In this task you are expected to fix an SQL query based on feedback. You will be given an SQL statement and an English description with what is wrong about that SQL statement. You must correct the SQL statement based off of the feedback. An SQL query works by selecting data from a table where certain conditions apply. A table contains columns where every row in that table must have a value for each column. Every table has a primary key that uniquely identifies each row, usually an id. To choose which columns are returned you specify that after the "SELECT" statement. Next, you use a "FROM" statement to specify what tables you want to select the data from. When you specify a table you can rename it with the "AS" statement. You can reference that table by whatever name follows the "AS" statement. If you want to select data from multiple tables you need to use the "JOIN" statement. This will join the tables together by pairing a row in one table with every row in the other table (Cartesian Product). To limit the number of rows returned you should use the "ON" statement. This will only return rows where the condition specified after the statement is true, this is usually an equals operator with primary keys. You can also use the "WHERE" statement to specify that only rows with column values statisfying a certain condition, should be returned. The "GROUP BY" statement will group rows together that have equal column values for whatever columns follows the statement. The "HAVING" statement will return groups that statisfy whatever condition follows the statement. Any column(s) being returned from grouped rows must either be an aggregate function, (AVG, MAX, COUNT, SUM, ...) of a column, or the column(s) that the data was grouped by. To sort the returned data you can use the "ORDER BY" command which will order the data by whatever aggregate function or column follows the statement. The "DESC" statement will sort in descending order and the "ASC" statement will sort in ascending order. Finally, you can use the "LIMIT" statement to return a certain number of rows. When "*" is used in an SQL statement every column is returned. For example, SELECT * FROM table WHERE attribute = 1, will select every column from rows with the attribute column equal to 1. 

Example Input: SQL: SELECT * FROM Prescribes AS T1 WHERE T1.Physician = "John Wen" EXCEPT SELECT T3.Name FROM Procedures AS T2 JOIN Nurse AS T3 JOIN Undergoes AS T4 ON T2.Code = T4.Procedures AND T4.AssistingNurse = T3.EmployeeID WHERE T2.Cost > 1000
Feedback: Make sure to find block code name for which John Wen is not Trained in .
Example Output: SELECT name FROM procedures WHERE cost  >  1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid  =  T2.physician JOIN procedures AS T3 ON T3.code  =  T2.treatment WHERE T1.name  =  "John Wen"

Example Input: SQL: SELECT name FROM Highschooler INTERSECT SELECT name FROM Highschooler
Feedback: In step 1 ensure corresponding student id present in friend , in step 2 corresponding student id present in likes .
Example Output: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id  =  T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id  =  T2.id

Example Input: SQL: SELECT T1.Artwork_ID , T1.Name FROM artwork AS T1 JOIN nomination AS T2 ON T1.Artwork_ID = T2.Artwork_ID GROUP BY T2.Festival_ID HAVING Count ( * ) > = 2
Feedback: Change artwork table with festival detail table and artwork id , name with festival id , festival name .
Example Output:
SELECT T1.Festival_ID ,  T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID GROUP BY T1.Festival_ID HAVING COUNT(*)  >=  2