CREATE TABLE table_name_42 (average INTEGER, evening_gown VARCHAR(255), interview VARCHAR(255), country VARCHAR(255))
Name the lowest average for interview more than 9.57 and delaware and evening gown more than 9.77
    
SQL: SELECT MIN(average) FROM table_name_42 WHERE interview > 9.57 AND country = "delaware" AND evening_gown > 9.77