This task is to find the number of 'For' loops present in the given cpp program.

[EX Q]: int f(int m,int min);
int main()
{
	int n,m,i;
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
		scanf("%d",&m);
		printf("%d\n",f(m,2));
	}
	return 0;
}
int f(int m,int min)
{
	int count=1,i;
	if(m==1)
		return 1;
	else if(m == 2)
		return 1;
	else
	{
		for(i=min;i<=sqrt(m);i++)
		{
			if(m%i==0)
			{
				count += f(m/i,i);
			}
		}
		return count;
	}
}
[EX A]: 2

[EX Q]: int s=0,p=1;
void fenjie(int a,int b)
{
	int i;
	if(a==1)
		s++;
	for(i=b;i<=a;i++)
		if(a%i==0) fenjie(a/i,i);
	return;
}
int main()
{
	int n,i,j,a[100];
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
		scanf("%d",&a[i]);
		for(j=2;j*j<=a[i];j++)
		{
			if(a[i]%j==0)
			{
				s=0;
				fenjie(a[i]/j,j);
				p=p+s;
			}
		}
        printf("%d\n",p);
		p=1;
	}
	return 0;
}

[EX A]: 3

[EX Q]: int multiply(int a,int b)
{
	int i=0,n=0,sum=1;
	if(a<b)
		return 0;
	else
	{
		for(i=b;i<=a;i++) //????
		{
			if(a%i==0)
			{
				sum=sum+multiply(a/i,i); //????
			}
		}
		return sum;
	}
}
int main()
{
	int n=0,m=0,i=0,sum=0,num,result[1000];
	cin>>n;
	do    //?????
	{
		cin>>num;
		result[i]=multiply(num,2); //????
		i=i+1;
		m=m+1;
	}while(m<n);
	for(i=0;i<n;i++)//????
	{
		cout<<result[i]<<endl;
	}
	return 0;
}

[EX A]:
2