE city  =  '上海'
Schema: CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
user: 找出犹他各州的银行的平均客户数。

assistant: SELECT avg(no_of_customers) FROM bank WHERE state  =  '江西'
Schema: CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
user: “江西”的银行的平均客户数是多少？

assistant: SELECT avg(no_of_customers) FROM bank WHERE state  =  '江西'
Schema: CREATE TABLE bank (no_of_customers INTEGER)
user: 找到所有银行的平均客户数。

assistant: SELECT avg(no_of_customers) FROM bank
Schema: CREATE TABLE bank (no_of_customers INTEGER)
user: 银行客户的平均数量是多少？

assistant: SELECT avg(no_of_customers) FROM bank
Schema: CREATE TABLE bank (city VARCHAR, state VARCHAR, bname VARCHAR)
user: 找到名为“浦发”的银行分行所在的城市和州。

assistant: SELECT city ,  state FROM bank WHERE bname  =  '浦发'
Schema: CREATE TABLE bank (city VARCHAR, state VARCHAR, bname VARCHAR)
user: 名为“浦发”的银行所在的城市和州是什么？

assistant: SELECT city ,  state FROM bank WHERE bname  =  '浦发'
Schema: CREATE TABLE bank (state VARCHAR, bname VARCHAR)
user: 查找“上海”的银行分行名称。

assistant: SELECT bname FROM bank WHERE state  =  '上海'
Schema: CREATE TABLE bank (state VARCHAR, bname VARCHAR)
user: “上海”的银行的名称是什么？

assistant: SELECT bname FROM bank WHERE state  =  '上海'
Schema: CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
user: 按帐户余额升序排列列出所有客户的名字。

assistant: SELECT cust_name FROM customer ORDER BY acc_bal
Schema: CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
user: 按账户余额排序，所有客户的名字是什么？

assistant: SELECT cust_name FROM customer ORDER BY acc_bal
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
user: 按贷款总额排序列出所有不同客户的名字。

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount)
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
user: 按贷款总额排序，不同客户的名字是什么？

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount)
Schema: CREATE TABLE customer (acc_type VARCHAR, state VARCHAR, credit_score VARCHAR, no_of_loans VARCHAR)
user: 查找贷款数额为0的客户的状态、帐户类型和信用评分。

assistant: SELECT state ,  acc_type ,  credit_score FROM customer WHERE no_of_loans  =  0
Schema: CREATE TABLE customer (acc_type VARCHAR, state VARCHAR, credit_score VARCHAR, no_of_loans VARCHAR)
user: 零贷款的客户的状态、账户类型和信用评分是什么？

assistant: SELECT state ,  acc_type ,  credit_score FROM customer WHERE no_of_loans  =  0
Schema: CREATE TABLE bank (city VARCHAR)
user: 找出银行所处的不同城市的数量。

assistant: SELECT count(DISTINCT city) FROM bank
Schema: CREATE TABLE bank (city VARCHAR)
user: 银行所在多少个不同的城市？

assistant: SELECT count(DISTINCT city) FROM bank
Schema: CREATE TABLE bank (state VARCHAR)
user: 找出银行所处的不同州的数目。

assistant: SELECT count(DISTINCT state) FROM bank
Schema: CREATE TABLE bank (state VARCHAR)
user: 银行所在有多少不同的州？

assistant: SELECT count(DISTINCT state) FROM bank
Schema: CREATE TABLE customer (acc_type VARCHAR)
user: 有多少种不同类型的账户？

assistant: SELECT count(DISTINCT acc_type) FROM customer
Schema: CREATE TABLE customer (acc_type VARCHAR)
user: 计算不同帐户类型的数量。

assistant: SELECT count(DISTINCT acc_type) FROM customer
Schema: CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
user: 找到名字中包含字母“a”的客户的姓名和账户余额.

assistant: SELECT cust_name ,  acc_bal FROM customer WHERE cust_name LIKE 'a'
Schema: CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
user: 名字中包含字母“a”的客户姓名和账户余额是什么？

assistant: SELECT cust_name ,  acc_bal FROM customer WHERE cust_name LIKE 'a'
Schema: CREATE TABLE customer (state VARCHAR, acc_bal INTEGER)
user: 查找来自“江西”或“云南”的每个客户的总账户余额。

assistant: SELECT sum(acc_bal) FROM customer WHERE state  =  '江西' OR state  =  '云南'
Schema: CREATE TABLE customer (state VARCHAR, acc_bal INTEGER)
user: 来自“江西”或“云南”的每个客户的总账户余额是多少？

assistant: SELECT sum(acc_bal) FROM customer WHERE state  =  '江西' OR state  =  '云南'
Schema: CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
user: 查找同时有“存储”和“支票”帐户类型的客户的名字。

assistant: SELECT cust_name FROM customer WHERE acc_type  =  '存储' INTERSECT SELECT cust_name FROM customer WHERE acc_type  =  '支票'
Schema: CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
user: 同时拥有“存储”账户和“支票”账户的客户名字是什么？

assistant: SELECT cust_name FROM customer WHERE acc_type  =  '存储' INTERSECT SELECT cust_name FROM customer WHERE acc_type  =  '支票'
Schema: CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
user: 查找没有“存储”账户的客户的名字。

assistant: SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type  =  '存储'
Schema: CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
user: 没有“存储”账户的客户的名字是什么？

assistant: SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type  =  '存储'
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (loan_type VARCHAR, cust_id VARCHAR)
user: 查找没有“抵押”类型贷款的客户的名字。

assistant: SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE T2.loan_type  =  '抵押'
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (loan_type VARCHAR, cust_id VARCHAR)
user: 那些没有接受过“抵押”贷款的客户的名字是什么？

assistant: SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE T2.loan_type  =  '抵押'
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 查找有“抵押”贷款和“汽车”贷款的客户的名字。

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE loan_type  =  '抵押' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE loan_type  =  '汽车'
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 有过“抵押”贷款和“汽车”贷款的客户的名字是什么？

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE loan_type  =  '抵押' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE loan_type  =  '汽车'
Schema: CREATE TABLE customer (credit_score INTEGER, cust_name VARCHAR)
user: 查找信用评分低于所有客户平均信用评分的客户的名字。

assistant: SELECT cust_name FROM customer WHERE credit_score  <  (SELECT avg(credit_score) FROM customer)
Schema: CREATE TABLE customer (credit_score INTEGER, cust_name VARCHAR)
user: 信用评分低于所有客户平均信用评分的客户的名字是什么？

assistant: SELECT cust_name FROM customer WHERE credit_score  <  (SELECT avg(credit_score) FROM customer)
Schema: CREATE TABLE bank (no_of_customers VARCHAR, bname VARCHAR)
user: 找到客户数量最多的银行支行名称。

assistant: SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1
Schema: CREATE TABLE bank (no_of_customers VARCHAR, bname VARCHAR)
user: 客户数量最多的银行支行的名称是什么？

assistant: SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1
Schema: CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR)
user: 查找信用评分最低的客户的名字。

assistant: SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1
Schema: CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR)
user: 信用评分最差的客户的名字是什么？

assistant: SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1
Schema: CREATE TABLE customer (acc_type VARCHAR, acc_bal VARCHAR, cust_name VARCHAR, credit_score VARCHAR)
user: 查找具有最高信用评分的客户的名字、帐户类型和帐户余额。

assistant: SELECT cust_name ,  acc_type ,  acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1
Schema: CREATE TABLE customer (acc_type VARCHAR, acc_bal VARCHAR, cust_name VARCHAR, credit_score VARCHAR)
user: 具有最高信用评分的客户相对应的名字、帐户类型和帐户余额是什么？

assistant: SELECT cust_name ,  acc_type ,  acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
user: 查找贷款金额最高的客户的名字。

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
user: 总贷款金额最大的客户名字是什么？

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1
Schema: CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
user: 找出客户数量最多的州。

assistant: SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1
Schema: CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
user: 哪一个州的银行客户总数最大？

assistant: SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1
Schema: CREATE TABLE customer (acc_type VARCHAR, credit_score INTEGER, acc_bal INTEGER)
user: 针对每个账户类型，找到信用评分低于50的客户的平均账户余额。

assistant: SELECT avg(acc_bal) ,  acc_type FROM customer WHERE credit_score  <  50 GROUP BY acc_type
Schema: CREATE TABLE customer (acc_type VARCHAR, credit_score INTEGER, acc_bal INTEGER)
user: 针对不同的账户类型，信用评分低于50的客户的平均账户余额是多少？

assistant: SELECT avg(acc_bal) ,  acc_type FROM customer WHERE credit_score  <  50 GROUP BY acc_type
Schema: CREATE TABLE customer (credit_score INTEGER, state VARCHAR, acc_bal INTEGER)
user: 针对每个州，找到信用评分超过100的客户的总账户余额。

assistant: SELECT sum(acc_bal) ,  state FROM customer WHERE credit_score  >  100 GROUP BY state
Schema: CREATE TABLE customer (credit_score INTEGER, state VARCHAR, acc_bal INTEGER)
user: 对于不同州的信用评分超过100的客户，帐户总余额是多少？

assistant: SELECT sum(acc_bal) ,  state FROM customer WHERE credit_score  >  100 GROUP BY state
Schema: CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
user: 找到每个银行分行所提供的贷款总额。

assistant: SELECT sum(amount) ,  T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id GROUP BY T1.bname
Schema: CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
user: 不同的银行分行的名称是什么，它们的贷款总额是多少？

assistant: SELECT sum(amount) ,  T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id GROUP BY T1.bname
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 查找拥有不止一笔贷款的客户的姓名。

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name HAVING count(*)  >  1
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 拥有一笔以上贷款的客户的姓名是什么？

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name HAVING count(*)  >  1
Schema: CREATE TABLE customer (acc_type VARCHAR, cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
user: 查找贷款总额超过5000的客户的姓名和账户余额。

assistant: SELECT T1.cust_name ,  T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount)  >  5000
Schema: CREATE TABLE customer (acc_type VARCHAR, cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
user: 贷款总额超过5000的客户的姓名和账户余额是多少？

assistant: SELECT T1.cust_name ,  T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount)  >  5000
Schema: CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (amount INTEGER, branch_id VARCHAR)
user: 查找提供最大贷款总额的银行支行的名称。

assistant: SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1
Schema: CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (amount INTEGER, branch_id VARCHAR)
user: 贷款额度最大的银行支行的名称是什么？

assistant: SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1
Schema: CREATE TABLE loan (amount INTEGER, cust_id VARCHAR, branch_id VARCHAR), CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
user: 找出向信用评分小于100的客户提供最大贷款总额的银行支行的名称。

assistant: SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id  =  T2.branch_id JOIN customer AS T3 ON T1.cust_id  =  T3.cust_id WHERE T3.credit_score  <  100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1
Schema: CREATE TABLE loan (amount INTEGER, cust_id VARCHAR, branch_id VARCHAR), CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
user: 针对那些信用评分低于100分的客户，放贷总额最大的银行支行的名字是什么？

assistant: SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id  =  T2.branch_id JOIN customer AS T3 ON T1.cust_id  =  T3.cust_id WHERE T3.credit_score  <  100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1
Schema: CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
user: 查找提供过贷款的银行支行的名称。

assistant: SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id
Schema: CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
user: 提供过贷款的不同银行的名称是什么？

assistant: SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR, credit_score VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 查找有贷款的客户的姓名和信用评分。

assistant: SELECT DISTINCT T1.cust_name ,  T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR, credit_score VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 贷过款的不同客户的姓名和信用评分是什么？

assistant: SELECT DISTINCT T1.cust_name ,  T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 找到贷款数额超过3000的客户的名字。

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE amount  >  3000
Schema: CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
user: 贷款金额超过3000的客户名字是什么？

assistant: SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id  =  T2.cust_id WHERE amount  >  3000
Schema: CREATE TABLE bank (city VARCHAR, bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (loan_type VARCHAR, branch_id VARCHAR)
user: 查找提供“商业”贷款的银行分行的名称和所在的城市名称。

assistant: SELECT T1.bname ,  T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id WHERE T2.loan_type  =  '商业'
Schema: CREATE TABLE bank (city VARCHAR, bname VARCHAR, branch_id VARCHAR), CREATE TABLE loan (loan_type VARCHAR, branch_id VARCHAR)
user: 提供“商业”贷款的银行支行的名称和所在城市是什么？

assistant: SELECT T1.bname ,  T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id WHERE T2.loan_type  =  '商业'
Schema: CREATE TABLE loan (cust_id VARCHAR, branch_id VARCHAR), CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
user: 查找向信用评分低于100的任何客户提供过贷款的银行分行的名称。

assistant: SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id  =  T2.branch_id JOIN customer AS T3 ON T1.cust_id  =  T3.cust_id WHERE T3.credit_score  <  100
Schema: CREATE TABLE loan (cust_id VARCHAR, branch_id VARCHAR), CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
user: 贷款给信用评分低于100分的客户的银行的名称是什么？

assistant: SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id  =  T2.branch_id JOIN customer AS T3 ON T1.cust_id  =  T3.cust_id WHERE T3.credit_score  <  100
Schema: CREATE TABLE bank (state VARCHAR, branch_id VARCHAR), CREATE TABLE loan (amount INTEGER, branch_id VARCHAR)
user: 查找“上海”的银行分行提供的贷款总额。

assistant: SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id WHERE T1.state  =  '上海'
Schema: CREATE TABLE bank (state VARCHAR, branch_id VARCHAR), CREATE TABLE loan (amount INTEGER, branch_id VARCHAR)
user: “上海”的银行贷款的总金额是多少？

assistant: SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id  =  T2.branch_id WHERE T1.state  =  '上海'
Schema: CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER), CREATE TABLE loan (cust_id VARCHAR, credit_score INTEGER)
user: 找到有贷款的客户的平均信用评分。

assistant: SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan)
Schema: CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER), CREATE TABLE loan (cust_id VARCHAR, credit_score INTEGER)
user: 贷过款的客户的平均信用评分是多少？

assistant: SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan)