CREATE TABLE locations (city VARCHAR(255), location_id VARCHAR(255)); CREATE TABLE employees (first_name VARCHAR(255), last_name VARCHAR(255), department_id VARCHAR(255)); CREATE TABLE departments (department_id VARCHAR(255), location_id VARCHAR(255))
display those employees who contain a letter z to their first name and also display their last name, city.
    
SQL: SELECT T1.first_name, T1.last_name, T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T1.first_name LIKE '%z%'