## 3 Results
### Key formulas. Calibration-curve recalibration accounting for background precise value.
If we take Equations (18) and (20) into account, we will easily obtain from Equation (19):  
\[I=a_{1}+b_{1}I^{\prime}, \tag{21}\]  
\[a_{1}=K_{\mathrm{C}}(\overset{\rightarrow}{Z^{\prime}})K(\overset{ \rightarrow}{X^{\prime}})\frac{dI_{1}(\overset{\rightarrow}{Y^{\prime}})}{d \overset{\rightarrow}{Y^{\prime}}}(\overset{\rightarrow}{Y}-\overset{ \rightarrow}{Y^{\prime}})+K(\overset{\rightarrow}{X^{\prime}})I_{pl}( \overset{\rightarrow}{Y^{\prime}})\frac{dK_{\mathrm{C}}(\overset{ \rightarrow}{Z^{\prime}})}{dZ^{\prime}}(Z-\overset{\rightarrow}{Z^{\prime}}) \tag{22}\] \[+I_{n}(\overset{\rightarrow}{X^{\prime}})\frac{dK_{\mathrm{C}}( \overset{\rightarrow}{Z^{\prime}})}{d\overset{\rightarrow}{Z^{\prime}}}(Z- \overset{\rightarrow}{Z^{\prime}})+K_{\mathrm{C}}(\overset{\rightarrow}{Z^{ \prime}})\frac{dI_{n}(\overset{\rightarrow}{X^{\prime}})}{d\overset{ \rightarrow}{X^{\prime}}}(\overset{\rightarrow}{X}-\overset{\rightarrow}{X^{ \prime}});\]  
\[b_{1}=1+\frac{1}{\overset{\rightarrow}{K(\overset{\rightarrow}{X^{\prime}})}} \frac{dK(\overset{\rightarrow}{X^{\prime}})}{d\overset{\rightarrow}{X^{ \prime}}}(\overset{\rightarrow}{X}-\overset{\rightarrow}{X^{\prime}})+ \frac{1}{\overset{\rightarrow}{K_{\mathrm{C}}(\overset{\rightarrow}{Z^{ \prime}})}}\frac{dK_{\mathrm{C}}(\overset{\rightarrow}{Z^{\prime}})}{d \overset{\rightarrow}{Z^{\prime}}}(\overset{\rightarrow}{Z}-\overset{ \rightarrow}{Z^{\prime}})+\frac{1}{\overset{\rightarrow}{A(\overset{\rightarrow }{Y^{\prime}})}}\frac{dA(\overset{\rightarrow}{Y^{\prime}})}{d\overset{ \rightarrow}{Y^{\prime}}}(\overset{\rightarrow}{Y}-\overset{\rightarrow}{Y^{ \prime}});\]  
where \(a_{1},b_{1}\), are the functions of only the parameters \(\overset{\rightarrow}{X},\overset{\rightarrow}{Y},\overset{\rightarrow}{Z}, \overset{\rightarrow}{X^{\prime}},\overset{\rightarrow}{Y^{\prime}},\overset{ \rightarrow}{Z^{\prime}}\). In this case, the following is fulfilled:  
\[a_{1}\to 0;\]  
\[b_{1}\to 1\]  
if \[\overset{\rightarrow}{X},\overset{\rightarrow}{Y},\overset{\rightarrow}{Y} \rightarrow\overset{\rightarrow}{Y^{\prime}},\overset{\rightarrow}{Z} \rightarrow\overset{\rightarrow}{Z^{\prime}}\] (23)Now we perform similar transformations under the same assumptions, but with accuracy to terms of the order of \(O\left[ \begin{array}{cccc}\rightarrow&\rightarrow&i&\rightarrow&j& \rightarrow&k\\ (X-X^{\prime})&(Y-Y^{\prime})&(Z-Z^{\prime})\end{array} \right]\), where \(i+j+k=2\). Then it is easy to obtain Equation (21), but with coefficients \(a_{2}\), \(b_{2}\):  
\[ \begin{array}{l}a_{2}=a_{1}+K_{\rm C}(Z^{\prime})\frac{d(K(X^{\prime})}{dX^ {\prime}})\frac{d_{I\!I_{\!I}(Y^{\prime})}}{dY^{\prime}}(\stackrel{{ \rightarrow}}{{X}}-X^{\prime})(Y-Y^{\prime})+K_{\rm C}(Z^{\prime})\frac{K( \stackrel{{\rightarrow}}{{X^{\prime}}})}{2}\frac{d^{2}I_{\!I_{ \!I}(\stackrel{{\rightarrow}}{{Y^{\prime}}})}}{dY^{\prime}}(Y-Y^ {\prime})\\ +\frac{K_{\rm C}(Z^{\prime})}{2}\frac{d^{2}I_{\!I_{\!I}(Y^{\prime})}}{dY^{ \prime}}(Y-\stackrel{{\rightarrow}}{{Y^{\prime}}})&+\frac{I_{\! I_{\!I}(Y^{\prime})}}{2}\frac{d^{2}K_{\rm C}(\stackrel{{ \rightarrow}}{{Z^{\prime}}})}{2}(\stackrel{{\rightarrow}}{{Z^{ \prime}}}-\stackrel{{\rightarrow}}{{Z^{\prime}}})^{2}\\ +\frac{1}{K_{\rm C}(\stackrel{{\rightarrow}}{{Z^{\prime}}})} \frac{dK_{\rm C}(\stackrel{{\rightarrow}}{{Z^{\prime}}})}{d \stackrel{{\rightarrow}}{{Z^{\prime}}}}d\frac{I_{\!I_{\!I}(Y^{ \prime})}}{dY^{\prime}}(\stackrel{{\rightarrow}}{{Z}}- \stackrel{{\rightarrow}}{{Z^{\prime}}})(Y-\stackrel{{ \rightarrow}}{{Y^{\prime}}});\\ \\ \end{array}  \tag{23}\]  
\[