CREATE TABLE table_15909409_2 (country VARCHAR(255), agricultural_use__m_3__p_yr__in__percentage_ VARCHAR(255))
What was the country in which the agricultural use (m 3 /p/yr)(in %) was 794(86%)?
    
SQL: SELECT country FROM table_15909409_2 WHERE agricultural_use__m_3__p_yr__in__percentage_ = "794(86%)"