jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”中哪里有好的“东北”餐厅？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 显示在“南山”好的“东北”餐厅吗

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“南山”地区一个好的“东北”菜餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 给出位置在“南山”的一家好的“东北”餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 请一个在“南山”的吃“东北”菜的好地方

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”中哪里有好的“东北”食物？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“南山”有什么餐厅可以吃到好吃的“东北”食品呢？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”地区有什么好的餐馆可以吃到“东北”菜？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 请一些“南山”地区好的“东北”餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 我能在“南山”附近的什么地方吃些好吃的“东北”菜呢？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 一些在“南山”附近吃“东北”菜的好地方

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”这边有哪里有好的“东北”菜餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 一家在“南山”的供应美味的“东北”食品的餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“南山”地区一些好的“东北”餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“南山”品尝“东北”菜的好地方在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“南山”中一些味道好的“东北”餐厅

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 一个在“南山”口碑好的餐馆吃“东北”菜

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”什么位置有好的“东北”餐厅？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”地区吃“东北”菜哪些地方比较好？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “南山”中的哪家餐馆能吃到可口的“东北”菜？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (food_type VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“南山”附近要品尝“东北”食物的一个合适的地方是哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "南山" AND t1.food_type  =  "东北" AND t1.rating  >  2.5;
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: 在“深圳”哪里可以找出“四川”菜肴？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.name  =  "四川";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”的“四川”菜餐馆在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.name  =  "四川";
Schema: CREATE TABLE restaurant (id VARCHAR, name VARCHAR), CREATE TABLE LOCATION (house_number VARCHAR, city_name VARCHAR, restaurant_id VARCHAR)
user: “深圳”的“四川”美食在哪里？

assistant: SELECT t2.house_number  ,  t1.name FROM restaurant AS t1 JOIN LOCATION AS t2 ON t1.id  =  t2.restaurant_id WHERE t2.city_name  =  "深圳" AND t1.name  =  "四川";
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: 在“厦门”我们可以在哪里找出一些餐厅？

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" );
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: 一些在“厦门”的餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" );
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: 一个位于“厦门”的饭店

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" );
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: 我在哪里可以找到“厦门”的餐厅？

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" );
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: 一家在“厦门”的好餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id  WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" ) AND t1.rating  >  2.5;
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”有什么好的餐馆？

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id  WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" ) AND t1.rating  >  2.5;
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: 一些地址在“厦门”的好餐馆

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id  WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" ) AND t1.rating  >  2.5;
Schema: CREATE TABLE LOCATION (house_number VARCHAR, restaurant_id VARCHAR), CREATE TABLE restaurant (city_name VARCHAR, id VARCHAR, name VARCHAR, rating INTEGER), CREATE TABLE geographic (region VARCHAR, city_name VARCHAR)
user: “厦门”的一家好餐馆是什么？

assistant: SELECT t2.house_number  ,  t1.name FROM LOCATION AS t2 JOIN restaurant AS t1 ON t1.id  =  t2.restaurant_id  WHERE t1.city_name IN ( SELECT city_name FROM geographic WHERE region  =  "厦门" ) AND t1.rating  >  2.5;