This task is to find the number of 'For' loops present in the given cpp program.
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Question: 
int Factorization(int n,int k){	//????????
	int sum=0;	//??????sum??????????
	if (n<k){	//?????????k
		return 0;	//??0
	}
	if (n%k==0){	//????????k???
		if (n==k){	//?n?k???
			return 1;	//??1
		}
		else{
			sum=sum+Factorization(n,k+1)+Factorization(n/k,k);	//??????????
		}
	}
	else{
		sum=sum+Factorization(n,k+1);	//?????????k????????
	}
	return sum;	//??sum??
}

int main(){	
	int t,i,a;	//???????t???????i??????a???????
	cin>>t;	//????????
	for (i=1;i<=t;i++){	//?????????
		cin>>a;
		cout<<Factorization(a,2)<<endl;
	}
	return 0;
}


Answer: 1


Question: int d;
int fen(int i,int a)
{
  if(i>a)
  {
   return 0;
  }
  int result=1;
  int j;
  for(j=i;j<a;j++)
  {
    if(a%j==0)
    {
      result=result+fen(j,a/j);
    }
  }
  return result;
}
int main()
{
  int n;
  cin >> n;
  int k=0;
  while(k<n)
  {
    
    int a;
    cin >> a;
    int i=2;
    d=fen(i,a);
    cout << d << endl;
    k++;
  }
  return 0;
  cin.get();cin.get();cin.get();
}


Answer: 1


Question: int fenjie(int max,int min)
{
    int num=1,i,k;
    for(i=min;i<max/2;i++)
    {
        k=max%i;
        if(k==0)
        {
            if(i<=max/i)
            num+=fenjie(max/i,i);
        }
    }
    return num;
}
int main()
{
    int a[10000],n,j;
    scanf("%d",&n);
    for(j=0;j<n;j++)
    {
        scanf("\n%d",&a[j]);
    }
    for(j=0;j<n;j++)
    {
        printf("%d\n",fenjie(a[j],2));
    }
    return 0;
}

Answer:
3