AMC8 2013 8, Problem 17

The sum of six consecutive positive integers is 2013. What is the largest of these six integers?

Solution: The arithmetic mean of these numbers is $\frac{\frac{2013}{3}}{2}=\frac{671}{2}=335.5$. Therefore the numbers are $333$, $334$, $335$, $336$, $337$, $338$, so the answer is $\fbox{338}$

Answer: 338