TASK DEFINITION: This task is to find the number of 'For' loops present in the given cpp program.
PROBLEM: int a[40000]={0};
void fun(int n,int j,int k){
     int i;
     for(i=j;i<=sqrt(n);i++){
                             if(n%i==0){
                                        j=i;
                                        a[k]++;
                                        fun(n/i,j,k);
                                        }
                             }
                             
     }
      
int main()
{
  int n;
  int m[40000]={0};
  int i;
  scanf("%d",&n);
  for(i=1;i<=n;i++){ scanf("%d",&m[i]);}  
  for(i=1;i<=n;i++){fun(m[i],2,i);}
  for(i=1;i<=n;i++){ printf("%d\n",a[i]+1);} 
 
	
  return 0;
}


SOLUTION: 4

PROBLEM: int f(int a,int min){
	if(a<min)
		return 0;
	int sum=1;
	for(int i=min;i<a;i++){
		if(a%i==0)
			sum+=f(a/i,i);
	}
	return sum;
}
int main(){
	int n;
	int a[100];
	scanf("%d",&n);
	for(int i=0;i<n;i++){
		scanf("%d",&a[i]);
		a[i]=f(a[i],2);
	}
	for(int i=0;i<n;i++){
		printf("%d\n",a[i]);
	}
	return 0;
}


SOLUTION: 3

PROBLEM: int main()
{
int digui(int p,int q); 
int n,i,j;
scanf("%d",&n);
for(i=0;i<n;i++)
{
int a,sum=1;
scanf("%d",&a);
for(j=2;j<a;j++)
{if(j*j>a)
break;
else if(a%j==0)
sum=sum+digui(j,a/j);
}
printf("%d\n",sum);
}
}
int digui(int p,int q)
{
int z=1,d;
if(p==q)
z=1;
else if(p>q)
z=0;
else
for(d=p;d<q;d++)
{if(d*d>q)
break;
else if(q%d==0)
z=z+digui(d,q/d);
}
return(z);
}

SOLUTION:
3