This task is to find the number of 'For' loops present in the given cpp program.

int fi(int a,int j);
void main()
{
	int a,n;
	scanf("%d",&n);
	while(n--){
		scanf("%d",&a);
		printf("%d\n",fi(a,2));
	}
}
int fi(int a,int k)
{
	int i,b=1;
	if(a==1)	
		return 0;
	for(i=k;i*i<=a;i++)
		if(a%i==0)
			b=b+fi(a/i,i);
	return b;
}
1

int fenjie(int out[16],int a,int n,int m,int sheng,int b[2])
//n??out?????????m?????????????2?????????,sheng???????
{
	int i;
	for(i=m;i<=a/2;i++)
	{
		if(sheng%i==0)
		{
			out[n]=i;
			int qiu=1,k;
			for(k=0;k<=n;k++)qiu=out[k]*qiu;
			//cout<<i<<" "<<qiu<<" "<<n<<endl;
			if(qiu==a){b[0]++;break;}
			if(qiu>a)break;
			else fenjie(out,a,n+1,i,sheng/i,b);


		}
		

	}
	return 0;
}
int main()
{
	int hang=0;
	cin>>hang;
	while(hang>0)
	{
		int a;
		int b[2]={0};
		cin>>a;
		int out[16]={0};
		fenjie(out,a,0,2,a,b);
		cout<<b[0]+1<<endl;
		hang--;
	}
	return 0;
}

2

int a=0,s=0;
void find(int n,int prim)
 {
  if (n==a){s++;}
  else
   {
    for (int i=prim;i<=a/n;i++)
     if ((a%(n*i)==0)){find(n*i,i);}
   }
 }
int main()
{int n=0;cin>>n;
for (int i=1;i<=n;i++)
 {
  cin>>a;s=0;
  for (int i=2;i<=a;i++)
   {
    if (a%i==0) {find(i,i);}
   }
   cout<<s<<endl;
 }
return 0;
}


3