Aleksa and Stack (Codeforces 1878B)
Tags: Math, constructive algorithms

After the Serbian Informatics Olympiad, Aleksa was very sad, because he didn't win a medal (he didn't know stack), so Vasilije came to give him an easy problem, just to make his day better.Vasilije gave Aleksa a positive integer $$$n$$$ ($$$n \ge 3$$$) and asked him to construct a strictly increasing array of size $$$n$$$ of positive integers, such that   $$$3\cdot a_{i+2}$$$ is not divisible by $$$a_i+a_{i+1}$$$ for each $$$i$$$ ($$$1\le i \le n-2$$$).  Note that a strictly increasing array $$$a$$$ of size $$$n$$$ is an array where $$$a_i < a_{i+1}$$$ for each $$$i$$$ ($$$1 \le i \le n-1$$$).Since Aleksa thinks he is a bad programmer now, he asked you to help him find such an array.

Input: Each test consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. The description of test cases follows.The first line of each test case contains a single integer $$$n$$$ ($$$3 \le n \le 2 \cdot 10^5$$$) — the number of elements in array.It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$.

Output: For each test case, output $$$n$$$ integers $$$a_1, a_2, a_3, \dots, a_n$$$ ($$$1 \le a_i \le 10^9$$$).It can be proved that the solution exists for any $$$n$$$. If there are multiple solutions, output any of them.

Note: In the first test case, $$$a_1=6$$$, $$$a_2=8$$$, $$$a_3=12$$$, so $$$a_1+a_2=14$$$ and $$$3 \cdot a_3=36$$$, so $$$3 \cdot a_3$$$ is not divisible by $$$a_1+a_2$$$.

Sample Inputs:
3
3
6
7

Sample Outputs:
6 8 12
7 11 14 20 22 100
9 15 18 27 36 90 120

Solution (Python):
t = int(input())
for _ in range(t):
    n = int(input())
    print(' '.join(map(str, range(1, 2 * n, 2))))

Solution (Python):
for t in range(int(input())):
    print(' '.join(map(str, range(5, int(input()) + 5))))

Solution (Python):
for t in range(int(input())):
    print(' '.join(map(str, range(5, int(input()) + 5))))