Plus or Minus (Codeforces 1807A)
Tags: Implement, implementation

You are given three integers $$$a$$$, $$$b$$$, and $$$c$$$ such that exactly one of these two equations is true:   $$$a+b=c$$$  $$$a-b=c$$$  Output + if the first equation is true, and - otherwise.

Input: The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 162$$$) — the number of test cases.The description of each test case consists of three integers $$$a$$$, $$$b$$$, $$$c$$$ ($$$1 \leq a, b \leq 9$$$, $$$-8 \leq c \leq 18$$$). The additional constraint on the input: it will be generated so that exactly one of the two equations will be true.

Output: For each test case, output either + or - on a new line, representing the correct equation.

Note: In the first test case, $$$1+2=3$$$.In the second test case, $$$3-2=1$$$.In the third test case, $$$2-9=-7$$$. Note that $$$c$$$ can be negative.

Sample Inputs:
11
1 2 3
3 2 1
2 9 -7
3 4 7
1 1 2
1 1 0
3 3 6
9 9 18
9 9 0
1 9 -8
1 9 10

Sample Outputs:
+
-
-
+
+
-
+
+
-
-
+

Solution (Python):
t = int(input())
for _ in range(t):
    (a, b, c) = map(int, input().split())
    if a + b == c:
        print('+')
    else:
        print('-')

Solution (Python):
n = int(input())
for i in range(n):
    (a, b, c) = map(int, input().split())
    if a + b != c:
        print('-')
    else:
        print('+')
    print('\n')

Solution (Python):
for _ in range(int(input())):
    (a, b, r) = map(int, input().split())
    if a + b == r:
        print('+')
    else:
        print('-')