CREATE TABLE table_name_49 (date_s__administered VARCHAR(255), joe_sestak__d_ VARCHAR(255), margin_of_error VARCHAR(255))
WHAT DATE DID JOE SESTAK HAVE 46% WITH ± 3.0% MARGIN OF ERROR?
    
SQL: SELECT date_s__administered FROM table_name_49 WHERE joe_sestak__d_ = "46%" AND margin_of_error = "± 3.0%"