TASK DEFINITION: For the given English description, write an SQL command such that it accomplishes every step. An SQL query works by selecting data from a table where certain conditions apply. A table contains columns where every row in that table must have a value for each column. Every table has a primary key that uniquely identifies each row, usually an id. To choose which columns are returned you specify that after the "SELECT" statement. Next, you use a "FROM" statement to specify what tables you want to select the data from. When you specify a table you can rename it with the "AS" statement. You can reference that table by whatever name follows the "AS" statement. If you want to select data from multiple tables you need to use the "JOIN" statement. This will join the tables together by pairing a row in one table with every row in the other table (Cartesian Product). To limit the number of rows returned you should use the "ON" statement. This will only return rows where the condition specified after the statement is true, this is usually an equals operator with primary keys. You can also use the "WHERE" statement to specify that only rows with column values statisfying a certain condition, should be returned. The "GROUP BY" statement will group rows together that have equal column values for whatever columns follows the statement. The "HAVING" statement will return groups that statisfy whatever condition follows the statement. Any column(s) being returned from grouped rows must either be an aggregate function, (AVG, MAX, COUNT, SUM, ...) of a column, or the column(s) that the data was grouped by. To sort the returned data you can use the "ORDER BY" command which will order the data by whatever aggregate function or column follows the statement. The "DESC" statement will sort in descending order and the "ASC" statement will sort in ascending order. Finally, you can use the "LIMIT" statement to return a certain number of rows. When "*" is used in an SQL statement every column is returned. For example, SELECT * FROM table WHERE attribute = 1, will select every column from rows with the attribute column equal to 1.
PROBLEM: Did M6 's art director and cinematographer write M0 , M1 , M2 , M3 , M4 , and M5

SOLUTION: SELECT count(*) WHERE {
?x0 ns:film.cinematographer.film M6 .
?x0 ns:film.film_art_director.films_art_directed M6 .
?x0 ns:film.writer.film M0 .
?x0 ns:film.writer.film M1 .
?x0 ns:film.writer.film M2 .
?x0 ns:film.writer.film M3 .
?x0 ns:film.writer.film M4 .
?x0 ns:film.writer.film M5
}

PROBLEM: Did M0 's editor , director , and writer found M1 and found M2 , M3 , and M4

SOLUTION: SELECT count(*) WHERE {
?x0 ns:film.director.film M0 .
?x0 ns:film.editor.film M0 .
?x0 ns:film.writer.film M0 .
?x0 ns:organization.organization_founder.organizations_founded M1 .
?x0 ns:organization.organization_founder.organizations_founded M2 .
?x0 ns:organization.organization_founder.organizations_founded M3 .
?x0 ns:organization.organization_founder.organizations_founded M4
}

PROBLEM: Did M0 influence M1 , M2 , and M3 , influence M4 , M5 , and M6 , and influence M7

SOLUTION:
SELECT count(*) WHERE {
M0 ns:influence.influence_node.influenced M1 .
M0 ns:influence.influence_node.influenced M2 .
M0 ns:influence.influence_node.influenced M3 .
M0 ns:influence.influence_node.influenced M4 .
M0 ns:influence.influence_node.influenced M5 .
M0 ns:influence.influence_node.influenced M6 .
M0 ns:influence.influence_node.influenced M7
}