This task is to find the number of 'For' loops present in the given cpp program.

Example Input: /*
 *  Created on: 2011-11-18
 *      Author: 1100012870
 */

int su[40000],b[10000],ans;

void zhaosushu()
{
	int i,j,p;
	for(i=2;i<32768;i++)
	{
		p=1;
		for(j=2;j<=sqrt(i);j++)
			if(i%j==0){
				p=0;
				break;
			}
		if(p==0)continue;
		su[p]=1;
	}
}

void resolve(int a,int x)
{
	int i;
	if(a==1 || (su[a]==1 && a>=b[x-1])) {
		ans++;
		return;
	}
	for(i=2;i<=a;i++)
		if(a%i==0 && i>=b[x-1]){
			b[x]=i;
			resolve(a/i,x+1);
			b[x]=0;
		}
}

int main()
{
	int n,i,a;
	memset(su,0,sizeof(su));
	zhaosushu();
	cin>>n;
	for(i=1;i<=n;i++)
	{
		cin>>a;
		ans=0;
		memset(b,0,sizeof(b));
		resolve(a,1);
		cout<<ans<<endl;
	}
	return 0;
}
Example Output: 4

Example Input: int num =0;
void fenjie(int n,int x)
{
	extern int num;
	if ( n == 1)
		num ++;
	else

	for(int i = x; i<=n;i++)
		if(n % i ==  0)
			fenjie(n/i,i);
}
int main()
{
int n,k;
cin >> k;
for(int j = 0;j!= k;j++)
{extern int num;
num =0;
cin >> n;
fenjie(n,2);
cout<<num<<endl;
}
return 0;
}
Example Output: 2

Example Input: int times;
void fenjie(int m,int k)
{
	int i;
	{
		for(i=k;i<=sqrt(m);i++)
		{
			if(m%i==0)
			{
				fenjie(m/i,i);
			}
		}
	}
	times++;
}
int main()
{
	int n,i;
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
		int m;
		times=0;
		scanf("%d",&m);
		fenjie(m,2);
		printf("%d\n",times);
	}
}
Example Output:
2