jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE aircraft (Winning_Aircraft VARCHAR, Aircraft_ID VARCHAR, Aircraft VARCHAR), CREATE TABLE MATCH (Winning_Aircraft VARCHAR, Aircraft_ID VARCHAR, Aircraft VARCHAR)
user: 那些从来没有赢得任何比赛的飞机的名字是什么？

assistant: SELECT Aircraft FROM aircraft WHERE Aircraft_ID NOT IN (SELECT Winning_Aircraft FROM MATCH)
Schema: CREATE TABLE aircraft (Aircraft_ID VARCHAR, Aircraft VARCHAR), CREATE TABLE airport_aircraft (Aircraft_ID VARCHAR, Airport_ID VARCHAR), CREATE TABLE airport (Airport_Name VARCHAR, Airport_ID VARCHAR)
user: 显示与名为“北京首都机场”的机场和“北京南苑”的机场相关联的飞机的名称

assistant: SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID  =  T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID  =  T3.Airport_ID WHERE T3.Airport_Name  =  "北京首都机场" INTERSECT SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID  =  T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID  =  T3.Airport_ID WHERE T3.Airport_Name  =  "北京南苑"
Schema: CREATE TABLE aircraft (Aircraft_ID VARCHAR, Aircraft VARCHAR), CREATE TABLE airport_aircraft (Aircraft_ID VARCHAR, Airport_ID VARCHAR), CREATE TABLE airport (Airport_Name VARCHAR, Airport_ID VARCHAR)
user: 与“北京首都机场”机场和“北京南苑”机场有关的所有飞机的名称是什么？

assistant: SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID  =  T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID  =  T3.Airport_ID WHERE T3.Airport_Name  =  "北京首都机场" INTERSECT SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID  =  T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID  =  T3.Airport_ID WHERE T3.Airport_Name  =  "北京南苑"
Schema: CREATE TABLE airport (International_Passengers VARCHAR)
user: 显示国际旅客最多的机场的所有信息。

assistant: SELECT * FROM airport ORDER BY International_Passengers DESC LIMIT 1
Schema: CREATE TABLE airport (International_Passengers VARCHAR)
user: 国际旅客最多的机场有哪些信息？

assistant: SELECT * FROM airport ORDER BY International_Passengers DESC LIMIT 1
Schema: CREATE TABLE pilot (age INTEGER, name VARCHAR, pilot_id VARCHAR), CREATE TABLE MATCH (winning_pilot VARCHAR)
user: 找出在30岁以下的飞行员中获胜次数最多的飞行员的姓名和年龄。

assistant: SELECT t1.name ,  t1.age FROM pilot AS t1 JOIN MATCH AS t2 ON t1.pilot_id  =  t2.winning_pilot WHERE t1.age  <  30 GROUP BY t2.winning_pilot ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE pilot (age INTEGER, name VARCHAR, pilot_id VARCHAR), CREATE TABLE MATCH (winning_pilot VARCHAR)
user: 获胜次数最多的30岁以下的飞行员的姓名和年龄是多少？

assistant: SELECT t1.name ,  t1.age FROM pilot AS t1 JOIN MATCH AS t2 ON t1.pilot_id  =  t2.winning_pilot WHERE t1.age  <  30 GROUP BY t2.winning_pilot ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE pilot (age VARCHAR, name VARCHAR, pilot_id VARCHAR), CREATE TABLE MATCH (winning_pilot VARCHAR)
user: 最年轻的获奖飞行员的名字和年龄是多少？

assistant: SELECT t1.name ,  t1.age FROM pilot AS t1 JOIN MATCH AS t2 ON t1.pilot_id  =  t2.winning_pilot ORDER BY t1.age LIMIT 1
Schema: CREATE TABLE pilot (age VARCHAR, name VARCHAR, pilot_id VARCHAR), CREATE TABLE MATCH (winning_pilot VARCHAR)
user: 最年轻的中奖飞行员年龄多大？他们叫什么名字？

assistant: SELECT t1.name ,  t1.age FROM pilot AS t1 JOIN MATCH AS t2 ON t1.pilot_id  =  t2.winning_pilot ORDER BY t1.age LIMIT 1
Schema: CREATE TABLE pilot (country VARCHAR, name VARCHAR, pilot_id VARCHAR, Winning_Pilot VARCHAR), CREATE TABLE MATCH (country VARCHAR, name VARCHAR, pilot_id VARCHAR, Winning_Pilot VARCHAR)
user: 找出在“澳大利亚”举行的比赛中没有获胜的飞行员的名字。

assistant: SELECT name FROM pilot WHERE pilot_id NOT IN (SELECT Winning_Pilot  FROM MATCH WHERE country  =  '澳大利亚')
Schema: CREATE TABLE pilot (country VARCHAR, name VARCHAR, pilot_id VARCHAR, Winning_Pilot VARCHAR), CREATE TABLE MATCH (country VARCHAR, name VARCHAR, pilot_id VARCHAR, Winning_Pilot VARCHAR)
user: 在“澳大利亚”没有赢得任何比赛的飞行员的名字是什么？

assistant: SELECT name FROM pilot WHERE pilot_id NOT IN (SELECT Winning_Pilot  FROM MATCH WHERE country  =  '澳大利亚')
Schema: CREATE TABLE properties (property_id VARCHAR), CREATE TABLE residents (property_id VARCHAR)
user: 每个房产有多少居民？列出属性ID和常驻计数。

assistant: SELECT T1.property_id ,  count(*) FROM properties AS T1 JOIN residents AS T2 ON T1.property_id  =  T2.property_id GROUP BY T1.property_id
Schema: CREATE TABLE services (organization_id VARCHAR, service_type_code VARCHAR), CREATE TABLE organizations (organization_id VARCHAR, organization_details VARCHAR)
user: 有“父子聚会”细节的组织提供哪些不同的服务类型？

assistant: SELECT DISTINCT T1.service_type_code FROM services AS T1 JOIN organizations AS T2 ON T1.organization_id  =  T2.organization_id WHERE T2.organization_details  =  '父子聚会'
Schema: CREATE TABLE Residents (resident_id VARCHAR, other_details VARCHAR), CREATE TABLE Residents_Services (resident_id VARCHAR)
user: 每个居民需要多少服务？以计数的降序列出常驻ID、详细信息和计数。

assistant: SELECT T1.resident_id ,  T1.other_details ,  count(*) FROM Residents AS T1 JOIN Residents_Services AS T2 ON T1.resident_id  =  T2.resident_id GROUP BY T1.resident_id ORDER BY count(*) DESC
Schema: CREATE TABLE Services (service_id VARCHAR, service_details VARCHAR), CREATE TABLE Residents_Services (service_id VARCHAR)
user: 提供某一服务的最大数目是多少？列出服务ID、详细信息和号码。

assistant: SELECT T1.service_id ,  T1.service_details ,  count(*) FROM Services AS T1 JOIN Residents_Services AS T2 ON T1.service_id  =  T2.service_id GROUP BY T1.service_id ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Things (type_of_Thing_Code VARCHAR, thing_id VARCHAR, organization_id VARCHAR), CREATE TABLE Organizations (organization_id VARCHAR, organization_details VARCHAR)
user: 列出每个事物的id和类型，以及拥有它的组织的详细信息。

assistant: SELECT T1.thing_id ,  T1.type_of_Thing_Code ,  T2.organization_details FROM Things AS T1 JOIN Organizations AS T2 ON T1.organization_id  =  T2.organization_id
Schema: CREATE TABLE Customers (customer_details VARCHAR, customer_id VARCHAR), CREATE TABLE Customer_Events (customer_id VARCHAR)
user: 有3个事件的客户的id和细节是什么？

assistant: SELECT T1.customer_id ,  T1.customer_details FROM Customers AS T1 JOIN Customer_Events AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id HAVING count(*)  >=  3
Schema: CREATE TABLE Customers (customer_details VARCHAR, customer_id VARCHAR), CREATE TABLE Customer_Events (date_moved_in VARCHAR, customer_id VARCHAR)
user: 每个客户的移动日期是什么，以及相应的客户ID和细节？

assistant: SELECT T2.date_moved_in ,  T1.customer_id ,  T1.customer_details FROM Customers AS T1 JOIN Customer_Events AS T2 ON T1.customer_id  =  T2.customer_id
Schema: CREATE TABLE Customer_Events (customer_event_id VARCHAR, Customer_Event_ID VARCHAR, property_id VARCHAR), CREATE TABLE Customer_Event_Notes (Customer_Event_ID VARCHAR)
user: 哪些事件有一到三的记录？列出事件ID和属性ID。

assistant: SELECT T1.Customer_Event_ID  ,  T1.property_id FROM Customer_Events AS T1 JOIN Customer_Event_Notes AS T2 ON T1.Customer_Event_ID  =  T2.Customer_Event_ID GROUP BY T1.customer_event_id HAVING count(*) BETWEEN 1 AND 3
Schema: CREATE TABLE Timed_Status_of_Things (Date_and_Date INTEGER, thing_id VARCHAR, Status_of_Thing_Code VARCHAR), CREATE TABLE Things (Type_of_Thing_Code VARCHAR, thing_id VARCHAR)
user: 在日期“2017-06-19 02:59:21”之前具有“关闭”状态或状态记录的事物的不同id和类型是什么？

assistant: SELECT DISTINCT T2.thing_id ,  T2.Type_of_Thing_Code FROM Timed_Status_of_Things AS T1 JOIN Things AS T2 ON T1.thing_id  =  T2.thing_id WHERE T1.Status_of_Thing_Code  =  '关闭' OR T1.Date_and_Date  <  '2017-06-19 02:59:21'
Schema: CREATE TABLE Things (thing_id VARCHAR, service_details VARCHAR), CREATE TABLE Timed_Locations_of_Things (thing_id VARCHAR, Location_Code VARCHAR)
user: 有多少个不同的地点位于有东西的服务细节是“不满意的”的地方？

assistant: SELECT count(DISTINCT T2.Location_Code) FROM Things AS T1 JOIN Timed_Locations_of_Things AS T2 ON T1.thing_id  =  T2.thing_id WHERE T1.service_details  =  '不满意的'
Schema: CREATE TABLE Timed_Status_of_Things (Status_of_Thing_Code VARCHAR)
user: 有多少种不同的状态代码？

assistant: SELECT count(DISTINCT Status_of_Thing_Code) FROM Timed_Status_of_Things
Schema: CREATE TABLE organizations (parent_organization_id VARCHAR, organization_id VARCHAR)
user: 哪些组织不是其他组织的父组织？列出组织ID。

assistant: SELECT organization_id FROM organizations EXCEPT SELECT parent_organization_id FROM organizations
Schema: CREATE TABLE Residents (date_moved_in INTEGER)
user: 居民入住的最后一天是什么时候？

assistant: SELECT max(date_moved_in) FROM Residents
Schema: CREATE TABLE Residents (other_details VARCHAR)
user: 包含子字符串“女士”的驻留详细信息是什么？

assistant: SELECT other_details FROM Residents WHERE other_details LIKE '女士'
Schema: CREATE TABLE customer_events (property_id VARCHAR, date_moved_in VARCHAR, customer_event_id VARCHAR)
user: 列出客户事件ID和日期，入住日期和属性ID。

assistant: SELECT customer_event_id ,  date_moved_in ,  property_id FROM customer_events
Schema: CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_events (customer_id VARCHAR)
user: 有多少客户没有任何活动？

assistant: SELECT count(*) FROM customers WHERE customer_id NOT IN ( SELECT customer_id FROM customer_events )
Schema: CREATE TABLE residents (date_moved_in VARCHAR)
user: 居民的日期有什么不同？

assistant: SELECT DISTINCT date_moved_in FROM residents
Schema: CREATE TABLE school (LOCATION VARCHAR, Enrollment VARCHAR)
user: 按升学顺序列出学校的位置。

assistant: SELECT LOCATION FROM school ORDER BY Enrollment ASC
Schema: CREATE TABLE school (LOCATION VARCHAR, Enrollment VARCHAR)
user: 按入学升序排列的学校位置列表是什么？

assistant: SELECT LOCATION FROM school ORDER BY Enrollment ASC
Schema: CREATE TABLE school (LOCATION VARCHAR, Founded VARCHAR)
user: 按创办年的降序列出学校的位置。

assistant: SELECT LOCATION FROM school ORDER BY Founded DESC
Schema: CREATE TABLE school (LOCATION VARCHAR, Founded VARCHAR)
user: 学校创办年降序排列的学校名单是什么？

assistant: SELECT LOCATION FROM school ORDER BY Founded DESC
Schema: CREATE TABLE school (Denomination VARCHAR, Enrollment VARCHAR)
user: 教派教不是“天主教”的学校的入学人数是什么？

assistant: SELECT Enrollment FROM school WHERE Denomination != "天主教"
Schema: CREATE TABLE school (Denomination VARCHAR, Enrollment VARCHAR)
user: 列出没有“天主教”教派的每所学校的入学人数。

assistant: SELECT Enrollment FROM school WHERE Denomination != "天主教"
Schema: CREATE TABLE school (Enrollment INTEGER)
user: 学校平均入学数是多少？

assistant: SELECT avg(Enrollment) FROM school
Schema: CREATE TABLE school (Enrollment INTEGER)
user: 以平均入学数为准。

assistant: SELECT avg(Enrollment) FROM school
Schema: CREATE TABLE player (Team VARCHAR)
user: 按字母升序排列的队伍的球员是什么？

assistant: SELECT Team FROM player ORDER BY Team ASC
Schema: CREATE TABLE player (Team VARCHAR)
user: 找到每个球员的队伍并按字母顺序排列它们。

assistant: SELECT Team FROM player ORDER BY Team ASC
Schema: CREATE TABLE player (POSITION VARCHAR)
user: 球员有多少不同的位置？

assistant: SELECT count(DISTINCT POSITION) FROM player
Schema: CREATE TABLE player (POSITION VARCHAR)
user: 计算不同球员位置的数量。

assistant: SELECT count(DISTINCT POSITION) FROM player
Schema: CREATE TABLE player (Age VARCHAR, Team VARCHAR)
user: 找到最高年龄球员的队伍。

assistant: SELECT Team FROM player ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE player (Age VARCHAR, Team VARCHAR)
user: 哪个队的球员年龄最大？

assistant: SELECT Team FROM player ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE player (Age VARCHAR, Team VARCHAR)
user: 列出前5名年龄最大的球员所在的队伍。

assistant: SELECT Team FROM player ORDER BY Age DESC LIMIT 5
Schema: CREATE TABLE player (Age VARCHAR, Team VARCHAR)
user: 有5个最老球员的球队是什么？

assistant: SELECT Team FROM player ORDER BY Age DESC LIMIT 5
Schema: CREATE TABLE player (School_ID VARCHAR, Team VARCHAR), CREATE TABLE school (School_ID VARCHAR, Location VARCHAR)
user: 对于每个球员，显示他们所在的队伍和学校的所在地。

assistant: SELECT T1.Team ,  T2.Location FROM player AS T1 JOIN school AS T2 ON T1.School_ID  =  T2.School_ID
Schema: CREATE TABLE player (School_ID VARCHAR, Team VARCHAR), CREATE TABLE school (School_ID VARCHAR, Location VARCHAR)
user: 每个球员的队伍和学校的位置是什么？

assistant: SELECT T1.Team ,  T2.Location FROM player AS T1 JOIN school AS T2 ON T1.School_ID  =  T2.School_ID
Schema: CREATE TABLE player (School_ID VARCHAR), CREATE TABLE school (School_ID VARCHAR, Location VARCHAR)
user: 展示有超过1名球员的学校的位置。

assistant: SELECT T2.Location FROM player AS T1 JOIN school AS T2 ON T1.School_ID  =  T2.School_ID GROUP BY T1.School_ID HAVING COUNT(*)  >  1
Schema: CREATE TABLE player (School_ID VARCHAR), CREATE TABLE school (School_ID VARCHAR, Location VARCHAR)
user: 哪些学校有超过1名球员？给我学校的位置。

assistant: SELECT T2.Location FROM player AS T1 JOIN school AS T2 ON T1.School_ID  =  T2.School_ID GROUP BY T1.School_ID HAVING COUNT(*)  >  1
Schema: CREATE TABLE player (School_ID VARCHAR), CREATE TABLE school (Denomination VARCHAR, School_ID VARCHAR)
user: 显示拥有最多球员的学校的教派。

assistant: SELECT T2.Denomination FROM player AS T1 JOIN school AS T2 ON T1.School_ID  =  T2.School_ID GROUP BY T1.School_ID ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE player (School_ID VARCHAR), CREATE TABLE school (Denomination VARCHAR, School_ID VARCHAR)
user: 拥有最多数球员的学校的教派是什么？

assistant: SELECT T2.Denomination FROM player AS T1 JOIN school AS T2 ON T1.School_ID  =  T2.School_ID GROUP BY T1.School_ID ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE school (School_ID VARCHAR, Location VARCHAR), CREATE TABLE school_details (Nickname VARCHAR, School_ID VARCHAR)
user: 显示学校的地点和昵称。

assistant: SELECT T1.Location ,  T2.Nickname FROM school AS T1 JOIN school_details AS T2 ON T1.School_ID  =  T2.School_ID
Schema: CREATE TABLE school (School_ID VARCHAR, Location VARCHAR), CREATE TABLE school_details (Nickname VARCHAR, School_ID VARCHAR)
user: 每个学校的位置和昵称是什么？

assistant: SELECT T1.Location ,  T2.Nickname FROM school AS T1 JOIN school_details AS T2 ON T1.School_ID  =  T2.School_ID
Schema: CREATE TABLE school (Denomination VARCHAR)
user: 请出示不同的教派和相应的学校的数量。

assistant: SELECT Denomination ,  COUNT(*) FROM school GROUP BY Denomination
Schema: CREATE TABLE school (Denomination VARCHAR)
user: 对于每个教派，返回教派和具有该教派的学校的数量。

assistant: SELECT Denomination ,  COUNT(*) FROM school GROUP BY Denomination
Schema: CREATE TABLE school (Denomination VARCHAR)
user: 请按降序显示不同的教派和相应的学校数量。

assistant: SELECT Denomination ,  COUNT(*) FROM school GROUP BY Denomination ORDER BY COUNT(*) DESC
Schema: CREATE TABLE school (Denomination VARCHAR)
user: 按学校数量的降序排列教派。返回每个教派及其对应学校的数量。

assistant: SELECT Denomination ,  COUNT(*) FROM school GROUP BY Denomination ORDER BY COUNT(*) DESC
Schema: CREATE TABLE school (School_Colors VARCHAR, Enrollment VARCHAR)
user: 列出学校招生人数最多的学校颜色。

assistant: SELECT School_Colors FROM school ORDER BY Enrollment DESC LIMIT 1
Schema: CREATE TABLE school (School_Colors VARCHAR, Enrollment VARCHAR)
user: 招生人数最多的学校的学校色彩是什么？

assistant: SELECT School_Colors FROM school ORDER BY Enrollment DESC LIMIT 1
Schema: CREATE TABLE school (LOCATION VARCHAR, School_ID VARCHAR), CREATE TABLE Player (LOCATION VARCHAR, School_ID VARCHAR)
user: 列出没有任何球员的学校的位置。

assistant: SELECT LOCATION FROM school WHERE School_ID NOT IN (SELECT School_ID FROM Player)
Schema: CREATE TABLE school (LOCATION VARCHAR, School_ID VARCHAR), CREATE TABLE Player (LOCATION VARCHAR, School_ID VARCHAR)
user: 哪些学校没有球员？给我学校的位置。

assistant: SELECT LOCATION FROM school WHERE School_ID NOT IN (SELECT School_ID FROM Player)
Schema: CREATE TABLE school (Denomination VARCHAR, Founded INTEGER)
user: 显示1890年前建立的学校和1900后建立的学校所共有的教派

assistant: SELECT Denomination FROM school WHERE Founded  <  1890 INTERSECT SELECT Denomination FROM school WHERE Founded  >  1900
Schema: CREATE TABLE school (Denomination VARCHAR, Founded INTEGER)
user: 1890年以前建立的学校和1900年以后建立的学校都使用什么教派?

assistant: SELECT Denomination FROM school WHERE Founded  <  1890 INTERSECT SELECT Denomination FROM school WHERE Founded  >  1900
Schema: CREATE TABLE school_details (Nickname VARCHAR, Division VARCHAR)
user: 显示不属于“第一机构”的学校的昵称。

assistant: SELECT Nickname FROM school_details WHERE Division != "第一机构"
Schema: CREATE TABLE school_details (Nickname VARCHAR, Division VARCHAR)
user: 不是“第一机构”学校划分的是什么？

assistant: SELECT Nickname FROM school_details WHERE Division != "第一机构"
Schema: CREATE TABLE school (Denomination VARCHAR)
user: 显示一个以上学校共享的教派。

assistant: SELECT Denomination FROM school GROUP BY Denomination HAVING COUNT(*)  >  1
Schema: CREATE TABLE school (Denomination VARCHAR)
user: 一个学校有多少教派？

assistant: SELECT Denomination FROM school GROUP BY Denomination HAVING COUNT(*)  >  1
Schema: CREATE TABLE district (District_name VARCHAR, city_area VARCHAR)
user: 查找城市区域降序排列的所有区域名称。

assistant: SELECT DISTINCT District_name FROM district ORDER BY city_area DESC
Schema: CREATE TABLE district (District_name VARCHAR, city_area VARCHAR)
user: 按市区区域降序排列的不同的区域名称是什么？

assistant: SELECT DISTINCT District_name FROM district ORDER BY city_area DESC
Schema: CREATE TABLE product (max_page_size VARCHAR)
user: 找出具有超过3个产品列表的页面大小列表

assistant: SELECT max_page_size FROM product GROUP BY max_page_size HAVING count(*)  >  3
Schema: CREATE TABLE product (max_page_size VARCHAR)
user: 超过3个产品列表的所有产品的最大页面大小是多少？

assistant: SELECT max_page_size FROM product GROUP BY max_page_size HAVING count(*)  >  3
Schema: CREATE TABLE district (District_name VARCHAR, City_Population INTEGER)
user: 查找人口在20万到200万之间的地区的名称和人口

assistant: SELECT District_name ,  City_Population FROM district WHERE City_Population BETWEEN 200000 AND 2000000
Schema: CREATE TABLE district (District_name VARCHAR, City_Population INTEGER)
user: 20万到200万居民之间的所有地区的区名和城市人口是多少？

assistant: SELECT District_name ,  City_Population FROM district WHERE City_Population BETWEEN 200000 AND 2000000
Schema: CREATE TABLE district (City_Population INTEGER, district_name VARCHAR, city_area INTEGER)
user: 查找城市面积大于10或人口大于10万的所有地区的名称

assistant: SELECT district_name FROM district WHERE city_area  >  10 OR City_Population  >  100000
Schema: CREATE TABLE district (City_Population INTEGER, district_name VARCHAR, city_area INTEGER)
user: 市区面积大于10或居住10万人以上的地区名称是什么？

assistant: SELECT district_name FROM district WHERE city_area  >  10 OR City_Population  >  100000
Schema: CREATE TABLE district (city_population VARCHAR, district_name VARCHAR)
user: 哪个地区人口最多？

assistant: SELECT district_name FROM district ORDER BY city_population DESC LIMIT 1
Schema: CREATE TABLE district (city_population VARCHAR, district_name VARCHAR)
user: 居民最多的地区叫什么名字？

assistant: SELECT district_name FROM district ORDER BY city_population DESC LIMIT 1
Schema: CREATE TABLE district (city_area VARCHAR, district_name VARCHAR)
user: 哪个地区的面积最少？

assistant: SELECT district_name FROM district ORDER BY city_area ASC LIMIT 1
Schema: CREATE TABLE district (city_area VARCHAR, district_name VARCHAR)
user: 面积最小的地区叫什么名字？

assistant: SELECT district_name FROM district ORDER BY city_area ASC LIMIT 1
Schema: CREATE TABLE district (city_area VARCHAR, city_population INTEGER)
user: 找出总面积最大的3个区的总人口。

assistant: SELECT sum(city_population) FROM district ORDER BY city_area DESC LIMIT 3
Schema: CREATE TABLE district (city_area VARCHAR, city_population INTEGER)
user: 三大最大区域的居民总数是多少？

assistant: SELECT sum(city_population) FROM district ORDER BY city_area DESC LIMIT 3
Schema: CREATE TABLE store (TYPE VARCHAR)
user: 查找所有类型的商店和其对应的数量。

assistant: SELECT TYPE ,  count(*) FROM store GROUP BY TYPE
Schema: CREATE TABLE store (TYPE VARCHAR)
user: 对于每种类型的商店，有多少种？

assistant: SELECT TYPE ,  count(*) FROM store GROUP BY TYPE
Schema: CREATE TABLE store (store_id VARCHAR, store_name VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, district_name VARCHAR)
user: 找到“上城区”所有商店的名称。

assistant: SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id WHERE t3.district_name  =  "上城区"
Schema: CREATE TABLE store (store_id VARCHAR, store_name VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, district_name VARCHAR)
user: “上城区”所有商店的名称是什么？

assistant: SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id WHERE t3.district_name  =  "上城区"
Schema: CREATE TABLE store (store_id VARCHAR, store_name VARCHAR), CREATE TABLE store_district (store_id VARCHAR), CREATE TABLE district (city_population VARCHAR, district_id VARCHAR)
user: 找到人口最多的地区所有的商店。

assistant: SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id WHERE district_id  =  (SELECT district_id FROM district ORDER BY city_population DESC LIMIT 1)
Schema: CREATE TABLE store (store_id VARCHAR, store_name VARCHAR), CREATE TABLE store_district (store_id VARCHAR), CREATE TABLE district (city_population VARCHAR, district_id VARCHAR)
user: 人口最多的地区所有商店的名称是什么？

assistant: SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id WHERE district_id  =  (SELECT district_id FROM district ORDER BY city_population DESC LIMIT 1)
Schema: CREATE TABLE store (store_id VARCHAR, store_name VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, headquartered_city VARCHAR)
user: 哪个城市是“卡西欧”店的总部？

assistant: SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id WHERE t1.store_name  =  "卡西欧"
Schema: CREATE TABLE store (store_id VARCHAR, store_name VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, headquartered_city VARCHAR)
user: 哪个商店是“卡西欧”商场的总部？

assistant: SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id WHERE t1.store_name  =  "卡西欧"
Schema: CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, headquartered_city VARCHAR)
user: 查找每个城市的商店数量。

assistant: SELECT t3.headquartered_city ,  count(*) FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id GROUP BY t3.headquartered_city
Schema: CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, headquartered_city VARCHAR)
user: 每个城市都有多少商店的总部？

assistant: SELECT t3.headquartered_city ,  count(*) FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id GROUP BY t3.headquartered_city
Schema: CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, headquartered_city VARCHAR)
user: 找到拥有最多商店的城市。

assistant: SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id GROUP BY t3.headquartered_city ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (store_id VARCHAR, district_id VARCHAR), CREATE TABLE district (district_id VARCHAR, headquartered_city VARCHAR)
user: 哪一个城市的旗舰店数量最多？

assistant: SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id  =  t2.store_id JOIN district AS t3 ON t2.district_id  =  t3.district_id GROUP BY t3.headquartered_city ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE product (pages_per_minute_color INTEGER)
user: 每分钟颜色的平均页数是多少？

assistant: SELECT avg(pages_per_minute_color) FROM product
Schema: CREATE TABLE product (pages_per_minute_color INTEGER)
user: 每分钟颜色的平均页数的数量是多少？

assistant: SELECT avg(pages_per_minute_color) FROM product
Schema: CREATE TABLE product (product_id VARCHAR, product VARCHAR), CREATE TABLE store_product (product_id VARCHAR, store_id VARCHAR), CREATE TABLE store (store_id VARCHAR, store_name VARCHAR)
user: 叫“安踏”商店里有什么产品？

assistant: SELECT t1.product FROM product AS t1 JOIN store_product AS t2 ON t1.product_id  =  t2.product_id JOIN store AS t3 ON t2.store_id  =  t3.store_id WHERE t3.store_name  =  "安踏"
Schema: CREATE TABLE product (product_id VARCHAR, product VARCHAR), CREATE TABLE store_product (product_id VARCHAR, store_id VARCHAR), CREATE TABLE store (store_id VARCHAR, store_name VARCHAR)
user: 在“安踏”店里卖什么产品？

assistant: SELECT t1.product FROM product AS t1 JOIN store_product AS t2 ON t1.product_id  =  t2.product_id JOIN store AS t3 ON t2.store_id  =  t3.store_id WHERE t3.store_name  =  "安踏"