(* Author: Joshua Schneider, ETH Zurich *) section \Regression tests for applicative lifting\ theory Applicative_Test imports Stream_Algebra Applicative_Environment Applicative_List Applicative_Option Applicative_Set Applicative_Sum Abstract_AF begin unbundle applicative_syntax subsection \Normal form conversion\ notepad begin have "\x. x = af_pure (\x. x) \ x" by applicative_nf rule have "\x. af_pure x = af_pure x" by applicative_nf rule have "\f x. af_pure f \ x = af_pure f \ x" by applicative_nf rule have "\f x y. af_pure f \ x \ y = af_pure f \ x \ y" by applicative_nf rule have "\g f x. af_pure g \ (f \ x) = af_pure (\f x. g (f x)) \ f \ x" by applicative_nf rule have "\f x y. f \ x \ y = af_pure (\f x y. f x y) \ f \ x \ y" by applicative_nf rule have "\g f x. g \ (f \ x) = af_pure (\g f x. g (f x)) \ g \ f \ x" by applicative_nf rule have "\f x. f \ af_pure x = af_pure (\f. f x) \ f" by applicative_nf rule have "\x y. af_pure x \ af_pure y = af_pure (x y)" by applicative_nf rule have "\f x y. f \ x \ af_pure y = af_pure (\f x. f x y) \ f \ x" by applicative_nf rule have "\f x y. af_pure f \ x \ af_pure y = af_pure (\x. f x y) \ x" by applicative_nf rule have "\f x y z. af_pure f \ x \ af_pure y \ z = af_pure (\x z. f x y z) \ x \ z" by applicative_nf rule have "\f x g y. af_pure f \ x \ (af_pure g \ y) = af_pure (\x y. f x (g y)) \ x \ y" by applicative_nf rule have "\f g x y. f \ (g \ x) \ y = af_pure (\f g x y. f (g x) y) \ f \ g \ x \ y" by applicative_nf rule have "\f g x y z. f \ (g \ x \ y) \ z = af_pure (\f g x y z. f (g x y) z) \ f \ g \ x \ y \ z" by applicative_nf rule have "\f g x y z. f \ (g \ (x \ af_pure y)) \ z = af_pure (\f g x z. f (g (x y)) z) \ f \ g \ x \ z" by applicative_nf rule have "\f g x. f \ (g \ x \ x) = af_pure (\f g x x'. f (g x x')) \ f \ g \ x \ x" by applicative_nf rule have "\f x y. f x \ y = af_pure (\f x. f x) \ f x \ y" by applicative_nf rule next fix f :: "('a \ 'b) af" and g :: "('b \ 'c) af" and x have "g \ (f \ x) = af_pure (\g f x. g (f x)) \ g \ f \ x" by applicative_nf rule end (* TODO automatic test for names of new variables *) lemma "\f x::'a af. f \ x = x" apply applicative_nf oops subsection \Sets\ instantiation set :: (plus) plus begin definition set_plus_def[applicative_unfold]: "(X::('a::plus)set) + Y = {plus} \ X \ Y" instance .. end lemma "(X :: _ :: semigroup_add set) + Y + Z = X + (Y + Z)" by (fact add.assoc[applicative_lifted set]) instantiation set :: (semigroup_add) semigroup_add begin instance proof fix X Y Z :: "'a set" from add.assoc show "X + Y + Z = X + (Y + Z)" by applicative_lifting qed end instantiation set :: (ab_semigroup_add) ab_semigroup_add begin instance proof fix X Y :: "'a set" from add.commute show "X + Y = Y + X" by applicative_lifting qed end subsection \Sum type (a.k.a. either)\ lemma "Inl plus \ (x :: nat + 'e list) \ x = Inl (\x. 2 * x) \ x" by applicative_lifting simp lemma "rel_sum (\) (\) (x :: nat + nat) (Inl Suc \ x)" proof - interpret either_af "(\) :: nat \ _" by unfold_locales (rule reflpI, simp) show ?thesis by applicative_lifting simp qed subsection \Streams\ lemma "(x::int stream) * sconst 0 = sconst 0" by applicative_lifting simp lemma "(x::int stream) * (y + z) = x * y + x * z" by applicative_lifting algebra definition "lift_streams xs = foldr (smap2 Cons) xs (sconst [])" lemma lift_streams_Nil[applicative_unfold]: "lift_streams [] = sconst []" unfolding lift_streams_def by simp lemma lift_streams_Cons[applicative_unfold]: "lift_streams (x # xs) = smap2 Cons x (lift_streams xs)" unfolding lift_streams_def by applicative_unfold lemma stream_append_Cons: "smap2 append (smap2 Cons x ys) zs = smap2 Cons x (smap2 append ys zs)" by applicative_lifting simp lemma lift_streams_append[applicative_unfold]: "lift_streams (xs @ ys) = smap2 append (lift_streams xs) (lift_streams ys)" proof (induction xs) case Nil (* case could be proved directly if "lift_streams ([] @ ys) = lift_streams ys" is solved in head_cong_tac (invoke simplifier?) -- but only with applicative_nf *) have "lift_streams ys = sconst append \ lift_streams [] \ lift_streams ys" by applicative_lifting simp thus ?case by applicative_unfold next case (Cons x xs) with stream_append_Cons (* the actual lifted fact *) show ?case by applicative_unfold (rule sym) qed lemma "lift_streams (rev x) = smap rev (lift_streams x)" proof (induction x) case Nil have "lift_streams [] = smap rev (lift_streams [])" by applicative_lifting simp thus ?case by simp next case (Cons x xs) have "\y ys. rev ys @ [y] = rev (y # ys)" by simp hence "\y ys. smap2 append (smap rev ys) (smap2 Cons y (sconst [])) = smap rev (smap2 Cons y ys)" by applicative_lifting simp with Cons.IH show ?case by applicative_unfold blast qed definition [applicative_unfold]: "sconcat xs = smap concat xs" lemma "sconcat (lift_streams [sconst ''Hello '', sconst ''world!'']) = sconst ''Hello world!''" by applicative_lifting simp subsection \Relators\ lemma "rel_fun (=) (\) (const (0::nat)) x" by applicative_lifting simp lemma "list_all2 (\) (map (\_. {}) x) (map set x)" by applicative_nf simp lemma "x = Some a \ rel_option (\) (map_option (\_. a) x) (map_option Suc x)" by applicative_lifting simp schematic_goal "\g f x. rel_sum ?R (=) (ap_either f x) (ap_either (ap_either (Inl g) f) x)" apply applicative_lifting oops schematic_goal "stream_all2 ?R (?f \ (pure ?g \ ?x + ?y)) (?x + ?z)" apply applicative_lifting oops print_applicative end