jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE Employee (eid VARCHAR, name VARCHAR), CREATE TABLE Certificate (aid VARCHAR, eid VARCHAR), CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER)
user: 持有距离超过5000飞机证书最多的员工的工资和姓名是什么？

assistant: SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid  =  T2.eid JOIN Aircraft AS T3 ON T3.aid  =  T2.aid WHERE T3.distance  >  5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Allergy_type (allergy VARCHAR)
user: 有多少过敏反应？

assistant: SELECT count(DISTINCT allergy) FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergy VARCHAR)
user: 有多少过敏项目？

assistant: SELECT count(DISTINCT allergy) FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 有多少种不同的过敏反应类型？

assistant: SELECT count(DISTINCT allergytype) FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 有多少种不同的过敏反应？

assistant: SELECT count(DISTINCT allergytype) FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 显示所有过敏类型。

assistant: SELECT DISTINCT allergytype FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 过敏的类型有哪些？

assistant: SELECT DISTINCT allergytype FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 显示所有过敏和他们的类型。

assistant: SELECT allergy ,  allergytype FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 过敏和它们的类型是什么？

assistant: SELECT allergy ,  allergytype FROM Allergy_type
Schema: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 显示所有类型的“食物”过敏。

assistant: SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype  =  "食物"
Schema: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 所有不同的“食物"过敏是什么？

assistant: SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype  =  "食物"
Schema: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 过敏原是"猫”的过敏类型是什么？

assistant: SELECT allergytype FROM Allergy_type WHERE allergy  =  "猫"
Schema: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: “猫”过敏是什么类型的？

assistant: SELECT allergytype FROM Allergy_type WHERE allergy  =  "猫"
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 有多少“动物”过敏反应？

assistant: SELECT count(*) FROM Allergy_type WHERE allergytype  =  "动物"
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 有多少种“动物”过敏？

assistant: SELECT count(*) FROM Allergy_type WHERE allergytype  =  "动物"
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 显示所有过敏类型和每种类型的数量。

assistant: SELECT allergytype ,  count(*) FROM Allergy_type GROUP BY allergytype
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 过敏类型有哪些？每种类型有多少种过敏反应？

assistant: SELECT allergytype ,  count(*) FROM Allergy_type GROUP BY allergytype
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 哪种过敏类型有最多的过敏反应？

assistant: SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 哪种过敏反应类型最常见？

assistant: SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 哪种过敏类型有最少的过敏反应？

assistant: SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE Allergy_type (allergytype VARCHAR)
user: 哪种过敏类型最不常见？

assistant: SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1
Schema: CREATE TABLE Student (Id VARCHAR)
user: 有多少学生？

assistant: SELECT count(*) FROM Student
Schema: CREATE TABLE Student (Id VARCHAR)
user: 学生总数是多少？

assistant: SELECT count(*) FROM Student
Schema: CREATE TABLE Student (Lname VARCHAR, Fname VARCHAR)
user: 显示所有学生的名字和姓氏。

assistant: SELECT Fname ,  Lname FROM Student
Schema: CREATE TABLE Student (Lname VARCHAR, Fname VARCHAR)
user: 所有学生的全名是什么？

assistant: SELECT Fname ,  Lname FROM Student
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 列出了多少不同的顾问？

assistant: SELECT count(DISTINCT advisor) FROM Student
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 有多少顾问？

assistant: SELECT count(DISTINCT advisor) FROM Student
Schema: CREATE TABLE Student (Major VARCHAR)
user: 显示所有专业。

assistant: SELECT DISTINCT Major FROM Student
Schema: CREATE TABLE Student (Major VARCHAR)
user: 不同专业有哪些？

assistant: SELECT DISTINCT Major FROM Student
Schema: CREATE TABLE Student (city_code VARCHAR)
user: 显示所有学生居住的城市。

assistant: SELECT DISTINCT city_code FROM Student
Schema: CREATE TABLE Student (city_code VARCHAR)
user: 学生居住在什么城市？

assistant: SELECT DISTINCT city_code FROM Student
Schema: CREATE TABLE Student (Age VARCHAR, Sex VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 显示所有女学生的名、姓氏、年龄。他们的性别是“女”.

assistant: SELECT Fname ,  Lname ,  Age FROM Student WHERE Sex  =  '女'
Schema: CREATE TABLE Student (Age VARCHAR, Sex VARCHAR, Lname VARCHAR, Fname VARCHAR)
user: 所有性别为“女”的女生全名和年龄是多少？

assistant: SELECT Fname ,  Lname ,  Age FROM Student WHERE Sex  =  '女'
Schema: CREATE TABLE Student (Sex VARCHAR, StuID VARCHAR)
user: 显示所有男生的学生ID。

assistant: SELECT StuID FROM Student WHERE Sex  =  '男'
Schema: CREATE TABLE Student (Sex VARCHAR, StuID VARCHAR)
user: 所有男生的学生ID是什么？

assistant: SELECT StuID FROM Student WHERE Sex  =  '男'
Schema: CREATE TABLE Student (age VARCHAR)
user: 18岁的学生有多少？

assistant: SELECT count(*) FROM Student WHERE age  =  18
Schema: CREATE TABLE Student (age VARCHAR)
user: 有多少18岁的学生？

assistant: SELECT count(*) FROM Student WHERE age  =  18
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR)
user: 显示所有20岁以上的学生ID。

assistant: SELECT StuID FROM Student WHERE age  >  20
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR)
user: 20岁以上学生的学生ID是什么？

assistant: SELECT StuID FROM Student WHERE age  >  20
Schema: CREATE TABLE Student (LName VARCHAR, city_code VARCHAR)
user: 姓“金”的学生住在哪个城市？

assistant: SELECT city_code FROM Student WHERE LName  =  "金"
Schema: CREATE TABLE Student (LName VARCHAR, city_code VARCHAR)
user: 给出姓“金”的学生所住的城市。

assistant: SELECT city_code FROM Student WHERE LName  =  "金"
Schema: CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
user: 谁是ID1004的学生的导师？

assistant: SELECT Advisor FROM Student WHERE StuID  =  1004
Schema: CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
user: 谁指导1004学生？

assistant: SELECT Advisor FROM Student WHERE StuID  =  1004
Schema: CREATE TABLE Student (city_code VARCHAR)
user: “香港”或“深圳”有多少学生聚准？

assistant: SELECT count(*) FROM Student WHERE city_code  =  "香港" OR city_code  =  "深圳"
Schema: CREATE TABLE Student (city_code VARCHAR)
user: 给出居住在“香港”或“深圳”学生的人数。

assistant: SELECT count(*) FROM Student WHERE city_code  =  "香港" OR city_code  =  "深圳"
Schema: CREATE TABLE Student (age INTEGER)
user: 显示所有学生的最低、平均和最大年龄。

assistant: SELECT min(age) ,  avg(age) ,  max(age) FROM Student
Schema: CREATE TABLE Student (age INTEGER)
user: 所有学生的最低年龄、平均年龄和最大年龄是多少？

assistant: SELECT min(age) ,  avg(age) ,  max(age) FROM Student
Schema: CREATE TABLE Student (age INTEGER, LName VARCHAR)
user: 最小的学生的姓是什么？

assistant: SELECT LName FROM Student WHERE age  =  (SELECT min(age) FROM Student)
Schema: CREATE TABLE Student (age INTEGER, LName VARCHAR)
user: 提供最年轻学生的姓氏。

assistant: SELECT LName FROM Student WHERE age  =  (SELECT min(age) FROM Student)
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR)
user: 显示最老学生的学生ID。

assistant: SELECT StuID FROM Student WHERE age  =  (SELECT max(age) FROM Student)
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR)
user: 最老的学生的学生ID是什么？

assistant: SELECT StuID FROM Student WHERE age  =  (SELECT max(age) FROM Student)
Schema: CREATE TABLE Student (major VARCHAR)
user: 显示所有专业和相应的学生数量。

assistant: SELECT major ,  count(*) FROM Student GROUP BY major
Schema: CREATE TABLE Student (major VARCHAR)
user: 每个专业有多少学生？

assistant: SELECT major ,  count(*) FROM Student GROUP BY major
Schema: CREATE TABLE Student (major VARCHAR)
user: 哪个专业的学生最多？

assistant: SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Student (major VARCHAR)
user: 最大的专业是什么？

assistant: SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Student (age VARCHAR)
user: 显示所有年龄和对应学生的数量。

assistant: SELECT age ,  count(*) FROM Student GROUP BY age
Schema: CREATE TABLE Student (age VARCHAR)
user: 每个学生年龄有多大？每个年龄段有多少学生？

assistant: SELECT age ,  count(*) FROM Student GROUP BY age
Schema: CREATE TABLE Student (sex VARCHAR, age INTEGER)
user: 显示男女学生的平均年龄。

assistant: SELECT avg(age) ,  sex FROM Student GROUP BY sex
Schema: CREATE TABLE Student (sex VARCHAR, age INTEGER)
user: 男女学生平均年龄是多少？

assistant: SELECT avg(age) ,  sex FROM Student GROUP BY sex
Schema: CREATE TABLE Student (city_code VARCHAR)
user: 显示所有城市和相应的学生数量。

assistant: SELECT city_code ,  count(*) FROM Student GROUP BY city_code
Schema: CREATE TABLE Student (city_code VARCHAR)
user: 每个城市有多少学生？

assistant: SELECT city_code ,  count(*) FROM Student GROUP BY city_code
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 显示所有的顾问和相应的学生人数。

assistant: SELECT advisor ,  count(*) FROM Student GROUP BY advisor
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 每位导师有多少学生？

assistant: SELECT advisor ,  count(*) FROM Student GROUP BY advisor
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 哪位导师的学生最多？

assistant: SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 给出最多学生的导师。

assistant: SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Has_allergy (Allergy VARCHAR)
user: 有多少学生患有“猫”过敏？

assistant: SELECT count(*) FROM Has_allergy WHERE Allergy  =  "猫"
Schema: CREATE TABLE Has_allergy (Allergy VARCHAR)
user: 有多少学生受到“猫”过敏的影响？

assistant: SELECT count(*) FROM Has_allergy WHERE Allergy  =  "猫"
Schema: CREATE TABLE Has_allergy (StuID VARCHAR)
user: 显示所有至少有两种过敏症的学生。

assistant: SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*)  >=  2
Schema: CREATE TABLE Has_allergy (StuID VARCHAR)
user: 有多个过敏反应的的学生的学生ID是什么？

assistant: SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*)  >=  2
Schema: CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Has_allergy (StuID VARCHAR)
user: 没有过敏的学生的学生ID是什么？

assistant: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
Schema: CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Has_allergy (StuID VARCHAR)
user: 哪些学生不受过敏影响？

assistant: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
Schema: CREATE TABLE has_allergy (allergy VARCHAR, StuID VARCHAR), CREATE TABLE Student (sex VARCHAR, StuID VARCHAR)
user: 有多少女学生有“鸡蛋”或“牛奶”过敏？

assistant: SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.sex  =  "女" AND T1.allergy  =  "牛奶" OR T1.allergy  =  "鸡蛋"
Schema: CREATE TABLE has_allergy (allergy VARCHAR, StuID VARCHAR), CREATE TABLE Student (sex VARCHAR, StuID VARCHAR)
user: 有多少女生对“鸡蛋”或“牛奶"过敏？

assistant: SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.sex  =  "女" AND T1.allergy  =  "牛奶" OR T1.allergy  =  "鸡蛋"
Schema: CREATE TABLE Has_allergy (allergy VARCHAR), CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 有多少学生有“食物”过敏？

assistant: SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy WHERE T2.allergytype  =  "食物"
Schema: CREATE TABLE Has_allergy (allergy VARCHAR), CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 有多少学生受“食物”过敏的影响？

assistant: SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy WHERE T2.allergytype  =  "食物"
Schema: CREATE TABLE Has_allergy (Allergy VARCHAR)
user: 哪些过敏反应影响的学生数量最多？

assistant: SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Has_allergy (Allergy VARCHAR)
user: 哪种过敏最常见？

assistant: SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Has_allergy (Allergy VARCHAR)
user: 显示所有受过敏影响的学生人数。

assistant: SELECT Allergy ,  count(*) FROM Has_allergy GROUP BY Allergy
Schema: CREATE TABLE Has_allergy (Allergy VARCHAR)
user: 每种过敏反应有多少学生？

assistant: SELECT Allergy ,  count(*) FROM Has_allergy GROUP BY Allergy
Schema: CREATE TABLE Has_allergy (allergy VARCHAR), CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 显示所有过敏类型与受影响的学生数量。

assistant: SELECT T2.allergytype ,  count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy GROUP BY T2.allergytype
Schema: CREATE TABLE Has_allergy (allergy VARCHAR), CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
user: 每一种过敏类型有多少学生受影响？

assistant: SELECT T2.allergytype ,  count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy GROUP BY T2.allergytype
Schema: CREATE TABLE Student (Allergy VARCHAR, lname VARCHAR, age VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR, lname VARCHAR, age VARCHAR, StuID VARCHAR)
user: 找出对“牛奶”和“猫”过敏的学生的姓氏和年龄。

assistant: SELECT lname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "牛奶" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy  =  "猫")
Schema: CREATE TABLE Student (Allergy VARCHAR, lname VARCHAR, age VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR, lname VARCHAR, age VARCHAR, StuID VARCHAR)
user: 对“牛奶”和“猫”过敏的学生的姓氏和年龄是多少？

assistant: SELECT lname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "牛奶" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy  =  "猫")
Schema: CREATE TABLE Allergy_type (AllergyType VARCHAR, Allergy VARCHAR), CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR), CREATE TABLE Student (Fname VARCHAR, StuID VARCHAR)
user: 名字是“莎莎”的学生有哪些过敏症和过敏类型？并以过敏反应的名称来分类结果。

assistant: SELECT T1.Allergy ,  T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy  =  T2.Allergy JOIN Student AS T3 ON T3.StuID  =  T2.StuID WHERE T3.Fname  =  "莎莎" ORDER BY T1.Allergy
Schema: CREATE TABLE Allergy_type (AllergyType VARCHAR, Allergy VARCHAR), CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR), CREATE TABLE Student (Fname VARCHAR, StuID VARCHAR)
user: 那个叫“莎莎”的女孩有什么过敏反应？它们的类型是什么？并以过敏反应的名称来分类结果。

assistant: SELECT T1.Allergy ,  T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy  =  T2.Allergy JOIN Student AS T3 ON T3.StuID  =  T2.StuID WHERE T3.Fname  =  "莎莎" ORDER BY T1.Allergy
Schema: CREATE TABLE Student (fname VARCHAR, Allergy VARCHAR, sex VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (fname VARCHAR, Allergy VARCHAR, sex VARCHAR, StuID VARCHAR)
user: 找出对“牛奶”过敏但不对“猫”过敏的学生的名字和性别。

assistant: SELECT fname ,  sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "牛奶" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy  =  "猫")
Schema: CREATE TABLE Student (fname VARCHAR, Allergy VARCHAR, sex VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (fname VARCHAR, Allergy VARCHAR, sex VARCHAR, StuID VARCHAR)
user: 对“牛奶”过敏但能忍受“猫”的学生的名字和性别是什么？

assistant: SELECT fname ,  sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "牛奶" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy  =  "猫")
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 找出对“动物”和“食物”类型过敏的学生的平均年龄。

assistant: SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "动物")
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 对“动物”和“食物”过敏的学生的平均年龄有多大？

assistant: SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "动物")
Schema: CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 列出没有“食物”过敏的学生的名字和姓氏。

assistant: SELECT fname ,  lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物")
Schema: CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 对任何类型的“食物”都不过敏的每个学生的全名是什么？

assistant: SELECT fname ,  lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物")
Schema: CREATE TABLE Student (sex VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 找到有“食物”类型过敏的男性(性别是“男”)的数量。

assistant: SELECT count(*) FROM Student WHERE sex  =  "男" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物")
Schema: CREATE TABLE Student (sex VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 有多少男学生(性别是“男”)对任何类型的“食物”过敏？

assistant: SELECT count(*) FROM Student WHERE sex  =  "男" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物")
Schema: CREATE TABLE Student (fname VARCHAR, stuid VARCHAR, city_code VARCHAR), CREATE TABLE Has_Allergy (stuid VARCHAR, Allergy VARCHAR)
user: 找出对“牛奶”或“猫”过敏的学生的不同名字和城市。

assistant: SELECT DISTINCT T1.fname ,  T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid  =  T2.stuid WHERE T2.Allergy  =  "牛奶" OR T2.Allergy  =  "猫"
Schema: CREATE TABLE Student (fname VARCHAR, stuid VARCHAR, city_code VARCHAR), CREATE TABLE Has_Allergy (stuid VARCHAR, Allergy VARCHAR)
user: 那些对“牛奶”或“猫”过敏的学生的不同名字和城市是什么？

assistant: SELECT DISTINCT T1.fname ,  T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid  =  T2.stuid WHERE T2.Allergy  =  "牛奶" OR T2.Allergy  =  "猫"
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 找出18岁以上、对“食物”和“动物”不过敏的学生人数。

assistant: SELECT count(*) FROM Student WHERE age  >  18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物" OR T2.allergytype  =  "动物")
Schema: CREATE TABLE Student (age INTEGER, StuID VARCHAR), CREATE TABLE Has_allergy (Allergy VARCHAR), CREATE TABLE Allergy_Type (allergytype VARCHAR, Allergy VARCHAR)
user: 有多少学生超过18岁，对“食物”类型或“动物”类型不过敏？

assistant: SELECT count(*) FROM Student WHERE age  >  18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy  =  T2.Allergy WHERE T2.allergytype  =  "食物" OR T2.allergytype  =  "动物")
Schema: CREATE TABLE Student (fname VARCHAR, Allergy VARCHAR, major VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (fname VARCHAR, Allergy VARCHAR, major VARCHAR, StuID VARCHAR)
user: 找到对“大豆”不过敏的学生的名字和专业。

assistant: SELECT fname ,  major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "大豆")
Schema: CREATE TABLE Student (fname VARCHAR, Allergy VARCHAR, major VARCHAR, StuID VARCHAR), CREATE TABLE Has_allergy (fname VARCHAR, Allergy VARCHAR, major VARCHAR, StuID VARCHAR)
user: 可以食用“大豆”的学生的名字和专业是什么？

assistant: SELECT fname ,  major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "大豆")
Schema: CREATE TABLE invoices (billing_country VARCHAR)
user: 给我一个发票数量前5的国家的列表。列出国家名称和发票数量。

assistant: SELECT billing_country ,  COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5;
Schema: CREATE TABLE invoices (billing_country VARCHAR)
user: 发票数量最多的5个国家是什么？他们有多少发票？

assistant: SELECT billing_country ,  COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5;
Schema: CREATE TABLE invoices (total INTEGER, billing_country VARCHAR)
user: 一个发票总额前8的国家的列表。列出国家名称和发票总额。

assistant: SELECT billing_country ,  SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8;
Schema: CREATE TABLE invoices (total INTEGER, billing_country VARCHAR)
user: 按发票总额计算，前8个国家的名称是什么？那些总额有多大？

assistant: SELECT billing_country ,  SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8;
Schema: CREATE TABLE invoices (total INTEGER, billing_country VARCHAR)
user: 平均发票大小前10的国家的列表。列出国家名称和平均发票大小。

assistant: SELECT billing_country ,  AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10;
Schema: CREATE TABLE invoices (total INTEGER, billing_country VARCHAR)
user: 平均发票大小最大的国家的名称和平均发票大小是多少？

assistant: SELECT billing_country ,  AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10;
Schema: CREATE TABLE customers (last_name VARCHAR, id VARCHAR, first_name VARCHAR), CREATE TABLE invoices (customer_id VARCHAR, invoice_date VARCHAR)
user: 找出最近购买了东西的5个客户。列出客户的名字和姓氏。

assistant: SELECT T1.first_name ,  T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id  =  T1.id ORDER BY T2.invoice_date DESC LIMIT 5;
Schema: CREATE TABLE customers (last_name VARCHAR, id VARCHAR, first_name VARCHAR), CREATE TABLE invoices (customer_id VARCHAR, invoice_date VARCHAR)
user: 最近买东西的5个顾客的名字和姓是什么？

assistant: SELECT T1.first_name ,  T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id  =  T1.id ORDER BY T2.invoice_date DESC LIMIT 5;
Schema: CREATE TABLE customers (last_name VARCHAR, id VARCHAR, first_name VARCHAR), CREATE TABLE invoices (customer_id VARCHAR)
user: 从订单总数中找出前10名客户。列出客户的姓氏和总订单数量。

assistant: SELECT T1.first_name ,  T1.last_name ,  COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id  =  T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10;
Schema: CREATE TABLE customers (last_name VARCHAR, id VARCHAR, first_name VARCHAR), CREATE TABLE invoices (customer_id VARCHAR)
user: 按订单总数计算，前十位客户的姓名和名字是什么？他们订了多少货？

assistant: SELECT T1.first_name ,  T1.last_name ,  COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id  =  T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10;
Schema: CREATE TABLE customers (last_name VARCHAR, id VARCHAR, first_name VARCHAR), CREATE TABLE invoices (total INTEGER, customer_id VARCHAR)
user: 列出总销售额的前10名客户。列出客户的姓名和总销售额。

assistant: SELECT T1.first_name ,  T1.last_name ,  SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id  =  T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10;
Schema: CREATE TABLE customers (last_name VARCHAR, id VARCHAR, first_name VARCHAR), CREATE TABLE invoices (total INTEGER, customer_id VARCHAR)
user: 销售总额最高的前10位客户的姓氏和名字是什么？销售量是多少？

assistant: SELECT T1.first_name ,  T1.last_name ,  SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id  =  T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10;
Schema: CREATE TABLE genres (id VARCHAR, name VARCHAR), CREATE TABLE tracks (genre_id VARCHAR)
user: 按照曲目数列出前5的流派。列出流派名称和总曲目。

assistant: SELECT T1.name ,  COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id  =  T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5;
Schema: CREATE TABLE genres (id VARCHAR, name VARCHAR), CREATE TABLE tracks (genre_id VARCHAR)
user: 前5名的流派有多少曲目，名字是什么？

assistant: SELECT T1.name ,  COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id  =  T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5;
Schema: CREATE TABLE albums (title VARCHAR)
user: 列出每一张专辑的标题。

assistant: SELECT title FROM albums;
Schema: CREATE TABLE albums (title VARCHAR)
user: 所有专辑的标题是什么？

assistant: SELECT title FROM albums;
Schema: CREATE TABLE albums (title VARCHAR)
user: 按专辑标题升序排列，列出每张专辑。

assistant: SELECT title FROM albums ORDER BY title;