CREATE TABLE table_name_71 (competition VARCHAR(255), round VARCHAR(255), score VARCHAR(255))
Which Competition has a 2nd round score of 1:0, 0:1 (4:3 a.p.)?
    
SQL: SELECT competition FROM table_name_71 WHERE round = "2nd round" AND score = "1:0, 0:1 (4:3 a.p.)"