You are a professional chemist. Your task is to generate a natural, concise, and chemically accurate description of a given molecule.

Please provide a step-by-step analysis explaining how you interpret the molecular structure, identify key features and functional groups, and summarize it into a clear and informative description.

Think step by step, and your final answer **must** be returned in the format: <answer> ... </answer>. For example:
<answer>The molecule is an epoxy(hydroxy)icosatrienoate that is the conjugate base of 11-hydroxy-(14R,15S)-epoxy-(5Z,8Z,12E)-icosatrienoic acid, obtained by deprotonation of the carboxy group; major species at pH 7.3. It is a conjugate base of an 11-hydroxy-(14R,15S)-epoxy-(5Z,8Z,12E)-icosatrienoic acid.</answer>

[N][C@H1][C@@H1][Branch1][#Branch2][O][P][=Branch1][C][=O][Branch1][C][O][O][O][C@H1][Branch3][Ring1][Ring1][#Branch2][C][O][C@@H1][O][C@H1][Branch2][P][=N][C][O][C@][Branch1][=Branch1][C][=Branch1][C][=O][O][C][C@@H1][Branch2][Ring1][#C][O][C@][Branch1][=Branch1][C][=Branch1][C][=O][O][C][C@@H1][Branch1][C][O][C@@H1][Branch1][C][O][C@@H1][Branch1][#Branch1][C@H1][Branch1][C][O][C][O][O][Ring1][#C][C@@H1][Branch2][=N][#C][O][C@H1][O][C@H1][Branch1][#Branch1][C@@H1][Branch1][C][O][C][O][C@@H1][Branch1][#Branch2][O][P][=Branch1][C][=O][Branch1][C][O][O][C@H1][Branch2][O][=C][O][C@H1][O][C@H1][Branch2][Ring1][=C][C@@H1][Branch1][C][O][C][O][C@H1][O][C@H1][Branch1][#Branch1][C@@H1][Branch1][C][O][C][O][C@@H1][Branch1][C][O][C@H1][Branch1][C][O][C@@H1][Ring1][N][O][C@@H1][Branch1][#Branch2][O][P][=Branch1][C][=O][Branch1][C][O][O][C@H1][Branch2][Branch2][Branch1][O][C@H1][O][C@H1][Branch1][Ring1][C][O][C@@H1][Branch1][C][O][C@H1][Branch2][=Branch1][S][O][C@H1][O][C@H1][Branch1][Ring1][C][O][C@@H1][Branch1][C][O][C@H1][Branch2][Ring1][Branch1][O][C@@H1][O][C@H1][Branch1][Ring1][C][O][C@@H1][Branch1][C][O][C@H1][Branch1][C][O][C@H1][Ring1][#Branch2][O][C@H1][Ring2][Ring1][Branch1][O][C@H1][O][C@H1][Branch1][Ring1][C][O][C@H1][Branch1][C][O][C@H1][Branch1][C][O][C@H1][Ring1][#Branch2][O][C@H1][O][C@H1][Branch1][Ring1][C][O][C@H1][Branch1][C][O][C@H1][Branch1][C][O][C@H1][Ring1][#Branch2][O][C@H1][Ring2][Branch1][=Branch1][O][C@@H1][Ring2][#Branch1][Ring2][O][C@@H1][Ring2][Branch2][Branch1][O][C@@H1][Branch1][#Branch1][C@H1][Branch1][C][O][C][O][O][Ring2][#Branch2][Ring2][C@@H1][Branch1][#Branch2][O][P][=Branch1][C][=O][Branch1][C][O][O][C@H1][Branch1][C][O][C@H1][Ring2][O][C][N][C@@H1][Branch1][C][O][C@@H1][Ring2][O][P][O]

The molecule is a branched twelve-membered oligosaccharide phosphate consisting of two galactose residues, three glucose residues, two 3-deoxy-D-manno-oct-2-ulosonic acid residues, three L-glycero-alpha-D-manno-heptose residues and two glucosamine residues, one of which is at the reducing end. The unit constitutes one of the two core oligosaccharide structures of enterobacterial lipopolysaccharide obtained from E. coli strain F470.

SMILES: NC1C(OP(=O)(O)O)OC(COC2OC(COC3(C(=O)O)CC(OC4(C(=O)O)CC(O)C(O)C(C(O)CO)O4)C(OC4OC(C(O)CO)C(OP(=O)(O)O)C(OC5OC(C(O)COC6OC(C(O)CO)C(O)C(O)C6O)C(OP(=O)(O)O)C(OC6OC(CO)C(O)C(OC7OC(CO)C(O)C(OC8OC(CO)C(O)C(O)C8O)C7OC7OC(CO)C(O)C(O)C7OC7OC(CO)C(O)C(O)C7O)C6O)C5O)C4O)C(C(O)CO)O3)C(OP(=O)(O)O)C(O)C2N)C(O)C1O