jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (product_id VARCHAR, order_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
user: 既订购了“拿铁”产品又订购了“美式咖啡”产品的客户的名字是什么？

assistant: SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id  =  t2.customer_id JOIN order_items AS t3 ON t2.order_id  =  t3.order_id JOIN products AS t4 ON t3.product_id  =  t4.product_id WHERE t4.product_details  =  "拿铁" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id  =  t2.customer_id JOIN order_items AS t3 ON t2.order_id  =  t3.order_id JOIN products AS t4 ON t3.product_id  =  t4.product_id WHERE t4.product_details  =  "美式咖啡"
Schema: CREATE TABLE artist (Id VARCHAR)
user: 那里有多少艺术家？

assistant: SELECT count(*) FROM artist
Schema: CREATE TABLE artist (Age VARCHAR)
user: 列出所有音乐艺术家的年龄。

assistant: SELECT Age FROM artist
Schema: CREATE TABLE artist (Age VARCHAR)
user: 所有音乐艺术家的年龄是多少？

assistant: SELECT Age FROM artist
Schema: CREATE TABLE artist (Age INTEGER)
user: 所有艺术家的平均年龄是多少？

assistant: SELECT avg(Age) FROM artist
Schema: CREATE TABLE artist (Age INTEGER)
user: 返回所有艺术家的平均年龄。

assistant: SELECT avg(Age) FROM artist
Schema: CREATE TABLE artist (Artist VARCHAR, Famous_Title VARCHAR)
user: 艺术家“徐悲鸿”著名的称号是什么？

assistant: SELECT Famous_Title FROM artist WHERE Artist  =  "徐悲鸿"
Schema: CREATE TABLE artist (Artist VARCHAR, Famous_Title VARCHAR)
user: 返回著名艺术家的名字叫做“徐悲鸿”的称号。

assistant: SELECT Famous_Title FROM artist WHERE Artist  =  "徐悲鸿"
Schema: CREATE TABLE artist (Famous_Release_date VARCHAR)
user: 什么是不同的著名的发行日期？

assistant: SELECT distinct(Famous_Release_date) FROM artist
Schema: CREATE TABLE artist (Famous_Release_date VARCHAR)
user: 给所有艺术家不同的著名的发行日期。

assistant: SELECT distinct(Famous_Release_date) FROM artist
Schema: CREATE TABLE music_festival (RESULT VARCHAR, Date_of_ceremony VARCHAR)
user: 返回仪式的日期和所有音乐节的结果

assistant: SELECT Date_of_ceremony ,  RESULT FROM music_festival
Schema: CREATE TABLE music_festival (RESULT VARCHAR, Date_of_ceremony VARCHAR)
user: 仪式的日期和所有音乐节的结果是什么？

assistant: SELECT Date_of_ceremony ,  RESULT FROM music_festival
Schema: CREATE TABLE music_festival (RESULT VARCHAR, Category VARCHAR)
user: 结果是“已获奖”的音乐节的类别是什么？

assistant: SELECT Category FROM music_festival WHERE RESULT  =  "已获奖"
Schema: CREATE TABLE music_festival (RESULT VARCHAR, Category VARCHAR)
user: 返回结果是“已获奖”的音乐节的类别。

assistant: SELECT Category FROM music_festival WHERE RESULT  =  "已获奖"
Schema: CREATE TABLE volume (Weeks_on_Top INTEGER)
user: 所有专辑的最大和最小登顶周是多少？

assistant: SELECT max(Weeks_on_Top) ,  min(Weeks_on_Top) FROM volume
Schema: CREATE TABLE volume (Weeks_on_Top INTEGER)
user: 给出所有专辑的最大和最小登顶周数。

assistant: SELECT max(Weeks_on_Top) ,  min(Weeks_on_Top) FROM volume
Schema: CREATE TABLE volume (Weeks_on_Top INTEGER, Song VARCHAR)
user: 音源超过1周的登顶歌曲是什么？

assistant: SELECT Song FROM volume WHERE Weeks_on_Top  >  1
Schema: CREATE TABLE volume (Weeks_on_Top INTEGER, Song VARCHAR)
user: 给出超过一周登顶的被收录在专辑的歌曲。

assistant: SELECT Song FROM volume WHERE Weeks_on_Top  >  1
Schema: CREATE TABLE volume (Song VARCHAR)
user: 请按升序字母顺序列出所有专辑的歌曲。

assistant: SELECT Song FROM volume ORDER BY Song
Schema: CREATE TABLE volume (Song VARCHAR)
user: 专辑的歌曲按升序排列是什么？

assistant: SELECT Song FROM volume ORDER BY Song
Schema: CREATE TABLE volume (Artist_ID VARCHAR)
user: 专辑有多少不同的艺术家？

assistant: SELECT COUNT(DISTINCT Artist_ID) FROM volume
Schema: CREATE TABLE volume (Artist_ID VARCHAR)
user: 计算拥有专辑的不同艺术家的数量。

assistant: SELECT COUNT(DISTINCT Artist_ID) FROM volume
Schema: CREATE TABLE music_festival (Volume VARCHAR, Date_of_ceremony VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Volume_ID VARCHAR)
user: 请显示超过两周登顶的专辑典礼日期。

assistant: SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume  =  T2.Volume_ID WHERE T2.Weeks_on_Top  >  2
Schema: CREATE TABLE music_festival (Volume VARCHAR, Date_of_ceremony VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Volume_ID VARCHAR)
user: 在音乐节上，超过两周登顶的专辑典礼日期是什么？

assistant: SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume  =  T2.Volume_ID WHERE T2.Weeks_on_Top  >  2
Schema: CREATE TABLE music_festival (Volume VARCHAR, Result VARCHAR), CREATE TABLE volume (Volume_ID VARCHAR, Song VARCHAR)
user: 请显示在音乐节上有“提名”的歌曲。

assistant: SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume  =  T2.Volume_ID WHERE T1.Result  =  "提名"
Schema: CREATE TABLE music_festival (Volume VARCHAR, Result VARCHAR), CREATE TABLE volume (Volume_ID VARCHAR, Song VARCHAR)
user: 在音乐节上有“提名”的歌曲有哪些？

assistant: SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume  =  T2.Volume_ID WHERE T1.Result  =  "提名"
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Artist VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR, Issue_Date VARCHAR)
user: 与艺术家“张敬轩”相关的专辑的发行日期是什么？

assistant: SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.Artist  =  "张敬轩"
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Artist VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR, Issue_Date VARCHAR)
user: 返回由名字是“张敬轩”的艺术家的专辑的发行日期。

assistant: SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.Artist  =  "张敬轩"
Schema: CREATE TABLE artist (age INTEGER, Artist_ID VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR, Song VARCHAR)
user: 专辑中32岁或以上的艺术家相关的歌曲是什么？

assistant: SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.age  >=  32
Schema: CREATE TABLE artist (age INTEGER, Artist_ID VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR, Song VARCHAR)
user: 返回专辑中由至少32岁的艺术家创作的歌曲名。

assistant: SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.age  >=  32
Schema: CREATE TABLE artist (age INTEGER, Artist_ID VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
user: 25岁或更小的艺术家专辑登顶的平均周数是多少？

assistant: SELECT avg(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.age  <=  25
Schema: CREATE TABLE artist (age INTEGER, Artist_ID VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
user: 返回最大25岁的艺术家专辑登顶的平均周数。

assistant: SELECT avg(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.age  <=  25
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Famous_Title VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
user: 与登顶超过2周的专辑有关艺术家的著名作品是什么？

assistant: SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T2.Weeks_on_Top  >  2
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Famous_Title VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
user: 返回登顶超过2周的专辑有关艺术家的著名作品。

assistant: SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T2.Weeks_on_Top  >  2
Schema: CREATE TABLE artist (Age VARCHAR, Famous_Title VARCHAR)
user: 请按年龄降序列出艺术家的年龄和著名作品名称。

assistant: SELECT Famous_Title ,  Age FROM artist ORDER BY Age DESC
Schema: CREATE TABLE artist (Age VARCHAR, Famous_Title VARCHAR)
user: 按年龄顺序排列的每个艺术家的著名作品和年龄是什么？

assistant: SELECT Famous_Title ,  Age FROM artist ORDER BY Age DESC
Schema: CREATE TABLE artist (Age VARCHAR, Famous_Release_date VARCHAR)
user: 年龄最大的艺术家的著名发行日期是什么？

assistant: SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE artist (Age VARCHAR, Famous_Release_date VARCHAR)
user: 返回年龄最大的艺术家的著名发行日期。

assistant: SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1
Schema: CREATE TABLE music_festival (Category VARCHAR)
user: 请显示音乐节的类别和数量。

assistant: SELECT Category ,  COUNT(*) FROM music_festival GROUP BY Category
Schema: CREATE TABLE music_festival (Category VARCHAR)
user: 返回每个种类音乐节的数量。

assistant: SELECT Category ,  COUNT(*) FROM music_festival GROUP BY Category
Schema: CREATE TABLE music_festival (RESULT VARCHAR)
user: 音乐节最常见的结果是什么？

assistant: SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE music_festival (RESULT VARCHAR)
user: 返回在音乐节最频繁的结果。

assistant: SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE music_festival (Category VARCHAR)
user: 请显示计数超过1的音乐节的类别。

assistant: SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*)  >  1
Schema: CREATE TABLE music_festival (Category VARCHAR)
user: 超过1个的音乐节有哪些类别？

assistant: SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*)  >  1
Schema: CREATE TABLE volume (Weeks_on_Top VARCHAR, Song VARCHAR)
user: 专辑中登顶最多周数的歌曲是什么？

assistant: SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1
Schema: CREATE TABLE volume (Weeks_on_Top VARCHAR, Song VARCHAR)
user: 返回专辑中登顶最多周数的歌曲。

assistant: SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Famous_Title VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR, Famous_Title VARCHAR)
user: 找出那些没有任何专辑的艺术家的著名作品。

assistant: SELECT Famous_Title FROM artist WHERE Artist_ID NOT IN(SELECT Artist_ID FROM volume)
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Famous_Title VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR, Famous_Title VARCHAR)
user: 没有任何专辑的艺术家的著名作品是什么？

assistant: SELECT Famous_Title FROM artist WHERE Artist_ID NOT IN(SELECT Artist_ID FROM volume)
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Famous_Title VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
user: 展现艺术家的著名头衔，两卷的顶部持续超过2周，两卷的顶部持续不到2周。

assistant: SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T2.Weeks_on_Top  >  2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T2.Weeks_on_Top  <  2
Schema: CREATE TABLE artist (Artist_ID VARCHAR, Famous_Title VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
user: 什么是艺术家的著名头衔，他们不仅花了超过2周的卷顶部，而且花了不到2周的卷顶部？

assistant: SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T2.Weeks_on_Top  >  2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T2.Weeks_on_Top  <  2
Schema: CREATE TABLE music_festival (RESULT VARCHAR, Date_of_ceremony VARCHAR, Category VARCHAR)
user: “金曲”类别和“已获奖”类别音乐节相对应的仪式日期是什么？

assistant: SELECT Date_of_ceremony FROM music_festival WHERE Category  =  "金曲奖" AND RESULT  =  "已获奖"
Schema: CREATE TABLE music_festival (RESULT VARCHAR, Date_of_ceremony VARCHAR, Category VARCHAR)
user: 返回与“金曲”类别和“已获奖”类别音乐节相对应的仪式日期。

assistant: SELECT Date_of_ceremony FROM music_festival WHERE Category  =  "金曲奖" AND RESULT  =  "已获奖"
Schema: CREATE TABLE volume (Issue_Date VARCHAR, Weeks_on_Top VARCHAR)
user: 最短登顶周数专辑的发行日期是什么？

assistant: SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top ASC LIMIT 1
Schema: CREATE TABLE volume (Issue_Date VARCHAR, Weeks_on_Top VARCHAR)
user: 返回最短登顶周数专辑的发行日期。

assistant: SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top ASC LIMIT 1
Schema: CREATE TABLE volume (Artist_ID VARCHAR)
user: 有多少不同的艺术家有专辑？

assistant: SELECT COUNT(DISTINCT Artist_ID) FROM volume
Schema: CREATE TABLE volume (Artist_ID VARCHAR)
user: 统计有专辑的不同艺术家的数量。

assistant: SELECT COUNT(DISTINCT Artist_ID) FROM volume
Schema: CREATE TABLE music_festival (RESULT VARCHAR)
user: 请显示音乐节的结果和以此计数的音乐节的数量。

assistant: SELECT RESULT ,  COUNT(*) FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC
Schema: CREATE TABLE music_festival (RESULT VARCHAR)
user: 按次序递减，有多少个音乐节有结果？

assistant: SELECT RESULT ,  COUNT(*) FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC
Schema: CREATE TABLE artist (age INTEGER, Artist_ID VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR)
user: 23岁或更年轻的艺术家相关的专辑的发行日期是什么？

assistant: SELECT Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.age  <=  23
Schema: CREATE TABLE artist (age INTEGER, Artist_ID VARCHAR), CREATE TABLE volume (Artist_ID VARCHAR)
user: 返回23岁或更年轻的艺术家专辑的发行日期。

assistant: SELECT Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID  =  T2.Artist_ID WHERE T1.age  <=  23
Schema: CREATE TABLE roller_coaster (Id VARCHAR)
user: 有多少过山车？

assistant: SELECT count(*) FROM roller_coaster
Schema: CREATE TABLE roller_coaster (Name VARCHAR, LENGTH VARCHAR)
user: 按长度递增的顺序列出过山车的名称。

assistant: SELECT Name FROM roller_coaster ORDER BY LENGTH ASC
Schema: CREATE TABLE roller_coaster (Height VARCHAR, LENGTH VARCHAR)
user: 过山车的长度和高度是多少？

assistant: SELECT LENGTH ,  Height FROM roller_coaster
Schema: CREATE TABLE country (Name VARCHAR, Languages VARCHAR)
user: 列出那些语言不是“德语”的国家的名字。

assistant: SELECT Name FROM country WHERE Languages != "德语"
Schema: CREATE TABLE roller_coaster (Status VARCHAR, LENGTH INTEGER, Height INTEGER)
user: 显示长度超过3300或高度超过100的过山车的状态。

assistant: SELECT Status FROM roller_coaster WHERE LENGTH  >  3300 OR Height  >  100
Schema: CREATE TABLE roller_coaster (Speed VARCHAR, LENGTH VARCHAR)
user: 最长过山车的速度是多少？

assistant: SELECT Speed FROM roller_coaster ORDER BY LENGTH DESC LIMIT 1
Schema: CREATE TABLE roller_coaster (Speed INTEGER)
user: 过山车的平均速度是多少？

assistant: SELECT avg(Speed) FROM roller_coaster
Schema: CREATE TABLE roller_coaster (Status VARCHAR)
user: 显示不同状态和每一个状态过山车的数量。

assistant: SELECT Status ,  COUNT(*) FROM roller_coaster GROUP BY Status
Schema: CREATE TABLE roller_coaster (Status VARCHAR)
user: 请展示最普遍的过山车的状态。

assistant: SELECT Status FROM roller_coaster GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
Schema: CREATE TABLE roller_coaster (Status VARCHAR)
user: 列出两个过山车共享的状态。

assistant: SELECT Status FROM roller_coaster GROUP BY Status HAVING COUNT(*)  >  2
Schema: CREATE TABLE roller_coaster (Park VARCHAR, Speed VARCHAR)
user: 显示有最快的速度过山车的公园。

assistant: SELECT Park FROM roller_coaster ORDER BY Speed DESC LIMIT 1
Schema: CREATE TABLE country (Country_ID VARCHAR, Name VARCHAR), CREATE TABLE roller_coaster (Country_ID VARCHAR, Name VARCHAR)
user: 显示过山车的名字和他们所在的国家的名字。

assistant: SELECT T2.Name ,  T1.Name FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID  =  T2.Country_ID
Schema: CREATE TABLE country (Country_ID VARCHAR, Name VARCHAR), CREATE TABLE roller_coaster (Country_ID VARCHAR)
user: 显示有超过一辆过山车的国家的名字。

assistant: SELECT T1.Name FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID  =  T2.Country_ID GROUP BY T1.Name HAVING COUNT(*)  >  1
Schema: CREATE TABLE country (Country_ID VARCHAR, population VARCHAR, Name VARCHAR), CREATE TABLE roller_coaster (Country_ID VARCHAR, Height VARCHAR)
user: 显示具有最高过山车的国家的名称和人口。

assistant: SELECT T1.Name ,  T1.population FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID  =  T2.Country_ID ORDER BY T2.Height DESC LIMIT 1
Schema: CREATE TABLE country (Country_ID VARCHAR, Name VARCHAR), CREATE TABLE roller_coaster (Country_ID VARCHAR, Speed INTEGER)
user: 显示国家名称和每个国家的过山车的平均速度。

assistant: SELECT T1.Name ,  avg(T2.Speed) FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID  =  T2.Country_ID GROUP BY T1.Name
Schema: CREATE TABLE country (country_id VARCHAR, LENGTH INTEGER), CREATE TABLE roller_coaster (country_id VARCHAR, LENGTH INTEGER)
user: 有多少国家没有长度超过3000的过山车？

assistant: SELECT count(*) FROM country WHERE country_id NOT IN ( SELECT country_id FROM roller_coaster WHERE LENGTH  >  3000 )
Schema: CREATE TABLE country (Country_ID VARCHAR, population VARCHAR, area VARCHAR, name VARCHAR), CREATE TABLE roller_coaster (Country_ID VARCHAR, speed INTEGER)
user: 拥有更快速的过山车的国家名称，区域和人口是什么？

assistant: SELECT T1.name ,  T1.area ,  T1.population FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID  =  T2.Country_ID WHERE T2.speed  >  60 INTERSECT SELECT T1.name ,  T1.area ,  T1.population FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID  =  T2.Country_ID WHERE T2.speed  <  55
Schema: CREATE TABLE captain (rank VARCHAR)
user: 有多少不同船长等级？

assistant: SELECT count(DISTINCT rank) FROM captain
Schema: CREATE TABLE captain (rank VARCHAR)
user: 计算不同船长等级的数量。

assistant: SELECT count(DISTINCT rank) FROM captain
Schema: CREATE TABLE captain (rank VARCHAR)
user: 每个级别有多少船长？

assistant: SELECT count(*) ,  rank FROM captain GROUP BY rank
Schema: CREATE TABLE captain (rank VARCHAR)
user: 计算每个等级的船长的数量。

assistant: SELECT count(*) ,  rank FROM captain GROUP BY rank
Schema: CREATE TABLE captain (age INTEGER, rank VARCHAR)
user: 每一个等级有多少个50岁以下的船长？

assistant: SELECT count(*) ,  rank FROM captain WHERE age  <  50 GROUP BY rank
Schema: CREATE TABLE captain (age INTEGER, rank VARCHAR)
user: 计算每个等级中50岁以下的船长人数。

assistant: SELECT count(*) ,  rank FROM captain WHERE age  <  50 GROUP BY rank
Schema: CREATE TABLE captain (age VARCHAR, name VARCHAR)
user: 把船长的姓名按年龄从老到年轻分类。

assistant: SELECT name FROM captain ORDER BY age DESC
Schema: CREATE TABLE captain (age VARCHAR, name VARCHAR)
user: 按年龄下降排序的船长的名字是什么？

assistant: SELECT name FROM captain ORDER BY age DESC
Schema: CREATE TABLE captain (CLASS VARCHAR, name VARCHAR, rank VARCHAR)
user: 找出所有船长的姓名、级别和等级。

assistant: SELECT name ,  CLASS ,  rank FROM captain
Schema: CREATE TABLE captain (CLASS VARCHAR, name VARCHAR, rank VARCHAR)
user: 所有船长的姓名、级别和等级是多少？

assistant: SELECT name ,  CLASS ,  rank FROM captain
Schema: CREATE TABLE captain (rank VARCHAR)
user: 队长中哪一个等级最常见？

assistant: SELECT rank FROM captain GROUP BY rank ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE captain (rank VARCHAR)
user: 返回船长数量最少的等级。

assistant: SELECT rank FROM captain GROUP BY rank ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE captain (CLASS VARCHAR)
user: 哪个班有两个以上的队长？

assistant: SELECT CLASS FROM captain GROUP BY CLASS HAVING count(*)  >  2
Schema: CREATE TABLE captain (CLASS VARCHAR)
user: 给出拥有两个以上船长的班级。

assistant: SELECT CLASS FROM captain GROUP BY CLASS HAVING count(*)  >  2
Schema: CREATE TABLE captain (rank VARCHAR, name VARCHAR)
user: 找出等级是“少尉”或“中卫”的船长的名字。

assistant: SELECT name FROM captain WHERE rank  =  "少尉" OR rank  =  "中尉"
Schema: CREATE TABLE captain (rank VARCHAR, name VARCHAR)
user: 等级是“少尉”或“中卫”的船长名字是什么？

assistant: SELECT name FROM captain WHERE rank  =  "少尉" OR rank  =  "中尉"
Schema: CREATE TABLE captain (age INTEGER, CLASS VARCHAR)
user: 不同级别的船长平均年龄和最小年龄是多少？

assistant: SELECT avg(age) ,  min(age) ,  CLASS FROM captain GROUP BY CLASS
Schema: CREATE TABLE captain (age INTEGER, CLASS VARCHAR)
user: 返回每个班队长的平均年龄和最小年龄。

assistant: SELECT avg(age) ,  min(age) ,  CLASS FROM captain GROUP BY CLASS
Schema: CREATE TABLE captain (CLASS VARCHAR, rank VARCHAR)
user: 找出在“切割机”类和“武装纵帆船”类的船长的级别。

assistant: SELECT rank FROM captain WHERE CLASS  =  "切割机" INTERSECT SELECT rank FROM captain WHERE CLASS  =  "武装纵帆船"
Schema: CREATE TABLE captain (CLASS VARCHAR, rank VARCHAR)
user: 在“切割机”和“武装纵帆船”类的船长的级别是什么？

assistant: SELECT rank FROM captain WHERE CLASS  =  "切割机" INTERSECT SELECT rank FROM captain WHERE CLASS  =  "武装纵帆船"
Schema: CREATE TABLE captain (CLASS VARCHAR, rank VARCHAR)
user: 找出没有在“第三级船的线路类”的船长的级别。

assistant: SELECT rank FROM captain EXCEPT SELECT rank FROM captain WHERE CLASS  =  "第三级船的线路类"
Schema: CREATE TABLE captain (CLASS VARCHAR, rank VARCHAR)
user: 没有在“第三级船的线路类”的船长的级别是什么？

assistant: SELECT rank FROM captain EXCEPT SELECT rank FROM captain WHERE CLASS  =  "第三级船的线路类"
Schema: CREATE TABLE captain (age VARCHAR, name VARCHAR)
user: 最年轻的船长叫什么名字？

assistant: SELECT name FROM captain ORDER BY age LIMIT 1
Schema: CREATE TABLE captain (age VARCHAR, name VARCHAR)
user: 返回最年轻的船长的名字。

assistant: SELECT name FROM captain ORDER BY age LIMIT 1
Schema: CREATE TABLE ship (Id VARCHAR)
user: 计算船的数量。

assistant: SELECT count(*) FROM ship
Schema: CREATE TABLE ship (built_year VARCHAR, name VARCHAR, flag VARCHAR, TYPE VARCHAR)
user: 找出最近一年建造的船的名称、类型和标志。

assistant: SELECT name ,  TYPE ,  flag FROM ship ORDER BY built_year DESC LIMIT 1
Schema: CREATE TABLE ship (built_year VARCHAR, name VARCHAR, flag VARCHAR, TYPE VARCHAR)
user: 最近一年建造的船的名称、类型和标志是什么？

assistant: SELECT name ,  TYPE ,  flag FROM ship ORDER BY built_year DESC LIMIT 1
Schema: CREATE TABLE ship (flag VARCHAR)
user: 以标志为单位，返回每种标志的船舶数量。

assistant: SELECT count(*) ,  flag FROM ship GROUP BY flag
Schema: CREATE TABLE ship (flag VARCHAR)
user: 不同的船的标志是真么，每种标志的船有多少艘？

assistant: SELECT count(*) ,  flag FROM ship GROUP BY flag
Schema: CREATE TABLE ship (flag VARCHAR)
user: 哪种标志在船上使用最广？

assistant: SELECT flag FROM ship GROUP BY flag ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE ship (flag VARCHAR)
user: 返回所有船只中最常见的标志。

assistant: SELECT flag FROM ship GROUP BY flag ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE ship (built_year VARCHAR, CLASS VARCHAR, name VARCHAR)
user: 按建造年份和类别的顺序列出所有的船名。

assistant: SELECT name FROM ship ORDER BY built_year ,  CLASS
Schema: CREATE TABLE ship (built_year VARCHAR, CLASS VARCHAR, name VARCHAR)
user: 按建造年份和类别的顺序列出所有船的名字是什么？

assistant: SELECT name FROM ship ORDER BY built_year ,  CLASS
Schema: CREATE TABLE ship (TYPE VARCHAR, flag VARCHAR)
user: 找出使用“巴拿马”和“马耳他”标志的船型。

assistant: SELECT TYPE FROM ship WHERE flag  =  "巴拿马" INTERSECT SELECT TYPE FROM ship WHERE flag  =  "马耳他"
Schema: CREATE TABLE ship (TYPE VARCHAR, flag VARCHAR)
user: 既使用“巴拿马”又使用“马耳他”标志的船型是什么？

assistant: SELECT TYPE FROM ship WHERE flag  =  "巴拿马" INTERSECT SELECT TYPE FROM ship WHERE flag  =  "马耳他"
Schema: CREATE TABLE ship (built_year VARCHAR)
user: 多数船是在哪一年建造的？

assistant: SELECT built_year FROM ship GROUP BY built_year ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE ship (built_year VARCHAR)
user: 多数船建造的年份是哪一年？

assistant: SELECT built_year FROM ship GROUP BY built_year ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE ship (ship_id VARCHAR, name VARCHAR), CREATE TABLE captain (ship_id VARCHAR)
user: 找出拥有不止一个船长的船的名称。

assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id  =  t2.ship_id GROUP BY t2.ship_id HAVING count(*)  >  1
Schema: CREATE TABLE ship (ship_id VARCHAR, name VARCHAR), CREATE TABLE captain (ship_id VARCHAR)
user: 拥有不止一个船长的船的名称是什么？

assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id  =  t2.ship_id GROUP BY t2.ship_id HAVING count(*)  >  1
Schema: CREATE TABLE ship (CLASS VARCHAR, name VARCHAR, ship_id VARCHAR), CREATE TABLE captain (CLASS VARCHAR, name VARCHAR, ship_id VARCHAR)
user: 那些没有船长的船的名字和级别是什么？

assistant: SELECT name ,  CLASS FROM ship WHERE ship_id NOT IN (SELECT ship_id FROM captain)
Schema: CREATE TABLE ship (CLASS VARCHAR, name VARCHAR, ship_id VARCHAR), CREATE TABLE captain (CLASS VARCHAR, name VARCHAR, ship_id VARCHAR)
user: 返回没有船长的船的名字和类别.

assistant: SELECT name ,  CLASS FROM ship WHERE ship_id NOT IN (SELECT ship_id FROM captain)
Schema: CREATE TABLE ship (ship_id VARCHAR, name VARCHAR), CREATE TABLE captain (ship_id VARCHAR, age VARCHAR)
user: 找出最年轻船长指挥的那艘船的名字。

assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id  =  t2.ship_id ORDER BY t2.age LIMIT 1
Schema: CREATE TABLE ship (ship_id VARCHAR, name VARCHAR), CREATE TABLE captain (ship_id VARCHAR, age VARCHAR)
user: 最年轻的船长指挥的那艘船叫什么名字？

assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id  =  t2.ship_id ORDER BY t2.age LIMIT 1
Schema: CREATE TABLE ship (rank VARCHAR, ship_id VARCHAR, name VARCHAR, flag VARCHAR), CREATE TABLE captain (rank VARCHAR, ship_id VARCHAR, name VARCHAR, flag VARCHAR)
user: 找出没有“中尉”级别的船长指挥的船名和标志。

assistant: SELECT name ,  flag FROM ship WHERE ship_id NOT IN (SELECT ship_id FROM captain WHERE rank  =  "中尉")
Schema: CREATE TABLE ship (rank VARCHAR, ship_id VARCHAR, name VARCHAR, flag VARCHAR), CREATE TABLE captain (rank VARCHAR, ship_id VARCHAR, name VARCHAR, flag VARCHAR)
user: 没有“中尉”级别的船长指挥的船名和标志是什么？

assistant: SELECT name ,  flag FROM ship WHERE ship_id NOT IN (SELECT ship_id FROM captain WHERE rank  =  "中尉")
Schema: CREATE TABLE ship (ship_id VARCHAR, name VARCHAR), CREATE TABLE captain (ship_id VARCHAR, rank VARCHAR)
user: 找出既由“少尉”级别的船长也由“中尉”级别的船长驾驶的船名。

assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id  =  t2.ship_id WHERE t2.rank  =  "少尉" INTERSECT SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id  =  t2.ship_id WHERE t2.rank  =  "中尉"