CREATE TABLE Has_allergy (lname VARCHAR(255), age VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255)); CREATE TABLE Student (lname VARCHAR(255), age VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255))
Find the last name and age of the student who has allergy to both milk and cat.
    
SQL: SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")