// MAXIMINIMAX FLOW // Official Solution by Jacob Plachta #define DEBUG 0 #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define LL long long #define LD long double #define PR pair #define Fox(i,n) for (i=0; i=0; i--) #define FoxR1(i,n) for (i=n; i>0; i--) #define FoxRI(i,a,b) for (i=b; i>=a; i--) #define Foxen(i,s) for (i=s.begin(); i!=s.end(); i++) #define Min(a,b) a=min(a,b) #define Max(a,b) a=max(a,b) #define Sz(s) int((s).size()) #define All(s) (s).begin(),(s).end() #define Fill(s,v) memset(s,v,sizeof(s)) #define pb push_back #define mp make_pair #define x first #define y second template T Abs(T x) { return(x<0 ? -x : x); } template T Sqr(T x) { return(x*x); } string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); } const int INF = (int)1e9; const LD EPS = 1e-9; const LD PI = acos(-1.0); //#if DEBUG #define GETCHAR getchar /*#else #define GETCHAR getchar_unlocked #endif*/ bool Read(int &x) { char c,r=0,n=0; x=0; for(;;) { c=GETCHAR(); if ((c<0) && (!r)) return(0); if ((c=='-') && (!r)) n=1; else if ((c>='0') && (c<='9')) x=x*10+c-'0',r=1; else if (r) break; } if (n) x=-x; return(1); } bool ReadLL(LL &x) { char c,r=0,n=0; x=0; for(;;) { c=GETCHAR(); if ((c<0) && (!r)) return(0); if ((c=='-') && (!r)) n=1; else if ((c>='0') && (c<='9')) x=x*10+c-'0',r=1; else if (r) break; } if (n) x=-x; return(1); } #define LIM 500005 #define LIM2 1000000 LL BLT[2][2][LIM2+1]; void Update(int a,int b,int i,int v) { for (; i<=LIM2; i+=(i&-i)) BLT[a][b][i]+=v; } void Update2(int a,int i,int v) { Update(a,0,i,v); Update(a,1,i,i*v); } LL Query(int a,int b,LL ii) { int i=(int)min(ii,(LL)LIM2); LL v=0; for(; i>0; i-=(i&-i)) v+=BLT[a][b][i]; return(v); } int main() { if (DEBUG) freopen("in.txt","r",stdin); //vars int T,t; int N,M; int i,j,k; LL r1,r2,m,m2; LL tot,rem,cnt,sum; LL ans; static vector con[LIM]; static int C[LIM],dep[LIM],cyc[LIM]; static PR par[LIM]; queue Q; set S; set::iterator I; //testcase loop Read(T); Fox1(t,T) { //input Read(N),Read(M); Fox(i,N) { Read(j),Read(k),Read(C[i]); j--,k--; con[j].pb(mp(k,i)); con[k].pb(mp(j,i)); } //BFS to find the single cycle Fill(dep,-1); Q.push(0),dep[0]=0; for(;;) { i=Q.front(),Q.pop(); Fox(j,Sz(con[i])) if ((k=con[i][j].x)!=par[i].x) if (dep[k]>=0) goto Done; else Q.push(k),dep[k]=dep[i]+1,par[k]=mp(i,con[i][j].y); } //retrace all edges in the cycle Done:; Fill(cyc,0); cyc[con[i][j].y]=1; while (i!=k) if (dep[i]>dep[k]) { cyc[par[i].y]=1; i=par[i].x; } else { cyc[par[k].y]=1; k=par[k].x; } //init BLTs Fox(i,N) { Update2(cyc[i],C[i],1); if (cyc[i]) S.insert(mp(C[i],i)); } //handle operations ans=0; while (M--) { Read(i); if (i==1) { //delete and re-add the adge Read(i),i--; Update2(cyc[i],C[i],-1); if (cyc[i]) S.erase(mp(C[i],i)); Read(C[i]); Update2(cyc[i],C[i],1); if (cyc[i]) S.insert(mp(C[i],i)); } else { //binary search on the answer ReadLL(tot); r1=1,r2=(LL)1e13; while (r2>r1) { m=(r1+r2+1)>>1; rem=tot; //non-cycle edges cnt=Query(0,0,m); sum=Query(0,1,m); rem-=cnt*m - sum; if (rem<0) goto Bad; //cycle edges I=S.begin(),i=I->x; I++,j=I->x; if (m<=(j<<1)) rem-=max(0LL,m - (i+j)); else { m2=(m+1)>>1; cnt=Query(1,0,m2); sum=Query(1,1,m2); rem-=cnt*m2 - sum; if (m&1) rem++; } if (rem<0) { Bad:; r2=m-1; continue; } r1=m; } ans+=r1; } } //output printf("Case #%d: ",t); cout << ans << endl; //reset Fox(i,N) con[i].clear(); while (!Q.empty()) Q.pop(); S.clear(); Fill(BLT,0); } return(0); }