jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (department_id VARCHAR)
user: 每个部门的部门名称和每个部门对应的员工人数是多少？

assistant: SELECT department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY department_name
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (location_id VARCHAR, city VARCHAR)
user: 显示在“北京”工作的员工的全名（名字和姓氏）和薪水。

assistant: SELECT first_name ,  last_name ,  salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN  locations AS T3 ON T2.location_id  =  T3.location_id WHERE  T3.city  =  '北京'
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (location_id VARCHAR, city VARCHAR)
user: 在“北京”工作的员工的全名和薪水是多少？

assistant: SELECT first_name ,  last_name ,  salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN  locations AS T3 ON T2.location_id  =  T3.location_id WHERE  T3.city  =  '北京'
Schema: CREATE TABLE song (song_name VARCHAR, releasedate VARCHAR)
user: 最近一年发行的歌叫什么名字？

assistant: SELECT song_name ,  releasedate FROM song ORDER BY releasedate DESC LIMIT 1
Schema: CREATE TABLE song (song_name VARCHAR, releasedate VARCHAR)
user: 最近发行的那首歌叫什么名字？

assistant: SELECT song_name ,  releasedate FROM song ORDER BY releasedate DESC LIMIT 1
Schema: CREATE TABLE files (duration VARCHAR, f_id VARCHAR)
user: 最长的歌的ID是什么？

assistant: SELECT f_id FROM files ORDER BY duration DESC LIMIT 1
Schema: CREATE TABLE files (duration VARCHAR, f_id VARCHAR)
user: 找出最长的歌曲的ID。

assistant: SELECT f_id FROM files ORDER BY duration DESC LIMIT 1
Schema: CREATE TABLE song (song_name VARCHAR, languages VARCHAR)
user: 找出所有“英文”歌曲的名字。

assistant: SELECT song_name FROM song WHERE languages  =  "英文"
Schema: CREATE TABLE song (song_name VARCHAR, languages VARCHAR)
user: 所有“英文”歌曲的名字是什么？

assistant: SELECT song_name FROM song WHERE languages  =  "英文"
Schema: CREATE TABLE files (f_id VARCHAR, formats VARCHAR)
user: 格式为“MP3”的歌曲的ID是什么？

assistant: SELECT f_id FROM files WHERE formats  =  "mp3"
Schema: CREATE TABLE files (f_id VARCHAR, formats VARCHAR)
user: “MP3”格式的所有文件的ID是什么？

assistant: SELECT f_id FROM files WHERE formats  =  "mp3"
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (rating INTEGER, artist_name VARCHAR)
user: 列出所有评分在9以上的歌曲的歌手的姓名和原籍国。

assistant: SELECT DISTINCT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.rating  >  9
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (rating INTEGER, artist_name VARCHAR)
user: 所有评分在9以上的歌曲的歌手的姓名和原籍国是什么？

assistant: SELECT DISTINCT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.rating  >  9
Schema: CREATE TABLE files (file_size VARCHAR, f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR)
user: 列出所有分辨率低于800的歌曲的文件大小和格式。

assistant: SELECT DISTINCT T1.file_size ,  T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T2.resolution  <  800
Schema: CREATE TABLE files (file_size VARCHAR, f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR)
user: 分辨率低于800的所有歌曲的文件大小和格式是什么？

assistant: SELECT DISTINCT T1.file_size ,  T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T2.resolution  <  800
Schema: CREATE TABLE song (f_id VARCHAR, artist_name VARCHAR), CREATE TABLE files (duration VARCHAR, f_id VARCHAR)
user: 制作最短歌曲的艺术家叫什么名字？

assistant: SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id  =  T2.f_id ORDER BY T2.duration LIMIT 1
Schema: CREATE TABLE song (f_id VARCHAR, artist_name VARCHAR), CREATE TABLE files (duration VARCHAR, f_id VARCHAR)
user: 演唱最短歌曲的艺术家的名字是什么？

assistant: SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id  =  T2.f_id ORDER BY T2.duration LIMIT 1
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (rating VARCHAR, artist_name VARCHAR)
user: 制作评分最高的三首歌曲的艺术家的名字和原籍国是什么？

assistant: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.rating DESC LIMIT 3
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (rating VARCHAR, artist_name VARCHAR)
user: 演唱三大最受欢迎歌曲的歌手的名字是什么？他们来自哪个国家？

assistant: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.rating DESC LIMIT 3
Schema: CREATE TABLE files (duration VARCHAR)
user: 有多少歌曲有“4”分钟的持续时间？

assistant: SELECT count(*) FROM files WHERE duration LIKE "4:%"
Schema: CREATE TABLE files (duration VARCHAR)
user: 能持续约“4”分钟的歌曲的总数是多少？

assistant: SELECT count(*) FROM files WHERE duration LIKE "4:%"
Schema: CREATE TABLE artist (country VARCHAR)
user: 有多少艺术家来自“孟加拉国”？

assistant: SELECT count(*) FROM artist WHERE country  =  "孟加拉国"
Schema: CREATE TABLE artist (country VARCHAR)
user: 有多少“孟加拉国”的艺术家在表中？

assistant: SELECT count(*) FROM artist WHERE country  =  "孟加拉国"
Schema: CREATE TABLE artist (gender VARCHAR, artist_name VARCHAR), CREATE TABLE song (artist_name VARCHAR, rating INTEGER)
user: “女性”艺人创作的歌曲平均评级是多少？

assistant: SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "女"
Schema: CREATE TABLE artist (gender VARCHAR, artist_name VARCHAR), CREATE TABLE song (artist_name VARCHAR, rating INTEGER)
user: “女性”歌手演唱的平均歌曲数是多少？

assistant: SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "女"
Schema: CREATE TABLE files (formats VARCHAR)
user: 什么是最流行的文件格式？

assistant: SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1
Schema: CREATE TABLE files (formats VARCHAR)
user: 找到大多数文件使用的文件格式。

assistant: SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1
Schema: CREATE TABLE artist (country VARCHAR, languages VARCHAR, artist_name VARCHAR), CREATE TABLE song (country VARCHAR, languages VARCHAR, artist_name VARCHAR)
user: 找出来自“英国”并制作了“英文”歌曲的艺术家的名字。

assistant: SELECT artist_name FROM artist WHERE country  =  "英国" INTERSECT SELECT artist_name FROM song WHERE languages  =  "英文"
Schema: CREATE TABLE artist (country VARCHAR, languages VARCHAR, artist_name VARCHAR), CREATE TABLE song (country VARCHAR, languages VARCHAR, artist_name VARCHAR)
user: 来自“英国”且用“英文”唱歌的艺术家的名字是什么？

assistant: SELECT artist_name FROM artist WHERE country  =  "英国" INTERSECT SELECT artist_name FROM song WHERE languages  =  "英文"
Schema: CREATE TABLE files (resolution INTEGER, f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR, formats VARCHAR)
user: 找出可用“mp4”格式且分辨率低于1000的歌曲的ID。

assistant: SELECT f_id FROM files WHERE formats  =  "mp4" INTERSECT SELECT f_id FROM song WHERE resolution  <  1000
Schema: CREATE TABLE files (resolution INTEGER, f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR, formats VARCHAR)
user: 可用“mp4”格式且分辨率低于1000的歌曲的ID是什么？

assistant: SELECT f_id FROM files WHERE formats  =  "mp4" INTERSECT SELECT f_id FROM song WHERE resolution  <  1000
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR, gender VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 用“孟加拉语”创作的“女性”艺术家的原籍国是什么？

assistant: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "女" AND T2.languages  =  "孟加拉语"
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR, gender VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: “孟加拉语”创作的“女性”艺术家来自哪个国家？

assistant: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T1.gender  =  "女" AND T2.languages  =  "孟加拉语"
Schema: CREATE TABLE files (f_id VARCHAR, formats VARCHAR, duration INTEGER), CREATE TABLE song (resolution INTEGER, f_id VARCHAR)
user: 格式为“mp3”且分辨率低于800的歌曲的平均持续时间是多少？

assistant: SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" AND T2.resolution   <  800
Schema: CREATE TABLE files (f_id VARCHAR, formats VARCHAR, duration INTEGER), CREATE TABLE song (resolution INTEGER, f_id VARCHAR)
user: “mp3”格式且分辨率低于800的所有歌曲的平均歌曲持续时间是多长？

assistant: SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" AND T2.resolution   <  800
Schema: CREATE TABLE artist (gender VARCHAR)
user: 每个性别的艺术家数量是多少？

assistant: SELECT count(*) ,  gender FROM artist GROUP BY gender
Schema: CREATE TABLE artist (gender VARCHAR)
user: 有多少艺术家是男性，有多少艺术家是女性？

assistant: SELECT count(*) ,  gender FROM artist GROUP BY gender
Schema: CREATE TABLE song (languages VARCHAR, rating INTEGER)
user: 每种语言的歌曲的平均评分是多少？

assistant: SELECT avg(rating) ,  languages FROM song GROUP BY languages
Schema: CREATE TABLE song (languages VARCHAR, rating INTEGER)
user: 每种语言的平均歌曲评分是多少？

assistant: SELECT avg(rating) ,  languages FROM song GROUP BY languages
Schema: CREATE TABLE artist (artist_name VARCHAR, gender VARCHAR), CREATE TABLE song (resolution VARCHAR, artist_name VARCHAR)
user: 返回制作分辨率最低的歌曲的艺术家的性别和姓名。

assistant: SELECT T1.gender ,  T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.resolution LIMIT 1
Schema: CREATE TABLE artist (artist_name VARCHAR, gender VARCHAR), CREATE TABLE song (resolution VARCHAR, artist_name VARCHAR)
user: 制作分辨率最低的歌曲的艺术家的性别和姓名是什么？

assistant: SELECT T1.gender ,  T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name ORDER BY T2.resolution LIMIT 1
Schema: CREATE TABLE files (formats VARCHAR)
user: 对于每个文件格式，返回以该格式发布歌曲的艺术家的数量。

assistant: SELECT count(*) ,  formats FROM files GROUP BY formats
Schema: CREATE TABLE files (formats VARCHAR)
user: 每种不同的音乐格式发行了多少首歌？

assistant: SELECT count(*) ,  formats FROM files GROUP BY formats
Schema: CREATE TABLE song (resolution INTEGER, song_name VARCHAR, languages VARCHAR)
user: 找出所有比“英文”歌曲分辨率更高的歌曲的不同名称。

assistant: SELECT DISTINCT song_name FROM song WHERE resolution  >  (SELECT min(resolution) FROM song WHERE languages  =  "英文")
Schema: CREATE TABLE song (resolution INTEGER, song_name VARCHAR, languages VARCHAR)
user: 对于分辨率高于“英文”歌曲的所有不同歌曲的名字是什么？

assistant: SELECT DISTINCT song_name FROM song WHERE resolution  >  (SELECT min(resolution) FROM song WHERE languages  =  "英文")
Schema: CREATE TABLE song (song_name VARCHAR, genre_is VARCHAR, rating INTEGER)
user: 评价比“蓝调”风格的歌曲低的歌曲名字是什么？

assistant: SELECT song_name FROM song WHERE rating  <  (SELECT max(rating) FROM song WHERE genre_is  =  "蓝调")
Schema: CREATE TABLE song (song_name VARCHAR, genre_is VARCHAR, rating INTEGER)
user: 比至少一首“蓝调”歌曲的评级低的歌曲的名字是什么？

assistant: SELECT song_name FROM song WHERE rating  <  (SELECT max(rating) FROM song WHERE genre_is  =  "蓝调")
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (song_name VARCHAR, artist_name VARCHAR)
user: 发行了一首标题中包含“爱”字的歌曲的艺术家的名字和原籍国是什么？

assistant: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.song_name LIKE "爱"
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (song_name VARCHAR, artist_name VARCHAR)
user: 发行了一首名为“爱”的歌曲的艺术家叫什么名字？这些艺术家来自哪里？

assistant: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.song_name LIKE "爱"
Schema: CREATE TABLE artist (gender VARCHAR, artist_name VARCHAR), CREATE TABLE song (releasedate VARCHAR, artist_name VARCHAR)
user: 列出在“三月”发布歌曲的所有艺人的姓名和性别。

assistant: SELECT T1.artist_name ,  T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.releasedate LIKE "三月"
Schema: CREATE TABLE artist (gender VARCHAR, artist_name VARCHAR), CREATE TABLE song (releasedate VARCHAR, artist_name VARCHAR)
user: 在“三月”发行歌曲的所有艺术家的姓名和性别是什么？

assistant: SELECT T1.artist_name ,  T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.releasedate LIKE "三月"
Schema: CREATE TABLE genre (rating VARCHAR, g_name VARCHAR)
user: 按字母顺序列出所有流派的名称及他们对应的评级。

assistant: SELECT g_name ,  rating FROM genre ORDER BY g_name
Schema: CREATE TABLE genre (rating VARCHAR, g_name VARCHAR)
user: 按字母顺序排列的所有流派的名称及其评级是什么？

assistant: SELECT g_name ,  rating FROM genre ORDER BY g_name
Schema: CREATE TABLE song (song_name VARCHAR, resolution VARCHAR)
user: 按分辨率排序列出所有歌曲的名称。

assistant: SELECT song_name FROM song ORDER BY resolution
Schema: CREATE TABLE song (song_name VARCHAR, resolution VARCHAR)
user: 根据他们的分辨率数字列出的歌曲的名字是什么？

assistant: SELECT song_name FROM song ORDER BY resolution
Schema: CREATE TABLE files (resolution INTEGER, f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR, formats VARCHAR)
user: 那些歌曲在“mp4”格式或者分辨率高于720的歌曲中是可用的？列出可用歌曲的id。

assistant: SELECT f_id FROM files WHERE formats  =  "mp4" UNION SELECT f_id FROM song WHERE resolution  >  720
Schema: CREATE TABLE files (resolution INTEGER, f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR, formats VARCHAR)
user: 在“mp4”格式上或分辨率高于720的所有可用歌曲的id是什么？

assistant: SELECT f_id FROM files WHERE formats  =  "mp4" UNION SELECT f_id FROM song WHERE resolution  >  720
Schema: CREATE TABLE files (duration VARCHAR, f_id VARCHAR), CREATE TABLE song (song_name VARCHAR, languages VARCHAR)
user: 列出所有有“4”分钟持续时间或语言是“英文”的歌曲的名字。

assistant: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages  =  "英文"
Schema: CREATE TABLE files (duration VARCHAR, f_id VARCHAR), CREATE TABLE song (song_name VARCHAR, languages VARCHAR)
user: 大约“4”分钟长的歌曲或语言是“英文”歌曲的名称是什么？

assistant: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages  =  "英文"
Schema: CREATE TABLE song (languages VARCHAR)
user: 歌曲中最常用的语言是什么？

assistant: SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE song (languages VARCHAR)
user: 在歌曲中最经常被使用的语言是什么？

assistant: SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE song (resolution INTEGER, languages VARCHAR, artist_name VARCHAR)
user: 在分辨率超过500的歌曲中，最常用的语言是什么？

assistant: SELECT artist_name FROM song WHERE resolution  >  500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE song (resolution INTEGER, languages VARCHAR, artist_name VARCHAR)
user: 每种语言具有最多数量超过500分辨率的歌曲的歌手叫什么名字？

assistant: SELECT artist_name FROM song WHERE resolution  >  500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR, gender VARCHAR)
user: 来自“英国”的“男”艺术家的名字是什么？

assistant: SELECT artist_name FROM artist WHERE country  =  "英国" AND gender  =  "男"
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR, gender VARCHAR)
user: 所有“英国”的“男”艺术家的名字是什么？

assistant: SELECT artist_name FROM artist WHERE country  =  "英国" AND gender  =  "男"
Schema: CREATE TABLE song (song_name VARCHAR, genre_is VARCHAR, languages VARCHAR)
user: 找出体裁是“现代”的或语言是“英文”的歌曲的名字。

assistant: SELECT song_name FROM song WHERE genre_is  =  "现代" OR languages  =  "英文"
Schema: CREATE TABLE song (song_name VARCHAR, genre_is VARCHAR, languages VARCHAR)
user: 体裁是“现代”的或语言是“英文”的歌曲的名字是什么？

assistant: SELECT song_name FROM song WHERE genre_is  =  "现代" OR languages  =  "英文"
Schema: CREATE TABLE files (f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, song_name VARCHAR)
user: 返回格式为“MP3”且分辨率低于1000的歌曲名称。

assistant: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" INTERSECT SELECT song_name FROM song WHERE resolution  <  1000
Schema: CREATE TABLE files (f_id VARCHAR, formats VARCHAR), CREATE TABLE song (resolution INTEGER, song_name VARCHAR)
user: 所有“mp3”格式且分辨率低于1000的歌曲的名称是什么？

assistant: SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.formats  =  "mp3" INTERSECT SELECT song_name FROM song WHERE resolution  <  1000
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 返回来自“英国”并发布一首“英文”歌曲的歌手的名字。

assistant: SELECT artist_name FROM artist WHERE country  =  "英国" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "英文"
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 所有来自“英国”且用“英文”发行歌曲的歌手的名字是什么？

assistant: SELECT artist_name FROM artist WHERE country  =  "英国" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "英文"
Schema: CREATE TABLE song (resolution INTEGER, languages VARCHAR, rating INTEGER)
user: “孟加拉语”歌曲的平均评分和分辨率是多少？

assistant: SELECT avg(rating) ,  avg(resolution) FROM song WHERE languages  =  "孟加拉语"
Schema: CREATE TABLE song (resolution INTEGER, languages VARCHAR, rating INTEGER)
user: 所有“孟加拉语”歌曲的平均评级和分辨率是多少？

assistant: SELECT avg(rating) ,  avg(resolution) FROM song WHERE languages  =  "孟加拉语"
Schema: CREATE TABLE files (duration VARCHAR, f_id VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR)
user: 持续时间为“3”分钟的歌曲的最大分辨率和最小分辨率是什么？

assistant: SELECT max(T2.resolution) ,  min(T2.resolution) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "3:%"
Schema: CREATE TABLE files (duration VARCHAR, f_id VARCHAR), CREATE TABLE song (resolution INTEGER, f_id VARCHAR)
user: 大约“3”分钟长的所有歌曲的最大和最小分辨率是多少？

assistant: SELECT max(T2.resolution) ,  min(T2.resolution) FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id WHERE T1.duration LIKE "3:%"
Schema: CREATE TABLE files (f_id VARCHAR, duration INTEGER), CREATE TABLE song (resolution INTEGER, f_id VARCHAR, languages VARCHAR)
user: 按语言分组和排序的歌曲的最大持续时间和分辨率是多少？

assistant: SELECT max(T1.duration) ,  max(T2.resolution) ,  T2.languages FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.languages ORDER BY T2.languages
Schema: CREATE TABLE files (f_id VARCHAR, duration INTEGER), CREATE TABLE song (resolution INTEGER, f_id VARCHAR, languages VARCHAR)
user: 按语言字母顺序排列的每种语言的所有歌曲的最大持续时间和分辨率是多少？

assistant: SELECT max(T1.duration) ,  max(T2.resolution) ,  T2.languages FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.languages ORDER BY T2.languages
Schema: CREATE TABLE files (f_id VARCHAR, duration INTEGER), CREATE TABLE song (genre_is VARCHAR, f_id VARCHAR, rating INTEGER)
user: 按体裁分组并排序的歌曲的最短持续时间和最低评级是什么？

assistant: SELECT min(T1.duration) ,  min(T2.rating) ,  T2.genre_is FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.genre_is ORDER BY T2.genre_is
Schema: CREATE TABLE files (f_id VARCHAR, duration INTEGER), CREATE TABLE song (genre_is VARCHAR, f_id VARCHAR, rating INTEGER)
user: 按体裁的字母顺序排列的每种体裁最短且评分最低的歌曲是什么？

assistant: SELECT min(T1.duration) ,  min(T2.rating) ,  T2.genre_is FROM files AS T1 JOIN song AS T2 ON T1.f_id  =  T2.f_id GROUP BY T2.genre_is ORDER BY T2.genre_is
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 找出所有至少有一首“英文”歌曲的艺术家的名字和作品数量。

assistant: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "英文" GROUP BY T2.artist_name HAVING count(*)  >=  1
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 所有至少唱过一首“英文”歌曲的艺术家作品的名称和数量是多少？

assistant: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "英文" GROUP BY T2.artist_name HAVING count(*)  >=  1
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (resolution INTEGER, artist_name VARCHAR)
user: 找出所有已经发布了900首以上分辨率歌曲的艺术家的名字和原籍国。

assistant: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.resolution  >  900 GROUP BY T2.artist_name HAVING count(*)  >=  1
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (resolution INTEGER, artist_name VARCHAR)
user: 每位发行了一首分辨率超过900的歌曲的艺术家的名字和原籍国是什么？

assistant: SELECT T1.artist_name ,  T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.resolution  >  900 GROUP BY T2.artist_name HAVING count(*)  >=  1
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (artist_name VARCHAR)
user: 找出制作歌曲最多的三位艺术家的姓名和作品数量。

assistant: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (artist_name VARCHAR)
user: 制作歌曲最多的三位艺术家的名字是什么？他们制作了多少作品？

assistant: SELECT T1.artist_name ,  count(*) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (artist_name VARCHAR)
user: 找出歌手数量最少的国家？

assistant: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) LIMIT 1
Schema: CREATE TABLE artist (country VARCHAR, artist_name VARCHAR), CREATE TABLE song (artist_name VARCHAR)
user: 制作歌曲最少的艺术家来自于哪个国家？

assistant: SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name GROUP BY T2.artist_name ORDER BY count(*) LIMIT 1
Schema: CREATE TABLE song (song_name VARCHAR, languages VARCHAR, rating INTEGER)
user: 哪些歌曲的评级低于所有“英文”歌曲的评级？

assistant: SELECT song_name FROM song WHERE rating  <   (SELECT min(rating) FROM song WHERE languages  =  '英文')
Schema: CREATE TABLE song (song_name VARCHAR, languages VARCHAR, rating INTEGER)
user: 评分低于最低“英文”歌曲的每首歌曲的名称是什么？

assistant: SELECT song_name FROM song WHERE rating  <   (SELECT min(rating) FROM song WHERE languages  =  '英文')
Schema: CREATE TABLE song (resolution INTEGER, f_id VARCHAR, rating INTEGER)
user: 分辨率高于任何评级低于8的歌曲的分辨率的歌曲的id是什么？

assistant: SELECT f_id FROM song WHERE resolution  >  (SELECT max(resolution) FROM song WHERE rating  <  8)
Schema: CREATE TABLE song (resolution INTEGER, f_id VARCHAR, rating INTEGER)
user: 高于评级低于8的歌曲的分辨率的所有歌曲的id是多少呢？

assistant: SELECT f_id FROM song WHERE resolution  >  (SELECT max(resolution) FROM song WHERE rating  <  8)
Schema: CREATE TABLE song (resolution INTEGER, genre_is VARCHAR, f_id VARCHAR)
user: 在现代流派中，分辨率高于平均分辨率的歌曲的id是什么？

assistant: SELECT f_id FROM song WHERE resolution  >  (SELECT avg(resolution) FROM song WHERE genre_is  =  "现代")
Schema: CREATE TABLE song (resolution INTEGER, genre_is VARCHAR, f_id VARCHAR)
user: 在“现代”音乐流派中，所有具有高于平均分辨率的歌曲的id是什么？

assistant: SELECT f_id FROM song WHERE resolution  >  (SELECT avg(resolution) FROM song WHERE genre_is  =  "现代")
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 找出“孟加拉语”歌曲数量前3多的艺术家。

assistant: SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "孟加拉语" GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE artist (artist_name VARCHAR), CREATE TABLE song (languages VARCHAR, artist_name VARCHAR)
user: 用“孟加拉语”演唱的歌曲数量最多的前三位艺术家有哪些？

assistant: SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name  =  T2.artist_name WHERE T2.languages  =  "孟加拉语" GROUP BY T2.artist_name ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE song (rating VARCHAR, f_id VARCHAR, languages VARCHAR, artist_name VARCHAR, genre_is VARCHAR)
user: 列出按评级排序的“英文”歌曲的ID、流派和艺术家名字。

assistant: SELECT f_id ,  genre_is ,  artist_name FROM song WHERE languages  =   "英文" ORDER BY rating