分类：教育/科学-升学入学-考研
问题：数学作业题目在附件中,谢谢! 
题目在附件中,谢谢!
回答：15.原式=
∫<0,1>[(1/3)x^2dx^2-(1/2)(x^2)^2]dx
+∫<1,0>[(1/3)x^2d√x-(1/2)x]dx
=∫<0,1>[(2/3)x^3-(1/2)x^4]dx
+∫<1,0>[(1/6)x^(3/2)-(1/2)x]dx
=∫<0,1>[-(1/2)x^4+(2/3)x^3-(1/6)x^(3/2)+(1/2)x]dx
=[-x^5/10+x^4/6-x^(5/2)/15+x^2/4]<0,1>
=-1/10+1/6-1/15+1/4
=1/4,故选C.
16.和12.重了.-1≤x-1≤1,解得0≤x≤2,故选C.
17.√x^2-y^2>0,即x^2-y^2>0,选D.