## 3 Results and Discussion  
### Analysis of the Microporous Body-Reaction Combustion Simulation  
As methane and air mainly burn in micropores [31], the gas in micropores is taken as the simulation object and discretized. Then, the above sensor physical model, thermal analysis theoretical model, and reaction mechanism are loaded into FLUENT, after which certain boundary conditions are applied for calculation. Based on this data, the volume \begin{table}
\begin{tabular}{c c c c c c} \hline \hline
**Reaction Serial** & **Response** & **Pre-Exponential** & **Temperature** & **Activation** & \\
**Serial** & **Equation** & **Factor** & **Index** & **Energy E\({}_{a}\)** & **Reaction Rate Index** \\
**Number** & **Equation** & **(A,m.mol.s)** & **(\(\beta\))** & **(J/mol)** & \\ \hline
1 & CH\({}_{4}\) + 1.5O\({}_{2}\)\(\geq\) CO + 2H\({}_{2}\)O & 1.6596 \(\times 10^{15}\) & 0.000 & 1.72 \(\times 10^{8}\) & FORD/CH\({}_{4}\) 1.46/O\({}_{2}\) 0.5217/ \\ \hline
2 & CO + 0.5O\({}_{2}\)\(\geq\) CO\({}_{2}\) & 7.9799 \(\times 10^{14}\) & 0.000 & 9.654 \(\times 10^{7}\) & FORD/CO 1.6904/O\({}_{2}\) 1.57/ \\ \hline
3 & CO\({}_{2}\)\(\geq\) CO + 0.5O\({}_{2}\) & 2.2336 \(\times 10^{14}\) & 0.000 & 5.1774 \(\times 10^{8}\) & \\ \hline
4 & N\({}_{2}\) + O\({}_{2}\)\(\geq\) 2 NO & 8.8308 \(\times 10^{23}\) & 0.000 & 4.4366 \(\times 10^{8}\) & \\ \hline
5 & N\({}_{2}\) + O\({}_{2}\)\(\geq\) 2 NO & 9.2683 \(\times 10^{14}\) & \(-\)0.500 & 5.727 \(\times 10^{8}\) & \\ \hline \hline \end{tabular}
\end{table} 
Table 1: Body reaction mechanism. \begin{table}
\begin{tabular}{c c c c c c c} \hline \hline
**Reaction Serial** & **Response** & **Pre-Exponential** & **Cover** & **Temperature** & **Activation** & \\
**Number** & **Equation** & **Factor** & **Index** & **Energy E\({}_{a}\)** & **Reaction Rate Index** \\ \hline
1 & O\({}_{2}\) + 2 PT(S) \(\geq\) 2O(S) & - & 0.003 & 0 & 0 \\ \hline
2 & CH\({}_{4}\) + 2 PT(S) \(\geq\) CH\({}_{3}\)(S) + H(S) & - & 0.15 & 9.654 \(\times 10^{7}\) & 28,000.00 & FORD/PT(S) 2.3/ \\ \hline
3 & CH\({}_{4}\) + O(S) \(\geq\) CH\({}_{3}\)(S) + OH(S) & - & 0.43 & 0 & 59,200.00 & \\ \hline
4 & CO + PT(S) \(\geq\) CO(S) & - & 0.840 & 0 & 0 & FORD/PT(S) 2/ \\ \hline
5 & H2 + 2 PT(S) \(\geq\) 2H(S) & - & 0.046 & 0.00 & 0.00 & FORD/PT(S) 1.0/ \\ \hline
6 & OH + PT(S) \(\geq\) OH(S) & - & 1.00 & 0.0 & 0.0 & \\ \hline
7 & H\({}_{2}\)O + PT(S) \(\geq\) H\({}_{2}\)O(S) & - & 0.5 & 0.0 & 0.0 & \\ \hline
8 & CH\({}_{3}\)(S) + PT(S) \(\geq\) CH(S) & \(1.0\times 10^{21}\) & - & 0.00 & 20,000.0 & \\ \hline
9 & CH\({}_{2}\)(S) + PT(S) \(\geq\) CH(S) + H(S) & \(1.0\times 10^{21}\) & - & 0.00 & 20,000.0 & \\ \hline
10 & CH(S) + PT(S) \(\geq\) C(S) + H(S) & \(1.0\times 10^{21}\) & - & 0.00 & 20,000.0 & \\ \hline
11 & H(S) + O(S) = OH + 2 PT(S) & \(1.0\times 10^{20}\) & - & 0.00 & 10,500.0 & \\ \hline
12 & OH(S) = H(S) +O(S) & \(1.0\times 10^{12}\) & - & 0.00 & 20,800.0 & \\ \hline
13 & H(S) + OH(S) = H\({}_{2}\)O(S) & \(1.0\times 10^{21}\) & - & 0.00 & 62,500.0 & \\ \hline
14 & OH(S) + OH(S) = H\({}_{2}\)O(S) + O(S) & \(1.0\times 10^{20}\) & - & 0.00 & 51,250.0 & \\ \hline
15 & H\({}_{2}\)O(S) \(\geq\) H(S) + OH(S) & \(1.0\times 10^{13}\) & - & 0.00 & 51,200.0 & \\ \hline
16 & C(S) + O(S) \(\geq\) CO(S) & \(5.0\times 10^{20}\) & - & 0.00 & 62,500.0 & \\ \hline
17 & CO(S) \(\geq\) C(S) + O(S) & \(1.0\times 10^{13}\) & - & 0.00 & 156,500.0 & \\ \hline
18 & CO(S) + O(S) \(\geq\) CO + PT(S) & \(4.0\times 10^{20}\) & - & 0.00 & 49,140.0 & \\ \hline
19 & 2O(S) \(\geq\) O\({}_{2}\) + 2 PT(S) & \(1.0\times 10^{21}\) & - & 0.00 & 21,600.0 & \\ \hline
20 & CO(S) \(\geq\) CO + 2 PT(S) & \(8.5\times 10^{12}\) & - & 0.00 & 152,500.0 & \\ \hline
21 & 2H(S) \(\geq\) H\({}_{2}\) + 2 PT(S) & \(5.0\times 10^{20}\) & - & 0.00 & 67,400.0 & \\ \hline
22 & OH(S) \(\geq\) OH + PT(S) & \(1.5\times 10^{13}\) & - & 0.00 & 192,800.0 & \\ \hline
23 & H\({}_{2}\)O(S) \(\geq\) H\({}_{2}\)O + PT(S) & \(1.0\times 10^{13}\) & - & 0.00 & 45,000.0 & \\ \hline \hline \end{tabular}
\end{table} 
Table 2: Wall reaction mechanism.