jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE MINOR_IN (DNO VARCHAR)
user: 找到辅修人数最多的系的名字？

assistant: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE MINOR_IN (DNO VARCHAR)
user: 有辅修学生最多的专业叫什么名字？

assistant: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE MINOR_IN (DNO VARCHAR)
user: 找到没有学生参与辅修的专业的名字。

assistant: SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE MINOR_IN (DNO VARCHAR)
user: 没有学生参与辅修的专业的名字 是什么？

assistant: SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE MEMBER_OF (DNO VARCHAR)
user: 找出拥有最少会员人数的部门的名称。

assistant: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE MEMBER_OF (DNO VARCHAR)
user: 拥有最少会员人数的部门名称是什么？

assistant: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE FACULTY (Rank VARCHAR)
user: 找出教职人员最少的教职人员的职级。

assistant: SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE FACULTY (Rank VARCHAR)
user: 什么是最不常见的教职员工职级？

assistant: SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE COURSE (Instructor VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 教授课程数前三多的老师的名字和姓氏是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE COURSE (Instructor VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 教授课程数最多的3名老师的名字和姓氏是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE COURSE (Instructor VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Building VARCHAR)
user: 教课最多的老师住在哪栋楼里？

assistant: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE COURSE (Instructor VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Building VARCHAR)
user: 给出教授课程数最多的老师住的大楼。

assistant: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE COURSE (CID VARCHAR, CName VARCHAR), CREATE TABLE ENROLLED_IN (CID VARCHAR)
user: 至少有五人参加的课程名称是什么？

assistant: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Schema: CREATE TABLE COURSE (CID VARCHAR, CName VARCHAR), CREATE TABLE ENROLLED_IN (CID VARCHAR)
user: 列出至少有五人的课程的名称。

assistant: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Schema: CREATE TABLE COURSE (Instructor VARCHAR, CName VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 找出具有课程名称为“计算机基础”的教师的名字和姓氏

assistant: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "计算机基础"
Schema: CREATE TABLE COURSE (Instructor VARCHAR, CName VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 有“计算机基础”课程的老师的全名是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "计算机基础"
Schema: CREATE TABLE COURSE (DNO VARCHAR, CName VARCHAR), CREATE TABLE DEPARTMENT (DNO VARCHAR, Dname VARCHAR, Room VARCHAR)
user: 查找教授“计算机导论”的部门名称和房间。

assistant: SELECT T2.Dname ,  T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO  =  T2.DNO WHERE T1.CName  =  "计算机导论"
Schema: CREATE TABLE COURSE (DNO VARCHAR, CName VARCHAR), CREATE TABLE DEPARTMENT (DNO VARCHAR, Dname VARCHAR, Room VARCHAR)
user: “计算机导论”这门课的系名和课室是什么？

assistant: SELECT T2.Dname ,  T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO  =  T2.DNO WHERE T1.CName  =  "计算机导论"
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (lettergrade VARCHAR, gradepoint VARCHAR), CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR, Fname VARCHAR)
user: 找到所有注册学生的名字、姓氏和分数。

assistant: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (lettergrade VARCHAR, gradepoint VARCHAR), CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR, Fname VARCHAR)
user: 所有注册学生的全名和分数是什么？

assistant: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR), CREATE TABLE STUDENT (StuID VARCHAR, Fname VARCHAR)
user: 找出一门课程的分数至少是3.8的所有学生的不同名字。

assistant: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR), CREATE TABLE STUDENT (StuID VARCHAR, Fname VARCHAR)
user: 在至少一门课程中，成绩在3.8或以上的学生的名字是什么？

assistant: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
Schema: CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR, Fname VARCHAR), CREATE TABLE MEMBER_OF (FacID VARCHAR, DNO VARCHAR)
user: 查找系号为520的系人员中教员的全名。

assistant: SELECT T1.Fname ,  T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID  =  T2.FacID WHERE T2.DNO  =  520
Schema: CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR, Fname VARCHAR), CREATE TABLE MEMBER_OF (FacID VARCHAR, DNO VARCHAR)
user: 系号为520的系人员中教员的全名是什么？

assistant: SELECT T1.Fname ,  T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID  =  T2.FacID WHERE T2.DNO  =  520
Schema: CREATE TABLE MINOR_IN (DNO VARCHAR, StuID VARCHAR), CREATE TABLE STUDENT (Lname VARCHAR, StuID VARCHAR, Fname VARCHAR)
user: 在DNO 140系辅修的学生的名字和姓氏是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
Schema: CREATE TABLE MINOR_IN (DNO VARCHAR, StuID VARCHAR), CREATE TABLE STUDENT (Lname VARCHAR, StuID VARCHAR, Fname VARCHAR)
user: 参与140系辅修课程的学生的全名是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR), CREATE TABLE MEMBER_OF (FacID VARCHAR, DNO VARCHAR)
user: 查找“计算机科学”系成员的姓氏。

assistant: SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO  =  T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID  =  T3.FacID WHERE T1.DName  =  "计算机科学"
Schema: CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR), CREATE TABLE FACULTY (FacID VARCHAR, Lname VARCHAR), CREATE TABLE MEMBER_OF (FacID VARCHAR, DNO VARCHAR)
user: “计算机科学”系教员的姓氏是什么？

assistant: SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO  =  T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID  =  T3.FacID WHERE T1.DName  =  "计算机科学"
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR), CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR)
user: 找出姓"帅"的学生的平均成绩。

assistant: SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.LName  =  "帅"
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR), CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR)
user: 姓"帅"的学生平均成绩是多少？

assistant: SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.LName  =  "帅"
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR), CREATE TABLE STUDENT (city_code VARCHAR, StuID VARCHAR)
user: 住在“上海”的生的最高和最低分数是多少？

assistant: SELECT max(T2.gradepoint) ,  min(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.city_code  =  "上海"
Schema: CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR), CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR), CREATE TABLE STUDENT (city_code VARCHAR, StuID VARCHAR)
user: 给出住在“上海”的学生的最高和最低分数。

assistant: SELECT max(T2.gradepoint) ,  min(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T3.city_code  =  "上海"
Schema: CREATE TABLE COURSE (Credits VARCHAR, CName VARCHAR, Hours VARCHAR)
user: 查找学分为3学分或有1学分但有4学时的课程名称。

assistant: SELECT CName FROM COURSE WHERE Credits  =  3 UNION SELECT CName FROM COURSE WHERE Credits  =  1 AND Hours  =  4
Schema: CREATE TABLE COURSE (Credits VARCHAR, CName VARCHAR, Hours VARCHAR)
user: 学分为3学分或有1学分但有4学时的课程名称是什么？

assistant: SELECT CName FROM COURSE WHERE Credits  =  3 UNION SELECT CName FROM COURSE WHERE Credits  =  1 AND Hours  =  4
Schema: CREATE TABLE DEPARTMENT (Division VARCHAR, DName VARCHAR, Building VARCHAR)
user: 查找在“管理部”部门或在“财务部”部门和建筑“行政”的部门的名称。

assistant: SELECT DName FROM DEPARTMENT WHERE Division  =  "管理部" UNION SELECT DName FROM DEPARTMENT WHERE Division  =  "财务部" AND Building  =  "行政"
Schema: CREATE TABLE DEPARTMENT (Division VARCHAR, DName VARCHAR, Building VARCHAR)
user: 在“管理部”部门或在“财务部”部门和建筑“行政”部门的名称是什么？

assistant: SELECT DName FROM DEPARTMENT WHERE Division  =  "管理部" UNION SELECT DName FROM DEPARTMENT WHERE Division  =  "财务部" AND Building  =  "行政"
Schema: CREATE TABLE STUDENT (StuID VARCHAR, Fname VARCHAR), CREATE TABLE ENROLLED_IN (StuID VARCHAR, Fname VARCHAR)
user: 找到不参加任何课程的学生的名字。

assistant: SELECT Fname FROM STUDENT WHERE StuID NOT IN (SELECT StuID FROM ENROLLED_IN)
Schema: CREATE TABLE STUDENT (StuID VARCHAR, Fname VARCHAR), CREATE TABLE ENROLLED_IN (StuID VARCHAR, Fname VARCHAR)
user: 没有参加课程的所有学生的名字是什么？

assistant: SELECT Fname FROM STUDENT WHERE StuID NOT IN (SELECT StuID FROM ENROLLED_IN)
Schema: CREATE TABLE product_suppliers (product_id VARCHAR, total_amount_purchased VARCHAR)
user: 购买量前三大产品的id是什么？

assistant: SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3
Schema: CREATE TABLE product_suppliers (product_id VARCHAR, total_amount_purchased VARCHAR)
user: 给出购买金额最大的三种产品的ID。

assistant: SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3
Schema: CREATE TABLE products (product_id VARCHAR, product_price VARCHAR, product_type_code VARCHAR)
user: 最便宜产品的产品ID和产品类型是什么？

assistant: SELECT product_id ,  product_type_code FROM products ORDER BY product_price LIMIT 1
Schema: CREATE TABLE products (product_id VARCHAR, product_price VARCHAR, product_type_code VARCHAR)
user: 给出最低价格产品的ID和产品类型。

assistant: SELECT product_id ,  product_type_code FROM products ORDER BY product_price LIMIT 1
Schema: CREATE TABLE products (product_type_code VARCHAR)
user: 查找不同产品类型的数量。

assistant: SELECT count(DISTINCT product_type_code) FROM products
Schema: CREATE TABLE products (product_type_code VARCHAR)
user: 计算不同产品类型的数量。

assistant: SELECT count(DISTINCT product_type_code) FROM products
Schema: CREATE TABLE addresses (address_id VARCHAR, address_details VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR)
user: 返回客户10的地址。

assistant: SELECT T1.address_details FROM addresses AS T1 JOIN customer_addresses AS T2 ON T1.address_id  =  T2.address_id WHERE T2.customer_id  =  10
Schema: CREATE TABLE addresses (address_id VARCHAR, address_details VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR)
user: 客户ID为10的地址是什么？

assistant: SELECT T1.address_details FROM addresses AS T1 JOIN customer_addresses AS T2 ON T1.address_id  =  T2.address_id WHERE T2.customer_id  =  10
Schema: CREATE TABLE staff (staff_id VARCHAR, staff_gender VARCHAR), CREATE TABLE staff_department_assignments (staff_id VARCHAR, job_title_code VARCHAR)
user: 所有职称是“部门经理”的员工的id和性别是什么？

assistant: SELECT T1.staff_id ,  T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.job_title_code  =  "部门经理"
Schema: CREATE TABLE staff (staff_id VARCHAR, staff_gender VARCHAR), CREATE TABLE staff_department_assignments (staff_id VARCHAR, job_title_code VARCHAR)
user: 返回任何职称是“部门经理”的员工的员工ID和性别。

assistant: SELECT T1.staff_id ,  T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.job_title_code  =  "部门经理"
Schema: CREATE TABLE customers (payment_method_code VARCHAR)
user: 对于每个支付方法，返回多少客户使用它。

assistant: SELECT payment_method_code ,  count(*) FROM customers GROUP BY payment_method_code
Schema: CREATE TABLE customers (payment_method_code VARCHAR)
user: 每种付款方式有多少客户使用？

assistant: SELECT payment_method_code ,  count(*) FROM customers GROUP BY payment_method_code
Schema: CREATE TABLE order_items (product_id VARCHAR)
user: 最经常订购的产品的ID是什么？

assistant: SELECT product_id FROM order_items GROUP BY product_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE order_items (product_id VARCHAR)
user: 给最频繁订购的产品的ID。

assistant: SELECT product_id FROM order_items GROUP BY product_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE customers (customer_phone VARCHAR, customer_name VARCHAR, customer_id VARCHAR, customer_email VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR)
user: 订单数量最多的客户的姓名、电话号码和电子邮件地址是什么？

assistant: SELECT T1.customer_name ,  T1.customer_phone ,  T1.customer_email FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T2.customer_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE customers (customer_phone VARCHAR, customer_name VARCHAR, customer_id VARCHAR, customer_email VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR)
user: 返回订单最多的客户的姓名、电话号码和电子邮件地址。

assistant: SELECT T1.customer_name ,  T1.customer_phone ,  T1.customer_email FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T2.customer_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
user: 每种产品的平均价格是多少？

assistant: SELECT product_type_code ,  avg(product_price) FROM products GROUP BY product_type_code
Schema: CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
user: 返回每个产品类型的平均价格。

assistant: SELECT product_type_code ,  avg(product_price) FROM products GROUP BY product_type_code
Schema: CREATE TABLE department_stores (dept_store_chain_id VARCHAR), CREATE TABLE department_store_chain (dept_store_chain_id VARCHAR, dept_store_chain_name VARCHAR)
user: “大洋”连锁店有多少家百货公司？

assistant: SELECT count(*) FROM department_stores AS T1 JOIN department_store_chain AS T2 ON T1.dept_store_chain_id  =  T2.dept_store_chain_id WHERE T2.dept_store_chain_name  =  "大洋"
Schema: CREATE TABLE department_stores (dept_store_chain_id VARCHAR), CREATE TABLE department_store_chain (dept_store_chain_id VARCHAR, dept_store_chain_name VARCHAR)
user: 算一下“大洋”连锁店的数量。

assistant: SELECT count(*) FROM department_stores AS T1 JOIN department_store_chain AS T2 ON T1.dept_store_chain_id  =  T2.dept_store_chain_id WHERE T2.dept_store_chain_name  =  "大洋"
Schema: CREATE TABLE staff (staff_id VARCHAR, staff_name VARCHAR), CREATE TABLE staff_department_assignments (date_assigned_to VARCHAR, staff_id VARCHAR, job_title_code VARCHAR)
user: 最新指派的工作人员的姓名和职称是什么？

assistant: SELECT T1.staff_name ,  T2.job_title_code FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY T2.date_assigned_to DESC LIMIT 1
Schema: CREATE TABLE staff (staff_id VARCHAR, staff_name VARCHAR), CREATE TABLE staff_department_assignments (date_assigned_to VARCHAR, staff_id VARCHAR, job_title_code VARCHAR)
user: 返回最新指派的工作人员的姓名和职称。

assistant: SELECT T1.staff_name ,  T2.job_title_code FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY T2.date_assigned_to DESC LIMIT 1
Schema: CREATE TABLE product_suppliers (product_id VARCHAR, supplier_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_name VARCHAR, product_price VARCHAR, product_type_code VARCHAR)
user: 请告诉我由供应商ID是3提供的所有产品的类型、名称和价格。

assistant: SELECT T2.product_type_code ,  T2.product_name ,  T2.product_price FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  3
Schema: CREATE TABLE product_suppliers (product_id VARCHAR, supplier_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_name VARCHAR, product_price VARCHAR, product_type_code VARCHAR)
user: 返回供应商3提供的产品类型、名称和价格。

assistant: SELECT T2.product_type_code ,  T2.product_name ,  T2.product_price FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  3
Schema: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_status_code VARCHAR, customer_id VARCHAR)
user: 按照客户id的顺序返回订单状态为“延迟”的客户的不同名字。

assistant: SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "延迟" ORDER BY T2.customer_id
Schema: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_status_code VARCHAR, customer_id VARCHAR)
user: 按客户ID排序的具有“延迟”订单状态的客户的不同名字是什么？

assistant: SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "延迟" ORDER BY T2.customer_id
Schema: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, customer_address VARCHAR), CREATE TABLE customer_orders (order_status_code VARCHAR, customer_id VARCHAR)
user: 查找既有“新”订单又有“延迟”订单的客户的名称和地址。

assistant: SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "新" INTERSECT SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "延迟"
Schema: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, customer_address VARCHAR), CREATE TABLE customer_orders (order_status_code VARCHAR, customer_id VARCHAR)
user: 既有“新”订单又有“延迟”的客户的姓名和地址是什么？

assistant: SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "新" INTERSECT SELECT T1.customer_name ,  T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.order_status_code  =  "延迟"
Schema: CREATE TABLE product_suppliers (product_id VARCHAR, supplier_id VARCHAR), CREATE TABLE products (product_price INTEGER)
user: 返回由供应商ID2供应并且比所有产品的平均价格更贵的所有产品的ID。

assistant: SELECT T1.product_id FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  2 AND T2.product_price  >  (SELECT avg(product_price) FROM products)
Schema: CREATE TABLE product_suppliers (product_id VARCHAR, supplier_id VARCHAR), CREATE TABLE products (product_price INTEGER)
user: 来自id 2的供应商的产品的id且比所有产品的平均价格都贵的是id什么？

assistant: SELECT T1.product_id FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id  =  T2.product_id WHERE T1.supplier_id  =  2 AND T2.product_price  >  (SELECT avg(product_price) FROM products)
Schema: CREATE TABLE departments (dept_store_id VARCHAR, department_name VARCHAR), CREATE TABLE department_stores (dept_store_id VARCHAR, store_name VARCHAR)
user: 有“市场”部和“管理”部的百货公司的id和名称是什么？

assistant: SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "市场" INTERSECT SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "管理"
Schema: CREATE TABLE departments (dept_store_id VARCHAR, department_name VARCHAR), CREATE TABLE department_stores (dept_store_id VARCHAR, store_name VARCHAR)
user: 既有“市场”部又有“管理”部百货公司的id和名称是什么？

assistant: SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "市场" INTERSECT SELECT T2.dept_store_id ,  T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id  =  T2.dept_store_id WHERE T1.department_name  =  "管理"
Schema: CREATE TABLE department_stores (dept_store_chain_id VARCHAR)
user: 百货商店数量最多的两家连锁店的ID是什么？

assistant: SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY count(*) DESC LIMIT 2
Schema: CREATE TABLE department_stores (dept_store_chain_id VARCHAR)
user: 返回百货商店数量最多的两家连锁店的ID。

assistant: SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY count(*) DESC LIMIT 2
Schema: CREATE TABLE staff_department_assignments (department_id VARCHAR)
user: 员工人数最少的部门的id是什么？

assistant: SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY count(*) LIMIT 1
Schema: CREATE TABLE staff_department_assignments (department_id VARCHAR)
user: 返回员工人数最少的部门的id。

assistant: SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY count(*) LIMIT 1
Schema: CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
user: 对于每种产品类型，返回最高和最低价格。

assistant: SELECT product_type_code ,  max(product_price) ,  min(product_price) FROM products GROUP BY product_type_code
Schema: CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
user: 每种产品的最高和最低的产品价格是多少？

assistant: SELECT product_type_code ,  max(product_price) ,  min(product_price) FROM products GROUP BY product_type_code
Schema: CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
user: 找出平均价格高于所有产品平均价格的产品类型。

assistant: SELECT product_type_code FROM products GROUP BY product_type_code HAVING avg(product_price)  >  (SELECT avg(product_price) FROM products)
Schema: CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
user: 该类型产品的平均价格高于所有产品平均价格的产品类型的代码是什么？

assistant: SELECT product_type_code FROM products GROUP BY product_type_code HAVING avg(product_price)  >  (SELECT avg(product_price) FROM products)
Schema: CREATE TABLE staff (staff_id VARCHAR, staff_name VARCHAR), CREATE TABLE Staff_Department_Assignments (staff_id VARCHAR)
user: 找到被指派时间最短的员工的id和姓名。

assistant: SELECT T1.staff_id ,  T1.staff_name FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1
Schema: CREATE TABLE staff (staff_id VARCHAR, staff_name VARCHAR), CREATE TABLE Staff_Department_Assignments (staff_id VARCHAR)
user: 被指派时间最短的员工的id和姓名是什么？

assistant: SELECT T1.staff_id ,  T1.staff_name FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id  =  T2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1