CREATE TABLE table_name_32 (july VARCHAR(255), plant_hardiness_zone VARCHAR(255), january VARCHAR(255))
What is the July temperature where plant hardiness zone is 2B and January figure is −12/−23°c (10-9°f)?
    
SQL: SELECT july FROM table_name_32 WHERE plant_hardiness_zone = "2b" AND january = "−12/−23°c (10-9°f)"