分类：教育/科学-学习帮助
问题：请帮忙解一下极限lim(lnsinx)/(π
lim (ln sinx)/(π-2x)^     x→(π/2) 
回答：lim<x→π/2>(ln sinx)/[(π-2x)^2]
=lim<x→π/2>(cosx/sinx)/[-4(π-2x)]
=-(1/4)lim<x→π/2>cosx/(π-2x)
=-(1/4)lim<x→π/2>(-sinx)/(-2)=-(1/4)(1/2)=-1/8