gkaradzhov/DeliData huggingface dataset:
SYSTEM: SYSTEM,Tiger,Kiwi,Leopard&&E,1,R,6
Tiger: is the chat working?
Leopard: seems its working
Tiger: So first things first
Tiger: dose every one knows whats a vowel and what are even numbers? :D
Kiwi: yes, and i think i marked too many
Tiger: Well I see that we see one vowel.
Tiger: `E`
Leopard: i think that vowels are a,e,i,o,u, even numbers are those devided by two without reminder.
Tiger: So that one we definetly need to check
Kiwi: :)
Tiger: IMO we do not need to turn 1.
Tiger: as we do not care whats on the other side of Odd numbers
Leopard: why? if 1 will have vowel on the other side it will break the rule, as 1 is not considered an even number
Kiwi: rulw does not say anything about odd
Kiwi: so we dont need to turn 1
Tiger: we dont care about whats on the other side
Tiger: of an odd number
Tiger: it says that all vowels has a even number
Tiger: but a odd number can have whatever
Tiger: But we need to check `6` as it is direct check
Tiger: and we need to turn `R` as it might brake the rule
Kiwi: 'all card with vowels - we need to check if the is a vowel on car ''1'''
Kiwi: card 1
Kiwi: we dont care about 6, it could be any letter
Kiwi: we dont care about r
Tiger: Oh damn. I think Kiwi is right. I understood it the other way around
Kiwi: we need to check E if there is a even number, we dont care about R
Tiger: So we need to check `6`, `E` and `1`
Leopard: 'I understood it as that there is no ''primary'' side of the card. So if one side is 1 and another is A it will break the rule. Because it reads both directions 1->A, A->1'
Kiwi: 6 is ok
Kiwi: dont ceck it
Kiwi: i am ready to submit
Leopard: 'I''m also thinking that it''s 6,e,1. Could there be a trick somewhere that we missed'
Kiwi: e and 1
Kiwi: 6- could have any thing, it will not break the rule
Kiwi: i think
Leopard: ahh, damn, your right!
Tiger: Ye.
Tiger: Lets go with E and 1
Tiger: E,1
Kiwi: E,1
Leopard: agree
Tiger: I submited game
Leopard: E,1