分类：教育/科学-升学入学-中考
问题：数学解方程组x^2
  x^2-y^2=1
{
 (x-y)^2-2(x-y)-3=0
回答：∵(x-y)^2-2(x-y)-3=0 
∴[(x-y)-3][(x-y)+1]=0
(x-y)=3,(x-y)=-1
∴x^2-y^2=1
(x-y)(x+y)=1
∴当(x-y)=3,(x+y)=1/3;x=5/3,y=-4/3
当(x-y)=-1,(x+y)=-1;x=-1,y=0.