CREATE TABLE table_name_7 (agricultural_use__m_3__p_yr__in__percentage_ VARCHAR(255), per_capita_withdrawal__m_3__p_yr_ VARCHAR(255), domestic_use__m_3__p_yr__in__percentage_ VARCHAR(255))
What is Agricultural Use (m 3 /p/yr)(in %), when Per Capita Withdrawal (m 3 /p/yr) is greater than 923, and when Domestic Use (m 3 /p/yr)(in %) is 73(7%)?
    
SQL: SELECT agricultural_use__m_3__p_yr__in__percentage_ FROM table_name_7 WHERE per_capita_withdrawal__m_3__p_yr_ > 923 AND domestic_use__m_3__p_yr__in__percentage_ = "73(7%)"