In this task you are expected to provide an SQL statement from an english description of what that SQL statement does. The description may include multiple steps but you should only ouput one SQL statement that accomplishes every step. An SQL query works by selecting data from a table where certain conditions apply. A table contains columns where every row in that table must have a value for each column. Every table has a primary key that uniquely identifies each row, usually an id. To choose which columns are returned you specify that after the "SELECT" statement. Next, you use a "FROM" statement to specify what tables you want to select the data from. When you specify a table you can rename it with the "AS" statement. You can reference that table by whatever name follows the "AS" statement. If you want to select data from multiple tables you need to use the "JOIN" statement. This will join the tables together by pairing a row in one table with every row in the other table (Cartesian Product). To limit the number of rows returned you should use the "ON" statement. This will only return rows where the condition specified after the statement is true, this is usually an equals operator with primary keys. You can also use the "WHERE" statement to specify that only rows with column values statisfying a certain condition, should be returned. The "GROUP BY" statement will group rows together that have equal column values for whatever columns follows the statement. The "HAVING" statement will return groups that statisfy whatever condition follows the statement. Any column(s) being returned from grouped rows must either be an aggregate function, (AVG, MAX, COUNT, SUM, ...) of a column, or the column(s) that the data was grouped by. To sort the returned data you can use the "ORDER BY" command which will order the data by whatever aggregate function or column follows the statement. The "DESC" statement will sort in descending order and the "ASC" statement will sort in ascending order. Finally, you can use the "LIMIT" statement to return a certain number of rows. When "*" is used in an SQL statement every column is returned. For example, SELECT * FROM table WHERE attribute = 1, will select every column from rows with the attribute column equal to 1.

Input: Consider Input: Step 1: For each row in Document_Structures table, find the corresponding rows in Documents table.
Step 2: for each value of Document_Structures's document_structure_code in the results of step 1, calculate number of rows.
Step 3: show each value of Document_Structures's document_structure_code in the results of step 1 along with the average access_count with smallest value in the results of step 2

Output: SELECT T2.access_count , Avg ( T2.access_count ) FROM Document_Structures AS T1 JOIN Documents AS T2 ON T1.document_structure_code = T2.document_structure_code GROUP BY T1.document_structure_code ORDER BY Count ( * ) Asc LIMIT 1


Input: Consider Input: Step 1: For each row in Campuses table, find corresponding rows in csu_fees table and in discipline_enrollments table.
Step 2: find the average CampusFee in the results of step 1 whose csu_fees's Year equals 2005 and discipline_enrollments's Campus equals 1

Output: SELECT Avg ( T2.CampusFee ) FROM Campuses AS T1 JOIN csu_fees AS T2 ON T2.Campus = T1.Id JOIN discipline_enrollments AS T3 ON T1.Id = T3.Campus WHERE T2.Year = 2005 AND T3.Campus = 1


Input: Consider Input: Step 1: For each row in Student_Course_Enrolment table, find corresponding rows in Students table and in Courses table.
Step 2: find date_of_latest_logon, course_name of the results of step 1 whose personal_name equals Karson and course_name equals database


Output: SELECT T1.date_of_latest_logon , T2.course_name FROM Students AS T1 JOIN Courses AS T2 JOIN Student_Course_Enrolment AS T3 ON T1.student_id = T3.student_id AND T3.course_id = T2.course_id WHERE T1.personal_name = "Karson" AND T2.course_name = "database"