This task is to find the number of 'For' loops present in the given cpp program.

Ex Input:
int t, a, flag, a1;
/*bool prime(int k)
{
	int j, sqrt_k;
	if (k == 2)
		return 1;
	else
	{
		sqrt_k = sqrt((double)k);
		for (j = 2; j <= sqrt_k; j++)
		{
			if (k % (int)j == 0)
				break;
		}
		if (j == sqrt_k + 1)
			return 1;
		else
			return 0;
	}
}
/*
void find(int m)
{
	int i;
	if (prime(m))
	{
		flag = 1;
		t++;
	//	cout << t << endl;
		return;
	}
	for (i = 2; i <= sqrt((double) m); i++)
	{
		if ((m % i == 0) && (a1 <= i))
		{
		//	cout << a1 << 2<< endl;
			//cout << i <<  " " << 1 <<endl;
			a1 = i;
			//if (!prime(m / i))
				t++;
		//	cout << t << endl;
			find(m / i);
		}
	}
	return;
}*/
void find(int m, int min)
{
	int i;
	//int a[];
	for (i = 2; i <= sqrt((double)m); i++)
	{
		if (m % i == 0)
		{
			if (i >= min)
			//if (a1 >= i)
			{
				t++;
		//	if (!/*((m / i > i) && */(prime(m / i)))
			//	cout << t << " ";
			//	cout <<i<<" " << m / i << " " << t <<endl;
			//	t++;
			//	cout << " " << a1 <<endl;
				//cout << t<<endl;
			//	a1 = i;
				min = i;
				//cout << min << endl;
				find(m / i, min);
				
			}
			
		}
	}
	/*if (i == (int)sqrt((double)m) - 1)
		return;*/
	return;
}
int main()
{
	int n, ii;
	cin >> n;
	for (ii = 1; ii <= n; ii++)
	{
		t = 0;
		flag = 0;
		cin >> a;
	//	if (prime(a)) t--;
		a1 = a;
		find(a, 2);
		cout << t + 1<< endl;
	}

	return 0;
}

Ex Output:
4


Ex Input:
int main()
{
	int ys(int s,int p);
	int n,m,i,t;
	scanf("%d",&n);
    for(i=1;i<=n;i++)
	{
		scanf("%d",&m);
        t=ys(m,2);
		printf("%d\n",t);
	}
    return 0;
}
int ys(int s,int p)
{
	int j,a=1,b;
	for(j=p;j*j<=s;j++)
	{
        if(s%j==0)
		{
			b=s/j;
			a=a+ys(b,j);
		}
	}
	return(a);
}

Ex Output:
2


Ex Input:
int n,i;//????  n ???????
int f(int a,int min){      //??????f  ?????a n
if(a < min){     //?????a ??n
return 0;     //????0?   ???????????
}
int result = 1;       //???????  ???1
for(int i = min;i<a;i++){   //for?? ? ??????a
if(a % i == 0){   //?a???i???
result += f(a/i,i);  //???? ??result
}
}
return result; //??????
}
      int main(){  //?????
    	  cin>>n;//??????
    	  int a[n];
    	  for(i=0;i<n;i++){   //????
    		  cin>>a[i];
    	  }
    	  for(i=0;i<n;i++){
    	  cout<<f(a[i],2)<<endl;  //??????????  ????
    	  }
    	  return 0;
      }

Ex Output:

3