This task is to find the number of 'For' loops present in the given cpp program.

int f(int,int);
int main()
{
	int n,a[32768],i;
	cin>>n;
	for(i=0;i<=n-1;i++)
	{
		cin>>a[i];
	}
	for(i=0;i<=n-1;i++)
	{
		cout<<f(a[i],2)+1<<endl;
	}
	return 0;
}
int f(int a,int p)
{
	int i,sum=0;
	for(i=2;i<=sqrt(a);i++)
	{
		if(((double)a/i==a/i)&&(i>=p))
		{   p=i;
			sum=sum+1+f(a/i,p);
		}
	}
	return sum;
}

3

//============================================================================
// Name        : hanshu0109.cpp
// Author      : 1300012911
// Version     : 20131120,Wed,11th week
// Copyright   :
// Description : ????
//============================================================================


int fenjie(int a,int max){//a:?????max??1??????????????
	int i = 0;
	int sum = 0;//????
	if (a == 1) return 1;//1???????1??????
	for (i = max;i >= 2;i--)
	{
		if ((a % i) == 0) sum += fenjie(a/i,i);//i??????
	}
	return sum;//????
}

int main() {
	int k = 0;
	int n = 0;
	int num = 0;
	cin >> n;//??
	for (k = 1;k <= n;k++)
	{
		cin >> num;//?????
		cout << fenjie(num,num);//????????
		if (k < n) cout << endl;
	}
	return 0;
}

2

int get(int n,int m)//??????????????????n??????m??????
{
	if(n==1)return 1;//??n?1???????????1???
	while(m>=2)//?m?????????????????????????????????????
	{
		if(n%m==0)break;
		--m;
	}
	if(m==1)return 0;//??m?1??????????
	return get(n/m,m)+get(n,m-1);//?????????????????????????????????????n/m??????????
}
int main()
{
	int t;
	cin>>t;
	for(int i=0;i<t;++i)
	{
		int n;
		cin>>n;
		cout<<get(n,n)<<endl;	
	}
	return 0;
}


1