This task is to find the number of 'For' loops present in the given cpp program.

[Q]: int min(int a,int b)
{
    if(a>=b)
    return b;
    else
    return a;
}

  
  int f(int a,int b)
{ 
    int count=0;
    int k[32768]={0};
    if(a==1)
    return 1;
    else
    {
    int i,j;
    for(i=min(a,b);i>=2;i--)
    {                     
        if(a%i==0)
        k[i]=i; 
    }
    for(j=0;j<32768;j++)
    {
         if(k[j]!=0)
         {
         count=count+f(a/k[j],j);
         k[j]=0;
         }
    }
    return count; 
    }
}
main()
{
      int n,i,a,number;
      scanf("%d",&n);
      for(i=0;i<n;i++)
      {
      scanf("%d",&a);
      number=f(a,a);
      printf("%d\n",number);
      }
}

[A]: 3


[Q]: /*
 *?????
 *???2010 - 12 - 07
 *?????????  ????
 */
int num(int,int,int);
int qufen(int);
int power(int,int);
int main()
{
	int t;
	cin >> t;
	while(t >= 1)
	{
		int n,i,x,sum = 1;
		cin >> n;
		x = qufen(n);                  //qufen????????????????????
		for(i = 2; i <= x; i++)
			sum = sum + num(n,i,2);      //num?????????????i????????
		cout << sum << endl;
		t--;
	}
	return 0;
}
int qufen(int n)
{
	int j;
	for(j = 1; ; j++)
	{
		if(power(2,j) > n)
		{
			return j - 1;
			break;
		}
	}
}
int power(int a,int b)
{
	int sum = 1,k;
	for(k = 1; k <= b; k++)             //?????????
		sum = sum * a;
	return sum;
}
int num(int n,int g,int h)
{
	if((g == 1)&&(n >= h))          //???????
		return 1;
	int i,j = 0,count = 0,a[20000];  
	for(i = h; i < n; i++)                 //???????????? n ?? i ?? g ??????n / i????? g - 1?
	{                                      //?n = i * ?g?? ???? n / i = h * (g - 1 ???h??????i???
		if(n % i == 0)
		{
			a[j] = i;
			j++;
		}
	}
	if(j == 0)                     //j == 0?????????????????
		return 0;
	else
	{
		for(i = 0; i < j; i++)
			count = count + num(n / a[i],g - 1,a[i]);
		return count;
	}
}
[A]: 5


[Q]: void count(int, int);
int k;

int main()
{
	int n, i, j, m;
	int num;
	cin >> n;
	for (i = 0; i < n; i++)
	{
		k = 0;
		cin >> num;
		m = sqrt(num) + 1;
		for (j = 2; j < m; j++)
			if (num % j == 0)
			{
				k++;
				count(num / j, j);
			}
		cout << k + 1 << endl;
	}
	return 0;
}
void count(int num, int i)
{
	int j;
	int n = sqrt(num);
	for (j = i; j <= n; j++)
	{
		if (num % j == 0)
		{
			k++;
			count((num / j), j);
		}
	}
}
[A]:
3