AMC10 2015 10A, Problem 1

What is the value of $(2^0-1+5^2-0)^{-1}\times5?$

Solution: $(2^0-1+5^2-0)^{-1}\times5 = (1-1+25-0)^{-1} \times 5 = 25^{-1} \times 5 = \frac{1}{25} \times 5 = \fbox{\frac{1}{5}}$.

Answer: \frac{1}{5}