jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE home_game (year VARCHAR, park_id VARCHAR, attendance VARCHAR), CREATE TABLE park (park_id VARCHAR, park_name VARCHAR)
user: 哪一个公园在2008年餐馆的最多？

assistant: SELECT T2.park_name FROM home_game AS T1 JOIN park AS T2 ON T1.park_id  =  T2.park_id WHERE T1.year = 2008 ORDER BY T1.attendance DESC LIMIT 1;
Schema: CREATE TABLE home_game (year VARCHAR, park_id VARCHAR, attendance VARCHAR), CREATE TABLE park (park_id VARCHAR, park_name VARCHAR)
user: 2008年参观人数最多的公园是哪一个？

assistant: SELECT T2.park_name FROM home_game AS T1 JOIN park AS T2 ON T1.park_id  =  T2.park_id WHERE T1.year = 2008 ORDER BY T1.attendance DESC LIMIT 1;
Schema: CREATE TABLE camera_lens (focal_length_mm INTEGER)
user: 有多少照相机的镜头焦距大于15毫米？

assistant: SELECT count(*) FROM camera_lens WHERE focal_length_mm  >  15
Schema: CREATE TABLE camera_lens (brand VARCHAR, name VARCHAR, max_aperture VARCHAR)
user: 找出按最大光圈的降序排列的每个相机镜头的品牌和名称。

assistant: SELECT brand ,  name FROM camera_lens ORDER BY max_aperture DESC
Schema: CREATE TABLE photos (name VARCHAR, id VARCHAR, color VARCHAR)
user: 列出所有照片的ID、颜色方案和名称。

assistant: SELECT id ,  color ,  name FROM photos
Schema: CREATE TABLE mountain (height INTEGER)
user: 山的最大高度和平均高度是多少？

assistant: SELECT max(height) ,  avg(height) FROM mountain
Schema: CREATE TABLE mountain (prominence INTEGER, country VARCHAR)
user: 在“峨眉山”山脉的平均突出度是多少？

assistant: SELECT avg(prominence) FROM mountain WHERE country  =  '峨眉山'
Schema: CREATE TABLE mountain (range VARCHAR, prominence VARCHAR, name VARCHAR, height VARCHAR)
user: 不属于“长白山脉”的山脉的名称、高度和突出度是什么？

assistant: SELECT name ,  height ,  prominence FROM mountain WHERE range != '长白山脉'
Schema: CREATE TABLE mountain (height INTEGER, name VARCHAR, id VARCHAR), CREATE TABLE photos (mountain_id VARCHAR)
user: 有照片的山的id和名字是什么？

assistant: SELECT T1.id ,  T1.name FROM mountain AS T1 JOIN photos AS T2 ON T1.id  =  T2.mountain_id WHERE T1.height  >  4000
Schema: CREATE TABLE mountain (name VARCHAR, id VARCHAR), CREATE TABLE photos (mountain_id VARCHAR)
user: 至少有2张照片的山的id和名字是什么？

assistant: SELECT T1.id ,  T1.name FROM mountain AS T1 JOIN photos AS T2 ON T1.id  =  T2.mountain_id GROUP BY T1.id HAVING count(*)  >=  2
Schema: CREATE TABLE photos (camera_lens_id VARCHAR), CREATE TABLE camera_lens (id VARCHAR, name VARCHAR)
user: 拍摄了最多山脉的照相机的名字是什么？

assistant: SELECT T2.name FROM photos AS T1 JOIN camera_lens AS T2 ON T1.camera_lens_id  =  T2.id GROUP BY T2.id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE camera_lens (brand VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE photos (camera_lens_id VARCHAR)
user: 镜头品牌为“尼康”或“奥林巴斯”拍摄的照片名称是什么？

assistant: SELECT T1.name FROM camera_lens AS T1 JOIN photos AS T2 ON T2.camera_lens_id  =  T1.id WHERE T1.brand  =  '尼康' OR T1.brand  =  '奥林巴斯'
Schema: CREATE TABLE camera_lens (brand VARCHAR)
user: 有多少种不同的镜片品牌？

assistant: SELECT count(DISTINCT brand) FROM camera_lens
Schema: CREATE TABLE camera_lens (id VARCHAR, camera_lens_id VARCHAR), CREATE TABLE photos (id VARCHAR, camera_lens_id VARCHAR)
user: 拍摄照片时没有使用的镜头数有多少？

assistant: SELECT count(*) FROM camera_lens WHERE id NOT IN ( SELECT camera_lens_id FROM photos )
Schema: CREATE TABLE mountain (country VARCHAR, id VARCHAR), CREATE TABLE photos (mountain_id VARCHAR, camera_lens_id VARCHAR)
user: 有多少种不同的相机镜头被用来拍摄“华山”的山脉？

assistant: SELECT count(DISTINCT T2.camera_lens_id) FROM mountain AS T1 JOIN photos AS T2 ON T1.id  =  T2.mountain_id WHERE T1.country  =  '华山'
Schema: CREATE TABLE mountain (range VARCHAR, id VARCHAR), CREATE TABLE photos (mountain_id VARCHAR, camera_lens_id VARCHAR), CREATE TABLE camera_lens (brand VARCHAR, id VARCHAR)
user: 列出那些拍摄“青藏高原”区域照片和拍摄“泰山”区域山峰的照片的镜头品牌

assistant: SELECT T3.brand FROM mountain AS T1 JOIN photos AS T2 ON T1.id  =  T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id  =  T3.id WHERE T1.range  =  '青藏高原' INTERSECT SELECT T3.brand FROM mountain AS T1 JOIN photos AS T2 ON T1.id  =  T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id  =  T3.id WHERE T1.range  =  '泰山'
Schema: CREATE TABLE mountain (prominence VARCHAR, name VARCHAR, id VARCHAR), CREATE TABLE photos (mountain_id VARCHAR, camera_lens_id VARCHAR), CREATE TABLE camera_lens (brand VARCHAR, id VARCHAR)
user: 展示那些没有被“尼康”品牌的镜头拍摄的山脉的名字和突出度。

assistant: SELECT name ,  prominence FROM mountain EXCEPT SELECT T1.name ,  T1.prominence FROM mountain AS T1 JOIN photos AS T2 ON T1.id  =  T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id  =  T3.id WHERE T3.brand  =  '尼康'
Schema: CREATE TABLE camera_lens (name VARCHAR)
user: 列出包含“数码”子字符串的相机镜头的名称。

assistant: SELECT name FROM camera_lens WHERE name LIKE "数码"
Schema: CREATE TABLE camera_lens (id VARCHAR, name VARCHAR), CREATE TABLE photos (camera_lens_id VARCHAR)
user: 根据照片的数量排序的每个镜头的名称和用该镜头拍摄照片的数量是多少？

assistant: SELECT T1.name ,  count(*) FROM camera_lens AS T1 JOIN photos AS T2 ON T1.id  =  T2.camera_lens_id GROUP BY T1.id ORDER BY count(*)
Schema: CREATE TABLE channel (OWNER VARCHAR, name VARCHAR)
user: 查找不属于“央视”的频道名称。

assistant: SELECT name FROM channel WHERE OWNER != '央视'
Schema: CREATE TABLE channel (OWNER VARCHAR, name VARCHAR)
user: 哪些频道不属于“央视”？返回频道的名字。

assistant: SELECT name FROM channel WHERE OWNER != '央视'
Schema: CREATE TABLE channel (name VARCHAR, rating_in_percent VARCHAR)
user: 按其评级从大到小排序列出所有频道名称。

assistant: SELECT name FROM channel ORDER BY rating_in_percent DESC
Schema: CREATE TABLE channel (name VARCHAR, rating_in_percent VARCHAR)
user: 给出一个按频道评级降序排序的所有频道名称的列表。

assistant: SELECT name FROM channel ORDER BY rating_in_percent DESC
Schema: CREATE TABLE channel (OWNER VARCHAR, rating_in_percent VARCHAR)
user: 拥有最高评级比率的频道的所有者是什么？

assistant: SELECT OWNER FROM channel ORDER BY rating_in_percent DESC LIMIT 1
Schema: CREATE TABLE channel (OWNER VARCHAR, rating_in_percent VARCHAR)
user: 给我看一个拥有最高评级的频道的所有者。

assistant: SELECT OWNER FROM channel ORDER BY rating_in_percent DESC LIMIT 1
Schema: CREATE TABLE program (Id VARCHAR)
user: 有多少节目？

assistant: SELECT count(*) FROM program
Schema: CREATE TABLE program (Id VARCHAR)
user: 计算节目的数量。

assistant: SELECT count(*) FROM program
Schema: CREATE TABLE program (launch VARCHAR, name VARCHAR)
user: 按启动时间排序列出所有的节目名称。

assistant: SELECT name FROM program ORDER BY launch
Schema: CREATE TABLE program (launch VARCHAR, name VARCHAR)
user: 按启动日期顺序排列的节目名称列表是什么？

assistant: SELECT name FROM program ORDER BY launch
Schema: CREATE TABLE program (OWNER VARCHAR, origin VARCHAR, name VARCHAR)
user: 列出每个节目名称、来源和所有者。

assistant: SELECT name ,  origin ,  OWNER FROM program
Schema: CREATE TABLE program (OWNER VARCHAR, origin VARCHAR, name VARCHAR)
user: 每个节目的名称、来源和拥有者是什么？

assistant: SELECT name ,  origin ,  OWNER FROM program
Schema: CREATE TABLE program (launch VARCHAR, name VARCHAR)
user: 查找最近启动的节目的名称。

assistant: SELECT name FROM program ORDER BY launch DESC LIMIT 1
Schema: CREATE TABLE program (launch VARCHAR, name VARCHAR)
user: 最近推出了哪个项目？返回节目的名称。

assistant: SELECT name FROM program ORDER BY launch DESC LIMIT 1
Schema: CREATE TABLE channel (OWNER VARCHAR, Share_in_percent INTEGER)
user: 找出“央视”拥有的所有频道的总百分比。

assistant: SELECT sum(Share_in_percent) FROM channel WHERE OWNER  =  '央视'
Schema: CREATE TABLE channel (OWNER VARCHAR, Share_in_percent INTEGER)
user: “央视”拥有的所有频道的总份额（占总数的百分比）是多少？

assistant: SELECT sum(Share_in_percent) FROM channel WHERE OWNER  =  '央视'
Schema: CREATE TABLE channel (name VARCHAR, channel_id VARCHAR), CREATE TABLE broadcast (time_of_day VARCHAR, channel_id VARCHAR)
user: 找出“早上”时间播出的频道的名字。

assistant: SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id  =  t2.channel_id WHERE t2.time_of_day  =  '早上'
Schema: CREATE TABLE channel (name VARCHAR, channel_id VARCHAR), CREATE TABLE broadcast (time_of_day VARCHAR, channel_id VARCHAR)
user: 哪些频道在“早上”时间播出？把频道的名字给我。

assistant: SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id  =  t2.channel_id WHERE t2.time_of_day  =  '早上'
Schema: CREATE TABLE channel (name VARCHAR, channel_id VARCHAR), CREATE TABLE broadcast (time_of_day VARCHAR, channel_id VARCHAR)
user: 既在“早上”又在“晚上”播出的频道的名称是什么？

assistant: SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id  =  t2.channel_id WHERE t2.time_of_day  =  '早上' INTERSECT SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id  =  t2.channel_id WHERE t2.time_of_day  =  '晚上'
Schema: CREATE TABLE channel (name VARCHAR, channel_id VARCHAR), CREATE TABLE broadcast (time_of_day VARCHAR, channel_id VARCHAR)
user: 哪些频道既在“早上”时间又在“晚上”时间播出？把频道的名字给我。

assistant: SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id  =  t2.channel_id WHERE t2.time_of_day  =  '早上' INTERSECT SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id  =  t2.channel_id WHERE t2.time_of_day  =  '晚上'
Schema: CREATE TABLE broadcast (time_of_day VARCHAR)
user: 一天中每个时间段有多少个节目在播出？

assistant: SELECT count(*) ,  time_of_day FROM broadcast GROUP BY time_of_day
Schema: CREATE TABLE broadcast (time_of_day VARCHAR)
user: 计算一天中每个时间段播放节目的数量。

assistant: SELECT count(*) ,  time_of_day FROM broadcast GROUP BY time_of_day
Schema: CREATE TABLE broadcast (time_of_day VARCHAR, program_id VARCHAR)
user: 找出“晚上”时段播放的不同节目的数量。

assistant: SELECT count(DISTINCT program_id) FROM broadcast WHERE time_of_day  =  '晚上'
Schema: CREATE TABLE broadcast (time_of_day VARCHAR, program_id VARCHAR)
user: 在“晚上”时间播出多少个不同的节目？

assistant: SELECT count(DISTINCT program_id) FROM broadcast WHERE time_of_day  =  '晚上'
Schema: CREATE TABLE program (program_id VARCHAR, name VARCHAR), CREATE TABLE broadcast (Time_of_day VARCHAR, program_id VARCHAR)
user: 找出“早上”时段从未播出过的节目名称。

assistant: SELECT name FROM program EXCEPT SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id WHERE t2.Time_of_day  =  "早上"
Schema: CREATE TABLE program (program_id VARCHAR, name VARCHAR), CREATE TABLE broadcast (Time_of_day VARCHAR, program_id VARCHAR)
user: 哪些节目从来不在“早上”时段播出？给我节目的名字。

assistant: SELECT name FROM program EXCEPT SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id WHERE t2.Time_of_day  =  "早上"
Schema: CREATE TABLE program (owner VARCHAR, program_id VARCHAR), CREATE TABLE broadcast (Time_of_day VARCHAR, program_id VARCHAR)
user: 找出在“早上”时段和“晚上”时段都有节目播出的频道的所有者。

assistant: SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id WHERE t2.Time_of_day  =  "早上" INTERSECT SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id WHERE t2.Time_of_day  =  "晚上"
Schema: CREATE TABLE program (owner VARCHAR, program_id VARCHAR), CREATE TABLE broadcast (Time_of_day VARCHAR, program_id VARCHAR)
user: 在“早上”时段和“晚上”时段都有节目播出的频道的所有者是谁？

assistant: SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id WHERE t2.Time_of_day  =  "早上" INTERSECT SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id WHERE t2.Time_of_day  =  "晚上"
Schema: CREATE TABLE program (origin VARCHAR)
user: 按字母顺序列出所有节目的来源。

assistant: SELECT origin FROM program ORDER BY origin
Schema: CREATE TABLE program (origin VARCHAR)
user: 按字母顺序排列的节目来源列表是什么？

assistant: SELECT origin FROM program ORDER BY origin
Schema: CREATE TABLE channel (OWNER VARCHAR)
user: 不同频道所有者的数量是多少？

assistant: SELECT count(DISTINCT OWNER) FROM channel
Schema: CREATE TABLE channel (OWNER VARCHAR)
user: 计算不同频道所有者的数量。

assistant: SELECT count(DISTINCT OWNER) FROM channel
Schema: CREATE TABLE program (origin VARCHAR, name VARCHAR)
user: 查找来源不在“北京”的节目的名称。

assistant: SELECT name FROM program WHERE origin != '北京'
Schema: CREATE TABLE program (origin VARCHAR, name VARCHAR)
user: 哪些节目的起源不是“北京”？给出节目的名称。

assistant: SELECT name FROM program WHERE origin != '北京'
Schema: CREATE TABLE channel (OWNER VARCHAR, name VARCHAR)
user: 被“央视”或“湖南卫视”拥有的频道名称是什么？

assistant: SELECT name FROM channel WHERE OWNER  =  '央视' OR OWNER  =  '湖南卫视'
Schema: CREATE TABLE channel (OWNER VARCHAR, name VARCHAR)
user: 列出“央视”或“湖南卫视”所拥有的所有频道的名称

assistant: SELECT name FROM channel WHERE OWNER  =  '央视' OR OWNER  =  '湖南卫视'
Schema: CREATE TABLE channel (OWNER VARCHAR, Rating_in_percent INTEGER)
user: 找到每个频道所有者的总评级比率。

assistant: SELECT sum(Rating_in_percent) ,  OWNER FROM channel GROUP BY OWNER
Schema: CREATE TABLE channel (OWNER VARCHAR, Rating_in_percent INTEGER)
user: 每个频道所有者的频道总评级是多少？

assistant: SELECT sum(Rating_in_percent) ,  OWNER FROM channel GROUP BY OWNER
Schema: CREATE TABLE program (program_id VARCHAR, name VARCHAR), CREATE TABLE broadcast (program_id VARCHAR)
user: 找出播放最频繁的节目名称。

assistant: SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id GROUP BY t2.program_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE program (program_id VARCHAR, name VARCHAR), CREATE TABLE broadcast (program_id VARCHAR)
user: 哪个节目的播出最频繁？给出节目的名字。

assistant: SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id  =  t2.program_id GROUP BY t2.program_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE COURSES (Id VARCHAR)
user: 一共有多少门课？

assistant: SELECT count(*) FROM COURSES
Schema: CREATE TABLE COURSES (Id VARCHAR)
user: 找到所提供课程的总数。

assistant: SELECT count(*) FROM COURSES
Schema: CREATE TABLE COURSES (course_description VARCHAR, course_name VARCHAR)
user: “数据库”课程的课程描述是什么？

assistant: SELECT course_description FROM COURSES WHERE course_name  =  "数据库"
Schema: CREATE TABLE COURSES (course_description VARCHAR, course_name VARCHAR)
user: 返回“数据库”课程的描述。

assistant: SELECT course_description FROM COURSES WHERE course_name  =  "数据库"
Schema: CREATE TABLE Course_Authors_and_Tutors (personal_name VARCHAR, address_line_1 VARCHAR)
user: 课程的作者或导师姓名是“琪琪”的地址是什么？

assistant: SELECT address_line_1 FROM Course_Authors_and_Tutors WHERE personal_name	 =  "琪琪"
Schema: CREATE TABLE Course_Authors_and_Tutors (personal_name VARCHAR, address_line_1 VARCHAR)
user: 返回个人名字为“琪琪”的课程作者或导师的地址。

assistant: SELECT address_line_1 FROM Course_Authors_and_Tutors WHERE personal_name	 =  "琪琪"
Schema: CREATE TABLE Course_Authors_and_Tutors (address_line_1 VARCHAR)
user: 列出所有课程的作者或导师的地址。

assistant: SELECT address_line_1 FROM Course_Authors_and_Tutors
Schema: CREATE TABLE Course_Authors_and_Tutors (address_line_1 VARCHAR)
user: 每个课程的作者或导师的地址是什么？

assistant: SELECT address_line_1 FROM Course_Authors_and_Tutors
Schema: CREATE TABLE Course_Authors_and_Tutors (family_name VARCHAR, login_name VARCHAR)
user: 列出所有作者和导师的登录名和姓氏。

assistant: SELECT login_name ,  family_name FROM Course_Authors_and_Tutors
Schema: CREATE TABLE Course_Authors_and_Tutors (family_name VARCHAR, login_name VARCHAR)
user: 作者和导师的登录名和姓氏是什么？

assistant: SELECT login_name ,  family_name FROM Course_Authors_and_Tutors
Schema: CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR, date_of_completion VARCHAR)
user: 列出所有学生的入学日期和完成日期。

assistant: SELECT date_of_enrolment ,  date_of_completion FROM Student_Course_Enrolment
Schema: CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR, date_of_completion VARCHAR)
user: 所有记录的入学日期和完成日期是什么？

assistant: SELECT date_of_enrolment ,  date_of_completion FROM Student_Course_Enrolment
Schema: CREATE TABLE Student_Course_Enrolment (student_id VARCHAR)
user: 有多少不同的学生参加课程？

assistant: SELECT count(DISTINCT student_id) FROM Student_Course_Enrolment
Schema: CREATE TABLE Student_Course_Enrolment (student_id VARCHAR)
user: 找出参加课程的不同学生的人数。

assistant: SELECT count(DISTINCT student_id) FROM Student_Course_Enrolment
Schema: CREATE TABLE Student_Course_Enrolment (course_id VARCHAR)
user: 学生选择上了多少门课？

assistant: SELECT count(course_id) FROM Student_Course_Enrolment
Schema: CREATE TABLE Student_Course_Enrolment (course_id VARCHAR)
user: 超出有学生参加的不同课程的数量。

assistant: SELECT count(course_id) FROM Student_Course_Enrolment
Schema: CREATE TABLE Student_Tests_Taken (date_test_taken VARCHAR, test_result VARCHAR)
user: 找到测试结果为“通过”的日期。

assistant: SELECT date_test_taken FROM Student_Tests_Taken WHERE test_result  =  "通过"
Schema: CREATE TABLE Student_Tests_Taken (date_test_taken VARCHAR, test_result VARCHAR)
user: 哪些测试有“通过”的结果？返回测试时的日期。

assistant: SELECT date_test_taken FROM Student_Tests_Taken WHERE test_result  =  "通过"
Schema: CREATE TABLE Student_Tests_Taken (test_result VARCHAR)
user: 有多少测试的结果是“失败”？

assistant: SELECT count(*) FROM Student_Tests_Taken WHERE test_result  =  "失败"
Schema: CREATE TABLE Student_Tests_Taken (test_result VARCHAR)
user: 计算测试结果是“失败”的考试的次数。

assistant: SELECT count(*) FROM Student_Tests_Taken WHERE test_result  =  "失败"
Schema: CREATE TABLE Students (family_name VARCHAR, login_name VARCHAR)
user: 姓氏是“睿”的学生的登录名是什么？

assistant: SELECT login_name FROM Students WHERE family_name  =  "睿"
Schema: CREATE TABLE Students (family_name VARCHAR, login_name VARCHAR)
user: 返回姓氏为“睿”的学生的登录名。

assistant: SELECT login_name FROM Students WHERE family_name  =  "睿"
Schema: CREATE TABLE Students (date_of_latest_logon VARCHAR, family_name VARCHAR)
user: 姓“龚”或“铭”的学生最近登录的日期是什么？

assistant: SELECT date_of_latest_logon FROM Students WHERE family_name  =  "龚" OR family_name  =  "铭"
Schema: CREATE TABLE Students (date_of_latest_logon VARCHAR, family_name VARCHAR)
user: 查找姓氏为“龚”或“铭”的学生的最新登录日期。

assistant: SELECT date_of_latest_logon FROM Students WHERE family_name  =  "龚" OR family_name  =  "铭"
Schema: CREATE TABLE Students (personal_name VARCHAR)
user: 有多少学生的名字中包含有“孙”这个词？

assistant: SELECT COUNT(*) FROM Students WHERE personal_name LIKE "孙"
Schema: CREATE TABLE Students (personal_name VARCHAR)
user: 找出学生名字中有“孙”一词的学生数。

assistant: SELECT COUNT(*) FROM Students WHERE personal_name LIKE "孙"
Schema: CREATE TABLE SUBJECTS (subject_name VARCHAR)
user: 列出所有的科目名称。

assistant: SELECT subject_name FROM SUBJECTS
Schema: CREATE TABLE SUBJECTS (subject_name VARCHAR)
user: 所有科目的名字是什么？

assistant: SELECT subject_name FROM SUBJECTS
Schema: CREATE TABLE Course_Authors_and_Tutors (personal_name VARCHAR)
user: 按照个人姓名的字母顺序列出所有有关课程作者和导师的信息。

assistant: SELECT * FROM Course_Authors_and_Tutors ORDER BY personal_name
Schema: CREATE TABLE Course_Authors_and_Tutors (personal_name VARCHAR)
user: 按照个人姓名的字母顺序排列关于课程作者和导师的信息。

assistant: SELECT * FROM Course_Authors_and_Tutors ORDER BY personal_name
Schema: CREATE TABLE Students (personal_name VARCHAR, family_name VARCHAR)
user: 按姓氏的字母顺序列出所有学生的个人姓名和姓氏。

assistant: SELECT personal_name ,  family_name FROM Students ORDER BY family_name
Schema: CREATE TABLE Students (personal_name VARCHAR, family_name VARCHAR)
user: 按姓氏的字母顺序排序的学生的名字和姓氏是什么？

assistant: SELECT personal_name ,  family_name FROM Students ORDER BY family_name
Schema: CREATE TABLE Student_Tests_Taken (test_result VARCHAR)
user: 以计数的递减顺序列出每个测试结果及其计数。

assistant: SELECT test_result ,  COUNT(*) FROM Student_Tests_Taken GROUP BY test_result ORDER BY COUNT(*) DESC
Schema: CREATE TABLE Student_Tests_Taken (test_result VARCHAR)
user: 对于每一个不同的测试结果，找出得到结果的学生的数量。

assistant: SELECT test_result ,  COUNT(*) FROM Student_Tests_Taken GROUP BY test_result ORDER BY COUNT(*) DESC
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, login_name VARCHAR), CREATE TABLE Courses (author_id VARCHAR, course_name VARCHAR)
user: 查找教授课程名为“高级数据库”的作者的登录名。

assistant: SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "高级数据库"
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, login_name VARCHAR), CREATE TABLE Courses (author_id VARCHAR, course_name VARCHAR)
user: 哪个课程的作者教“高级数据库”课程？给我他或她的登录名。

assistant: SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "高级数据库"
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, address_line_1 VARCHAR), CREATE TABLE Courses (author_id VARCHAR, course_name VARCHAR)
user: 查找课程名是“操作系统”或“数据结构”的课程作者的地址。

assistant: SELECT T1.address_line_1 FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "操作系统" OR T2.course_name  =  "数据结构"
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, address_line_1 VARCHAR), CREATE TABLE Courses (author_id VARCHAR, course_name VARCHAR)
user: 讲授“操作系统”或“数据结构”课程的作者的地址是什么？

assistant: SELECT T1.address_line_1 FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "操作系统" OR T2.course_name  =  "数据结构"
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, personal_name VARCHAR, family_name VARCHAR), CREATE TABLE Courses (author_id VARCHAR)
user: 查找教授最多数量课程的课程作者的个人姓名、姓氏和作者ID。

assistant: SELECT T1.personal_name ,  T1.family_name ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, personal_name VARCHAR, family_name VARCHAR), CREATE TABLE Courses (author_id VARCHAR)
user: 授课最多课程的作者的个人姓名、姓氏和作者id是什么？

assistant: SELECT T1.personal_name ,  T1.family_name ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, address_line_1 VARCHAR), CREATE TABLE Courses (author_id VARCHAR)
user: 找到至少教授两门课程的课程作者的地址和作者ID。

assistant: SELECT T1.address_line_1 ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id HAVING Count(*)  >=  2
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, address_line_1 VARCHAR), CREATE TABLE Courses (author_id VARCHAR)
user: 哪个课程的作者教两个或更多课程？给出他们的地址和作者id。

assistant: SELECT T1.address_line_1 ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id HAVING Count(*)  >=  2
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, personal_name VARCHAR), CREATE TABLE Courses (author_id VARCHAR, course_name VARCHAR)
user: 找到导师的名字是“志华”的课程的名字。

assistant: SELECT T2.course_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T1.personal_name  =  "志华"
Schema: CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR, personal_name VARCHAR), CREATE TABLE Courses (author_id VARCHAR, course_name VARCHAR)
user: 名字是“志华”的导师教的课程的名称是什么？

assistant: SELECT T2.course_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T1.personal_name  =  "志华"
Schema: CREATE TABLE Courses (course_description VARCHAR, course_name VARCHAR, subject_id VARCHAR), CREATE TABLE Subjects (subject_name VARCHAR, subject_id VARCHAR)
user: 查找属于“计算机科学”课程的名称和说明。

assistant: SELECT T1.course_name ,  T1.course_description FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id  =  T2.subject_id WHERE T2.subject_name  =  "计算机科学"
Schema: CREATE TABLE Courses (course_description VARCHAR, course_name VARCHAR, subject_id VARCHAR), CREATE TABLE Subjects (subject_name VARCHAR, subject_id VARCHAR)
user: 在“计算机科学”科目下所有课程的名称和描述是什么？

assistant: SELECT T1.course_name ,  T1.course_description FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id  =  T2.subject_id WHERE T2.subject_name  =  "计算机科学"
Schema: CREATE TABLE Courses (subject_id VARCHAR), CREATE TABLE Subjects (subject_name VARCHAR, subject_id VARCHAR)
user: 找出课程ID、课程名称和每个科目对应的可用课程数量。

assistant: SELECT T1.subject_id ,  T2.subject_name ,  COUNT(*) FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id  =  T2.subject_id GROUP BY T1.subject_id
Schema: CREATE TABLE Courses (subject_id VARCHAR), CREATE TABLE Subjects (subject_name VARCHAR, subject_id VARCHAR)
user: 课程ID、课程名称和每个科目的可用课程数量是多少？

assistant: SELECT T1.subject_id ,  T2.subject_name ,  COUNT(*) FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id  =  T2.subject_id GROUP BY T1.subject_id
Schema: CREATE TABLE Courses (subject_id VARCHAR), CREATE TABLE Subjects (subject_name VARCHAR, subject_id VARCHAR)
user: 找出按课程数的升序进行排序的课程ID、课程名称和每个科目的可用课程数量。

assistant: SELECT T1.subject_id ,  T2.subject_name ,  COUNT(*) FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id  =  T2.subject_id GROUP BY T1.subject_id ORDER BY COUNT(*) ASC