Ordinary Numbers (Codeforces 1520B)
Tags: Math, number theory

Let's call a positive integer $$$n$$$ ordinary if in the decimal notation all its digits are the same. For example, $$$1$$$, $$$2$$$ and $$$99$$$ are ordinary numbers, but $$$719$$$ and $$$2021$$$ are not ordinary numbers.For a given number $$$n$$$, find the number of ordinary numbers among the numbers from $$$1$$$ to $$$n$$$.

Input: The first line contains one integer $$$t$$$ ($$$1 \le t \le 10^4$$$). Then $$$t$$$ test cases follow.Each test case is characterized by one integer $$$n$$$ ($$$1 \le n \le 10^9$$$).

Output: For each test case output the number of ordinary numbers among numbers from $$$1$$$ to $$$n$$$.


Sample Inputs:
6
1
2
3
4
5
100

Sample Outputs:
1
2
3
4
5
18

Solution (Python):
for s in [*open(0)][1:]:
    print(9 * len(s) - 18 + int((c := s[0])) - ('.' < s.strip(c) < c))

Solution (Python):
for s in [*open(0)][1:]:
    print(9 * len(s) - 18 + int((c := s[0])) - ('.' < s.strip(c) < c))

Solution (Python):
for s in [*open(0)][1:]:
    print(9 * len(s) - 18 + int((c := s[0])) - ('.' < s.strip(c) < c))