This task is to find the number of 'For' loops present in the given cpp program.

int a=0,s=0;
void find(int n,int prim)
 {
  if (n==a){s++;}
  else
   {
    for (int i=prim;i<=a/n;i++)
     if ((a%(n*i)==0)){find(n*i,i);}
   }
 }
int main()
{int n=0;cin>>n;
for (int i=1;i<=n;i++)
 {
  cin>>a;s=0;
  for (int i=2;i<=a;i++)
   {
    if (a%i==0) {find(i,i);}
   }
   cout<<s<<endl;
 }
return 0;
}

3

int f(int n,int m)
{
	int sum=1,i;
	if(n<m)
		sum=0;
	else 
		if(n==m)
			sum=1;
	else 
	{
		for(i=m;i<=n;i++)
			if(n%i==0)
				sum=sum+f(n/i,i);
	}
	return(sum);
}
void main()
{
	int x,j,a[100000];
	scanf("%d",&x);
	for(j=0;j<x;j++)
		scanf("%d",&a[j]);
	for(j=0;j<x;j++)
		printf("%d\n",f(a[j],2));
}                                               
                       
3

int shuliang(int m,int n);
main()
{
    int n;
    scanf("%d",&n);
    for (int i = 1;i <= n;i ++)
    {
        int x,q,answer=1;
        scanf("%d",&x);
        q=sqrt(x)+1;
        for (int j = 2; j < q; j ++)
        {
            if (x%j==0)
                answer+=shuliang(j,x/j);
                
        }
        printf("%d\n\n",answer);
    }
}

int shuliang(int m,int n)
{
    int q,answer=0,y=0;
    q=sqrt(n)+1;
    for (int j = m;j < q;j ++)
    {
        if (n%j==0)
            answer+=shuliang(j,n/j),y=1;
    }
    if(y==1)
        return answer+1;
    else
        return 1;
}

3