CREATE TABLE table_name_60 (evening_gown VARCHAR(255), preliminary VARCHAR(255), average VARCHAR(255), country VARCHAR(255))
What is the evening gown number when the average is more than 8.984 in Louisiana and the preliminary is more than 8.597?
    
SQL: SELECT COUNT(evening_gown) FROM table_name_60 WHERE average > 8.984 AND country = "louisiana" AND preliminary > 8.597