one power source to many power sources circuit - Page 1
Forum section: electronics / beginners

author: Capernicus
author_rank: Frequent Contributor
timestamp: October 06, 2021, 08:33:03 am
content: Ive got another pure RC circuit for you guys.This circuit can turn one battery into as many separate power sources you want, with the negative and positive rail separated via resistance.There's no cross conduction on the rail, and its just a pure RC circuit. No transformers required, and no spark gaps.You could even use it on the power grid to stop houses stealing each others power and conducting into each other. all 3 isolations have a separate amp quota that cant be exceeded.There is a little voltage loss, but its not much, and the previous level is guaranteed not to enter the next levels discharge, via always keeping one end shorted no resistance at each level. There is two levels, one level resists the positive rail, and the other level resists the negative.The cool thing, but I haven't tested it to be honest, is it should work all the way to miniscule femto farad symmetrical's, really cheap capacitors.If you require even more isolation, you can add more capacitor levels to it, but its a little wasteful of components.Note, u cant actually split houses with this, because the caps aren't allowed to ever clip for this to function properly, so you have to constantly expend it at the units, but if its say a computer or a motor driver or something, you can make it so it always does fairly easily.Does anyone here have another way of doing it? And does this actually happen between our fuse boxes when we connect to the power grid?

author: gcewing
author_rank: Regular Contributor
timestamp: October 06, 2021, 10:04:23 am
content: Quote from: Capernicus on October 06, 2021, 08:33:03 amThat's about the only true thing you've said here. The rest is complete nonsense.Each of your 1 ohm loads is being fed through 2k of resistance, so the current is limited to about 1/2000 of what it would be if they were connected directly to the source. And they will see about 1/2000 of the voltage. And the 1k resistors will waste about 2000 times as much power as is delivered to the loads.If this is being fed with DC, the capacitors make no difference at all, except maybe to deliver a short burst of current when a load is turned on. After that initial transient, they might as well not be there. Imagine removing them altogether and see what you've got left.Using AC for the supply will only make things worse, as the capacitors will just partially short out the supply, drawing more current and wasting more power in the resistors. They won't "assist" anything.QuoteI encourage you to do so (safely, with low voltage, NOT mains!) -- you'll learn a lot. You'll find it won't do anything remotely like you imagine it will do.QuoteIt's not entirely clear what "it" is supposed to be. If the loads are something like motors or batteries that could potentially feed power back the other way, and you don't want that to happen, you could isolate them with diodes.That assumes the supply is DC, if it's AC you have a more difficult problem.QuoteIn a word, no.This is not a problem that exists in practice. The only way for another house to "steal" power from yours is if you have a solar installation or something that produces more power than you use, and you've installed equipment that is capable of feeding it back into the grid. If you've done that, then presumably you want it to happen.The power company won't mind if you give them power, and they might even pay you something for it if you've come to an arrangement about that. If not, they might rig your meter so that you don't get a negative power bill, but I don't think they generally go out of their way to block reverse power flow.

author: Capernicus
author_rank: Frequent Contributor
timestamp: October 06, 2021, 10:22:27 am
content: Its for dc not ac. sorry for the confusion.Yes... indeed your right about the final voltage division there, from the 1k- 1ohm, it seems like it would be really bad, but it still worked on my desk, maybe I'm not seeing something yet. (and theres a better way to wire it!) But that only happens once on the final capacitor, the one before is fine. (well, it gets /2 only)If you have a varying load inside the unit, then your voltage division would be charging the capacitor different voltages, so maybe it evens out in this case over time?AND NOTE! that only changes the effective maximum capacity of the capacitor, the amount of the charge is the same, so if its constantly releasing it it might not make a dif! (it clips faster, but its coming out faster so it balances out.)It may be a little less electricity, the amount I'm not sure of exactly, but it wont stop it from working entirely.Its actually kind of strange, the less ohmage the less voltage going in, the more ohmage the more voltage going in, how does that work out? the same?I dont think you can isolate a rail with diodes, because youd be hitting it simultaneous both sides and it wouldnt activate/deactivate properly.