Table:
text: Computus
Meeus Julian algorithm
Meeus Julian algorithm
Expression Y_is_2008 Y_is_2009 Y_is_2010 Y_is_2011
a = Y mod 4 a = 0 a = 1 a = 2 a = 3
b = Y mod 7 b = 6 b = 0 b = 1 b = 2
c = Y mod 19 c = 13 c = 14 c = 15 c = 16
d = (19c + 15) mod 30 d = 22 d = 11 d = 0 d = 19
e = (2a + 4b − d + 34) mod 7 e = 1 e = 4 e = 0 e = 1

Question: What is y = 2008 when y = 2011 a = 3 under Computus?