CREATE TABLE table_name_84 (other VARCHAR(255), joe_sestak__d_ VARCHAR(255), margin_of_error VARCHAR(255), pat_toomey__r_ VARCHAR(255))
WHAT CANDIDATE HAD A MARGIN OF ERROR OF ± 4.5%, WHEN PAT TOOMEY WAS 45% AND JOE SESTAK WAS 38%?
    
SQL: SELECT other FROM table_name_84 WHERE margin_of_error = "± 4.5%" AND pat_toomey__r_ = "45%" AND joe_sestak__d_ = "38%"