This task is to find the number of 'For' loops present in the given cpp program.

Ex Input:
//* * * * * * * * * * * * * * * * * * * * * * * * 
//*????????                             *
//*???????? .cpp                        *
//*?????  1000012839                       *
//*???2010.12.04                             *
//* * * * * * * * * * * * * * * * * * * * * * * * 


int ways(int a, int min);	//	????ways?????????a??????,a??????min?
int main()
{
	int n, a, i, sum = 0, k, min;	//	n?????????,a????????????i,k?a??????min??????sum?
	cin >> n;
	for (i = 0; i < n; i++)
	{
		cin >> a;
		sum = 0;
		for (k = 2; k <= a; k++)
		{
			if (a % k == 0)
			{
				min = k;
				break;
			}
		}	//	???????
		if (a != min)
			sum = ways(a, min);	//	??a??????????
		else
			sum = 1;	//	??a?????????????
		cout << sum << endl;
	}
	return 0;
}
int ways(int a, int min)	
{
	int result = 1, i;	//	result????1??a = a???,i??????
	if(a < min)
		return 0;	//	????????????? 
	for (i = min; i < a; i++)
	{		
		if (a % i == 0)
			result += ways(a / i, i);	//	?????i??a/i????????????
	}
	return result;
}



Ex Output:
3


Ex Input:
int m=0;
int main()
{
	void count(int a,int b);
	int r,i,k,n;
	scanf("%d",&r);
	for(i=0;i<r;i++)
	{
		scanf("%d",&n);
		for(k=2;k<=sqrt(n);k++)
		{
			if(n%k==0)
			{
				m++;
				count(k,n/k);
			}
		}
		printf("%d\n",m+1);
		m=0;
	}
}

void count(int a,int b)
{
	int j;
	double t=sqrt(b);
	for(j=a;j<=t;j++)
	{
		if(b%j==0)
		{
			m++;
			count(j,b/j);
		}
	}
}


Ex Output:
3


Ex Input:
int fj(int n,int m)
{
	int i,j,k=0;
	if(n==1) return 1;
	for(i=m;i<=n;i++)
	{
		if(n%i==0)
		k+=fj(n/i,i);
	}
	return k;
}
int main()
{
	int n,i;
	scanf("%d",&n);
	for(;n>0;n--)
	{
		scanf("%d",&i);
		printf("%d",fj(i,2));
		if(n-1) printf("\n");
	}
}

Ex Output:

2