CREATE TABLE table_name_47 (number_of_examinees VARCHAR(255), number_of_passed_students VARCHAR(255), year VARCHAR(255), pass_percentage VARCHAR(255))
What number of examines after 2005 has a pass percentage of 78.35% with less than 297 students?
    
SQL: SELECT COUNT(number_of_examinees) FROM table_name_47 WHERE year > 2005 AND pass_percentage = "78.35%" AND number_of_passed_students < 297