分类：教育/科学-理工学科-数学
问题：导数的推导一,((X
一,((X-5)*X^2/3)的导数是怎么推导为(5/3X^2/3)-(10/3X^-1/3)的.
二,(10/9X^-1/3)+(10/9X^-4/3)=10*(X+1)/9X^4/3的计算过程.要具体一点的.我要加分.
回答：一,((X-5)*X^2/3)的导数是怎么推导为(5/3X^2/3)-(10/3X^-1/3)的. 
就一步一步来啊
[(x-5)*(x^2/3)]'
=(x-5)'*(x^2/3)+(x-5)*(x^2/3)'
=1*(x^2/3)+(x-5)*(2/3)*x^[(2/3)-1]
=x^(2/3)+(x-5)*(2/3)*x^(-1/3)
=x^(2/3)+(2/3)x^(2/3)-(10/3)x^(-1/3)
=(5/3)x^(2/3)-(10/3)x^(-1/3)

二,(10/9X^-1/3)+(10/9X^-4/3)=10*(X+1)/9X^4/3的计算过程.
[(10/9X^-1/3)+(10/9X^-4/3)]'
=(10/9)*{[x^(-1/3)]'+[x^(-4/3)]'}
=(10/9)*[(-1/3)*x^(-1/3-1)+(-4/3)*x^(-4/3-1)]
=(10/9)*[(-1/3)x^(-4/3)+(-4/3)x^(-7/3)]
=(-10/27)*x^(-4/3)*[1+(4/x)]
实在是不能得到你所给的答案。
估计是我没有看懂你的题目。。。