CREATE TABLE Student (age INTEGER, StuID VARCHAR(255)); CREATE TABLE Allergy_Type (Allergy VARCHAR(255), allergytype VARCHAR(255)); CREATE TABLE Has_allergy (StuID VARCHAR(255), Allergy VARCHAR(255))
Find the average age of the students who have allergies with food and animal types.
    
SQL: SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")