CREATE TABLE table_name_35 (kinka_12 VARCHAR(255), kinka_pre_release VARCHAR(255), kinka_developer VARCHAR(255))
What is the KINKA 1.2 when the pre-release is no and the developer is yes?
    
SQL: SELECT kinka_12 FROM table_name_35 WHERE kinka_pre_release = "no" AND kinka_developer = "yes"