jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE weather (max_temperature_f VARCHAR, min_temperature_f VARCHAR, date VARCHAR)
user: 找出最大温度与最小温度之差最小的一天。并报告差异。

assistant: SELECT date ,  max_temperature_f - min_temperature_f FROM weather ORDER BY max_temperature_f - min_temperature_f LIMIT 1
Schema: CREATE TABLE weather (max_temperature_f VARCHAR, min_temperature_f VARCHAR, date VARCHAR)
user: 哪些天具有最小的温度范围，那个范围是什么？

assistant: SELECT date ,  max_temperature_f - min_temperature_f FROM weather ORDER BY max_temperature_f - min_temperature_f LIMIT 1
Schema: CREATE TABLE station (name VARCHAR, id VARCHAR), CREATE TABLE status (station_id VARCHAR, bikes_available INTEGER)
user: 有超过12辆可用自行车的车站的ID和名称是什么？

assistant: SELECT DISTINCT T1.id ,  T1.name FROM station AS T1 JOIN status AS T2 ON T1.id  =  T2.station_id WHERE T2.bikes_available  >  12
Schema: CREATE TABLE station (name VARCHAR, id VARCHAR), CREATE TABLE status (station_id VARCHAR, bikes_available INTEGER)
user: 有超过12辆可用自行车的车站有哪些不同的ID和名称？

assistant: SELECT DISTINCT T1.id ,  T1.name FROM station AS T1 JOIN status AS T2 ON T1.id  =  T2.station_id WHERE T2.bikes_available  >  12
Schema: CREATE TABLE weather (mean_humidity INTEGER, zip_code VARCHAR), CREATE TABLE trip (mean_humidity INTEGER, zip_code VARCHAR)
user: 给我平均湿度低于70，至少有100个路线的地区邮编。

assistant: SELECT zip_code FROM weather GROUP BY zip_code HAVING avg(mean_humidity)  <  70 INTERSECT SELECT zip_code FROM trip GROUP BY zip_code HAVING count(*)  >=  100
Schema: CREATE TABLE weather (mean_humidity INTEGER, zip_code VARCHAR), CREATE TABLE trip (mean_humidity INTEGER, zip_code VARCHAR)
user: 平均湿度低于70并且至少有100次旅行的邮政编码是什么？

assistant: SELECT zip_code FROM weather GROUP BY zip_code HAVING avg(mean_humidity)  <  70 INTERSECT SELECT zip_code FROM trip GROUP BY zip_code HAVING count(*)  >=  100
Schema: CREATE TABLE station (city VARCHAR, name VARCHAR, end_station_name VARCHAR), CREATE TABLE trip (city VARCHAR, name VARCHAR, end_station_name VARCHAR)
user: 位于“西安”市但没能成为100次以上路线的终点的车站叫什么名字？

assistant: SELECT name FROM station WHERE city  =  "西安" EXCEPT SELECT end_station_name FROM trip GROUP BY end_station_name HAVING count(*)  >  100
Schema: CREATE TABLE station (city VARCHAR, name VARCHAR, end_station_name VARCHAR), CREATE TABLE trip (city VARCHAR, name VARCHAR, end_station_name VARCHAR)
user: 位于“西安”但从未成为路线终点的车站叫什么名字？

assistant: SELECT name FROM station WHERE city  =  "西安" EXCEPT SELECT end_station_name FROM trip GROUP BY end_station_name HAVING count(*)  >  100
Schema: CREATE TABLE station (city VARCHAR, id VARCHAR), CREATE TABLE trip (end_station_id VARCHAR, id VARCHAR)
user: 从“重庆”出发到“西安”有多少路线？

assistant: SELECT count(*) FROM station AS T1 JOIN trip AS T2 JOIN station AS T3 JOIN trip AS T4 ON T1.id  =  T2.start_station_id AND T2.id  =  T4.id AND T3.id  =  T4.end_station_id WHERE T1.city  =  "重庆" AND T3.city  =  "西安"
Schema: CREATE TABLE station (city VARCHAR, id VARCHAR), CREATE TABLE trip (end_station_id VARCHAR, id VARCHAR)
user: 从“重庆”的一个车站到“西安”的一个车站，总共有多少次旅行？

assistant: SELECT count(*) FROM station AS T1 JOIN trip AS T2 JOIN station AS T3 JOIN trip AS T4 ON T1.id  =  T2.start_station_id AND T2.id  =  T4.id AND T3.id  =  T4.end_station_id WHERE T1.city  =  "重庆" AND T3.city  =  "西安"
Schema: CREATE TABLE station (id VARCHAR, long INTEGER, lat INTEGER), CREATE TABLE trip (start_station_id VARCHAR)
user: 所有路线起点的平均纬度和经度是多少？

assistant: SELECT avg(T1.lat) ,  avg(T1.long) FROM station AS T1 JOIN trip AS T2 ON T1.id  =  T2.start_station_id
Schema: CREATE TABLE station (id VARCHAR, long INTEGER, lat INTEGER), CREATE TABLE trip (start_station_id VARCHAR)
user: 所有出发站的平均纬度和经度是多少？

assistant: SELECT avg(T1.lat) ,  avg(T1.long) FROM station AS T1 JOIN trip AS T2 ON T1.id  =  T2.start_station_id
Schema: CREATE TABLE book (Id VARCHAR)
user: 有多少本书？

assistant: SELECT count(*) FROM book
Schema: CREATE TABLE book (Writer VARCHAR)
user: 按字母顺序列出书的作者。

assistant: SELECT Writer FROM book ORDER BY Writer ASC
Schema: CREATE TABLE book (Issues VARCHAR, Title VARCHAR)
user: 按出版升序排列，列出书名。

assistant: SELECT Title FROM book ORDER BY Issues ASC
Schema: CREATE TABLE book (Writer VARCHAR, Title VARCHAR)
user: 作者不是“钱钟书”的书名是什么？

assistant: SELECT Title FROM book WHERE Writer != "钱钟书"
Schema: CREATE TABLE book (Issues VARCHAR, Title VARCHAR)
user: 书的题目和出版是什么？

assistant: SELECT Title ,  Issues FROM book
Schema: CREATE TABLE publication (Price VARCHAR, Publication_Date VARCHAR)
user: 按价格降序排列的出版物日期是什么？

assistant: SELECT Publication_Date FROM publication ORDER BY Price DESC
Schema: CREATE TABLE publication (Price INTEGER, Publisher VARCHAR)
user: 哪些不同出版商有格高于5000000的出版物？

assistant: SELECT DISTINCT Publisher FROM publication WHERE Price  >  5000000
Schema: CREATE TABLE publication (Price VARCHAR, Publisher VARCHAR)
user: 列出出版物价格最高的出版商。

assistant: SELECT Publisher FROM publication ORDER BY Price DESC LIMIT 1
Schema: CREATE TABLE publication (Price VARCHAR, Publication_Date VARCHAR)
user: 列出3个最低价格的出版物的出版日期。

assistant: SELECT Publication_Date FROM publication ORDER BY Price ASC LIMIT 3
Schema: CREATE TABLE book (Book_ID VARCHAR, Title VARCHAR), CREATE TABLE publication (Book_ID VARCHAR, Publication_Date VARCHAR)
user: 显示图书的书名和出版日期。

assistant: SELECT T1.Title ,  T2.Publication_Date FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID  =  T2.Book_ID
Schema: CREATE TABLE book (Book_ID VARCHAR, Writer VARCHAR), CREATE TABLE publication (Book_ID VARCHAR, Price INTEGER)
user: 显示已经出版的一本价格超过4000000的书的作家。

assistant: SELECT T1.Writer FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID  =  T2.Book_ID WHERE T2.Price  >  4000000
Schema: CREATE TABLE book (Book_ID VARCHAR, Title VARCHAR), CREATE TABLE publication (Book_ID VARCHAR, Price VARCHAR)
user: 按出版物价格的顺序显示书名。

assistant: SELECT T1.Title FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID  =  T2.Book_ID ORDER BY T2.Price DESC
Schema: CREATE TABLE publication (Publisher VARCHAR)
user: 显示有不止一个出版物的出版商。

assistant: SELECT Publisher FROM publication GROUP BY Publisher HAVING COUNT(*)  >  1
Schema: CREATE TABLE publication (Publisher VARCHAR)
user: 展示不同的出版商以及他们出版的出版物数量。

assistant: SELECT Publisher ,  COUNT(*) FROM publication GROUP BY Publisher
Schema: CREATE TABLE publication (Publication_Date VARCHAR)
user: 请显示最常见的出版日期。

assistant: SELECT Publication_Date FROM publication GROUP BY Publication_Date ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE book (Writer VARCHAR)
user: 列出那些写过不止一本书的作家。

assistant: SELECT Writer FROM book GROUP BY Writer HAVING COUNT(*)  >  1
Schema: CREATE TABLE book (Book_ID VARCHAR, Title VARCHAR), CREATE TABLE publication (Book_ID VARCHAR, Title VARCHAR)
user: 列出未出版的书名。

assistant: SELECT Title FROM book WHERE Book_ID NOT IN (SELECT Book_ID FROM publication)
Schema: CREATE TABLE publication (Price INTEGER, Publisher VARCHAR)
user: 显示价格高于10000000和价格低于50000000的出版物的出版商。

assistant: SELECT Publisher FROM publication WHERE Price  >  10000000 INTERSECT SELECT Publisher FROM publication WHERE Price  <  5000000
Schema: CREATE TABLE publication (Publication_Date VARCHAR)
user: 不同出版日期的出版物数量是多少？

assistant: SELECT COUNT (DISTINCT Publication_Date) FROM publication
Schema: CREATE TABLE publication (Publication_Date VARCHAR)
user: 我们的记录中有多少种不同的出版日期？

assistant: SELECT COUNT (DISTINCT Publication_Date) FROM publication
Schema: CREATE TABLE publication (Price VARCHAR, Publisher VARCHAR)
user: 显示出版商是“文学”或“机械”的出版物价格。

assistant: SELECT Price FROM publication WHERE Publisher  =  "文学" OR Publisher  =  "机械"
Schema: CREATE TABLE actor (Id VARCHAR)
user: 那儿有多少演员？

assistant: SELECT count(*) FROM actor
Schema: CREATE TABLE actor (Id VARCHAR)
user: 统计演员的数量。

assistant: SELECT count(*) FROM actor
Schema: CREATE TABLE actor (Name VARCHAR)
user: 按照升序字母顺序列出演员的名字。

assistant: SELECT Name FROM actor ORDER BY Name ASC
Schema: CREATE TABLE actor (Name VARCHAR)
user: 演员的名字是什么，按字母顺序排列？

assistant: SELECT Name FROM actor ORDER BY Name ASC
Schema: CREATE TABLE actor (Character VARCHAR, Duration VARCHAR)
user: 演员的角色和持续时间是什么？

assistant: SELECT Character ,  Duration FROM actor
Schema: CREATE TABLE actor (Character VARCHAR, Duration VARCHAR)
user: 返回每个演员的角色和持续时间。

assistant: SELECT Character ,  Duration FROM actor
Schema: CREATE TABLE actor (Age VARCHAR, Name VARCHAR)
user: 列出年龄不是20岁的演员的名字。

assistant: SELECT Name FROM actor WHERE Age != 20
Schema: CREATE TABLE actor (Age VARCHAR, Name VARCHAR)
user: 不是20岁的演员的名字是什么？

assistant: SELECT Name FROM actor WHERE Age != 20
Schema: CREATE TABLE actor (age VARCHAR, Character VARCHAR)
user: 按照年龄降序，演员的角色是什么？

assistant: SELECT Character FROM actor ORDER BY age DESC
Schema: CREATE TABLE actor (age VARCHAR, Character VARCHAR)
user: 返回演员的角色，按年龄降序排序。

assistant: SELECT Character FROM actor ORDER BY age DESC
Schema: CREATE TABLE actor (Age VARCHAR, Duration VARCHAR)
user: 最老演员的持续时间是多少？

assistant: SELECT Duration FROM actor ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE actor (Age VARCHAR, Duration VARCHAR)
user: 返回最大年龄的演员的持续时间。

assistant: SELECT Duration FROM actor ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE musical (Nominee VARCHAR, Name VARCHAR)
user: 提名“梁朝伟”的音乐剧名称是什么？

assistant: SELECT Name FROM musical WHERE Nominee  =  "梁朝伟"
Schema: CREATE TABLE musical (Nominee VARCHAR, Name VARCHAR)
user: 返回有提名“梁朝伟”的音乐剧名称。

assistant: SELECT Name FROM musical WHERE Nominee  =  "梁朝伟"
Schema: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR)
user: 除了“金鸡奖”之外，还有哪些音乐剧的不同提名呢？

assistant: SELECT DISTINCT Nominee FROM musical WHERE Award != "金鸡奖"
Schema: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR)
user: 返回奖项不是“金鸡奖”的音乐剧的不同提名。

assistant: SELECT DISTINCT Nominee FROM musical WHERE Award != "金鸡奖"
Schema: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 显示演员姓名和音乐剧名称。

assistant: SELECT T1.Name ,  T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID
Schema: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 演员和他们出演的音乐剧的名字是什么？

assistant: SELECT T1.Name ,  T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID
Schema: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 显示以“歌剧魅影”为名字的音乐剧中的演员的名字。

assistant: SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID WHERE T2.Name  =  "歌剧魅影"
Schema: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 音乐剧“歌剧魅影”的演员叫什么名字？

assistant: SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID WHERE T2.Name  =  "歌剧魅影"
Schema: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE musical (Musical_ID VARCHAR, Year VARCHAR)
user: 以出演的音乐剧获奖的年份降序排列，显示演员姓名。

assistant: SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID ORDER BY T2.Year DESC
Schema: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE musical (Musical_ID VARCHAR, Year VARCHAR)
user: 按出演的音乐剧获奖年份降序排列，演员姓名是什么？

assistant: SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID ORDER BY T2.Year DESC
Schema: CREATE TABLE actor (Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 显示音乐剧的名称和在音乐剧中出现的演员的数目。

assistant: SELECT T2.Name ,  COUNT(*) FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID GROUP BY T1.Musical_ID
Schema: CREATE TABLE actor (Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 每个音乐剧中有多少演员？

assistant: SELECT T2.Name ,  COUNT(*) FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID GROUP BY T1.Musical_ID
Schema: CREATE TABLE actor (Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 显示至少有三个演员的音乐剧名称。

assistant: SELECT T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID GROUP BY T1.Musical_ID HAVING COUNT(*)  >=  3
Schema: CREATE TABLE actor (Musical_ID VARCHAR), CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR)
user: 有3个或更多演员的音乐剧名称是什么？

assistant: SELECT T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID  =  T2.Musical_ID GROUP BY T1.Musical_ID HAVING COUNT(*)  >=  3
Schema: CREATE TABLE musical (Nominee VARCHAR)
user: 显示不同的被提名者和他们提名的音乐剧的数量。

assistant: SELECT Nominee ,  COUNT(*) FROM musical GROUP BY Nominee
Schema: CREATE TABLE musical (Nominee VARCHAR)
user: 每个被提名者有多少音乐剧被提名？

assistant: SELECT Nominee ,  COUNT(*) FROM musical GROUP BY Nominee
Schema: CREATE TABLE musical (Nominee VARCHAR)
user: 请显示被提名次数最多的被提名者。

assistant: SELECT Nominee FROM musical GROUP BY Nominee ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE musical (Nominee VARCHAR)
user: 谁是被提名音乐剧最多的的被提名人？

assistant: SELECT Nominee FROM musical GROUP BY Nominee ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE musical (RESULT VARCHAR)
user: 列出音乐剧最常见的结局。

assistant: SELECT RESULT FROM musical GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE musical (RESULT VARCHAR)
user: 返回所有音乐剧中最常见的结局。

assistant: SELECT RESULT FROM musical GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE musical (Nominee VARCHAR)
user: 列出被提名超过两部音乐剧的被提名者。

assistant: SELECT Nominee FROM musical GROUP BY Nominee HAVING COUNT(*)  >  2
Schema: CREATE TABLE musical (Nominee VARCHAR)
user: 被提名超过两次的被提名者是谁？

assistant: SELECT Nominee FROM musical GROUP BY Nominee HAVING COUNT(*)  >  2
Schema: CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR)
user: 列出没有演员的音乐剧名称。

assistant: SELECT Name FROM musical WHERE Musical_ID NOT IN (SELECT Musical_ID FROM actor)
Schema: CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR), CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR)
user: 没有演员的音乐剧名称是什么？

assistant: SELECT Name FROM musical WHERE Musical_ID NOT IN (SELECT Musical_ID FROM actor)
Schema: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR)
user: 显示被提名“金鸡奖”和“金马奖”的被提名人。

assistant: SELECT Nominee FROM musical WHERE Award  =  "金鸡奖" INTERSECT SELECT Nominee FROM musical WHERE Award  =  "金马奖"
Schema: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR)
user: 谁被提名过“金鸡奖”和“金马奖”？

assistant: SELECT Nominee FROM musical WHERE Award  =  "金鸡奖" INTERSECT SELECT Nominee FROM musical WHERE Award  =  "金马奖"
Schema: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR)
user: 显示获得“金鸡奖”或“金像奖”奖的被提名音乐人。

assistant: SELECT Nominee FROM musical WHERE Award  =  "金鸡奖" OR Award  =  "金像奖"
Schema: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR)
user: 谁被提名过“金鸡奖”或“金像奖”奖项？

assistant: SELECT Nominee FROM musical WHERE Award  =  "金鸡奖" OR Award  =  "金像奖"
Schema: CREATE TABLE user_profiles (email VARCHAR, name VARCHAR)
user: 找到名为“马丽”的用户的电子邮件。

assistant: SELECT email FROM user_profiles WHERE name  =  '马丽'
Schema: CREATE TABLE user_profiles (name VARCHAR, partitionid VARCHAR)
user: 名为“钢铁侠”的用户的ID是什么？

assistant: SELECT partitionid FROM user_profiles WHERE name  =  '钢铁侠'
Schema: CREATE TABLE user_profiles (Id VARCHAR)
user: 有多少用户？

assistant: SELECT count(*) FROM user_profiles
Schema: CREATE TABLE follows (Id VARCHAR)
user: 每个用户有多少追随者？

assistant: SELECT count(*) FROM follows
Schema: CREATE TABLE follows (f1 VARCHAR)
user: 查找每个用户的追随者数量。

assistant: SELECT count(*) FROM follows GROUP BY f1
Schema: CREATE TABLE tweets (Id VARCHAR)
user: 在记录中找到推文的数量。

assistant: SELECT count(*) FROM tweets
Schema: CREATE TABLE tweets (UID VARCHAR)
user: 查找发布了的推文的用户的数量。

assistant: SELECT count(DISTINCT UID) FROM tweets
Schema: CREATE TABLE user_profiles (email VARCHAR, name VARCHAR)
user: 找出用户名字中含有“往事随风”的人的名字和电子邮箱。

assistant: SELECT name ,  email FROM user_profiles WHERE name LIKE '往事随风'
Schema: CREATE TABLE user_profiles (email VARCHAR, name VARCHAR)
user: 找出电子邮箱中中含有“superstar”或是“edu”的用户的名字。

assistant: SELECT name FROM user_profiles WHERE email LIKE '巨星' OR email LIKE 'qq'
Schema: CREATE TABLE tweets (text VARCHAR)
user: 返回关于“实习”主题的推文。

assistant: SELECT text FROM tweets WHERE text LIKE '实习'
Schema: CREATE TABLE user_profiles (email VARCHAR, name VARCHAR, followers INTEGER)
user: 查找拥有超过1000个追随者的用户的姓名和电子邮件。

assistant: SELECT name ,  email FROM user_profiles WHERE followers  >  1000
Schema: CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR), CREATE TABLE follows (f1 VARCHAR)
user: 查找追随者数量大于名为“蔡依林”的用户的用户名称。

assistant: SELECT T1.name FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid  =  T2.f1 GROUP BY T2.f1 HAVING count(*)  >  (SELECT count(*) FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid  =  T2.f1 WHERE T1.name  =  '蔡依林')
Schema: CREATE TABLE user_profiles (email VARCHAR, name VARCHAR, uid VARCHAR), CREATE TABLE follows (f1 VARCHAR)
user: 查找有不止一个跟随者的用户的姓名和电子邮件。

assistant: SELECT T1.name ,  T1.email FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid  =  T2.f1 GROUP BY T2.f1 HAVING count(*)  >  1
Schema: CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR), CREATE TABLE tweets (uid VARCHAR)
user: 查找拥有不止一条推特的用户的姓名。

assistant: SELECT T1.name FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid  =  T2.uid GROUP BY T2.uid HAVING count(*)  >  1
Schema: CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR), CREATE TABLE follows (f1 VARCHAR, f2 VARCHAR)
user: 找到被“马丽”和“苏晴”跟随的用户的ID。

assistant: SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid  =  T2.f2 WHERE T1.name  =  "马丽" INTERSECT SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid  =  T2.f2 WHERE T1.name  =  "苏晴"
Schema: CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR), CREATE TABLE follows (f1 VARCHAR, f2 VARCHAR)
user: 找到“马丽”或“苏晴”共同追随的用户的ID。

assistant: SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid  =  T2.f2 WHERE T1.name  =  "马丽" OR T1.name  =  "苏晴"
Schema: CREATE TABLE user_profiles (followers VARCHAR, name VARCHAR)
user: 查找有最多追随者的用户的名称。

assistant: SELECT name FROM user_profiles ORDER BY followers DESC LIMIT 1
Schema: CREATE TABLE user_profiles (email VARCHAR, followers VARCHAR, name VARCHAR)
user: 找到有最少追随者的用户的名字和电子邮件。

assistant: SELECT name ,  email FROM user_profiles ORDER BY followers LIMIT 1
Schema: CREATE TABLE user_profiles (followers VARCHAR, name VARCHAR)
user: 按跟随者数量的降序进行排序，列出每个用户的名称和追随者数目。

assistant: SELECT name ,  followers FROM user_profiles ORDER BY followers DESC
Schema: CREATE TABLE user_profiles (followers VARCHAR, name VARCHAR)
user: 列出拥有追随者的最多的前5个用户的名字。

assistant: SELECT name FROM user_profiles ORDER BY followers DESC LIMIT 5
Schema: CREATE TABLE tweets (createdate VARCHAR, text VARCHAR)
user: 按日期顺序列出所有推文的文本。

assistant: SELECT text FROM tweets ORDER BY createdate
Schema: CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR), CREATE TABLE tweets (uid VARCHAR)
user: 找出每个用户的名字和推特的数量。

assistant: SELECT T1.name ,  count(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid  =  T2.uid GROUP BY T2.uid
Schema: CREATE TABLE user_profiles (partitionid VARCHAR, name VARCHAR, uid VARCHAR), CREATE TABLE tweets (uid VARCHAR)
user: 查找发了不到两次推特的用户的名称和ID。

assistant: SELECT T1.name ,  T1.partitionid FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid  =  T2.uid GROUP BY T2.uid HAVING count(*)  <  2
Schema: CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR), CREATE TABLE tweets (uid VARCHAR)
user: 查找不止一次发推特的用户的姓名，以及他们发推特的次数。

assistant: SELECT T1.name ,  count(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid  =  T2.uid GROUP BY T2.uid HAVING count(*)  >  1
Schema: CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR), CREATE TABLE tweets (followers INTEGER, UID VARCHAR)
user: 查找没有任何推特的用户的平均追随者数量。

assistant: SELECT avg(followers) FROM user_profiles WHERE UID NOT IN (SELECT UID FROM tweets)
Schema: CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR), CREATE TABLE tweets (followers INTEGER, UID VARCHAR)
user: 查找有一些推文的用户的平均追随者数量。

assistant: SELECT avg(followers) FROM user_profiles WHERE UID IN (SELECT UID FROM tweets)
Schema: CREATE TABLE user_profiles (followers INTEGER)
user: 查找所有用户的追随者的最大数量和总数。

assistant: SELECT max(followers) ,  sum(followers) FROM user_profiles
Schema: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR)
user: 查找所有目录项的名称。

assistant: SELECT distinct(catalog_entry_name) FROM catalog_contents
Schema: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR)
user: 所有目录项名称是什么？

assistant: SELECT distinct(catalog_entry_name) FROM catalog_contents
Schema: CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR)
user: 查找拥有多于3个属性定义的属性数据类型的列表。

assistant: SELECT attribute_data_type FROM Attribute_Definitions GROUP BY attribute_data_type HAVING count(*)  >  3
Schema: CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR)
user: 哪些属性数据类型有超过3个属性定义？

assistant: SELECT attribute_data_type FROM Attribute_Definitions GROUP BY attribute_data_type HAVING count(*)  >  3
Schema: CREATE TABLE Attribute_Definitions (attribute_name VARCHAR, attribute_data_type VARCHAR)
user: 属性名为“绿色”的属性数据类型是什么？

assistant: SELECT attribute_data_type FROM Attribute_Definitions WHERE attribute_name  =  "绿色"
Schema: CREATE TABLE Attribute_Definitions (attribute_name VARCHAR, attribute_data_type VARCHAR)
user: 查找属性名为“绿色”的属性数据类型。

assistant: SELECT attribute_data_type FROM Attribute_Definitions WHERE attribute_name  =  "绿色"
Schema: CREATE TABLE Catalog_Structure (catalog_level_name VARCHAR, catalog_level_number INTEGER)
user: 查找级别在5到10之间的目录结构的名称和级别。

assistant: SELECT catalog_level_name ,  catalog_level_number FROM Catalog_Structure WHERE catalog_level_number BETWEEN 5 AND 10
Schema: CREATE TABLE Catalog_Structure (catalog_level_name VARCHAR, catalog_level_number INTEGER)
user: 级别在5到10之间的目录结构的名称和级别是什么？

assistant: SELECT catalog_level_name ,  catalog_level_number FROM Catalog_Structure WHERE catalog_level_number BETWEEN 5 AND 10
Schema: CREATE TABLE catalogs (catalog_publisher VARCHAR)
user: 查找所有名字包含“小刚”的目录出版商。

assistant: SELECT distinct(catalog_publisher) FROM catalogs WHERE catalog_publisher LIKE "小刚"
Schema: CREATE TABLE catalogs (catalog_publisher VARCHAR)
user: 哪些目录出版商的名字内包含"小刚"这个子串？

assistant: SELECT distinct(catalog_publisher) FROM catalogs WHERE catalog_publisher LIKE "小刚"
Schema: CREATE TABLE catalogs (catalog_publisher VARCHAR)
user: 哪个目录出版商出版了最多的目录？

assistant: SELECT catalog_publisher FROM catalogs GROUP BY catalog_publisher ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE catalogs (catalog_publisher VARCHAR)
user: 查找目录最多的目录出版商。

assistant: SELECT catalog_publisher FROM catalogs GROUP BY catalog_publisher ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE catalogs (date_of_publication VARCHAR, catalog_id VARCHAR, catalog_name VARCHAR), CREATE TABLE catalog_structure (catalog_id VARCHAR)
user: 查找目录级别号大于5的所有目录的名称和发布日期。

assistant: SELECT t1.catalog_name ,  t1.date_of_publication FROM catalogs AS t1 JOIN catalog_structure AS t2 ON t1.catalog_id  =  t2.catalog_id WHERE catalog_level_number  >  5
Schema: CREATE TABLE catalogs (date_of_publication VARCHAR, catalog_id VARCHAR, catalog_name VARCHAR), CREATE TABLE catalog_structure (catalog_id VARCHAR)
user: 级别号在5以上的目录的名称和发布日期是什么？

assistant: SELECT t1.catalog_name ,  t1.date_of_publication FROM catalogs AS t1 JOIN catalog_structure AS t2 ON t1.catalog_id  =  t2.catalog_id WHERE catalog_level_number  >  5
Schema: CREATE TABLE Catalog_Contents (catalog_entry_id VARCHAR, catalog_entry_name VARCHAR), CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_value VARCHAR)
user: 具有最多条目所具有的属性所属的目录的条目名称是什么？

assistant: SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id  =  t2.catalog_entry_id WHERE t2.attribute_value  =  (SELECT attribute_value FROM Catalog_Contents_Additional_Attributes GROUP BY attribute_value ORDER BY count(*) DESC LIMIT 1)
Schema: CREATE TABLE Catalog_Contents (catalog_entry_id VARCHAR, catalog_entry_name VARCHAR), CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_value VARCHAR)
user: 查找具有最多条目的属性所属的目录的条目名称。

assistant: SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id  =  t2.catalog_entry_id WHERE t2.attribute_value  =  (SELECT attribute_value FROM Catalog_Contents_Additional_Attributes GROUP BY attribute_value ORDER BY count(*) DESC LIMIT 1)
Schema: CREATE TABLE catalog_contents (price_in_dollars VARCHAR, catalog_entry_name VARCHAR)
user: 最贵的目录（美元）的条目名称是什么？

assistant: SELECT catalog_entry_name FROM catalog_contents ORDER BY price_in_dollars DESC LIMIT 1