jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE employees (hire_date INTEGER)
user: “1987-09-07”以后雇佣了哪些员工？

assistant: SELECT * FROM employees WHERE hire_date  >  '1987-09-07'
Schema: CREATE TABLE jobs (min_salary INTEGER, job_title VARCHAR)
user: 显示最低工资大于9000的职位名称。

assistant: SELECT job_title FROM jobs WHERE min_salary  >  9000
Schema: CREATE TABLE jobs (min_salary INTEGER, job_title VARCHAR)
user: 哪些职位对应的薪水超过9000？

assistant: SELECT job_title FROM jobs WHERE min_salary  >  9000
Schema: CREATE TABLE jobs (min_salary VARCHAR, max_salary INTEGER, job_title VARCHAR)
user: 显示最高工资在1200至1800范围内的职位名称和最低和最高工资之间的差额。

assistant: SELECT job_title ,  max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
Schema: CREATE TABLE jobs (min_salary VARCHAR, max_salary INTEGER, job_title VARCHAR)
user: 最高工资在12000至1800之间的工作名称，以及工资范围是什么？

assistant: SELECT job_title ,  max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
Schema: CREATE TABLE employees (email VARCHAR, commission_pct VARCHAR, salary INTEGER, department_id VARCHAR)
user: 显示那些没有佣金百分比而且薪水在7000-12000范围内并且工作于50号部门的员工的电子邮件。

assistant: SELECT email FROM employees WHERE commission_pct  =  "空" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
Schema: CREATE TABLE employees (email VARCHAR, commission_pct VARCHAR, salary INTEGER, department_id VARCHAR)
user: 那些没有佣金，工资在7000到120000之间，而且在部门50工作的员工的电子邮件是什么？

assistant: SELECT email FROM employees WHERE commission_pct  =  "空" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
Schema: CREATE TABLE job_history (end_date INTEGER, employee_id VARCHAR)
user: 显示每个雇员的雇员ID和他结束前一份工作的日期。

assistant: SELECT employee_id ,  MAX(end_date) FROM job_history GROUP BY employee_id
Schema: CREATE TABLE job_history (end_date INTEGER, employee_id VARCHAR)
user: 每个雇员的雇员id是什么？他们的上一份工作的最后工作日期是什么？

assistant: SELECT employee_id ,  MAX(end_date) FROM job_history GROUP BY employee_id
Schema: CREATE TABLE employees (commission_pct VARCHAR, department_id VARCHAR)
user: 显示那些有10多名员工工作并获得佣金的部门。

assistant: SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
Schema: CREATE TABLE employees (commission_pct VARCHAR, department_id VARCHAR)
user: 有哪些部门有超过10名拿到佣金的员工，这些部门的id是什么？

assistant: SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
Schema: CREATE TABLE employees (manager_id VARCHAR, department_id VARCHAR, employee_id VARCHAR)
user: 查找任何管理4名或更多员工的经理所在部门的ID。

assistant: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Schema: CREATE TABLE employees (manager_id VARCHAR, department_id VARCHAR, employee_id VARCHAR)
user: 管理超过3名员工的经理所在部门的部门id是什么？

assistant: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Schema: CREATE TABLE employees (commission_pct VARCHAR, salary INTEGER, department_id VARCHAR)
user: 显示每个部门获得佣金百分比的雇员的平均工资。

assistant: SELECT department_id ,  AVG(salary) FROM employees WHERE commission_pct != "空" GROUP BY department_id
Schema: CREATE TABLE employees (commission_pct VARCHAR, salary INTEGER, department_id VARCHAR)
user: 佣金百分比不为零的雇员的平均工资是多少？

assistant: SELECT department_id ,  AVG(salary) FROM employees WHERE commission_pct != "空" GROUP BY department_id
Schema: CREATE TABLE locations (country_id VARCHAR)
user: 显示每个国家的城市ID和城市数量。

assistant: SELECT country_id ,  COUNT(*) FROM locations GROUP BY country_id
Schema: CREATE TABLE locations (country_id VARCHAR)
user: 给出每个国家的城市ID和相应的城市数量。

assistant: SELECT country_id ,  COUNT(*) FROM locations GROUP BY country_id
Schema: CREATE TABLE job_history (end_date VARCHAR, start_date VARCHAR, job_id VARCHAR)
user: 显示有两次或更多次超过300天才完成的作业的ID。

assistant: SELECT job_id FROM job_history WHERE end_date - start_date  > 300 GROUP BY job_id HAVING COUNT(*) >= 2
Schema: CREATE TABLE job_history (end_date VARCHAR, start_date VARCHAR, job_id VARCHAR)
user: 对于不止一次超过300天才完成的工作，这些工作的ID是什么？

assistant: SELECT job_id FROM job_history WHERE end_date - start_date  > 300 GROUP BY job_id HAVING COUNT(*) >= 2
Schema: CREATE TABLE job_history (employee_id VARCHAR)
user: 显示那些过去做过两个或更多工作的员工id。

assistant: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Schema: CREATE TABLE job_history (employee_id VARCHAR)
user: 做过两个或更多工作的员工的员工ID是什么？

assistant: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Schema: CREATE TABLE employees (department_id VARCHAR, employee_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (country_id VARCHAR, location_id VARCHAR), CREATE TABLE countries (country_name VARCHAR, country_id VARCHAR)
user: 找到员工的id和目前他正在工作的国家的名称。

assistant: SELECT T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Schema: CREATE TABLE employees (department_id VARCHAR, employee_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (country_id VARCHAR, location_id VARCHAR), CREATE TABLE countries (country_name VARCHAR, country_id VARCHAR)
user: 所有员工的id和他们工作的国家的名称是什么？

assistant: SELECT T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 显示部门名称和每个部门的员工人数。

assistant: SELECT T2.department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY T2.department_name
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 给出每个部门的名称和部门中员工的人数。

assistant: SELECT T2.department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY T2.department_name
Schema: CREATE TABLE job_history (employee_id VARCHAR), CREATE TABLE employees (salary INTEGER, employee_id VARCHAR)
user: 你能返回目前工资在120000及以上的员工所从事的工作的详细信息吗？

assistant: SELECT * FROM  job_history AS T1 JOIN employees AS T2 ON T1.employee_id  =  T2.employee_id WHERE T2.salary  >=  12000
Schema: CREATE TABLE job_history (employee_id VARCHAR), CREATE TABLE employees (salary INTEGER, employee_id VARCHAR)
user: 由工资高于或等于12000的员工完成的工作的历史信息是什么？

assistant: SELECT * FROM  job_history AS T1 JOIN employees AS T2 ON T1.employee_id  =  T2.employee_id WHERE T2.salary  >=  12000
Schema: CREATE TABLE employees (job_id VARCHAR), CREATE TABLE jobs (job_id VARCHAR, job_title VARCHAR)
user: 显示员工的职称和平均工资。

assistant: SELECT job_title ,  AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id GROUP BY T2.job_title
Schema: CREATE TABLE employees (job_id VARCHAR), CREATE TABLE jobs (job_id VARCHAR, job_title VARCHAR)
user: 每个职位的平均工资是多少？

assistant: SELECT job_title ,  AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id GROUP BY T2.job_title
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR, employee_id VARCHAR)
user: 工资高于id为163的员工的那些员工的全名（姓、名）是多少？

assistant: SELECT first_name ,  last_name FROM employees WHERE salary  >  (SELECT salary FROM employees WHERE employee_id = 163 )
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR, employee_id VARCHAR)
user: 提供工资超过id为163号的员工的员工的全名。

assistant: SELECT first_name ,  last_name FROM employees WHERE salary  >  (SELECT salary FROM employees WHERE employee_id = 163 )
Schema: CREATE TABLE employees (salary INTEGER, department_id VARCHAR)
user: 返回每个部门的最低工资。

assistant: SELECT MIN(salary) ,  department_id FROM employees GROUP BY department_id
Schema: CREATE TABLE employees (salary INTEGER, department_id VARCHAR)
user: 每个部门的最低工资是多少？

assistant: SELECT MIN(salary) ,  department_id FROM employees GROUP BY department_id
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR, department_id VARCHAR)
user: 找到在所有部门中挣的工资最低的员工的名字、姓氏和部门id。

assistant: SELECT first_name ,  last_name ,  department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR, department_id VARCHAR)
user: 所有部门工资最低的员工的全名和部门id是什么？

assistant: SELECT first_name ,  last_name ,  department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
Schema: CREATE TABLE employees (salary INTEGER, employee_id VARCHAR)
user: 找到所有挣的工资超过平均工资的员工的ID。

assistant: SELECT employee_id FROM employees WHERE salary  >  (SELECT AVG(salary) FROM employees)
Schema: CREATE TABLE employees (salary INTEGER, employee_id VARCHAR)
user: 挣的工资超过平均工资的所有员工的id是什么？

assistant: SELECT employee_id FROM employees WHERE salary  >  (SELECT AVG(salary) FROM employees)
Schema: CREATE TABLE employees (manager_id VARCHAR, first_name VARCHAR, salary VARCHAR, employee_id VARCHAR)
user: 显示向“王总”（姓）报告的所有员工的员工id和工资。

assistant: SELECT employee_id ,  salary FROM employees WHERE manager_id  =  (SELECT employee_id FROM employees WHERE first_name  =  '王总' )
Schema: CREATE TABLE employees (manager_id VARCHAR, first_name VARCHAR, salary VARCHAR, employee_id VARCHAR)
user: 向“王总”报告的员工的id是什么？他们的薪水是多少？

assistant: SELECT employee_id ,  salary FROM employees WHERE manager_id  =  (SELECT employee_id FROM employees WHERE first_name  =  '王总' )
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 查找实际分配了一个或多个员工的所有部门的名称。

assistant: SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 有至少一名员工的部门名称是什么？

assistant: SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id
Schema: CREATE TABLE employees (department_id VARCHAR, employee_id VARCHAR), CREATE TABLE departments (manager_id VARCHAR, department_id VARCHAR)
user: 获取管理部门的员工的详细信息。

assistant: SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T1.employee_id  =  T2.manager_id
Schema: CREATE TABLE employees (department_id VARCHAR, employee_id VARCHAR), CREATE TABLE departments (manager_id VARCHAR, department_id VARCHAR)
user: 关于管理人员的所有信息是什么？

assistant: SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T1.employee_id  =  T2.manager_id
Schema: CREATE TABLE departments (department_name VARCHAR)
user: 显示“市场”部门的所有信息。

assistant: SELECT * FROM  departments WHERE department_name  =  '市场'
Schema: CREATE TABLE job_history (employee_id VARCHAR)
user: 显示之前做过两份或更多工作的员工的id。

assistant: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Schema: CREATE TABLE job_history (employee_id VARCHAR)
user: 那些有过两个或更多工作的员工的ID是什么？

assistant: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
Schema: CREATE TABLE employees (manager_id VARCHAR, department_id VARCHAR, employee_id VARCHAR)
user: 任何管理4名或4名以上员工的经理所在的部门的唯一id是什么？

assistant: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Schema: CREATE TABLE employees (manager_id VARCHAR, department_id VARCHAR, employee_id VARCHAR)
user: 给出负责4个或更多员工的经理所在的部门的不同部门ID？

assistant: SELECT DISTINCT department_id FROM employees GROUP BY department_id ,  manager_id HAVING COUNT(employee_id)  >= 4
Schema: CREATE TABLE employees (salary INTEGER, job_id VARCHAR)
user: 找到平均工资在8000以上的职位的职位ID。

assistant: SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
Schema: CREATE TABLE employees (salary INTEGER, job_id VARCHAR)
user: 平均工资在8000以上的工作对应的工作ID是什么？

assistant: SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
Schema: CREATE TABLE employees (job_id VARCHAR, employee_id VARCHAR, department_id VARCHAR), CREATE TABLE jobs (job_id VARCHAR, job_title VARCHAR)
user: 显示部门80中所有职位的员工ID和职位名称。

assistant: SELECT T1.employee_id ,  T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id WHERE T1.department_id = 80
Schema: CREATE TABLE employees (job_id VARCHAR, employee_id VARCHAR, department_id VARCHAR), CREATE TABLE jobs (job_id VARCHAR, job_title VARCHAR)
user: 部门80的员工ID和职称是什么？

assistant: SELECT T1.employee_id ,  T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id  =  T2.job_id WHERE T1.department_id = 80
Schema: CREATE TABLE employees (job_id VARCHAR, first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: “财务”部门所有员工的名字和职位ID是什么？

assistant: SELECT T1.first_name ,  T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T2.department_name  =  '财务'
Schema: CREATE TABLE employees (job_id VARCHAR, first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR)
user: 给出“财务”部的所有员工的名字和职位ID。

assistant: SELECT T1.first_name ,  T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id WHERE T2.department_name  =  '财务'
Schema: CREATE TABLE employees (salary INTEGER)
user: 如果员工的工资在最低工资至2500的范围内，那么显示他们的所有信息。

assistant: SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
Schema: CREATE TABLE employees (salary INTEGER)
user: 对于工资高于最低限度而且低于2500的员工，他们的所有信息是什么？

assistant: SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
Schema: CREATE TABLE employees (manager_id INTEGER, department_id VARCHAR), CREATE TABLE departments (manager_id INTEGER, department_id VARCHAR)
user: 查找不在某些部门工作的员工的id，这些部门的经理的id在100和200范围内。

assistant: SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
Schema: CREATE TABLE employees (manager_id INTEGER, department_id VARCHAR), CREATE TABLE departments (manager_id INTEGER, department_id VARCHAR)
user: 对于不在部门经理ID在100-200之间的那些部门工作的员工，他们的id是什么？

assistant: SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
Schema: CREATE TABLE employees (last_name VARCHAR, department_id VARCHAR, first_name VARCHAR, hire_date VARCHAR)
user: 显示所有和“明明”在同一个部门工作的员工的姓名（名字和姓氏）以及聘用日期。

assistant: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  (SELECT department_id FROM employees WHERE first_name  =  "明明")
Schema: CREATE TABLE employees (last_name VARCHAR, department_id VARCHAR, first_name VARCHAR, hire_date VARCHAR)
user: 同一个姓克拉拉的员工的全名和聘用日期是什么？

assistant: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  (SELECT department_id FROM employees WHERE first_name  =  "明明")
Schema: CREATE TABLE employees (last_name VARCHAR, department_id VARCHAR, first_name VARCHAR, hire_date VARCHAR)
user: 显示与名字是“明明”的同事在同一个部门但不包括“明明”的其它雇员的全名（名字和姓氏）和雇用日期。

assistant: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  ( SELECT department_id FROM employees WHERE first_name  =  "明明") AND first_name != "明明"
Schema: CREATE TABLE employees (last_name VARCHAR, department_id VARCHAR, first_name VARCHAR, hire_date VARCHAR)
user: 与名字是“明明”的同事在同一个部门但不包括“明明”的其它雇员的全名和雇用日期是什么？

assistant: SELECT first_name ,  last_name ,  hire_date FROM employees WHERE department_id  =  ( SELECT department_id FROM employees WHERE first_name  =  "明明") AND first_name != "明明"
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, employee_id VARCHAR, department_id VARCHAR)
user: 显示与名字中包含汉字“T”的雇员在同一部门工作的员工的id和全名（名字和姓氏）。

assistant: SELECT employee_id ,  first_name ,  last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '洋' )
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, employee_id VARCHAR, department_id VARCHAR)
user: 与名字中包含汉字“洋”的雇员在同一部门工作的员工的id和全名是什么？

assistant: SELECT employee_id ,  first_name ,  last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '洋' )
Schema: CREATE TABLE employees (salary INTEGER, first_name VARCHAR, employee_id VARCHAR, department_id VARCHAR, last_name VARCHAR)
user: 显示与名字中包含汉字“江”的雇员在同一部门工作且工资高于平均工资的员工的id、全名（名字和姓氏）和工资。

assistant: SELECT employee_id ,  first_name ,  last_name ,  salary FROM employees WHERE salary  >  ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '江')
Schema: CREATE TABLE employees (salary INTEGER, first_name VARCHAR, employee_id VARCHAR, department_id VARCHAR, last_name VARCHAR)
user: 与名字中包含汉字“江”的雇员在同一部门工作且工资高于平均工资的员工的id、全名（名字和姓氏）和工资是多少？

assistant: SELECT employee_id ,  first_name ,  last_name ,  salary FROM employees WHERE salary  >  ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '江')
Schema: CREATE TABLE employees (salary INTEGER, job_id VARCHAR, employee_id VARCHAR)
user: 显示所有工资低于工作职称是“机械工人”的员工工资的所有员工的雇员id和工作ID。

assistant: SELECT employee_id ,  job_id FROM employees WHERE salary  <  ( SELECT min(salary) FROM employees WHERE job_id  =  '机械工人' )
Schema: CREATE TABLE employees (salary INTEGER, job_id VARCHAR, employee_id VARCHAR)
user: 所有工资低于工作职称是“机械工人”的员工工资的所有员工的雇员id和工作ID是什么？

assistant: SELECT employee_id ,  job_id FROM employees WHERE salary  <  ( SELECT min(salary) FROM employees WHERE job_id  =  '机械工人' )
Schema: CREATE TABLE employees (job_id VARCHAR, salary INTEGER, first_name VARCHAR, employee_id VARCHAR, last_name VARCHAR)
user: 显示所有工资金额高于“工程师”职称的员工工资的所有雇员的员工id、姓名（名字和姓氏）和职称。

assistant: SELECT employee_id ,  first_name ,  last_name ,  job_id FROM employees WHERE salary  >  ( SELECT max(salary) FROM employees WHERE job_id  =  '工程师' )
Schema: CREATE TABLE employees (job_id VARCHAR, salary INTEGER, first_name VARCHAR, employee_id VARCHAR, last_name VARCHAR)
user: 所有工资金额高于“工程师”职称的员工工资的雇员的员工ID、全名和工作ID是什么？

assistant: SELECT employee_id ,  first_name ,  last_name ,  job_id FROM employees WHERE salary  >  ( SELECT max(salary) FROM employees WHERE job_id  =  '工程师' )
Schema: CREATE TABLE employees (salary INTEGER, department_id VARCHAR)
user: 显示包含至少两个员工的部门ID和部门总工资。

assistant: SELECT department_id ,  SUM(salary) FROM employees GROUP BY department_id HAVING count(*)  >=  2
Schema: CREATE TABLE employees (salary INTEGER, department_id VARCHAR)
user: 包含至少两个员工的部门ID和部门总工资是多少？

assistant: SELECT department_id ,  SUM(salary) FROM employees GROUP BY department_id HAVING count(*)  >=  2
Schema: CREATE TABLE employees (employee_id VARCHAR), CREATE TABLE job_history (employee_id VARCHAR)
user: 显示过去没有工作过的员工的所有信息。

assistant: SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history)
Schema: CREATE TABLE employees (employee_id VARCHAR), CREATE TABLE job_history (employee_id VARCHAR)
user: 过去从未工作过的员工的所有信息是什么？

assistant: SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history)
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR, department_id VARCHAR)
user: 显示部门ID、全名（名字和姓氏）、每个部门中工资最高的员工的工资。

assistant: SELECT first_name ,   last_name ,   salary ,  department_id ,  MAX(salary) FROM employees GROUP BY department_id
Schema: CREATE TABLE employees (last_name VARCHAR, salary INTEGER, first_name VARCHAR, department_id VARCHAR)
user: 部门ID、全名和每个部门中工资最高的员工的工资是什么？

assistant: SELECT first_name ,   last_name ,   salary ,  department_id ,  MAX(salary) FROM employees GROUP BY department_id
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_name VARCHAR, department_id VARCHAR), CREATE TABLE locations (state_province VARCHAR, location_id VARCHAR, city VARCHAR)
user: 显示每个员工的名字和姓氏、部门、城市和省。

assistant: SELECT T1.first_name ,  T1.last_name ,  T2.department_name ,  T3.city ,  T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_name VARCHAR, department_id VARCHAR), CREATE TABLE locations (state_province VARCHAR, location_id VARCHAR, city VARCHAR)
user: 每个雇员的全名、部门、城市和所在省份是那些？

assistant: SELECT T1.first_name ,  T1.last_name ,  T2.department_name ,  T3.city ,  T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (location_id VARCHAR, city VARCHAR)
user: 显示那些包含汉字“文”的员工的名字，姓氏和所在的城市。

assistant: SELECT T1.first_name ,  T1.last_name ,  T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id WHERE T1.first_name LIKE '文'
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (location_id VARCHAR, city VARCHAR)
user: 名字中包含汉字“文”的员工的全名和所在的城市是什么？

assistant: SELECT T1.first_name ,  T1.last_name ,  T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id WHERE T1.first_name LIKE '文'
Schema: CREATE TABLE departments (location_id VARCHAR, department_name VARCHAR), CREATE TABLE locations (state_province VARCHAR, location_id VARCHAR, city VARCHAR)
user: 显示各部门的部门名称、城市和所在省份。

assistant: SELECT T1.department_name ,  T2.city ,  T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id  =  T1.location_id
Schema: CREATE TABLE departments (location_id VARCHAR, department_name VARCHAR), CREATE TABLE locations (state_province VARCHAR, location_id VARCHAR, city VARCHAR)
user: 每个部门的部门名称、城市和所在省份都有哪些？

assistant: SELECT T1.department_name ,  T2.city ,  T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id  =  T1.location_id
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, employee_id VARCHAR, department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (country_id VARCHAR, location_id VARCHAR), CREATE TABLE countries (country_name VARCHAR, country_id VARCHAR)
user: 显示员工的全名（姓名和姓氏），ID和当前工作所在国家的名称。

assistant: SELECT T1.first_name ,  T1.last_name , T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Schema: CREATE TABLE employees (last_name VARCHAR, first_name VARCHAR, employee_id VARCHAR, department_id VARCHAR), CREATE TABLE departments (location_id VARCHAR, department_id VARCHAR), CREATE TABLE locations (country_id VARCHAR, location_id VARCHAR), CREATE TABLE countries (country_name VARCHAR, country_id VARCHAR)
user: 每个雇员的全名、id和他们工作所在国家的名称是什么？

assistant: SELECT T1.first_name ,  T1.last_name , T1.employee_id ,  T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id JOIN locations AS T3 ON T2.location_id  =  T3.location_id JOIN countries AS T4 ON T3.country_id  =  T4.country_id
Schema: CREATE TABLE employees (department_id VARCHAR), CREATE TABLE departments (department_id VARCHAR)
user: 显示每个部门的部门名称和员工人数。

assistant: SELECT department_name ,  COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id  =  T2.department_id GROUP BY department_name