Question: I want to send data from app.post() to app.get() using RedirectResponse. @app.get('/', response_class=HTMLResponse, name='homepage') async def get_main_data(request: Request, msg: Optional[str] = None, result: Optional[str] = None): if msg: response = templates.TemplateResponse('home.html', {'request': request, 'msg': msg}) elif result: response = templates.TemplateResponse('home.html', {'request': request, 'result': result}) else: response = templates.TemplateResponse('home.html', {'request': request}) return response  @app.post('/', response_model=FormData, name='homepage_post') async def post_main_data(request: Request, file: FormData = Depends(FormData.as_form)): if condition: ...... ...... return RedirectResponse(request.url_for('homepage', **{'result': str(trans)}), status_code=status.HTTP_302_FOUND) return RedirectResponse(request.url_for('homepage', **{'msg': str(err)}), status_code=status.HTTP_302_FOUND)   How do I send result or msg via RedirectResponse, url_for() to app.get()? Is there a way to hide the data in the URL either as path parameter or query parameter? How do I achieve this?  I am getting the error starlette.routing.NoMatchFound: No route exists for name "homepage" and params "result". when trying this way. Update: I tried the below: return RedirectResponse(app.url_path_for(name='homepage') + '?result=' + str(trans), status_code=status.HTTP_303_SEE_OTHER)  The above works, but it works by sending the param as query param, i.e., the URL looks like this localhost:8000/?result=hello. Is there any way to do the same thing but without showing it in the URL?

Answer: In brief, as explained in this answer and this answer, as well as mentioned by @tiangolo here, when performing a RedirectResponse from a POST request route to a GET request route, the response status code has to change to 303 See Other. For instance (completet working example is given below): return RedirectResponse(redirect_url, status_code=status.HTTP_303_SEE_OTHER)  As for the reason for getting starlette.routing.NoMatchFound error, this is because request.url_for() receives path parameters, not query parameters. Your msg and result parameters are query ones; hence, the error. A solution would be to use a CustomURLProcessor, as suggested in this and this answer, allowing you to pass both path (if need to) and query parameters to the url_for() function and obtain the URL. As for hiding the path and/or query parameters from the URL, you can use a similar approach to this answer that uses history.pushState() (or history.replaceState()) to replace the URL in the browser's address bar. Working example can be found below (you can use your own TemplateResponse in the place of HTMLResponse). Working Example from fastapi import FastAPI, Request, status from fastapi.responses import RedirectResponse, HTMLResponse from typing import Optional import urllib app = FastAPI() class CustomURLProcessor: def __init__(self): self.path = "" self.request = None def url_for(self, request: Request, name: str, **params: str): self.path = request.url_for(name, **params) self.request = request return self def include_query_params(self, **params: str): parsed = list(urllib.parse.urlparse(self.path)) parsed[4] = urllib.parse.urlencode(params) return urllib.parse.urlunparse(parsed) @app.get('/', response_class=HTMLResponse) def event_msg(request: Request, msg: Optional[str] = None): if msg: html_content = """ <html> <head> <script> window.history.pushState('', '', "/"); </script> </head> <body> <h1>""" + msg + """</h1> </body> </html> """ return HTMLResponse(content=html_content, status_code=200) else: html_content = """ <html> <body> <h1>Create an event</h1> <form method="POST" action="/"> <input type="submit" value="Create Event"> </form> </body> </html> """ return HTMLResponse(content=html_content, status_code=200) @app.post('/') def event_create(request: Request): redirect_url = CustomURLProcessor().url_for(request, 'event_msg').include_query_params(msg="Succesfully created!") return RedirectResponse(redirect_url, status_code=status.HTTP_303_SEE_OTHER)  Update 1 - About including query parameters Regarding adding query params to url_for() function, another solution would be using Starlette's starlette.datastructures.URL, which now provides a method to include_query_params. Example: from starlette.datastructures import URL redirect_url = URL(request.url_for('event_msg')).include_query_params(msg="Succesfully created!")  Update 2 - About including query parameters The request.url_for() function now returns a starlette.datastructures.URL object. Hence, you could add query parameters as follows: redirect_url = request.url_for('event_msg').include_query_params(msg="Succesfully created!")