This task is to find the number of 'For' loops present in the given cpp program.

[EX Q]: int num;
void divide(int n,int n2)
{
	int i,m1;
	m1=(int)sqrt((double)n);
	for(i=n2;i<=m1;i++)
	{if(n%i==0)
	{num++;divide(n/i,i);}//?????????????????????????????
	}
}
int main()
{
	int n,i,m;
	cin>>n;
	for(i=0;i<n;i++)
	{
		num=1;
		cin>>m;
		
		divide(m,2);
		cout<<num<<endl;
	}
	return 0;
}
[EX A]: 2

[EX Q]: int f(int m,int min);					//????????
int main()
{
	int n,i,a[100],sum[100];
	cin>>n;								//??????
	for(i=0;i<n;i++)
		cin>>a[i];
	for(i=0;i<n;i++)
	{
		sum[i]=f(a[i],2);				//??????????????
		cout<<sum[i]<<endl;
	}
	return 0;
}

int f(int m,int min)					/*???????????????????????????
										??????????????*/
{
	int i,sum=0;
	if(m==min||m==1)					//???????????????????1???1?					
		return 1;
	else if(m<min)						//????????????????????
		return 0;
	else if(m>min)						//??????????????????????????????????
	{	for(i=min;i<=m;i++)
			if(m%i==0)
				sum+=f(m/i,i);
		return sum;
	}
}
[EX A]: 3

[EX Q]: 
int c = 1;

void fenjie(int a, int k)
{
	if (a == 1) 
	{
		c++;
		return;
	}
	for (int i = k; i <= a; i++)
	{
		if (a % i == 0)
		{
			fenjie(a / i, i);
		}
	}
}

int main()
{
	int n, a;
	cin >> n;
	while (n--)
	{
		c = 0;
		cin >> a;
		fenjie(a, 2);
		cout << c << endl;
	}
	return 0;
}

[EX A]:
1