In this task you are expected to provide an SQL statement from an english description of what that SQL statement does. The description may include multiple steps but you should only ouput one SQL statement that accomplishes every step. An SQL query works by selecting data from a table where certain conditions apply. A table contains columns where every row in that table must have a value for each column. Every table has a primary key that uniquely identifies each row, usually an id. To choose which columns are returned you specify that after the "SELECT" statement. Next, you use a "FROM" statement to specify what tables you want to select the data from. When you specify a table you can rename it with the "AS" statement. You can reference that table by whatever name follows the "AS" statement. If you want to select data from multiple tables you need to use the "JOIN" statement. This will join the tables together by pairing a row in one table with every row in the other table (Cartesian Product). To limit the number of rows returned you should use the "ON" statement. This will only return rows where the condition specified after the statement is true, this is usually an equals operator with primary keys. You can also use the "WHERE" statement to specify that only rows with column values statisfying a certain condition, should be returned. The "GROUP BY" statement will group rows together that have equal column values for whatever columns follows the statement. The "HAVING" statement will return groups that statisfy whatever condition follows the statement. Any column(s) being returned from grouped rows must either be an aggregate function, (AVG, MAX, COUNT, SUM, ...) of a column, or the column(s) that the data was grouped by. To sort the returned data you can use the "ORDER BY" command which will order the data by whatever aggregate function or column follows the statement. The "DESC" statement will sort in descending order and the "ASC" statement will sort in ascending order. Finally, you can use the "LIMIT" statement to return a certain number of rows. When "*" is used in an SQL statement every column is returned. For example, SELECT * FROM table WHERE attribute = 1, will select every column from rows with the attribute column equal to 1.

Ex Input:
find the average monthly_rental and the average monthly_rental in Student_Addresses table

Ex Output:
SELECT Avg ( monthly_rental ) , Avg ( monthly_rental ) FROM Student_Addresses


Ex Input:
Step 1: For each row in Services table, find corresponding rows in Ref_Service_Types table and in Drama_Workshop_Groups table.
Step 2: find the number of different Currency_Code in the results of step 1 whose Service_Type_Description equals provide photo service

Ex Output:
SELECT Count ( DISTINCT T2.Currency_Code ) FROM Ref_Service_Types AS T1 JOIN Drama_Workshop_Groups AS T2 JOIN Services AS T3 ON T1.Service_Type_Code = T3.Service_Type_Code AND T3.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T1.Service_Type_Description = "provide photo service"


Ex Input:
Step 1: For each row in CMI_Cross_References table, find corresponding rows in Customer_Master_Index table and in Parking_Fines table.
Step 2: find council_tax_id of the results of step 1 whose cmi_details equals Schmitt-Lang.
Step 3: find council_tax_id of the results of step 1 whose cmi_details equals Schmidt ,  Kertzmann and Lubowitz.
Step 4: show the rows that are in the results of step 2 but not in the results of step 3

Ex Output:

SELECT T3.council_tax_id FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id JOIN Parking_Fines AS T3 ON T2.cmi_cross_ref_id = T3.cmi_cross_ref_id WHERE T1.cmi_details = "Schmitt-Lang" EXCEPT SELECT T3.council_tax_id FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id JOIN Parking_Fines AS T3 ON T2.cmi_cross_ref_id = T3.cmi_cross_ref_id WHERE T1.cmi_details = "Schmidt ,  Kertzmann and Lubowitz"