Question: I have a video file on my local disk and i want to create an rtsp stream from it, which i am going to use in one of my project. One way is to create a rtsp stream from vlc but i want to do it with code (python would be better). I have tried opencv's VideoWritter like this import cv2 _dir = "/path/to/video/file.mp4" cap = cv2.VideoCapture(_dir) framerate = 25.0 out = cv2.VideoWriter( "appsrc ! videoconvert ! x264enc noise-reduction=10000 speed-preset=ultrafast tune=zerolatency ! rtph264pay config-interval=1 pt=96 ! tcpserversink host=127.0.0.1 port=5000 sync=false", 0, framerate, (1920, 1080), ) counter = 0 while cap.isOpened(): ret, frame = cap.read() if ret: out.write(frame) print(f"Read {counter} frames",sep='',end="\r",flush=True) counter += 1 if cv2.waitKey(1) & 0xFF == ord("q"): break else: break cap.release() out.release()  But when i stream it on vlc like this  vlc -v rtsp://127.0.0.1:5000 I am getting   [00007fbb307a3e18] access_realrtsp access error: cannot connect to 127.0.0.1:5000 [00007fbb2c189f08] core input error: open of `rtsp://127.0.0.1:5000' failed [00007fbb307a4278] live555 demux error: Failed to connect with rtsp://127.0.0.1:5000  Gstreamer is another option but as i have never used it, so would be nice if someone points me in the right direction. 

Answer: You tried to expose RTP protocol via TCP server but please note that RTP is not RTSP and that RTP (and RTCP) can only be part of RTSP. Anyways, there is a way to create RTSP server with GStreamer and Python by using GStreamer's GstRtspServer and Python interface for Gstreamer (gi package). Assuming that you already have Gstreamer on your machine, first install gi python package and then install Gstreamer RTSP server (which is not part of standard Gstreamer installation). Python code to expose mp4 container file via simple RTSP server #!/usr/bin/env python import sys import gi gi.require_version('Gst', '1.0') gi.require_version('GstRtspServer', '1.0') from gi.repository import Gst, GstRtspServer, GObject, GLib loop = GLib.MainLoop() Gst.init(None) class TestRtspMediaFactory(GstRtspServer.RTSPMediaFactory): def __init__(self): GstRtspServer.RTSPMediaFactory.__init__(self) def do_create_element(self, url): #set mp4 file path to filesrc's location property src_demux = "filesrc location=/path/to/dir/test.mp4 ! qtdemux name=demux" h264_transcode = "demux.video_0" #uncomment following line if video transcoding is necessary #h264_transcode = "demux.video_0 ! decodebin ! queue ! x264enc" pipeline = "{0} {1} ! queue ! rtph264pay name=pay0 config-interval=1 pt=96".format(src_demux, h264_transcode) print ("Element created: " + pipeline) return Gst.parse_launch(pipeline) class GstreamerRtspServer(): def __init__(self): self.rtspServer = GstRtspServer.RTSPServer() factory = TestRtspMediaFactory() factory.set_shared(True) mountPoints = self.rtspServer.get_mount_points() mountPoints.add_factory("/stream1", factory) self.rtspServer.attach(None) if __name__ == '__main__': s = GstreamerRtspServer() loop.run()  Note that  this code will expose RTSP stream named stream1 on default port 8554 I used qtdemux to get video from MP4 container. You could extend above pipeline to extract audio too (and expose it too via RTSP server) to decrease CPU processing you can only extract video without decoding it and encoding it again to H264. However, if transcoding is needed, I left one commented line that will do the job (but it might choke less powerful CPUs).  You can play this with VLC vlc -v rtsp://127.0.0.1:8554/stream1  or with Gstreamer  gst-launch-1.0 playbin uri=rtsp://127.0.0.1:8554/stream1  However, If you actually do not need RTSP but just end-to-end RTP following Gstreamer pipeline (that utilizes rtpbin) will do the job gst-launch-1.0 -v rtpbin name=rtpbin \ filesrc location=test.mp4 ! qtdemux name=demux \ demux.video_0 ! decodebin ! x264enc ! rtph264pay config-interval=1 pt=96 ! rtpbin.send_rtp_sink_0 \ rtpbin.send_rtp_src_0 ! udpsink host=127.0.0.1 port=5000 sync=true async=false  and VLC can play it with vlc -v rtp://127.0.0.1:5000