CREATE TABLE table_name_86 (score VARCHAR(255), team_1 VARCHAR(255))
What is the 2nd round with a score of 3 - 3, and a team 1 fc gueugnon (d2)?
    
SQL: SELECT 2 AS nd_round FROM table_name_86 WHERE score = "3 - 3" AND team_1 = "fc gueugnon (d2)"