分类：教育/科学-理工学科-数学
问题：(1/x2
回答：分式化简：
1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)
=1/[(x-1)(x-2)]+1/[(x-2)(x-3)]+1/[(x-3)(x-1)]
=[(x-3)+(x-1)+(x-2)]/[(x-1)(x-2)(x-3)]
=(3x-6)/[(x-1)(x-2)(x-3)]
=3(x-2)/[(x-1)(x-2)(x-3)]
=3/[(x-1)(x-3)].