CREATE TABLE table_name_47 (portfolio_attachment VARCHAR(255), age_at_appointment VARCHAR(255), chinese_name VARCHAR(255))
What is the portfolio attachment of the Undersecretary appointed at age 48 with a Chinese name of 梁鳳儀?
    
SQL: SELECT portfolio_attachment FROM table_name_47 WHERE age_at_appointment = 48 AND chinese_name = "梁鳳儀"