CREATE TABLE table_10798421_1 (village__german_ VARCHAR(255), percent_of_slovenes_1951 VARCHAR(255))
Provide me with the name of the village (German) where there is 96.9% Slovenes in 1951. 
    
SQL: SELECT village__german_ FROM table_10798421_1 WHERE percent_of_slovenes_1951 = "96.9%"