CREATE TABLE table_15909409_2 (country VARCHAR(255), agricultural_use__m_3__p_yr__in__percentage_ VARCHAR(255))
What are the countries in which the agricultural use  (m 3 /p/yr)(in %) is 2040(93%)?
    
SQL: SELECT country FROM table_15909409_2 WHERE agricultural_use__m_3__p_yr__in__percentage_ = "2040(93%)"