CREATE TABLE table_1341930_33 (party VARCHAR(255), candidates VARCHAR(255))
how many party with candidates being alton lennon (d) 89.0% c. dana malpass (r) 11.0%
    
SQL: SELECT COUNT(party) FROM table_1341930_33 WHERE candidates = "Alton Lennon (D) 89.0% C. Dana Malpass (R) 11.0%"