This task is to find the number of 'For' loops present in the given cpp program.

Input: Consider Input: int Fz(int,int);
int main()
{
    int n,num[1000];
    cin>>n;
    for(int i=0;i<n;i++)
    {
        int a;
        cin>>a;
       num[i]=Fz(a,2);
    }   
for(int i=0;i<n;i++){
	cout<<num[i]<<endl;
}
    return 0;
}
int Fz(int x,int m)
{
    int s=1,i;
    int y=(int)sqrt((double)x);
    for(i=m;i<=y;i++)
    {
        if(x%i==0)
        {
        s=s+Fz(x/i,i);
        }
    }  
    return s;
}


Output: 3


Input: Consider Input: int digui(int x,int min);
int main()
{
	int n,i,m,y;
	scanf("%d",&n);
	for(i=0;i<=n-1;i++)
	{
		scanf("%d",&m);
		y=digui(m,2);
		printf("%d\n",y);
	}
	return 0;
}
int digui(int x,int min)
{
	int i,result;
	result=1;
	if(x<min)
	{
		return 0;
	}
	for(i=min;i<=x-1;i++)
	{
		if(x%i==0)
		{
			result=result+digui(x/i,i);
		}
	}
	return result;
}



Output: 2


Input: Consider Input: int f(int x,int y);// ??????x????????y????????????????? 
int main()
{
    int n,i,j,a,sum;
    cin>>n;
    for(i=1;i<=n;i++)//?? 
   {
      cin>>a;
      sum=0;     //??? 
    for(j=1;j<=a;j++)
     sum+=f(a,j);   //?? 
    
    cout<<sum<<endl;  //?? 
    
   }
    return 0;
    }
  int f(int x,int y)//??? 
  {
     int i,num=0;
     if(y==1)
       return 0;
    else
    {   
     if(x%y!=0) 
      return 0;
     else if(x==y)
      return 1;  
     else
    {
       for(i=y;i>=1;i--)      
         num+=f(x/y,i); //?? 
         
       return num;     
                 }
       
      }
      }  
    /* 
      ???????????? 
      ?100?? 
      sum=???? 
      f(100,100)=1   ??100=100 
      f(100,99) =0
      f(100,98)=0
      ....
      ....
      f(100,50)=f(2,50)+f(2,49)+........+f(2,2)+f(2,1) =1   ?????50????f(2,2)?1,?????? 
      ....
      ....
     f(100,2) =  f(50,2)+f(50,1)=f(25,2)+0=0
     f(100,1) =0
     ????? ?????????????? 
  */  


Output: 3