CREATE TABLE table_25042332_16 (median_income___intl INTEGER, below_60_percentage_of_median_income VARCHAR(255))
What is the median income for the region where 24.4% pf people make below 60% of the median income?
    
SQL: SELECT MIN(median_income___intl) AS $__ FROM table_25042332_16 WHERE below_60_percentage_of_median_income = "24.4%"