Display The Number (Codeforces 1295A)
Tags: Greedy, greedy

You have a large electronic screen which can display up to $$$998244353$$$ decimal digits. The digits are displayed in the same way as on different electronic alarm clocks: each place for a digit consists of $$$7$$$ segments which can be turned on and off to compose different digits. The following picture describes how you can display all $$$10$$$ decimal digits:As you can see, different digits may require different number of segments to be turned on. For example, if you want to display $$$1$$$, you have to turn on $$$2$$$ segments of the screen, and if you want to display $$$8$$$, all $$$7$$$ segments of some place to display a digit should be turned on.You want to display a really large integer on the screen. Unfortunately, the screen is bugged: no more than $$$n$$$ segments can be turned on simultaneously. So now you wonder what is the greatest integer that can be displayed by turning on no more than $$$n$$$ segments.Your program should be able to process $$$t$$$ different test cases.

Input: The first line contains one integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases in the input.Then the test cases follow, each of them is represented by a separate line containing one integer $$$n$$$ ($$$2 \le n \le 10^5$$$) — the maximum number of segments that can be turned on in the corresponding testcase.It is guaranteed that the sum of $$$n$$$ over all test cases in the input does not exceed $$$10^5$$$.

Output: For each test case, print the greatest integer that can be displayed by turning on no more than $$$n$$$ segments of the screen. Note that the answer may not fit in the standard $$$32$$$-bit or $$$64$$$-bit integral data type.


Sample Inputs:
2
3
4

Sample Outputs:
7
11

Solution (Python):
t = int(input())
for _ in range(t):
    n = int(input())
    print('7' * (n % 2) + '1' * ((n - 3 * (n % 2)) // 2))

Solution (Python):
t = int(input())
for _ in range(t):
    n = int(input())
    if n % 2 == 0:
        print('1' * (n // 2))
    else:
        print('7' + '1' * (n // 2 - 1))

Solution (Python):
t = int(input())
for i in range(t):
    n = int(input())
    k = n // 2
    m = n % 2
    ans = ''
    if m == 0:
        ans += '1' * k
    else:
        ans += '7'
        ans += '1' * (k - 1)
    print(ans)