CREATE TABLE table_name_79 (interview INTEGER, evening_gown VARCHAR(255), average VARCHAR(255), swimsuit VARCHAR(255))
Which mean interview number had an average of more than 9.233, a swimsuit stat of more than 9.473, and an evening gown score of more than 9.671?
    
SQL: SELECT AVG(interview) FROM table_name_79 WHERE average > 9.233 AND swimsuit = 9.473 AND evening_gown > 9.671