This task is to find the number of 'For' loops present in the given cpp program.
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Question: int sum;
void zhongshu(int qian,int a);
int main()
{
    int n,i,j,a[100];
    cin>>n;
    for(i=0;i<n;i++)
    cin>>a[i];
    for(i=0;i<n;i++)
    {  sum=0;
       zhongshu(2,a[i]);
       cout<<sum<<endl;
       }
    return 0;
}
void zhongshu(int qian,int a)
{
   int i,j,c;
   if(a==1)
   {
   sum=sum+1;
   return;
  }
   for(i=qian;i<=a;i++)
   {
      if(a%i==0)
         zhongshu(i,a/i);
   }
}

Answer: 3


Question: int varieties=0,p;
int dfs(int dep,int last,int k)    //???????????k????? ?? 
{
    if (k == 1)              //??k=1 
    {
        varieties++;            //???+1 
        return 0;
    }
    for (int i = last; i <= k; i++)      
    if (k % i == 0)                    //??k??i????????????k=1 
    {
        dfs(dep+1,i,k/i);
    }
}
int main()
{
    int i,n,t;
    cin>>n;            //?????? 
    int m[n];          //????n???????? 
    for(i=0;i<n;i++)
    {
        cin>>t;            
        dfs(0,2,t);
        m[i]=varieties;
        varieties=0;
    }
    for(i=0;i<n;i++)
    cout<<m[i]<<endl;      //??????????? 
    return 0;
}

Answer: 3


Question: 
int sum[50];
int i;

int main()
{
	void digui(int x, int y);
	int n;
	int j[50],m[50];


	scanf("%d",&n);

	for(i=0;i<n;i++)
	{	
		scanf("%d",&m[i]);
		sum[i]=0;
		for (j[i]=2;j[i]*j[i]<=m[i];j[i]++)
		{
			if(m[i]%j[i]==0)
			{
				sum[i]++;
				digui(j[i],m[i]/j[i]);
			}
		}
		printf("%d\n",sum[i]+1);
	}

	return 0;
}

void digui(int x, int y)
{
	int s;
	for(s=x; s*s<=y; s++) 
	{
		if(y%s==0) 
		{
			sum[i]++;
			digui(s,y/s);
		}
	}
}


Answer:
3