This task is to find the number of 'For' loops present in the given cpp program.
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Question: int f(int a,int b)
{
	if(a==b)return 1;
	if(b>a)return 0;
	if(a%b!=0)return f(a,b+1);
	if(a%b==0)return f(a,b+1)+f(a/b,b);
}
int main()
{
	int n=0,i=0,x,y;
	cin>>n;
	for(i=0;i<n;i++)
	{
		cin>>x;
		y=2;
		cout<<f(x,y)<<endl;
	}
	return 0;
}

Answer: 1


Question: 
void factor(int a, int k);
int sum = 0;
int main()
{
	int n, a, i = 0;
	cin >> n;
	for (i = 1; i <= n; i++)
	{
		cin >> a;
		factor(a, 2);
		cout << sum + 1 << endl;
		sum = 0;
	}
	return 0;
}

void factor(int a, int k)
{
	int b, j;
	b = (int)sqrt((double)a);
	for (j = k; j <= b; j++)
	{
		if (a % j == 0)
		{
			sum++;
			factor(a / j, j);
		}
	}
	j = k;
}





Answer: 2


Question: int main()
{
    int n,i,fenjie(int x,int y),*a,re=0,j;//x?????????y???????????
    scanf("%d",&n);
    a=(int*)malloc(n*sizeof(int));
    for(i=0;i<n;i++)
    {
                    scanf("%d",&a[i]);
                    
    }
    for(i=0;i<n;i++)
    {
                   printf("%d\n",fenjie(a[i],2)+1);
    }
    return 0;
}

fenjie(int x,int y)
{
           int i,flag=0,re=0,flag2=0,k=0;
           if(x<y) return 0;
           else if(x==y) return 0;
           else
           {
                for(i=y;i<x;i++)
                {
                                 if(x%i==0) flag2+=1;
                }
                if(flag2==0) return 0;    
                else
           {
                   for(i=y;i<=x;i++)
                   {
                                    if(x%i==0) 
                                    {
                                               re+=fenjie(x/i,i);
                                               if(x/i>=i) k+=1;
                                    }
                   }
                   re+=k;
                   return(re);
           } 
           }
}

Answer:
4