## 3 Results
### Dielectric Loss Tangent
Then, the following is obtained:  
\[\text{r}_{\rm D}(\text{T})=\text{d}\sqrt{\frac{\text{T}}{\text{T}_{A}}\times \frac{W^{(0)}(\text{T})}{W^{(1)}(\text{T})}}. \tag{160}\]1  
Taking the condition \(\mathrm{T}=\mathrm{T}_{cr,move}\) and \(\mathrm{X}\to\Lambda\), when \(\zeta_{st}(\mathrm{T}_{\sigma,move})=\eta_{st}\), we have the following:  
\[\text{r}_{\rm D}(\text{T})=\text{d}\sqrt{\frac{\text{T}}{\text{T}_{A}}\times \frac{W^{(0)}(\text{T})}{W^{(1)}(\text{T})}}. \tag{160}\]2  
The intersection point of function graphs \(\mathrm{D}_{quant,tunnstationary}(\mathrm{T})\), \(\mathrm{D}_{therM,stationary}(\mathrm{T})\) calculated from equation \(\exp\,\left(-\mathrm{X}(\mathrm{T})\right)\times\mathrm{ch}\,\left(\zeta_{ st}(\mathrm{T})\right)=\frac{\exp\,\left(-\Lambda\right)\times\mathrm{ch}\,\eta_{st}}{2- \frac{\Lambda}{\mathrm{X}(\mathrm{T})}}\) indicates temperature \(\mathrm{T}_{c}>\mathrm{T}_{cr,move}\). Here, we present the results of numerical calculations as expressions (163) and (164). We will separately investigate temperature dependencies for the stationary probabilities of the following classical form:  
\[\text{r}_{\rm D}(\text{T})=\text{d}\sqrt{\frac{\text{T}}{\text{T}_{A}}\times \frac{W^{(0)}(\text{T})}{W^{(1)}(\text{T})}}. \tag{160}\]3  
and the quantum tunnel character on the basis of equality:  
\[\text{r}_{\rm D}(\text{T})=\text{d}\sqrt{\frac{\text{T}}{\text{T}_{A}}\times \frac{W^{(0)}(\text{T})}{W^{(1)}(\text{T})}}. \tag{160}\]4  
The temperature is accepted within the range from 0 to 2500 K. The value of the polarizing field strength is taken as \(\mathrm{E}_{0}=10^{6}\) V/m. According to the results of numerical calculations, the value of the polarizing field strength has practically no effect on the values of quantum transparency \(\mathrm{D}_{quant,tunnstationary}(\mathrm{T})\) in the region of fields \(\mathrm{E}_{0}=\left(10^{6}-10^{7}\right)\) V/m at a wide range of temperatures T = 0-2500 K; only in the region of \(\mathrm{E}_{0}=\left(10^{8}-10^{9}\right)\) V/m did the field begin to affect the quantum transparency value. The maximum point of the functions \(\mathrm{D}_{quant,tunnstationary}(\mathrm{T})\) is calculated from the following equation:  
\[\text{r}_{\rm D}(\text{T})=\text{d}\sqrt{\frac{\text{T}}{\text{T}_{A}}\times \frac{W^{(0)}(\text{T})}{W^{(1)}(\text{T})}}. \tag{160}\]5  
Thus, the tunnel components of kinetic coefficients (163) and (164) in the absence of external disturbance (disabled polarizing field) \(\eta_{st}=0\), \(\zeta_{st}(\mathrm{T})=0\) take the form \(\mathrm{D}_{therm,\,\,activestationary}^{(0)}(\mathrm{T})=\exp\,\left(-\mathrm{ X}(\mathrm{T})\right)\) and \(\mathrm{D}_{quant,tunn,stationary}^{(0)}(\mathrm{T})=\frac{\exp\,\left(-\Lambda \right)-\exp\,\left(-\mathrm{X}\right)}{1-\frac{\Lambda}{\mathrm{X}(\mathrm{T} )}}\) and agree with (133), (134), and (10a) \(W^{(0)}(\mathrm{T})=W_{therm,\,\,active}^{(0)}(\mathrm{T})+W_{quant,tunn}^{(0)}( \mathrm{T})\), where we accept the following designations:  
\[\text{r}_{\rm D}(\text{T})=\text{d}\sqrt{\frac{\text{T}}{\text{T}_{A}}\times \frac{W^{(0)}(\text{T})}{W^{(1)}(\text{T})}}. \tag{160}\]6  
According to the results of numerical calculations, at an activation energy of \(\mathrm{U_{01}}=0.01\) eV, when the characteristic parameter is \(\Lambda_{1}=\frac{\pi\mathrm{\kappa_{0}}\sqrt{\mathrm{U_{01}}}}{\hbar\sqrt{2 }}=X_{\sigma,move,1}=\frac{\mathrm{U_{01}}}{\mathrm{R_{0}}\mathrm{T}_{\sigma, move,1}}\approx 2.921406892621811\), the critical temperature of \(\mathrm{T}_{cr,move,1}=\frac{\hbar\mathrm{\gamma_{0}}\mathrm{U_{01}}}{\pi \mathrm{R_{0}}\mathrm{R_{0}}\sqrt{\mathrm{M}}}\approx 39.5774\) K at which the stationary statistically averaged transparency of the unperturbed external field parabolic potential barrier is \(\mathrm{D}_{quant,tunnstationary}^{(0)}(\mathrm{T}_{cr,move,1})\approx 0.1555\).