jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE Lessons (lesson_status_code VARCHAR, customer_id VARCHAR), CREATE TABLE Customers (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
user: 以“文祥”和“赵”为姓的客户“完成”学习了多少课程？

assistant: SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id  = T2.customer_id WHERE T2.first_name = "文祥" AND T2.last_name = "赵" AND T1.lesson_status_code = "完成";
Schema: CREATE TABLE Lessons (lesson_status_code VARCHAR, customer_id VARCHAR), CREATE TABLE Customers (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
user: 客户“赵”“文祥”“完成”了多少课程？

assistant: SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id  = T2.customer_id WHERE T2.first_name = "文祥" AND T2.last_name = "赵" AND T1.lesson_status_code = "完成";
Schema: CREATE TABLE Customers (amount_outstanding INTEGER)
user: 客户的最大、最小和平均金额是多少？

assistant: SELECT max(amount_outstanding) ,  min(amount_outstanding) ,  avg(amount_outstanding) FROM Customers;
Schema: CREATE TABLE Customers (amount_outstanding INTEGER)
user: 对于所有客户来说，最大金额、最小金额和平均金额是多少？

assistant: SELECT max(amount_outstanding) ,  min(amount_outstanding) ,  avg(amount_outstanding) FROM Customers;
Schema: CREATE TABLE Customers (last_name VARCHAR, first_name VARCHAR, amount_outstanding INTEGER)
user: 列出金额在1000至3000之间的客户的姓名和姓氏。

assistant: SELECT first_name ,  last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
Schema: CREATE TABLE Customers (last_name VARCHAR, first_name VARCHAR, amount_outstanding INTEGER)
user: 1000到3000美元之间的所有客户的名字和姓氏是什么？

assistant: SELECT first_name ,  last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
Schema: CREATE TABLE Customers (last_name VARCHAR, customer_address_id VARCHAR, first_name VARCHAR), CREATE TABLE Addresses (address_id VARCHAR, city VARCHAR)
user: 列出居住在“福州”市的客户的姓名和姓氏。

assistant: SELECT T1.first_name ,  T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "福州";
Schema: CREATE TABLE Customers (last_name VARCHAR, customer_address_id VARCHAR, first_name VARCHAR), CREATE TABLE Addresses (address_id VARCHAR, city VARCHAR)
user: 住在“福州”市的所有客户的姓氏和姓氏是什么？

assistant: SELECT T1.first_name ,  T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "福州";
Schema: CREATE TABLE Customers (last_name VARCHAR, customer_address_id VARCHAR, first_name VARCHAR), CREATE TABLE Addresses (country VARCHAR, address_id VARCHAR)
user: 名字是“诚”和姓氏是“钟”的顾客住在哪个国家？

assistant: SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "诚" AND T1.last_name = "钟"
Schema: CREATE TABLE Customers (last_name VARCHAR, customer_address_id VARCHAR, first_name VARCHAR), CREATE TABLE Addresses (country VARCHAR, address_id VARCHAR)
user: 客户“钟”“诚”居住的国家是什么？

assistant: SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "诚" AND T1.last_name = "钟"
Schema: CREATE TABLE Customers (last_name VARCHAR, customer_address_id VARCHAR, first_name VARCHAR), CREATE TABLE Addresses (address_id VARCHAR, zip_postcode VARCHAR)
user: 名字是“诚”和姓氏是“钟”的顾客的邮政编码是什么？

assistant: SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "诚" AND T1.last_name = "钟"
Schema: CREATE TABLE Customers (last_name VARCHAR, customer_address_id VARCHAR, first_name VARCHAR), CREATE TABLE Addresses (address_id VARCHAR, zip_postcode VARCHAR)
user: 客户“钟”“诚”的邮政编码是什么？

assistant: SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "诚" AND T1.last_name = "钟"
Schema: CREATE TABLE Customers (customer_address_id VARCHAR), CREATE TABLE Addresses (address_id VARCHAR, city VARCHAR)
user: 哪个城市有最多的客户？

assistant: SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
Schema: CREATE TABLE Customers (customer_address_id VARCHAR), CREATE TABLE Addresses (address_id VARCHAR, city VARCHAR)
user: 什么城市拥有最多的客户？

assistant: SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
Schema: CREATE TABLE Customer_Payments (amount_payment INTEGER, customer_id VARCHAR), CREATE TABLE Customers (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
user: 名字是“诚”和姓氏是“钟”的顾客总共付了多少钱？

assistant: SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "诚" AND T2.last_name = "钟"
Schema: CREATE TABLE Customer_Payments (amount_payment INTEGER, customer_id VARCHAR), CREATE TABLE Customers (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
user: 顾客“钟”“诚”支付的总金额是多少？

assistant: SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "诚" AND T2.last_name = "钟"
Schema: CREATE TABLE Customers (customer_id VARCHAR), CREATE TABLE Customer_Payments (customer_id VARCHAR)
user: 列出没有支付历史记录的客户数量。

assistant: SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
Schema: CREATE TABLE Customers (customer_id VARCHAR), CREATE TABLE Customer_Payments (customer_id VARCHAR)
user: 有多少客户没有付款记录？

assistant: SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
Schema: CREATE TABLE Customer_Payments (customer_id VARCHAR), CREATE TABLE Customers (last_name VARCHAR, customer_id VARCHAR, first_name VARCHAR)
user: 列出超过2次付款的客户的名字和姓氏。

assistant: SELECT T2.first_name ,  T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*)  >  2;
Schema: CREATE TABLE Customer_Payments (customer_id VARCHAR), CREATE TABLE Customers (last_name VARCHAR, customer_id VARCHAR, first_name VARCHAR)
user: 所有超过2次付款的客户的名字和姓氏是什么？

assistant: SELECT T2.first_name ,  T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*)  >  2;
Schema: CREATE TABLE Customer_Payments (payment_method_code VARCHAR)
user: 列出所有付款方式和每种付款方式的付款次数。

assistant: SELECT payment_method_code ,  count(*) FROM Customer_Payments GROUP BY payment_method_code;
Schema: CREATE TABLE Customer_Payments (payment_method_code VARCHAR)
user: 对于每种支付方式，支付了多少？

assistant: SELECT payment_method_code ,  count(*) FROM Customer_Payments GROUP BY payment_method_code;
Schema: CREATE TABLE Lessons (lesson_status_code VARCHAR)
user: “取消”的课有多少？

assistant: SELECT count(*) FROM Lessons WHERE lesson_status_code = "取消";
Schema: CREATE TABLE Lessons (lesson_status_code VARCHAR)
user: 有多少课被“取消”了？

assistant: SELECT count(*) FROM Lessons WHERE lesson_status_code = "取消";
Schema: CREATE TABLE Lessons (staff_id VARCHAR, lesson_id VARCHAR), CREATE TABLE Staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR)
user: 列出名字是 “子君” ，姓氏是“温” ，昵称包含字“子”的职工教的课程ID。

assistant: SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "子君" AND T2.last_name = "温" AND nickname LIKE "%子%";
Schema: CREATE TABLE Lessons (staff_id VARCHAR, lesson_id VARCHAR), CREATE TABLE Staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR)
user: 昵称包含字“子”的职员“温”“子君” ，她教的所有职员的ID是什么？

assistant: SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "子君" AND T2.last_name = "温" AND nickname LIKE "%子%";
Schema: CREATE TABLE Lessons (staff_id VARCHAR), CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR)
user: 名字中有“安”字的教职员教了多少课？

assistant: SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%安%"
Schema: CREATE TABLE Lessons (staff_id VARCHAR), CREATE TABLE Staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR)
user: 以“子君”为名字，“温”为姓氏的员工教的总课时有多长？

assistant: SELECT sum(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "子君" AND T2.last_name = "温";
Schema: CREATE TABLE Lessons (staff_id VARCHAR), CREATE TABLE Staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR)
user: “温”“子君”教授的所有课程的总时间是多少？

assistant: SELECT sum(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "子君" AND T2.last_name = "温";
Schema: CREATE TABLE Lessons (staff_id VARCHAR), CREATE TABLE Staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR)
user: 名字是 “子君” ，姓氏是“温” 的员工平均授课价格是多少？

assistant: SELECT avg(price) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "子君" AND T2.last_name = "温";
Schema: CREATE TABLE Lessons (staff_id VARCHAR), CREATE TABLE Staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR)
user:  “温”“子君” 教授的课的平均价格是多少？

assistant: SELECT avg(price) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "子君" AND T2.last_name = "温";
Schema: CREATE TABLE Lessons (customer_id VARCHAR), CREATE TABLE Customers (first_name VARCHAR, customer_id VARCHAR)
user: 名字叫“瑞”的客户上了多少课？

assistant: SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id  = T2.customer_id WHERE T2.first_name = "瑞"
Schema: CREATE TABLE Customers (last_name VARCHAR), CREATE TABLE Staff (last_name VARCHAR)
user: 客户和员工都使用哪些姓氏？

assistant: SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff
Schema: CREATE TABLE Customers (last_name VARCHAR), CREATE TABLE Staff (last_name VARCHAR)
user: 客户和员工使用的姓氏是什么？

assistant: SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff
Schema: CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR), CREATE TABLE Lessons (staff_id VARCHAR)
user: 没有给授课的员工的名字是什么？

assistant: SELECT first_name FROM Staff EXCEPT SELECT T2.first_name FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id  =  T2.staff_id
Schema: CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR), CREATE TABLE Lessons (staff_id VARCHAR)
user: 不教任何课程的员工的第一个名字是什么？

assistant: SELECT first_name FROM Staff EXCEPT SELECT T2.first_name FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id  =  T2.staff_id
Schema: CREATE TABLE Vehicles (vehicle_details VARCHAR, vehicle_id VARCHAR), CREATE TABLE Lessons (vehicle_id VARCHAR)
user: 在大部分时间里，车辆使用的ID和详细信息是什么？

assistant: SELECT T1.vehicle_id ,  T1.vehicle_details FROM Vehicles AS T1 JOIN Lessons AS T2 ON T1.vehicle_id  =  T2.vehicle_id GROUP BY T1.vehicle_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Faculty (Id VARCHAR)
user: 我们有多少教员？

assistant: SELECT count(*) FROM Faculty
Schema: CREATE TABLE Faculty (Id VARCHAR)
user: 全体教员的总数是多少？

assistant: SELECT count(*) FROM Faculty
Schema: CREATE TABLE Faculty (rank VARCHAR)
user: 我们有什么等级的教员？

assistant: SELECT DISTINCT rank FROM Faculty
Schema: CREATE TABLE Faculty (rank VARCHAR)
user: 找出不同等级的教员。

assistant: SELECT DISTINCT rank FROM Faculty
Schema: CREATE TABLE Faculty (building VARCHAR)
user: 显示所有有教学室的不同建筑。

assistant: SELECT DISTINCT building FROM Faculty
Schema: CREATE TABLE Faculty (building VARCHAR)
user: 什么建筑有教学办公室？

assistant: SELECT DISTINCT building FROM Faculty
Schema: CREATE TABLE Faculty (Lname VARCHAR, rank VARCHAR, Fname VARCHAR)
user: 显示所有教员的等级、名字和姓氏。

assistant: SELECT rank ,  Fname ,  Lname FROM Faculty
Schema: CREATE TABLE Faculty (Lname VARCHAR, rank VARCHAR, Fname VARCHAR)
user: 教员的职称、名字和姓氏是什么？

assistant: SELECT rank ,  Fname ,  Lname FROM Faculty
Schema: CREATE TABLE Faculty (phone VARCHAR, Sex VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 显示所有“女”教员的姓名、姓氏和电话号码。

assistant: SELECT Fname ,  Lname ,  phone FROM Faculty WHERE Sex  =  "女"
Schema: CREATE TABLE Faculty (phone VARCHAR, Sex VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 所有“女”教员的名字、姓氏和电话号码是什么？

assistant: SELECT Fname ,  Lname ,  phone FROM Faculty WHERE Sex  =  "女"
Schema: CREATE TABLE Faculty (FacID VARCHAR, Sex VARCHAR)
user: 显示所有“男”性教师的ID。

assistant: SELECT FacID FROM Faculty WHERE Sex  =  "男"
Schema: CREATE TABLE Faculty (FacID VARCHAR, Sex VARCHAR)
user: 所有“男”性教职员工的教师ID是什么？

assistant: SELECT FacID FROM Faculty WHERE Sex  =  "男"
Schema: CREATE TABLE Faculty (Rank VARCHAR, Sex VARCHAR)
user: 我们有多少“女”“教授”？

assistant: SELECT count(*) FROM Faculty WHERE Sex  =  "女" AND Rank  =  "教授"
Schema: CREATE TABLE Faculty (Rank VARCHAR, Sex VARCHAR)
user: 统计一下我们有多少“女”“教授”。

assistant: SELECT count(*) FROM Faculty WHERE Sex  =  "女" AND Rank  =  "教授"
Schema: CREATE TABLE Faculty (room VARCHAR, Fname VARCHAR, Lname VARCHAR, phone VARCHAR, building VARCHAR)
user: 展示教师名为“王”“睿”的电话，房间，和建筑。

assistant: SELECT phone ,  room ,  building FROM Faculty WHERE Fname  =  "睿" AND Lname  =  "王"
Schema: CREATE TABLE Faculty (room VARCHAR, Fname VARCHAR, Lname VARCHAR, phone VARCHAR, building VARCHAR)
user: 教师“王”“睿”的电话、房间和建筑是什么？

assistant: SELECT phone ,  room ,  building FROM Faculty WHERE Fname  =  "睿" AND Lname  =  "王"
Schema: CREATE TABLE Faculty (building VARCHAR, Rank VARCHAR)
user: “逸夫”楼有多少“教授”？

assistant: SELECT count(*) FROM Faculty WHERE Rank  =  "教授" AND building  =  "逸夫"
Schema: CREATE TABLE Faculty (building VARCHAR, Rank VARCHAR)
user: 统计在“逸夫”楼拥有办公室的“教授”的数量。

assistant: SELECT count(*) FROM Faculty WHERE Rank  =  "教授" AND building  =  "逸夫"
Schema: CREATE TABLE Faculty (fname VARCHAR, Rank VARCHAR, lname VARCHAR)
user: 显示所有“教员”的名字和姓氏。

assistant: SELECT fname ,  lname FROM Faculty WHERE Rank  =  "教员"
Schema: CREATE TABLE Faculty (fname VARCHAR, Rank VARCHAR, lname VARCHAR)
user: 所有“教员”的名字和姓氏是什么？

assistant: SELECT fname ,  lname FROM Faculty WHERE Rank  =  "教员"
Schema: CREATE TABLE Faculty (building VARCHAR)
user: 显示所有的建筑物以及建筑物的教职员数。

assistant: SELECT building ,  count(*) FROM Faculty GROUP BY building
Schema: CREATE TABLE Faculty (building VARCHAR)
user: 每个建筑有多少教员？以建筑物的名称列出结果。

assistant: SELECT building ,  count(*) FROM Faculty GROUP BY building
Schema: CREATE TABLE Faculty (building VARCHAR)
user: 哪一栋楼的教员最多？

assistant: SELECT building FROM Faculty GROUP BY building ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Faculty (building VARCHAR)
user: 找出拥有最多教员的建筑。

assistant: SELECT building FROM Faculty GROUP BY building ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Faculty (building VARCHAR, rank VARCHAR)
user: 展示所有至少有10位“教授”的建筑。

assistant: SELECT building FROM Faculty WHERE rank  =  "教授" GROUP BY building HAVING count(*)  >=  10
Schema: CREATE TABLE Faculty (building VARCHAR, rank VARCHAR)
user: 在哪栋楼里至少有十位“教授”？

assistant: SELECT building FROM Faculty WHERE rank  =  "教授" GROUP BY building HAVING count(*)  >=  10
Schema: CREATE TABLE Faculty (rank VARCHAR)
user: 对于每一个教职员工等级，显示该等级有教职员工的人数。

assistant: SELECT rank ,  count(*) FROM Faculty GROUP BY rank
Schema: CREATE TABLE Faculty (rank VARCHAR)
user: 我们每个教员等级有多少教员？

assistant: SELECT rank ,  count(*) FROM Faculty GROUP BY rank
Schema: CREATE TABLE Faculty (sex VARCHAR, rank VARCHAR)
user: 显示所有等级和各等级的男女教师人数。

assistant: SELECT rank ,  sex ,  count(*) FROM Faculty GROUP BY rank ,  sex
Schema: CREATE TABLE Faculty (sex VARCHAR, rank VARCHAR)
user: 我们每个年级有多少教员和性别？

assistant: SELECT rank ,  sex ,  count(*) FROM Faculty GROUP BY rank ,  sex
Schema: CREATE TABLE Faculty (rank VARCHAR)
user: 哪一个教职员工人数最少？

assistant: SELECT rank FROM Faculty GROUP BY rank ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE Faculty (rank VARCHAR)
user: 找出最少人数的教员级别。

assistant: SELECT rank FROM Faculty GROUP BY rank ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE Faculty (sex VARCHAR, rank VARCHAR)
user: 显示男女“助理教授”的数量。

assistant: SELECT sex ,  count(*) FROM Faculty WHERE rank  =  "助理教授" GROUP BY sex
Schema: CREATE TABLE Faculty (sex VARCHAR, rank VARCHAR)
user: 我们有多少男女“助理教授”？

assistant: SELECT sex ,  count(*) FROM Faculty WHERE rank  =  "助理教授" GROUP BY sex
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR), CREATE TABLE Student (fname VARCHAR, advisor VARCHAR, lname VARCHAR)
user: “张”“晴”的导师的名字和姓氏是什么？

assistant: SELECT T1.fname ,  T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor WHERE T2.fname  =  "晴" AND T2.lname  =  "张"
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR), CREATE TABLE Student (fname VARCHAR, advisor VARCHAR, lname VARCHAR)
user: 谁是“张”“晴”的导师？给我名字和姓氏。

assistant: SELECT T1.fname ,  T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor WHERE T2.fname  =  "晴" AND T2.lname  =  "张"
Schema: CREATE TABLE Faculty (FacID VARCHAR, rank VARCHAR), CREATE TABLE Student (advisor VARCHAR, StuID VARCHAR)
user: 显示导师是“教授”的学生的ID。

assistant: SELECT T2.StuID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor WHERE T1.rank  =  "Professor"
Schema: CREATE TABLE Faculty (FacID VARCHAR, rank VARCHAR), CREATE TABLE Student (advisor VARCHAR, StuID VARCHAR)
user: 哪些学生有“教授”作为他们的导师？找出他们的学生ID。

assistant: SELECT T2.StuID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor WHERE T1.rank  =  "Professor"
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR), CREATE TABLE Student (fname VARCHAR, advisor VARCHAR, lname VARCHAR)
user: 显示“李”“斌”指导的所有学生的名字和姓氏。

assistant: SELECT T2.fname ,  T2.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor WHERE T1.fname  =  "斌" AND T1.lname  =  "李"
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR), CREATE TABLE Student (fname VARCHAR, advisor VARCHAR, lname VARCHAR)
user: “李”“斌”指导哪些学生？给我他们的名字和姓氏。

assistant: SELECT T2.fname ,  T2.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor WHERE T1.fname  =  "斌" AND T1.lname  =  "李"
Schema: CREATE TABLE Faculty (FacID VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 显示教员的教员ID和他或她指导的学生人数。

assistant: SELECT T1.FacID ,  count(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.FacID
Schema: CREATE TABLE Faculty (FacID VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 每个教员的教员ID和每个教员的学生人数是多少？

assistant: SELECT T1.FacID ,  count(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.FacID
Schema: CREATE TABLE Faculty (FacID VARCHAR, rank VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 显示所有教员等级和每个等级指导的学生人数。

assistant: SELECT T1.rank ,  count(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.rank
Schema: CREATE TABLE Faculty (FacID VARCHAR, rank VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 每一位教职工等级有多少指导学生？列出等级和学生人数。

assistant: SELECT T1.rank ,  count(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.rank
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 拥有最多学生的教师的名字和姓氏是什么？

assistant: SELECT T1.fname ,  T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.FacID ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 请给出我给指导最多学生的老师的名字和姓氏。

assistant: SELECT T1.fname ,  T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.FacID ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Faculty (FacID VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 为所有有至少2名学生的教职工的ID 。

assistant: SELECT T1.FacID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.FacID HAVING count(*)  >=  2
Schema: CREATE TABLE Faculty (FacID VARCHAR), CREATE TABLE Student (advisor VARCHAR)
user: 哪个教职工指导两个以上的学生？给我他们的教职工ID。

assistant: SELECT T1.FacID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID  =  T2.advisor GROUP BY T1.FacID HAVING count(*)  >=  2
Schema: CREATE TABLE Faculty (FacID VARCHAR, advisor VARCHAR), CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR)
user: 显示不指导任何学生的教职工的ID 。

assistant: SELECT FacID FROM Faculty EXCEPT SELECT advisor FROM Student
Schema: CREATE TABLE Faculty (FacID VARCHAR, advisor VARCHAR), CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR)
user: 不指导任何学生的教职工的ID是什么？

assistant: SELECT FacID FROM Faculty EXCEPT SELECT advisor FROM Student
Schema: CREATE TABLE Activity (activity_name VARCHAR)
user: 我们有什么活动？

assistant: SELECT activity_name FROM Activity
Schema: CREATE TABLE Activity (activity_name VARCHAR)
user: 列出我们所有的活动。

assistant: SELECT activity_name FROM Activity
Schema: CREATE TABLE Activity (Id VARCHAR)
user: 我们有多少活动？

assistant: SELECT count(*) FROM Activity
Schema: CREATE TABLE Activity (Id VARCHAR)
user: 找出可用的活动数。

assistant: SELECT count(*) FROM Activity
Schema: CREATE TABLE Faculty_participates_in (FacID VARCHAR)
user: 有多少教职工参加一项活动？

assistant: SELECT count(DISTINCT FacID) FROM Faculty_participates_in
Schema: CREATE TABLE Faculty_participates_in (FacID VARCHAR)
user: 给我参加活动的教职工人数

assistant: SELECT count(DISTINCT FacID) FROM Faculty_participates_in
Schema: CREATE TABLE Faculty (FacID VARCHAR), CREATE TABLE Faculty_participates_in (FacID VARCHAR)
user: 显示不参与任何活动的教职工的ID。

assistant: SELECT FacID FROM Faculty EXCEPT SELECT FacID FROM Faculty_participates_in
Schema: CREATE TABLE Faculty (FacID VARCHAR), CREATE TABLE Faculty_participates_in (FacID VARCHAR)
user: 哪些教职工不参与任何活动？找出他们的教职工ID。

assistant: SELECT FacID FROM Faculty EXCEPT SELECT FacID FROM Faculty_participates_in
Schema: CREATE TABLE Faculty_participates_in (FacID VARCHAR, advisor VARCHAR), CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR)
user: 请出示所有参加活动且指导学生的教职员工的ID。

assistant: SELECT FacID FROM Faculty_participates_in INTERSECT SELECT advisor FROM Student
Schema: CREATE TABLE Faculty_participates_in (FacID VARCHAR, advisor VARCHAR), CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR)
user: 哪些是既参加活动又指导学生的教职工的ID？

assistant: SELECT FacID FROM Faculty_participates_in INTERSECT SELECT advisor FROM Student
Schema: CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, facID VARCHAR), CREATE TABLE Faculty_participates_in (facID VARCHAR)
user: “马”“文杰”参加了多少活动？

assistant: SELECT count(*) FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID  =  T2.facID WHERE T1.fname  =  "文杰" AND T1.lname  =  "马"
Schema: CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, facID VARCHAR), CREATE TABLE Faculty_participates_in (facID VARCHAR)
user: 找出“马”“文杰”参与的活动数量。

assistant: SELECT count(*) FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID  =  T2.facID WHERE T1.fname  =  "文杰" AND T1.lname  =  "马"
Schema: CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, facID VARCHAR), CREATE TABLE Faculty_participates_in (actid VARCHAR, facID VARCHAR), CREATE TABLE Activity (actid VARCHAR, activity_name VARCHAR)
user: 显示“马”“文杰”参与的所有活动的名称。

assistant: SELECT T3.activity_name FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID  =  T2.facID JOIN Activity AS T3 ON T3.actid  =  T2.actid WHERE T1.fname  =  "文杰" AND T1.lname  =  "马"
Schema: CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, facID VARCHAR), CREATE TABLE Faculty_participates_in (actid VARCHAR, facID VARCHAR), CREATE TABLE Activity (actid VARCHAR, activity_name VARCHAR)
user: “马”“文杰”参与的活动的名称是什么？

assistant: SELECT T3.activity_name FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID  =  T2.facID JOIN Activity AS T3 ON T3.actid  =  T2.actid WHERE T1.fname  =  "文杰" AND T1.lname  =  "马"
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR, facID VARCHAR), CREATE TABLE Faculty_participates_in (facID VARCHAR)
user: 显示所有参加某项活动的教职员工的名字和姓氏，以及他们参加的活动数量。

assistant: SELECT  T1.fname ,  T1.lname ,  count(*) ,  T1.FacID FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID  =  T2.facID GROUP BY T1.FacID
Schema: CREATE TABLE Faculty (fname VARCHAR, FacID VARCHAR, lname VARCHAR, facID VARCHAR), CREATE TABLE Faculty_participates_in (facID VARCHAR)
user: 参加至少一项活动的教职员工的名字和姓氏是什么？对于他们中的每一个人，也显示他们参加的活动的数量。

assistant: SELECT  T1.fname ,  T1.lname ,  count(*) ,  T1.FacID FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID  =  T2.facID GROUP BY T1.FacID
Schema: CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR), CREATE TABLE Faculty_participates_in (actID VARCHAR)
user: 显示所有活动名称和参与每个活动的教职工人数。

assistant: SELECT T1.activity_name ,  count(*) FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID  =  T2.actID GROUP BY T1.actID