gkaradzhov/DeliData huggingface dataset:
SYSTEM: Emu,Dolphin,Lobster,SYSTEM,Alpaca&&E,2,7,S
Alpaca: Hello all
Emu: Hey there!
Lobster: Hey all!
Emu: I chose E.
Dolphin: Howdy!
Alpaca: Card E is the only vowel
Dolphin: I chose E and 7
Lobster: I chose E and 7 too
Dolphin: Choosing 7 guards against the exception
Emu: Vowels have an even number on one side. Does that mean all evens also have a vowel?
Dolphin: Rule does not say all evens have a voweel
Emu: Ok. That’s what I was thinking.
Alpaca: We have to choose the card that tests the rule
Alpaca: 2 and E
Alpaca: E,2
Emu: So, yes, I see the logic with choosing both E and 7.
Emu: 2 vs. 7… explain your logic :)
Dolphin: 2 can have a consonant and the rule would still be true
Lobster: E,7
Emu: I agree.
Alpaca: 2 should have a vowel
Emu: Can anyone explain the 7 logic.
Emu: All vowels have an even number. But that doesn’t mean all even numbers have to have a vowel. Does that make sense?
Emu: E,7
Dolphin: If all cards with vowels have an even number, then the 7 cannot have a vowel.  If it does, this demonstrates breakage of the rule.
Alpaca: An even number should have a vowel
Emu: I think that is a perfect explanation. I’m willing to choose E and 7 and be done. How about you all?
Alpaca: E2
Emu: What say you, Dolphin and Lobster?
Lobster: 'I agree with Emu, doesn''t necessarily mean 2 has an even number on the back. That''s the whole point'
Dolphin: Rule states all cards with even have a vowel, but it does not require that all even numbers have a vowel.  Thus, the 2 can have either a vowel or a consonan
Lobster: 'They''re manipulating the wording to go with the most obvious answer.'
Emu: I’m happy with that explanation. Are we done?
Lobster: 'I''m going E7'
Emu: Same.
Dolphin: i am cool wirth E7
Lobster: Cool, seems like we are all in agreement!
Dolphin: E,7