CREATE TABLE table_name_8 (money___ INTEGER, to_par VARCHAR(255), score VARCHAR(255))
What is the average money (£) that has +8 as the to par, with 73-72-72-71=288 as the score?
    
SQL: SELECT AVG(money___) AS £__ FROM table_name_8 WHERE to_par = "+8" AND score = 73 - 72 - 72 - 71 = 288