CREATE TABLE table_name_34 (scored_1 VARCHAR(255), years_played VARCHAR(255), name VARCHAR(255))
WHich Scored 1,500 Points has a Years Played of 2004–2008 and a Name of jolene anderson?
    
SQL: SELECT scored_1, 500 AS _points FROM table_name_34 WHERE years_played = "2004–2008" AND name = "jolene anderson"