CREATE TABLE table_name_98 (name VARCHAR(255), nat VARCHAR(255), app_l_c_e_ VARCHAR(255))
Who has a nationality of GRE and an App(L/C/E) of 49 (40/8/1)?
    
SQL: SELECT name FROM table_name_98 WHERE nat = "gre" AND app_l_c_e_ = "49 (40/8/1)"