CREATE TABLE table_name_69 (date VARCHAR(255), edition VARCHAR(255), result VARCHAR(255))
What date was the 1988 world group i edition with a result of 7–6 (7–5) , 6–3?
    
SQL: SELECT date FROM table_name_69 WHERE edition = "1988 world group i" AND result = "7–6 (7–5) , 6–3"