:: Planes in Affine Spaces :: by Wojciech Leo\'nczuk, Henryk Oryszczyszyn and Krzysztof Pra\.zmowski environ vocabularies DIRAF, SUBSET_1, ANALOAF, AFF_1, INCSP_1, STRUCT_0, XBOOLE_0, TARSKI, RELAT_1, PARSP_1, AFF_2, ARYTM_3, AFF_4; notations TARSKI, XBOOLE_0, SUBSET_1, STRUCT_0, ANALOAF, DIRAF, AFF_1, AFF_2; constructors AFF_1, AFF_2; registrations XBOOLE_0, STRUCT_0; requirements SUBSET, BOOLE; definitions TARSKI; expansions TARSKI; theorems AFF_1, DIRAF, TARSKI, AFF_2, XBOOLE_0, XBOOLE_1; begin reserve AS for AffinSpace; reserve a,b,c,d,a9,b9,c9,d9,p,q,r,x,y for Element of AS; reserve A,C,K,M,N,P,Q,X,Y,Z for Subset of AS; Lm1: for x being set st x in X holds x is Element of AS; theorem Th1: (LIN p,a,a9 or LIN p,a9,a) & p<>a implies ex b9 st LIN p,b,b9 & a ,b // a9,b9 proof assume that A1: LIN p,a,a9 or LIN p,a9,a and A2: p<>a; LIN p,a,a9 by A1,AFF_1:6; then p,a // p,a9 by AFF_1:def 1; then a,p // p,a9 by AFF_1:4; then consider b9 such that A3: b,p // p,b9 and A4: b,a // a9,b9 by A2,DIRAF:40; p,b // p,b9 by A3,AFF_1:4; then A5: LIN p,b, b9 by AFF_1:def 1; a,b // a9,b9 by A4,AFF_1:4; hence thesis by A5; end; theorem Th2: (a,b // A or b,a // A) & a in A implies b in A proof assume that A1: a,b // A or b,a // A and A2: a in A; a,b // A & A is being_line by A1,AFF_1:26,34; hence thesis by A2,AFF_1:23; end; theorem Th3: (a,b // A or b,a // A) & A // K implies a,b // K & b,a // K proof assume that A1: a,b // A or b,a // A and A2: A // K; a,b // A by A1,AFF_1:34; hence a,b // K by A2,AFF_1:43; hence thesis by AFF_1:34; end; theorem Th4: (a,b // A or b,a // A) & (a,b // c,d or c,d // a,b) & a<>b implies c,d // A & d,c // A proof assume that A1: ( a,b // A or b,a // A)&( a,b // c,d or c,d // a,b) and A2: a<>b; a,b // A & a,b // c,d by A1,AFF_1:4,34; hence c,d // A by A2,AFF_1:32; hence thesis by AFF_1:34; end; theorem (a,b // M or b,a // M) & (a,b // N or b,a // N) & a<>b implies M // N proof assume that A1: ( a,b // M or b,a // M)&( a,b // N or b,a // N) and A2: a<>b; a,b // M & a,b // N by A1,AFF_1:34; hence thesis by A2,AFF_1:53; end; theorem (a,b // M or b,a // M) & (c,d // M or d,c // M) implies a,b // c,d proof assume ( a,b // M or b,a // M)&( c,d // M or d,c // M); then A1: a,b // M & c,d // M by AFF_1:34; then M is being_line by AFF_1:26; hence thesis by A1,AFF_1:31; end; theorem Th7: (A // C or C // A) & a<>b & (a,b // c,d or c,d // a,b) & a in A & b in A & c in C implies d in C proof assume that A1: A // C or C // A and A2: a<>b &( a,b // c,d or c,d // a,b) and A3: a in A & b in A and A4: c in C; A is being_line by A1,AFF_1:36; then a,b // A by A3,AFF_1:52; then c,d // A by A2,Th4; then c,d // C by A1,Th3; hence thesis by A4,Th2; end; Lm2: A // K & a in A & a9 in A & d in K implies ex d9 st d9 in K & a,d // a9, d9 proof assume that A1: A // K and A2: a in A & a9 in A and A3: d in K; A4: A is being_line by A1,AFF_1:36; now assume A5: a<>a9; consider d9 such that A6: a,a9 // d,d9 and A7: a,d // a9,d9 by DIRAF:40; d,d9 // a,a9 by A6,AFF_1:4; then d,d9 // A by A2,A4,A5,AFF_1:27; then d,d9 // K by A1,Th3; then d9 in K by A3,Th2; hence thesis by A7; end; hence thesis by A3,AFF_1:2; end; theorem Th8: q in M & q in N & a in M & b in N & b9 in N & q<>a & q<>b & M<>N & (a,b // a9,b9 or b,a // b9,a9) & M is being_line & N is being_line & q=a9 implies q=b9 proof assume that A1: q in M and A2: q in N and A3: a in M and A4: b in N and A5: b9 in N and A6: q<>a and A7: q<>b & M<>N and A8: a,b // a9,b9 or b,a // b9,a9 and A9: M is being_line and A10: N is being_line and A11: q=a9; A12: not LIN q,a,b proof assume not thesis; then consider A such that A13: A is being_line & q in A and A14: a in A and A15: b in A by AFF_1:21; M=A by A1,A3,A6,A9,A13,A14,AFF_1:18; hence contradiction by A2,A4,A7,A10,A13,A15,AFF_1:18; end; LIN q,b,b9 & a,b // a9,b9 by A2,A4,A5,A8,A10,AFF_1:4,21; hence thesis by A11,A12,AFF_1:55; end; theorem Th9: q in M & q in N & a in M & a9 in M & b in N & b9 in N & q<>a & q <>b & M<>N & (a,b // a9,b9 or b,a // b9,a9) & M is being_line & N is being_line & a=a9 implies b=b9 proof assume that A1: q in M and A2: q in N and A3: a in M and A4: a9 in M and A5: b in N and A6: b9 in N and A7: q<>a and A8: q<>b & M<>N and A9: a,b // a9,b9 or b,a // b9,a9 and A10: M is being_line and A11: N is being_line and A12: a=a9; A13: a,b // a9,b & a,b // a9,b9 by A9,A12,AFF_1:2,4; A14: not LIN q,a,b proof assume not thesis; then consider A such that A15: A is being_line & q in A and A16: a in A and A17: b in A by AFF_1:21; M=A by A1,A3,A7,A10,A15,A16,AFF_1:18; hence contradiction by A2,A5,A8,A11,A15,A17,AFF_1:18; end; A18: LIN q,b,b by AFF_1:7; LIN q,a,a9 & LIN q,b,b9 by A1,A2,A3,A4,A5,A6,A10,A11,AFF_1:21; hence thesis by A14,A18,A13,AFF_1:56; end; theorem Th10: (M // N or N // M) & a in M & b in N & b9 in N & M<>N & (a,b // a9,b9 or b,a // b9,a9) & a=a9 implies b=b9 proof assume that A1: M // N or N // M and A2: a in M and A3: b in N & b9 in N and A4: M<>N and A5: ( a,b // a9,b9 or b,a // b9,a9)& a=a9; a,b // a,b9 by A5,AFF_1:4; then LIN a,b,b9 by AFF_1:def 1; then A6: LIN b,b9,a by AFF_1:6; assume A7: b<>b9; N is being_line by A1,AFF_1:36; then a in N by A3,A6,A7,AFF_1:25; hence contradiction by A1,A2,A4,AFF_1:45; end; theorem Th11: ex A st a in A & b in A & A is being_line proof LIN a,b,b by AFF_1:7; then ex A st A is being_line & a in A & b in A & b in A by AFF_1:21; hence thesis; end; theorem Th12: A is being_line implies ex q st not q in A proof assume A1: A is being_line; then consider a,b such that A2: a in A & b in A and A3: a<>b by AFF_1:19; consider q such that A4: not LIN a,b,q by A3,AFF_1:13; not q in A by A1,A2,A4,AFF_1:21; hence thesis; end; definition let AS,K,P; func Plane(K,P) -> Subset of AS equals {a: ex b st a,b // K & b in P}; coherence proof set X = {a: ex b st a,b // K & b in P}; now let x be object; assume x in X; then ex a st a=x & ex b st a,b // K & b in P; hence x in the carrier of AS; end; hence thesis by TARSKI:def 3; end; end; definition let AS,X; attr X is being_plane means ex K,P st K is being_line & P is being_line & not K // P & X = Plane(K,P); end; Lm3: for q holds (q in Plane(K,P) iff ex b st q,b // K & b in P) proof let q; now assume q in Plane(K,P); then ex a st a=q & ex b st a,b // K & b in P; hence ex b st q,b // K & b in P; end; hence thesis; end; theorem not K is being_line implies Plane(K,P) = {} proof assume A1: not K is being_line; set x = the Element of Plane(K,P); assume Plane(K,P)<>{}; then x in Plane(K,P); then ex a st x=a & ex b st a,b // K & b in P; hence contradiction by A1,AFF_1:26; end; theorem Th14: K is being_line implies P c= Plane(K,P) proof assume A1: K is being_line; let x be object; assume A2: x in P; then reconsider a=x as Element of AS; a,a // K by A1,AFF_1:33; hence x in Plane(K,P) by A2; end; theorem K // P implies Plane(K,P) = P proof set X=Plane(K,P); assume A1: K // P; then A2: P is being_line by AFF_1:36; now let x be object; assume x in X; then consider a such that A3: x=a and A4: ex b st a,b // K & b in P; consider b such that A5: a,b // K and A6: b in P by A4; a,b // P by A1,A5,AFF_1:43; then b,a // P by AFF_1:34; hence x in P by A2,A3,A6,AFF_1:23; end; then A7: X c= P; K is being_line by A1,AFF_1:36; then P c= X by Th14; hence thesis by A7,XBOOLE_0:def 10; end; theorem Th16: K // M implies Plane(K,P) = Plane(M,P) proof assume A1: K // M; now let x be object; A2: now assume x in Plane(M,P); then consider a such that A3: x=a and A4: ex b st a,b // M & b in P; consider b such that A5: a,b // M and A6: b in P by A4; a,b // K by A1,A5,AFF_1:43; hence x in Plane(K,P) by A3,A6; end; now assume x in Plane(K,P); then consider a such that A7: x=a and A8: ex b st a,b // K & b in P; consider b such that A9: a,b // K and A10: b in P by A8; a,b // M by A1,A9,AFF_1:43; hence x in Plane(M,P) by A7,A10; end; hence x in Plane(K,P) iff x in Plane(M,P) by A2; end; hence thesis by TARSKI:2; end; theorem p in M & a in M & b in M & p in N & a9 in N & b9 in N & not p in P & not p in Q & M<>N & a in P & a9 in P & b in Q & b9 in Q & M is being_line & N is being_line & P is being_line & Q is being_line implies (P // Q or ex q st q in P & q in Q) proof assume that A1: p in M and A2: a in M and A3: b in M and A4: p in N and A5: a9 in N and A6: b9 in N and A7: not p in P and A8: not p in Q and A9: M<>N and A10: a in P and A11: a9 in P and A12: b in Q and A13: b9 in Q and A14: M is being_line and A15: N is being_line and A16: P is being_line and A17: Q is being_line; A18: a<>a9 by A1,A2,A4,A5,A7,A9,A10,A14,A15,AFF_1:18; LIN p,a,b by A1,A2,A3,A14,AFF_1:21; then consider c such that A19: LIN p,a9,c and A20: a,a9 // b,c by A7,A10,Th1; set D=Line(b,c); A21: b in D by AFF_1:15; A22: c in D by AFF_1:15; A23: b<>b9 by A1,A3,A4,A6,A8,A9,A12,A14,A15,AFF_1:18; A24: c in N by A4,A5,A7,A11,A15,A19,AFF_1:25; then A25: b<>c by A1,A3,A4,A8,A9,A12,A14,A15,AFF_1:18; then A26: D is being_line by AFF_1:def 3; now assume D<>Q; then A27: c <>b9 by A12,A13,A17,A23,A26,A21,A22,AFF_1:18; LIN b9,c,a9 by A5,A6,A15,A24,AFF_1:21; then consider q such that A28: LIN b9,b,q and A29: c,b // a9,q by A27,Th1; a9,a // c,b by A20,AFF_1:4; then a9,a // a9,q by A25,A29,AFF_1:5; then LIN a9,a,q by AFF_1:def 1; then A30: q in P by A10,A11,A16,A18,AFF_1:25; q in Q by A12,A13,A17,A23,A28,AFF_1:25; hence ex q st q in P & q in Q by A30; end; hence thesis by A10,A11,A12,A16,A17,A18,A20,A25,A22,AFF_1:38; end; theorem Th18: a in M & b in M & a9 in N & b9 in N & a in P & a9 in P & b in Q & b9 in Q & M<>N & M // N & P is being_line & Q is being_line implies (P // Q or ex q st q in P & q in Q) proof assume that A1: a in M and A2: b in M and A3: a9 in N and A4: b9 in N and A5: a in P and A6: a9 in P and A7: b in Q and A8: b9 in Q and A9: M<>N and A10: M // N and A11: P is being_line and A12: Q is being_line; A13: a<>a9 by A1,A3,A9,A10,AFF_1:45; A14: N is being_line by A10,AFF_1:36; A15: b<>b9 by A2,A4,A9,A10,AFF_1:45; A16: M is being_line by A10,AFF_1:36; now assume A17: a<>b; consider c such that A18: a,b // a9,c and A19: a,a9 // b,c by DIRAF:40; set D=Line(b,c); A20: b in D by AFF_1:15; A21: c in D by AFF_1:15; a,b // N by A1,A2,A10,A16,AFF_1:43,52; then a9,c // N by A17,A18,AFF_1:32; then A22: c in N by A3,A14,AFF_1:23; then A23: b<>c by A2,A9,A10,AFF_1:45; then A24: D is being_line by AFF_1:def 3; now assume D<>Q; then A25: c <>b9 by A7,A8,A12,A15,A24,A20,A21,AFF_1:18; LIN b9,c,a9 by A3,A4,A14,A22,AFF_1:21; then consider q such that A26: LIN b9,b,q and A27: c,b // a9,q by A25,Th1; a9,a // c,b by A19,AFF_1:4; then a9,a // a9,q by A23,A27,AFF_1:5; then LIN a9,a,q by AFF_1:def 1; then A28: q in P by A5,A6,A11,A13,AFF_1:25; q in Q by A7,A8,A12,A15,A26,AFF_1:25; hence ex q st q in P & q in Q by A28; end; hence thesis by A5,A6,A7,A11,A12,A13,A19,A23,A21,AFF_1:38; end; hence thesis by A5,A7; end; Lm4: a in Q & a in Plane(K,P) & K // Q implies Q c= Plane(K,P) proof assume that A1: a in Q and A2: a in Plane(K,P) and A3: K // Q; A4: Plane(K,P) = Plane(Q,P) by A3,Th16; let x be object such that A5: x in Q; reconsider c = x as Element of AS by A5; A6: Q is being_line by A3,AFF_1:36; consider b such that A7: a,b // K and A8: b in P by A2,Lm3; a,b // Q by A3,A7,AFF_1:43; then b in Q by A1,A6,AFF_1:23; then c,b // Q by A5,A6,AFF_1:23; hence x in Plane(K,P) by A8,A4; end; Lm5: K is being_line & P is being_line & Q is being_line & a in Plane(K,P) & b in Plane(K,P) & a<>b & a in Q & b in Q implies Q c= Plane(K,P) proof assume that A1: K is being_line and A2: P is being_line and A3: Q is being_line and A4: a in Plane(K,P) and A5: b in Plane(K,P) and A6: a<>b and A7: a in Q and A8: b in Q; let x be object; assume A9: x in Q; then reconsider c = x as Element of AS; consider a9 such that A10: a,a9 // K and A11: a9 in P by A4,Lm3; consider Y such that A12: b in Y and A13: K // Y by A1,AFF_1:49; consider X such that A14: a in X and A15: K // X by A1,AFF_1:49; consider b9 such that A16: b,b9 // K and A17: b9 in P by A5,Lm3; b,b9 // Y by A16,A13,AFF_1:43; then A18: b9 in Y by A12,Th2; a,a9 // X by A10,A15,AFF_1:43; then A19: a9 in X by A14,Th2; A20: X // Y by A15,A13,AFF_1:44; A21: now A22: now given q such that A23: q in P and A24: q in Q and A25: not P // Q; A26: P<>Q by A2,A25,AFF_1:41; A27: now assume A28: q<>b; then A29: b<>b9 by A2,A3,A8,A17,A23,A24,A26,AFF_1:18; A30: now A31: q,b9 // P by A2,A17,A23,AFF_1:23; LIN q,b,c by A3,A8,A9,A24,AFF_1:21; then consider c9 such that A32: LIN q,b9, c9 and A33: b,b9 // c,c9 by A28,Th1; assume A34: q<>b9; q,b9 // q,c9 by A32,AFF_1:def 1; then q,c9 // P by A34,A31,AFF_1:32; then A35: c9 in P by A23,Th2; c,c9 // K by A16,A29,A33,AFF_1:32; hence x in Plane(K,P) by A35; end; now assume A36: q=b9; b,q // Q by A3,A8,A24,AFF_1:23; then Q c= Plane(K,P) by A4,A7,A16,A28,A36,Lm4,AFF_1:53; hence x in Plane(K,P) by A9; end; hence x in Plane(K,P) by A30; end; now assume A37: q<>a; then A38: a<>a9 by A2,A3,A7,A11,A23,A24,A26,AFF_1:18; A39: now A40: q,a9 // P by A2,A11,A23,AFF_1:23; LIN q,a,c by A3,A7,A9,A24,AFF_1:21; then consider c9 such that A41: LIN q,a9, c9 and A42: a,a9 // c,c9 by A37,Th1; assume A43: q<>a9; q,a9 // q,c9 by A41,AFF_1:def 1; then q,c9 // P by A43,A40,AFF_1:32; then A44: c9 in P by A23,Th2; c,c9 // K by A10,A38,A42,AFF_1:32; hence x in Plane(K,P) by A44; end; now assume A45: q=a9; a,q // Q by A3,A7,A24,AFF_1:23; then Q c= Plane(K,P) by A4,A7,A10,A37,A45,Lm4,AFF_1:53; hence x in Plane(K,P) by A9; end; hence x in Plane(K,P) by A39; end; hence x in Plane(K,P) by A6,A27; end; A46: now assume A47: P // Q; A48: now assume P<>Q; then A49: b<>b9 by A8,A17,A47,AFF_1:45; now assume A50: c <>b; consider c9 such that A51: b,c // b9,c9 and A52: b,b9 // c,c9 by DIRAF:40; b,c // Q by A3,A8,A9,AFF_1:23; then b9,c9 // Q by A50,A51,AFF_1:32; then b9,c9 // P by A47,AFF_1:43; then A53: c9 in P by A17,Th2; c,c9 // K by A16,A49,A52,AFF_1:32; hence x in Plane(K,P) by A53; end; hence x in Plane(K,P) by A5; end; now assume A54: P=Q; c,c // K by A1,AFF_1:33; hence x in Plane(K,P) by A9,A54; end; hence x in Plane(K,P) by A48; end; assume X<>Y; then P // Q or ex q st q in P & q in Q by A2,A3,A7,A8,A11,A17,A14,A12,A20 ,A19,A18,Th18; hence x in Plane(K,P) by A46,A22; end; A55: X is being_line by A10,A15,AFF_1:26,43; now assume X=Y; then Q = X by A3,A6,A7,A8,A14,A12,A55,AFF_1:18; then Q c= Plane(K,P) by A4,A7,A15,Lm4; hence x in Plane(K,P) by A9; end; hence x in Plane(K,P) by A21; end; theorem Th19: X is being_plane & a in X & b in X & a<>b implies Line(a,b) c= X proof assume that A1: X is being_plane and A2: a in X & b in X and A3: a<>b; set Q = Line(a,b); A4: a in Q & b in Q by AFF_1:15; Q is being_line & ex K,P st K is being_line & P is being_line & not K // P & X=Plane(K,P) by A1,A3,AFF_1:def 3; hence thesis by A2,A3,A4,Lm5; end; Lm6: K is being_line & Q c= Plane(K,P) implies Plane(K,Q) c= Plane(K,P) proof assume that A1: K is being_line and A2: Q c= Plane(K,P); let x be object; assume x in Plane(K,Q); then consider a such that A3: x=a and A4: ex b st a,b // K & b in Q; consider b such that A5: a,b // K and A6: b in Q by A4; consider c such that A7: b,c // K and A8: c in P by A2,A6,Lm3; consider M such that A9: b in M and A10: K // M by A1,AFF_1:49; a,b // M by A5,A10,AFF_1:43; then A11: a in M by A9,Th2; b,c // M by A7,A10,AFF_1:43; then c in M by A9,Th2; then a,c // K by A10,A11,AFF_1:40; hence x in Plane(K,P) by A3,A8; end; theorem Th20: K is being_line & P is being_line & Q is being_line & not K // Q & Q c= Plane(K,P) implies Plane(K,Q) = Plane(K,P) proof assume that A1: K is being_line and A2: P is being_line and A3: Q is being_line and A4: not K // Q and A5: Q c= Plane(K,P); A6: Plane(K,Q) c= Plane(K,P) by A1,A5,Lm6; consider a,b such that A7: a in Q and A8: b in Q and A9: a<>b by A3,AFF_1:19; consider b9 such that A10: b,b9 // K and A11: b9 in P by A5,A8,Lm3; b9,b // K by A10,AFF_1:34; then A12: b9 in Plane(K,Q) by A8; consider a9 such that A13: a,a9 // K and A14: a9 in P by A5,A7,Lm3; A15: a9<>b9 proof consider A such that A16: a9 in A and A17: K // A by A1,AFF_1:49; a9,a // A by A13,A17,Th3; then A18: a in A by A16,Th2; assume a9=b9; then a9,b // A by A10,A17,Th3; then A19: b in A by A16,Th2; A is being_line by A17,AFF_1:36; hence contradiction by A3,A4,A7,A8,A9,A17,A19,A18,AFF_1:18; end; a9,a // K by A13,AFF_1:34; then a9 in Plane(K,Q) by A7; then Plane(K,P) c= Plane(K,Q) by A1,A2,A3,A14,A11,A15,A12,Lm5,Lm6; hence thesis by A6,XBOOLE_0:def 10; end; theorem Th21: K is being_line & P is being_line & Q is being_line & Q c= Plane (K,P) implies P // Q or ex q st q in P & q in Q proof assume that A1: K is being_line and A2: P is being_line and A3: Q is being_line and A4: Q c= Plane(K,P); consider a,b such that A5: a in Q and A6: b in Q and A7: a<>b by A3,AFF_1:19; consider a9 such that A8: a,a9 // K and A9: a9 in P by A4,A5,Lm3; consider A such that A10: a9 in A and A11: K // A by A1,AFF_1:49; A12: a9,a // A by A8,A11,Th3; then A13: a in A by A10,Th2; consider b9 such that A14: b,b9 // K and A15: b9 in P by A4,A6,Lm3; consider M such that A16: b9 in M and A17: K // M by A1,AFF_1:49; A18: b9,b // M by A14,A17,Th3; then A19: b in M by A16,Th2; A20: A is being_line by A11,AFF_1:36; A21: now assume A=M; then A22: b in A by A16,A18,Th2; a in A by A10,A12,Th2; then a9 in Q by A3,A5,A6,A7,A10,A20,A22,AFF_1:18; hence ex q st q in P & q in Q by A9; end; A // M by A11,A17,AFF_1:44; hence thesis by A2,A3,A5,A6,A9,A15,A10,A16,A13,A19,A21,Th18; end; theorem Th22: X is being_plane & M is being_line & N is being_line & M c= X & N c= X implies M // N or ex q st q in M & q in N proof assume that A1: X is being_plane and A2: M is being_line and A3: N is being_line and A4: M c= X & N c= X; consider K,P such that A5: K is being_line and A6: P is being_line and not K // P and A7: X = Plane(K,P) by A1; A8: now assume not K // N; then M c= Plane(K,N) by A3,A4,A5,A6,A7,Th20; then N // M or ex q st q in N & q in M by A2,A3,A5,Th21; hence thesis; end; now assume not K // M; then N c= Plane(K,M) by A2,A4,A5,A6,A7,Th20; hence thesis by A2,A3,A5,Th21; end; hence thesis by A8,AFF_1:44; end; theorem Th23: X is being_plane & a in X & M c= X & a in N & (M // N or N // M) implies N c= X proof assume that A1: X is being_plane and A2: a in X and A3: M c= X and A4: a in N and A5: M // N or N // M; A6: M is being_line by A5,AFF_1:36; consider K,P such that A7: K is being_line and A8: P is being_line and not K // P and A9: X = Plane(K,P) by A1; A10: N is being_line by A5,AFF_1:36; A11: now assume A12: not K // M; then A13: X = Plane(K,M) by A3,A6,A7,A8,A9,Th20; A14: a in Plane(K,M) by A2,A3,A6,A7,A8,A9,A12,Th20; now consider a9 such that A15: a,a9 // K and A16: a9 in M by A14,Lm3; consider b9 such that A17: a9<>b9 and A18: b9 in M by A6,AFF_1:20; consider b such that A19: a9,a // b9,b and A20: a9,b9 // a,b by DIRAF:40; assume A21: M<>N; then a<>a9 by A4,A5,A16,AFF_1:45; then b,b9 // K by A15,A19,Th4; then A22: b in Plane(K,M) by A18; A23: a<>b proof assume a=b; then a,a9 // a,b9 by A19,AFF_1:4; then LIN a, a9,b9 by AFF_1:def 1; then LIN a9,b9,a by AFF_1:6; then a in M by A6,A16,A17,A18,AFF_1:25; hence contradiction by A4,A5,A21,AFF_1:45; end; a,b // M by A6,A16,A17,A18,A20,AFF_1:32,52; then a,b // N by A5,Th3; then b in N by A4,Th2; hence thesis by A2,A4,A6,A10,A7,A13,A23,A22,Lm5; end; hence thesis by A3; end; now assume K // M; then K // N by A5,AFF_1:44; hence thesis by A2,A4,A9,Lm4; end; hence thesis by A11; end; theorem Th24: X is being_plane & Y is being_plane & a in X & b in X & a in Y & b in Y & X<>Y & a<>b implies X /\ Y is being_line proof assume that A1: X is being_plane and A2: Y is being_plane and A3: a in X & b in X and A4: a in Y & b in Y and A5: X<>Y and A6: a<>b; set Z = X /\ Y; set Q = Line(a,b); A7: Q c= X by A1,A3,A6,Th19; A8: Q c= Y by A2,A4,A6,Th19; A9: Q is being_line by A6,AFF_1:def 3; A10: Z c= Q proof assume not Z c= Q; then consider x being object such that A11: x in Z and A12: not x in Q; reconsider a9=x as Element of AS by A11; A13: x in Y by A11,XBOOLE_0:def 4; A14: x in X by A11,XBOOLE_0:def 4; for y being object holds y in X iff y in Y proof let y be object; A15: now assume A16: y in Y; now reconsider b9=y as Element of AS by A16; set M = Line(a9,b9); A17: a9 in M by AFF_1:15; A18: b9 in M by AFF_1:15; assume A19: y<>x; then A20: M is being_line by AFF_1:def 3; A21: M c= Y by A2,A13,A16,A19,Th19; A22: now assume not M // Q; then consider q such that A23: q in M and A24: q in Q by A2,A9,A8,A20,A21,Th22; M = Line(a9,q) by A12,A20,A17,A23,A24,AFF_1:57; then M c= X by A1,A7,A12,A14,A24,Th19; hence y in X by A18; end; now assume M // Q; then M c= X by A1,A7,A14,A17,Th23; hence y in X by A18; end; hence y in X by A22; end; hence y in X by A11,XBOOLE_0:def 4; end; now assume A25: y in X; now reconsider b9=y as Element of AS by A25; set M = Line(a9,b9); A26: a9 in M by AFF_1:15; A27: b9 in M by AFF_1:15; assume A28: y<>x; then A29: M is being_line by AFF_1:def 3; A30: M c= X by A1,A14,A25,A28,Th19; A31: now assume not M // Q; then consider q such that A32: q in M and A33: q in Q by A1,A9,A7,A29,A30,Th22; M = Line(a9,q) by A12,A29,A26,A32,A33,AFF_1:57; then M c= Y by A2,A8,A12,A13,A33,Th19; hence y in Y by A27; end; now assume M // Q; then M c= Y by A2,A8,A13,A26,Th23; hence y in Y by A27; end; hence y in Y by A31; end; hence y in Y by A11,XBOOLE_0:def 4; end; hence thesis by A15; end; hence contradiction by A5,TARSKI:2; end; Q c= Z by A7,A8,XBOOLE_1:19; hence thesis by A9,A10,XBOOLE_0:def 10; end; theorem Th25: X is being_plane & Y is being_plane & a in X & b in X & c in X & a in Y & b in Y & c in Y & not LIN a,b,c implies X = Y proof assume that A1: X is being_plane & Y is being_plane and A2: a in X & b in X and A3: c in X and A4: a in Y & b in Y and A5: c in Y and A6: not LIN a,b,c; assume A7: not thesis; a<>b by A6,AFF_1:7; then A8: X /\ Y is being_line by A1,A2,A4,A7,Th24; A9: c in X /\ Y by A3,A5,XBOOLE_0:def 4; a in X /\ Y & b in X /\ Y by A2,A4,XBOOLE_0:def 4; hence contradiction by A6,A8,A9,AFF_1:21; end; Lm7: M is being_line & a in M & b in M & a<>b & not c in M implies not LIN a,b ,c proof assume A1: M is being_line & a in M & b in M & a<>b & not c in M; assume not thesis; then ex N st N is being_line & a in N & b in N & c in N by AFF_1:21; hence contradiction by A1,AFF_1:18; end; theorem Th26: X is being_plane & Y is being_plane & M is being_line & N is being_line & M c= X & N c= X & M c= Y & N c= Y & M<>N implies X = Y proof assume that A1: X is being_plane and A2: Y is being_plane and A3: M is being_line and A4: N is being_line and A5: M c= X & N c= X and A6: M c= Y & N c= Y and A7: M<>N; consider a,b such that A8: a in M and A9: b in M and A10: a<>b by A3,AFF_1:19; A11: now given q such that A12: q in M and A13: q in N; consider p such that A14: q<>p and A15: p in N by A4,AFF_1:20; A16: not p in M by A3,A4,A7,A12,A13,A14,A15,AFF_1:18; A17: now assume b<>q; then not LIN b,q,p by A3,A9,A12,A16,Lm7; hence thesis by A1,A2,A5,A6,A9,A12,A15,Th25; end; now assume a<>q; then not LIN a,q,p by A3,A8,A12,A16,Lm7; hence thesis by A1,A2,A5,A6,A8,A12,A15,Th25; end; hence thesis by A10,A17; end; consider c,d such that A18: c in N and d in N and c <>d by A4,AFF_1:19; now assume M // N; then not c in M by A7,A18,AFF_1:45; then not LIN a,b,c by A3,A8,A9,A10,Lm7; hence thesis by A1,A2,A5,A6,A8,A9,A18,Th25; end; hence thesis by A1,A3,A4,A5,A11,Th22; end; definition let AS,a,K such that A1: K is being_line; func a*K -> Subset of AS means :Def3: a in it & K // it; existence by A1,AFF_1:49; uniqueness by AFF_1:50; end; theorem Th27: A is being_line implies a*A is being_line proof set M = a*A; assume A is being_line; then A // M by Def3; hence thesis by AFF_1:36; end; theorem Th28: X is being_plane & M is being_line & a in X & M c= X implies a*M c= X proof assume that A1: X is being_plane and A2: M is being_line and A3: a in X & M c= X; set N = a*M; a in N & M // N by A2,Def3; hence thesis by A1,A3,Th23; end; theorem Th29: X is being_plane & a in X & b in X & c in X & a,b // c,d & a<>b implies d in X proof assume that A1: X is being_plane & a in X & b in X & c in X and A2: a,b // c,d and A3: a<>b; set M=Line(a,b), N=c*M; A4: M is being_line by A3,AFF_1:def 3; then A5: N c= X by A1,A3,Th19,Th28; A6: a in M & b in M by AFF_1:15; c in N & M // N by A4,Def3; then d in N by A2,A3,A6,Th7; hence thesis by A5; end; theorem A is being_line implies ( a in A iff a*A = A ) proof assume A1: A is being_line; now assume A2: a in A; A // A by A1,AFF_1:41; hence a*A = A by A1,A2,Def3; end; hence thesis by A1,Def3; end; theorem Th31: A is being_line implies a*A = a*(q*A) proof assume A1: A is being_line; then A // q*A & A // a*A by Def3; then A2: a*A // q*A by AFF_1:44; A3: q*A is being_line by A1,Th27; then A4: a in a*(q*A) by Def3; q*A // a*(q*A) by A3,Def3; then A5: a*A // a*(q*A) by A2,AFF_1:44; a in a*A by A1,Def3; hence thesis by A4,A5,AFF_1:45; end; Lm8: A is being_line & a in A implies a*A=A proof assume that A1: A is being_line and A2: a in A; A // A by A1,AFF_1:41; hence thesis by A1,A2,Def3; end; theorem Th32: K // M implies a*K=a*M proof assume A1: K // M; then A2: K is being_line by AFF_1:36; then K // a*K by Def3; then A3: a*K // M by A1,AFF_1:44; A4: M is being_line by A1,AFF_1:36; then A5: a in a*M by Def3; M // a*M by A4,Def3; then A6: a*K // a*M by A3,AFF_1:44; a in a*K by A2,Def3; hence thesis by A5,A6,AFF_1:45; end; definition let AS,X,Y; pred X '||' Y means for a,A st a in Y & A is being_line & A c= X holds a*A c= Y; end; theorem Th33: X c= Y & ( X is being_line & Y is being_line or X is being_plane & Y is being_plane ) implies X=Y proof assume that A1: X c= Y and A2: X is being_line & Y is being_line or X is being_plane & Y is being_plane; A3: now assume that A4: X is being_plane and A5: Y is being_plane; consider K,P such that A6: K is being_line and A7: P is being_line and A8: not K // P and A9: X=Plane(K,P) by A4; consider a,b such that A10: a in P and b in P and a<>b by A7,AFF_1:19; set M=a*K; A11: K // M by A6,Def3; A12: P c= X by A6,A9,Th14; then A13: P c= Y by A1; A14: M is being_line by A6,Th27; a in M & P c= Plane(K,P) by A6,Def3,Th14; then A15: M c= X by A9,A10,A11,Lm4; then M c= Y by A1; hence thesis by A4,A5,A7,A8,A11,A14,A12,A13,A15,Th26; end; now assume that A16: X is being_line and A17: Y is being_line; consider a,b such that A18: a<>b and A19: X=Line(a,b) by A16,AFF_1:def 3; a in X & b in X by A19,AFF_1:15; hence thesis by A1,A17,A18,A19,AFF_1:57; end; hence thesis by A2,A3; end; theorem Th34: X is being_plane implies ex a,b,c st a in X & b in X & c in X & not LIN a,b,c proof assume X is being_plane; then consider K,P such that A1: K is being_line and A2: P is being_line and A3: not K // P and A4: X = Plane(K,P); consider a,b such that A5: a in P and A6: b in P and A7: a<>b by A2,AFF_1:19; set Q = a*K; consider c such that A8: a<>c and A9: c in Q by A1,Th27,AFF_1:20; take a,b,c; A10: P c= Plane(K,P) by A1,Th14; hence a in X & b in X by A4,A5,A6; A11: K // Q & a in Q by A1,Def3; then Q c= Plane(K,P) by A5,A10,Lm4; hence c in X by A4,A9; A12: Q is being_line by A1,Th27; thus not LIN a,b,c proof assume LIN a,b,c; then c in P by A2,A5,A6,A7,AFF_1:25; hence contradiction by A2,A3,A5,A11,A12,A8,A9,AFF_1:18; end; end; Lm9: X is being_plane implies ex b,c st b in X & c in X & not LIN a,b,c proof assume X is being_plane; then consider p,q,r such that A1: p in X & q in X and A2: r in X and A3: not LIN p,q,r by Th34; now assume A4: LIN a,r,p & LIN a,r,q; take b=p,c =q; thus b in X & c in X by A1; LIN a,r,r by AFF_1:7; then a=r by A3,A4,AFF_1:8; hence not LIN a,b,c by A3,AFF_1:6; end; hence thesis by A1,A2; end; theorem M is being_line & X is being_plane implies ex q st q in X & not q in M proof assume that A1: M is being_line and A2: X is being_plane; consider a,b,c such that A3: a in X & b in X and A4: c in X and A5: not LIN a,b,c by A2,Th34; assume A6: not ex q st q in X & not q in M; then A7: c in M by A4; a in M & b in M by A6,A3; hence contradiction by A1,A5,A7,AFF_1:21; end; theorem Th36: for a,A st A is being_line ex X st a in X & A c= X & X is being_plane proof let a,A; assume A1: A is being_line; then consider p,q such that A2: p in A and q in A and p<>q by AFF_1:19; A3: now consider b such that A4: not b in A by A1,Th12; consider P such that A5: a in P & b in P and A6: P is being_line by Th11; set X=Plane(P,A); A7: A c= X by A6,Th14; assume A8: a in A; then not P // A by A4,A5,AFF_1:45; then X is being_plane by A1,A6; hence thesis by A8,A7; end; now consider P such that A9: a in P and A10: p in P and A11: P is being_line by Th11; set X=Plane(P,A); A c= X by A11,Th14; then A12: P c= X by A2,A10,A11,Lm4,AFF_1:41; assume not a in A; then not P // A by A2,A9,A10,AFF_1:45; then X is being_plane by A1,A11; hence thesis by A9,A11,A12,Th14; end; hence thesis by A3; end; theorem Th37: ex X st a in X & b in X & c in X & X is being_plane proof consider A such that A1: a in A & b in A and A2: A is being_line by Th11; ex X st c in X & A c= X & X is being_plane by A2,Th36; hence thesis by A1; end; theorem Th38: q in M & q in N & M is being_line & N is being_line implies ex X st M c= X & N c= X & X is being_plane proof assume that A1: q in M and A2: q in N and A3: M is being_line and A4: N is being_line; consider a such that A5: a<>q and A6: a in N by A4,AFF_1:20; A7: ex X st a in X & M c= X & X is being_plane by A3,Th36; N=Line(q,a) by A2,A4,A5,A6,AFF_1:24; hence thesis by A1,A5,A7,Th19; end; theorem Th39: M // N implies ex X st M c= X & N c= X & X is being_plane proof assume A1: M // N; then N is being_line by AFF_1:36; then consider a,b such that A2: a in N and b in N and a<>b by AFF_1:19; A3: M is being_line by A1,AFF_1:36; then A4: ex X st a in X & M c= X & X is being_plane by Th36; N=a*M by A1,A3,A2,Def3; hence thesis by A3,A4,Th28; end; theorem M is being_line & N is being_line implies (M // N iff M '||' N) proof assume that A1: M is being_line and A2: N is being_line; A3: now assume A4: M // N; now let a,A; assume that A5: a in N and A6: A is being_line & A c= M; N=a*M by A1,A4,A5,Def3; hence a*A c= N by A1,A6,Th33; end; hence M '||' N; end; now consider a,b such that A7: a in N and b in N and a<>b by A2,AFF_1:19; A8: a*M is being_line by A1,Th27; assume M '||' N; then a*M c= N by A1,A7; then a*M=N by A2,A8,Th33; hence M // N by A1,Def3; end; hence thesis by A3; end; theorem Th41: M is being_line & X is being_plane implies (M '||' X iff ex N st N c= X & (M // N or N // M) ) proof assume that A1: M is being_line and A2: X is being_plane; A3: now given N such that A4: N c= X and A5: M // N or N // M; now let a,A; assume that A6: a in X and A7: A is being_line and A8: A c= M; A=M by A1,A7,A8,Th33; then M // a*A by A7,Def3; then A9: N // a*A by A5,AFF_1:44; a in a*A by A7,Def3; hence a*A c= X by A2,A4,A6,A9,Th23; end; hence M '||' X; end; now consider a,b,c such that A10: a in X and b in X and c in X and not LIN a,b,c by A2,Th34; assume A11: M '||' X; take N=a*M; thus N c= X by A1,A11,A10; thus M // N or N // M by A1,Def3; end; hence thesis by A3; end; theorem M is being_line & X is being_plane & M c= X implies M '||' X proof assume that A1: M is being_line and A2: X is being_plane & M c= X; M // M by A1,AFF_1:41; hence thesis by A1,A2,Th41; end; theorem A is being_line & X is being_plane & a in A & a in X & A '||' X implies A c= X proof assume that A1: A is being_line and A2: X is being_plane and A3: a in A and A4: a in X and A5: A '||' X; consider N such that A6: N c= X and A7: A // N or N // A by A1,A2,A5,Th41; A8: N is being_line by A7,AFF_1:36; A=a*A by A1,A3,Lm8 .= a*N by A7,Th32; hence thesis by A2,A4,A6,A8,Th28; end; definition let AS,K,M,N; pred K,M,N is_coplanar means ex X st K c= X & M c= X & N c= X & X is being_plane; end; theorem K,M,N is_coplanar implies K,N,M is_coplanar & M,K,N is_coplanar & M,N,K is_coplanar & N,K,M is_coplanar & N,M,K is_coplanar; theorem M is being_line & N is being_line & M,N,K is_coplanar & M,N,A is_coplanar & M<>N implies M,K,A is_coplanar proof assume that A1: M is being_line & N is being_line and A2: M,N,K is_coplanar and A3: M,N,A is_coplanar and A4: M<>N; consider X such that A5: M c= X and A6: N c= X and A7: K c= X and A8: X is being_plane by A2; ex Y st M c= Y & N c= Y & A c= Y & Y is being_plane by A3; then A c= X by A1,A4,A5,A6,A8,Th26; hence thesis by A5,A7,A8; end; theorem Th46: K is being_line & M is being_line & X is being_plane & K c= X & M c= X & K<>M implies (K,M,A is_coplanar iff A c= X) by Th26; theorem Th47: q in K & q in M & K is being_line & M is being_line implies K,M, M is_coplanar & M,K,M is_coplanar & M,M,K is_coplanar proof assume q in K & q in M & K is being_line & M is being_line; then ex X st K c= X & M c= X & X is being_plane by Th38; hence thesis; end; theorem Th48: AS is not AffinPlane & X is being_plane implies ex q st not q in X proof assume that A1: AS is not AffinPlane and A2: X is being_plane; assume A3: not ex q st not q in X; for a,b,c,d st not a,b // c,d ex q st a,b // a,q & c,d // c,q proof let a,b,c,d; set M=Line(a,b),N=Line(c,d); A4: a in M & b in M by AFF_1:15; A5: c in N & d in N by AFF_1:15; assume A6: not a,b // c,d; then A7: a<>b by AFF_1:3; then A8: M is being_line by AFF_1:def 3; A9: c <>d by A6,AFF_1:3; then A10: N is being_line by AFF_1:def 3; c in X & d in X by A3; then A11: N c= X by A2,A9,Th19; a in X & b in X by A3; then M c= X by A2,A7,Th19; then consider q such that A12: q in M and A13: q in N by A2,A6,A11,A8,A10,A4,A5,Th22,AFF_1:39; LIN c,d,q by A10,A5,A13,AFF_1:21; then A14: c,d // c, q by AFF_1:def 1; LIN a,b,q by A8,A4,A12,AFF_1:21; then a,b // a,q by AFF_1:def 1; hence thesis by A14; end; hence contradiction by A1,DIRAF:def 7; end; Lm10: q in A & q in P & q in C & not A,P,C is_coplanar & q<>a & q<>b & q<>c & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A<>P & A<>C & a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 proof assume that A1: q in A and A2: q in P and A3: q in C and A4: not A,P,C is_coplanar and A5: q<>a and A6: q<>b and A7: q<>c and A8: a in A and A9: a9 in A and A10: b in P and A11: b9 in P and A12: c in C and A13: c9 in C and A14: A is being_line and A15: P is being_line and A16: C is being_line and A17: A<>P and A18: A<>C and A19: a,b // a9,b9 and A20: a,c // a9,c9; A21: c <>a by A1,A3,A5,A8,A12,A14,A16,A18,AFF_1:18; A22: P<>C by A1,A2,A4,A14,A15,Th47; then A23: b<>c by A2,A3,A6,A10,A12,A15,A16,AFF_1:18; consider X such that A24: P c= X & C c= X and A25: X is being_plane by A2,A3,A15,A16,Th38; consider Y such that A26: A c= Y and A27: C c= Y and A28: Y is being_plane by A1,A3,A14,A16,Th38; A29: a<>b by A1,A2,A5,A8,A10,A14,A15,A17,AFF_1:18; A30: now assume A31: q<>a9; then A32: q<>c9 by A1,A3,A5,A7,A8,A9,A12,A14,A16,A18,A20,Th8; A33: now set BC=Line(b,c),BC9=Line(b9,c9),AB=Line(a,b),AB9=Line(a9,b9), AC=Line(a ,c),AC9=Line(a9,c9); assume A34: a<>a9; assume A35: not b,c // b9,c9; A36: b9 in BC9 & c9 in BC9 by AFF_1:15; A37: BC c= X by A10,A12,A24,A25,A23,Th19; A38: c in BC by AFF_1:15; A39: BC is being_line & b in BC by A23,AFF_1:15,def 3; A40: c9<>b9 by A2,A3,A11,A13,A15,A16,A22,A32,AFF_1:18; then A41: BC9 is being_line by AFF_1:def 3; BC9 c= X by A11,A13,A24,A25,A40,Th19; then consider p such that A42: p in BC and A43: p in BC9 by A25,A35,A41,A39,A38,A36,A37,Th22,AFF_1:39; A44: a9 in AC9 by AFF_1:15; LIN c9,b9,p by A41,A36,A43,AFF_1:21; then consider y such that A45: LIN c9,a9,y and A46: b9,a9 // p,y by A40,Th1; A47: c in AC by AFF_1:15; LIN c,b,p by A39,A38,A42,AFF_1:21; then consider x such that A48: LIN c,a,x and A49: b,a // p,x by A23,Th1; A50: a in AB by AFF_1:15; A51: AC is being_line & a in AC by A21,AFF_1:15,def 3; then A52: x in AC by A21,A47,A48,AFF_1:25; set K = p*AB; A53: b in AB by AFF_1:15; A54: AB is being_line by A29,AFF_1:def 3; then A55: AB // K by Def3; A56: p in K by A54,Def3; p,x // a,b by A49,AFF_1:4; then p,x // AB by A29,AFF_1:def 4; then p,x // K by A55,Th3; then A57: x in K by A56,Th2; A58: a9<>b9 by A1,A2,A9,A11,A14,A15,A17,A31,AFF_1:18; p,y // a9,b9 by A46,AFF_1:4; then A59: p,y // AB9 by A58,AFF_1:def 4; AB // AB9 by A19,A29,A58,AFF_1:37; then AB9 // K by A55,AFF_1:44; then p,y // K by A59,Th3; then A60: y in K by A56,Th2; A61: AC c= Y by A8,A12,A26,A27,A28,A21,Th19; A62: c9 in AC9 by AFF_1:15; A63: a9<>c9 by A1,A3,A9,A13,A14,A16,A18,A31,AFF_1:18; then AC9 is being_line by AFF_1:def 3; then A64: y in AC9 by A63,A44,A62,A45,AFF_1:25; A65: AC9 c= Y by A9,A13,A26,A27,A28,A63,Th19; A66: now assume A67: x<>y; then K=Line(x,y) by A54,A57,A60,Th27,AFF_1:57; then K c= Y by A28,A61,A65,A52,A64,A67,Th19; then A68: AB c= Y by A8,A26,A28,A50,A55,Th23; P=Line(q,b) by A2,A6,A10,A15,AFF_1:57; then P c= Y by A1,A6,A26,A28,A53,A68,Th19; hence contradiction by A4,A26,A27,A28; end; A69: AC // AC9 by A20,A21,A63,AFF_1:37; now assume x=y; then a9 in AC by A44,A69,A52,A64,AFF_1:45; then c in A by A8,A9,A14,A34,A51,A47,AFF_1:18; hence contradiction by A1,A3,A7,A12,A14,A16,A18,AFF_1:18; end; hence contradiction by A66; end; now assume a=a9; then b=b9 & c =c9 by A1,A2,A3,A5,A6,A7,A8,A10,A11,A12,A13,A14,A15,A16,A17 ,A18,A19,A20,Th9; hence thesis by AFF_1:2; end; hence thesis by A33; end; now assume q=a9; then q=b9 & q=c9 by A1,A2,A3,A5,A6,A7,A8,A10,A11,A12,A13,A14,A15,A16,A17 ,A18,A19,A20,Th8; hence thesis by AFF_1:3; end; hence thesis by A30; end; theorem Th49: AS is not AffinPlane & q in A & q in P & q in C & q<>a & q<>b & q<>c & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A<>P & A<>C & a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 proof assume that A1: AS is not AffinPlane and A2: q in A and A3: q in P and A4: q in C and A5: q<>a and A6: q<>b and A7: q<>c and A8: a in A & a9 in A and A9: b in P & b9 in P and A10: c in C & c9 in C and A11: A is being_line and A12: P is being_line and A13: C is being_line and A14: A<>P and A15: A<>C and A16: a,b // a9,b9 and A17: a,c // a9,c9; now assume A,P,C is_coplanar; then consider X such that A18: A c= X and A19: P c= X and A20: C c= X and A21: X is being_plane; consider d such that A22: not d in X by A1,A21,Th48; LIN q,a,a9 by A2,A8,A11,AFF_1:21; then consider d9 such that A23: LIN q,d,d9 and A24: a,d // a9,d9 by A5,Th1; set K=Line(q,d); A25: d in K by AFF_1:15; then A26: not K c= X by A22; A27: q<>d by A2,A18,A22; then A28: q in K & K is being_line by AFF_1:15,def 3; then A29: d9 in K by A25,A27,A23,AFF_1:25; now assume A30: P<>C; A31: not K,P,C is_coplanar proof assume K,P,C is_coplanar; then P,C,K is_coplanar; hence contradiction by A12,A13,A19,A20,A21,A26,A30,Th46; end; A32: K<>A by A18,A22,A25; not A,K,P is_coplanar proof assume A,K,P is_coplanar; then A,P,K is_coplanar; hence contradiction by A11,A12,A14,A18,A19,A21,A26,Th46; end; then A33: d,b // d9,b9 by A2,A3,A5,A6,A8,A9,A11,A12,A14,A16,A25,A27,A28,A24,A29,A32 ,Lm10; A34: K<>P & K<>C by A19,A20,A22,A25; not A,K,C is_coplanar proof assume A,K,C is_coplanar; then A,C,K is_coplanar; hence contradiction by A11,A13,A15,A18,A20,A21,A26,Th46; end; then d,c // d9,c9 by A2,A4,A5,A7,A8,A10,A11,A13,A15,A17,A25,A27,A28,A24,A29 ,A32,Lm10; hence thesis by A3,A4,A6,A7,A9,A10,A12,A13,A25,A27,A28,A29,A34,A31,A33 ,Lm10; end; hence thesis by A9,A10,A12,AFF_1:51; end; hence thesis by A2,A3,A4,A5,A6,A7,A8,A9,A10,A11,A12,A13,A14,A15,A16,A17,Lm10; end; theorem AS is not AffinPlane implies AS is Desarguesian proof assume AS is not AffinPlane; then for A,P,C,q,a,b,c,a9,b9,c9 holds q in A & q in P & q in C & q<>a & q<>b & q<>c & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A<>P & A<>C & a,b // a9,b9 & a ,c // a9,c9 implies b,c // b9,c9 by Th49; hence thesis by AFF_2:def 4; end; Lm11: A // P & A // C & not A,P,C is_coplanar & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & A<>P & A<>C & a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 proof assume that A1: A // P and A2: A // C and A3: not A,P,C is_coplanar and A4: a in A and A5: a9 in A and A6: b in P and A7: b9 in P and A8: c in C and A9: c9 in C and A10: A is being_line and A11: A<>P and A12: A<>C and A13: a,b // a9,b9 and A14: a,c // a9,c9; A15: c <>a by A2,A4,A8,A12,AFF_1:45; A16: P // C by A1,A2,AFF_1:44; then consider X such that A17: P c= X & C c= X and A18: X is being_plane by Th39; consider Y such that A19: A c= Y and A20: C c= Y and A21: Y is being_plane by A2,Th39; A22: P<>C by A3,A19,A20,A21; then A23: b<>c by A6,A8,A16,AFF_1:45; A24: a<>b by A1,A4,A6,A11,AFF_1:45; A25: now set BC=Line(b,c),BC9=Line(b9,c9),AB=Line(a,b),AB9=Line(a9,b9), AC=Line(a,c ),AC9=Line(a9,c9); assume A26: a<>a9; assume A27: not b,c // b9,c9; A28: b9 in BC9 & c9 in BC9 by AFF_1:15; A29: BC c= X by A6,A8,A17,A18,A23,Th19; A30: c in BC by AFF_1:15; A31: BC is being_line & b in BC by A23,AFF_1:15,def 3; A32: c9<>b9 by A7,A9,A16,A22,AFF_1:45; then A33: BC9 is being_line by AFF_1:def 3; BC9 c= X by A7,A9,A17,A18,A32,Th19; then consider p such that A34: p in BC and A35: p in BC9 by A18,A27,A33,A31,A30,A28,A29,Th22,AFF_1:39; A36: a9 in AC9 by AFF_1:15; LIN c9,b9,p by A33,A28,A35,AFF_1:21; then consider y such that A37: LIN c9,a9,y and A38: b9,a9 // p,y by A32,Th1; A39: c in AC by AFF_1:15; LIN c,b,p by A31,A30,A34,AFF_1:21; then consider x such that A40: LIN c,a,x and A41: b,a // p,x by A23,Th1; A42: a in AB by AFF_1:15; A43: AC is being_line & a in AC by A15,AFF_1:15,def 3; then A44: x in AC by A15,A39,A40,AFF_1:25; set K = p*AB; A45: b in AB by AFF_1:15; A46: AB is being_line by A24,AFF_1:def 3; then A47: AB // K by Def3; A48: p in K by A46,Def3; p,x // a,b by A41,AFF_1:4; then p,x // AB by A24,AFF_1:def 4; then p,x // K by A47,Th3; then A49: x in K by A48,Th2; A50: a9<>b9 by A1,A5,A7,A11,AFF_1:45; p,y // a9,b9 by A38,AFF_1:4; then A51: p,y // AB9 by A50,AFF_1:def 4; AB // AB9 by A13,A24,A50,AFF_1:37; then AB9 // K by A47,AFF_1:44; then p,y // K by A51,Th3; then A52: y in K by A48,Th2; A53: AC c= Y by A4,A8,A19,A20,A21,A15,Th19; A54: c9 in AC9 by AFF_1:15; A55: a9<>c9 by A2,A5,A9,A12,AFF_1:45; then AC9 is being_line by AFF_1:def 3; then A56: y in AC9 by A55,A36,A54,A37,AFF_1:25; A57: AC9 c= Y by A5,A9,A19,A20,A21,A55,Th19; A58: now assume A59: x<>y; then K=Line(x,y) by A46,A49,A52,Th27,AFF_1:57; then K c= Y by A21,A53,A57,A44,A56,A59,Th19; then A60: AB c= Y by A4,A19,A21,A42,A47,Th23; P=b*A by A1,A6,A10,Def3; then P c= Y by A10,A19,A21,A45,A60,Th28; hence contradiction by A3,A19,A20,A21; end; A61: AC // AC9 by A14,A15,A55,AFF_1:37; now assume x=y; then a9 in AC by A36,A61,A44,A56,AFF_1:45; then c in A by A4,A5,A10,A26,A43,A39,AFF_1:18; hence contradiction by A2,A8,A12,AFF_1:45; end; hence contradiction by A58; end; now assume a=a9; then b=b9 & c =c9 by A1,A2,A4,A6,A7,A8,A9,A11,A12,A13,A14,Th10; hence thesis by AFF_1:2; end; hence thesis by A25; end; theorem Th51: AS is not AffinPlane & A // P & A // C & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A<>P & A<>C & a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 proof assume that A1: AS is not AffinPlane and A2: A // P and A3: A // C and A4: a in A & a9 in A and A5: b in P & b9 in P and A6: c in C & c9 in C and A7: A is being_line and A8: P is being_line and A9: C is being_line and A10: A<>P and A11: A<>C and A12: a,b // a9,b9 and A13: a,c // a9,c9; now assume A,P,C is_coplanar; then consider X such that A14: A c= X and A15: P c= X and A16: C c= X and A17: X is being_plane; consider d such that A18: not d in X by A1,A17,Th48; set K=d*A; A19: d in K by A7,Def3; then A20: not K c= X by A18; A21: A // K by A7,Def3; ex d9 st d9 in K & a,d // a9,d9 proof A22: now assume A23: a<>a9; consider d9 such that A24: a,a9 // d,d9 and A25: a,d // a9,d9 by DIRAF:40; d,d9 // a,a9 by A24,AFF_1:4; then d,d9 // A by A4,A7,A23,AFF_1:27; then d,d9 // K by A21,Th3; then d9 in K by A19,Th2; hence thesis by A25; end; now assume A26: a=a9; take d9=d; thus d9 in K by A7,Def3; thus a,d // a9,d9 by A26,AFF_1:2; end; hence thesis by A22; end; then consider d9 such that A27: d9 in K and A28: a,d // a9,d9; A29: K // P & K // C by A2,A3,A21,AFF_1:44; now assume A30: P<>C; A31: not K,P,C is_coplanar proof assume K,P,C is_coplanar; then P,C,K is_coplanar; hence contradiction by A8,A9,A15,A16,A17,A20,A30,Th46; end; A32: K<>A by A14,A18,A19; not A,K,P is_coplanar proof assume A,K,P is_coplanar; then A,P,K is_coplanar; hence contradiction by A7,A8,A10,A14,A15,A17,A20,Th46; end; then A33: d,b // d9,b9 by A2,A4,A5,A7,A10,A12,A19,A21,A27,A28,A32,Lm11; A34: K<>P & K<>C by A15,A16,A18,A19; not A,K,C is_coplanar proof assume A,K,C is_coplanar; then A,C,K is_coplanar; hence contradiction by A7,A9,A11,A14,A16,A17,A20,Th46; end; then d,c // d9,c9 by A3,A4,A6,A7,A11,A13,A19,A21,A27,A28,A32,Lm11; hence thesis by A5,A6,A7,A19,A29,A27,A34,A31,A33,Lm11,Th27; end; hence thesis by A5,A6,A8,AFF_1:51; end; hence thesis by A2,A3,A4,A5,A6,A7,A10,A11,A12,A13,Lm11; end; theorem AS is not AffinPlane implies AS is translational proof assume AS is not AffinPlane; then for A,P,C,a,b,c,a9,b9,c9 holds A // P & A // C & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A<>P & A<>C & a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 by Th51; hence thesis by AFF_2:def 11; end; theorem Th53: AS is AffinPlane & not LIN a,b,c implies ex c9 st a,c // a9,c9 & b,c // b9,c9 proof assume that A1: AS is AffinPlane and A2: not LIN a,b,c; consider C such that A3: b in C & c in C and A4: C is being_line by Th11; consider N such that A5: b9 in N and A6: C // N by A4,AFF_1:49; A7: N is being_line by A6,AFF_1:36; consider P such that A8: a in P and A9: c in P and A10: P is being_line by Th11; consider M such that A11: a9 in M and A12: P // M by A10,AFF_1:49; A13: not M // N proof assume M // N; then N // P by A12,AFF_1:44; then C // P by A6,AFF_1:44; then b in P by A3,A9,AFF_1:45; hence contradiction by A2,A8,A9,A10,AFF_1:21; end; M is being_line by A12,AFF_1:36; then consider c9 such that A14: c9 in M and A15: c9 in N by A1,A7,A13,AFF_1:58; A16: b,c // b9,c9 by A3,A5,A6,A15,AFF_1:39; a,c // a9,c9 by A8,A9,A11,A12,A14,AFF_1:39; hence thesis by A16; end; Lm12: not LIN a,b,c & a,b // a9,b9 & a in X & b in X & c in X & X is being_plane & a9 in X implies ex c9 st a,c // a9,c9 & b,c // b9,c9 proof assume that A1: not LIN a,b,c and A2: a,b // a9,b9 and A3: a in X and A4: b in X and A5: c in X and A6: X is being_plane and A7: a9 in X; set C=Line(b,c),P=Line(a,c),P9=a9*P,C9=b9*C; A8: b<>c by A1,AFF_1:7; then A9: C is being_line by AFF_1:def 3; then A10: C // C9 by Def3; a<>b by A1,AFF_1:7; then b9 in X by A2,A3,A4,A6,A7,Th29; then A11: C9 c= X by A4,A5,A6,A8,A9,Th19,Th28; A12: c in P by AFF_1:15; A13: C9 is being_line by A9,Th27; A14: a in P by AFF_1:15; A15: c <>a by A1,AFF_1:7; then A16: P is being_line by AFF_1:def 3; then A17: P9 is being_line by Th27; A18: b in C & c in C by AFF_1:15; A19: P // P9 by A16,Def3; A20: not C9 // P9 proof assume C9 // P9; then C9 // P by A19,AFF_1:44; then C // P by A10,AFF_1:44; then b in P by A12,A18,AFF_1:45; hence contradiction by A1,A14,A12,A16,AFF_1:21; end; P9 c= X by A3,A5,A6,A7,A15,A16,Th19,Th28; then consider c9 such that A21: c9 in C9 and A22: c9 in P9 by A6,A17,A13,A20,A11,Th22; b9 in C9 by A9,Def3; then A23: b,c // b9,c9 by A18,A10,A21,AFF_1:39; a9 in P9 by A16,Def3; then a,c // a9,c9 by A14,A12,A19,A22,AFF_1:39; hence thesis by A23; end; theorem Th54: not LIN a,b,c & a9<>b9 & a,b // a9,b9 implies ex c9 st a,c // a9 ,c9 & b,c // b9,c9 proof assume that A1: not LIN a,b,c and A2: a9<>b9 and A3: a,b // a9,b9; now consider X such that A4: a in X and A5: b in X and A6: c in X and A7: X is being_plane by Th37; assume A8: AS is not AffinPlane; now set A=Line(a,a9),P=Line(b,b9); set AB=Line(a,b),AB9=Line(a9,b9); A9: a in AB by AFF_1:15; assume A10: not a9 in X; then A11: A is being_line by A4,AFF_1:def 3; A12: a<>b by A1,AFF_1:7; then A13: AB c= X by A4,A5,A7,Th19; A14: AB // AB9 by A2,A3,A12,AFF_1:37; then consider Y such that A15: AB c= Y and A16: AB9 c= Y and A17: Y is being_plane by Th39; A18: b in AB by AFF_1:15; A19: a9 in AB9 by AFF_1:15; then A20: A c= Y by A4,A10,A9,A15,A16,A17,Th19; A21: b9 in AB9 by AFF_1:15; A22: not b9 in X proof assume b9 in X; then AB9 c= X by A7,A21,A14,A13,Th23; hence contradiction by A10,A19; end; then A23: P is being_line by A5,AFF_1:def 3; A24: b9 in P by AFF_1:15; A25: a in A by AFF_1:15; A26: a<>c by A1,AFF_1:7; A27: b in P by AFF_1:15; A28: a9 in A by AFF_1:15; A29: AB is being_line by A12,AFF_1:def 3; A30: A<>P proof assume A=P; then A=AB by A12,A9,A18,A29,A11,A25,A27,AFF_1:18; hence contradiction by A10,A13,A28; end; A31: now set C=c*A; assume A32: A // P; A33: c in C by A11,Def3; A34: A<>C proof assume A=C; then A=Line(a,c) by A26,A11,A25,A33,AFF_1:57; then A c= X by A4,A6,A7,A26,Th19; hence contradiction by A10,A28; end; A35: A // C by A11,Def3; then consider c9 such that A36: c9 in C and A37: a,c // a9,c9 by A25,A28,A33,Lm2; C is being_line by A11,Th27; then b,c // b9,c9 by A3,A8,A11,A23,A25,A28,A27,A24,A30,A32,A33,A35,A36 ,A37,A34,Th51; hence thesis by A37; end; A38: a9 in Y by A19,A16; A39: now given q such that A40: q in A and A41: q in P; A42: q<>a proof assume q=a; then AB=P by A12,A9,A18,A29,A23,A27,A41,AFF_1:18; hence contradiction by A13,A22,A24; end; A43: q<>b proof assume q=b; then AB=A by A12,A9,A18,A29,A11,A25,A40,AFF_1:18; hence contradiction by A10,A13,A28; end; set C=Line(q,c); A44: c in C by AFF_1:15; A45: A<>C proof assume A=C; then A=Line(a,c) by A26,A11,A25,A44,AFF_1:57; then A c= X by A4,A6,A7,A26,Th19; hence contradiction by A10,A28; end; LIN q,a,a9 by A11,A25,A28,A40,AFF_1:21; then consider c9 such that A46: LIN q,c,c9 and A47: a,c // a9,c9 by A42,Th1; A48: q<>c by A1,A4,A5,A6,A7,A10,A9,A18,A15,A17,A38,A20,A40,Th25; then A49: q in C & C is being_line by AFF_1:15,def 3; then c9 in C by A48,A44,A46,AFF_1:25; then b,c // b9,c9 by A3,A8,A11,A23,A25,A28,A27,A24,A30,A40,A41,A42,A43,A48 ,A44,A49,A47,A45,Th49; hence thesis by A47; end; P c= Y by A5,A18,A21,A22,A15,A16,A17,Th19; hence thesis by A17,A11,A23,A20,A31,A39,Th22; end; hence thesis by A1,A3,A4,A5,A6,A7,Lm12; end; hence thesis by A1,Th53; end; theorem Th55: X is being_plane & Y is being_plane implies (X '||' Y iff ex A,P ,M,N st not A // P & A c= X & P c= X & M c= Y & N c= Y & (A // M or M // A) & ( P // N or N // P) ) proof assume that A1: X is being_plane and A2: Y is being_plane; A3: now given A,P,M,N such that A4: not A // P and A5: A c= X and A6: P c= X and A7: M c= Y and A8: N c= Y and A9: A // M or M // A and A10: P // N or N // P; A11: M is being_line by A9,AFF_1:36; A12: not M // N proof assume M // N; then P // M by A10,AFF_1:44; hence contradiction by A4,A9,AFF_1:44; end; N is being_line by A10,AFF_1:36; then consider q such that A13: q in M and A14: q in N by A2,A7,A8,A11,A12,Th22; A15: A is being_line by A9,AFF_1:36; A16: P is being_line by A10,AFF_1:36; then consider p such that A17: p in A and A18: p in P by A1,A4,A5,A6,A15,Th22; now let a,Z; assume that A19: a in Y and A20: Z is being_line and A21: Z c= X; A22: a in a*Z by A20,Def3; A23: Z // a*Z by A20,Def3; A24: now assume Z // P; then Z // N by A10,AFF_1:44; then a*Z // N by A23,AFF_1:44; hence a*Z c= Y by A2,A8,A19,A22,Th23; end; A25: now assume that A26: not Z // A and A27: not Z // P; consider b such that A28: p<>b and A29: b in A by A15,AFF_1:20; set Z1= b*Z; A30: Z1 is being_line by A20,Th27; A31: not Z1 // P proof assume A32: Z1 // P; Z // b*Z by A20,Def3; hence contradiction by A27,A32,AFF_1:44; end; A33: Z // Z1 by A20,Def3; Z1 c= X by A1,A5,A20,A21,A29,Th28; then consider c such that A34: c in Z1 and A35: c in P by A1,A6,A16,A30,A31,Th22; A36: b in Z1 by A20,Def3; then A37: p<>c by A15,A17,A26,A28,A29,A30,A33,A34,AFF_1:18; A38: A<>P by A4,A15,AFF_1:41; A39: not LIN p,b,c proof assume LIN p,b,c; then c in A by A15,A17,A28,A29,AFF_1:25; hence contradiction by A15,A16,A17,A18,A35,A37,A38,AFF_1:18; end; then A40: b<>c by AFF_1:7; consider b9 such that A41: q<>b9 and A42: b9 in M by A11,AFF_1:20; p,b // q,b9 by A9,A17,A13,A29,A42,AFF_1:39; then consider c9 such that A43: p,c // q,c9 and A44: b,c // b9,c9 by A41,A39,Th54; set Z2=Line(b9,c9); A45: b9 in Z2 & c9 in Z2 by AFF_1:15; A46: b9<>c9 proof assume A47: b9=c9; q,b9 // M by A11,A13,A42,AFF_1:52; then p,c // M by A41,A43,A47,Th4; then p,c // A by A9,Th3; then c in A by A17,Th2; hence contradiction by A15,A16,A17,A18,A35,A37,A38,AFF_1:18; end; then Z2 is being_line by AFF_1:def 3; then Z1 // Z2 by A30,A36,A34,A44,A40,A46,A45,AFF_1:38; then Z // Z2 by A33,AFF_1:44; then A48: a*Z // Z2 by A23,AFF_1:44; c9 in N by A10,A18,A14,A35,A37,A43,Th7; then Z2 c= Y by A2,A7,A8,A42,A46,Th19; hence a*Z c= Y by A2,A19,A22,A48,Th23; end; now assume Z // A; then Z // M by A9,AFF_1:44; then a*Z // M by A23,AFF_1:44; hence a*Z c= Y by A2,A7,A19,A22,Th23; end; hence a*Z c= Y by A24,A25; end; hence X '||' Y; end; now consider a9,b9,c9 such that A49: a9 in Y and b9 in Y and c9 in Y and not LIN a9,b9,c9 by A2,Th34; assume A50: X '||' Y; consider a,b,c such that A51: a in X and A52: b in X and A53: c in X and A54: not LIN a,b,c by A1,Th34; set A=Line(a,b),P=Line(a,c); A55: b in A & c in P by AFF_1:15; A56: a<>c by A54,AFF_1:7; then A57: P c= X by A1,A51,A53,Th19; take A,P,M=a9*A,N=a9*P; A58: a in A by AFF_1:15; A59: a<>b by A54,AFF_1:7; then A60: A is being_line by AFF_1:def 3; A61: a in P by AFF_1:15; A62: not A // P proof assume A // P; then A=P by A58,A61,AFF_1:45; hence contradiction by A54,A58,A55,A60,AFF_1:21; end; A63: P is being_line by A56,AFF_1:def 3; A c= X by A1,A51,A52,A59,Th19; hence not A // P & A c= X & P c= X & M c= Y & N c= Y & (A // M or M // A) & (P // N or N // P) by A50,A60,A63,A49,A62,A57,Def3; end; hence thesis by A3; end; theorem A // M & M '||' X implies A '||' X proof assume that A1: A // M and A2: M '||' X; A3: M is being_line by A1,AFF_1:36; A4: A is being_line by A1,AFF_1:36; now consider q,p such that A5: q in A and p in A and q<>p by A4,AFF_1:19; let a,C; assume that A6: a in X and A7: C is being_line & C c= A; A8: a*A = a*(q*M) by A1,A3,A5,Def3 .= a*M by A3,Th31; C = A by A4,A7,Th33; hence a*C c= X by A2,A3,A6,A8; end; hence thesis; end; theorem Th57: X is being_plane implies X '||' X by Th28; theorem Th58: X is being_plane & Y is being_plane & X '||' Y implies Y '||' X proof assume that A1: X is being_plane & Y is being_plane and A2: X '||' Y; consider A,P,M,N such that A3: not A // P and A4: A c= X & P c= X & M c= Y & N c= Y and A5: A // M or M // A and A6: P // N or N // P by A1,A2,Th55; not M // N proof assume M // N; then A // N by A5,AFF_1:44; hence contradiction by A3,A6,AFF_1:44; end; hence thesis by A1,A4,A5,A6,Th55; end; theorem Th59: X is being_plane implies X <> {} proof assume X is being_plane; then ex a,b,c st a in X & b in X & c in X & not LIN a,b,c by Th34; hence thesis; end; theorem Th60: X '||' Y & Y '||' Z & Y <> {} implies X '||' Z proof assume that A1: X '||' Y and A2: Y '||' Z and A3: Y <> {}; set x = the Element of Y; reconsider p=x as Element of AS by A3,Lm1; now let a,A; assume that A4: a in Z and A5: A is being_line and A6: A c= X; p*A c= Y & p*A is being_line by A1,A3,A5,A6,Th27; then a*(p*A) c= Z by A2,A4; hence a*A c= Z by A5,Th31; end; hence thesis; end; theorem Th61: X is being_plane & Y is being_plane & Z is being_plane & ( X '||' Y & Y '||' Z or X '||' Y & Z '||' Y or Y '||' X & Y '||' Z or Y '||' X & Z '||' Y ) implies X '||' Z proof assume that A1: X is being_plane and A2: Y is being_plane and A3: Z is being_plane &( X '||' Y & Y '||' Z or X '||' Y & Z '||' Y or Y '||' X & Y '||' Z or Y '||' X & Z '||' Y); X '||' Y & Y '||' Z by A1,A2,A3,Th58; hence thesis by A2,Th59,Th60; end; Lm13: X is being_plane & Y is being_plane & X '||' Y & X<>Y implies not ex a st a in X & a in Y proof assume that A1: X is being_plane and A2: Y is being_plane and A3: X '||' Y and A4: X<>Y; assume not thesis; then consider a such that A5: a in X and A6: a in Y; consider b,c such that A7: b in X and A8: c in X and A9: not LIN a,b,c by A1,Lm9; set M=Line(a,b),N=Line(a,c); A10: a<>c by A9,AFF_1:7; then A11: N c= X by A1,A5,A8,Th19; A12: a<>b by A9,AFF_1:7; then A13: M is being_line by AFF_1:def 3; A14: M<>N proof assume M=N; then A15: c in M by AFF_1:15; a in M & b in M by AFF_1:15; hence contradiction by A9,A13,A15,AFF_1:21; end; A16: N is being_line by A10,AFF_1:def 3; then a in N & a*N c= Y by A3,A6,A11,AFF_1:15; then A17: N c= Y by A16,Lm8; A18: M c= X by A1,A5,A7,A12,Th19; then a in M & a*M c= Y by A3,A6,A13,AFF_1:15; then M c= Y by A13,Lm8; hence contradiction by A1,A2,A4,A13,A16,A18,A11,A17,A14,Th26; end; theorem X is being_plane & Y is being_plane & a in X & a in Y & X '||' Y implies X=Y by Lm13; theorem Th63: X is being_plane & Y is being_plane & Z is being_plane & X '||' Y & X<>Y & a in X /\ Z & b in X /\ Z & c in Y /\ Z & d in Y /\ Z implies a,b // c,d proof assume that A1: X is being_plane and A2: Y is being_plane and A3: Z is being_plane and A4: X '||' Y and A5: X<>Y and A6: a in X /\ Z and A7: b in X /\ Z and A8: c in Y /\ Z and A9: d in Y /\ Z; A10: c in Z by A8,XBOOLE_0:def 4; A11: a in X & a in Z by A6,XBOOLE_0:def 4; then A12: Z<>Y by A1,A2,A4,A5,Lm13; A13: c in Y by A8,XBOOLE_0:def 4; then A14: Z<>X by A1,A2,A4,A5,A10,Lm13; set A = X /\ Z, C = Y /\ Z; A15: b in X & b in Z by A7,XBOOLE_0:def 4; A16: d in Y & d in Z by A9,XBOOLE_0:def 4; now A17: C c= Y & C c= Z by XBOOLE_1:17; set K=c*A; assume that A18: a<>b and A19: c <>d; A20: A is being_line by A1,A3,A11,A15,A14,A18,Th24; then A21: A // K by Def3; A c= X by XBOOLE_1:17; then A22: K c= Y by A4,A13,A20; A23: K c= Z by A3,A10,A20,Th28,XBOOLE_1:17; C is being_line & K is being_line by A1,A2,A3,A11,A15,A13,A10,A16,A12,A14 ,A18,A19,Th24,Th27; then K=C by A2,A3,A12,A17,A23,A22,Th26; hence thesis by A6,A7,A8,A9,A21,AFF_1:39; end; hence thesis by AFF_1:3; end; theorem X is being_plane & Y is being_plane & Z is being_plane & X '||' Y & a in X /\ Z & b in X /\ Z & c in Y /\ Z & d in Y /\ Z & X<>Y & a<>b & c <>d implies X/\Z // Y/\Z proof assume that A1: X is being_plane and A2: Y is being_plane and A3: Z is being_plane and A4: X '||' Y and A5: a in X /\ Z and A6: b in X /\ Z and A7: c in Y /\ Z and A8: d in Y /\ Z and A9: X<>Y and A10: a<>b and A11: c <>d; A12: d in Y & d in Z by A8,XBOOLE_0:def 4; set A = X /\ Z, C = Y /\ Z; A13: c in Y & c in Z by A7,XBOOLE_0:def 4; A14: a in X & a in Z by A5,XBOOLE_0:def 4; then Z<>Y by A1,A2,A4,A9,Lm13; then A15: C is being_line by A2,A3,A11,A13,A12,Th24; A16: b in X & b in Z by A6,XBOOLE_0:def 4; Z<>X by A1,A2,A4,A9,A13,Lm13; then A17: A is being_line by A1,A3,A10,A14,A16,Th24; a,b // c,d by A1,A2,A3,A4,A5,A6,A7,A8,A9,Th63; hence thesis by A5,A6,A7,A8,A10,A11,A17,A15,AFF_1:38; end; theorem Th65: for a,X st X is being_plane ex Y st a in Y & X '||' Y & Y is being_plane proof let a,X; assume A1: X is being_plane; then consider p,q,r such that A2: p in X and A3: q in X and A4: r in X and A5: not LIN p,q,r by Th34; set M=Line(p,q),N=Line(p,r); A6: p<>r by A5,AFF_1:7; then A7: N c= X by A1,A2,A4,Th19; set M9=a*M,N9=a*N; A8: p<>q by A5,AFF_1:7; then A9: M is being_line by AFF_1:def 3; then A10: M9 is being_line by Th27; A11: p in N & r in N by AFF_1:15; A12: p in M by AFF_1:15; A13: q in M by AFF_1:15; A14: not M // N proof assume M // N; then r in M by A12,A11,AFF_1:45; hence contradiction by A5,A12,A13,A9,AFF_1:21; end; A15: N is being_line by A6,AFF_1:def 3; then A16: N // N9 by Def3; A17: M // M9 by A9,Def3; A18: a in M9 by A9,Def3; N9 is being_line & a in N9 by A15,Def3,Th27; then consider Y such that A19: M9 c= Y and A20: N9 c= Y and A21: Y is being_plane by A10,A18,Th38; M c= X by A1,A2,A3,A8,Th19; then X '||' Y by A1,A17,A16,A19,A20,A21,A7,A14,Th55; hence thesis by A18,A19,A21; end; definition let AS,a,X such that A1: X is being_plane; func a+X -> Subset of AS means :Def6: a in it & X '||' it & it is being_plane; existence by A1,Th65; uniqueness proof let Y1,Y2 be Subset of AS such that A2: a in Y1 and A3: X '||' Y1 and A4: Y1 is being_plane and A5: a in Y2 and A6: X '||' Y2 and A7: Y2 is being_plane; Y1 '||' Y2 by A1,A3,A4,A6,A7,Th61; hence thesis by A2,A4,A5,A7,Lm13; end; end; theorem X is being_plane implies ( a in X iff a+X = X ) proof assume A1: X is being_plane; now assume A2: a in X; X '||' X by A1,Th57; hence a+X = X by A1,A2,Def6; end; hence thesis by A1,Def6; end; theorem X is being_plane implies a+X = a+(q+X) proof assume A1: X is being_plane; then A2: a in a+X by Def6; A3: a+X is being_plane by A1,Def6; A4: q+X is being_plane by A1,Def6; then A5: q+X '||' a+(q+X) by Def6; A6: a in a+(q+X) by A4,Def6; A7: a+(q+X) is being_plane by A4,Def6; X '||' q+X & X '||' a+X by A1,Def6; then a+X '||' q+X by A1,A4,A3,Th61; then a+X '||' a+(q+X) by A4,A5,A3,A7,Th61; hence thesis by A2,A6,A3,A7,Lm13; end; theorem A is being_line & X is being_plane & A '||' X implies a*A c= a+X proof assume that A1: A is being_line and A2: X is being_plane and A3: A '||' X; A4: X '||' a+X & a in a+ X by A2,Def6; consider N such that A5: N c= X and A6: A // N or N // A by A1,A2,A3,Th41; a*A = a*N & N is being_line by A6,Th32,AFF_1:36; hence thesis by A5,A4; end; theorem X is being_plane & Y is being_plane & X '||' Y implies a+X = a+Y proof assume that A1: X is being_plane and A2: Y is being_plane and A3: X '||' Y; A4: a+X is being_plane by A1,Def6; A5: a in a+X & a in a+Y by A1,A2,Def6; A6: a+Y is being_plane by A2,Def6; X '||' a+X by A1,Def6; then A7: a+X '||' Y by A1,A2,A3,A4,Th61; Y '||' a+Y by A2,Def6; then a+X '||' a+Y by A2,A4,A6,A7,Th61; hence thesis by A5,A4,A6,Lm13; end;