gkaradzhov/DeliData huggingface dataset:
SYSTEM: SYSTEM,Butterfly,Koala,Leopard&&3,2,K,E
Leopard: Hello, I chose 3 and E
Koala: e
Leopard: If there is an odd number behind the E, the rule is false. Is there is a vowel behind the 3, it is false.
Butterfly: Why 3 and E?  I chose 2 and E.
Koala: i choose 2 and e
Butterfly: If there is an vowel behind 2 it is true
Leopard: There could be a consonant behind 3, but that would not necessarily make the rule false.
Koala: i still think 2 and e makes the most since
Butterfly: I think we need to do 3 cards to find out truth
Butterfly: I picked 2 3 E
Koala: ok lets do three i picke 2 3 e
Koala: 3,2,E
Butterfly: 3,2,E
Leopard: okay
Butterfly: does anybody have any other thoughts on what we should pick
Koala: oh ok i agree with yall i dont have any other thoughts
Koala: i think it could possible be 2 3 and e makes sense to me
Butterfly: I think that if we just chose 2 and E they can be true but 2 could have a vowel behind it too
Koala: yeah i am not sure i understand how three would work so maybe just 2 and e
Leopard: Yeah, the numbers and letters could be random, and yet still fit the rule. We would need to find out examples that make the rule false, rather than true.
Koala: yes how would we do that
Butterfly: Exactly what Leopard said
Butterfly: check them all lol
Koala: oh yeah we could check them all if thats what yall think lol
Butterfly: K could also have an even number behind it
Koala: 3,2,K,E
Koala: yes thats true
Koala: E,2,K
Butterfly: 3,2,K,E
Koala: i dont think we should pick 3
Butterfly: What do you want to pick?
Koala: i think 2 e k
Butterfly: I will go with that
Butterfly: E,2,K
Koala: is this are final decision
Butterfly: sounds good, we all agree?
Butterfly: ok lets do it i think its been long enough
Butterfly: Thanks have a great day everyone
Leopard: 3,E