In this task you are expected to fix an SQL query based on feedback. You will be given an SQL statement and an English description with what is wrong about that SQL statement. You must correct the SQL statement based off of the feedback. An SQL query works by selecting data from a table where certain conditions apply. A table contains columns where every row in that table must have a value for each column. Every table has a primary key that uniquely identifies each row, usually an id. To choose which columns are returned you specify that after the "SELECT" statement. Next, you use a "FROM" statement to specify what tables you want to select the data from. When you specify a table you can rename it with the "AS" statement. You can reference that table by whatever name follows the "AS" statement. If you want to select data from multiple tables you need to use the "JOIN" statement. This will join the tables together by pairing a row in one table with every row in the other table (Cartesian Product). To limit the number of rows returned you should use the "ON" statement. This will only return rows where the condition specified after the statement is true, this is usually an equals operator with primary keys. You can also use the "WHERE" statement to specify that only rows with column values statisfying a certain condition, should be returned. The "GROUP BY" statement will group rows together that have equal column values for whatever columns follows the statement. The "HAVING" statement will return groups that statisfy whatever condition follows the statement. Any column(s) being returned from grouped rows must either be an aggregate function, (AVG, MAX, COUNT, SUM, ...) of a column, or the column(s) that the data was grouped by. To sort the returned data you can use the "ORDER BY" command which will order the data by whatever aggregate function or column follows the statement. The "DESC" statement will sort in descending order and the "ASC" statement will sort in ascending order. Finally, you can use the "LIMIT" statement to return a certain number of rows. When "*" is used in an SQL statement every column is returned. For example, SELECT * FROM table WHERE attribute = 1, will select every column from rows with the attribute column equal to 1. 

SQL: SELECT Avg ( T2.access_count ) FROM Functional_Areas AS T1 JOIN Documents AS T2 JOIN Document_Functional_Areas AS T3 ON T1.functional_area_code = T3.functional_area_code AND T3.document_code = T2.document_code WHERE T1.parent_functional_area_code = "Acknowledgement"
Feedback: Supersede functional area description with parent functional area code in step 2.
SELECT avg(t1.access_count) FROM documents AS t1 JOIN document_functional_areas AS t2 ON t1.document_code  =  t2.document_code JOIN functional_areas AS t3 ON t2.functional_area_code  =  t3.functional_area_code WHERE t3.functional_area_description  =  "Acknowledgement"

SQL: SELECT T2.Name , T2.Location FROM race AS T1 JOIN track AS T2 ON T1.Track_ID = T2.Track_ID WHERE T1.Class = 1
Feedback: Replace class with race id .
SELECT T2.name ,  T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id  =  T2.track_id GROUP BY T1.track_id HAVING count(*)  =  1

SQL: SELECT T1.Name , T1.Height_feet FROM building AS T1 JOIN Institution AS T2 ON T1.building_id = T2.building_id WHERE T2.Founded > 1880 GROUP BY T2.Institution HAVING Count ( * ) > = 2
Feedback: Remove "and greater than" and also add founded year is greater than 1880.

SELECT T1.name ,  T1.height_feet FROM building AS T1 JOIN institution AS T2 ON T1.building_id  =  T2.building_id WHERE T2.founded  >  1880 GROUP BY T1.building_id HAVING count(*)  >=  2