jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE products (manufacturer VARCHAR, Price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
user: 按制造商名称分组的产品平均价格是多少？

assistant: SELECT avg(T1.Price) ,  T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer  =  T2.code GROUP BY T2.name
Schema: CREATE TABLE products (price INTEGER, manufacturer VARCHAR, Price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
user: 选择产品平均价格高于或等于$150的制造商的名称。

assistant: SELECT avg(T1.Price) ,  T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer  =  T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
Schema: CREATE TABLE products (price INTEGER, manufacturer VARCHAR, Price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
user: 产品平均成本在150或以上的制造商的产品名称和平均价格是多少？

assistant: SELECT avg(T1.Price) ,  T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer  =  T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
Schema: CREATE TABLE Products (price VARCHAR, name VARCHAR)
user: 选择最便宜产品的名称和价格。

assistant: SELECT name ,  price FROM Products ORDER BY price ASC LIMIT 1
Schema: CREATE TABLE Products (price VARCHAR, name VARCHAR)
user: 最便宜的产品的名称和价格是多少？

assistant: SELECT name ,  price FROM Products ORDER BY price ASC LIMIT 1
Schema: CREATE TABLE products (manufacturer VARCHAR, Name VARCHAR, Price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
user: 选择每个制造商的名称及其最昂贵产品的名称和价格。

assistant: SELECT T1.Name ,  max(T1.Price) ,  T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer  =  T2.code GROUP BY T2.name
Schema: CREATE TABLE products (manufacturer VARCHAR, Name VARCHAR, Price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
user: 对于每个制造商的名字，他们最贵的产品的名称和价格是什么？

assistant: SELECT T1.Name ,  max(T1.Price) ,  T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer  =  T2.code GROUP BY T2.name
Schema: CREATE TABLE products (price INTEGER, name VARCHAR, code VARCHAR)
user: 选择每个产品类别中最便宜的产品代码。

assistant: SELECT code ,  name ,  min(price) FROM products GROUP BY name
Schema: CREATE TABLE products (price INTEGER, name VARCHAR, code VARCHAR)
user: 每个类别中最便宜的产品的代码和名称是什么？

assistant: SELECT code ,  name ,  min(price) FROM products GROUP BY name
Schema: CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR)
user: 最近创建的问题日志的ID是什么？

assistant: SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
Schema: CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR)
user: 哪一个问题日志是最近创建的？把日志ID给我。

assistant: SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
Schema: CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, log_entry_date VARCHAR)
user: 最老的日志ID和对应的问题ID是什么？

assistant: SELECT problem_log_id ,  problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
Schema: CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, log_entry_date VARCHAR)
user: 找出最老的日志ID及其对应的问题ID。

assistant: SELECT problem_log_id ,  problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
Schema: CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, log_entry_date VARCHAR)
user: 根据ID为10的问题找出所有日志的ID和日期。

assistant: SELECT problem_log_id ,  log_entry_date FROM problem_log WHERE problem_id = 10
Schema: CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, log_entry_date VARCHAR)
user: 对于ID为10的问题，返回其问题日志的ID和日期。

assistant: SELECT problem_log_id ,  log_entry_date FROM problem_log WHERE problem_id = 10
Schema: CREATE TABLE problem_log (log_entry_description VARCHAR, problem_log_id VARCHAR)
user: 列出所有日志ID及其从问题日志中的描述。

assistant: SELECT problem_log_id ,  log_entry_description FROM problem_log
Schema: CREATE TABLE problem_log (log_entry_description VARCHAR, problem_log_id VARCHAR)
user: 每个问题的日志ID和条目描述是什么？

assistant: SELECT problem_log_id ,  log_entry_description FROM problem_log
Schema: CREATE TABLE staff (staff_id VARCHAR), CREATE TABLE problem_log (problem_id VARCHAR, assigned_to_staff_id VARCHAR)
user: 列出分配到id为1的问题的所有不同工作人员的名字和姓氏。

assistant: SELECT DISTINCT staff_first_name ,  staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
Schema: CREATE TABLE staff (staff_id VARCHAR), CREATE TABLE problem_log (problem_id VARCHAR, assigned_to_staff_id VARCHAR)
user: 哪些员工被分配到ID是1的问题？给我他们的名字和姓氏。

assistant: SELECT DISTINCT staff_first_name ,  staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
Schema: CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR), CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR)
user: 列出分配给名为“马” “军军”的工作人员的问题id和日志id。

assistant: SELECT DISTINCT T2.problem_id ,  T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "马" AND T1.staff_last_name = "军军"
Schema: CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR), CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR)
user: 哪个问题ID和日志ID被指派给名为“马” “军军”的员工？

assistant: SELECT DISTINCT T2.problem_id ,  T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "马" AND T1.staff_last_name = "军军"
Schema: CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE problems (product_id VARCHAR)
user: “显示器”产品有多少问题？

assistant: SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "显示器"
Schema: CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE problems (product_id VARCHAR)
user: 被称为“显示器”的产品有多少问题被记录？

assistant: SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "显示器"
Schema: CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE problems (product_id VARCHAR)
user: 出问题最多的产品有多少问题？列出问题的数量和产品名称。

assistant: SELECT count(*) ,  T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE problems (product_id VARCHAR)
user: 哪种产品有最多数量的问题？给出问题数量和产品名称。

assistant: SELECT count(*) ,  T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR)
user: 请给出一个名字为“梁”的工作人员报告的问题的描述列表。

assistant: SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁"
Schema: CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR)
user: 名字是“梁”的员工报告了哪些问题？显示问题的描述。

assistant: SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁"
Schema: CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR)
user: 找出姓氏为“兰兰”的工作人员报告的问题的ID。

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "兰兰"
Schema: CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR)
user: 姓“兰兰”的员工报告了哪些问题？显示问题的ID。

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "兰兰"
Schema: CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
user: “1978-06-26”后报告的问题的ID是什么？

assistant: SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
Schema: CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
user: 找出“1978-06-26”后所报告问题的ID。

assistant: SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
Schema: CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
user: “1978-06-26”之前报告的问题的ID是什么？

assistant: SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
Schema: CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
user: “1978-06-26”之前有哪些问题？把问题的ID告诉我。

assistant: SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
Schema: CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_id VARCHAR)
user: 对于每个有问题的产品，问题的数量和产品id是什么？

assistant: SELECT count(*) ,  T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
Schema: CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_id VARCHAR)
user: 对于每个有问题的产品，列出问题的数量和产品id。

assistant: SELECT count(*) ,  T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
Schema: CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER), CREATE TABLE product (product_id VARCHAR)
user: 对于每个有问题的产品，查找“1986-11-13”之后报告的问题的数量和产品ID？

assistant: SELECT count(*) ,  T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
Schema: CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER), CREATE TABLE product (product_id VARCHAR)
user: 在“1986-11-13”之后有哪些产品出现了问题？给我产品ID和“1986-11-13”后报告的问题数。

assistant: SELECT count(*) ,  T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
Schema: CREATE TABLE product (product_name VARCHAR)
user: 按字母顺序列出所有不同产品名称的名称。

assistant: SELECT DISTINCT product_name FROM product ORDER BY product_name
Schema: CREATE TABLE product (product_name VARCHAR)
user: 按字母顺序排列所有的不同的产品名称。

assistant: SELECT DISTINCT product_name FROM product ORDER BY product_name
Schema: CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
user: 按产品ID排序列出所有不同的产品名称。

assistant: SELECT DISTINCT product_name FROM product ORDER BY product_id
Schema: CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
user: 用产品ID排序的不同产品名称列表是什么？

assistant: SELECT DISTINCT product_name FROM product ORDER BY product_id
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 名字为“李” “航”或“白” “博文”的工作人员报告的问题的ID是什么？

assistant: SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李" AND T2.staff_last_name = "航" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "白" AND T2.staff_last_name = "博文"
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: “李” “航”或“白” “博文”的工作人员报告了哪些问题？给出问题的ID。

assistant: SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李" AND T2.staff_last_name = "航" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "白" AND T2.staff_last_name = "博文"
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR, closure_authorised_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 对于“梁” “天一”报告的由“李红” “军”授权关闭的问题的产品标识是什么？

assistant: SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁" AND T2.staff_last_name = "天一" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李红" AND T2.staff_last_name = "军"
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR, closure_authorised_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: “梁” “天一”报告了哪些产品的问题被“李红” “军”授权关闭？返回产品的ID。

assistant: SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁" AND T2.staff_last_name = "天一" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李红" AND T2.staff_last_name = "军"
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 在“严” “冰”报告的任何问题发生之前报告的问题的ID是什么？

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported  <  ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "严" AND T4.staff_last_name = "冰" )
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 在工作人员“严” “冰”报告任何问题的日期之前，报告了哪些问题？把问题的ID告诉我。

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported  <  ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "严" AND T4.staff_last_name = "冰" )
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 在“马” “军军”报告的问题之后报告的问题的ID是什么？

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported  >  ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "马" AND T4.staff_last_name = "军军" )
Schema: CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 找出在“马” “军军”员工报告的任何问题日期之后报告的问题的ID。

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported  >  ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "马" AND T4.staff_last_name = "军军" )
Schema: CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
user: 找出问题数量最多的3个产品。

assistant: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
user: 哪三种产品有最多的问题？

assistant: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
Schema: CREATE TABLE problems (product_id VARCHAR, problem_id VARCHAR, date_problem_reported INTEGER), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
user: 列出1995年以后报告的产品“显示器”中问题的ID？

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "显示器" AND T1.date_problem_reported > "1995"
Schema: CREATE TABLE problems (product_id VARCHAR, problem_id VARCHAR, date_problem_reported INTEGER), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
user: 在1995年以后报告了产品名字是“显示器”相关问题的id是什么？

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "显示器" AND T1.date_problem_reported > "1995"
Schema: CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_first_name VARCHAR, staff_id VARCHAR)
user: 找到那些从产品“内存”而不是“硬盘”报告问题的员工的名字和姓氏？

assistant: SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "内存" EXCEPT SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "硬盘"
Schema: CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_first_name VARCHAR, staff_id VARCHAR)
user: 哪些员工报告“内存”产品而不是“硬盘”产品的问题？给出他们的名字和姓氏。

assistant: SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "内存" EXCEPT SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "硬盘"
Schema: CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: 找出“刘” “兰兰”和“王” “平之”都报告有问题的产品

assistant: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "刘" AND T3.staff_last_name = "兰兰" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "王" AND T3.staff_last_name = "平之"
Schema: CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_id VARCHAR, product_name VARCHAR), CREATE TABLE staff (staff_last_name VARCHAR, staff_id VARCHAR, staff_first_name VARCHAR)
user: “刘” “兰兰”和员工“王” “平之”报告有问题的产品是哪些？

assistant: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "刘" AND T3.staff_last_name = "兰兰" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "王" AND T3.staff_last_name = "平之"
Schema: CREATE TABLE branch (membership_amount INTEGER)
user: 有多少分支机构的会员人数超过平均数？

assistant: SELECT count(*) FROM branch WHERE membership_amount  >  (SELECT avg(membership_amount) FROM branch)
Schema: CREATE TABLE branch (membership_amount INTEGER)
user: 有多少分支机构的成员数超过了平均数？

assistant: SELECT count(*) FROM branch WHERE membership_amount  >  (SELECT avg(membership_amount) FROM branch)
Schema: CREATE TABLE branch (city VARCHAR, address_road VARCHAR, name VARCHAR, open_year VARCHAR)
user: 按开业年份分列出所有分行名称、地址、道路和城市。

assistant: SELECT name ,  address_road ,  city FROM branch ORDER BY open_year
Schema: CREATE TABLE branch (city VARCHAR, address_road VARCHAR, name VARCHAR, open_year VARCHAR)
user: 按开业年份排序的分行的名称、地址道路和城市是什么？

assistant: SELECT name ,  address_road ,  city FROM branch ORDER BY open_year
Schema: CREATE TABLE branch (membership_amount VARCHAR, name VARCHAR)
user: 会员人数最多的三大分支机构是什么？

assistant: SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3
Schema: CREATE TABLE branch (membership_amount VARCHAR, name VARCHAR)
user: 拥有前三多会员人数的分支机构的名称是什么？

assistant: SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3
Schema: CREATE TABLE branch (membership_amount INTEGER, city VARCHAR)
user: 显示所有具有至少100个会员人数的分支机构所在的城市。

assistant: SELECT DISTINCT city FROM branch WHERE membership_amount  >=  100
Schema: CREATE TABLE branch (membership_amount INTEGER, city VARCHAR)
user: 哪些城市拥有超过100个会员资格？

assistant: SELECT DISTINCT city FROM branch WHERE membership_amount  >=  100
Schema: CREATE TABLE branch (open_year VARCHAR)
user: 列出至少两个商店开业的所有营业年。

assistant: SELECT open_year FROM branch GROUP BY open_year HAVING count(*)  >=  2
Schema: CREATE TABLE branch (open_year VARCHAR)
user: 开店时间至少有两个的营业年有哪些？

assistant: SELECT open_year FROM branch GROUP BY open_year HAVING count(*)  >=  2
Schema: CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR)
user: 显示2011年开业或位于"北京"的所有分行的最低和最高会员数量。

assistant: SELECT min(membership_amount) ,  max(membership_amount) FROM branch WHERE open_year  =  2011 OR city  =  '北京'
Schema: CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR)
user: 2011年开业或位于"北京"的所有分行的最低和最高会员人数是多少？

assistant: SELECT min(membership_amount) ,  max(membership_amount) FROM branch WHERE open_year  =  2011 OR city  =  '北京'
Schema: CREATE TABLE branch (city VARCHAR, open_year INTEGER)
user: 显示每个城市在2010年开放的每个分支机构的数量。

assistant: SELECT city ,  count(*) FROM branch WHERE open_year  <  2010 GROUP BY city
Schema: CREATE TABLE branch (city VARCHAR, open_year INTEGER)
user: 每一个城市，有多少分支机构在2010年之前开放？

assistant: SELECT city ,  count(*) FROM branch WHERE open_year  <  2010 GROUP BY city
Schema: CREATE TABLE member (LEVEL VARCHAR)
user: 会员有多少不同级别？

assistant: SELECT count(DISTINCT LEVEL) FROM member
Schema: CREATE TABLE member (LEVEL VARCHAR)
user: 不同的会员级别有哪些？

assistant: SELECT count(DISTINCT LEVEL) FROM member
Schema: CREATE TABLE member (LEVEL VARCHAR, card_number VARCHAR, name VARCHAR, hometown VARCHAR)
user: 按照级别的降序显示所有成员的卡号、姓名和家乡。

assistant: SELECT card_number ,  name ,  hometown FROM member ORDER BY LEVEL DESC
Schema: CREATE TABLE member (LEVEL VARCHAR, card_number VARCHAR, name VARCHAR, hometown VARCHAR)
user: 按降序排列的每个会员的卡号、姓名和家乡是什么？

assistant: SELECT card_number ,  name ,  hometown FROM member ORDER BY LEVEL DESC
Schema: CREATE TABLE member (LEVEL VARCHAR)
user: 显示成员数量最多的会员级别。

assistant: SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE member (LEVEL VARCHAR)
user: 人数最多的会员等级是什么？

assistant: SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE membership_register_branch (register_year VARCHAR, branch_id VARCHAR, member_id VARCHAR), CREATE TABLE branch (name VARCHAR, branch_id VARCHAR), CREATE TABLE member (name VARCHAR, member_id VARCHAR)
user: 按注册年份排序显示所有成员名字和的注册分支名称。

assistant: SELECT T3.name ,  T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id  =  T2.branch_id JOIN member AS T3 ON T1.member_id  =  T3.member_id ORDER BY T1.register_year
Schema: CREATE TABLE membership_register_branch (register_year VARCHAR, branch_id VARCHAR, member_id VARCHAR), CREATE TABLE branch (name VARCHAR, branch_id VARCHAR), CREATE TABLE member (name VARCHAR, member_id VARCHAR)
user: 按注册年份排序的注册会员和分支机构的名称是什么？

assistant: SELECT T3.name ,  T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id  =  T2.branch_id JOIN member AS T3 ON T1.member_id  =  T3.member_id ORDER BY T1.register_year
Schema: CREATE TABLE membership_register_branch (register_year INTEGER, branch_id VARCHAR), CREATE TABLE branch (name VARCHAR, branch_id VARCHAR)
user: 显示所有分支名称以及2015年后每个分支注册的成员数量。

assistant: SELECT T2.name ,  count(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id  =  T2.branch_id WHERE T1.register_year  >  2015 GROUP BY T2.branch_id
Schema: CREATE TABLE membership_register_branch (register_year INTEGER, branch_id VARCHAR), CREATE TABLE branch (name VARCHAR, branch_id VARCHAR)
user: 对于每个分支ID，2015年以后登记的分支名称是什么？

assistant: SELECT T2.name ,  count(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id  =  T2.branch_id WHERE T1.register_year  >  2015 GROUP BY T2.branch_id