jtjt520j/cspider_for_chinese_llama2_1.3b huggingface dataset:
Schema: CREATE TABLE Locations (Address VARCHAR, Location_ID VARCHAR), CREATE TABLE Tourist_Attractions (Location_ID VARCHAR, Name VARCHAR, How_to_Get_There VARCHAR)
user: “公共汽车”能到达或地址在 “长江路292号” 的旅游景点叫什么名字？

assistant: SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID  =  T2.Location_ID WHERE T1.Address  =  "长江路292号" OR T2.How_to_Get_There  =  "公共汽车"
Schema: CREATE TABLE Locations (Address VARCHAR, Location_ID VARCHAR), CREATE TABLE Tourist_Attractions (Location_ID VARCHAR, Name VARCHAR, How_to_Get_There VARCHAR)
user: 找出旅游景点的名称，可以乘坐“公共汽车”或地址在 “长江路292号” 。

assistant: SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID  =  T2.Location_ID WHERE T1.Address  =  "长江路292号" OR T2.How_to_Get_There  =  "公共汽车"
Schema: CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR), CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR), CREATE TABLE VISITS (Tourist_ID VARCHAR, Tourist_Attraction_ID VARCHAR)
user: “维华”和 “慧兰” 参观的旅游景点名称是什么？

assistant: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "维华" INTERSECT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "慧兰"
Schema: CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR), CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR), CREATE TABLE VISITS (Tourist_ID VARCHAR, Tourist_Attraction_ID VARCHAR)
user: 游客“维华”和“慧兰”参观哪些景点？告诉我景点的名字。

assistant: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "维华" INTERSECT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "慧兰"
Schema: CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR), CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR), CREATE TABLE VISITS (Tourist_ID VARCHAR, Tourist_Attraction_ID VARCHAR)
user: “张颖”参观但 “李强” 没有参观的旅游景点叫什么名字？

assistant: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "李强" EXCEPT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "张颖"
Schema: CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR), CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR), CREATE TABLE VISITS (Tourist_ID VARCHAR, Tourist_Attraction_ID VARCHAR)
user: 找出叫“张颖”的游客但 “李强” 没去的旅游景点的名字。

assistant: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "李强" EXCEPT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID  =  T3.Tourist_Attraction_ID AND T2.Tourist_ID  =  T3.Tourist_ID WHERE T2.Tourist_Details  =  "张颖"
Schema: CREATE TABLE Visitors (Tourist_ID VARCHAR), CREATE TABLE Visits (Tourist_ID VARCHAR)
user: 有多少游客没有去参观？

assistant: SELECT count(*) FROM Visitors WHERE Tourist_ID NOT IN ( SELECT Tourist_ID FROM Visits )
Schema: CREATE TABLE Visitors (Tourist_ID VARCHAR), CREATE TABLE Visits (Tourist_ID VARCHAR)
user: 统计没有参观任何地方的游客人数。

assistant: SELECT count(*) FROM Visitors WHERE Tourist_ID NOT IN ( SELECT Tourist_ID FROM Visits )
Schema: CREATE TABLE Video_games (Id VARCHAR)
user: 有多少视频游戏存在？

assistant: SELECT count(*) FROM Video_games
Schema: CREATE TABLE Video_games (Id VARCHAR)
user: 你有多少个电子游戏？

assistant: SELECT count(*) FROM Video_games
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 有多少种电子游戏类型？

assistant: SELECT count(DISTINCT gtype) FROM Video_games
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 不同游戏类型的计数是多少？

assistant: SELECT count(DISTINCT gtype) FROM Video_games
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 显示所有视频游戏类型。

assistant: SELECT DISTINCT gtype FROM Video_games
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 电子游戏有什么不同的类型？

assistant: SELECT DISTINCT gtype FROM Video_games
Schema: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
user: 按照他们名字的顺序显示所有的电子游戏和他们的类型。

assistant: SELECT gname ,  gtype FROM Video_games ORDER BY gname
Schema: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
user: 所有的电子游戏的名称和字母顺序的类型是什么？

assistant: SELECT gname ,  gtype FROM Video_games ORDER BY gname
Schema: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
user: 显示所有“收集卡片”类型的视频游戏。

assistant: SELECT gname FROM Video_games WHERE gtype  =  "收集卡片"
Schema: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
user: 所有“收集卡片”类型的电子游戏的名字是什么？

assistant: SELECT gname FROM Video_games WHERE gtype  =  "收集卡片"
Schema: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
user: “使命召唤”的类型是什么？

assistant: SELECT gtype FROM Video_games WHERE gname  =  "使命召唤"
Schema: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
user: “使命召唤”是什么类型的游戏？

assistant: SELECT gtype FROM Video_games WHERE gname  =  "使命召唤"
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 有多少视频游戏是“大型多人在线游戏”？

assistant: SELECT count(*) FROM Video_games WHERE gtype  =  "大型多人在线游戏"
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 计算“大型多人在线游戏”类型的游戏数量。

assistant: SELECT count(*) FROM Video_games WHERE gtype  =  "大型多人在线游戏"
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 显示所有视频游戏类型和每种类型的视频游戏的数量。

assistant: SELECT gtype ,  count(*) FROM Video_games GROUP BY gtype
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 有什么类型的电子游戏和每种类型有多少？

assistant: SELECT gtype ,  count(*) FROM Video_games GROUP BY gtype
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 哪种游戏类型有最多的游戏？

assistant: SELECT gtype FROM Video_games GROUP BY gtype ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 什么类型的游戏最多？

assistant: SELECT gtype FROM Video_games GROUP BY gtype ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 哪种游戏类型的游戏数量最少？

assistant: SELECT gtype FROM Video_games GROUP BY gtype ORDER BY count(*) LIMIT 1
Schema: CREATE TABLE Video_games (gtype VARCHAR)
user: 什么类型的游戏最少？

assistant: SELECT gtype FROM Video_games GROUP BY gtype ORDER BY count(*) LIMIT 1
Schema: CREATE TABLE Student (city_code VARCHAR, StuID VARCHAR)
user: 显示所有住在“慧园”的学生的 ID 。

assistant: SELECT StuID FROM Student WHERE city_code  =  "慧园"
Schema: CREATE TABLE Student (city_code VARCHAR, StuID VARCHAR)
user: 生活在“慧园”中的所有学生的ID是什么？

assistant: SELECT StuID FROM Student WHERE city_code  =  "慧园"
Schema: CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
user: 显示所有导师是1121号的学生的ID 。

assistant: SELECT StuID FROM Student WHERE Advisor  =  1121
Schema: CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
user: 有1121号导师的学生的ID是什么？

assistant: SELECT StuID FROM Student WHERE Advisor  =  1121
Schema: CREATE TABLE Student (Major VARCHAR, Fname VARCHAR)
user: 显示主修课程编号是600的学生的名字。

assistant: SELECT Fname FROM Student WHERE Major  =  600
Schema: CREATE TABLE Student (Major VARCHAR, Fname VARCHAR)
user: 所有主修课程编号是600课程的学生的名字是什么？

assistant: SELECT Fname FROM Student WHERE Major  =  600
Schema: CREATE TABLE Student (age INTEGER, major VARCHAR)
user: 显示不同专业的平均年龄、最小年龄和最大年龄。

assistant: SELECT major ,  avg(age) ,  min(age) ,  max(age) FROM Student GROUP BY major
Schema: CREATE TABLE Student (age INTEGER, major VARCHAR)
user: 每个专业的平均年龄、最小年龄和最大年龄是多少？

assistant: SELECT major ,  avg(age) ,  min(age) ,  max(age) FROM Student GROUP BY major
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 显示所有至少有两个学生的导师。

assistant: SELECT advisor FROM Student GROUP BY advisor HAVING count(*)  >=  2
Schema: CREATE TABLE Student (advisor VARCHAR)
user: 什么是导师？

assistant: SELECT advisor FROM Student GROUP BY advisor HAVING count(*)  >=  2
Schema: CREATE TABLE Sportsinfo (sportname VARCHAR)
user: 我们有多少运动？

assistant: SELECT count(DISTINCT sportname) FROM Sportsinfo
Schema: CREATE TABLE Sportsinfo (sportname VARCHAR)
user: 我们提供多少种不同类型的运动？

assistant: SELECT count(DISTINCT sportname) FROM Sportsinfo
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR)
user: 有多少学生参加体育活动？

assistant: SELECT count(DISTINCT StuID) FROM Sportsinfo
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR)
user: 有多少不同的学生参与体育运动？

assistant: SELECT count(DISTINCT StuID) FROM Sportsinfo
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, StuID VARCHAR)
user: 列出所有获得奖学金的学生的ID 。

assistant: SELECT StuID FROM Sportsinfo WHERE onscholarship  =  "Y"
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, StuID VARCHAR)
user: 所有获得奖学金的运动生的ID是什么？

assistant: SELECT StuID FROM Sportsinfo WHERE onscholarship  =  "Y"
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, StuID VARCHAR), CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR)
user: 显示所有获得奖学金的学生的姓氏。

assistant: SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T1.onscholarship  =  "Y"
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, StuID VARCHAR), CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR)
user: 所有奖学金学生的姓氏是什么？

assistant: SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T1.onscholarship  =  "Y"
Schema: CREATE TABLE Sportsinfo (gamesplayed INTEGER)
user: 所有学生玩多少种游戏？

assistant: SELECT sum(gamesplayed) FROM Sportsinfo
Schema: CREATE TABLE Sportsinfo (gamesplayed INTEGER)
user: 游戏的总数是多少？

assistant: SELECT sum(gamesplayed) FROM Sportsinfo
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, gamesplayed INTEGER, sportname VARCHAR)
user: 所有有奖学金学生的“足球”比赛共有多少场比赛？

assistant: SELECT sum(gamesplayed) FROM Sportsinfo WHERE sportname  =  "足球" AND onscholarship  =  "Y"
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, gamesplayed INTEGER, sportname VARCHAR)
user: 有奖学金学生的所有“足球”比赛的总数是多少？

assistant: SELECT sum(gamesplayed) FROM Sportsinfo WHERE sportname  =  "足球" AND onscholarship  =  "Y"
Schema: CREATE TABLE Sportsinfo (sportname VARCHAR)
user: 显示所有体育名称和学生人数。

assistant: SELECT sportname ,  count(*) FROM Sportsinfo GROUP BY sportname
Schema: CREATE TABLE Sportsinfo (sportname VARCHAR)
user: 每项运动有多少学生玩？

assistant: SELECT sportname ,  count(*) FROM Sportsinfo GROUP BY sportname
Schema: CREATE TABLE Sportsinfo (gamesplayed INTEGER, StuID VARCHAR)
user: 显示所有学生ID与运动的数量和游戏的总数

assistant: SELECT StuID ,  count(*) ,  sum(gamesplayed) FROM Sportsinfo GROUP BY StuID
Schema: CREATE TABLE Sportsinfo (gamesplayed INTEGER, StuID VARCHAR)
user: 所有学生的ID和他们参加了多少运动和游戏？

assistant: SELECT StuID ,  count(*) ,  sum(gamesplayed) FROM Sportsinfo GROUP BY StuID
Schema: CREATE TABLE Sportsinfo (hoursperweek INTEGER, StuID VARCHAR)
user: 显示所有参加运动项目每周超过10小时的学生的ID。

assistant: SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING sum(hoursperweek)  >  10
Schema: CREATE TABLE Sportsinfo (hoursperweek INTEGER, StuID VARCHAR)
user: 每周参加所有运动项目上超过10个小时的学生的ID是什么？

assistant: SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING sum(hoursperweek)  >  10
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR, Fname VARCHAR)
user: 运动次数最多的学生的名字和姓氏是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID GROUP BY T1.StuID ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR, Fname VARCHAR)
user: 运动最多次数的学生的名字和姓氏是什么？

assistant: SELECT T2.Fname ,  T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID GROUP BY T1.StuID ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, sportname VARCHAR)
user: 哪项运动获得奖学金的学生参加最多？

assistant: SELECT sportname FROM Sportsinfo WHERE onscholarship  =  "Y" GROUP BY sportname ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Sportsinfo (onscholarship VARCHAR, sportname VARCHAR)
user: 有奖学金的学生最多参加的运动是什么？

assistant: SELECT sportname FROM Sportsinfo WHERE onscholarship  =  "Y" GROUP BY sportname ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR)
user: 显示没有任何运动的学生ID 。

assistant: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
Schema: CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR)
user: 不参加体育运动的学生的ID是什么？

assistant: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
Schema: CREATE TABLE Student (onscholarship VARCHAR, major VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (onscholarship VARCHAR, major VARCHAR, StuID VARCHAR)
user: 显示有奖学金且主修编号是600课程的学生ID 。

assistant: SELECT StuID FROM Student WHERE major  =  600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship  =  "Y"
Schema: CREATE TABLE Student (onscholarship VARCHAR, major VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (onscholarship VARCHAR, major VARCHAR, StuID VARCHAR)
user: 主修编号是600课程且有奖学金的学生的ID是什么？

assistant: SELECT StuID FROM Student WHERE major  =  600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship  =  "Y"
Schema: CREATE TABLE Student (sex VARCHAR, sportname VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (sex VARCHAR, sportname VARCHAR, StuID VARCHAR)
user: 显示是女性和踢“足球”的学生ID。

assistant: SELECT StuID FROM Student WHERE sex  =  "F" INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname  =  "足球"
Schema: CREATE TABLE Student (sex VARCHAR, sportname VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (sex VARCHAR, sportname VARCHAR, StuID VARCHAR)
user: 所有女生踢“足球”的ID是什么？

assistant: SELECT StuID FROM Student WHERE sex  =  "F" INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname  =  "足球"
Schema: CREATE TABLE Student (sex VARCHAR, sportname VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (sex VARCHAR, sportname VARCHAR, StuID VARCHAR)
user: 展示所有不踢“足球”的男学生ID 。

assistant: SELECT StuID FROM Student WHERE sex  =  "M" EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname  =  "足球"
Schema: CREATE TABLE Student (sex VARCHAR, sportname VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (sex VARCHAR, sportname VARCHAR, StuID VARCHAR)
user: 不踢“足球”的所有男生的ID是什么？

assistant: SELECT StuID FROM Student WHERE sex  =  "M" EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname  =  "足球"
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, StuID VARCHAR)
user: 显示每周的总小时数和学生“韩”“江城”玩游戏的次数。

assistant: SELECT sum(hoursperweek) ,  sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.Fname  =  "江城" AND T2.Lname  =  "韩"
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, StuID VARCHAR)
user: “韩”“江城”每次工作的总小时数和玩游戏的次数是多少？

assistant: SELECT sum(hoursperweek) ,  sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.Fname  =  "江城" AND T2.Lname  =  "韩"
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (age INTEGER, StuID VARCHAR)
user: 显示每周的总小时数和20岁以下学生玩游戏的数目。

assistant: SELECT sum(hoursperweek) ,  sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.age  <  20
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (age INTEGER, StuID VARCHAR)
user: 每周的总小时数和20岁以下的学生游戏次数是多少？

assistant: SELECT sum(hoursperweek) ,  sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.age  <  20
Schema: CREATE TABLE Plays_games (StuID VARCHAR)
user: 有多少学生玩电子游戏？

assistant: SELECT count(DISTINCT StuID) FROM Plays_games
Schema: CREATE TABLE Plays_games (StuID VARCHAR)
user: 有多少不同的学生玩游戏？

assistant: SELECT count(DISTINCT StuID) FROM Plays_games
Schema: CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
user: 显示不玩电子游戏的学生的ID。

assistant: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
Schema: CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
user: 所有不是电子游戏玩家的学生的ID是什么？

assistant: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
user: 显示玩电子游戏和运动的学生ID。

assistant: SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
Schema: CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
user: 玩电子游戏和体育运动的学生的ID是什么？

assistant: SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
Schema: CREATE TABLE Plays_games (hours_played INTEGER, gameid VARCHAR)
user: 显示所有游戏的ID和玩的小时数。

assistant: SELECT gameid ,  sum(hours_played) FROM Plays_games GROUP BY gameid
Schema: CREATE TABLE Plays_games (hours_played INTEGER, gameid VARCHAR)
user: 每个游戏的ID和每个游戏玩的总小时数？

assistant: SELECT gameid ,  sum(hours_played) FROM Plays_games GROUP BY gameid
Schema: CREATE TABLE Plays_games (hours_played INTEGER, Stuid VARCHAR)
user: 显示所有学生ID和玩的小时数。

assistant: SELECT Stuid ,  sum(hours_played) FROM Plays_games GROUP BY Stuid
Schema: CREATE TABLE Plays_games (hours_played INTEGER, Stuid VARCHAR)
user: 所有学生的ID和玩的小时数是多少？

assistant: SELECT Stuid ,  sum(hours_played) FROM Plays_games GROUP BY Stuid
Schema: CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
user: 显示玩最多小时数的游戏名称。

assistant: SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid  =  T2.gameid GROUP BY T1.gameid ORDER BY sum(hours_played) DESC LIMIT 1
Schema: CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
user: 玩的最多的游戏名字是什么？

assistant: SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid  =  T2.gameid GROUP BY T1.gameid ORDER BY sum(hours_played) DESC LIMIT 1
Schema: CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
user: 显示所有至少玩1000小时的游戏名称。

assistant: SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid  =  T2.gameid GROUP BY T1.gameid HAVING sum(hours_played)  >=  1000
Schema: CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
user: 已经玩了至少玩1000个小时的所有游戏的名字是什么？

assistant: SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid  =  T2.gameid GROUP BY T1.gameid HAVING sum(hours_played)  >=  1000
Schema: CREATE TABLE Plays_games (Stuid VARCHAR, gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR), CREATE TABLE Student (Lname VARCHAR, Stuid VARCHAR, Fname VARCHAR)
user: 显示 “张”“晴” 所玩的所有游戏名称

assistant: SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid  =  T2.gameid JOIN Student AS T3 ON T3.Stuid  =  T1.Stuid WHERE T3.Lname  =  "张" AND T3.Fname  =  "晴"
Schema: CREATE TABLE Plays_games (Stuid VARCHAR, gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR), CREATE TABLE Student (Lname VARCHAR, Stuid VARCHAR, Fname VARCHAR)
user: “张”“晴” 玩的所有游戏的名字是什么？

assistant: SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid  =  T2.gameid JOIN Student AS T3 ON T3.Stuid  =  T1.Stuid WHERE T3.Lname  =  "张" AND T3.Fname  =  "晴"
Schema: CREATE TABLE SportsInfo (SportName VARCHAR, StuID VARCHAR), CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR)
user: 找出踢“足球”或“曲棍球”的学生的名字和姓氏。

assistant: SELECT T2.lname ,  T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T1.SportName  =  "足球" OR T1.SportName  =  "曲棍球"
Schema: CREATE TABLE SportsInfo (SportName VARCHAR, StuID VARCHAR), CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR)
user: 所有踢“足球”或“曲棍球”的学生的名字和姓氏是什么？

assistant: SELECT T2.lname ,  T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T1.SportName  =  "足球" OR T1.SportName  =  "曲棍球"
Schema: CREATE TABLE Student (fname VARCHAR, age VARCHAR, SportName VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (fname VARCHAR, age VARCHAR, SportName VARCHAR, StuID VARCHAR)
user: 找出同时踢“足球”和“曲棍球”的学生的名字和年龄。

assistant: SELECT fname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName  =  "足球" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName  =  "曲棍球")
Schema: CREATE TABLE Student (fname VARCHAR, age VARCHAR, SportName VARCHAR, StuID VARCHAR), CREATE TABLE Sportsinfo (fname VARCHAR, age VARCHAR, SportName VARCHAR, StuID VARCHAR)
user: 所有同时踢“足球”和“曲棍球”的学生的名字和年龄是多少？

assistant: SELECT fname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName  =  "足球" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName  =  "曲棍球")
Schema: CREATE TABLE Student (sex VARCHAR, lname VARCHAR, StuID VARCHAR), CREATE TABLE Plays_games (GameID VARCHAR, StuID VARCHAR), CREATE TABLE Video_games (GameID VARCHAR, Gname VARCHAR)
user: 找出同时玩“使命召唤”和“绝地求生”游戏的学生的姓氏和性别。

assistant: SELECT lname ,  sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID  =  T2.GameID WHERE T2.Gname  =  "使命召唤" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID  =  T2.GameID WHERE T2.Gname  =  "绝地求生")
Schema: CREATE TABLE Student (sex VARCHAR, lname VARCHAR, StuID VARCHAR), CREATE TABLE Plays_games (GameID VARCHAR, StuID VARCHAR), CREATE TABLE Video_games (GameID VARCHAR, Gname VARCHAR)
user: 所有同时演奏“使命召唤”和“绝地求生”的学生的姓氏和性别是什么？

assistant: SELECT lname ,  sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID  =  T2.GameID WHERE T2.Gname  =  "使命召唤" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID  =  T2.GameID WHERE T2.Gname  =  "绝地求生")
Schema: CREATE TABLE customers (customer_name VARCHAR)
user: 查找所有客户的姓名。

assistant: SELECT customer_name FROM customers
Schema: CREATE TABLE customers (customer_name VARCHAR)
user: 所有顾客的名字是什么？

assistant: SELECT customer_name FROM customers
Schema: CREATE TABLE customers (Id VARCHAR)
user: 返回不同客户的总数。

assistant: SELECT count(*) FROM customers
Schema: CREATE TABLE order_items (order_quantity INTEGER)
user: 每一个订单所订购的物品的平均数量是多少？

assistant: SELECT avg(order_quantity) FROM order_items
Schema: CREATE TABLE order_items (order_quantity INTEGER)
user: 找出每个订单的平均订单数量。

assistant: SELECT avg(order_quantity) FROM order_items
Schema: CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR)
user: 使用支付方式为“现金”的客户姓名是什么？

assistant: SELECT customer_name FROM customers WHERE payment_method  =  "现金"
Schema: CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR)
user: 哪些客户使用“现金”支付方式？返回客户姓名。

assistant: SELECT customer_name FROM customers WHERE payment_method  =  "现金"
Schema: CREATE TABLE customers (customer_id INTEGER, date_became_customer VARCHAR)
user: 找出ID在10到20之间的客户的成为客户的日期。

assistant: SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
Schema: CREATE TABLE customers (customer_id INTEGER, date_became_customer VARCHAR)
user: ID介于10和20之间的客户成为客户的日期是什么时候？

assistant: SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
Schema: CREATE TABLE customers (payment_method VARCHAR)
user: 客户使用最多种是什么付款方式？

assistant: SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE customers (payment_method VARCHAR)
user: 找出最常用的支付方式。

assistant: SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1
Schema: CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR)
user: 使用最流行的支付方式的客户姓名是什么？

assistant: SELECT customer_name FROM customers WHERE payment_method  =  (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1)
Schema: CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR)
user: 查找使用最常用支付方式的客户姓名。

assistant: SELECT customer_name FROM customers WHERE payment_method  =  (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1)
Schema: CREATE TABLE customers (payment_method VARCHAR)
user: 所有的付款方式是什么？

assistant: SELECT DISTINCT payment_method FROM customers