This task is to find the number of 'For' loops present in the given cpp program.
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Question: int main()
{
	int f(int k,int m);
	int n;
	scanf("%d",&n);
	int i;
	for(i=1;i<=n;i++)
	{
		int k;
		scanf("%d",&k);
		printf("%d\n",f(k,2));
	}

	return 0;
}
int  f(int k,int m)
{   
	int i;
	int j=0;
	if(k<=m)
	{
		if(k==m){

		j=1;
		return j;
		}
		else 
		{
			j=0;
			return j;
		}
	}
	else
	{
	for(i=m;i<=k;i++)
	{
		if(k%i==0&&k/i!=1)
			j=j+f(k/i,i);
		if(k%i==0&&k/i==1)
			j=j+1;
	}
	return j;
	}

}

Answer: 2


Question: int num=0;
void yinshu(int x,int y)
{
	if (x==y) num++;
	else if ((x%y==0)&&(x>y)) {yinshu(x/y,y);yinshu(x,y+1);}
	else if (x>y) yinshu(x,y+1);
}
int main()
{
	int n,x;
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>x;
	yinshu(x,2);
	cout<<num<<endl;
	num=0;
	}
}


Answer: 1


Question: int sum;
void zhongshu(int qian,int a);
int main()
{
    int n,i,j,a[100];
    cin>>n;
    for(i=0;i<n;i++)
    cin>>a[i];
    for(i=0;i<n;i++)
    {  sum=0;
       zhongshu(2,a[i]);
       cout<<sum<<endl;
       }
    return 0;
}
void zhongshu(int qian,int a)
{
   int i,j,c;
   if(a==1)
   {
   sum=sum+1;
   return;
  }
   for(i=qian;i<=a;i++)
   {
      if(a%i==0)
         zhongshu(i,a/i);
   }
}

Answer:
3