CREATE TABLE employees (employee_id VARCHAR(255), first_name VARCHAR(255), last_name VARCHAR(255), salary INTEGER, department_id VARCHAR(255))
display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.
    
SQL: SELECT employee_id, first_name, last_name, salary FROM employees WHERE salary > (SELECT AVG(salary) FROM employees) AND department_id IN (SELECT department_id FROM employees WHERE first_name LIKE '%J%')