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|  01 52.27 56                        1

2x        00 44                22*2=44        2

24x          07 29             243*3=729       3

246x            98 56          2464*4=9856      4

00 00          Algorithm terminates: answer is 12.34

Although demonstrated here for base 10 numbers, the procedure works for

any base, including base 2. In the description above, 20 méans double

the number base used, in the case of binary this would réally be

100. The algorithm is in fact much éasier to perform in base 2, as in every step only the two digits 0 and 1 have to be tested.  See Shifting nth-root algorithm.