Question: How can I compute time to first target event per user using Pandas efficiently (with edge cases)? I'm analyzing user behavior using a Pandas DataFrame that logs events on an app. Each row includes a user_id, event_type, and timestamp. I want to calculate the time (in seconds) from each user's first recorded event to their first occurrence of a target event (e.g., "purchase"). However, there are a few requirements that complicate things: Some users never trigger the target event, so I want to exclude or mark them as NaN. The timestamp column is a datetime. I’d like this to be vectorized and efficient (not using for loops). I want to return a DataFrame with user_id and seconds_to_first_purchase. import pandas as pd data = [ {'user_id': 'u1', 'event_type': 'login', 'timestamp': '2023-01-01 10:00:00'}, {'user_id': 'u1', 'event_type': 'purchase', 'timestamp': '2023-01-01 10:05:00'}, {'user_id': 'u2', 'event_type': 'login', 'timestamp': '2023-01-01 09:00:00'}, {'user_id': 'u2', 'event_type': 'scroll', 'timestamp': '2023-01-01 09:03:00'}, {'user_id': 'u3', 'event_type': 'login', 'timestamp': '2023-01-01 11:00:00'}, {'user_id': 'u3', 'event_type': 'purchase', 'timestamp': '2023-01-01 11:20:00'}, ] df = pd.DataFrame(data) df['timestamp'] = pd.to_datetime(df['timestamp'])  What’s the cleanest and most efficient way to compute the time to first "purchase" event per user? What I tried: I grouped the DataFrame by user_id and tried to extract the first timestamp for each user using groupby().first(), and then did the same for the first "purchase" event using a filtered DataFrame. Then I tried merging both results to calculate the time difference like this: first_event = df.groupby('user_id')['timestamp'].min() first_purchase = df[df['event_type'] == 'purchase'].groupby('user_id')['timestamp'].min() result = (first_purchase - first_event).dt.total_seconds()  What I expected: I expected this to give me a clean Series or DataFrame with user_id and the number of seconds between the user's first event and their first "purchase". What went wrong: It mostly works, but:  Users who never purchased are missing from the result and I want to keep them (with NaN). I'm not sure this is the most efficient or cleanest approach.  I’m also wondering if there's a better way to avoid intermediate merges or repetitive groupby operations.

Answer: I grouped by user_id to get the first event timestamp, then did the same for 'purchase' events. Instead of subtracting the Series directly, I used pd.concat() to combine both into one DataFrame. Then I used .assign() with .dt.total_seconds() to calculate the difference. This gave me a clean DataFrame where I could see the first event, the first purchase (if it happened), and the time difference in seconds. It also kept users with no purchase in the output, which you needed. Made things much easier to debug and extend. The entire code should be import pandas as pd # Sample data data = [ {'user_id': 'u1', 'event_type': 'login', 'timestamp': '2023-01-01 10:00:00'}, {'user_id': 'u1', 'event_type': 'purchase', 'timestamp': '2023-01-01 10:05:00'}, {'user_id': 'u2', 'event_type': 'login', 'timestamp': '2023-01-01 09:00:00'}, {'user_id': 'u2', 'event_type': 'scroll', 'timestamp': '2023-01-01 09:03:00'}, {'user_id': 'u3', 'event_type': 'login', 'timestamp': '2023-01-01 11:00:00'}, {'user_id': 'u3', 'event_type': 'purchase', 'timestamp': '2023-01-01 11:20:00'}, ] df = pd.DataFrame(data) df['timestamp'] = pd.to_datetime(df['timestamp']) # Step 1: First overall event per user first_event = df.groupby('user_id')['timestamp'].min().rename('first_event_time') # Step 2: First 'purchase' event per user first_purchase = ( df[df['event_type'] == 'purchase'] .groupby('user_id')['timestamp'] .min() .rename('first_purchase_time') ) # Step 3: Combine and calculate time delta in seconds result = ( pd.concat([first_event, first_purchase], axis=1) .assign(seconds_to_first_purchase=lambda x: ( (x['first_purchase_time'] - x['first_event_time']).dt.total_seconds() )) .reset_index() ) print(result)