Thermal resistance of unknown heatsink - Page 1
Forum section: electronics / beginners

author: ttyz
author_rank: Newbie
timestamp: September 17, 2013, 03:13:05 pm
content: Hello everybody,I have a small silly question, but I hope somebody could help me. I am now working on my pawer supply project. I have some considerations on thermal design. I have watched Dave's video on this topic, but I still have a question. I found a heatsink but the problem is that I don't know what part number it is, so I cannot look the thermal resistance in the datasheet to do the calculations. Is there any method to calculate or mesure thermal resistance?Thank you in advance,Ebgeny

author: Monkeh
author_rank: Super Contributor
timestamp: September 17, 2013, 03:14:29 pm
content: Apply known amount of heat, measure temperature..

author: ttyz
author_rank: Newbie
timestamp: September 17, 2013, 03:20:08 pm
content: Yes, thank you Monkeh. That was my first thought. But I could not really think of the source of this known amount of heat.

author: Balaur
author_rank: Unknown
timestamp: September 17, 2013, 03:25:43 pm
content: If you want to be rigorous about it:select a device close or identical to the one you are planning to use in the final designi.e. the same regulator or transistor or at least one transistor with the same packageforce it to dissipate the power you want(i.e. polarize the transistor, force the regulator to deliver some power to an external load and vary the input voltage)Or you can use a power resistor, but attaching it to the radiator is a bit more delicate.PS (sorry for the initial incomplete submit, was a mistake)

author: Dave
author_rank: Super Contributor
timestamp: September 17, 2013, 03:26:07 pm
content: You actually need to apply a known amount of power, not heat.Heat - energyPower - heat over timeAll you need is a power resistor, a power supply and couple of multimeters.

author: ttyz
author_rank: Newbie
timestamp: September 17, 2013, 03:28:32 pm
content: Thank you, guys, now I think I am getting the idea. I will give it a try.

author: mariush
author_rank: Super Contributor
timestamp: September 17, 2013, 03:28:40 pm
content: Get a linear regulator like 7805 or a 7812, connect a lightbulb or a resistor, something that would use a few hundred mA (measure the exact current) ... measure the tab temperature after a minute or so.Put the linear regulator on the heatsink, repeat and measure temperature.You have the tab thermal resistance in the datasheet, so now it's just an issue of math to get the heatsink's thermal performance.

author: AG6QR
author_rank: Frequent Contributor
timestamp: September 17, 2013, 03:33:15 pm
content: Quote from: ttyz on September 17, 2013, 03:20:08 pmAttach a resistor or transistor to the heat sink, using the same type of package that it's designed to accept. Using an adjustable power supply or something else appropriate, dissipate power in the device. Measure the voltage and current.It's dead simple with a TO-220 resistor, which they do make. It's only a bit more complicated with a transistor. A voltage regulator is pretty easy to throw a known amount of power into.

author: Jay_Diddy_B
author_rank: Super Contributor
timestamp: September 17, 2013, 03:56:10 pm
content: Hi,You can use a little Physics.First you weigh the heatsink.Let say it weighs to 200g.You then multiply this by the specific heat capacity of the material:Aluminum 0.897 J/g/degrees C200 x 0.897 = 179 J / degrees CYou can then heat the heatsink in an oven, or any other way.Place the heatsink in the orientation that you plan to use it. If you are using a fan, arrange the fan to blow across the heatsink.Allow the heatsink to cool. While the heatsink is cooling measure and record the temperature changes.Lets say you raise the heatsink to 60C and the room temperature is 20CWhen the temperature has dropped by 63%, (60-20) x 0.64 = 25.6C, Would be 60-25.6 = 34.4CRecord the time, this is the thermal time constant.Let's say it takes 300 seconds.Thermal Resistance = Thermal time constant / Thermal mass = 300 / 179 = 1.67 C/WI apologize for using physics.Jay_Diddy_B

author: ttyz
author_rank: Newbie
timestamp: September 17, 2013, 04:08:05 pm
content: Jay_Diddy_B, cool method, thank you very much, I have to do it this way. Using phisics is always great