分类：教育/科学-学习帮助
问题：初二数学若a=1/bc,求a/(ab+a+1)+b/(bc+b+ 
若a=1/bc,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)的值？
回答：已知a=1/bc，所以：abc=1

a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
=[ac/(abc+ac+c)]+[b/(bc+b+abc)]+[c/(ac+c+1)]
=[ac/(1+ac+c)]+[1/(c+1+ac)]+[c/(ac+c+1)]
=(ac+1+c)/(1+ac+c)
=1.